Based on your data and using deductive reasoning, what can you conclude about the trends in the solubilities of the compounds of the alkaline earth metals?

Answer:

0.067M Fe(NO3)3

Explanation:

A stock solution is a concentrated solution that is diluted to prepare the solutions that you will use.

The volume of the stock solution is 3.0mL + 10.0mL + 17.0mL= 30.0mL.

The ratio between volume of the aliquot (10.0mL) and total volume (30.0mL) is called dilution factor, that is: 30.0mL / 10.0mL = 3

That means the Fe(NO3)3 is diluted 3 times. That means the molar concentration of the stock solution is:

0.200M / 3 =

Answer: i think its protons and electrons but it also might just be atoms because protons and electrons  make atoms when there are also neutrons

Explanation:

A. The balanced equation is: Zn + 2HCI -> ZnCl₂ + H₂

B. The mass of zinc chloride formed is 10.43 g

C. The volume of hydrogen gas produced is 1.68 L

First, we shall write the balanced equation for the reaction. This is given below:

Zn + 2HCI -> ZnCl₂ + H₂

Now, we shall determine the mass of zinc chloride, ZnCl₂ formed. Details below:

Zn + 2HCI -> ZnCl₂ + H₂

From the balanced equation above,

65.38 g of Zn reacted to produce 136.38 g of ZnCl₂

Therefore,

5 g of Zn will react to produce = (5 × 136.38) / 65.38 = 10.43 g of ZnCl₂

Thus, the mass of ZnCl₂ formed is 10.43 g

First, we shall obtain the mass of hydrogen gas produced. Details below:

Zn + 2HCI -> ZnCl₂ + H₂

From the balanced equation above,

65.38 g of Zn reacted to produce 2 g of H₂

Therefore,

5 g of Zn will react to produce = (5 × 2) / 65.38 = 0.15 g of H₂

Finally, we shall determine the volume of H₂ produced. Details below:

2 g of H₂ = 22.4 L

Therefore

0.15 g of H₂ = (0.15 g × 22.4 L) / 2 g

0.15 g of H₂ = 1.68 L

Thus, the volume of H₂ produced is 1.68 L

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The percent by mass of the fluorine in the compound is 46.472%.

We know that the percent by mass has to do with the ratio of the total mass of the atom that is part of the compound and the total molar mass of the compound multiplied by one hundred.

The question in this case has demanded that we ought to obtain the mass percent of fluorine from the compound that we can be able to identify from the formula of the compound that is shown here as xenon hexa fluoride.

Mass of the compound can be obtained from; 131 + 6(19)

= 245 g/mol

The total mass of the fluorine atom in the compound is 114 g

Thus we have the use of;  114 /245 * 100/1

= 46.472%

The percent  by mass is now gotten for the fluorine atom as 46.472%.

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Answer:

\(Molec_{\ H_{tot}}=1.206x10^{25}molec\)

Explanation:

Hello.

In this case, taking into account that HCl has one molecule of hydrogen per mole of compound which weights 36.45 g/mol, we compute the number of molecules of hydrogen in hydrochloric acid by considering the given mass and the Avogadro's number:

\(molec_{\ H}=3.65gHCl*\frac{1molHCl}{36.45gHCl} *\frac{1molH}{1molHCl}*\frac{6.022x10^{23}molec_\ H}{1molH} =6.03x10^{22}molec\)

Now, from the 180 g of water, we see two hydrogen molecules per molecule of water, thus, by also using the Avogadro's number we compute the molecules of hydrogen in water:

\(molec_{\ H}=180gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O}*\frac{6.022x10^{23}molec_\ H}{1molH} =1.20x10^{25}molec\)

Thus, the total number of molecules turns out:

\(Molec_{\ H_{tot}}=6.03x10^{22}+1.20x10^{25}\\\\Molec_{\ H_{tot}}=1.206x10^{25}molec\)

Regards.

Answer:

C₅H₁₀O (l) + 7 O₂ (g) --> 5 H₂O (g) + 5 CO₂ (g)

Explanation:

In the original equation: C₅H₁₀O (l) + O₂ (g) --> H₂O (g) + CO₂ (g)

Reactants: 5 carbon, 10 hydrogen, 3 oxygen

Products: 1 carbon, 2 hydrogen, 3 oxygen

Cleary, the equation is not balanced. When deciding which element to balance first, avoid balancing elements that are present in more than one molecule on either side (ex. the oxygen on the reactant side). In this case, I started with carbon. Once the carbon was balanced, I balanced the hydrogen, keeping in mind the new coefficients I added when balancing the carbons. Lastly, I balanced the oxygen.

The balanced equation: C₅H₁₀O (l) + 7 O₂ (g) --> 5 H₂O (g) + 5 CO₂ (g)

Reactants: 5 carbon, 10 hydrogen, 15 oxygen

Products: 5 carbon, 10 hydrogen, 15 oxygen

Answer: true

Explanation: An atom does of a positively charged nucleus, surrounded by one or more negatively charged particles called electrons. The positive charges equal the negative charges, so the atom has no overall charge; it is electrically neutral. Protons and neutrons have nearly equal masses, but in a way they DO differ in charge.

The theoretical yield of Acetylsalicylic acid is found out to be: 3.01 grams.

The limiting reagent is a substance that prevents a chemical reaction from occurring completely.

When a limiting reagent is used in a chemical reaction, the atoms, molecules, or ions of the other reactant that it (the limiting reagent) reacts with will either stay free or unreacted.

Popular compounds called acids and bases interact with one another to create salt and water. The Latin word "acere," which meaning "sour," is where the term "acid" originates.

According to the problem, we have 2.31 grams of salicylic acid. We need to determine the theoretical yield of acetylsalicylic acid.

The molar mass of salicylic acid is 138.12 g/mol. Therefore, the number of moles of salicylic acid we have is:

n = mass / molar mass

n = 2.31 g / 138.12 g/mol

n = 0.0167 mol

According to the balanced equation, 1 mole of salicylic acid reacts with 1 mole of acetic anhydride to produce 1 mole of acetylsalicylic acid. Therefore, the number of moles of acetylsalicylic acid produced is also 0.0167 mol.

The molar mass of acetylsalicylic acid is 180.16 g/mol. Therefore, the theoretical yield of acetylsalicylic acid is:

mass = n x molar mass

mass = 0.0167 mol x 180.16 g/mol

mass = 3.01 g

Therefore, the theoretical yield of acetylsalicylic acid is 3.01 grams.

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Answer:

When conducting a chemistry lab experiment using chalk (calcium carbonate) in vinegar (acetic acid), there are several limitations and precautions to be aware of:

Limitations of chalk in vinegar chemistry experiment:

Reaction rate: The reaction between chalk and vinegar is relatively slow, which may require a longer observation period or higher concentration of vinegar to observe significant changes within a reasonable time frame.

Solubility: Chalk may not dissolve completely in vinegar, resulting in incomplete reaction or difficulty in obtaining accurate results.

Product formation: The reaction between chalk and vinegar produces carbon dioxide gas, water, and calcium acetate. The carbon dioxide gas may escape into the atmosphere, leading to loss of product and inaccurate measurements.

pH: Chalk is a basic substance, and the reaction with vinegar, which is acidic, may result in neutralization, leading to a decrease in the overall acidity of the reaction mixture.

Precautions to take in chalk in vinegar chemistry experiment:

Ventilation: The reaction between chalk and vinegar produces carbon dioxide gas, which can displace air and potentially cause asphyxiation in a closed or poorly ventilated area. Conduct the experiment in a well-ventilated area or under a fume hood to ensure adequate air circulation.

Eye and skin protection: Vinegar is an acid and can cause skin and eye irritation. Wear appropriate personal protective equipment (PPE), such as gloves and goggles, to protect yourself from contact with vinegar or any other chemicals used in the experiment.

Chemical handling: Handle the chemicals, including chalk and vinegar, with care, following proper lab safety protocols. Avoid ingestion, inhalation, or direct contact with the chemicals, and dispose of them properly according to local regulations.

Accuracy in measurements: Use calibrated and accurate measuring tools, such as graduated cylinders or burettes, to measure the amount of chalk, vinegar, and other reagents accurately. This will ensure the reliability and accuracy of the experimental results.

Observations: Make careful and detailed observations during the experiment, noting any changes in appearance, gas evolution, or other relevant observations. Take measurements at appropriate intervals and record the data accurately for analysis and interpretation.

It is important to follow good laboratory practices, including proper chemical handling, accurate measurements, and cautious observations, to ensure safe and reliable results in a chalk in vinegar chemistry lab experiment. Consult with a qualified instructor or supervisor for specific guidelines and precautions related to your experiment.

Answer:

has 5, ans 3 decimals.

thats as simple as i can put it.

The accurate systematic name of the coordination compound is diaminodicyano platinum II.

A coordination compound is which contains a central metal atom or ion along with ligands in its coordination sphere. Some times, counterions may alaso be present to balance the charges.

The accurate systematic name of the coordination compound is diaminodicyano platinum II.

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Answer:

C. Physical weathering.

Answer: C. Physical weathering.

Explanation:

Answer:

Compazine belongs to a class of drugs called Antiemetic Agents; Antipsychotics, Phenothiazine.

The flow rate of the IV pump should be 17.06mL/hr.

1st) We need to calculate the patient's weight knowing that 1 lb is equal to 0.45 kg:

The patient weighs 106.65 kg.

2nd) If the patient needs a drip at 8.0 units per kg of body weight, we have to calculate the units for the patient:

So, the patient needs 853.2 units per hour.

3rd) To calculate the flow rate of the IV pump, we need to know the mL equivalent to 853.2 units:

So, the flow rate of the IV pump should be 17.06mL/hr.

The machine exerts a force of 9 newtons on the baseball to accelerate it from 0 m/s to 30 m/s in 0.5 seconds.

To calculate the force exerted by the machine on the baseball, we can use Newton's second law of motion, which states that force (F) is equal to the product of mass (m) and acceleration (a).

In this case, the acceleration can be determined using the formula a = (v - u) / t, where v is the final velocity, u is the initial velocity, and t is the time taken for the acceleration.

Given:

Mass of the baseball (m) = 0.15 kg

Initial velocity (u) = 0 m/s (as the baseball starts from rest)

Final velocity (v) = 30 m/s

Time (t) = 0.5 s

First, let's calculate the acceleration:

a = (v - u) / t

a = (30 m/s - 0 m/s) / 0.5 s

a = 60 m/s^2

Now, we can use the calculated acceleration and the given mass to determine the force:

F = m * a

F = 0.15 kg * 60 m/s^2

F = 9 N

The machine exerts a force of 9 newtons on the baseball. This force is calculated using Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.

By determining the acceleration of the baseball using the formula a = (v - u) / t and substituting the given values, we find that the acceleration is 60 m/s^2. Multiplying the mass of the baseball (0.15 kg) by the acceleration gives the force exerted by the machine as 9 newtons.

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Answer:

we use atom in our sentences all the time

Explanation:

that what i put

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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0.02g/L

This question involves conversion of units and in this case, we are converting from g/ml to g/l.

1 g/ml = 1000 g/L

And we are given 0.020 g/ml to convert into g/L. The easiest way to do this is simply multiply 0.020 g/mL by 1000 to convert it into g/L

From the calculation above, 0.020g/ml is equivalent to 20g/L.

Answer:How many moles of aluminum are needed to react completely with 1.2 mol of FeO? 2Al(s) + 3FeO(s) = 3Fe(s) + Al2O3(s). 0.8 mols.

Explanation:

Answer:

Explanation:The volume of the box is 8.6 × 10³ in².

V = lwh = 26 in × 18.4 in × 17.92 in = 8.6 × 10³ in²

Note: The answer can have only two significant figures because that is all you gave for the length of the box.

bezglasnaaz and 23 more users found this answer helpful

Answer:

0.02 moles of O₂ will be leftover.

Explanation:

The reaction is:

2NO(g) + O₂(g) → 2NO₂(g)    (1)

We have the mass of NO and O₂, so we need to find the number of moles:

\( n_{NO} = \frac{m}{M} = \frac{24.7 g}{30.01 g/mol} = 0.82 moles \)

\( n_{O_{2}} = \frac{m}{M} = \frac{13.8 g}{31.99 g/mol} = 0.43 moles \)

From equation (1) we have that 2 moles of NO reacts with 1 mol of O₂ to produce 2 moles of NO₂, so the excess reactant is:

\( n_{NO} = \frac{2}{1}*0.43 moles = 0.86 moles \)          

\(n_{O_{2}} = \frac{1}{2}*0.82 moles = 0.41 moles\)                                                                                

Hence, from above we can see that the excess reactant is O₂ since 0.41 moles react with 0.86 moles of NO and we have 0.43 moles in total for O₂.

The number of moles of excess reactant is:

\(n_{T} = 0.43 moles - 0.41 moles = 0.02 moles\)  

Therefore, 0.02 moles of O₂ will be leftover.

I hope it helps you!                    

The number of moles of excess reactant that would be left over is 0.0197 mole

From the question,

We are to determine the number of moles of excess reactant that would be left over.

The given balanced chemical equation for the reaction is

2NO(g) + O₂(g) → 2NO₂ (g)

This means,

2 moles of NO is needed to completely react with 1 mole of O₂

Now, we will determine the number of moles of each reactant present

Mass = 24.7 g

Molar mass = 30.01 g/mol

From the formula

\(Number\ of\ moles = \frac{Mass}{Molar\ mass}\)

∴ Number of moles of NO present = \(\frac{24.7}{30.01}\)

Number of moles of NO present = 0.823059 mole

Mass = 13.8 g

Molar mass = 32.0 g/mol

∴ Number of moles of O₂ present = \(\frac{13.8}{32.0}\)

Number of moles of O₂ present = 0.43125 mole

Since,

2 moles of NO is needed to completely react with 1 mole of O₂

Then,

0.823059 mole of NO is will react with completely react with \(\frac{0.823059 }{2}\) mole of O₂

\(\frac{0.823059 }{2} = 0.4115295\)

∴ Number of moles of O₂ that reacted is 0.4115295 mole

This means O₂ is the excess reactant and NO is the limiting reactant

Now, for the number of moles of excess reactant left over

Number of moles of excess reactant left over = Number of moles of O₂ present - Number of moles of O₂ that reacted

∴ Number of moles of excess reactant left over = 0.43125 mole - 0.4115295 mole

Number of moles of excess reactant left over = 0.0197205 mole

Number of moles of excess reactant left over ≅ 0.0197 mole

Hence, the number of moles of excess reactant that would be left over is 0.0197 mole

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Answer:

72.04g Ti and 7.75g Na

Explanation:

1.505 mol Ti x (47.87g/1 mol) = 72.04g Ti

0.337 mol Na x (22.99g/1 mol) = 7.75g Na

72.04g Ti and 7.75g Na mass in grams of these samples.

Molecular mass can be determined by the measure of mass related to a molecule which is otherwise called as atomic weight, means the mass of every atom present in the molecule.

For example, water have 2 hydrogen atoms and 1 oxygen atom, the molecular mass of water is equals to  the normal atomic mass of hydrogen increased by two or more the atomic mass of oxygen.

molecular mass can be controlled by many factors like Mass Spectrometry which is used to decide the mass of little molecule which is otherwise called as monoisotopic mass.

It can also be controlled by Hydrodynamic Strategy requires calibration and  determine the relative atomic weight; Static Light Scattering where the  Molecular weight is determined from the measure of light dispersed utilizing the Zimm technique.

So, 1.505 mol Ti x (47.87g/1 mol) = 72.04g Ti

0.337 mol Na x (22.99g/1 mol) = 7.75g Na, hence the answer is 72.04g Ti and 7.75g Na

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Answer:

The death of Jesus was a unique, one of a kind, once for all death that ransomed mankind from sin and satisfied the righteousness of God and made it possible for man to once again have a personal relationship with God. The simple definition of death is separation.

Explanation:

hope this helps? :))

Answer:

He was nailed to the cross to save his people

Explanation:

its simple in the bible they say how he died

Answer:

This question appears incomplete

Explanation:

However, an alpha hydrogen is the hydrogen that is found on the alpha, α-carbon in an organic molecule. Alpha carbon is referred to the first carbon that is attached to a functional group. Generally, compounds that do not have alpha carbon do not have alpha hydrogen. For example, first member of all functional groups do not usually have alpha carbon and hence do not have alpha hydrogen.

Also, Alkanes, alkenes and alkynes do not have also

Answer:

288 g/mol

Explanation:

What is diffusion?

• It is a process whereby the random motion of particles move from a region of higher concentration to a region of lower concentration.

Graham's law of diffusion of gas

• states that at constant conditions of temperature and pressure, the rate of diffusion of gases is inversely proportional to the square root of their molar masses

\(\boxed{ \frac{Rate_1}{Rate_2} = \sqrt{ \frac{M_2}{M_1} } } \)

Calculations

Oxygen exist as O₂ at room temperature, thus its molar mass is 2(16)= 32.

Let the rate of O₂ be Rate₁, while the rate and molar mass of the unknown gas be Rate₂ and M₂ respectively.

Since O₂ diffuses 3 times as fast as the unknown gas,

Rate₁= 3(Rate₂)

\(\frac{Rate_1}{Rate_2} = 3 \)

\( 3 = \sqrt{ \frac{M_2}{32} } \)

\( \sqrt{ \frac{M_2}{32} } = 3\)

Square both sides:

\( \frac{M_2}{32} = 3^{2} \)

\( \frac{M_2}{32} = 9\)

Multiply both sides by 32:

M₂= 9(32)

M₂= 288

To answer this question, we need to convert grams to moles and then use the Avogadro's number to convert moles to molecules.

The molar mass of Mg(OH)2 is 58.32 g/mol.

First, we need to find the number of moles of Mg(OH)2 in 75.0 g.

75.0 g / 58.32 g/mol = 1.287 mol

Next, we need to convert moles to molecules.

1.287 mol x 6.022 x 10^23 molecules/mol = 7.75 x 10^23 molecules

Finally, we can use the molecular formula of Mg(OH)2 to calculate the number of miles of Mg(OH)2.

1 molecule of Mg(OH)2 contains 3 atoms of oxygen (O) and 2 atoms of hydrogen (H).

So, the total number of miles of Mg(OH)2 is:

7.75 x 10^23 molecules x 2 miles/molecule = 1.55 x 10^24 miles

Therefore, there are 1.55 x 10^24 miles of magnesium hydroxide in 75.0 g of magnesium hydroxide.