Based on the following titration curve, what is the concentration of the weak base that is being titrated if the initial volume of base solution is 10 ml and the concentration of the hcl is 0. 2 m?.

Answer

• Hydrogen bromide: dispersion and dipole-dipole

• Bromine: dispersion

• Hypochlorus acid : dispersion, dipole-dipole, hydrogen bond

• Molecular oxygen: dispersion

Procedure

The London dispersion force is a temporary attractive force that results when the electrons are in two adjacent atoms. These are the weakest intermolecular forces and exist between all types of molecules, whether ionic or covalent—polar or nonpolar.

Dipole-dipole: occur between polar molecules when the partially positively charged part of a molecule interacts with the partially negatively charged part of another molecule.

A hydrogen bond: is a special kind of dipole-dipole interaction that occurs specifically between a hydrogen atom bonded to an oxygen, nitrogen, or fluorine atom.

Based on the previous:

Hydrogen bromide: dispersion and dipole-dipole

Bromine: dispersion

Hypochlorus acid : dispersion, dipole-dipole, hydrogen bond

Oxygen: dispersion

Answer:

Why are small quantities of chlorofluorocarbons so harmful to the ozone layer?  Free oxygen atoms can replace the chlorine in chlorine monoxide, releasing a free atom of chlorine which can then recombine with an oxygen atom in ozone, destroying more ozone.

Explanation:

The statement for small quantities of chlorofluorocarbons so harmful to the ozone layer is "Free oxygen atoms can replace the chlorine in chlorine monoxide, releasing a free atom of chlorine which can then recombine with an oxygen atom in ozone, destroying more ozone."

The ozone layer is a thin layer of air in the Earth's atmosphere that absorbs nearly all of the sun's damaging UV radiation.

CFCs (chlorofluorocarbons) are harmless and nonflammable compounds made up of carbon, chlorine, and fluorine atoms.

The earth's protective ozone layer is destroyed by chlorofluorocarbons (CFCs), hydrochlorofluorocarbons (HCFCs), and halons, which shield the earth from damaging ultraviolet (UV-B) rays released by the sun. CFCs and HCFCs also warm the earth's lower atmosphere, causing global climate change.

When some substances are exposed to high UV radiation in the stratosphere, they emit chlorine or bromine. Ozone-depleting chemicals are compounds that contribute to ozone depletion (ODS). Chlorofluorocarbons (CFCs), hydrochlorofluorocarbons (HCFCs), carbon tetrachloride, and methyl chloroform are examples of ODS that produce chlorine. Halons and methyl bromide are two ODS that emit bromine.

Because there isn't much ozone in the atmosphere, what little there is is critical for protecting the Earth's surface from excessive UV light from the Sun. It turns out that it reacts with chlorine, which means that chlorine effectively eliminates ozone.

When the chlorine in CFCs combines with ultraviolet light, it releases chlorine, which then reacts with ozone, reducing the protection humans get from ultraviolet light, allowing more CFCs to release chlorine, and so on. Multiple ozone molecules will interact with one free chlorine atom, which is free because UV light has hit the CFC molecule. As a result, the damage it can cause is likely to be significantly more than you might imagine.

Hence the correct option is c.

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There are approximately 1.387 moles in 25 grams of water (1) and 134.46 grams in 4.5 moles of Li₂O (2).

1. To calculate the number of moles, we need to divide the given mass of water by the molar mass of water, which is approximately 18.015 g/mol.

Number of moles = 25 grams / 18.015 g/mol

≈ 1.387 moles

Therefore, there are approximately 1.387 moles in 25 grams of water.

2. To calculate the mass in grams, we need to multiply the number of moles by the molar mass of Li₂O, which is approximately 29.88 g/mol.

Mass in grams = 4.5 moles x 29.88 g/mol

≈ 134.46 grams

Therefore, there are approximately 134.46 grams in 4.5 moles of Li₂O.

3. To determine the number of molecules in 23 moles of oxygen, we can use Avogadro's number, which states that there are 6.022 x 10²³ molecules in one mole of any substance. Therefore, for 23 moles of oxygen, we can calculate:

Number of molecules = 23 moles x 6.022 x 10²³ molecules/mole

= 1.38646 x 10²⁵ molecules

So, there are approximately 1.38646 x 10²⁵ molecules in 23 moles of oxygen.

4. To determine the number of moles in 3.4 x 10²³ molecules of H₂SO₄, we can use Avogadro's number. Since one mole contains 6.022 x 10²³ molecules, we can calculate:

Number of moles = (3.4 x 10²³ molecules) / (6.022 x 10²³ molecules/mole)

= 0.564 moles

So, there are approximately 0.564 moles in 3.4 x 10²³ molecules of H₂SO₄.

5. To determine the number of molecules in 25 grams of NH₃, we need to convert grams to moles using the molar mass of NH₃. The molar mass of NH₃ is 17.03 g/mol.

Number of moles = 25 grams / 17.03 g/mol

≈ 1.468 moles

Using Avogadro's number, we can calculate the number of molecules:

Number of molecules = (1.468 moles) x (6.022 x 10²³ molecules/mole)

= 8.831 x 10²³ molecules

So, there are approximately 8.831 x 10²³ molecules in 25 grams of NH₃.

The complete question is:

Answer the following questions:

1) How many moles are in 25 grams of water?

2) How many grams are in 4.5 moles of Li₂O?

3) How many molecules are in 23 moles of oxygen?

4) How many moles are in 3.4 x 10²³ molecules of H₂SO₄?

5) How many molecules are in 25 grams of NH₃ ?

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1,2-dibromo-1,2-diphenylethane is prepared through the bromination of trans-stilbene, a reaction involving an electrophilic addition mechanism.

The reaction starts with the generation of a bromine radical (Br•) by a free-radical initiator. This radical reacts with trans-stilbene, producing a brominated stilbene radical (Ph-CH=CH-Ph•Br). The brominated radical further reacts with another bromine radical to form the final product, 1,2-dibromo-1,2-diphenylethane (Ph-CHBr-CHBr-Ph).

Arrow pushing in the mechanism:
1. The π bond of trans-stilbene donates an electron pair to Br•, forming a bond between the carbon and bromine.
2. The brominated stilbene radical donates an electron pair to another Br•, forming a bond between the second carbon and bromine.

A potential undesired side reaction is the formation of 1,1-dibromo-1,2-diphenylethane, a regioisomer. This occurs when the brominated stilbene radical reacts with another bromine molecule (Br₂) instead of a bromine radical. The carbon-bromine bond in the intermediate species can break, forming a carbocation (Ph-CHBr-CH⁺-Ph) and a bromide ion (Br⁻). The carbocation then captures the bromide ion, resulting in the undesired product (Ph-CHBr₂-CHBr-Ph).

Arrow pushing in the side reaction:
1. The brominated stilbene radical donates an electron pair to Br₂, forming a bond between the second carbon and one bromine.
2. The carbon-bromine bond in the intermediate species breaks, producing a carbocation and a bromide ion.
3. The carbocation captures the bromide ion, forming the undesired product.

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Answer:

It will explode, I have plenty of research on this. Let me know if you want the sources. :)

Explanation:

Answer:

Explanation:

There will be no reaction when carbon tetrachloride is added to water.  This is because the two substances do not mix.  It is not due to density difference (like the case of Mercury and water) but rather carbon tetrachloride is non-polar while water is polar.  So they will separate and form two different layers with no reaction happening.

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 127 g

volume = 11 mL

We have

\(density = \frac{127}{11} \\ = 11.545454...\)

We have the final answer as

Hope this helps you

Answer:

2 8 8 2 is a correct answer

Answer:

2 8 8 2 yup

Explanation:

b. false Water is a good conductor of electricity, and if it comes into contact with electrical components or wiring, it can create a risk of electrical shock. Therefore, team members should indeed be careful not to let water splash into the lemonade dispenser when the panels are off for cleaning.

This precaution is necessary to ensure the safety of the individuals handling the equipment. It is important to note that electrical shock can occur when there is a complete or partial path for electric current to flow through the body. Water can provide this path of conductivity and increase the likelihood of electrical shock. Therefore, team members should take appropriate precautions to prevent water from reaching the electrical components and ensure their own safety.

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Answer:

-269.75 degrees Celsius

Explanation:

The new pressure of a nitrogen gas at STP is 0.021atm.

The pressure of a gas can be calculated by using the combined gas law equation as follows:

P₁V₁/T₁ = P₂V₂/T₂

Where;

At STP, a gas has the following:

0.073 × 1/273 = 4.53 × P/353

0.0002674 × 353 = 4.53P

P = 0.021atm

Therefore, 0.021atm is the pressure of the nitrogen gas.

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The new pressure of the gas would be  0.0208 atm.

According to the general gas law, the ratio of the product of the pressure and volume to its temperature is constant.

The general gas law is summarily expressed as the following equation:

\(p_1v_1/t_1\) = \(p_2v_2/t_2\). where:

\(p_1\) = initial pressure of a gas

\(v_1\) = initial volume of the gas

\(t_1\) = initial temperature of the gas

\(p_2\) = final pressure of the gas

\(v_2\) = final volume of the gas

\(t_2\) = final temperature of the gas

In this case:

\(p_1\) = standard pressure = 1 atm

\(v_1\) = 73 mL or 0.073 L

\(t_1\) = standard temperature = 273 K

\(p_2\) = ?

\(v_2\) = 4.53 L

\(t_2\) = 80 + 273 = 353 K

\(p_2\) = \(p_1v_1t_2/t_1v_2\)

   = 1x0.073x353/273x4.53

   = 25.769/1236.69

    = 0.0208 atm

Thus, the new pressure of 73.0 mL nitrogen that was heated to a volume of 4.53 L at STP is 0.0208 atm.

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Answer:

313.2 g of \({K_{2} }S O_{4}\)  must be added to 1.20 liters of water to produce a 1.50 molar solution.

Explanation:

What is molarity?

According to the given question,

Solution :

∴ Number of moles of solute, here, \({K_{2} }S O_{4}\)

= molarity x volume of the solution

= 1.20 x  1.50 = 1.8

∴ Mass of 1.8 moles of \({K_{2} }S O_{4}\) = 1.8 x molar mass of   \({K_{2} }S O_{4}\)  

Now the molar mass of \(K_{2} SO_{4}\)

= (Gram atomic mass of K x 2) + (Gram atomic mass of S) + (Gram atomic mass of O x 4)

= (39x2) + 32 + (16 x 4) g

= 174 g.

∴ Mass of 1.5 moles of \({K_{2} }S O_{4}\)

= 1.8 x molar mass of   \({K_{2} }S O_{4}\)  

= 1.8 x 174 g

= 313.2 g.

Thus, 313.2 g of \({K_{2} }S O_{4}\)  must be added to 1.20 liters of water to produce a 1.50 M solution.

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After 10 seconds, 88 grams of unobtanium-31 are present, after 20 seconds, 44 grams are present, after 30 seconds, 22 grams are present, after 40 seconds, 11 grams are present, and after 50 seconds, 5.5 grams are present.

The amount of unobtanium-31 remaining after certain intervals of time, given that the half-life of the radioactive element is 10 seconds is calculated below.

Initial quantity of the element is given as 176 grams.  

After 10 seconds:

Let's first figure out the fraction of the sample remaining after each time period because the half-life of a radioactive element tells us the fraction that decays over a certain period of time.

Using the half-life equation:

amount remaining = original amount x (1/2)^(time elapsed / half-life)

After 10 seconds, the time elapsed is equal to the half-life of the element,

So:

amount remaining = 176 x (1/2)^(10/10)

                               = 88 grams

After 20 seconds:

amount remaining = 176 x (1/2)^(20/10)

                               = 44 grams

After 30 seconds:

amount remaining = 176 x (1/2)^(30/10)

                               = 22 grams

After 40 seconds:

amount remaining = 176 x (1/2)^(40/10)

                               = 11 grams

After 50 seconds:

amount remaining = 176 x (1/2)^(50/10)

                               = 5.5 grams

Therefore, after 10 seconds, 88 grams of unobtanium-31 are present, after 20 seconds, 44 grams are present, after 30 seconds, 22 grams are present, after 40 seconds, 11 grams are present, and after 50 seconds, 5.5 grams are present.

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As an animal grows, its mass increases. The matter that makes up this new mass comes mostly from the food  that the animal consumes.

Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.

Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.

The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.

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Answer:

the natural and man made thing which we can see around us is known as environment. not enviorement.

Answer:

Environment means anything that surrounds us. It can be living (biotic) or non-living (abiotic) things. It includes physical, chemical and other natural forces. ... In the environment there are different interactions between animals, plants, soil, water, and other living and non-living things.

The mole percent of toluene in the vapor mixture can be obtained by multiplying y_toluene by 100. substitute the known values into the DIPPR equation,  the mole fraction of toluene in the vapor phase (y_toluene) is  47.47%.

To calculate the mole percent of toluene in the vapor mixture at equilibrium with a liquid mixture of benzene and toluene, we can use the DIPPR equation. The DIPPR (Design Institute for Physical Property Data) equation is an empirical equation that relates the vapor-liquid equilibrium (VLE) composition to temperature and composition.

The DIPPR equation for calculating mole fraction in a vapor-liquid equilibrium is given as: y_i = x_i * P_i_sat(T) / P. where: y_i is the mole fraction of component i in the vapor phase, x_i is the mole fraction of component i in the liquid phase, P_i_sat(T) is the vapor pressure of pure component i at temperature T, and P is the total pressure of the system.

In this case, we have a liquid mixture of 40% benzene and 60% toluene. Let's assume a total pressure of P for the system and consider the vapor phase at equilibrium. We can use the DIPPR equation to calculate the mole fraction of toluene (y_toluene) in the vapor phase.

First, we need to determine the mole fraction of toluene in the liquid phase (x_toluene). Since the liquid mixture is composed of 40% benzene and 60% toluene, we have x_toluene = 0.60. Next, we need the vapor pressure of pure toluene at the given temperature of 50 °C. We can obtain this value from reliable sources or thermodynamic databases, such as the DIPPR database.

Finally, substitute the known values into the DIPPR equation to calculate the mole fraction of toluene in the vapor phase (y_toluene). The mole percent of toluene in the vapor mixture can be obtained by multiplying y_toluene by 100.

It's important to note that the DIPPR equation is an approximation, and for accurate calculations, it's advisable to consult more comprehensive thermodynamic models or databases specific to the system being analyzed.

We can calculate the mole fraction of toluene in the vapor phase: yT = 0.6 * 0.7911 = 0.4747 Therefore, the mole% of toluene in the vapor mixture at equilibrium with a liquid mixture of 40% benzene and 60% toluene at 50°C is 47.47%.

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The correct formula of the molecule is C4H9O2.

The model of a compound is a representation of the molecule. It gives us an idea of what the molecule looks like as well as its molecular formula.

Looking at the structure of the compound as shown in the model in the question, the correct formula of the molecule is C4H9O2.

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Answer:C4H9O2.

Explanation:

The melting points of stearic acid and linoleic acid can be attributed to differences in their molecular structures.

Stearic acid, also known as octadecanoic acid, is a saturated fatty acid with a straight carbon chain consisting of 18 carbon atoms. Each carbon atom in stearic acid is bonded to two hydrogen atoms and a carboxylic acid group (-COOH). The presence of saturated carbon-carbon (C-C) bonds throughout the molecule allows for strong intermolecular interactions, such as van der Waals forces, which require a relatively higher amount of energy to break. As a result, stearic acid has a higher melting point of 69 °C.

On the other hand, linoleic acid is an unsaturated fatty acid with 18 carbon atoms, but it contains two double bonds in its carbon chain. The presence of these double bonds introduces kinks in the molecule, preventing the carbon chain from packing closely together. This reduces the strength of intermolecular forces, resulting in a lower melting point. Linoleic acid has a melting point of approximately -5 °C.

In summary, the difference in the melting points of stearic acid and linoleic acid is primarily due to the presence of saturated versus unsaturated carbon-carbon bonds in their respective molecular structures.

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Both combinations are stable, but the stability of atoms is determined by the balance of the attractive forces of protons and the repulsive forces between protons in the nucleus, as well as the balance of attractive forces between electrons and the positively charged nucleus.

In this case, the combination of 10 protons and 12 neutrons can form two different isotopes of boron: 11B (with 1 neutron) and 11B (with 2 neutrons). Both of these isotopes are stable, although 11B is more abundant.

On the other hand, the combination of 10 protons and 12 neutrons can also form a stable neon isotope, 22Ne, which has 10 electrons in its neutral state.

In terms of stability, both combinations are energetically favorable and stable, and it is not possible to say which is more stable without further information.

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The system is now in equilibrium when both the forward reaction rate and the reverse reaction rate are equal. When the concentration and number of moles of a products and reactants are constant.

Whenever the rates of the forward or reverse reactions are equal, a system is said to be in equilibrium. The pace of the ahead reaction rises with the addition of more reactants. It appears that the equilibrium is shifting towards the product, and right, part of the equation since the rate of a reverse reaction remains unchanged at first.

When there is no trend for the amounts of reactants and byproducts to fluctuate, a chemical process is in equilibrium. They both produce the same mixture all components after the transition is complete, and they both represent the very same chemical reaction process in which the components' functions are reversed.

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Precipitates are insoluble ionic solid products of a reaction, formed when certain cations and anions combine in an aqueous solution. The determining factors of the formation of a precipitate can vary.

The common way is the use of active voice when writing an abstract because passive voice make an indirect writing of the action and indication of a person in the action.

Abstract is the first phase of a thesis or a publication in a journal. It briefly summarizes about what we are going tp communicate through that paper or thesis what are the major methods used and also tell about the major findings and conclusions.

Thus, abstract must be concise but sharp and clear to the point about each step in the experiment of the scientific investigation whatever. It must be following the same tense of action that is in past or present. All sentence should follow the same tense.

Now, it is commonly better to avoid passive voice to write the actions and if possible write it in active voice. Direct indication of the person in charge and the action is good to read.

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Answer:

HBr

Explanation:

Answer:

The answer is in fact HBr

Explanation:

I took the quiz

:)

Answer:

the throwing back by a body or surface of light, heat, or sound without absorbing it.

Explanation:

I think the answer is A. I know it's Planet X.

Answer:

the pool table one

Explanation:

cuz gas just goes EVERYWHERE