The AH of the reaction is given as C. -571.6 kJ/mol
How to solveThe enthalpy change of a reaction (∆H) can be calculated using the formula:
∆H = Σn ∆Hf°(products) - Σn ∆Hf°(reactants),
where n is the stoichiometric coefficient of each substance in the balanced equation.
If we apply this to the reaction of H2(g) and O2(g) forming H2O(l), we get ∆H = -571.6 kJ/mol, where ∆Hf°(H2(g)) = 0 kJ/mol and ∆Hf°(O2(g)) = 0 kJ/mol.
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Given the following reaction equation and the enthalpies of formation (∆Hf°) for each substance, what is the ∆H of the reaction?
2 H2(g) + O2(g) → 2 H2O(l)
∆Hf°(H2(g)) = 0 kJ/mol
∆Hf°(O2(g)) = 0 kJ/mol
∆Hf°(H2O(l)) = -285.8 kJ/mol
A. -5335.8 kJ/mol
B. -2815.8 kJ/mol
C. -571.6 kJ/mol
D. 580.7 kJ/mol
The density of a liquid substance is 0.95 g/mL. Three students calculated the density as 0.56 g/mL. Calculate the percent
error.
Answer:
The answer is 41.05 %Explanation:
The percentage error of a certain measurement can be found by using the formula
\(P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ \)
From the question we have
actual number = 0.95 g/mL
error = 0.95 - 0.56 = 0.39
We have
\(p(\%) = \frac{0.39}{0.95} \times 100 \\ = 41.0526315...\)
We have the final answer as
41.05 %Hope this helps you
to chemicals mixed together to make heat physiacal or chemical change THATS IS ALL IMMA SAY ( DONT ANSWER IF THERES NO EXPLATION )THXSSS HAVE A GOOD DAY
Answer:its a chemixal change because there are stuff getting mixed togehter making it a chemiacl change
Explanation:
One characteristic that is unique to water is that it
A - has a low specific heat.
B - can be changed from a liquid to a solid.
C - Dissolves very few substances.
D - exists naturally in three states on Earth.
Choose ALL that apply for NEAP tides Moon and Sun are at right angles to the Earth gravity of the Sun and Moon work against each other Moon, Sun, and Earth are in alignment smaller than normal range of highs and low tides
Answer:
i think it is..... smaller than normal range of highs and low tides
Moon and Sun are at right angles to the Earth
Explanation:
Moon and Sun are at right angles to the Earth and gravity of the Sun and Moon work against is the right statement about NEAP tides.
What are tides?Tides are the cyclic deformation of water body occur due to external gravitational force.
NEAP tides are also known as small tides as their heights are not very much and this is occur due to opposite attraction of water towards the gravity of the sun and moon. As sun and moon are present in the right angle direction with respect to the earth.
Hence, option (1) & (2) is correct, i.e. gravity of sun and moon is opposite and they are present at the right angle to the earth.
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An object is located 360 millimeters from a converging lens. The image formed is 150 millimeters high, at a distance of 90 millimeters from the lens. What’s the height of the object?
The height of the object : 600 mm
Further explanationGiven
d object=360 mm(object distance)
d image=90 mm(image distance)
Required
h object
Solution
focal length = f :
\(\tt \dfrac{1}{f}=\dfrac{1}{d_o}+\dfrac{1}{d_i}\\\\\dfrac{1}{f}=\dfrac{1}{360}+\dfrac{1}{90}\rightarrow f=72~mm\)
The magnification :
\(\tt M=\dfrac{d_i}{d_o}=\dfrac{90}{360}=0.25\)
\(\tt M=\dfrac{h_i}{h_o}\\\\0.25=\dfrac{150}{h_o}\rightarrow h_o=600~mm\)
One of the reactions used to extract zinc metal from ore is shown below. Find the mass of sulfide that can be converted into zinc oxide using 2.64 L of oxygen gas measured at 21 °Cand 101 kPa.
2 ZnS(s) + 3 02 (g) -> Z ZnO (s) + 2 SO2 (g)
Approximately 6.63 grams of sulfide can be converted into zinc oxide using 2.64 L of oxygen gas measured at 21°C and 101 kPa.
The balanced equation is:2 ZnS(s) + 3 \(O_2\)(g) → 2 ZnO(s) + 2 S\(O_2\)(g)
The stoichiometric coefficient of ZnS is 2, while that of \(O_2\)is 3. So, the number of moles of \(O_2\)required to react with 1 mole of ZnS is given by (3/2) moles (i.e. 1.5 moles).
At STP (i.e. standard temperature and pressure), 1 mole of any gas occupies a volume of 22.4 L.
So, at 21°C and 101 kPa, the volume of 2.64 moles of oxygen gas is given by:
V = (n x R x T)/P= (2.64 x 8.31 x 294)/101= 62.7 L
Approximately 62.7 L of oxygen gas is needed to react completely with the sulfide and convert it into zinc oxide.
Therefore, to find the mass of sulfide that can be converted into zinc oxide using 2.64 L of oxygen gas measured at 21°C and 101 kPa, we first convert 2.64 L to moles of \(O_2\):
PV = nRTn = PV/RTn = (101 kPa)(2.64 L) / (8.31 L kPa/mol K)(294 K)= 0.102 moles of \(O_2\)
Since 3 moles of \(O_2\)re needed to react with 2 moles of ZnS, then the moles of ZnS required would be:
(2/3)(0.102 mol) = 0.068 mol ZnS.
To find the mass of ZnS, we use its molar mass:MM of ZnS = 97.47 g/molmass of ZnS
= (0.068 mol)(97.47 g/mol)mass of ZnS = 6.63 g
Hence, approximately 6.63 grams of sulfide can be converted into zinc oxide using 2.64 L of oxygen gas measured at 21°C and 101 kPa.
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Dear brother, please solve the q
3 - A mixture of 2kmol of CO and 3kmol of O
2
is heated to 2600 K at a pressure of 304 kPa. Given that Kp=16.461, determine the equilibrium composition of CO
2
is :
The equilibrium composition of CO₂ is determined to be 0.59 kmol.
To solve this problem, we can use the ideal gas law and the equilibrium constant expression for the reaction:
CO + 1/2O₂ ⇌ CO₂
Given the initial number of moles of CO and O₂, we can set up an ICE (Initial, Change, Equilibrium) table. Let's assume that x kmol of CO is consumed and converted to CO₂. Then, the change in the number of moles for each species is:
CO: -x kmol
O₂: -0.5x kmol
CO₂: +x kmol
At equilibrium, the number of moles of CO is (2 - x) kmol, O₂ is (3 - 0.5x) kmol, and CO₂ is x kmol. The equilibrium constant expression can be written as:
Kp = (P_CO₂) / (P_CO * P_O₂(1/2))
Given Kp = 16.461 and the pressure conditions, we can substitute the equilibrium partial pressures into the expression:
16.461 = x / ((2 - x) * (3 - 0.5x)(1/2))
Solving this equation yields x ≈ 0.59 kmol.
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Primary amines with three or four carbon atoms are _____ at room temperature whereas higher ones are ______.
Primary amines are a class of organic compounds that contain a nitrogen atom bonded to two hydrogen atoms and a carbon atom. The carbon atom can be bonded to one, two, or three other carbon atoms.
The number of carbon atoms in the primary amine molecule can affect its physical properties, including its boiling and melting points.Primary amines with three or four carbon atoms are generally liquid at room temperature, while higher ones are solids. This is due to the difference in intermolecular forces between the molecules. In general, the larger the molecule, the stronger the intermolecular forces, which result in higher melting and boiling points. This is because the larger the molecule, the more atoms are present, and the greater the potential for intermolecular interactions such as van der Waals forces.Carbon atoms play a key role in determining the physical and chemical properties of organic compounds, including primary amines. The number and arrangement of carbon atoms in a molecule can affect its reactivity, solubility, and stability. The presence of multiple carbon atoms in a primary amine molecule can also result in the formation of different isomers, which have similar chemical properties but different physical properties. Overall, the number of carbon atoms in a primary amine molecule is an important factor in determining its behavior and properties.
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It is given that the probability of requiring ICU care for patients hospitalized for COVID-19 is 5%. What is the probability of observing at least one ICU admissions, among the next six patients hospitalized for COVID-19?| Answer: a. 0.26491 b. 0.73509 c. 0.03125 d. 0.98437 e. 0.23213
The probability of observing at least one ICU admission, among the next six patients hospitalized for COVID-19 is 0.26491. Option A is correct.
The probability of not observing any ICU admission among the next six patients hospitalized for COVID-19:
Probability of not observing ICU admission = 1 - Probability of observing ICU admission
= 1 - 0.05
= 0.95
Probability of no ICU admission among the next six patients hospitalized for COVID-19:
Probability of no ICU admission in one trial = 0.95
Probability of no ICU admission in six trials (patients)
= 0.95 × 0.95 × 0.95 × 0.95 × 0.95 × 0.95
= 0.73509
Now, we can calculate the probability of observing at least one ICU admission among the next six patients hospitalized for COVID-19:
Probability of at least one ICU admission= 1 - Probability of no ICU admission
= 1 - 0.73509
= 0.26491
Therefore, the answer is A.
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PLEASE HURRY!!!!!!! Which statements correctly describe the movement of water into and out of the ground?
Choose two correct answers.
Gravity helps move water into the ground.
Mountains help move water out of the ground.
Rocks on Earth’s surface help move water into the ground.
The Sun helps move water into the ground.
The roots of trees help move water out of the ground.
Answer:
Gravity helps move water into the ground.
Use the nuclear decay reaction to answer the following questions. Does undergo transmutation? Explain your answer.
Let's consider the following nuclear decay reaction: Uranium-238 → Thorium-234 + Helium-4
In this reaction, Uranium-238 undergoes alpha decay, where it loses an alpha particle (consisting of two protons and two neutrons) to form Thorium-234 and Helium-4.
This means that Uranium-238 has undergone transmutation, as it has transformed into a different element (Thorium-234) through the process of alpha decay.
Transmutation refers to the conversion of one element into another through nuclear reactions.
Thus, in this case, the uranium nucleus has transformed into a thorium nucleus, which is a different element with a different number of protons. Therefore, the decay reaction involves transmutation.
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Your question seems incomplete, the probable complete question is:
Use the nuclear decay reaction
\(^1_0n+^{235}_{92}U--- > ^{141}_{56}Ba+^{92}_{36}Kr+3^1_0n\)
to answer the following questions. Does undergo transmutation? Explain your answer.
Use the mass and volume data to calculate the density of an unknown metal to the nearest hundredth.
Mass of unknown metal = 222.50 g
Volume of unknown metal = 25.00
What is the density of the unknown metal?
0.11
0.89
8.90
5,562.50
Answer:
8.90
Explanation:
Density = mass ÷ volume
D = 222.50 g ÷ 25.00
= 8.9
The density of the unknown metal is 8.90.
Hope that helps.
Answer:
C: 8.90
Explanation:
QUICK PLEASE IM TIMED
A summary table may contain __________ categories than the original data table.
A) many more
B) a few more
C) fewer
D) none of the above
How many particles are in one mole of copper (II) sulfate, CuSO4?
Which of these describes a physical change? Choose the correct answer. You may only choose one.
A. Wood logs are burned in a fire.
B. Coconut oil begins to crystallize after being placed in a freezer.
C. Milk left out of the refrigerator for a week starts to smell different.
D. Sodium hydroxide and hydrochloride acid are mixed in water to form a salt.
Answer:
A. Wood logs are burned in a fire
Explanation:
To solve this, we must know each and every concept behind physical change and Chemical change. Therefore, thee correct option is option A that is wood logs are burned in a fire.
What is physical change?A physical change is characterized by a differences in physical attributes. Melting, transformation to a gas, changes in strength, change in durability, changes in crystal structure, texturing change, shape, color, volume, and density are all examples of physical qualities. Tempering steel to make a knife blade is an instance of a physical change.
Chemical change is a reaction in which breaking and forming of new bonds take place. One molecule completely converted to totally different molecule. The number of atoms remains same
Therefore, thee correct option is option A that is wood logs are burned in a fire.
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What is the final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l?
The final temperature of the gas that expands from a volume of 22.4 l at 278k to a volume of 38.3 l will be 475 K.
The volume as well as Kelvin temperature will be directly proportional whenever the pressure on even a sample of such a dry gas remains held constant. PV = k would be the law's equation.
Charle's law give the relation between the temperature and volume is shown as:
\(V_{1} / T_{1} = V_{2} / T_{2}\)
where. V is volume and T is temperature.
Given data :
\(V_{1} =22.4 l\\V_{2} = 38.3 l\\T_{1} = 278 K\\T_{2} = ?\)
Put the value of given data in above equation.
22.4 l / 38.3 l = 278k / \(T_{2}\)
\(T_{2}\) = 475 K.
Therefore, the final temperature will be 475 K.
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8. What causes the shielding effect to remain constant across a period? O The atomic radius increases.O Electrons are added to the same principal energy level. OElectrons are added to different principal energy levels. O The charge on the nucleus is constant.
The charge on the nucleus is constant.
Explanation:-The number of inner shell electrons being constant causes the shielding effect to remain constant across a period
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Thank you:)how do scientists describe the behavior of particles in solids and plasmas?
Answer:
The properties of a solid are that they form at a low temperature, particles have long range order meaning that the particles are fixed in place, the particles have a defined shape and volume, the solid particles are a low-energy state of matter, and solid particles are dense and incompressible. But on the other hand plasma particles form at high temperatures, plasma particles have short range order meaning that the plasma particles have little interaction, plasma particles fill all available space meaning plasma particles have no fixed shape or volume, plasma particles are the highest energy-state of matter, plasma particles are highly compressible, and plasma particles conduct electricity extremely well.
Explanation:
Plasma particles also form at high temperatures, have short-range order, fill all available space, and are the highest energy state of matter.
What is the matter?The matter is anything that occupies space. There are three states of matter. Solid, liquid, and gases. The fourth state of matter is plasma.
A solid has the following characteristics:
It forms at low temperatures. Its particles have long-range order. Solids have a specific shape and volume.They are a low-energy state of matterThey are dense and incompressible.However, plasma particles are the highest energy state of matter, they are highly compressible, they have short-range order, which means that they have little interaction, and they have excellent electrical conductivity.
Plasma particles also form at high temperatures:
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what is the molecular formula of benzoyl peroxide (c7h5o2) of the molecular mass is 0.242 kg/mol?(show work please)
Answer : The molecular formula of benzoyl peroxide is \(C_{14}H_{10}O_4\)
Explanation :
Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.
Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :
\(n=\frac{\text{Molecular mass}}{\text{Empirical mass}}\)
As we are given that the molar mass of compound is, 0.242 kg/mol.
Molecular mass = 0.242 kg/mol = 242 g/mol (1 kg = 1000 g)
The empirical mass of \(C_7H_5O_2\) = 7(12) + 5(1) + 2(16) = 121 g/eq
\(n=\frac{\text{Molecular mass}}{\text{Empirical mass}}\)
\(n=\frac{242}{121}\)
\(n=2\)
Molecular formula = \((C_7H_5O_2)_n\) = \((C_7H_5O_2)_2\) = \(C_{14}H_{10}O_4\)
Thus, the molecular formula of benzoyl peroxide is \(C_{14}H_{10}O_4\)
Describe 2 physical properties of the following items
What is physical properties?
It is a characteristic of matter which is not associated with a change in its chemical composition
2 physical properties of:
Paper clip - They usually have an oblong shape with straight sides, they may also be triangular or circular, or have more elaborate shapes. The most common material is steel but molded plastic is also used.Vinegar - It is a colorless liquid with a corrosive pungent odor with a sour taste.Its density is 1.05 g/ml and molecular mass is 60.052 g/mol.Carbon Dioxide gas - It is a colourless , odourless gas and non-flammable gas.It has a melting point of -55.6°C and has boiling point of -78.5°C. It has density of 1.977g/ml.Learn more about properties of Carbon Dioxide gas at https://brainly.com/question/1183060
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A little help here please
Answer:
Prokaryotic Cells:
- Bacteria
- Unicellular Organisms
- DNA as genetic material
- Ribosomes
- Do not have membrane bound organelles
- Always contain cell wall
Eukaryotic Cells:
- Contains organelles
- Have membrane bound organelles
- Unicellular Organism
- DNA as genetic material
- Ribosomes
- Have loose strand of DNA
- Has nucleus
- Multicellular Organism
- Plant cell
- Animal cell
Explanation:
I have separated them and made the common characteristics in bold. I cannot guarantee that it is correct, these are my educated estimates.
Use the balanced equation to solve the problem.N2 + 3H22NH323.0g NH3 are made.How many liters of H₂ gas reacted at Stp? L
By using the ideal gas law to get volume we have"
\(V=\frac{nRT}{P}\)Where v is volume, T is temperatute, n is number of moles, R is the molar gas constant and P is pressure. At STP P= 101,325 Pa, T= 273.15 K and R= 8.314 J/mol K
\(\begin{gathered} \frac{RT}{P}=0.022414cm^3mol^{-1} \\ \\ V=0.0022414n \end{gathered}\)We must first convert mass to moles:
\(\begin{gathered} mole=\frac{mass}{molecular\text{ }mass} \\ mole=\frac{23.0g}{17.0g\text{ }mol^{-1}} \\ \\ mole=1.35 \end{gathered}\)\(To\text{ }determine\text{ }the\text{ }moles\text{ }of\text{ }H2\text{ }gas\text{ }reacted\text{ }we:\frac{2}{3}\times1.35=0.87\text{ }mol\)By substituting this value into the ideal gas law we have:
\(\begin{gathered} V=0.0022414cm^3mol^{-1}\times0.87mol \\ V=0.0019502cm^3 \\ \\ V=1.9502\times10^{-6}L \end{gathered}\)1.9502e-6L of H2 gas reacted at STP
Nitrogen reacts with hydrogen to produce ammonia. The chemical equation for this reaction, located below, indicates all of the following information except...
N2(g) + 3 H2(g) ---> 2 NH3(g)
Select one:
a. All substances are in the same physical state.
b. One molecule of ammonia is composed of two atoms of nitrogen and three atoms of hydrogen.
c. Two molecules of ammonia are produced.
d. Three molecules of hydrogen react with one molecule of nitrogen.
Answer:
b. One molecule of ammonia is composed of two atoms of nitrogen and three atoms of hydrogen.
Explanation:
N2(g) + 3 H2(g) ---> 2 NH3(g)
reason its b.
1 molecule of ammonia would be NH3 , there is 1 atom of nitrogen and 3 atoms of hydrogen. There is not 2 atoms of nitrogen in one molecule of ammonia therefore the reaction does not indicate B.
Reasons its not a, c or d
A. The g means "gas". Each compound and element in this reaction has a g therefore they are all gases. Because all substances in the reaction are gases (or in the same physical state) the reaction indicates answer choice A.
C. That two molecules of ammonia are produced, the product of the reaction is 2NH3. NH3 is ammonia and there is a coefficient of 2 before the NH3 so 2 molecules of ammonia is produced during the reaction.
D. 1 molecule of nitrogen ( N2 ) reacts with 3 molecules of hydrogen ( 3H2 ). This is true looking at the reaction. N2(g) + 3 H2(g)
the quantity of groundwater that can be stored within sedimentary material is most directly controlled by which of the following parameters? view available hint(s)for part a the quantity of groundwater that can be stored within sedimentary material is most directly controlled by which of the following parameters? the porosity of the material the composition of the sediment the capillary fringe the permeability of the material the location of the water table
The quantity of groundwater that can be stored within sedimentary material is most directly controlled by the porosity of the material. The porosity of the material is the parameter that most directly controls the quantity of groundwater that can be stored within sedimentary material.
Porosity refers to the amount of empty space or voids within the sediment, which can hold and store water. Sedimentary rocks, such as sandstones and conglomerates, generally have higher porosity compared to other rock types like igneous or metamorphic rocks.
Porosity is influenced by various factors. Grain size plays a significant role, as sediments with larger grains have higher porosity due to the larger spaces between particles. Sorting, which refers to the uniformity of grain sizes, also affects porosity. Well-sorted sediments have higher porosity than poorly sorted ones. Compaction of sediments due to pressure over time reduces porosity, while cementation of particles can further decrease porosity by filling in pore spaces.
Higher porosity means there is more space available to store groundwater within the sedimentary material. This stored groundwater can be accessed through wells or extracted from aquifers. It is important to note that the movement and availability of groundwater are also influenced by permeability, which refers to the ability of the material to transmit water. While porosity determines the potential storage capacity, permeability controls the flow and accessibility of groundwater within the sediment.
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1. What is the correct order of the water cycle?
A cloud, water vapor, rain,
B rain, cloud, water vapor
C water vapor, cloud, rain
D water vapor, rain, cloud
A 25.0 mL sample of Ba (OH)2 solution was neutralized by 45.3 mL of 0.150 N HCl. What is the Normality of the Ba (OH)2
The required normality of Ba(OH)2 is 0.1012 N.
A 25.0 mL sample of Ba (OH)2 solution was neutralized by 45.3 mL of 0.150 N HCl. What is the Normality of the Ba (OH)2?The balanced equation for the reaction between Ba(OH)2 and HCl is:Ba(OH)2 + 2HCl → BaCl2 + 2H2OAccording to the reaction equation, we can see that one mole of Ba(OH)2 reacts with two moles of HCl.
The molarity of the HCl is given as 0.150 N, where N is the normality. It can be calculated as shown below:N = M × nwhere M is the molarity of the solution, and n is the number of equivalents.N = 0.150 × 2 = 0.300 NFrom the reaction equation, we know that 2 moles of HCl are required to neutralize 1 mole of Ba(OH)2.25 mL of Ba(OH)2 is neutralized by 45.3 mL of 0.150 N HCl. The amount of Ba(OH)2 can be calculated as follows:Volume of Ba(OH)2 = (45.3 mL / 2) × (25 mL / volume of Ba(OH)2)
volume of Ba(OH)2 = 16.87 mLThe number of moles of Ba(OH)2 in the solution is calculated as follows:n = M × V where M is the molarity and V is the volume.n = M × V = (0.150 N) × (16.87 / 1000 L) = 0.00253 molThe normality of Ba(OH)2 can be calculated using the formula below:N = n / Vwhere n is the number of equivalents and V is the volume.N = n / V = 0.00253 / (25.0 / 1000) = 0.1012 N
Therefore, the normality of Ba(OH)2 is 0.1012 N.
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draw the structure of the compound whose data is shown below, then select all functional groups in the correct structure. compound 3 c10h14
Compound 3 with the molecular formula C10H14 can have various structural isomers. Without further specific information, it is challenging to determine the exact structure of the compound.
However, I can provide a general idea of a possible structure and list some common functional groups that may be present.
One possible structure for C10H14 is cyclohexane, which consists of a ring of six carbon atoms with hydrogen atoms attached to each carbon. However, please note that this is just one example, and there are other possible structures based on the given molecular formula.
Some common functional groups that can be present in organic compounds include alcohols (-OH), alkenes (-C=C-), alkynes (-C≡C-), aldehydes (-CHO), ketones (-C=O-), carboxylic acids (-COOH), esters (-COO-), amines (-NH2), and ethers (-O-).
The presence of specific functional groups in Compound 3 would depend on the actual structure of the compound.
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When a 0.3546 g of vanadium metal is heated in air, it reacts with oxygen to achieve a
final mass of 0.6330 g. Calculate the empirical formula of this vanadium oxide
Answer:
V2O5 is the empirical formula of vanadium oxide
Explanation:
The molecular mass of Vanadium is 50.949 g/mol
Number of moles of vanadium = 0.3456 g/50.949 g/mol = 0.00696 moles
The molecular mass of Oxygen is 16.0 g/mol
Number of moles of Oxygen = (0.6330 – 0.354) g/16 g/mol = 0.0174 moles
Emperical formula
V (0.00696 moles/0.00696 moles) O (0.0174 moles /0.00696 moles)
V 1 O2.5
Multiply by two get a whole number
V2 O5
Please help with these two (last question is nwse)
Answer:
your answer gonna be 20 miles
How many formula units are contained in 1.67 g CaO
There are approximately 1.79 x 10²² formula units of CaO in 1.67 g of CaO.
What is Avogadro's constant?Avogadro's constant, also known as Avogadro's number (N_A), is a fundamental physical constant that represents the number of constituent particles (usually atoms or molecules) in one mole of a substance.
The value of Avogadro's constant is approximately 6.022 x 10²³ particles per mole. This means that one mole of any substance contains 6.022 x 10²³ particles. For example, one mole of oxygen gas (O2) contains 6.022 x 10²³ oxygen molecules, and one mole of sodium chloride (NaCl) contains 6.022 x 10²³ sodium ions and 6.022 x 10²³ chloride ions.
To determine the number of formula units of CaO in 1.67 g of CaO, we need to use the molar mass of CaO and Avogadro's number.
The molar mass of CaO is:
CaO = 40.08 g/mol (Ca) + 16.00 g/mol (O) = 56.08 g/mol
Using the molar mass, we can calculate the number of moles of CaO:
n = m/M = 1.67 g / 56.08 g/mol = 0.0298 mol
Finally, we can use Avogadro's number, which is 6.022 x 10²³ formula units/mol, to calculate the number of formula units of CaO:
number of formula units = n x N_A = 0.0298 mol x 6.022 x 10²³ formula units/mol = 1.79 x 10²² formula units.
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