The time that is taken for the radio signal to travel is 5 * 10^-7 s.
What is the period of the a wave?The period of a wave is the time it takes for one complete cycle of the wave to pass a given point. In other words, it is the time it takes for the wave to repeat itself. The period is usually denoted by the symbol T and is measured in units of time, such as seconds (s).
We know that the period of the wave is the inverse of the frequency of the wave. We are asked here to find the time taken for the the radio signal to travel from Earth to the spaceship.
Thus we have;
T = f-1
T = 1/2.00 × 10^6
T = 5 * 10^-7 s
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Find the potential energy of a 0.75 kg hammer when its raised 0.35 meters.
Answer:
the potential energy = 2.625
Explanation:
potential energy = mass× acceleration due to gravity × height
mass = 0.75kg
acceleration due to gravity =10m/s²
height =0.35 meters
potential energy = 0.75kg× 10m/s² × 0.35m =2.625 N
A cheetah can accelerate from rest to a speed of 30. 0 m/s in 7. 00 s. What is its acceleration?.
The cheetah that can accelerate from rest to a speed of 30.0 m/s in 7.00s has an acceleration of: 4.285 m/s²
The formula and procedure we will use to solve this exercise is:
a = (vf - vi) /t
Where:
a = accelerationvf = final velocityvi = initial velocityt = timeInformation about the problem:
vi= 0 m/svf = 30.0 m/st = 7.00 sa=?Applying the acceleration formula we have:
a = (vf - vi) /t
a = (30.0 m/s - 0 m/s) /7.00 s
a = (30.0 m/s m/s) /7.00 s
a = 4.285 m/s²
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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Where are the young stars in spiral galaxies? In the disk. In the bulge. In the halo. Question 24 Where are the young stars in elliptical galaxies? In the bulge. In the disk. There are none. Question 25 Where are stars formed in our galaxy? In the halo. In the disk In the bulge
23. Young stars in spiral galaxies are typically found in the disk.
24. in the elliptical galaxies a few new stars might show up in the bulge
25. Stars are formed in the disk of our galaxy.
What should you know about the Elliptical galaxies?Elliptical galaxies are generally composed of older stars, with little to no ongoing star formation. This is due to the fact that they have used up or lost most of their interstellar medium. So, there are typically no young stars in elliptical galaxies.
Our galaxy, the Milky Way, is a barred spiral galaxy.
Stars are primarily formed in the disk of our galaxy, particularly in the spiral arms where the interstellar medium is densest.
This is where new stars, including young blue stars and star clusters, are most frequently born. The bulge and halo regions of the Milky Way are primarily composed of older stars, with very little ongoing star formation.
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A bus starts from rest.if the acceleration is 2m/s square, find
i.the distance travelled
ii.the velocity after 2 seconds.
Answer:
The velocity after 2 seconds can be found through:
V = u +a*t
Where V is final velocity, u is initial velocity, a is acceleration and t is time.
V = 0 + 2* 2= 4 meters/second
The distance (s) can be found through:
V^2= u^2 +2*a* s
Where V is final velocity, u is initial velocity, a is acceleration.
4^2= 0^2 + 2 *2*s
16= 0 + 4s
s= 4 meters
Distance (s) can also be found through:
s= ut + 1/2 at^2
s= 0+ 1/2 *2*2^2= 1 *2*2
s= 4 meters
Explanation:
A man running at 5 M/S increases his velocity to 10 M/S in 2 Seconds. What was his acceleration?
Cellular respiration takes place in the mitochondria of cells.
Answer:
True
Because mitochondria is the powerhouse of the cell.
Explanation:
Hope this helps you
Answer:
True
Explanation:
What is the ozone * 10 points layer and why it is important? What are the effects of depletion of ozone layer? ( 500 words approx.)
The ozone layer is a region of the Earth's stratosphere that contains a high concentration of ozone (O3) molecules.
It plays a crucial role in protecting life on Earth by absorbing the majority of the Sun's harmful ultraviolet (UV) radiation. The depletion of the ozone layer, primarily caused by human activities, leads to an increase in UV radiation reaching the Earth's surface. This has significant adverse effects on human health, ecosystems, and the environment.
The ozone layer is located in the Earth's stratosphere, approximately 10 to 50 kilometers above the surface. It is formed by the interaction of UV radiation from the Sun with oxygen molecules (O2). The UV radiation breaks apart the oxygen molecules, and the resulting oxygen atoms (O) combine with other oxygen molecules to form ozone (O3).
The ozone layer is essential because it acts as a shield, absorbing the majority of the Sun's UV-B and UV-C radiation, preventing it from reaching the Earth's surface. UV radiation is harmful to living organisms, as it can cause DNA damage, skin cancer, cataracts, and weakened immune systems. The ozone layer's ability to filter out these harmful rays helps protect human health and supports the functioning of ecosystems.
However, human activities have significantly contributed to the depletion of the ozone layer, primarily through the release of certain chemicals known as ozone-depleting substances (ODS), such as chlorofluorocarbons (CFCs) and halons. These substances were commonly used in aerosols, refrigeration, air conditioning, and fire suppression systems. Once released into the atmosphere, ODS molecules can reach the stratosphere and undergo reactions that break down ozone molecules.
The depletion of the ozone layer has several detrimental effects. Increased UV radiation reaching the Earth's surface can lead to an increase in skin cancer cases, cataracts, and other health issues in humans. UV radiation also harms phytoplankton, which are vital for marine ecosystems and the global carbon cycle. Additionally, UV radiation can negatively impact terrestrial and aquatic ecosystems, causing DNA damage, reduced plant growth, disruption of food chains, and harm to coral reefs and other sensitive marine organisms.
Recognizing the importance of protecting the ozone layer, the international community developed the Montreal Protocol in 1987, which aims to phase out the production and use of ODS. Through global efforts to reduce ODS emissions, there has been a gradual recovery of the ozone layer in recent years.
In short , the ozone layer acts as a natural shield, protecting life on Earth from harmful UV radiation. The depletion of the ozone layer due to human activities has severe consequences for human health, ecosystems, and the environment. It is crucial to continue efforts to reduce ozone-depleting substances and preserve the integrity of the ozone layer for the well-being of present and future generations.
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which answer is it??
Answer:
hmm...
Explanation:
Answer: wave a has the higher ampllitude while wave b has the lower amplitude.
Explanation:
wave a has the amplitude of 4 while wave b has the amplitude of one
. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2
The length of the rubber band that the boy must use is 0.024 m or 24 mm.
What will be the length of the rubber required?To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:
U = 1/2 kx²where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.
Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.
We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):
v = √(2mk/M)where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:
k = (v² M) / (2 m)
We can now combine the two equations to solve for the length of the rubber band, L:
U = 1/2 k x²
U = 1/2 ((v² M) / (2 m)) (0.25 L)²
U = (v² M L²) / (32 m)
The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:
U = 1/2 M v²
(v² M L²) / (32 m) = 1/2 M v²
L = ((16 m v²) / (k M))
L = ((16 m v²) / ((v² M) / (2 m) M))
L = √(32 m^2 / M)
L = (0.032 M)
Substituting the given values, we get:
L = √(0.032 * 0.006)
L = 0.024 m
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c. Describe how a manometer could be used to find the pressure of the laboratory gas supply.
Answer:
A manometer is a device similar to a barometer that can be used to measure the pressure of a gas in a vessel. An enclosed pressure gauge is a U-shaped tube with one arm closed, another arm that connects to the electricity to be measured, and a permanent liquid (usually mercury) in between.
hope it helps you<3Potential Energy (kJ)
Reaction Progress →
A) Does this graph represent an endothermic or exothermic reaction? Explain your answer. (2 points) HELP PLEASE ITS URGENT !!
Answer:
Endothermic reaction
Explanation:
(a) Endothermic reaction: These are reactions that absorb heat from the surrounding during a chemical reaction. The enthalpy change for endothermic reaction is always positive, and the energy level of the product is higher than that of the reactant
(b) Exothermic reaction: These are reactions that release heat to the surrounding during chemical reaction. The enthalpy change for exothermic reaction is always positive, and the energy level of the product is lower than that of the reactant.
From the diagram in the question,
Since the energy level of the product is higher than that of the reactant then the reaction is an endothermic reaction and as such, ΔH is positive
12. Describe Binding energy and how it plays a role in nuclear fusion up to 56Fe (the synthesis of iron
nuclei). Include a description of the relationship between the strong nuclear force, the
electromagnetic force, and the number of nucleons involved in the fusion in your answer.
Help me on thiss one once again ughh ! asap ! hurry
003 (part 1 of 2) 10.0 points
on Planet X, an object weights 18 N. On planet B where the magnitude of the free-fall acceleration is 1.87g (where g=9.8m/s^2 is the gravitational acceleration on Earth), the object weighs 36.9 N
The acceleration of gravity is 9.8m/s^2.
What is the mass of the object be on Earth?
Answer in units of kg.
004 (part 2 of 2) 10.0 points what is the free-fall acceleration on Planet X? Answer in units of m/s2
A measurement of a change
in distance over time
Explanation:
Speed is the rate of change of distance with time.What is called gravitational potential energy?
Answer:
Potential gravitational energy is the energy that the body has due to the Earth's gravitational attraction. In this way, the potential gravitational energy depends on the position of the body in relation to a reference level.
Explanation:
Which statement below is Gauss's Law for electric fields? Please note, we are not asking which statement is true, we are asking which statement is Gauss's Law. As an example, 2+2-4 is true but it is not a statement of Gauss's Law. O The electric flux through a surface is equal to the integral of the normal component of the electric field over the surface O 2+2-4 The electric flux through a closed surface is equal to the net charge inside the surface divided by the physical constant The electric flux is equal to the amount of charge flowing through a surface in a given time.
“The electric flux through a closed surface is equal to the net charge inside the surface divided by the physical constant. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.
Gauss’s Law for electric fields is a fundamental principle in physics, specifically in the study of electrostatics. The law describes the relationship between the electric flux and the distribution of electric charges in a given space. Simply put, it states that the electric flux through a closed surface is proportional to the total amount of electric charges inside the surface. In mathematical terms, the statement of Gauss’s Law for electric fields is as follows: E.ds = Q/ε0Here, E.ds represents the electric flux through a closed surface, Q represents the total electric charge enclosed within the surface, and ε0 is the physical constant known as the permittivity of free space. This equation can be used to calculate the electric field created by a given charge distribution, provided that the electric flux through a closed surface around the distribution is known.
Gauss’s Law for electric fields states that the electric flux through a closed surface is proportional to the net electric charge enclosed within the surface. This law is a fundamental principle in electrostatics and is expressed mathematically as E.ds = Q/ε0.
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pressure exerted by a liquid ______ with an increase in depth (increases/decreases)
Answer:
increases
Explanation:
as we know, that submarines need to be really really strong to go down in the ocean. That means that the more they go down in the water (liquid) then, they will face more pressure. That as we said, that the more down they go, the more pressure will be on them, which means that the pressure will keep on increasing as you go down and down in the ocean.
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many bird wings are more convex on the upper surface than they are on the lower surface. this enables the wing to provide greater lift because a. air moves more slowly over the top surface of the wing than over the lower surface. b. air moves more quickly over the top surface of the wing than over the lower surface. c. the pressure above the wing is greater than below the wing. d. the pressure above the wing is less than below the wing.
Many bird wings are more convex on the upper surface than they are on the lower surface, this enables the wing to provide greater lift because A. air moves more slowly over the top surface of the wing than over the lower surface.
This difference in air pressure leads to the creation of an upward force called lift that counteracts the force of gravity on a bird's wings to keep it aloft.The upper surface of the bird's wings has a more curved shape and a higher angle of attack than the lower surface. Due to this shape, the air moves faster over the wing's surface, which results in a lower pressure zone above the wing.
Meanwhile, the air below the wings moves slower and thus, there's a higher pressure zone below the wing. The difference in pressure creates a lifting force that helps the bird to fly. In summary, the more convex shape of the upper surface of a bird's wing creates a lower air pressure zone above it and a higher air pressure zone below it, thus providing greater lift that enables the bird to fly and glide. So the correct answer is A. air moves more slowly over the top surface of the wing than over the lower surface.
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choose the appropriate wavelengths of light in nanometers. note that answers may be used multiple times or not at all. what wavelength of light is too long to be visible to the human eye? what wavelength of light is absorbed by the atmosphere and doesn't reach the earth's surface? what is the shortest wavelength of uvc light?
Red has a wavelength of about 700 nanometers, while violet has a wavelength of about 380 nanometers.
Why is UVC light important?Ultra - violet (UVC) light, also referred to as germicidal UV light, is a type of electromagnetic spectrum that is broken up into groups based on wavelength. Radio signals, microwave, thermal daylight, white spectrum, X-rays, & gamma rays are some other well-known subcategories.
What distinguishes UVC light from UV light?The UVB & UVC rays have the lowest wavelengths, while UVA rays have the greatest ones. The ozone on Earth filters all UVC as well as some UVB photons while transmitting Uva and Uvb through the atmosphere.
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1. Convert the following to Scientific notation
A) 0.005
An atom of 108In has a mass of 107.909678 amu. Calculate the mass defect (deficit) in amu/atom. Use the masses:
mass of 1H atom = 1.007825 amu
mass of a neutron = 1.008665 amu
1 amu = 931.5 MeV/c2
Give your answer to 4 significant figures and DO NOT use E notation.
The mass defect (deficit) of an atom is defined as the difference between the actual mass of the atom and the sum of the masses of its individual protons and neutrons.
To calculate the mass defect in amu/atom for the given atom of 108In, we need to first determine the number of protons and neutrons in its nucleus. The atomic number of indium (In) is 49, which means that an atom of 108In has 49 protons. To determine the number of neutrons, we subtract the atomic number from the mass number:
Number of neutrons = Mass number - Atomic number
= 108 - 49
= 59
The mass of 59 neutrons is:
mass of 59 neutrons = 59 x 1.008665 amu = 59.476935 amu
The mass of 49 protons is:
mass of 49 protons = 49 x 1.007825 amu = 49.397725 amu
The total mass of the 108In nucleus is:
total mass = mass of protons + mass of neutrons
= 49.397725 amu + 59.476935 amu
= 108.87466 amu
The actual mass of the atom is given as 107.909678 amu, so the mass defect is:
mass defect = actual mass - total mass
= 107.909678 amu - 108.87466 amu
= -0.964982 amu
The negative sign indicates that the mass of the nucleus is less than the sum of the masses of its individual protons and neutrons. Finally, to convert the mass defect to energy, we can use the mass-energy equivalence formula:
1 amu = 931.5 MeV/c^2
Therefore, the mass defect in energy units is:
mass defect = 0.964982 amu x 931.5 MeV/c^2
= 898.82416 MeV\(/c^2\)
Note that the mass defect is negative and the corresponding energy is positive, indicating that energy is released when the nucleus is formed.
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Problem 2: A rock is dropped from a cliff. If it falls for 10 seconds, what is its displacement?
Answer:
100 feet
Explanation:
if both the graph representing the constant net force and the graph representing the variable net force represent the same impulse acting on the baseball, which geometric properties must the two graphs have in common?
The impulse acting on an object is equal to the change in momentum it experiences. When we talk about net force, we're really talking about the rate at which momentum is changing. A constant net force means that momentum is changing at a constant rate, while a variable net force means that momentum is changing at a changing rate.
Now, if both graphs represent the same impulse acting on the baseball, it means that they both represent the same change in momentum. This tells us that the area under both graphs must be the same. This is because the area under a force-time graph represents the impulse experienced by an object.
So, in terms of geometric properties, the two graphs must have the same area under them if they represent the same impulse acting on the baseball. This holds true whether the net force is constant or variable.
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The Juan de Fuca plate is a tectonic plate to the northwest of California that is actively sinking below the North American plate. If the Juan de Fuca plate is moving east at roughly 26 mm every year and is roughly 450 km across, about how long will it take to completely sink below the North American plate assuming the plate continues to move with the same speed and direction?
So, if the Juan de Fuca plate keeps moving at its current rate and direction, it would take around 17,307,692.3 years for it to entirely bury beneath the North American plate.
The Juan de Fuca plate is a particular kind of plate border. how did you find out?The Juan de Fuca plate is subducting beneath the North American plate at the Cascadia trench at a pace of approximately 9.8 to 13.8 feet per 100 years as a result of this plate's movement northeastward in relation to North America along a convergent plate boundary.
To begin, we can apply the formula: distance = rate x time
To begin, multiply 450 km by 1,000,000 mm/km to convert the breadth of the Juan de Fuca plate from kilometres to millimetres:
450 km x 1,000,000 mm/km = 450,000,000 mm
The Juan de Fuca plate is therefore 450,000,000 mm wide.
The values we have can then be entered into the algorithm to solve for time: distance = rate x time
450,000,000 mm = 26 mm/year x time
time = 450,000,000 mm / 26 mm/year
time ≈ 17,307,692.3 years
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find the volume of a rectangular prism that is 8m long, 4m wide, and 300cm high
\(\\ \bull\tt\longmapsto Volume=LBH\)
\(\\ \bull\tt\longmapsto Volume=8(4)(3)\)
\(\\ \bull\tt\longmapsto Volume=96m^3\)
Answer:
Formular:
\({ \boxed{ \bf{v = length \times width \times height}}}\)
» length, l = 8m
» width, w = 4m
» height, h = 300cm = 3 m
\({ \tt{• Therefore :→}} \: { \sf{ volume = (8 \times 4 \times 3)}} \\ → { \sf{ \underline{ \: \: volume = 96 \: {m}^{3} \: \: }}}\)
an proton accelerates through an electric potential difference of 50 v. how much energy does the proton gain in joules
Answer:
E(nergy) = V * Q where V(oltage) = work/charge
E = 50 J/C * 1.6E-19 C = 8.0E-18 Joules
The proton gains approximately 8.01 x \(10^-18\) joules of energy as it accelerates through the 50-volt electric potential difference.
To calculate the energy gained by a proton as it accelerates through an electric potential difference, we can use the formula:
Energy (in joules) = Charge of the particle (in coulombs) × Electric potential difference (in volts)
The charge of a proton is approximately 1.602 x \(10^-19\) coulombs.
Given that the electric potential difference is 50 volts, we can now calculate the energy gained by the proton:
Energy = (1.602 x \(10^-19\) C) × (50 V)
Energy ≈ 8.01 x \(10^-18\) joules
Hence, the proton gains approximately 8.01 x \(10^-18\) joules of energy as it accelerates through the 50-volt electric potential difference.
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When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge?.
Answer:
B
Explanation:
A cylindrical rod of steel (E = 87 GPa) having a yield strength
of 310 MPa (45,000 psi) is to be subjected to a load of 650 N. If
the length of the rod is 880 mm, what must be the diameter to allow
an
To determine the diameter of the cylindrical rod that can withstand a load of 650 N, we need to consider the yield strength of the material and the applied load. the diameter of the rod is approximately 11.62 mm.
By using the formula for stress (force divided by area) and rearranging it to solve for the diameter, we can find the required diameter of the rod.
The stress experienced by the rod can be calculated using the formula:
Stress = Force / Area
Given that the yield strength of the steel is 310 MPa, we can set up the equation:
310 MPa = 650 N / (π * (diameter/2)^2)
We can rearrange the equation to solve for the diameter:
diameter = √(650 N / (310 MPa * π)) * 2
Substituting the given values, we find:
diameter ≈ √(650 / (310 * 10^6 * π)) * 2 ≈ 11.62 mm
Therefore, the required diameter of the rod to withstand the load is approximately 11.62 mm.
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The displacement from equilibrium of an oscillating weight suspended by a spring and subject to the damping effect of friction is given by y(t) = 2e−t cos 4t, where y is the displacement (in centimeters) and t is the time (in seconds). Find the displacement when t = 0, t = 1 4 , and t = 1 2 . (Round your answers to two decimal places.)
Note that the correct times are t = 0, t = 1/4, t = 1/2. You can tell from the spaces between the two digits. i.e 1&4 and 1&2
Answer:
y(0) = 2.00 cm
y(1/4) = 1.56 cm
y(1/2) = 1.21 cm
Explanation:
This is a very simple exercise, the displacement of the oscillating weight from equilibrium has already been modeled by the equation:
\(y(t) = 2e^{-t} cos 4t\)
Where y = displacement ( in cm)
and t = time (in seconds)
The task is to find the displacement when t = 0, 1/4 and 1/2
When t = 0 s
\(y(0) = 2e^{0} cos 4(0)\\y(0) = 2* 1*1\\y(0) = 2.00 cm\)
When t = 1/4 s
\(y(1/4) = 2e^{-1/4} cos 4(1/4)\\y(14) = 2e^{-1/4} cos (1)\\y(1/4) = 1.56 cm\)
When t = 1/2
\(y(1/2) = 2e^{-1/2} cos 4(1/2)\\y(14) = 2e^{-1/2} cos (2)\\y(1/2) = 1.21 cm\)
A child on a skateboard is moving at a speed of 2 m/s. After a force acts on the child, her speed is 3 m/s. What can you say about the work done by the external force on the child
The work done by the external force on the child is positive.
Why is the work done by the external force considered positive?When a force is applied to an object, work is done on that object. Work is defined as the product of the force applied on an object and the distance over which the force acts. In this case, the external force acted on the child on a skateboard, causing her speed to increase from 2 m/s to 3 m/s.
To calculate the work done, we can use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
Since the child's speed increased, we know that the force and displacement acted in the same direction. Therefore, the angle between the force and displacement vectors, denoted by theta (θ), is 0 degrees, and the cosine of 0 degrees is 1.
Considering the child's speed increased, we can conclude that the force applied in the direction of motion did positive work on the child. The positive work done by the external force resulted in an increase in the child's kinetic energy, causing her speed to change.
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