The balanced skeleton reactions are given below
2MnO₄⁻(aq) +5 H₂O₂(aq) + 6\(H^{+}\)(aq) → 2Mn²⁺(aq) + 5O₂(g) + 8\(H_{2}O\)(l)
The oxidising agent and reducing agents are Mn and H₂O₂(aq) .
The following are involved in an acidic medium's balancing redox reaction .
The reaction should first be split into two half reactions Balance the atoms present in half reaction other than oxygen and hydrogen atoms .Add \(H_{2}O\) on that side where number of oxygen atom is less to balance the oxygen atom .Add \(H^{+}\) on another side of in which water attached to make the hydrogen atom equal.Balance the charge by adding \(e^{-}\) .Now , add the two half reactions .The species which reduces the other species in the redox reaction is called oxidizing agent . Similarly , the species which oxidize the other species in the redox reaction is called reducing agent .
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IWhich of the following solutions would be most likely to have the highest water concentration?
Multiple Choice hypertonic solution isotonic solution hypotonic solution water concentration and tonicity of a solution cannot be compared
"Hypotonic solution," refers to a solution with the highest water concentration due to its lower solute concentration compared to the other options, leading to water influx into cells.
A hypotonic solution would be most likely to have the highest water concentration. In a hypotonic solution, the solute concentration is lower than that inside the cell or compared to another solution. As a result, water tends to move into the cell or the solution to equalize the concentration.
When a cell is placed in a hypotonic solution, water molecules will move into the cell through the process of osmosis. This influx of water increases the water concentration inside the cell, leading to cell swelling or even bursting in extreme cases.
Compared to hypertonic and isotonic solutions, a hypotonic solution has a lower solute concentration, allowing for a higher concentration of water molecules. This results in a higher water concentration in the solution. It's important to note that the concept of tonicity is related to the relative solute concentrations between two solutions and their effect on cell osmosis. In this case, a hypotonic solution is characterized by a higher water concentration compared to the other options.
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Describe the appearance and properties of a gas.
Answer:
A gas is light, the molecules are moving very fast, and a gas can change forms due to temp of the area its in.
The texture of many foods is determined by the physical state of the lipid phase. Which one of these statements is NOT true? a. The solid fat content versus temperature profile plays an important role in determining the texture
b. The morphology of the crystals formed plays an important role in determining the texture
c. The texture of foods containing partially crystalline lipids can be described as "plastic"
d. The polymorphic form of fat crystals is in a glassy state
d. The polymorphic form of fat crystals is in a glassy state is NOT true.
The statement that the polymorphic form of fat crystals is in a glassy state is not true. Polymorphism refers to the ability of a substance to exist in multiple crystal structures or forms. Lipids, including fats, can exhibit polymorphism, meaning they can crystallize in different arrangements or crystal forms.
When it comes to the texture of foods containing lipids, the polymorphic form of fat crystals does play a significant role. The specific crystal form and arrangement of the lipids can affect the texture of the food, influencing factors such as mouthfeel, creaminess, and stability.
The solid fat content versus temperature profile is an essential factor in determining texture, as stated in option a. The morphology of the crystals formed, as mentioned in option b, also plays a crucial role in texture. Option c is true as well, as foods containing partially crystalline lipids can exhibit a "plastic" texture.
However, option d is not accurate because the polymorphic form of fat crystals can exist in various states, including crystalline and semi-crystalline states, but not in a glassy state. Glassy states are typically associated with amorphous materials rather than crystalline structures.
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phyy S. Use different flowers to make a variety of dyes and try to market the dyes. State the properties of the dyes made.
The properties of the dyes you can make from different flowers are:
Color VariationNatural and Eco-friendlyAromatic QualitiesLightfastness and DurabilityNatural VariabilityWhat is the variety of dyesFlower dyes have unique colors to offer a range of options for marketing. Rose petals yield pink and red shades. They are Natural and safe. Eco-conscious consumers prefer synthetic-free products, making your dyes attractive.
In terms of Aromatic Qualities: Lavender and jasmine smell nice. Using these flowers in dyes adds subtle scents for a sensory experience. Lightfastness and durability are crucial for creating dyes that resist fading when in the sunlight.
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b Explain what would have happened if Jilly
had thrown the object with more force.
Answer:
force had thrown the object with more
Answer:
If an object is in motion and more force is applied to it, the object will begin moving faster
Explanation:
don't have any (sorry:[ )
A sample of helium had a volume of 3.20x102 mL at STP. What will be it’s new volume of the temperature is increased to 425.0k and it pressure is increased to 3.50 atm?
The new volume of the sample of helium gas as its temperature and pressure increases to the given values is 1.40×10²mL.
Combined gas law
Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.
It is expressed as;
P₁V₁/T₁ = P₂V₂/T₂
Given the data in the question;
Initial volume of helium gas V₁ = 3.20 × 10²mL = 0.32LAt standard remperature and pressure
Initial pressure P₁ = 1.0atmInitial temperature T₁ = 273.15KFinal pressure P₂ = 3.50atmFinal temperature T₂ = 425.0KFinal volume V₂ = ?To calculate the new volume of the helium gas, we subtsitute our given values into the expression above.
P₁V₁/T₁ = P₂V₂/T₂
P₁V₁T₂ = P₂V₂T₁
V₂ = P₁V₁T₂ / P₂T₁
V₂ = ( 1.0atm × 0.32L × 425.0K ) / ( 3.50atm × 273.15K )
V₂ = 136LatmK / 956.025atmK
V₂ = 0.14L
V₂ = 1.40×10²mL
Therefore, the new volume of the sample of helium gas as its temperature and pressure increases to the given values is 1.40×10²mL.
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what happens when you add a second drip and space both the drips close together? Describe the pattern they form and explain the cause for this pattern in detail.
Answer:
Superposition results in adding the two waves together. Constructive interference is when two waves superimpose and the resulting wave has a higher amplitude than the previous waves. Destructive interference is when two waves superimpose and cancel each other out, leading to a lower amplitude.
Explanation:
I hope I hlep :)
a -l container is filled with g argon. if the pressure is atm, what is the temperature? if the temperature is k, what is the pressure?
A) If, the pressure is 10.0 atm, the temperature in the 2.50 L container filled with 175 g of argon is approximately 57.3 K. B) If the temperature is 225 K, the pressure in the 2.50 L container filled with 175 g of argon is approximately 79.1 atm.
Firstly, we can use the ideal gas law equation;
PV = nRT
Where;
P = pressure (in atm)
V = volume (in liters)
n = number of moles of gas
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)
Given;
V = 2.50 L
m (mass of argon) = 175 g
P = 10.0 atm
First, we need to calculate the number of moles of argon using the given mass and the molar mass of argon.
The molar mass of argon will be approximately 39.95 g/mol.
Number of moles (n) = mass/molar mass
n = 175 g / 39.95 g/mol
n ≈ 4.38 mol
Now, we rearrange the ideal gas law equation to solve for temperature (T);
T = PV / (nR)
Substituting the given values, we have:
T = (10.0 atm) × (2.50 L) / (4.38 mol × 0.0821 L·atm/mol·K)
Calculating this expression, we find;
T ≈ 57.3 K
Therefore, if the pressure is 10.0 atm, the temperature in the 2.50 L container filled with 175 g of argon is approximately 57.3 K.
Given;
T = 225 K
To find the pressure (P), we rearrange the ideal gas law equation as follows;
P = nRT / V
Substituting the given values, we have:
P = (4.38 mol × 0.0821 L·atm/mol·K × 225 K) / (2.50 L)
Calculating this expression, we find:
P ≈ 79.1 atm
Therefore, if the temperature is 225 K, the pressure in the 2.50 L container filled with 175 g of argon is approximately 79.1 atm.
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--The given question is incomplete, the complete question is
"A 2.50-L container is filled with 175 g argon. a. If the pressure is 10.0 atm, what is the temperature? b. If the temperature is 225 K, what is the pressure? "--
3. The chemical formula of a mineral can be considered a statement about the chemical components and their proportions in a mineral's structure. One of the basic tenets is that the mineral must be electrically neutral. For each of the minerals listed below, write down the mineral formulae and list the valence (oxidation) state of cations and anions that make up that mineral.
2 | Page
EASC 219: Mineralogy Fall 2022
a. uvarovite
b. azurite
c. cuprite
d. gypsum
e. galena
The valence states provided are general representations and may vary depending on specific conditions and coordination environments.
a. Uvarovite: The mineral formula for uvarovite is Ca3Cr2(SiO4)3. In this formula, the valence state of calcium (Ca) is +2, the valence state of chromium (Cr) is +3, and the valence state of silicon (Si) is +4. Oxygen (O) is usually assigned a valence state of -2.
b. Azurite: The mineral formula for azurite is Cu3(CO3)2(OH)2. In this formula, the valence state of copper (Cu) is +2, carbonate (CO3) has a valence state of -2, and hydroxide (OH) has a valence state of -1.
c. Cuprite: The mineral formula for cuprite is Cu2O. In this formula, the valence state of copper (Cu) is +1, and oxygen (O) is usually assigned a valence state of -2.
d. Gypsum: The mineral formula for gypsum is CaSO4·2H2O. In this formula, the valence state of calcium (Ca) is +2, sulfur (S) has a valence state of +6, and oxygen (O) is usually assigned a valence state of -2. The water molecules (H2O) do not have a net charge.
e. Galena: The mineral formula for galena is PbS. In this formula, the valence state of lead (Pb) is +2, and sulfur (S) has a valence state of -2.
It's important to note that the valence states provided are general representations and may vary depending on specific conditions and coordination environments.
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Smoking is a huge societal issue. A sample of 35 young people was taken to investigate e- cigarette/vaporing smoking behaviour.
a) According to the sample on average 7.6% of people between 15-17 years old have used an e-cigarette or vaping device, with a standard deviation of 2.7. Construct a 98% confidence interval for the true proportion of e-cigarette smokers between 15-17 years of age.
b) The same sample found that on average young people smoked 8 hours a week, with a standard deviation of 1.5 hours a week. Construct 95% confidence interval for the true mean of times young people smoke e-cigarette a week.
c) Based on the information obtained above in question b) but knowing that the population standard deviation is 2.05 hours a week, construct 98% confidence interval for the true mean of times young people smoke e-cigarette a week.
a) The 98% confidence interval for the true proportion of e-cigarette smokers between 15-17 years of age is approximately 4.93% to 10.27%.
b) The 95% confidence interval for the true mean of times young people smoke e-cigarettes a week is approximately 7.45 hours to 8.55 hours.
c) The 98% confidence interval for the true mean of times young people smoke e-cigarettes a week, considering a known population standard deviation of 2.05 hours, is approximately 7.78 hours to 8.22 hours.
a) To construct the confidence interval for the true proportion of e-cigarette smokers, we can use the sample proportion, standard deviation, and the desired confidence level. With a sample proportion of 7.6% and a standard deviation of 2.7, we can calculate the standard error as the square root of (sample proportion * (1 - sample proportion) / sample size). Using the formula for a confidence interval, we find the margin of error by multiplying the standard error by the critical value corresponding to the desired confidence level (in this case, 98%). The margin of error is then added and subtracted from the sample proportion to obtain the lower and upper bounds of the confidence interval.
b) For constructing the confidence interval for the true mean of times young people smoke e-cigarettes a week, we use the sample mean, standard deviation, and the desired confidence level. With a sample mean of 8 hours and a standard deviation of 1.5 hours, we can calculate the standard error as the standard deviation divided by the square root of the sample size. Applying the formula for a confidence interval, the margin of error is obtained by multiplying the standard error by the critical value corresponding to the desired confidence level (95%). The margin of error is then added and subtracted from the sample mean to determine the lower and upper bounds of the confidence interval.
c) In this case, since the population standard deviation is known, we can use it instead of the sample standard deviation to construct the confidence interval. With a known population standard deviation of 2.05 hours, we can calculate the standard error using the population standard deviation divided by the square root of the sample size. Following the formula for a confidence interval, the margin of error is obtained by multiplying the standard error by the critical value corresponding to the desired confidence level (98%). The margin of error is added and subtracted from the sample mean to establish the lower and upper bounds of the confidence interval.
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What do these floors represent?
Explanation:
What type of floor. You have uploaded no image
The moment in a titration where exactly enough titrant has been added to completely react with the analyte is called _____.
The moment in a titration where exactly enough titrant has been added to completely react with the analyte is called "equivalence point ".
The titration's equivalence point occurs when precisely the right amount of titrant has just been added to cause the analyte to totally react.
The point during which chemically equivalent amounts of reactants have been combined is known as the equivalence point, also known as the stoichiometric point, in a chemical process. The equivalence point for an acid-base reaction is the point at which, in accordance with the chemical reaction, equal amounts of acid and base would neutralize one another.
Therefore, the moment in a titration where exactly enough titrant has been added to completely react with the analyte is called "equivalence point ".
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What is causing the shrinking of the taiga forest biome?
Answer:
Deforestation
Explanation:
The value of softwood means that large areas of Russia's taiga have been cleared: deforestation is occurring at a rate of 12 million hectares per year (2014). As much as half of the logging in the far east of Siberia is illegal
Answer:
deforestation
Explanation:
and tectonic plates
Give the % composition for each element found in tin (IV) nitride.
32.3699% Tin (Sn)
15.2774% Nitrogen (N)
52.3527% Oxygen (O)
Why has popular media had a negative impact on forensic science?
Answer:
Because it serves their agenda.
Example 13:0. 29 grams of a hydrocarbon with vapour density 29 when burnt completely in oxygen produce 448 ml of carbon dioxide at S. T. P. From the given information, calculate the (i) mass of carbon dioxide formed.
Answer:
0.779
Explanation:
Determine the molecular weight of the hydrocarbon. We know that its vapor density is 29, which means that one mole of the hydrocarbon has a mass of 29 grams. Therefore, the molecular weight of the hydrocarbon is 29 g/mol.
Calculate the number of moles of the hydrocarbon. We can use the formula:
moles = mass / molecular weight
Substituting the values, we get:
moles = 29 g / 29 g/mol = 1 mol
Therefore, we have one mole of the hydrocarbon.
Write the balanced chemical equation for the combustion of the hydrocarbon in oxygen. The general equation is:
hydrocarbon + oxygen → carbon dioxide + water
For one mole of the hydrocarbon, we need one mole of oxygen to completely burn it. The balanced equation is:
CnHm + (n+m/4) O2 → n CO2 + m/2 H2O
Calculate the volume of carbon dioxide produced. We know that 1 mole of any gas at STP occupies 22.4 L. Therefore, one mole of carbon dioxide occupies 22.4 L. The volume of 448 ml of carbon dioxide at STP can be converted to liters:
448 ml = 0.448 L
The number of moles of carbon dioxide produced can be calculated using the ideal gas law:
PV = nRT
where P is the pressure (1 atm), V is the volume (0.448 L), n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature (273 K). Substituting the values, we get:
n = PV/RT = (1 atm x 0.448 L) / (0.0821 L atm/mol K x 273 K) = 0.0177 mol
Therefore, 0.0177 moles of carbon dioxide are produced.
Calculate the mass of carbon dioxide produced. We can use the formula:
mass = moles x molecular weight
The molecular weight of carbon dioxide is 44 g/mol. Substituting the values, we get:
mass = 0.0177 mol x 44 g/mol = 0.779 g
Therefore, the mass of carbon dioxide produced is 0.779 grams.
Let c(x,y,z,t) denote the concentration of a pollutant (the amount per unit volume). (a) What is an expression for the total amount of pollutant in the region R ? (b) Suppose that the flow J of the pollutant is proportional to the gradient of the concentration. (Is this reasonable?) Express conservation of the pollutant. (c) Derive the partial differential equation governing the diffusion of the pollutant.
∂c/∂t represents the rate of change of concentration with respect to time, D is the diffusion coefficient, and ∇·(D∇c) represents the divergence of the diffusion flux.
(a) The total amount of pollutant in the region R can be found by integrating the concentration c(x,y,z,t) over the volume V of the region R. Mathematically, it can be expressed as:
Total amount of pollutant = ∫∫∫V c(x,y,z,t) dV
(b) It is reasonable to assume that the flow J of the pollutant is proportional to the gradient of the concentration, as this relationship is based on Fick's law of diffusion. According to Fick's law, the flow of a substance is proportional to the concentration gradient. Mathematically, it can be expressed as:
J = -D ∇c
Where J is the flow of the pollutant, D is the diffusion coefficient, and ∇c is the gradient of the concentration.
(c) To derive the partial differential equation governing the diffusion of the pollutant, we can apply the continuity equation, which states that the rate of change of the concentration in a given volume is equal to the divergence of the flow. Mathematically, it can be expressed as:
∂c/∂t = -∇·J
Using the relationship from part (b), we can substitute it into the continuity equation:
∂c/∂t = ∇·(D∇c)
This is the partial differential equation governing the diffusion of the pollutant, where ∂c/∂t represents the rate of change of concentration with respect to time, D is the diffusion coefficient, and ∇·(D∇c) represents the divergence of the diffusion flux.
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Describing Matter Matter is anything that has______ and takes up space (_________). The _______________ of an object measures the amount of matter or substance the object contains. Volume is the measure of _________________ by the object.
Answer:
Mass; mass; amount of space taken up.
Explanation:
Matter is anything that has mass and takes up space. The mass of an object measures the amount of matter or substance the object contains.
Volume is the measure of the amount of space taken up by the object.
The SI units for mass and volume are kilogram (kg) and cubic meter (m³) respectively.
Generally, matter exists in three (3) distinct phases and these are;
1. Solid: it is the state of matter in which the physical substance has a definite shape and fixed volume but not compressible. Examples of solids are pen, screwdriver, television, car etc.
2. Liquid: it is the state of matter in which the physical substance can be poured and takes the shape of its container. Also, liquids generally have a definite volume. Examples of liquids are urine, water, milk, blood etc.
3. Gas: it is the state of matter in which the physical substance has no definite shape or volume and as a result fills all available space. Also, gases are easily compressible and can flow. Examples of gases are hydrogen, oxygen, argon, nitrogen etc.
equation
4 is number 4
#13 Using equation 4, calculate the buffer capacity of water = M per unit pH change Answer format: Number: Round to: 4 decimal places. Show Hint √0 % #14 Please show your work for this answer using
Equation 4 is given as:pH = pKa + log ([A-]/[HA])Where pH is the negative log of the hydrogen ion concentration and pKa is the negative log of the acid dissociation constant. [A-] is the concentration of the conjugate base and [HA] is the concentration of the acid.
Using equation 4, the buffer capacity of water can be calculated using the following formula:
β = dC/dpH
where β is the buffer capacity, dC is the change in concentration of the acid or the base, and dpH is the change in pH per unit concentration.
To calculate the buffer capacity of water, we need to know the acid dissociation constant (Ka) of water. The Ka of water is 1.0 x 10-14 M at 25°C.
Therefore, the pKa of water is 14.0 at 25°C.We can assume that the concentration of water is constant, so the change in concentration of water (dC) is zero. Therefore,β = dC/dpH = 0/dpH = 0The buffer capacity of water is zero because water cannot act as a buffer since it is a neutral substance with no acid or base properties.Showing the work for Answer 14:β = dC/dpHwhere dC = 0 (since the concentration of water is constant) and dpH = 1Therefore,β = 0/1 = 0M/pHThe buffer capacity of water is zero M/pH.
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What does the presence of an estrogen receptor (ER) in the tissue sampling of a breast cancer biopsy indicate
The presence of an estrogen receptor (ER) in the tissue sampling of a breast cancer biopsy indicates that the cancer cells may respond to hormone-based therapies that target estrogen.
Estrogen receptors are proteins found on the surface of cells, including breast cancer cells. When estrogen binds to these receptors, it can stimulate the growth and division of cancer cells. However, the presence of an estrogen receptor in a breast cancer biopsy indicates that the cancer cells are receptive to hormone-based therapies, such as selective estrogen receptor modulators (SERMs) or aromatase inhibitors. These therapies work by blocking or suppressing the effects of estrogen on cancer cells, thereby inhibiting their growth. The presence of an estrogen receptor helps determine the appropriate treatment approach for breast cancer, as hormone-based therapies can be effective in hormone receptor-positive breast cancers but less effective in hormone receptor-negative breast cancers.
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True or False? The energy carried by a sound
wave is blocked by collisition
between the particles in the
material the name is traveling
in
Answer:
true
Explanation:
i checked on moogle
Which choice best describes a testable hypothesis?
A.) Carrots look better when given more water.
B.) Lilacs are better smelling than roses.
C.) Mountain lions travel over 100 km per day.
D.) The bacterium E. coli is worse than the bacterium S. aureus.
Answer:
A. carrots look better when given more water
Humans rely on water for
Answer:
almost everything
Explanation:
What is the type of reaction that happens between acid and alkali react together to give salt of acid and water?
The reaction is called as the neutralisation reaction in which reaction happens between acid and alkali react together to give salt of acid and water.
A neutralization response may be described as a chemical response wherein an acid and base quantitatively react collectively to shape a salt and water as products. In a neutralization response, there may be a aggregate of H+ ions and OH– ions which shape water. When an acid and alkali react collectively, they produce a salt and water: acid + alkali → salt + water .
As you can know, water is neutral, so the acid and the alkali have come collectively to neutralise every different (to make a pH 7).acid and alkali will neutralise every different and bring a salt and water. This is referred to as a neutralisation response.
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Which of the following describes a compound?
A.
a piece of pure carbon, containing only carbon atoms
B.
oxygen gas surrounding a solid piece of carbon
C.
a substance made of two oxygen atoms for each carbon atom
D.
carbon and oxygen atoms mixed without being bonded together
Answer:
Explanation:
D.
carbon and oxygen atoms mixed without being bonded together
Q. Explain why is sulfuric acid a corrosive?
.
.
.
.
.
.
Can we clean a dumb humans brain with windex?if yes then tell me how?
Answer: yes
Explanation: cut open their head and spray their head with windex. THAT SIMPLE
If 1000. mL of water freezes, which of the following is a reasonable approximation for the volume of the resulting ice?
Group of answer choices
1000. mL
961 mL
1040 mL
No answer text provided.
Previous Next
Answer:
If 1000. mL of water freezes, which of the following is a reasonable approximation for the volume of the resulting ice?
Group of answer choices
1000. mL
961 mL
1040 mL
Explanation:
Ice is fewer denser than water.
The reason is the volume occupied by the same mass of ice with water is more than the volume occupied by water. Ice has more empty space within it.
Due to this reason, ice floats on water.
When 1000ml of water freezes to ice then its volume is greater than water.
Among the given options the correct answer is 1040 mL .
Sedimentary cycle having a small gaseous component is found in A) Phosphorus B) Nitrogen C) Carbon D) Sulphur.
The sedimentary cycle is a set of processes by which sediment is created, transported, and deposited. Although the sedimentary cycle does not include a significant gaseous component, it does include small amounts of gases such as nitrogen, carbon, phosphorus and sulphur.
Here, all the options are correct.
These gases are essential nutrients for many organisms and are cycled through the environment by the sedimentary cycle. Nitrogen is a particularly important element in the sedimentary cycle. Nitrogen is vital to the growth of plants and animals, and it is cycled through the environment by the sedimentary cycle.
Nitrogen is taken up by plants, and then it is released by decomposers back into the environment. As it is transported in rivers and streams, it is eventually deposited into the ocean and is taken up by marine organisms.
Here, all the options are correct.
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Single Atomic Cu-N2 Catalytic Sites for Highly Active and Selective Hydroxylation of Benzene to Phenol
In a living animal's brain, a single-atom Cu-N2 catalyst eliminates oxygen interference for electrochemically sensing hydrogen peroxide.
How to find an effective single-atom catalyst for the conversion of benzene to phenol?
Finding an effective single-atom catalyst for the conversion of benzene to phenol is crucial, but the task is still difficult. Here, a single-atom catalyst (Cu1-N₂/HCNS) with distinctive Cu-N₂ moieties was created and verified by HAADF-STEM and EXAFS. Under the same reaction conditions, the turnover number (TON) over Cu1-N₂/HCNS (6,935) is 3.4 times that of Cu1-N₃/HCNS (2,034), and both show significantly greater phenol selectivity (almost 99%) and stability compared with Cu nanoparticles and nanoclusters. Experiments and DFT calculations show that atomically dispersed Cu species are active sites for the hydroxylation of benzene to phenol. The Cu-N₂ is more active than the Cu-N₃ due to its lower energy barrier for the activation of H₂O₂, which is caused by its special local atomic coordination state.Learn more about the Catalyst with the help of the given link:
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Which pairs are isomers? CH3CH2CH2CH3 and CH3CH(CH3)CH2CH3. CH3CH(CH3)CH2CH2CH2CH2CH2CH2CH3 and CH3CH2CH2CH2CH(CH2CH2CH3)CH2CH3. CH3CH2CH2CH2CH2CH3 and CH3CH2CH(CH3)CH2CH2CH3. CH3CH(CH3)CH2CH2CH(CH3)CH3 and CH3CH2CH2CH2CH2CH2CH2CH3. CH3CH(CH3)CH2CH3 and CH3CH2CH2CH2CH3
The pairs of compounds that are isomers are: CH3CH2CH2CH3 and CH3CH(CH3)CH2CH3, CH3CH2CH2CH2CH(CH2CH2CH3)CH2CH3 and CH3CH2CH2CH2CH2CH3, CH3CH2CH(CH3)CH2CH2CH3 and CH3CH(CH3)CH2CH2CH(CH3)CH3.
Isomers are the molecules which have the same molecular formula but differ in the arrangement of their atoms. The following pairs of compounds are isomers: CH3CH2CH2CH3 and CH3CH(CH3)CH2CH3.CH3CH2CH2CH2CH(CH2CH2CH3)CH2CH3 and CH3CH2CH2CH2CH2CH3.CH3CH2CH(CH3)CH2CH2CH3 and CH3CH(CH3)CH2CH2CH(CH3)CH3.In the first pair of compounds, the molecule on the left is n-butane, while the molecule on the right is 2-methylpropane or isobutane. They are isomers because both have the same molecular formula C4H10, but different structures.2. In the second pair of compounds, the molecule on the left is octane, while the molecule on the right is 2-methylheptane.
These compounds have the same molecular formula, C8H18, but different structures.3. In the third pair of compounds, the molecule on the left is 2-methylpentane, while the molecule on the right is 3-methylpentane.
They are isomers because they have the same molecular formula C6H14, but different structures.4.
In the fourth pair of compounds, the molecule on the left is 2,3-dimethylbutane, while the molecule on the right is 2,4-dimethylpentane.
They are isomers because they have the same molecular formula C8H18, but different structures.5. In the fifth pair of compounds, the molecule on the left is isopropyl group, while the molecule on the right is n-propyl group.
They are isomers because they have the same molecular formula C3H7, but different structures.
In conclusion, the pairs of compounds that are isomers are: CH3CH2CH2CH3 and CH3CH(CH3)CH2CH3, CH3CH2CH2CH2CH(CH2CH2CH3)CH2CH3 and CH3CH2CH2CH2CH2CH3, CH3CH2CH(CH3)CH2CH2CH3 and CH3CH(CH3)CH2CH2CH(CH3)CH3.
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