Balance the following chemical equation B+F2>BF3

Answer:

A) It is the length from the midpoint to the crest.

Explanation:

The correct statement about the amplitude of any transverse wave is: It is the length from the midpoint to the crest. The correct option is A.

A transverse wave is a type of wave in which the displacement of the medium is perpendicular to the direction of wave propagation.

Examples of transverse waves include light waves and water waves in which the surface of the water oscillates up and down while the wave moves horizontally.

The properties of a transverse wave include:

Amplitude: The maximum displacement of the medium from its rest position. This represents the intensity or strength of the wave.

Wavelength: The distance between two adjacent points in the wave that are in phase with each other, for example, between two consecutive crests or troughs. It is typically represented by the symbol λ.

Frequency: The number of complete wave cycles that pass a point in a given amount of time, usually measured in hertz (Hz). The frequency is inversely proportional to the wavelength and is represented by the symbol f.

Period: The time taken for one complete wave cycle to pass a given point, usually represented by the symbol T. The period is directly proportional to the wavelength and inversely proportional to the frequency.

Speed: The speed at which the wave propagates through the medium, usually represented by the symbol v. The speed is directly proportional to the frequency and wavelength.

These properties are related to each other by the wave equation:

v = fλ,

Where v = the speed of the wave,

f = the frequency,

and λ = the wavelength.

Therefore, The correct statement about the amplitude of any transverse wave is A. It is the length from the midpoint to the crest.

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Answer:

False

Explanation:

(I guess if it were written "properly" it would be ax=bx implies a=b).

Given the axioms we were given, it would seem that the statement should be true, no?

A related statement -- also listed as false -- is that "in any vector space, ax=ay implies that x=y." Again, given the axioms we have.

Answer:

False

Explanation:

Simply use the counterexample u = 0

For zero vector:

au=bu=0

holds for a=3, b=4

False

Answer:

Explanation:

Given:

V₀ = 0 m/s

V = 20m/s

t = 5 s

___________

a - ?

The acceleration:

\(a = \frac{(V -V_{0} )}{t} \\\\\)

\(a=\frac{(20 - 0)}{5} = 4 \frac{m}{s^{2} } \\\)

Answer:

1. Soil.

2. Soil profile.

3. Regolith.

4. Humus.

5. Soil texture.

6. Soil pH.

7. Inorganic.

8. Soil horizon.

9. Parent material.

10. Organic.

Explanation:

1. Soil: the thin upper layer of Earth's crust that supports plant life. There are three (3) main types of soil; sandy, clay and loamy soil.

2. Soil profile: a vertical section of soil that shows the horizon and parent material.

3. Regolith: the layer of loose rock on the surface of the earth; also called mantle rock.

4. Humus: dark colored organic material in soil; it is left over from the decay of living things.

5. Soil texture: a physical property of soil that describes how the soil feels, and the relative components of sand, silt, and clay sized particles.

6. Soil pH: a chemical property of soils that describes the measure of hydrogen ions in a soil sample; how acidic or basic a soil sample is.

7. Inorganic: a substance that does not contain carbon and hydrogen atoms, such as salts, rocks, and minerals.

8. Soil horizon: a distinct layer of soil that has characteristic properties.

9. Parent material: the rock material that was weathered to form the sediments in a given soil.

10. Organic: a substance that contains carbon and hydrogen atoms, such as carbon dioxide, glucose, methane, and nucleic acid.

The traffic cop needs 23.3 seconds to pass the automobile.

When your velocity (not speed) changes, you are accelerating. A automobile moving at a steady 100 km/h in a straight line has no acceleration. Average acceleration is equal to (change in velocity) / (duration). The car's acceleration is zero because its change in velocity is also zero.

\(d1 = v1*t1 = 35.0 m/s * 1 s = 35.0 m\)

\(d = d1 = 35.0 m\)

\(d2 = v2*t + (1/2)at^2\)

\(d2 = (1/2)at^2\)

\(v2*t + (1/2)at^2 = (1/2)at^2\)

\(v2*t = (1/2)at^2\)

Solving for t, we get:

\(t = (2v2/a) = (235.0 m/s)/3.0 m/s^2 = 23.3 s\) (rounded to 2 decimal places)

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By the use of law of reflection To get a complete view of the rear window of the car is enough for the rear-view mirror to have a height of 0.1137m or 11.37cm

According to the law of reflection, the angle of incidence and reflection is equal.

\(\theta_r=\theta_i\)

Both the incident and reflected rays lay on the same plane.

Plane mirrors are reflective surfaces where each point of the mirror has the same normal direction to the surface. As a result, the size of the images produced by flat mirrors is equal to that of the object, and the image's distance is equal to that of the object.

Mathematically, the plane mirror equation yields,,

\(i=-o\)

The virtual nature of the image is represented by the negative symbol. The plane mirror's lateral magnification is,

\(m=\frac{-i}{o}\) = 1.

We are assuming that the top of the mirror, with unknown height

h, matches the driver's eyes. The height of the window is

H= 0.55m, while the distances from the mirror to the eyes and from the window to the mirror are d=0.60m and D=1.70m, respectively.

The following is how the reflection process works: An angle is created when a light beam from the window hits the mirror, reflected on the road, reaches the driver's sight. The worst case scenario occurs at the window's angle's lowest point. \(\theta_r\),  . The mirror's height must be adjusted to guarantee that the reflected light hits the driver's eyes.

. Using the trigonometric relations,\(Tan \theta=\frac{H-h}{D+d}\)

for the large lower triangle, and,

\(Tan \theta=\frac{h}{d}\) for the small upper one.

Equating the tangents results in the equation,

 \(\frac{h}{d}=\frac{H-h}{D+d}\)

solving for h

h=\(\frac{Hd}{D+2d}\)

Substituting the numeric values,

\(h=\frac{0.55m\times0.60m}{1.70m +2\times0.60m}\)

h=0.1137m

To get a complete view of the rear window of the car is enough for the rear-view mirror to have a height of 0.1137m or 11.37cm

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What is the orbital speed of the satellite (in miles per hour) is 20465 miles per hour.

Orbital velocity is also called as critical velocity. It is minimum velocity must be given to the satellite or the body, so that it can revolve around the planet. i.e. orbital velocity is minimum velocity of body to revolve in stable orbit around a planet. Orbital velocity is given by,

\(v_{c}=\sqrt{\frac{GM}{R+h}}\)

where G = Gravitational constant (6.673×10⁻¹¹ Nm²/kg²) M = Mass of the planet R = Radius of the planet h = height of the object(satellite) Orbital velocity depends on mass of the planet, radius of the planet and height of the object(satellite). It is independent of mass of the body(satellite).

In this problem,

h = 120 miles,

R = 9000 miles

T = 2 hr, 50 min = 2.8 hr

ω = 2π/T

v/(R+h) = 2π/T

v = 2π(R+h)/T

putting all the values in the equation,

v = 2×3.14(120+9000)/2.8

v = 20465 miles per hour.

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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer:

The right answer is gamma rays.

Explanation:

Please mark me brainliest

Answer:

The time is 1.4 sec

The initial velocity is 10.7 m/s.

Explanation:

Given that,

Height = 10 m

Distance = 15 m

We need to calculate the time

Using equation of motion

\(s=ut-\dfrac{1}{2}gt^2\)

Put the value into the formula

\(10=0+\dfrac{1}{2}\times9.8\times t^2\)

\(t^2=\dfrac{2\times10}{9.8}\)

\(t=\sqrt{\dfrac{2\times10}{9.8}}\)

\(t=1.4\ sec\)

We need to calculate the initial velocity

Using formula of velocity

\(v=\dfrac{d}{t}\)

Put the value into the formula

\(v=\dfrac{15}{1.4}\)

\(v=10.7\ m/s\)

Hence, The time is 1.4 sec

The initial velocity is 10.7 m/s.

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

PE = 10 × 9.8 × 20

We have the final answer as

Hope this helps you

Answer:

a)   x = ⅔ d , b) the charge must be negative, c) Q

Explanation:

a) In this exercise the force is electric between the charges, we are asked that the system of the three charges is in equilibrium, we use Newton's second law. Balance is on the third load that we are placing

         ∑ F = 0

        -F₁₂ + F₂₃ = 0

         F₁₂ = F₂₃

let's replace the values

        k Q Q / r₁₂² = k Q 4Q / r₂₃²

            Q² / r₁₂² = 4 Q² / r₂₃²

suppose charge 3 is placed at point x

        r₁₂ = x

        r₂₃ = d-x

we substitute

             1 / x² = 4 / (d-x) 2

             1 / x = 2 / (d-x)

             x = 2 (x-d)

             x = 2x -2d

            3x = 2d

              x = ⅔ d

b) The sign of the charge must be negative, to have an attractive charge on the two initial charges

c)  Q

The orbital period of this asteroid is approximately 353.55 Earth years.

Kepler's third law states that the square of the orbital period (in years) of a planet or asteroid is proportional to the cube of its semi-major axis (in AU).

Therefore, we can use the following formula to calculate the orbital period:

(T / 1 year)^2 = (a / 1 AU)^3

where;

Plugging in the values for the asteroid at 50 AU, we get:

(T / 1 year)^2 = (50 / 1 AU)^3

(T / 1 year)^2 = 125000

T / 1 year = √(125000)

T = 353.55 Earth years (rounded to two decimal places)

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The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Louis de Broglie's principle of electrons states that (b) They behave as a wave and a particle.

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The constant acceleration of the train is 0.33 m/s.

The average velocity can be calculated by using the formula:

velocity = distance/time

For the 1st car, the velocity is calculated as:

v₁ = 8.60 m / 1.80 s = 4.78 m / s

For the second car, velocity can be calculated as:

v₂ = 8.60 m / 1.66 s = 5.34 m / s

Now we can solve for the acceleration using the formula:

v₂² = v₁² + 2 a d

Rewriting in terms of a, we get

a = (v₂² – v₁²) / 2 d

a = (5.34)² – (4.78)² / (2 × 8.6)

a = 0.33 m/s

Therefore, the constant acceleration of the train is 0.33m/s.

what is acceleration explain?

acceleration, fee at which speed modifications with time, in terms of each pace and course. A factor or an object shifting in a directly line is improved if it hastens or slows down. motion on a circle is improved even if the velocity is steady, due to the fact the route is constantly converting

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Answer:

B. 8,437.5 J

Explanation:

Given the following data;

Height = 400m

Mass = 75kg

Velocity = 15m/s

Time = 10 secs

To find the kinetic energy of the skier?

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

Substituting into the equation, we have;

\( K.E = \frac{1}{2}*75*15^{2}\)

\( K.E = 37.5*225\)

K.E = 8,437.5 Joules.

Answer:

Work is done by friction = -165 J

Explanation:

Given:

Mass of block (m) = 15 kg

Ramp inclined = 28°

Friction force (f) = 30 N

Distance (d) = 5.5 m

Find:

Work is done by friction.

Computation:

Work is done by friction = -Fd

Work is done by friction = -(30)(5.5)

Work is done by friction = -165 J

Answer:

One possible explanation students can make: The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.

Answer:

5

Explanation:

when you move 3 unit to the right your object is at 3.then when you move 4 units to the left your object is at -1 because

a number line also has negative numbers.Then if you move 6 units your object is at 5

Answer:

Approximately \(1.75\; {\rm s}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance is negligible.)

Explanation:

Find the velocity of the ball right before landing using the following SUVAT equation:

\(\displaystyle v^{2} - u^{2} = 2\, a\, x\),

Where:

Rearrange this equation to find \(v\):

\(\begin{aligned}v &= \sqrt{u^{2} + 2\, a\, x} \\ &= \sqrt{(8.45)^{2} + 2\, (9.81)\, (29.8)}\; {\rm m\cdot s^{-1}} \\ &\approx 25.61\; {\rm m\cdot s^{-1}}\end{aligned}\).

Divide the change in velocity by acceleration to find the time elapsed:

\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{25.61 - 8.45}{9.81} \; {\rm s}\\ &\approx 1.75\; {\rm s}\end{aligned}\).

Answer:

i think its skin..think so this answre help you

The acceleration due to gravity on Mars is 11.81 m/s².

The given parameters:

The equation of motion to determine the acceleration due to gravity on the moon is calculated as follows;

\(s = vt + \frac{1}{2} gt^2\)

where;

Since the time measured is two way time, the new equation for the total distance traveled is calculated as;

\(v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{320 \times 27.1}{2} \\\\d = 4,336 \ m\)

The acceleration due to gravity is calculated as follows;

\(s = vt + \frac{1}{2} gt^2\\\\4,336 = 0 \ + \ \frac{1}{2} \times g \times (27.1)^2\\\\4,336 = 367.21g\\\\g = \frac{4,336}{367.21} \\\\g = 11.8 1 \ m/s^2\)

Thus, the acceleration due to gravity on Mars is 11.81 m/s².

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This is the answer tab

First, we need to keep in mind that for inelastic collisions we cannot apply the Law of Conservation of Energy, as some of the energy will dissipate. However, we can apply the Law of Conservation of Momentum. This tells us that:

So, we'll start by writing the initial momentum of the system. This is:

This will have to be the same by the end. However, as we know, the mass will be 1.55+1.25=2.8kg. Then, we can write our equation as:

Then, our answer is b) 0.196 m/s

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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The reading on a vernier caliper can be represented as 45.75mm.

1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.

2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.

3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.

4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.

5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.

6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.

7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.

8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.

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