Mass of the lead that should be placed so that the top of the cube will be just level with the water surface will be 2.8 kg.
What does buoyancy mean?The term "buoyancy" refers to the upward push a liquid applies to an item submerged in it. An upward force is imposed on an object when you try to submerge it in water, and this force grows as the object is pushed deeper.
How to solve the complete question?Let's assume that the system is in equilibrium,
now, F = force due to gravity
B = buoyant force
L = length of cube
d = density
M = mass of lead
F = B - Mwood×g - M×g
at equilibrium, F=0
B = dwater×L³×g
L³= volume of water displaced
0 = dwater×L³×g - Mwood×g - M×g
d = Mass/ Volume
dwater×L³ - dwood×L³ - M = 0
M = (dwater - dwood) L³
M = (1 - 0.65) (20)³
M = 2.8 kg
Thus, the mass of lead that should be placed on the cube so that the top of the cube will be just level with the water surface will be 2.8 kg.
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The complete question is,
A cube of wood an edge dimension of 20.0 cm and a density of 650kg/m³ floats on water. What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface?
As gasoline flows steadily upward in a pipe of uniform diameter, its velocity decreases because of the negative influence of gravity
T/F
True, as gasoline flows steadily upward in a pipe of uniform diameter, its velocity decreases because of the negative influence of gravity.
This is because gravity opposes the upward flow of gasoline, causing a decrease in velocity as it moves against the gravitational force.
In a stream line flow of liquid, according to equation of continuity AV = constant
Where a is the area of cross section and v is the velocity of liquid flow.
When flowing in a broader pipe enters a narrow pipe, the area of cross-section of water decreases therefore the velocity of water increases.
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An unstrained horizontal spring has a length of 0.40 m and a spring constant of 340 N/m. Two small charged objects are attached to this spring, one at each end. The charges on the objects have equal magnitudes. Because of these charges, the spring stretches by 0.033 m relative to its unstrained length. Determine (a) the possible algebraic signs and (b) the magnitude of the charges.
Answer:
(a) Both the charges are positive or negative.
(b) Teh value of each charge is 1.53 x 10^-5 C.
Explanation:
Spring constant, K = 340 N/m
Natural length, L = 0.4 m
stretch, y = 0.033 m
(a) Let the charge on each sphere is q and they repel each other so the nature of charge of either sphere may be both positive or both negative.
(b) The electrostatic force is balanced by the spring force.
\(\frac{kq^2}{(L + y)^2}=Ky\\\\\\\frac{9\times 10^9 q^2}{(0.4 +0.033)^2} = 340\times0.033\\\\q= 1.53\times 10^{-5} C\)
What makes the eardrum vibrate?
Answer:
The sound waves are gathered by the outer ear and sent down the ear canal to the eardrum. The sound waves cause the eardrum to vibrate, which sets the three tiny bones in the middle ear into motion. The motion of the three bones causes the fluid in the inner ear, or cochlea, to move.
~+lil more info+~
The sound waves go through the ear canal into the middle ear, which includes the eardrum (a thin layer of tissue) and three tiny bones called ossicles. The sound causes the eardrum to vibrate. The ossicles amplify these vibrations and carry them to the inner ear.
An automobile cooling system holds 16 l of water. the specific heat of water is 4186 j/kg⋅c∘. How much heat does it absorb if its temperature rises from 17C to 87C?
The amount of heat that the water absorbs in cooling system of the automobile is 4688320 Joules.
The water holding capacity of the cooling system of the automobile s 16L.
The density of water is 1000Kg/m³. The specific heat of water is 4.186 J/KgC°.
The temperature of the water rises to 87°C from 17°C.
Now, the amount of heat that the water absorbs is,
Q = mcT
Where,
Q is the heat absorbed,
m is the mass of the water,
c is the specific heat of water,
T is the change in temperature of water.
Putting values,
Q = 1000 x 16 x 4.186 x 70
Q = 4688320 Joules.
So, the amount of heat absorbed is 4688320 Joules.
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Which has a greater atomic radius Calcium or Iron?
Iron has a greater atomic radius than calcium.
This comes from the fact that Iron has more electrons, this in turns means that the it has more shells and then the distance between its nucleos to the outer shells is greater.
a motorcycle covers a distance of 8.5 km in 15 minutes. Calculate the distance covered by the motorcycle in per second
If you get too many fouls, you may not be able to play in the rest of the game.
A. True
B. False
Answer:
In the NBA that's true
Predict how your observations would change if you used a beaker with the same mass of lower temperature water.
The transfer of warmth (heat) from one item to another is known as heat conduction. Therefore, we can witness heat or thermal conduction when two things with differing temperatures come into touch.
Thus, The heat transfers from the hotter (the cup) to the colder (our hands) object when we contact the hot cup. When we added hot water to the cup that was at normal temperature, thermal conduction also took place.
The object's temperature is actually a measurement of how quickly its atoms are moving. The total energy produced by the atoms' vibrations is measured by the heat.
As a result, the atoms inside it begin to travel more quickly, which inevitably raises the likelihood that they will collide and conduction. It also relies on the density of the material we are working with how much they will clash.
Thus, The transfer of warmth (heat) from one item to another is known as heat conduction. Therefore, we can witness heat or thermal conduction when two things with differing temperatures come into touch.
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If a customer bought $175,000 worth of goods and paid the firm cash eight days after the sale, how much cash would Stowe-Arts Holdings Co. get from the customer
We can see here that the cash that Stowe-Arts Holdings Co. would get from the customer is $171,500. C. $171,500.
Who is a customer?A customer is an individual, organization, or entity that purchases goods, services, or products from a business or supplier. Customers are the key stakeholders in business transactions and play a crucial role in driving economic activity.
To calculate the cash received by Stowe-Arts Holding Co., we can subtract the discount from the total amount owed.
Total amount owed: $175,000
Discount: 2% of $175,000 = $3,500
Cash received = Total amount owed - Discount
Cash received = $175,000 - $3,500
Cash received = $171,500
Therefore, the cash that Stowe-Arts Holdings Co. would get from the customer is $171,500.
Thus, the correct answer is C. $171,500.
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The complete question is:
Stowe-Arts Holdings Co. has a very attractive credit policy, and none of its customers pays in cash when the firm makes a sale. Stowe-Arts Holdings Co. sells to its customers on credit terms of 2/10, net 30.
If a customer bought $175,000 worth of goods and paid the firm cash eight days after the sale, how much cash would Stowe-Arts Holdings Co. get from the customer?
A. $183,750
B. $157,500
C. $171,500
D. $140,000
A single jersey fabric with the following specifications: Wale Density: 15 wales/cm Course Density: 18 courses/cm Loop Length: 0.30 cm Yarn Number: 22 tex Fabric Width: 70 cm
The fabric weight in oz/yd2 of a single jersey fabric will be 178.2
Fabric weight (oz/yd^2)= yarn length * conversion (16oz/lb) / yarn number
Loops = 15 x 100 x 18 x 100
= 27,00,000
Yarn length = (27,00,000 x 0.3) / 100
=8,100
Fabric Weight = [8,100 x 22(g)] / 1000
= 178.2
What is the use of fabric weight?
It is possible to weigh various textiles, including cotton, silk, polyester, and canvas. The thickness of the threads used to create the material affects this measurement.
What is the lightest weight fabric?
Cotton is by far the most popular lightweight material. Cotton is used to make half of the world's textiles, and for good reason. Cotton is breathable, making it useful in all conditions, but it is particularly helpful in hot weather, in both wet and dry heat.
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when an unknown weight w was suspended from a spring with an unknown force constant k it reached its equilibrium position and the spring was stretched by 21.9 cm because of the weight w . then the weight w was pulled further down to a position 30 cm (8.1 cm below its equilibrium position) and released, which caused an oscillation in the spring. calculate the cyclic frequency of the resulting motion. the acceleration due to gravity is 9.8 m/s 2 . answer in units of hz.
The cyclic frequency of the resulting motion is 1.438 Hz. when the acceleration due to gravity is 9.8 m/s 2. Because the mass possesses kinetic energy at the static equilibrium displacement, which is translated into potential energy stored in the spring at the extremes of its journey, oscillations happen.
Given:
Force constant of the spring = k
Displacement from equilibrium point = 21.9 cm
Displacement from equilibrium point during oscillation = 8.1 cm
Acceleration due to gravity = 9.8 m/s²Formula used:
The frequency of oscillation is given by the formula f = 1/2π √(k/m)
where k is the force constant of the spring and m is the mass of the object.
In this case, we do not have the mass of the weight, but we can assume that the weight is the only object oscillating, and therefore its mass will be considered as m. If the weight is denoted by w, then its mass will be w/g, where g is the acceleration due to gravity.
Therefore,
m = w/g
Displacement during oscillation = 8.1 cm
= 0.081 m
The maximum extension of the spring from the equilibrium point during the oscillation will be the sum of the equilibrium position and the displacement from the equilibrium point during oscillation, i.e.
y = 21.9 cm + 8.1 cm
= 30 cm
= 0.3 m
Frequency of oscillation f
1/2π √(k/m)
Substituting m = w/g, we get
f = 1/2π √(k/(w/g))
f = 1/2π √(kg/w)
Now we will calculate k.
k = mg/y
where m is the mass of the weight, g is the acceleration due to gravity, and y is the maximum extension of the spring from the equilibrium point during the oscillation.
Substituting values, we get
k = (w/g)(9.8 m/s²)/(0.3 m)
k = 32.67w/g
Substituting this value in the equation for frequency, we get
f = 1/2π √(32.67w/gw)
f = 1/2π √(32.67/g)
f = 1.438 Hz
Therefore, the cyclic frequency of the resulting motion is 1.438 Hz.
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which constellation is in contrast with ursa major
Answer: Ursa Major (/ˈɜːrsə ˈmeɪdʒər/; also known as the Great Bear) is a constellation in the northern sky, whose associated mythology likely dates back into prehistory. Its Latin name means "greater (or larger) she-bear," referring to and contrasting it with nearby Ursa Minor, the lesser bear.
Bordering constellations: Draco; Cameloparda...
Brightest star: ε UMa (Alioth) (1.76m)
Meteor showers: Alpha Ursa Majorids; Leonid...
Symbolism: the Great Bear
Which wave interaction results in a change in the direction of the wave as it passes through one medium to another medium? absorption diffraction reflection refraction.
Answer: Reflection
Explanation:
The incident wave is the wave coming from the source. When an incident wave hits an interface, it splits into two parts. There is the reflected wave and the transmitted wave. Assuming that the incident wave hits the interface directly, and not at an angle, the reflected wave will reflect back to the source, and the transmitted wave will pass through the interface and continue on its path. The reflected wave will be "upside down" as it gets sent back.
Answer:refraction
Explanation:
right on edge 2023
the secondary atmosphere of the earth was composed mainly of
7. sketch the electric field lines between two positively charged small spheres placed a short distance from each other.
The electric field lines between two positively charged small spheres placed a short distance from each other will originate from each sphere's surface, repel away from each other, and bend around the spheres, showing the repulsive force between the positive charges.
To sketch the electric field lines between two positively charged small spheres placed a short distance from each other follow the steps below:
Step 1: Draw two small circles, representing the positively charged spheres, placed a short distance apart from each other.
Step 2: Since both spheres are positively charged, the electric field lines will originate from each sphere and repel away from each other.
Step 3: Draw electric field lines starting from each sphere's surface and pointing outward. These lines should curve away from each other as they show repulsion between the positive charges.
Step 4: In the region between the two spheres, the electric field lines will bend outward from one sphere, towards the other sphere, and continue to curve away from the second sphere. These lines illustrate the repulsive force between the two positive charges.
Step 5: Finally, draw some electric field lines that start from one sphere and curve around the outer side of the other sphere, demonstrating the repulsion between the two positively charged spheres.
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If an object is acted upon by a net force, the change in velocity will be?
Answer:
posetive
Explanation:
an object with a force exerted on it will move forwards
11. A car travels 500 miles at an average speed of 54. 9 mi/hr. How long will the trip take?
If an automobile drives 500 miles at an average speed of 54.9%, it will take 14.6 hours to finish the journey. The total distance that the thing has gone is its average speed.
divided by the entire amount of time it took to go the distance. The equation for average speed is: The difference between instantaneous and average speed.
The measurement of distance between two objects or points can be quantitative or occasionally qualitative. Distance in physics or common language can refer to a physical length or an assumption based on other factors (e.g. "two counties over").
Time taken = distance travelled/ speed
Time taken = 500 miles/ 54.9minutes/hr
Time taken = 804.67 km/54.9minutes/hr
Time taken = 14.6 hours
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What should a student do if the hydrochloric acid splashes in their eyes?
.
First aid suggestions include:
Hold your face under running water for 15 to 20 minutes and allow the water stream to flood into your eyes. Use your fingers to hold your eyelids apart (make sure there is no trace of the chemical on your fingers).
If you wear contact lenses, remove them as soon as possible.
Seek immediate medical advice. Medical staff will need to know what chemical was involved, particularly whether it was acid or alkaline, liquid or powder.
Do not judge the seriousness of your eye injury on the degree of pain. For example, alkali chemicals don’t usually cause significant symptoms, but can seriously damage the eye.
Powder or particulate (granular matter, like wet concrete) chemicals can be particularly damaging since they are more difficult to flush out.
Answer:
immediately wash eyes with water
In the figure below, an electric dipole swings from an initial orientation i (?i = 20.0°) to a final orientation f (?f = 25.0°) in a uniform external electric field . The electric dipole moment is 1.90 10-27 C·m; the field magnitude is 3.50 106 N/C. What is the change in the dipole's potential energy?
The answer to the question is -3.63 x 10-19 J for the decrease inside the dipole's potential energy.
The electric dipole ratio is what?Two point charge +q and q coupled by a vector a generate an electrical dipole. The formula for the electric polarizability is p = qa. According to convention, the vector a transfers the charge from minus to positive.
Using the formula,
ΔU = -p * E * Δθ
where is the change in degree between the starting and ultimate orientations of the dipole, E is the strength of the electromagnetic field, and p is the dipole moment.
Δθ = 25.0° - 20.0° = 5.0°
p = 1.90 x 10^-27 C·m
E = 3.50 x 10^6 N/C
Putting in the values, we get:
ΔU = -p * E * Δθ
= -1.90 x 10^-27 C·m * 3.50 x 10^6 N/C * (5.0°)
= -3.63 x 10^-19 J.
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2. A mover is pushing on a very large box with a force of 850 N, but he can't get it to move.
What force is the box exerting on the mover?
A particular reflecting telescope has an objective mirror with a focal length of 1.2 m and an eyepiece of focal length 6mm. what is the magnifying power of this telescope?
A particular reflecting telescope has an objective mirror with a focal length of 1.2 m and an eyepiece of focal length 6mm. Hence the magnifying power of this telescope would be 2 meter.
The magnifying power of the telescope is the ratio of the focal length of the object to the focal length of the eyepiece, that is, m = \(\frac{fo}{fe}\)
Given, the focal length of a objective mirror = 1.2 m,
First, we will convert it to centimeters for ease,
∴ Now, the focal length of objective mirror is 120 centimeters, and,
the focal length of an eyepiece is 6mm which is also 0.6 centimeters.
For a telescope, the magnification is given as:
∵ m = \(\frac{fo}{fe}\)
⇒ m = \(\frac{120}{0.6}\)
⇒ m = 200 centimeters or 2 meter.
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factors affect the rate of evaporation accept
a) humidity
b) nature of liquid
c) pressure
d) temperature
e) turbidity
Answer: e) turbidity
Explanation:
Evaporation is defined as the process by which a liquid without being heated is converted into vapor.
The factors that affect the rate of evaporation of a liquid are:
a) humidity-When the humidity of an environment is high, it will take more time for water to escape to the atmosphere and less time, if the reverse is the case because Humidity is the amount of water vapor in the atmosphere. For example, on a rainy day, clothes tend to dry slower than a sunny day.
b) nature of liquid- different liquids have different rate of evaporation, For example, alcohol will evaporate faster than water
c) pressure - The higher the pressure on the surface of a body of water, the slower the evaporation rate and vice versa.
d) temperature- The temperature of a surrounding affect how fast a liquid ,(water) can evaporate. When the temperature of the liquid is increased, it raises the kinetic energy of the individual molecules that make up the liquid thereby reducing the inter molecular forces of attraction holding the liquid together and causing fast escape into the atmosphere as a vapor or gas
e) turbidity shows the extent water loses its transparency due to the presence of suspended particles lie clay, silt, organic matter etc and so is not a factor that affect rate of evapouration
A beam of protons moves through a uniform magnetic field with a certain magnitude, directed along the positive z-axis. The protons have a velocity of magnitude 7.1 ×105 m/s in the x-z plane at an angle of 22° to the positive z axis. If the force on a proton is 1.2 ×10-14 N, what is the magnitude of the magnetic field? The charge of the proton is q = +1.6×10−19 C.
The equation for the force on a charged particle in a magnetic field:
F = qvBsinθ
where F is the force on the particle, q is the charge of the particle, v is the velocity of the particle, B is the magnitude of the magnetic field, and θ is the angle between the velocity and the magnetic field.
In this case, we are given the force on a proton (F = 1.2 ×10-14 N), the charge of the proton (q = +1.6×10−19 C), and the velocity of the proton (v = 7.1 ×105 m/s) at an angle of 22° to the positive z-axis.
First, we need to find θ. Since the velocity is at an angle of 22° to the positive z-axis, the angle between the velocity and the magnetic field is also 22°.
Next, we can plug in the values we know into the equation for the force:
1.2 ×10-14 N = (+1.6×10−19 C) × (7.1 ×105 m/s) × B × sin(22°)
Now we can solve for B:
B = (1.2 ×10-14 N) / [(+1.6×10−19 C) × (7.1 ×105 m/s) × sin(22°)]
B = 3.39 ×10-5 T
So the magnitude of the magnetic field is 3.39 ×10-5 T.
Using the given information, we can calculate the magnitude of the magnetic field. The force on a proton moving through a magnetic field is given by the equation:
F = q * v * B * sin(θ)
Where F is the force, q is the charge of the proton, v is the velocity, B is the magnetic field magnitude, and θ is the angle between the velocity and the magnetic field direction.
We are given:
F = 1.2 × 10^(-14) N
q = 1.6 × 10^(-19) C
v = 7.1 × 10^(5) m/s
θ = 22°
We need to find the magnetic field magnitude, B. Rearranging the equation to solve for B:
B = F / (q * v * sin(θ))
Now, we can plug in the given values and calculate B:
B = (1.2 × 10^(-14) N) / ((1.6 × 10^(-19) C) * (7.1 × 10^(5) m/s) * sin(22°))
B ≈ 1.41 × 10^(-4) T
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A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
* Question Completion Status: Moving to another question will save this response. Question 29 Which one of the following statements is not true? (choose all apply) O UV radiation is a type of ionizing
One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.
UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.
UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.
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A truck is traveling at a constant speed of 20 m/s through a school zone. At time t = 0 seconds, he passes a hidden police car that is at rest. Five seconds after the truck passes, the police car begins accelerating at a constant rate of 2 m/s in order to catch the truck.
Determine the time at which the speed of the truck is equal to the speed of the police car. Mark this time as t↓1. How will the positions of the police car and the truck compare when they have the same speed and why?
Answer:
Let's define:
The position zero will be in the first point where the truck and police car meet. (So the initial position of both vehicles is zero)
Then, the position equation for the truck is:
T(t) = 20m/s*t
Where t is our variable, time in seconds.
Now, at t = 5s, the car starts accelerating.
Ac(t) = 2m/s^2 for( t ≥ 5s)
For the velocity of the car, we must integrate that.
V(t) = (2m/s^2)*(t - 5) for (t ≥ 5s)
Where i introduced a little change in the variable because the velocity of the car starts to increase for t larger than 5 seconds.
For the position of the car we integrate again.
C(t) = (1m/s)*(t - 5)^2 for (t ≥ 5s)
Now, let's answer the questions:
Determine the time at which the speed of the truck is equal to the speed of the police car.
Then we must have:
V(t) = (2m/s^2)*(t - 5) = 20m/s. (Remember that we only can use times requal or larger than 5 seconds).
2m/s^2*t - 10m/s = 20m/s
2m/s^2*t = 30m/s
t = (30/2) s = 15s
The velocities of both vehicles will be the same after 15 seconds.
t1 = 15s
How the positions will compare at this time?
The easier thing will be to evaluate the position equation of each vehicle in this time:
T(15s) = 20m/s*15s = 300m
C(15s) = (1m/s^2)*(15s - 5s)^2 = (1m/s^2)*(10s)^2 = 100m.
Then we can see that the truck is 200m ahead of the car.
But remember that the police car is accelerating, so the velocity will keep increasing meaning that eventually, the car will catch the truck.
A grapefruit has a weight on Earth of 4.9 newtons. What is the grapefruit’s mass?
Answer:
0.5 kg
Explanation:
W = mg
4.9 = m(9.8)
4.9 = 9.8m
4.9/9.8 = m
m = 0.5 kg
What type of matter is likely to absorb the most sound waves
Answer:
Things like cloth and softmaterial, pliable, or porous materials
Explanation:
Answer:
Porous absorbers e.g paper, cardboards
How many joules of potential energy does the pendulum have when it has 100 J of kinetic energy?
Answer: The maximum kinetic energy is 100 j.
Explanation: The kinetic energy = (potential energy) + (kinetic energy) and the potential energy of 0 J implying its kinetic energy is 100 J, which is its maximum.
If the maximum kinetic energy of the pendulum is 100 J, then the maximum potential energy of the pendulum will be 100 J as well.
The given parameters;
Kinetic energy of the pendulum = 100 JBased on the principles of conservation of mechanical energy, energy is always conserved.
If the maximum kinetic energy of the pendulum is 100 J, then its maximum potential energy will be 100 J as well.
M.A = K.E + P.E
where;
K.E is the kinetic energy P.E is the potential energyAt the lowest displacement of the pendulum;
M.A = K.E + 0
M.A = K.E = 100 J
At maximum displacement of the pendulum;
M.A = 0 + P.E
M.A = P.E = 100 J
Thus, if the maximum kinetic energy of the pendulum is 100 J, then the maximum potential energy of the pendulum will be 100 J as well.
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The central bright fringe in a single-slit diffraction pattern has a width that equals the distance between the screen and the slit. Find the ratio /W of the wavelength of the light to the width of the slit.
The wavelength of the light to the width of the slit (λ/W) is approximately 1.
To find the ratio λ/W, where λ is the wavelength of the light and W is the width of the slit, we can use the formula for the angular width of the central bright fringe in a single-slit diffraction pattern.
Step 1: Write down the formula for angular width of the central bright fringe.
The angular width of the central bright fringe (θ) can be given by the formula:
θ ≈ λ/W
Step 2: Convert angular width to linear width.
To convert the angular width to linear width, we can use the formula:
Linear width (L) = Distance between screen and slit (D) × tan(θ)
Step 3: Substitute the angular width formula from Step 1.
L = D × tan(λ/W)
Step 4: Since the linear width of the central bright fringe equals the distance between the screen and the slit, we can set L = D.
D = D × tan(λ/W)
Step 5: Divide both sides of the equation by D.
1 = tan(λ/W)
Step 6: Use the small angle approximation, where for very small angles, tan(θ) ≈ θ.
1 ≈ λ/W
So, the ratio of the wavelength of the light to the width of the slit (λ/W) is approximately 1.
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