(b) The volume of the cylinder is 0. 0020m". The pressure inside the cylinder is
initially 200 atmospheres. When the cylinder is connected to the balloon, the final
pressure in the cylinder and the balloon is 1. 0 atmosphere. The temperature of the
gas remains constant. Calculate the final volume of gas in the balloon. State the
equation that you use. ​

The relationship between Linear Expansivity and Cubic Expansivity is as follows: Cubic / Volume expansivity = 3 Linear expansivity

Now, consider a sheet of metal of Length (l), Breadth (b), and Height (h). Let the initial Length be (l₁), the initial Breadth be (b₁) and the initial Height be (h₁). Let the final Length be (l₂), the final Breadth be (b₂) and the final Height be (h₂) after the metal is heated through a temperature change of θ.

Considering,

the initial volume of the metal be V₁ = l₁*b₁*h₁

and, the final volume of the metal be V₂ = l₂*b₂*h₂

Then,

Using the formula of linear expansivity,

l₂ = l₁ (∝∆θ + 1 )

b₂ = b₁ (∝∆θ + 1 )

h₂ = h₁ (∝∆θ + 1 )

Remember that Volume = l * b*h

Therefore,

V₁ = l₁*b₁*h₁

V₂ = l₂*b₂ *h₂

V₂ =l₁ (∝∆θ + 1 ) * b₁ (∝∆θ + 1 ) * h₁ (∝∆θ + 1 )

V₂ = l₁* b₁*h₁ (∝∆θ + 1 ) * (∝∆θ + 1 ) * (∝∆θ + 1 )

V₂ = l₁* b₁*h₁ ((∝∆θ * (∝∆θ + 1 ) + 1 * (∝∆θ + 1 ) ) * (∝∆θ + 1 )

Let's open the brackets, now we get,

V₂ = l₁* b₁*h₁(∝²(∆θ)² + ∝∆θ + ∝∆θ + 1 ) * (∝∆θ + 1 )

V₂ = l₁* b₁*h₁(∝²(∆θ)² + 2∝∆θ +1 ) * (∝∆θ + 1 )

V₂ = l₁* b₁*h₁(∝²(∆θ)² * (∝∆θ + 1 ) + 2∝∆θ * (∝∆θ + 1 ) +1* (∝∆θ + 1 ) )

V₂ = l₁* b₁*h₁(∝³(∆θ)³ +∝²(∆θ)² + 2∝²(∆θ)² + 2∝∆θ +∝∆θ + 1 )

V₂ = l₁* b₁*h₁(∝³(∆θ)³ +∝²(∆θ)² + 2∝²(∆θ)² + 3∝∆θ + 1 )

V₂ = V₁(∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 )

Remember that ,

V₂ = V₁ ( ϒ * ∆θ + 1 )

Let us substitute for V₂ in the above formula. Then we will get,

V₁ ( ϒ * ∆θ + 1 ) = V₁(∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 )

ϒ * ∆θ + 1 = ∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ+1 (V₁ canceled V₁ and the brackets are removed)

ϒ * ∆θ = ∝³(∆θ)³ + 2∝²(∆θ)² + 3∝∆θ ( 1 cancelled 1 )

At this point,∝ tends to be zero because its value starts from 0.0000... Upward. Therefore,∝² and ∝³ are approximately zero. i.e. ∝² and ∝³ are = 0.

Therefore, we put zero in place of ∝² and ∝³. Now we get,

ϒ * ∆θ = 0*(∆θ)³ + 2*0*(∆θ)² + 3∝∆θ

ϒ * ∆θ = 0 + 0 + 3∝∆θ

ϒ * ∆θ = 3∝∆θ

ϒ = 3∝ ( ∆θ cancelled. ∆θ )

Therefore,

Cubic / Volume expansivity = 3 Linear expansivity

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The depth to which the block will float in the liquid with a density of 0.80 g/cm³ is 0.9375 times the height of the block.

The depth to which the rectangular block will float depends on the relative densities of the block and the two liquid reservoirs.

If the density of the block is much less than the density of the liquid, the block will float, and the depth to which it's going to float can be calculated the use of Archimedes' precept, which states that the buoyant pressure on a submerged item is equal to the load of the displaced fluid.

Let's count on that the rectangular block has a period (l), width (w), and height (h). The density of the block is 0.75 that of water, so its density is  0.75 g/cm³.

The two liquid reservoirs have densities of 1.20 g/cm³ and 0.80 g/cm³. To calculate the intensity to which the block will drift in every liquid, we can use the subsequent method:

d = (weight of block) / (buoyant force)

the load of the block is given by:

weight of block = density of block × volume of block × g

where g is the acceleration due to gravity (9.81 m/s²). The volume of the block is L × W × H. The buoyant force is given through:

buoyant force = density of liquid × volume of displaced liquid × g

in which the extent of displaced liquid is equal to the volume of the block that is submerged inside the liquid. Inside the liquid with a density of 1. 20 g/cm³, the buoyant force is greater than the load of the block, so the block will float completely.

The depth to which the block will go with the flow is equal to the peak of the block, which is h. Inside the liquid with a density of 0. 0.80 g/cm³, the buoyant force is much less than the weight of the block, so the block will best partially float.

The depth to which the block will float can be calculated by means of setting the buoyant force the same as the weight of the submerged part of the block:

(d × L × W × density of liquid) × g = (L × W × H × density of block) × g

simplifying and fixing for d, we get:

d = (density of block/density of liquid) × H

substituting the values, we get:

d = (0.75 g/cm³ / 0.80 g/cm³) × H = 0.9375 × H

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Answer:

smaller one

Explanation:

even though he is moving quicker doesn't mean he will be packing more force in the collision

No, the wattage rating of an electrical appliance does not depend on how long the appliance is on. The wattage rating of an electrical appliance is a measure of its power, which is defined as the rate at which energy is used or transferred. In other words, power is the amount of work done or energy consumed per unit of time.

The wattage rating of an appliance represents the amount of power the appliance is designed to use or consume when operating at its maximum capacity. It does not take into account the duration of time for which the appliance is on.

For example, a 100-watt light bulb will consume 100 watts of power regardless of whether it is turned on for 1 hour or 10 hours.

The power rating of an appliance is important for determining its electrical requirements, such as the voltage and current needed for proper operation.

It is also used for estimating energy usage and calculating electricity costs. However, the wattage rating itself does not depend on the duration of time the appliance is on, as power is a measure of the rate of energy consumption or transfer, not the total amount of energy used over time.

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Answer:

Hello! Your answer is BELOW

Explanation:

1.About 91.754% of all iron is iron-56. Of all nuclides, iron-56 has the lowest mass per nucleon. With 8.8 MeV binding energy per nucleon, iron-56 is one of the most tightly bound nuclei.

2.The atomic weight of lead is quite variable in nature because the three heaviest isotopes are the stable end-products of the radioactive decay of uranium (238U to 206Pb and 235U to 207Pb) and thorium (232Th to 208Pb).

3.Mass defect for uranium-238 is 3.983 × 10-25 kg.

4.Energy and Mass Are Relative

The equation E = mc^2 states that the amount of energy possessed by an object is equal to its mass multiplied by the square of the speed of light.

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Explanation:

what is it of? I maybe able to help.

Hi there!

We can use the power equation:
\(P = \frac{V^2}{R}\)

P = Power (W)
V = Potential Difference (V)
R = Resistance (Ω)

Rearrange to solve for Resistance:
\(R = \frac{V^2}{P} = \frac{220^2}{1477} = \boxed{32.769 \Omega}\)

Answer:

0.366×10^{-3} / s

Explanation:

θ = θmax e^{-bt/2m}

Given that

             θ = 5.50°

             θmax = 15.0°

So that we have

                ln (θ / θmax) = -bt /2m

            = - ln(5.50°/ 15.0°) / 1000s = b /2m

             = b / 2m = 0.366×10^{-3} / s

The Moon's rate of rotation about its own axis is synchronized with its rate of revolution around the Earth, which means it takes the same amount of time for the Moon to complete one rotation as it does to complete one orbit around the Earth.

The Moon is tidally locked with Earth, which means that its rotation period and revolution period are in sync. This synchronization is the result of gravitational forces between the Earth and the Moon. As a result, the Moon always presents the same face towards Earth, and it takes approximately 27.3 days for the Moon to complete one rotation on its axis.

This period is the same as its orbital period around Earth, known as the sidereal month. Consequently, we always see the same side of the Moon from Earth. The Moon's synchronous rotation and revolution make it an interesting celestial body to study.

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According to Newton's law, action and reaction are equal and opposite.

According to the Newton's third law of motion, action and reaction are equal and opposite. As such, when the arrow hits the vertical wood board, the board exerts some force on the arrow.

We can not determine the magnitude of this force numerically because the question is incomplete.

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Answer:

newtons law action and reaction are equal and opposite

Explanation:

The weather that is least likely to occur when a cold air mass moves in and overtakes a warm front in the presence of a low-pressure system is clear skies ( D ).

When a cold air mass moves in and overtakes a warm front in the presence of a low-pressure system, it is called as occluded front. During this the colder air is pushed beneath the warmer air. Depending on the direction of occlusion, it can be of two types of of occluded fronts such as

During occluded fronts the possible weather conditions are

Therefore, the weather that is least likely to occur with these conditions is clear skies ( D ).

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Rutherford's idea that electrons radiate energy while orbiting around a nucleus would have strengthened the idea of quantum mechanics, which explains the behavior of particles at the subatomic level.

what is mechanics ?

Mechanics is a branch of science that studies the behavior of physical objects, their interactions, and the forces that act on them. It is sometimes referred to as the fundamental science, as it provides the underlying principles of many other sciences, such as engineering, aeronautical science, and medicine.

Mechanics is divided into two main branches: classical mechanics and quantum mechanics. Classical mechanics studies the motion of macroscopic objects, such as automobiles and aircraft, and is a cornerstone of engineering and the physical sciences. Quantum mechanics is the study of the behavior of microscopic objects, such as atoms and molecules, and is a cornerstone of modern chemistry and physics.

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Answer:

3. 1.8A

Explanation:

Given the following data;

Quantity of charge, Q = 650C

Time = 6 minutes to seconds = 6 * 60 = 360 seconds.

To find the current l;

Quantity of charge = current * time

Substituting into the equation, we have;

650 = current * 360

Current = 650/360

Current = 1.8 Amperes

Answer: D. thousands to millions of years

Explanation: Stages within a rock's cycle cannot happen quickly. The formation and deterioration can take thousands to millions of years to occur.

I hope this helps!

Good luck <3

Answer:

30 mins

Explanation:

speee=distance/time

300m/h=15m/time

time=15miles/300miles/hous=1/2 hours=30 mins

Answer:

30 minutes.

Explanation:

If it takes you an hour to run 30 miles but you only need to run 15 miles then you split that hour in half, which results in half an hour or 30 minutes.

Answer:

See below

Explanation:

Measure the distance and the amount of time to cover that distance

 then speed   =    distance / time

Answer:

s=d/t

Explanation:

s=speed

d=distance

t=time

Just basic formula stuff

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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it's C

because the faster an object moves the more kinetic energy it has.

Answer:

The answers is A lol

Explanation:

To calculate the amount of time the clock ran, we can use the formula

time = charge / current

where charge is measured in coulombs (C), current is measured in amperes (A), and time is measured in seconds (s).

Given that the clock moved 10,700 C of charge at a rate of 0.490 mA, we can plug these values into the formula

time = 10,700 C / (0.490 mA / 1000) A

We convert the current from mA to A by dividing by 1000, since 1 A = 1000 mA.

time = 10,700 C / 0.490 A = 21857.142857142857 s

So the clock ran for approximately 21857.14 seconds or around 6.1 hours.

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Answer:

63016

Explanation:

Ri+R2+R3 this is called series circuit

Answer:

200

Explanation:

100+200=300

1/300+1/600=200

Answer:

500 Newton itself

Explanation:

Newton's third law of motion

The component of the weight of the box along the surface is 105.8 N.

The component of the weight of the box along the surface can be calculated using the formula

W_parallel = W * sin(angle),

where W is the weight of the box and angle is the angle of the inclined surface. To find the weight of the box, we can use the formula W = m * g, where m is the mass of the box and g is the acceleration due to gravity.

Given that the mass of the box is 14 kg, we can calculate the weight of the box as follows:

W = 14 kg * 9.8 m/s^2 = 137.2 N.

Now, let's find the component of the weight along the surface. The angle of the inclined surface is given as 52 degrees.

Using the formula W_parallel = W * sin(angle), we can calculate the component of the weight along the surface:

W_parallel = 137.2 N * sin(52 degrees)

= 105.8 N.

Therefore, the component of the weight of the box along the inclined surface is 105.8 N.

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The magnitude of the average emf induced during the 0.6s time interval is 1.8 V. During the first half of the 0.6s time interval, the induced current in the conducting ring flows in a clockwise direction and During the second half of the 0.6s time interval, the induced current in the conducting ring flows in a counterclockwise direction

The magnitude of the average electromotive force (emf) induced during the 0.6s time interval can be calculated using Faraday's law of electromagnetic induction.

The average emf is given by the equation: emf = (change in magnetic flux) / (change in time). In this case, the change in magnetic flux is equal to the change in magnetic field multiplied by the area of the conducting ring.

The change in magnetic field is 1.5T - (-1.5T) = 3T, and the area of the conducting ring is 0.20m². The change in time is 0.6s. Plugging these values into the equation, we get: emf = (3T * 0.20m²) / 0.6s = 1.8V.

During the first half of the 0.6s time interval, the induced current in the conducting ring flows in a clockwise direction when viewed as shown in the figure.

During the second half of the 0.6s time interval, the induced current in the conducting ring flows in a counterclockwise direction when viewed as shown in the figure.

According to Lenz's law, the direction of the induced current opposes the change in magnetic field. When the magnetic field changes from directed out of the page to directed into the page, the induced current in the conducting ring will create a magnetic field that opposes this change.

To do so, the current flows in a direction that creates a magnetic field in the opposite direction. Therefore, during the first half of the 0.6s time interval, the induced current flows in a clockwise direction to create a magnetic field out of the page.

During the second half of the time interval, the induced current flows in a counterclockwise direction to create a magnetic field into the page, opposing the change in the magnetic field.

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The magnitude of force is  F=91.214nN. The force is Repulsive in nature.

Solution:

According to coulombs law, the force between two charges is express as

F=(K*q1*q2) /r^2

constant K = 9*10^9

Hence for a charge q1=6.82nC = 6.82*10^-9,

q2=3.90*10^-9

distance r=1.62m

F = [(9×10^9) ×(6.82×10^-9) × (3.90×10^-9)] /(1.62^2)

F=(239.382×10^-9)/2.6244

F = 91.214×10^-9N

F = 91.214nN

Since the charges are both positive, the force is repulsive

Coulomb listed the following characteristics of the electric force for charges in a resting state: Unlike charges attract each other whereas like charges repel one another. As a result, a positive charge pulls a negative charge toward it whereas two negative charges repel one another. The line between the two charges is where the attraction or repulsion occurs.

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Correct question:

Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 6.82 nc, and the other has a charge of 3.90 nc. (a) What is the magnitude (in N) of the electric force that one particle exerts on the other? (b) is the force attractive or repulsive? O attractive O repulsive

Answer:

False.

Explanation:

Potential of Hydrogen is the full form of PH.

Potential of Hydrogen tells about the acidity or basicity of the solution.

The pH of a solution is a measure of the concentration of hydrogen ions \((H+)\) ions and hydroxide ions \((OH-)\) in a solution.

So, the given statement is false.

The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s

We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.

According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.

We know that;

\(F_{t}\) = \(p_{f}\) -\(p_{i}\)

F = force

t = time taken

\(p_{f}\)= final velocity

\(p_{i}\) = initial velocity

\(p_{f}\) = \(F_{t}\)  + -\(p_{i}\)

\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7

\(p_{f}\)  = 2.4 * 10^7 + 7.5 * 10^7

\(p_{f}\)  = 9.9 * 10^7 Kg m/s

Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.

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Missing parts;

A  space probe is traveling in outer space with a momentum that has a magnitude of  7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0  * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.