at the surface of earth, the escape velocity is 11.2 km/s. in this question you will investigate the escape velocity at the surface of a very small asteroid having a radius 10-4 that of earth and a mass 10-12 that of earth

Answer:

They are inversely proportional

Explanation:

The force of gravity and the distance between two objects involved are inversely proportional to one another.

According to newton's law of universal gravitation "the force of gravity between two bodies is a product of their masses and inversely proportional to the distances between them".

Answer:

Yes, it is possible for acceleration and velocity vectors to have opposite directions at a certain instant. This situation occurs when an object is slowing down or decelerating while still moving in a particular direction.

To illustrate this, consider a car traveling in the positive direction along a straight road. If the car starts to apply the brakes, it will experience a deceleration or negative acceleration. At that instant, the velocity vector (which represents the direction and magnitude of the car's motion) will still be in the positive direction, while the acceleration vector (which represents the change in velocity) will be in the negative direction, opposite to the velocity vector. The car's speed will decrease, and eventually, the velocity vector will align with the acceleration vector as the car comes to a stop.

So, while velocity and acceleration vectors typically have the same direction (e.g., both positive or both negative), there are instances when they can have opposite directions.

Answer:

22.1meter/min

Explanation:

Change 488s to min.

Speed= Distance÷Time

so 180m ÷ 122/15

= 22.1 (3s.f.) meter / min.

The frequency of the instantaneous power waveform in this circuit component is 10 rad/s.

The frequency of the instantaneous power waveform in this circuit component would also be 10 rad/s. In an AC circuit, the instantaneous power is given by the product of the instantaneous voltage and current.

Since both the voltage and current have a frequency of 10 rad/s, the frequency of the instantaneous power waveform will be the same.
To understand this, let's consider a sinusoidal voltage waveform and a sinusoidal current waveform. The power at any instant is given by the product of the voltage and current at that instant.

Since both waveforms have the same frequency, the product of the two waveforms will also have the same frequency.
Therefore, the frequency of the instantaneous power waveform in this circuit component is 10 rad/s.

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If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 44 N · m,  191.3 N of minimum force must be exerted by the mechanic at the end of a 23 cm-long wrench to loosen the nut.

The minimum force required to loosen the nut can be found using the formula: force= torque/lever arm,where torque is the torque required to loosen the nut, and the lever arm is the distance between the center of the nut and the point where the force is applied.

In this case, the torques are 44 N.m and the lever arm is 23 cm or 0.23 m. therefore the minimum force required to lose the nut is :

force=44 N.m/0.23 m =191.2 N, so the force minimum force that the mechanic must exert at the end of the 23 cm long wrench to loosen the nut is 191. N

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To calculate the tensile strength (T), we need to use the formula:

T = Force/Area

In this case, we are given the peak compressive force as 2084 N. However, we need to convert this to tensile force since we want to calculate the tensile strength. Tensile force is equal in magnitude but opposite in direction to compressive force.

Therefore, T = 2084 N

Next, we need to calculate the cross-sectional area (A) of the material. Given that the diameter of the material is 1 inch, we can calculate the radius (R) as half of the diameter:

R = 1 inch / 2 = 0.5 inch

We need to convert the radius to meters since the SI unit of force is Newton (N) and the SI unit of area is square meters (m^2). Since 1 inch is equal to 0.0254 meters, we can convert the radius as follows:

R = 0.5 inch * 0.0254 meters/inch = 0.0127 meters

Now, we can calculate the cross-sectional area (A) of the material using the formula for the area of a circle:

A = π * R^2

A = 3.1416 * (0.0127 meters)^2

A ≈ 0.0005087 square meters

Finally, we can calculate the tensile strength (T) using the formula:

T = 2084 N / 0.0005087 square meters

T ≈ 4,093,981.8 N/m^2

Therefore, the tensile strength (T) is approximately 4,093,981.8 N/m^2.

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According to question, we know that

ux=ucosθax=0

uy=usinθay=−g

The projectile's maximum height h is equal to one-half of H, the triangle's altitude. = H - 12H, resulting in h = H/2, which is the desired result. If a projectile's maximum height is 15 m, its maximum range is 4 * max height, which equals 60 m.

The highest point of the structure or sign measured from the average natural ground level at the base of the supporting structure is referred to as the maximum height.

at max. height

Vy=0

0- usinФ = gt

t = usinФ/g

Now, we know that

H = ut + 1/2g\(t^{2}\)

After putting all the values, we get

H(max) = \(u^{2} sin^{2}\)Ф/2g

Hence proved

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Answer:

Your answer should be d: Foot

Explanation:

The unit "foot" is part of the english system which includes inches, feet, yards, etc.

Answer:

d)60cm​

Explanation:

When an object is placed in front of a plane mirror, its image is formed behind the mirror at the same distance as the object is in front of the mirror. This means that the image distance (d_i) is equal to the object distance (d_o):

d_i = d_o

Initially, the object is placed 30 cm in front of the mirror, so the image distance is also 30 cm.

When the mirror is moved a distance of 6 cm towards the object, the new object distance becomes:

d_o' = d_o - 6 cm = 30 cm - 6 cm = 24 cm

Using the mirror formula, we can find the image distance for the new object distance:

1/d_o' + 1/d_i' = 1/f

where f is the focal length of the mirror, which is infinity for a plane mirror. Therefore, we can simplify the equation to:

1/d_o' + 1/d_i' = 0

Solving for d_i', we get:

1/d_i' = -1/d_o'

d_i' = - d_o'

Substituting the given values, we get:

d_i' = -24 cm

Since the image distance is negative, this means that the image is formed behind the mirror and is virtual (i.e., it cannot be projected onto a screen).

The distance between the object and its image is the difference between their positions:

distance = d_i' - d_o = (-24 cm) - (30 cm) = -54 cm

Since the image is virtual, we can take the absolute value of the distance to get the magnitude:

|distance| = |-54 cm| = 54 cm

Therefore, the distance between the object and its image is 54 cm. The answer is (d) 60 cm, which is the closest option to 54 cm.

Answer:

i think it is newtons third law of motion but i'm not sure sorry.i just really need point i don't know the answer.

Explanation:

The average kinetic energy of a substance's particles directly relates to the substance's Kelvin temperature. The atoms in a specimen of hydrogen, as an illustration

What is kinetic energy (KE)?

Kinetic energy (KE) is the term used in physics to describe an object's energy when it is in motion. The effort needed to move a surplus body at rest to a stated velocity is how it is defined.

What is the history of kinetic energy?

The terms "kinetic energy" and "labor" have been used in modern science since the beginning of the 19th century. The first knowledge of these ideas dates back to Gaspard-Gustave Coriolis, whose work Du Nalidixic acetylcholine receptors nachrs de l'Effet des Machines, published in 1829, explains the mechanics of kinetic energy.

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Answer:

The answer is d =10^6.43 Mpc

Explanation:

Solution

To calculate the absolute magnitude of the star, we apply or use the relation with the period

Mv = - [ 2.76 (log₁₀ (P) - 1.0)] -4.16

Here P =+ 0.5 days

Mv = - 0.569

To calculate m, we have the following relation given below:

Mₓ = - 2.5 Log₁₀ (Fₓ/Fₓ,0)

Fₓ,0 = 1 w/m² (This is assumed)

Fₓ = 2.3 * 10^-11 W/m^2 (Given)

Thus

Mₓ = - 2.5 Log₁₀ (2.3 * 10^ ⁻11

Mₓ = 26.595

Now, applying the formula we have the following given below:

d = ₁₀ ( Mₓ -Mv + 5)/5

d =₁₀ (26.595 - 0.569 +5)/5

d =10^6.43 Mpc

The potential difference between the ends of the 90-cm-long copper wire is 0.010 V.

The electric field inside a 90-cm-long copper wire as 0.011 V/m. You'd like to know the potential difference between the ends of the wire.

To find the potential difference, you can use the formula:

Potential Difference (V) = Electric Field (E) × Length of Wire (L)

First, convert the length of the wire from centimeters to meters:

90 cm = 0.90 m

Now, plug in the values:

Potential Difference (V) = 0.011 V/m × 0.90 m

V = 0.0099 V

Expressing the answer using two significant figures, the potential difference between the ends of the 90-cm-long copper wire is 0.010 V.

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To convert 15 gallons of gasoline to chemical energy in joule, multiply the figure above by 15 which is 1,800,000,000 Joules. Answer to b part is 60KWhrs

a.) A gallon of gasoline in most countries contain about 120 millions joule of chemical energy.

To convert 15 gallons of gasoline to chemical energy in joule, multiply the figure above by 15. That is,

Chemical energy = 15 x 120000000 = 1,800,000,000 Joules

b.) Also, the amount of energy cost per gallon of gasoline produced in most countries is equivalent to about 4 kilowatt hours. The capacity that would be equal to the energy in 15 gallons of  gasoline that a battery should have will be

Capacity = 4 x 15 = 60 KWhrs

Therefore, the capacity a battery will have to be equal to the energy in 15 gallons of gasoline will be 60 KWhrs.

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Answer:

c

Explanation:

Answer:

c

Explanation:

the DNA replication happens in the s phase of interphase

Answer:

this could probably be useful to you

As given, the motorcyclist starts from rest and reaches a speed of 6 m/s

after traveling with uniform acceleration for 3 seconds.

Here, initial velocity u=0

Final velocity v=6 m/s

Time t=3 sec.

Let the acceleration of the motorcycle be a.

On using the equation of motion, v=u+at

6=0+3×a

Or 3a=6

Or a=63

Or a=2 m/s2

→Therefore, the acceleration in a motorcycle is 2 m/s2.←

Explanation:

Given mass of the object is 1200kg and it's placed at a height of 45m above the ground. As we know that potential energy is ,

\(\longrightarrow PE = mgh \)

where,

Substituting the respective values ,

\(\longrightarrow P.E. = 1200kg * 10m/s^2* 45m\)

Multiply ,

\(\longrightarrow P.E. = 540000J \)

Hence the potential energy is 540000J .

I hope this helps.

Neuron and muscle cells have plasma membranes that undergo voltage changes in response to stimuli.

Neurons are messengers of information.

Between various brain regions and between the brain and the rest of the nervous system, information is transmitted using electrical impulses and chemical signals.

A neuron has a cell body that includes a nucleus and cytoplasm, from which long, thin hair-like structures emerge.

The axon, a solitary long component of the neuron, is responsible for carrying the nerve impulse to various body areas.

The dendrites are the neuron's small, branching body sections.

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Answer:

Answer is in the attached photo.

Explanation:

The solution is in the attached photo, do take note in order to solve this question, we have to use the formula for Kinetic Energy:

K.E = \(\frac{1}{2} mv^{2}\)

The kinetic energy of the penguin with an 8 kg mass and a speed of 3 m/s, is 36 joules.

The formula of kinetic energy is:

Where

What is the kinetic energy of a penguin with a mass of 8 kg that is running at a speed of 3 m/s?

Data:

Ec = ?

m = 8 kg

V = 3 m/s

As in the statement asks us to calculate the energy, we must not perform the formula clearance. We replace data and solve.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{Ec=\frac{m\times v^2}{2} \iff \ Ec=\frac{8 \ kg\times\left(3 \ \dfrac{m}{s}\right) }{2} } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=\frac{8 \ kg\times9 \ \dfrac{m^2}{s^2} }{2} } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=\frac{72 \ kg\times \ \dfrac{m^2}{s^2} }{2} } \end{gathered}$} }\)

We break down the units of m^2 = m * m.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=36 \ kg\times \ \frac{\not{m^2}}{s^2} \to \ m\times m } \end{gathered}$} }\)

We have kg * m/s^2 = Newton.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=36 \ N\times m } \end{gathered}$} }\)

\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ Ec=36 \ Joules} \end{gathered}$} }}\)

The kinetic energy of the penguin with an 8 kg mass and a speed of 3 m/s, is 36 joules.

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Answer:

14.4m

Explanation:

u = 0 i.e it started from rest

acceleration (a) = 3.2m/s2

time taken (t) = 3.0s

Using the second equation of motion:

s = ut + 1/2at2

s = 0(3.0) + 1/2(3.2)(3.0)2

s = 1.6(9.0)

s = 14.4m

hence the distance covered within that time is 14.4m.

Answer:

false its an attraction property

Answer:

True

The attraction is a chemical property.

The deceleration for a car traveling at 55 km/h can be interpolated to be 7.06 m/s².

A) To find whether the car will stop in time or not, we have to use the below formula:Where,

t = time taken to stop

v = initial velocity

u = final velocity

a = deceleration distance = vt + 0.5at²

We can use the above formula and find the distance covered by the car before stopping.

If the distance covered by the car is less than 40 m, then the car will stop in time and the child will be saved. If the distance is greater than or equal to 40 m, then the car will not be able to stop in time and the child will be hit.

For a car traveling at 55 km/h, the speed is 15.28 m/s. The deceleration values for different cars can be found from the table below:Speed (m/s) Braking Distance Toyota Corolla
(m) Nissan 200SX
(m) Mercedes C36
(m) Ferrari550 Maranello
(m) Lexus LS400
(m)60 14.9 17.2 20.1 24.8 16.070 20.3 23.4 27.4 33.8 21.880 26.5 30.6 35.8 44.1 28.490 33.6 38.7 45.3 55.8 36.0100 41.5 47.8 55.9 68.9 44.4110 50.2 57.8 67.7 83.4 53.8120 59.7 68.8 80.5 99.2 64.0

Therefore, Interpolation shows that the deceleration for an automobile moving at 55 km/h is 7.06 m/s2. .

Using the formula for deceleration with initial velocity of 15.28 m/s, we get the distance covered by the car before stopping to be:distance = (15.28)² / 2 * 7.06 = 19.68 m

As the distance covered by the car is less than 40 m, the car will stop in time.

B) The limitations of this model are:This model assumes that the car is traveling on a flat surface and the road conditions are good.

The model does not take into account the reaction time of the driver and assumes that the driver reacts immediately to the child running onto the road.

The model does not take into account the age of the vehicle, the weight of the vehicle, the condition of the brakes and tires, and other factors that may affect the braking distance of the car.

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The density (ρh) of hot air inside the balloon, assuming it is uniform throughout, can be expressed in terms of Th, Tc  and ρc (density of surrounding air) using the ideal gas law as follows: ρh = (ρc * Tc) / Th

The ideal gas law states that for a given amount of gas, the product of its pressure (P) and volume (V) is proportional to the product of its temperature (T) and the number of moles (n). Mathematically, it can be expressed as:

PV = nRT

Where R is the ideal gas constant.

Since we are considering a balloon filled with hot air, the pressure and volume inside the balloon remain constant. Therefore, we can modify the ideal gas law to relate the densities of hot air (ρh) and surrounding air (ρc) to their respective temperatures:

(ρh * V) / Th = (ρc * V) / Tc

Here, V represents the volume of the balloon, which cancels out on both sides of the equation.

Simplifying the equation:

ρh / Th = ρc / Tc

Rearranging the equation to solve for ρh:

ρh = (ρc * Tc) / Th

The density (ρh) of hot air inside the balloon, assuming it is uniform throughout, can be calculated using the ideal gas law. The expression for ρh in terms of Th (temperature of hot air), Tc (temperature of surrounding air), and ρc (density of surrounding air) is given as: ρh = (ρc * Tc) / Th.

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The magnetic field at the surface of the wire is;\(B = \mu_{0} * I / (2 * r)B = 4\pi * 10^{-7} T * m / A * 35 A / (2 * 1.15 * 10^{-3} m)B = 0.000480 T \approx 0.00048 T\)

The magnetic field inside the wire is;

\(B = (\mu_{0} * I / (2 * r)) * (a^2 - r^2) / (2 * a^2)B = (4\pi * 10^{-7} T * m / A * 35 A / (2 * 1.15 * 10^{-3} m)) * (1.65 * 10^{-3} m)^2 / (2 * (1.65 * 10^{-3} m)^2)B = 0.000226 T \approx 0.00023 T\)

The magnetic field inside the wire is;

\(B = (\mu_{0} * I * r^2) / (2 * (r^2 + a^2)^{(3/2)}))B = (4\pi * 10^{-7} T * m / A * 35 A * (1.15 * 10^{-3} m)^2) / (2 * ((1.15 * 10^{-3} m)^2 + (2.5 * 10^{-3} m)^2)^{(3/2)}))B = 5.18 * 10^{-7} T \approx 5.2 * 10^{-7} T\)

The magnetic field at the surface of the wire is 0.00048 T, the magnetic field inside the wire 0.00023 T, and the magnetic field outside the wire is \(5.2 * 10^{-7} T\).

Part A: Magnetic field at the surface of the wire The formula to find the magnetic field at the surface of the wire is given by;

\(B = \mu_{0} * I / (2 * r)\)

Where B is the magnetic field, μ₀ is the magnetic constant, I is the current, and r is the radius of the wire.

\(\mu_{0} = 4\pi * 10^{-7} T * m / A\); the constant value of the magnetic field.

The current I = 35 A The radius of the wire, r = d / 2 = 2.3 mm / 2 = 1.15 mm = \(1.15 * 10^{-3}m\)

Therefore, the magnetic field at the surface of the wire is;

\(B = \mu_{0} * I / (2 * r)B = 4\pi * 10^{-7} T * m / A * 35 A / (2 * 1.15 * 10^{-3} m)B = 0.000480 T \approx 0.00048 T\)

Part B: Magnetic field inside the wire 0.50 mm below the surface

The formula to calculate the magnetic field inside the wire is given by;

\(B = (\mu_{0} * I / (2 * r)) * (a^2 - r^2) / (2 * a^2)\)

Where B is the magnetic field, μ₀ is the magnetic constant, I is the current, r is the radius of the wire, and a is the distance from the center of the wire to the point where we want to calculate the magnetic field.

In this case,\(a = r + 0.50 mm = 1.15 * 10^{-3} m + 0.50 * 10^{-3} m = 1.65 * 10^{-3} m\)

Therefore, the magnetic field inside the wire is;

\(B = (\mu_{0} * I / (2 * r)) * (a^2 - r^2) / (2 * a^2)B = (4\pi * 10^{-7} T * m / A * 35 A / (2 * 1.15 * 10^{-3} m)) * (1.65 * 10^{-3} m)^2 / (2 * (1.65 * 10^{-3} m)^2)B = 0.000226 T \approx 0.00023 T\)

Part C: Magnetic field outside the wire 2.5 mm from the surface

The formula to calculate the magnetic field outside the wire is given by;

\(B = (\mu_{0} * I * r^2) / (2 * (r^2 + a^2)^{(3/2)}))\)

Where B is the magnetic field, μ₀ is the magnetic constant, I is the current, r is the radius of the wire, and a is the distance from the center of the wire to the point where we want to calculate the magnetic field.

In this case,\(a = 2.5 mm = 2.5 * 10^{-3} m\)

Therefore, the magnetic field inside the wire is;

\(B = (\mu_{0} * I * r^2) / (2 * (r^2 + a^2)^{(3/2)}))B = (4\pi * 10^{-7} T * m / A * 35 A * (1.15 * 10^{-3} m)^2) / (2 * ((1.15 * 10^{-3} m)^2 + (2.5 * 10^{-3} m)^2)^{(3/2)}))B = 5.18 * 10^{-7} T \approx 5.2 * 10^{-7} T\)

Therefore, the magnetic field at the surface of the wire is 0.00048 T, the magnetic field inside the wire 0.00023 T, and the magnetic field outside the wire is \(5.2 * 10^{-7} T\).

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Answer:

Below

Explanation:

The friction subtracts from the forward force

F = ma

(5000 - 1250) / 1500 = a    = 2.5 m/s^2

Hamilton's equations can be formulated for a body (mass m) falling in a homogeneous gravitational field by defining the generalized coordinates and momenta.

Let's consider the vertical motion of the body along the y-axis.

Generalized Coordinate:

We can choose the position of the body, y, as the generalized coordinate.

Generalized Momentum:

The momentum conjugate to the position y is the vertical component of the body's momentum, which is given by \(p_y = m * v_y\), where \(v_y\) is the vertical velocity.

The Hamiltonian (H) is the total energy of the system and is given by the sum of kinetic and potential energies:

H = T + V = (p_y^2 / (2m)) + m * g * y,

Hamilton's equations for this system are:

\(dy/dt = (∂H/∂p_y) = p_y / m,\\dp_y/dt = - (∂H/∂y) = -m * g.\)

These equations describe the time evolution of the generalized coordinate y and the generalized momentum p_y.

To solve these equations, we can integrate them. Integrating the first equation gives:

\(y = (p_y / m) * t + y_0,\)

where y_0 is the initial position of the body.

Integrating the second equation gives:

\(p_y = -m * g * t + p_y0,\)

where \(p_y0\) is the initial momentum of the body.

Therefore, the solutions for the position and momentum as functions of time are:

\(y = (p_y0 / m) * t - (1/2) * g * t^2 + y_0,\\p_y = -m * g * t + p_y0.\)

These equations describe the motion of the body falling in a homogeneous gravitational field as a function of time.

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Among the factors mentioned, the factor that does not influence stream velocity is stream elevation. Stream velocity is influenced by a combination of factors, including channel size and shape, discharge of stream, and stream gradient.

The size and shape of the channel impact the flow of water through the stream. A wide and deep channel will allow for higher flow rates than a narrow and shallow channel. Similarly, the discharge of the stream, or the amount of water flowing through the channel, affects the velocity of the stream. The more water flowing through the channel, the faster the velocity. Stream gradient is another factor that affects the velocity of the stream. The gradient refers to the slope or incline of the channel. Steeper gradients lead to faster flow rates, while flatter gradients lead to slower flow rates. Stream elevation, however, does not directly influence stream velocity. While elevation changes can affect the gradient and channel shape, they do not impact the velocity of the stream on their own. In conclusion, stream velocity is influenced by various factors, including channel size and shape, discharge of stream, and stream gradient. Stream elevation, however, does not directly impact the velocity of the stream.

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Answer:

An element's valence electron tells us about its ability to react and not react. More rules to this, but that's the gist of it. it also helps us form bonds

Explanation:

Valence electrons are used by an element for bonding and ionization, contributing to the element's chemical reactivity and behavior.

Valence electrons also play a vital role in ionization, which refers to the process of gaining or losing electrons to form ions. Elements tend to gain or lose electrons in order to achieve a stable electron configuration, typically by acquiring a full valence shell.

Metals, located on the left side of the periodic table, have fewer valence electrons, often one or two, and tend to lose them to form positive ions (cations). This characteristic makes them good conductors of electricity.

Nonmetals, located on the right side of the periodic table, have a nearly full valence shell and tend to gain electrons to achieve a stable configuration, forming negative ions (anions). Nonmetals generally do not conduct electricity as well as metals.

In summary, valence electrons are used by an element for bonding, where they participate in the formation of covalent and ionic bonds, and for ionization, where they are gained or lost to form ions and achieve a stable electron configuration.

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