The net angular momentum about point O is L = 9.51 kg⋅m²/s (magnitude).
What is angular momentum?Angular momentum is a fundamental concept in physics that describes the rotational motion of an object. It is a vector quantity that is defined as the cross product of the position vector and the linear momentum vector of an object with respect to a chosen point or axis. In other words, angular momentum is a measure of how much a rotating object "wants" to keep rotating, and it depends on the mass, speed, and distance of the object from the axis of rotation.
To find the net angular momentum about point O, we need to calculate the angular momentum for each particle and add them together. The direction of the angular momentum is perpendicular to both the position vector and the linear momentum vector, so we can use the right-hand rule to determine the direction.
For particle P₁:
r₁ = 1.4 m (in the radial direction from O)
p₁ = 7.4 kg × 2.2 m/s = 16.28 kg⋅m/s (tangential to the circle)
Using the right-hand rule, we can see that the direction of the angular momentum for particle P₁ is out of the plane of the page (in the +z direction).
For particle P₂:
r₂ = 2.8 m (in the radial direction from O)
p₂ = 3.1 kg × 4.1 m/s = 12.71 kg⋅m/s (tangential to the circle)
Using the right-hand rule, we can see that the direction of the angular momentum for particle P₂ is into the plane of the page (in the -z direction).
Therefore, the net angular momentum about point O is:
L = r₁ × p₁ + r₂ × p₂
L = (1.4 m × 16.28 kg⋅m/s) + (2.8 m × -12.71 kg⋅m/s)
L = 9.51 kg⋅m²/s (magnitude)
(b) The direction of the net angular momentum is perpendicular to the plane formed by the position vectors and the linear momentum vectors. From the calculation above, we can see that the net angular momentum is in the +z direction, which is perpendicular to the xy plane. Therefore, the direction of the net angular momentum is up, out of the plane of the page.
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6.
least 2 m. If the same car is moving with the speed 80K/h,what is the minimum stopping distance?
A car moving with a speed of 40 km/h can be stopped by applying the brakes after at-
The minimum stopping distance of the car is determined as 8 m.
What is the minimum stopping distance?The minimum stopping distance of the car is calculated as follows;
d = (u²)/(2a)
where;
d is the minimum stopping distanceu is the initial velocitya is the acceleration of the carwhen the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s
2 = (11.11²)/(2a)
a = (11.11²)/(2 x 2)
a = 30.86 m/s²
when the speed becomes 80 km/h, the minimum stopping distance is calculated as;
u = 80 km/h = 22.22 m/s
d = (22.22² )/ (2 x 30.86)
d = 8 m
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What is the mass of an object that requires a force of 182 N to accelerate at a rate of 13 m/s?
Answer:
\(m=14kg\)
Explanation:
Hello.
In this case, since the force is defined in terms of the mass and acceleration by:
\(F=m*a\)
We can easily compute the mass by solving for it:
\(m=\frac{F}{a}\)
Whereas the force is 182 N (kg*m/s²) and the acceleration is 13 m/s², therefore, we obtain:
\(m=\frac{182kg\frac{m}{s^2} }{13\frac{m}{s^2}}\\\\m=14kg\)
Best regards.
A 2800 kg speedboat starting from rest attains a speed of 16 m/s in 8.0 s as a combination of 1200 N of air resistance and water drag act on the boat. How much power is being expended by speedboat at the maximum speed?
Answer:
For me
Explanation:
power=workdone/time
power= 128×1200/8
power=19200
a.
13. A planet orbiting the sun
Newton's 1st Law
b. Newton's 2nd Law
c. Newton's 3rd Law
Newtons first law of motion.
A 200 kg motorcycle initially moving at 20 m/s applies its brakes. How
much work was done to stop the motorcycle?
Answer:
-40,000 J
Explanation:
Initial kinetic energy E1 = mv^2/2 = 200*20^2/2 = 40,000 J
Final kinetic energy E2 = 0
Work done = E2 - E1 = -40,000 J
Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed
Answer: The scenario violates the second law of thermodynamics.
Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.
1. Explain how sublimation works.
2. Explain how evaporation works.
3. Explain how the melting point works.
1.) In sublimation, solid changes to gas
2.) In evaporation, liquid changes to gas
3.) In melting point, solid changes to liquid.
What is phase change of matter?Phase change of matter is the ability of the various forms of matter, such as solid, liquid and gas, to change from one form to another without the destruction of the substance.
There are various ways a substance can change between these three forms and they include the following:
Sublimation: This is the phase change of matter that involves the direct change of a solid substance into a gaseous state.Evaporation: This is the phase change of matter that involves the direct change is liquid substance into gaseous state.Melting point: This is the phase change that occurs at a particular point when the solid substance dissolves to form liquid.Learn more about matter here:
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How have astronomers used models to explain galactic evolution through mergers and collisions? Use this model to explain how astronomers might test their understanding of the physical processes of the universe.
Answer:
Astronomers use computer models to simulate the process of galactic evolution through mergers and collisions. These models are based on our current understanding of the physical laws that govern the behavior of matter and energy in the universe. By running simulations of galactic mergers and collisions, astronomers can test their understanding of how these physical processes work in practice and how they contribute to the formation and evolution of galaxies.
One way that astronomers might test their understanding of the physical processes of the universe is by comparing the predictions of their models to observations of real galaxies. For example, if a model predicts that a particular type of galaxy should have a certain shape, size, or distribution of stars, astronomers can compare these predictions to observations of actual galaxies to see if they match up. If there is a discrepancy between the model's predictions and the observations, this can indicate that there are some physical processes that are not well understood or included in the model.
Another way that astronomers might test their understanding is by looking for patterns or trends in the properties of galaxies that are consistent with the predictions of their models. For example, if a model predicts that galaxies that have undergone a recent merger should have a particular distribution of gas and dust, astronomers can look for evidence of this pattern in observations of real galaxies. If they find that the predicted pattern is consistently observed in a large sample of galaxies, this can provide support for the model's predictions and the physical processes that it includes.
Overall, computer models of galactic evolution through mergers and collisions provide a powerful tool for astronomers to test their understanding of the physical processes of the universe. By comparing the predictions of their models to observations of real galaxies and looking for consistent patterns and trends, astronomers can refine their understanding of how galaxies form and evolve over time.
Microwaves travel at the speed of light 3.00x108 m/s. When the frequency of microwaves is 9.00x109Hz, what is their wavelength?
The wavelength of microwaves with a frequency of 9.00x10^9 Hz is approximately 0.0333 meters or 33.3 millimeters.
What is the speed of microwaves and what is their frequency?Microwaves are a type of electromagnetic radiation with a frequency range of around 300 MHz to 300 GHz. They are used for various applications, including communication, cooking, and medical imaging.
The speed of microwaves is the same as the speed of light, which is approximately 3.00x10^8 m/s. This means that microwaves travel at a very high speed and can cover long distances in a short amount of time.
How does the wavelength of microwaves change with their frequency?The wavelength of microwaves is inversely proportional to their frequency. This means that as the frequency of microwaves increases, their wavelength decreases.
In other words, higher frequency microwaves have shorter wavelengths, and vice versa. For example, the wavelength of microwaves with a frequency of 9.00x10^9 Hz is approximately 0.0333 meters or 33.3 millimeters.
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If you drive first at 40 km/h west and later at 60 km/h west, your average velocity is 50 km/h west.
and what else? is that all?
An airplane, starting at rest, takes off on a 600. m long runway accelerating at a rate of 12 m/s/s. How many seconds does it take to reach the end of the runway?
Answer:
10 seconds
Explanation:
As it starts from rest, then u=0
and by III rd equation of motion:
CAN SOMEONE PLS HELP ME!
In a loading a lorry a man lifts boxes each weight 200N through a height of 3.5m.
a). How much work does he do in lifting one box?
b). How much energy is transferred when one box is lifted?
c). If he lifts four boxes per minute at what power is he working?
The work done on the boxes and the energy spent is 700J while the power required to lift 4 boxes per minute is 2.8kW
This work done on an object is the force required to move that object from point A to point B.
Data Given;
Weight (mg) = 200NDistance (s) = 3.5mWork DoneThis is the work done to move the boxes from point A to point B.
\(w = F.s\\F = ma = mg = 200N\\w = 200 * 3.5\\w = 700J\)
The work done to move the object is 700J
EnergyThis is used to calculated the energy used to carry the work done and the formula is given as
\(E = force * displacement\\E = F.s\\E = 200 * 3.5\\E = 700J\)
The energy transferred when he lifts one box is 700J
PowerPower is the rate at which energy is used with respect to time
\(P = E/t\\\)
The energy required to lift 4 boxes in one minutes is
\(700 * 4 = 2800\)
Now we can calculate the power used
\(P = Energy / time\\P = 2800 / 1 \\P = 2800W = 2.8kW\)
The power required to move four boxes in 1 minutes is 2.8kW
From the calculations above, the following was gotten
work done = 700JEnergy = 700JPower = 2800W or 2.8kWLearn more on work done, energy and power here;
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a stone dropps 7,11m how long will it take it to fall
The time it takes the stone to fall from a height of 7.11 m is 1.2 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the stone to drop from an height of 7.11 m, we use the formula below.
Formula:
H = ut+gt²/2............ Equation 1Where:
H = Heightu = Initial velocityt = Timeg = Acceleration due to gravityFrom the question,
Given:
u = 0 m/sH = 7.11 mg = 9.8 m/s²Substitute these values into equation 1 and solve for t.
7.11 = (0×t)+9.8×t²/27.11 = 4.9t²t² = 7.11/4.9t² = 1.451t = √1.451t = 1.2 secondsHence, the time it takes the stone to fall is 1.2 seconds.
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An object of 20 kg accelerates at 10 m/s/s into a wall. What amount of force did it hit the wall?
The amount of force that hit the wall is 200N.
What is force?Force is a physical quantity that denotes ability to push, pull, twist or accelerate a body and which has a direction.
The force can be calculated by multiplying the mass by the acceleration as follows:
Force = mass × acceleration
According to this question, an object of 20kg accelerates at 10 m/s² into a wall. The force applied is as follows:
Force = 20kg × 10m/s² = 200N
Therefore, 200N is the force applied by the object on the wall.
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Electrons orbit the nucleus. They have a very ___ mass and do not contribute to atomic mass
Answer:
Electrons orbit the nucleus. They have a very small mass and do not contribute to atomic mass
What do all waves transfer?
Question 1 options:
matter
energy
particles
water
Answer:
Matter
Explanation:
A wave is a disturbance that transfers energy from one place to another without transferring matter. Waves transfer energy away from the source, or starting place, of the energy.
Answer:
energy
Explanation:
I took the test think of hydropower dams
The velocity of the water jet discharging from the orifice can be obtained from v=\12ih, where h = 2 m is the depth of the orifice from the water surface. Determine the time for a particle of water leaving the orifice to reach point B and the horizontal distance x where it hits from surface.
(a) The time for a particle of water leaving the orifice to reach point B is 0.63 s.
(b) The horizontal distance x where it hits from surface is 3.94 m.
Time for the water to reach the surface
The time of the water to reach the surface is calculated as follows;
h = ¹/₂gt²
2h = gt²
t² = 2h/g
t = √(2h/g)
where;
t is time of motionh is height of the orificet = √( (2 x 2)/(9.8) )
t = 0.63 s
Horizontal distanceThe horizontal distance is calculated as follows;
X = vt
where;
v is the velocity of the water = √2ghX = (√2gh)t
X = (√2 x 9.8 x 2) x 0.63
X = 3.94 m
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Each of the different colors that make up white light has a different ___________________.
Answer:
Wavelength?
Explanation:
If the universe were to suddenly begin shrinking rather than continue expanding, how would it affect the cosmic microwave background radiation?
A. It would decrease in temperature.
B. It would blue-shift.
C. It would red-shift.
D. It would increase in temperature.
If the universe were to suddenly begin shrinking rather than continuing to expand, it would have a significant effect on the cosmic microwave background radiation (CMB).
The CMB is the afterglow of the Big Bang and is observed as a nearly uniform background radiation in all directions. It is thought to have been emitted when the universe was about 380,000 years old and had cooled enough for neutral atoms to form.
If the universe were to suddenly begin shrinking, the photons in the CMB would lose energy as they travel through the contracting space. This would cause the CMB radiation to shift to shorter wavelengths, which is known as blue-shifting.
Therefore, the correct answer is B. It would blue-shift.
A monarchy is the type of government that the colonist do not want true or false
Answer:
Monarchy is rule from kings and queens
Explanation:
no i dont have one soory
Answer:
u dont have a question
Explanation:
?? bc i would gladly help u
The graph shows the velocity
of a T-Rex as a function
of time. The velocity
of the T-Rex between 2 and 4
seconds shown is
about...
The correct option is C, the velocity between 2s and 4s is 7 meters per second.
What is the velocity of the T-Rex between 2 and 4 seconds?Here we have the graph of the velocity of a T-Rex as function of time in seconds.
Here we need to find the average value between 2 seconds and 4 seconds.
At 2 seconds, the graph says that the velocity is 7m/s
And we can see an horizontal line that ends at 4s, so the veloicty at 4 seconds is 7m/s
Then the average velocity in that interval is that one (because it is constant)
Then the correct option is C.
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Describe sound and record
Answer:
record is information created, received and maintained as evidence and information by an organization or person.in simpler terms it's a collection of of fields probably of different data types.
sound is however something loud or soft.which can be defined as vibrations that travel through the air or another medium.
I hope this helps
Find distance between two object of radius 6 cm and 2 cm
The distance between two objects of radius 6 cm and 2 cm is zero
To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.
Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.
The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.
Substituting the values, we have d = 6 cm + 2 cm = 8 cm.
Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:
Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.
The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.
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How much work, in kilojoules, went into thermal energy produced by friction?
The question is incomplete. Here is the complete question.
Suppose the mass of a loaded elevator is 1600 kg.
(a) What force, in Newtons, must be supplied by the elveator's cable to produce an acceleration of 0.745 m/s² upwards against a 185N frictional force?
(b) How much work, in joules, is done by the cable in lifting the elevator 21m?
(c) What is the final speed, in meters per second, of the elevator if it starts from rest?
(d) How much work, in kilojoules, went into thermal energy produced by friction?
Answer: (a) F = 1377 N
(b) W = 28917 J
(c) v = 5.6 m/s
(d) W = 3.885 kJ
Explanation:
(a) According to Newton's Second Law: \(F_{net}=m.a\), in which, \(F_{net}\) is the vetorial sum of all the forces in a system and its unit is [F] = kg.m/s² or newton (N).
In the elevator's case, and assuming going upwards is positive:
\(F-F_{f}=m.a\)
F - 185 = 1600(0.745)
F = 1377 N
For an elevator to produce an acceleration of 0.745m/s² upwards, the cables have to supply a force of 1377 newtons.
(b) Work is the energy transferred to an object while is being moved. It is calculated as: W = F.s. Its unit is [W] = N.m or Joule (J)
In the elevator's cable:
W = 1377.21
W = 28917 J
The work done by the elevator's cable is W = 28917 joules.
(c) Acceleration is variation in velocity along time. Since we know the displacement of the elevator:
\(v^{2}=v_{0}^{2}+2a\Delta x\)
where:
v₀ is initial velocity, which is this case v₀=0 because it starts from rest;
a is acceleration;
Δx is the displacement
Replacing values:
\(v^{2}=2(0.745)(21)\)
\(v=\sqrt{31.29}\)
v = 5.6 m/s
Final speed of the elevator is 5.6 m/s.
(d) \(W=F_{f}.s\)
W = 185(21)
W = 3885 J
Work transferred into thermal energy because of friction is W = 3.885 kJ.
Two particles with charges Q=16 microC and -Q=-16 microC are fixed at the vertices of an equilateral triangle with sides of length a = 8 micrometers. The work required to move a particle with a charge q=19 microC from the other vertex to the centre of the line joining the fixed charges is ...J
The work required to move the particle with a charge of q = 19 microC from the other vertex to the center of the line joining the fixed charges is approximately -2.03 * 10^-14 J.
What is the work required?The work required to move a charge from one point to another in an electric field is given by the equation W = qV, where q is the charge and V is the potential difference.
In this case, the potential at the center of the line joining the two fixed charges can be calculated using Coulomb's law. The potential difference between the center and the third vertex can then be calculated, giving us the work required to move the particle with a charge q = 19 microC.
W = qV = 19 * 10^-6 C * V
Where V is the potential difference, which can be calculated as follows:
V = (1/(4 * pi * epsilon_0)) * ((Q / a) - (q / a))
Where epsilon_0 is the vacuum permittivity and a is the length of the sides of the equilateral triangle.
Substituting the values, we get:
W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * ((16 * 10^-6 C / 8 * 10^-6 m) - (19 * 10^-6 C / 8 * 10^-6 m))
W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * (-3 * 10^-6 C / 8 * 10^-6 m)
W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * (-3 * 10^-6 / 8) J
W = -2.03 * 10^-14 J
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A ball is projected at an angle of 53°. If the initial velocity is 48 meters/second, what is the vertical component of the velocity with which it was launched?
A.) 31 meters/second
B.) 38 meters/second
C.) 44 meters/second
D.) 55 meters/second
Answer:
The vertical component of the velocity can be found using the formula:
V₀y = V₀ * sin(θ)
where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.
Substituting the given values, we have:
V₀y = 48 * sin(53°)
Using a calculator, we can evaluate sin(53°) to be approximately 0.799:
V₀y = 48 * 0.799
V₀y ≈ 38.352
Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.
Answer:
B.) 38 meters/second
Explanation:
Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?
Question 12 options:
Put it in the fridge where it is cold
Cover it with a blanket so it's dark
Warm it up on the stove
There is nothing you can do to change the speed of the reaction
In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.
Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct
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A rod 16.0 cm long is uniformly charged and has a total charge of -25.0 µC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 42.0 cm from its center.
Answer:
-1.4x10^6N/C
Explanation:
Pls see attached file
The magnitude of the electric field.
Magnitude is the size of the object in properties that is determines the size of the object. It also displays the result of the order of class of the object. The direction of the electric field tells us about the position of the field in four different directions. As per the question, the answer is 1.4x10^6N/C.
The rod of 16cm of total length is given. Has a charge of a total of -25.0uc. The rod's axis is pointed at 42.0 cm from its center and is given in the question. The rod Length will be then 0.16m and the total change will be 25x10 cm and point where the electricity will be calculated is shown by the axis of the rod at the distance of 42 cms.The magnitude and direction will be calculated based on the measure of the formula of E. This answer to the question will be 1.4x10^6N/C.Learn more about the uniformly charged.
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