at noon, ship a is 170 km west of ship b. ship a is sailing east at 40 km/h and ship b is sailing north at 25 km/h. how fast is the distance between the ships changing at 4:00 pm?

Total Cost is =  $107,380 if The farm is 340 acres and had corn planted  add fertilizer to the soil before you plant this years' crop.

A fertiliser is a natural or artificial substance containing chemical elements (such as Nitrogen (N), Phosphorus (P) and Potassium (K)) that improve growth and productiveness of plants. Some synonyms include the terms "enrichment" or "plant nutrient".

Without fertilizers, nature struggles to replenish the nutrients in the soil. When crops are harvested, important nutrients are removed from the soil, because they follow the crop and end up at the dinner table. If the soil is not replenished with nutrients through fertilizing, crop yields will deteriorate over time.

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Answer:

That depends on your average speed and the number of stops you make. However, assuming you could average 55 miles per hour for the entire distance, your total driving time would be about 3 hours and 45 minutes.

Answer:

srarch from website please

We will have the following:

From the graph and the direction of the focus of the electric field assuming it is a negative electric field will be:

*Net torque: Clockwise.

*Net force: Zero.

The given statement about “An electric dipole consisting of charges of magnitude” is true because the electric dipole moment is a vector quantity that has a specific magnitude and direction.

A pair of equal and opposing charges that are separated by a very small distance form an electric dipole. Both of the charges that make up an electric dipole will have the same magnitude; we cannot contemplate a set of two charges that have different magnitudes because of the nature of the electric dipole. The definition of the dipole moment is given as the product of the magnitude of the charges and the distance that separates them from one another. The magnitude of the electric field that is produced by an electric dipole is directly proportional to its dipole moment.

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if the mass of ball is 'm' then force of friction is f=m*a [where a=deceleration ]

=6m

Answer:6m

Explanation:

if the mass of the volleyball is m the force of friction f=m*a

Answer:

375J

Explanation:

W=F x d

=250 x 15

=375J

The work W is equal to the force f times the distance d, or W = fd, to mathematically describe this idea. If the force is applied at an angle to the displacement, the work is W = fd cos.

Work in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, For a constant force that is oriented in the same direction as the motion, it is easiest expressed as the product of the force's magnitude and the distance travelled.

A desk is being subjected to applied force if someone is pushing it across the room. The person's force applied to the desk is known as the applied force.

Mass and weight are not the same.The normal force is the supporting force exerted on an object when it collides with another stable object.

Therefore, W=F × d =250 × 15 =375J

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Answer:

0.055 * 5.1 = 0.2805

Explanation:

I used a calculator so it should be accurate! yw!! :D

Alban Geissler, who developed the SKYRAY carbon fiber wing with Christoph Aarns, suggested after Baumgartner's jump that the wing he used was a copy of two prototype SKYRAY wings sold to Red Bull (Baumgartner's sponsor) two years earlier. - wiki

Answer:

A. 10

Explanation:

it increases by 10 each level

mark brainliest

Answer:

w = 0.01 t⁻²   rad/h

Explanation:

Let's use trigonometry to find the elevation angle of the telescope, we assume that the rocket remains fixed in the telescope.

        tan θ = CO / CA

the adjacent leg is CA = 16 km = 16 10³ m

Let's use kinematics to find the height of the rocket

          v = y / t

          y = v t

this height is equal to the opposite leg

          CO = v t

we substitute

         tan θ = vt / 16

         tan θ = 1200/16 t

         tan θ = 75 t

         θ = tan⁻¹ ( 75 t )

speed is defined by

          w = dθ/dt

          w = \(\frac{1}{1 + (75 t)^2} \ 75\)  

as time increases we can neglect the 1 of the denominator

          w = 1/75 t²

          w = 0.0133 t⁻²

Using three significant figures

           w = 0.01 t⁻²   rad/h

for this answer the time must be given in hours

Considering the depth and the speed, it would take approximately 2.5 to 3 hours to get to the Titanic from the surface.

The time it takes to get to the Titanic from the surface depends on various factors, such as the depth of the Titanic wreck and the speed of the vessel you are using to reach it. The Titanic is located approximately 12,500 feet (3,800 meters) below the surface of the ocean.

Assuming you are using a submarine or a deep-sea diving vessel, it typically takes around 2.5 to 3 hours to reach a depth of 12,500 feet. This is because these vessels generally have a cruising speed of about 4 to 5 knots (4.6 to 5.8 miles per hour).

Therefore, considering the depth and the speed, it would take approximately 2.5 to 3 hours to get to the Titanic from the surface.

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The electric field lines between two positively charged small spheres placed a short distance from each other will originate from each sphere's surface, repel away from each other, and bend around the spheres, showing the repulsive force between the positive charges.

To sketch the electric field lines between two positively charged small spheres placed a short distance from each other follow the steps below:

Step 1: Draw two small circles, representing the positively charged spheres, placed a short distance apart from each other.

Step 2: Since both spheres are positively charged, the electric field lines will originate from each sphere and repel away from each other.

Step 3: Draw electric field lines starting from each sphere's surface and pointing outward. These lines should curve away from each other as they show repulsion between the positive charges.

Step 4: In the region between the two spheres, the electric field lines will bend outward from one sphere, towards the other sphere, and continue to curve away from the second sphere. These lines illustrate the repulsive force between the two positive charges.

Step 5: Finally, draw some electric field lines that start from one sphere and curve around the outer side of the other sphere, demonstrating the repulsion between the two positively charged spheres.

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Person-1

\(\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{10-0}{10}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{10}{10}\)

\(\\ \sf\longmapsto Acceleration=1m/s^2\)

Person-2

\(\\ \sf\longmapsto Acceleration=\dfrac{0.25-0}{2}\)

\(\\ \sf\longmapsto Acceleration=\dfrac{0.25}{2}\)

\(\\ \sf\longmapsto Acceleration=0.125m/s^2\)

Person-1 is accelerating faster.

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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The main answer for expressing the function n3/1000 − 100n2 − 100n + 3 in terms of Θ-notation is Θ(n3).

To find the Θ-notation of the given function, we need to determine the highest degree term in the polynomial expression. In this case, the highest degree term is n3/1000.

Since the constant factor (1/1000) does not affect the order of growth, we can simplify the expression to n3.

Therefore, the function is Θ(n3).

Considering the dominant term in the given function, we can express it in Θ-notation as Θ(n^3).

Summary: The function n3/1000 − 100n2 − 100n + 3 can be expressed in terms of Θ-notation as Θ(n3), which represents the order of growth of the function as n cubed.

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The ability to see the world in three dimensions is called depth perception. It is the visual ability to perceive the relative distance of objects in space and to see them in three dimensions.

Depth perception is an important aspect of vision that allows us to accurately judge distances, perceive spatial relationships, and interact with our environment.

It is the result of the brain processing information from both eyes to create a single, three-dimensional image.

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His gravitational potential energy when he is halfway to the water is 100 joules.

Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.

The gravitational potential energy of an item, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are examples of potential energy.

Initial potential energy of John is 200 joules.

Hence, his gravitational potential energy when he is halfway to the water is = (200/2) joules = 100 joules.

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The correct answer is Option(C). The proper time between two events is measured by clocks at rest in a reference frame in which the two events are separated by the distance a light signal can travel during the time interval.

The concept of proper time is a fundamental concept in special relativity. It refers to the time interval measured by an observer who is at rest relative to the events being measured. According to special relativity, the passage of time can be affected by relative motion and gravitational fields.

The proper time between two events is independent of the reference frame from which it is measured. It is a fundamental property of the events themselves. In order to measure the proper time between two events, one must use clocks that are at rest relative to the events being measured.

Option (C)  states that the two events are separated by the distance a light signal can travel during the time interval. This is the correct choice because the speed of light is a fundamental constant in special relativity and is the maximum speed at which information can propagate. Using the distance traveled by light during a time interval ensures that the measurement of proper time is consistent with the principles of special relativity.

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--The question is incomplete, the complete question is:

"The proper time between two events is measured by clocks at rest in a reference frame in which the two events:  (A). occur at the same time  (B). occur at the same coordinates  (C). are separated by the distance a light signal can travel during the time interval  (D). occur in Boston  E. satisfy none of the above"--

Answer:

The rotation of the earth on its tilted axis is the reason behind the difference in the length of the day and night time in different parts of the earth throughout the year. The annual motion of the Earth is called revolution. Since the path of the Earth is elliptical, the interval between the Earth and the Sun keeps shifting.

Explanation:

By solving the given equation on [² f(u)du = t_ -L₁ €² 2 f(u)du is obtained, we can find t.= J 1+e²t / 1 + e2t / 1-e²tdt. Now, we need to solve the integral,∫ 1+e²t / (1 + e2t)(1-e²t) dt.

For this integral, let u = 1+ e²tSo, du/dt = 2e²And, dt = du/2e²= 1/2e² ∫1+e²t / (u)(1-e²t) du= 1/2e² ∫ (1/u) - (e²/(1-e²t)) du= 1/2e² [ln|u| - ln|1-e²t|] + c.

Now, substituting back the value of u,= 1/2e² [ln|1+ e²t| - ln|1-e²t|] + c= 1/2e² ln|1+ e²t / 1-e²t| + c.

Now, putting the limits in the above expression and solving it, we get the value of t.= [1/2e² ln|1+ e²t / 1-e²t|] t = 1 2t / [1 + e²t] - L₁ 2t / [1-e²t].

Hence, the answer is D) f(t)= 2t / [1 + e²t] - L₁ 2t / [1-e²t].

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Answer:

See below

Explanation:

KE = 1/2 m v ^2

    = 1/2 (250/1000) 300^2   j         the bullet is 250/1000  kg  ( assuming g is grams and not GRAINS - in which bullet weight is usually measured)

force to stop it is the same number

PE = mgh = .5 *9.81  *  .75 =

     doubling height will double PE

2 x 10^6  =  40 * 9.81  *  h      sove for 'h' in meters  

Initial kinetic energy is 11250 J and magnitude of force to stop bullet is 75 N.

The GPE for 0.75m height floor is 3.75J.

The GPE for double of 0.75m height is 7.5J.

The high on which 40 kg mass is lifted is 5000m.

The kinetic energy of an object is the energy that it possesses due to its motion.

\(KE = 1/2 m v ^2\)

      \(=1/2 (250/1000) 300^2 J\\= 11250 J\)

Work done,

\(W= fs\\\\f=\frac{W}{s}\\\\f=\frac{11250}{150}\)

\(f=75 N\)

Gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity.

PE = mgh

    = .5 *9.81  *  .75

    = 3.75 J

Potential energy when height doubles = 7.5J

The potential energy is given by

\(PE = mgh\\\\h = PE/ mg\\\\h = 2*10^6 J /40*9.8\\\\h = 5000 m\)

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For the designing of differential amplifier following were found out :

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

To design the differential amplifier according to the given specifications, we will follow these steps:

Step 1: Calculate the small-signal gain (Av)

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Step 4: Calculate the tail current (Itail) based on the specified Iss

Step 5: Determine the resistance (R) value

Step 6: Calculate the width (Wp) of the PMOS transistor

Step 7: Calculate the width (Wn) of the NMOS transistors

Now let's go through each step in detail.

Step 1: Calculate the small-signal gain (Av)

Given: Av = 10, VOP = VON = 3.5V

Av = (vop - von) / (vip - vin)

10 = (3.5 - 3.5) / (0.1)

10 = 0 / 0.1

Since the numerator is zero, the small-signal gain is zero.

Step 2: Determine the transconductance (gm) and output resistance (ro) of the NMOS transistors

Given: unCox = 400 μA/V², Vtn = 0.8V, n = 0.02 V^(-1), L = 0.2 μm

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

ro = 1 / (lambda * unCox * (W/L))

We need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vgs = Vin - Vbias) should be zero to operate the transistors in the saturation region.

For the NMOS transistors:

Vgs = 0 (since Vin = Vbias)

gm = 2 * unCox * (W/L) * (Vgs - Vtn)

  = 2 * 400 μA/V² * (W/L) * (0 - 0.8)

  = -640 * (W/L) μA/V

ro = 1 / (lambda * unCox * (W/L))

  = 1 / (0.02 V^(-1) * 400 μA/V² * (W/L))

  = 1 / (8 * (W/L)) kΩ

Step 3: Determine the transconductance (gm) and output resistance (ro) of the PMOS transistors

Given: upCox = 200 μA/V², Vtp = -0.8V, p = 0.04 V^(-1), L = 0.2 μm

Similarly, for the PMOS transistors, we need to design the amplifier for DC operation (Vin = Vbias), where the differential voltage (vsg = Vbias - Vin) should be zero to operate the transistors in the saturation region.

For the PMOS transistors:

Vsg = 0 (since Vin = Vbias)

gm = 2 * upCox * (W/L) * (Vtp - Vsg)

  = 2 * 200 μA/V² * (W/L) * (-0.8 - 0)

  = -320 * (W/L) μA/V

ro = 1 / (lambda * upCox * (W/L))

  = 1 / (0.04 V^(-1) * 200 μA/V² *

  = 1 / (5 * (W/L)) kΩ

Step 4: Calculate the tail current (Itail) based on the specified Iss

Given: Iss = 2 mA

Itail = Iss / 2

= 2 mA / 2

= 1 mA

Step 5: Determine the resistance (R) value

Given: Vs = 0.3 V, VDD = 5 V

We can calculate the resistance (R) value using Ohm's Law:

Vs = Itail * R

0.3 V = 1 mA * R

R = 0.3 kΩ

Step 6: Calculate the width (Wp) of the PMOS transistor

To calculate Wp, we'll use the equation for the tail current:

Itail = 2 * upCox * (Wp/L) * (VDD - Vtp)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5 V + 0.8 V)^2

1 mA = 2 * 200 μA/V² * (Wp/0.2 μm) * (5.8 V)^2

Solving for Wp:

Wp = (1 mA * 0.2 μm) / (2 * 200 μA/V² * (5.8 V)^2)

Wp = 0.01 μm / (2 * 200 μA/V² * 33.64 V^2)

Wp ≈ 0.0075 μm

Step 7: Calculate the width (Wn) of the NMOS transistors

Given: Wn = 4 * Wp

Wn = 4 * 0.0075 μm

Wn = 0.03 μm

So, the design parameters for the differential amplifier are as follows:

the small-signal gain is zero.

the transconductance (gm) and output resistance (ro) of the NMOS transistors are  -640 * (W/L) μA/V and 1 / (8 * (W/L)) kΩ respectively.

the transconductance (gm) and output resistance (ro) of the PMOS transistors are -320 * (W/L) μA/V and  respectively.

NMOS transistor: Wn = 0.03 μm, L = 0.2 μm

PMOS transistor: Wp = 0.0075 μm, L = 0.2 μm

Bias current: Itail = 1 mA

Resistance: R = 0.3 kΩ

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The exponential form of the given number is (-7)⁴. 6⁵.

Exponent is the term used to describe a way to represent huge numbers using powers. In other words, the exponent describes how many times a number has been multiplied by itself.

A number that appears as a superscript over another number is the exponent. In other words, it means that the base has been elevated to a particular level of power. Other names for the exponent are index and power. mn indicates that m has been multiplied by itself n times if m is a positive number and n is its exponent which can be said as the m raised to n.

The given numbers are,

(-7) . (-7) . (-7) . (-7) . 6. 6 . 6 . 6 . 6

So, 7 is multiplied by itself 4 times and 6 is multiplied by itself 5 times.

Therefore, it can be written in the exponential form as,

(-7)⁴. 6⁵

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Answer:

A. 30 yards

Explanation:

40 yards - 10 yards = 30 yards

So he displaced 30 yards. Since no directions are given, I'm guessing that it can be assumed he displaced in a positive direction and not negative. So just 30 yards.

Answer:

d

Explanation:

40 divided by 10 give u 4

Answer:

E = 120.77 J

Explanation:

Given that,

Mass of a baseball, m = 0.143 kg

Velocity of a baseball, v = 41.1 m/s

We need to find the kinetic energy of the baseball. We know that the kinetic energy of an object is associated with its motion. It can be given by the formula as follow :

\(E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 0.143\ kg\times (41.1\ m/s)^2\\E=120.77\ J\)

So, the kinetic energy of the baseball is 120.77 J.

The kinetic energy of the baseball is 120.8 J.

The kinetic energy of an object is associated with its motion. It can be related to the mass and velocity as

K.E = 1/2 mv²

Given is the Mass of a baseball, m = 0.143 kg and Velocity of a baseball, v = 41.1 m/s

substitute the values, we have

K.E = 1/2 x 0.143 x (41.1)²

K.E =  120.77 J

Hence, the kinetic energy of the baseball is 120.8 J.

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The situation described, where a school bus travels at 35 mph and slows down as it approaches a red light, is an example of deceleration or negative acceleration.

Acceleration refers to any change in velocity, which includes both increasing and decreasing speed. In this case, the bus is initially traveling at a constant speed of 35 mph, indicating zero acceleration. However, as it approaches the red light, the bus slows down, which means its velocity decreases. This change in velocity is known as deceleration or negative acceleration. The bus is slowing down to eventually come to a stop at the red light. A school bus is a type of vehicle specifically designed for transporting students to and from educational institutions. It is typically larger than a regular passenger car and is equipped with safety features to ensure the well-being of the students.

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Answer:

1) 10 m/s  2) 14.1 m/s  3) 6.7 m  4) 11.25 m  5) 4.5 m/s  6) 12 joules

Explanation: