At its initial temperature, the bar is too long by a distance of to fit into the gap between the rigid walls, which are separated by a distance. In order to make it fit tightly, the bar is cooled to a very low temperature so that it shrinks enough to fit easily into the gap. After it is fit in the gap, the temperature of the bar is raised to a temperature below the initial temperature and the bar fits tight between the walls.


Required:

What is the stress σ in the bar at this temperature ΔT?

Answer:

First we determine the tensile strength using the equation;

Tₓ (MPa) = 3.45 × HB

{ Tₓ is tensile strength, HB is Brinell hardness = 225 }

therefore

Tₓ = 3.45 × 225

Tₓ = 775 Mpa

From Conclusions, It is stated that in order to achieve a tensile strength of 775 MPa for a steel, the percentage of the cold work should be 10

When the percentage of cold work for steel is up to 10,the ductility is 16% EL.

And 16% EL is greater than 12% EL

Therefore, it is possible to cold work steel to a given minimum Brinell hardness of 225 and at the same time a ductility of at least 12% EL

The area of the gutter is therefore equal to the area of the rectangle plus the area of the triangles.

A = rectangle + 2 * triangle

= 10h + 2 * (1/2 hw)

Using trig work out h and w.

h = 10 sin ?

w = 10 cos ?

A = 10h + hw

= 100sin? + 100sin?cos?

Differentiate the expression (either use the product rule for sin? cos?, or write 100sin?cos? as 50sin2? using the double angle formula)

A = 100sin? + 50sin2?

dA/dt = 100cos? + 100cos2?

For A to be a max or min the derivative must equal zero

100cos? + 100cos2? = 0

cos? + cos2? = 0

Use the double angle formula to write cos2? as 2cos^2 ? - 1

cos? + 2cos^2 ? - 1 = 0

2cos^2 ? + cos? - 1 = 0

This quadratic factorizes:

(2cos? - 1)(cos? + 1) = 0

This means that

cos ? = 1/2 or cos ? = 1

giving:

? = pi/3 or ? = pi

Which means that to achieve the maximum area ? should be pi/3 = 60 degrees

You can check that this is the max by substituting in these values of theta and the two end points (theta = 0, theta = pi), and seeing that pi/3 gives the maximum.

The maximum area is therefore

A = 100sin? + 100sin?cos?

= 100sin(pi/3) + 100sin(pi/3)cos(pi/3)

= 100 sqrt(3) / 2 + 100 sqrt(3)/2 * 1/2

= 100 * 3/2 * sqrt(3) / 2

= 3 * 25 * sqrt(3)

= 75 sqrt(3)

= 129.9...

= 130 cm^3

You can learn more about this through link below:

https://brainly.com/question/20355154#SPJ4

Answer:

Volcanic outgassing

The burning of fossil fuels (coal, oil, gasoline, natural gas), for heating, power generation and transport

Some industrial processes such as cement making.

Explanation:

Answer:

Explanation:

Brake systems are most likely to fail at the ends.  One of the most common problems is a trailer lighting splitter is left on. With time and usage, the fuse can blow interrupting the signal path from the switch to the bulb.

Answered by the ONE & ONLY #QUEEN aka #DRIPPQUEENMO

HOPE THIS HELPED!!!

If two currents are in the same direction at any instant of time in a given branch of a circuit, the net current at that instant will be the sum of the two individual currents. In other words, the net current is the algebraic sum of the two currents.

For example, if one current is 2 amperes and the other current is 3 amperes, and they are flowing in the same direction in a given branch of the circuit, then the net current at that instant will be 5 amperes (2 + 3 = 5).

It's important to note that this only applies at a specific instant in time, and the net current may change as the circuit changes or the currents vary.

Read more about currents here:

https://brainly.com/question/24858512

#SPJ1

Answer:

The most accurate reading for an analog meter is a pointer position between 2/3 of full scale and full scale. Typically, dc voltage measurements use the full count capability of the ADC, since signal conditioning is rather straight forward: it uses resistive dividers and filters.

The factors that  you need to consider when preparing to move gondolas are:

In choosing gondola one need to look at some  factor in decisions such as height.

Know that it is good to  consider the construction material and also the center wall configuration for its building also.

The factors that  you need to consider when preparing to move gondolas are:

Learn more about gondola from

https://brainly.com/question/10652274

#SPJ1

The number of comparisons made by the algorithm is O(n^3).

a) To analyze the number of comparisons made by the algorithm, let's count the comparisons made in the innermost loop.

In the innermost loop, for each k from i + 1 to j, a comparison is made to update the value of mij if ak is smaller than the current value of mij. Since j can go up to n and k can go up to j, the innermost loop will execute j - (i + 1) + 1 = j - i times.

The outer two loops iterate over i from 1 to n and j from i + 1 to n. The total number of comparisons made in the innermost loop is the sum of j - i for all valid i and j.

Let's calculate the total number of comparisons:

∑(i=1 to n) ∑(j=i+1 to n) (j - i)

Rearranging the terms:

∑(i=1 to n) ∑(j=i+1 to n) j - ∑(i=1 to n) ∑(j=i+1 to n) i

Simplifying the expressions:

∑(i=1 to n) ( ∑(j=i+1 to n) j - ∑(j=i+1 to n) i )

The inner summations can be computed using the formulas for the sum of arithmetic series:

∑(j=i+1 to n) j = (n - i)(n + i + 1)/2

∑(j=i+1 to n) i = (n - i)(i)

Plugging in these values:

∑(i=1 to n) ( (n - i)(n + i + 1)/2 - (n - i)(i) )

Expanding and simplifying:

∑(i=1 to n) ( (n^2 + 2ni + n - i^2 - ni - i)/2 - (ni - i^2) )

∑(i=1 to n) ( n^2 + 2ni + n - i^2 - ni - i - ni + i^2 )

∑(i=1 to n) ( n^2 + n )

(n^2 + n) * n

n^3 + n^2

Therefore, the number of comparisons made by the algorithm is O(n^3).

b) The expression "!(n^3)" is not a valid notation in complexity analysis. I assume it was meant to be "Ω(n^3)" which represents the lower bound.

Since the algorithm uses O(n^3) comparisons (as shown in part a), and Ω(n^3) represents the lower bound, we can conclude that the algorithm uses Θ(n^3) comparisons.

To know more about algorithm, click here:

https://brainly.com/question/21172316

#SPJ11

Answer:

Explanation:

In the development of a torsion formula for a circular shaft, the following assumptions are made: Material of the shaft is homogeneous throughout the length of the shaft. Shaft is straight and of uniform circular cross section over its length. Torsion is constant along the length of the shaft.

For surface-mounted and pendant-hung luminaires, support rods should be placed so that they extend about one.

A particular disk is activated by mounting software, which makes its contents accessible to the computer's file system. A partition is created in the computer's file system for the mounted device when it is mounted.

A framework or foundation that supports or supports something else. Mounting is another word for support.

The procedure through which the operating system of a computer makes the files and directories on a storage device (such as a hard drive, CD-ROM, or network share) accessible to users via the computer's file system is known as mounting.

For surface-mounted and pendant-hung luminaires, mounting rods should be placed so that they develop about one.

To learn more about mounting, refer to:

https://brainly.com/question/14096584

#SPJ4

Answer:

Along the zero to measure an object on a ruler

Answer:

the third anwser is right on edgeinuity

Explanation:

Answer:

Technology can pull students’ focus away from their tasks.

Explanation:

Velocity needed to the system is 14 m / s

The displacement that an object or particle experiences with respect to time is expressed vectorially as velocity. The meter per second (m/s) is the accepted unit of velocity magnitude (also known as speed).

Let's use energy conservation as our starting point for this practice. On the ground right as you accelerate out Em0 = K = 12 m v2. No speed when on the building's roof.

Em f = U = m g h: conservation of energy

Em0 = Em f 12 m v2 = m g h v = u u = sqrt2 g h sqrt2 = 9.8 sqrt2 = 10

u = 14 m / s

Various Velocity Types are:

To learn more about velocity refer to:

https://brainly.com/question/16341861

#SPJ1

Yes, a pulsed current can have a zero net charge. This is because a pulsed current is a flow of electric charges that alternate in direction, creating a series of electrical pulses.

The net charge of a pulsed current is determined by the difference between the number of positive and negative charges flowing through the circuit. If the number of positive charges is equal to the number of negative charges, the net charge is zero.
Yes, a pulsed current can have a zero net charge. In a pulsed current, the flow of electric charge alternates between intervals of movement and no movement. If the positive and negative charges flowing in the current cancel each other out over time, the net charge will be zero. This means that the total amount of positive charge equals the total amount of negative charge, resulting in no overall charge being transferred.

Visit here to know more about electrical pulses:

brainly.com/question/842496

#SPJ11

Yes, a pulsed current can have a zero net charge. A pulsed current refers to the flow of electric charge that periodically changes its direction or magnitude. This can be seen in alternating current (AC) systems or electronic circuits that use pulse waveforms.

For such more question on charges

https://brainly.com/question/25923373

#SPJ11

Answer:

Emails and phone calls are both common forms of communication that are used in professional and personal settings. There are several similarities between email and phone calls:

1. Both are asynchronous forms of communication: Unlike instant messaging or face-to-face conversations, both emails and phone calls allow the sender or recipient to respond at their convenience. They don't require immediate attention or an instant response.

2. Both are written forms of communication: While phone calls rely on spoken words, emails are written. As a result, both can be used to convey detailed information and allow the sender to carefully consider their words before sending.

3. Both are forms of direct communication: Emails and phone calls both allow for direct communication between two parties. This can be beneficial for discussing sensitive information or resolving issues quickly.

4. Both can be used for formal and informal communication: Emails and phone calls can be used in both personal and professional contexts. They are both flexible forms of communication that can be adapted to fit different situations.

5. Both require attention to tone and etiquette: Just like with phone calls, emails require attention to tone and proper etiquette. Both forms of communication should be approached professionally and respectfully to ensure effective communication.

In conclusion, while there are differences between emails and phone calls, there are also similarities that make them useful communication tools. Both allow for direct, asynchronous communication and can be adapted to fit different situations.

Explanation:

The following should be done by the team member:

Learn more: brainly.com/question/17429689

Answer:

V = 20.6 m/s

Explanation:

Given that the temperature of the neon molecules = 356 Kelvin

Pressure = 0.9 bar

The mass number of Neon = 21.

Using the formula below

1/2 m v^2 = (3kT)/2

Where

T = temperature = 356 k

K = Bolzmann constant

= 1.38 × 10^-23jk^-1

NA = 6.02214076×10²³ mol⁻¹

Where NA = Avogadro number

Substitute all the parameters Into the formula

1/2 × 21/NA × v^2 = (3 × k × 356)/2

1.744×10^-23V^2 = 7.3692 × 10^-21

Make V^2 the subject of formula

V^2 = (7.37×10^-21)/1.744×10^-23

V^2 = 422.55

V = sqrt( 422.55)

V = 20.55

Therefore, the average (root mean square) velocity (m/s) of Neon molecules at 356 Kelvins and 0.9 bars is 20.55 m/s

When it comes to driving a car, braking is a very important skill to have. Braking is the process of slowing down or stopping a moving vehicle. Knowing how to brake effectively can be the difference between avoiding a crash and causing one.

Below are the three levels of braking that precede the need to lock up your wheels:

1. Perception braking: This is the first level of braking that precedes the need to lock up your wheels. Perception braking refers to the driver's ability to recognize the need to brake in response to a situation. This type of braking is necessary when you notice a potential hazard on the road, such as a pedestrian, a cyclist, or another car. Perception braking requires that you react quickly to the situation and apply the brakes as soon as possible.

2. Controlled braking: The second level of braking that precedes the need to lock up your wheels is controlled braking. This type of braking requires that you apply the brakes firmly but smoothly. The idea is to slow down the vehicle without locking up the wheels. Controlled braking is essential when you are driving on a wet or slippery road surface, as it allows you to slow down the car without losing control.

3. Threshold braking: The third level of braking that precedes the need to lock up your wheels is threshold braking. This is the most advanced form of braking and requires a lot of skill and experience. Threshold braking involves applying the brakes to the point just before the wheels start to lock up. At this point, the driver eases off the brakes slightly to maintain traction and control. Threshold braking is the most effective form of braking in emergency situations, as it allows the driver to slow down the vehicle quickly without losing control.

To know more about Braking visit:

https://brainly.com/question/32687728

#SPJ11

Answer:

1) The bending moment diagram of the shaft is shown in Figure 1. The weakest cross section A is located at the point where the bending moment is maximum.

2) The weakest point on cross section A is located at the point where the bending moment is maximum.

3) The von-Mises stress at the weakest point is given by:

σ = M/I

where M is the bending moment and I is the moment of inertia of the cross section.

4) The factor of safety n is given by:

n = Sy/σ

where Sy is the yield strength of the shaft and σ is the von-Mises stress at the weakest point.

Explanation:

Hope this helps!

The minimum clock period for this CPU should be at least 345 ps.

To determine the latencies and clock period requirements for different instructions in the given exercise, we will consider the provided values for the logic block latencies.

4.7.1:

The latency of an R-type instruction refers to the time required for the instruction to complete its execution. In this case, the R-type instruction consists of register read, ALU operation, and register write. From the given values, we can determine the total latency by summing the latencies of the logic blocks involved:

Latency = Register Read + ALU Adder + Register Write

Latency = 150 ps + 25 ps + 150 ps

Latency = 325 ps

Therefore, the clock period should be at least 325 ps to ensure the correct execution of an R-type instruction.

4.7.2:

The latency of ld (load) instruction represents the time required to complete the load operation, which involves register read, sign extension, ALU operation, and register write. Adding up the latencies of the involved logic blocks:

Latency = Register Read + Sign Extend + ALU Adder + Register Write

Latency = 150 ps + 20 ps + 25 ps + 150 ps

Latency = 345 ps

Thus, the clock period should be at least 345 ps for the correct execution of the ld instruction.

4.7.3:

Similar to the ld instruction, the sd (store) instruction involves register read, sign extension, ALU operation, and register write. Adding up the latencies:

Latency = Register Read + Sign Extend + ALU Adder + Register Write

Latency = 150 ps + 20 ps + 25 ps + 150 ps

Latency = 345 ps

The clock period should be at least 345 ps for the correct execution of the sd instruction.

4.7.4:

The latency of beq (branch equal) instruction involves register read, ALU operation, and control logic. Summing up the latencies:

Latency = Register Read + ALU Adder + Control

Latency = 150 ps + 25 ps + 50 ps

Latency = 225 ps

A clock period of at least 225 ps is required for the correct execution of the beq instruction.

4.7.5:

The I-type instruction refers to the load and store instructions (ld and sd). Since we have already determined their latencies in previous questions:

I-type Instruction Latency = Latency of ld or sd = 345 ps

4.7.6:

The minimum clock period for this CPU would be equal to the highest latency among all the instructions. From the previous calculations, the highest latency is 345 ps.

Therefore, the minimum clock period for this CPU should be at least 345 ps.

Learn more about CPU here

https://brainly.com/question/30458937

#SPJ11

Here's a function called Close Enough which takes a const reference to a vector of strings and an int. This function is used to check if there are two adjacent strings in a list that are very similar to each other by determining the number of characters that can be different between any two strings next to each other.

The function starts by iterating through the vector of strings from the first to the second to last string. For each string, it then counts the number of differences between it and the next string by comparing the characters at each position.

If the number of differences is less than or equal to the given integer n, the function returns the index of the current string. If there is no such index, the function returns -1.

To know more about vector visit:

https://brainly.com/question/24256726

#SPJ11

GUI Math Game programme is a program that generates random math questions and allows the user to input their answer. It then checks the answer and provides feedback. The game continues until the user decides to quit.

Here's how you can write a GUI Math Game program in Java that generates and displays 2 random numbers via the GUI:

import javax.swing.*;

import java.awt.*;

import java.awt.event.*;

import java.util.Random;

public class MathGame extends JFrame implements ActionListener{ JLabel lblNum1, lblNum2, lblSign, lblEquals, lblCorrect, lblWrong;

JTextField txtAnswer;

JButton btnSubmit, btnNew;

JPanel panel1, panel2, panel3;

int num1, num2, correct, wrong, answer;

char sign;

public MathGame(){ setTitle("Math Game");

setSize(500, 150);

setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

setResizable(false); panel1 = new JPanel();

panel2 = new JPanel();

panel3 = new JPanel();

lblNum1 = new JLabel();

lblNum2 = new JLabel();

lblSign = new JLabel();

lblEquals = new JLabel();

lblCorrect = new JLabel("Correct: 0");

lblWrong = new JLabel("Wrong: 0");

txtAnswer = new JTextField(5);

btnSubmit = new JButton("Submit");

btnNew = new JButton("New");

panel1.add(lblNum1);

panel1.add(lblSign);

panel1.add(lblNum2);

panel1.add(lblEquals);

panel1.add(txtAnswer);

panel2.add(btnSubmit);

panel2.add(btnNew);

panel3.add(lblCorrect);

panel3.add(lblWrong);

add(panel1, BorderLayout.NORTH);

add(panel2, BorderLayout.CENTER);

add(panel3, BorderLayout.SOUTH);

setVisible(true);

num1 = generateRandomNumber();

num2 = generateRandomNumber();

sign = '+'; lblNum1.setText("" + num1);

lblNum2.setText("" + num2);

lblSign.setText("" + sign);

btnSubmit.addActionListener(this);

btnNew.addActionListener(this); }

public void actionPerformed(ActionEvent e){

if(e.getSource() == btnSubmit){ try{ answer = Integer.parseInt(txtAnswer.getText()); }

catch(NumberFormatException ex){ JOptionPane.showMessageDialog(null, "Please enter a valid number."); }

if(answer == (num1 + num2)){ JOptionPane.showMessageDialog(null, "Correct!"); correct++; lblCorrect.setText("Correct: " + correct); }

else{ JOptionPane.showMessageDialog(null, "Wrong!"); wrong++; lblWrong.setText("Wrong: " + wrong); } }

else if(e.getSource() == btnNew){ num1 = generateRandomNumber(); num2 = generateRandomNumber(); sign = '+'; lblNum1.setText("" + num1); lblNum2.setText("" + num2); lblSign.setText("" + sign); txtAnswer.setText(""); } }

private int generateRandomNumber(){ Random rand = new Random(); return rand.nextInt(10) + 1; }

public static void main(String[] args){ MathGame mg = new MathGame(); }}

The program generates 2 random numbers and displays them on the GUI. The user enters their answer in a text field. The program evaluates the answer and updates the "Correct" and "Wrong" labels accordingly. The "New" button generates new random numbers and clears the text field.

For similar questions on writing GUI Math Game programme visit:

https://brainly.com/question/15050241

#SPJ11

The provided Java code implements a GUI Math Game program that generates two random numbers for addition and allows the user to enter their answer. It evaluates the correctness of the answer and updates the "Correct" and "Wrong" labels accordingly.

Here's an example code for a GUI Math Game program in Java that generates random numbers for addition and allows the user to enter their answer:

import javax.swing.*;

import java.awt.*;

import java.awt.event.ActionEvent;

import java.awt.event.ActionListener;

public class MathGame extends JFrame implements ActionListener {

   private JLabel numLabel1, numLabel2, resultLabel, feedbackLabel;

   private JTextField answerField;

   private JButton submitButton;

   public MathGame() {

       setTitle("Math Game");

       setSize(300, 200);

       setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

       // Create and set layout

       setLayout(new GridLayout(4, 2));

       // Create components

       numLabel1 = new JLabel();

       numLabel2 = new JLabel();

       resultLabel = new JLabel(" ");

       feedbackLabel = new JLabel(" ");

       answerField = new JTextField();

       submitButton = new JButton("Submit");

       // Add components to the frame

       add(new JLabel("Number 1:"));

       add(numLabel1);

       add(new JLabel("Number 2:"));

       add(numLabel2);

       add(new JLabel("Answer:"));

       add(answerField);

       add(new JLabel("Result:"));

       add(resultLabel);

       // Add ActionListener to the submit button

       submitButton.addActionListener(this);

       // Add feedback label

       add(feedbackLabel);

       // Generate random numbers and display

       generateNumbers();

       // Make the frame visible

       setVisible(true);

   }

   public void actionPerformed(ActionEvent e) {

       if (e.getSource() == submitButton) {

           // Get user's answer

           int userAnswer = Integer.parseInt(answerField.getText());

           // Get the correct answer

           int correctAnswer = Integer.parseInt(numLabel1.getText()) + Integer.parseInt(numLabel2.getText());

           // Check if the user's answer is correct

           if (userAnswer == correctAnswer) {

               resultLabel.setText("Correct");

               feedbackLabel.setText(" ");

           } else {

               resultLabel.setText("Wrong");

               feedbackLabel.setText("Try again!");

           }

           // Generate new numbers for the next question

           generateNumbers();

           // Clear the answer field

           answerField.setText("");

       }

   }

   public void generateNumbers() {

       // Generate random numbers

       int num1 = (int) (Math.random() * 10) + 1;

       int num2 = (int) (Math.random() * 10) + 1;

       // Display the numbers

       numLabel1.setText(Integer.toString(num1));

       numLabel2.setText(Integer.toString(num2));

   }

   public static void main(String[] args) {

       SwingUtilities.invokeLater(new Runnable() {

           public void run() {

               new MathGame();

           }

       });

   }

}

To run this program, create a new Java project, copy the code into a Java class file (e.g., MathGame.java), and execute the program. The GUI will be displayed with two random numbers for addition, and the user can enter their answer.

The program will evaluate the answer, update the "Correct" and "Wrong" labels accordingly, and generate new numbers for the next question.

Learn more about program here:

https://brainly.com/question/14368396

#SPJ4

Answer:

  0 ft

Explanation:

The equation of the plane can be found from the cross product AC×BC. That vector is ...

  N = (2, 11, -6) × (-3, -6, 4) = (8, 10, 21)

Then the equation of the plane is ...

  8x +10y +21z = 14 . . . . . 14 = N·A

Point P satisfies this equation, so is on the plane. The distance is 0 feet.

  8(9) +10(11) -8(21) = 72 +110 -168 = 14

0.925

What is the size in square inches of a 550 MCM size of a cable

Answer:

3 m/s²

Explanation:

Acceleration is calculated as :

a= Δv/ t

where ;

Δv = change in velocity

Δv = 45 - 0 = 45  m/s

t= 15 s

a= 45 /15

a= 3 m/s²