At a distance of 10.0 m from a loudspeaker, the sound intensity level is measured to be 70 dB. At what distance from the source will the intensity be 40 dB?

 wavefront is the long edge that moves, for example, the crest or the trough

The following situations represents a positive displacement:

B. An object moves from a height of 5 meters to a height of 10 meters.

Displacement is a vector quantity that measures the change in position of an object from its initial position to its final position. In this scenario, the positive position is measured vertically upward along the y-axis. Let's analyze each option to determine which one represents a positive displacement:

A. An object moves from a height of 10 meters to a height of 5 meters.

This represents a negative displacement since the object moves downward, opposite to the positive direction along the y-axis.

B. An object moves from a height of 5 meters to a height of 10 meters.

This represents a positive displacement as the object moves upward, in the positive direction along the y-axis.

C. An object remains at a height of 5 meters.

This represents zero displacement since there is no change in the object's position along the y-axis.

D. An object moves from a height of 5 meters to a height of 5 meters.

This also represents zero displacement since the object starts and ends at the same position along the y-axis.

Therefore, the situation that represents a positive displacement is option B, where the object moves from a height of 5 meters to a height of 10 meters.

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Answer:

27 degrees Fahrenheit is -2.78°c

Hamilton's equations of motion are a set of equations that describe the dynamics of a classical mechanical system in terms of a generalized coordinate and its conjugate momentum.

The equations are derived from the Hamiltonian formalism. Hamilton's equations can be derived from the Hamilton's principle, which is a variational principle that states that the action of a dynamical system is stationary.

To derive these equations, we start with the Hamiltonian function H(p, q) and use the principle of least action. The action S is defined as the integral of the Lagrangian L(q, q', t) over time:

S = ∫[L(q, q', t)] dt

To find dp/dt, we differentiate the Lagrangian with respect to q:

∂L/∂q = ∂(p * q' - H)/∂q

= -∂H/∂q

Using the chain rule, we find:

dL/dt = (∂L/∂q) * dq/dt + (∂L/∂q') * dq'/dt

= -∂H/∂q * dq/dt + p * d(q')/dt

= -∂H/∂q * dq/dt + p * d^2q/dt^2

= -∂H/∂q * dq/dt + dp/dt

Since the Lagrangian is equal to p * dq' - H, we can write:

dL/dt = -∂H/∂q * dq/dt + dp/dt

From the principle of least action, we know that the action S is stationary, so dL/dt = 0. Thus, we have:

-∂H/∂q * dq/dt + dp/dt = 0

Rearranging the equation, we obtain the first equation of motion:

dp/dt = -∂H/∂q

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For the first one, W = 7.3 kJ, Q = 25.83kJ

For the second one, W = Q = 124KJ

First One:

Parameters given are:

Mass m = 0.05kg

\(V_{2}\) = 0.0658 \(m^{3}\)

Since the pressure is constant, \(P_{1} = P_{2} = 2bar\)

While \(T_{1} = 130\)°C

Convert degree Celsius to degree kelvin

Temperature = 273 + 130 = 403 K

Before we can get the work done, we need to calculate the initial volume \(V_{1}\) by using Ideal gas general formula.

\(P_{1}V_{1} = mRT_{1}\)

Make \(V_{1}\) the subject of formula

\(V_{1}\) =  \(mRT_{1}\) / \(P_{1}\)

\(V_{1}\) = (0.05 x 287 x 403) / (2 x \(10^{5}\))

\(V_{1}\) = 0.0289\(m^{3}\)

From the table, specific volumes are:

\(u_{1}\) = 0.578\(m^{3}\)kg

\(u_{2}\) = 1.316\(m^{3}\)kg

Work done can be calculated by using the below formula

W = P( \(u_{2}\) - \(u_{1}\) )

W = 2 x \(10^{5}\)( 1.316 - 0.578)

W = 147600 J/kg

The Total work done = 147600 x 0.05 = 7380J = 7.3 kJ

To calculate the heat supplied by using the heat formula

Q = m\(C_{p}\)( \(T_{2} - T_{1}\)), we need to calculate for final temperature \(T_{2}\) and also check the table for

where \(C_{p}\) = 1.005

we can calculate for \(T_{2}\) by using Ideal gas formula

\(P_{2}V_{2} = mRT_{2}\)

make \(T_{2}\) the subject of formula

\(T_{2}\) = PV/mR

\(T_{2}\) = (2 x \(10^{5}\) x 0.0658) / (0.05 x 287)

\(T_{2}\) = 917 K

Substituting \(T_{2}\) and other parameters into the formula

Q = m\(C_{p}\)(\(T_{2} - T_{1}\))

Q = 0.05 x 1.005 ( 917 - 403)

Q = 25.83 KJ

Second one

From the question, the following parameters are given

mass m = 1kg

Molar M = 28kg/mol

Since the system is compressed reversibly and isothermally,

\(T_{2}\) = T = 20°C

\(P_{1}\) = 1.01 bar

\(P_{2}\) = 4.2 bar

To calculate both heat and work done, we will use the formula below

W = RTln\(P_{1}\)/\(P_{2}\)

But R = Ro/M

R = 8314/28

R = 297 J/kg.k

W = 297 x 293 x ln(1.01/4.2)

W = - 124kJ / kg

We can therefore conclude that the work input during the process is

124 KJ While the heat produced is also 124 KJ because W = Q

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Answer:

1. Knowing the rules for badminton is important because it affects everyone around you if you are playing. Not knowing the rules can make it not fun for the other players.

2. One characters a good badminton player should have is sportsmanship .

Explanation:

Hope this helps you out!

The height of the reproduction is 29 inches, which is the same as the height of the original painting with dimensions.

To find the height of the reproduction of Vincent Van Gogh's painting "The Starry Night," we can use the concept of proportional scaling. Since the reproduction has the same dimensions as the original painting, the ratio of the height and width of the reproduction must be the same as the ratio of the height and width of the original painting.

The ratio of height to width of the original painting can be calculated as:

29 / 36.25 = 0.8

Therefore, the ratio of height to width of the reproduction must also be 0.8. We can set up a proportion to solve for the height of the reproduction, which we'll call h:

h / 36.25 = 0.8

To solve for h, we can multiply both sides by 36.25:

h = 36.25 * 0.8

h = 29

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The magnetic flux through the small loop when the current through the solenoid is 2.50 A is 5.87*10⁻⁴ Wb, the induced emf in the loop is 1.4*10⁻³r.

What is magnetic flux  ?

The number of magnetic field lines that travel through a specific closed surface is referred to as magnetic flux. It gives a measurement of the overall magnetic field that traverses a specific surface region.

What is  induced emf  ?

A magnetic field is induced when a conductor carrying an electric current travels through it. Induced electromagnetic fields (EMFs) are created when a magnetic field rotates around an electric field.

Given data

length = 0.100 m

radius = 0.50 m

N= 1.5 *10⁴

I= 2.50A

a) the field inside the solenoid  is

B= μ₀ Ni/L

B= 1.25 *10⁻⁶*1.5*10⁴*2.50/0.100

B= 0.47 Tesla

B= 0.47 W₆/m²

Area, A= πr²= (0.02)²

=0.00125m²

Magnetic flux = ∅ = B.A

= 5.87*10⁻⁴ Wb

b) induced Emf in the loop

EMf =  μ₀ (dI/dT) (N/L) πr²

EMF= 1.4*10⁻³r

Therefore, the magnetic flux through the small loop when the current through the solenoid is 2.50 A is 5.87*10⁻⁴ Wb, the induced emf in the loop is 1.4*10⁻³r.

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(a) The average acceleration of the car is 8 m/s^2.

(b)  The car traveled a distance of  144 meters during this time period.

To find the average acceleration of the car, we can use the formula:

average acceleration = change in velocity / time

average acceleration = (48 m/s - 0 m/s) / 6 s

average acceleration = 8 m/s^2

So the average acceleration of the car is 8 m/s^2.

To find how far the car traveled during this time period, we can use the formula:

distance = initial velocity x time + (1/2) x acceleration x time^2

distance = 0 m/s x 6 s + (1/2) x 8 m/s^2 x (6 s)^2

distance = 0 m + 144 m

distance = 144 m

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Answer:

B a current flowing through a coil of wire :)

Explanation:

Answer:

\(d_2=3.16cm\)

Explanation:

So, in order to solve this problem, we must start by building a diagram of the problem itself. (See attached picture) And together with the diagram, we must build a free body diagram, which will include the forces that are being applied on the given charged particle together with their directions.

In this case we only care about the x-direction of the force, since the y-forces cancel each other. So if we do a sum of forces on the x-direction, we get the following:

\(\sum{F_{x}}=0\)

so:

[Tex]-F_{12}+F_{13x}+F_{14x}=0\)

Since \(F_{13x}=F_{14x}\) we can simplify the equation as:

\(-F_{12}+2F_{13x}=0\)

we can now solve this for \(F_{12}\) so we get:

\(F_{12}=2F_{13x}\)

Now we can substitute with the electrostatic force formula, so we get:

\(k_{e}\frac{q_{1}q_{2}}{r_{12}^{2}}=2k_{e}\frac{q_{1}q_{3}}{r_{13}^{2}}cos \theta\)

We can cancel \(k_{e}\) and \(q_{1}\)

so the simplified equation is:

\(\frac{q_{2}}{r_{12}^{2}}=2\frac{q_{3}}{r_{13}^{2}}cos \theta\)

From the given diagram we know that:

\(cos \theta = \frac{d_{1}}{r_{13}}\)

so when solving for \(r_{13}\) we get:

\(r_{13}=\frac{d_{1}}{cos\theta}\)

and if we square both sides of the equation, we get:

\(r_{13}^{2}=\frac{d_{1}^{2}}{cos^{2}\theta}\)

and we can substitute this into our equation:

\(\frac{q_{2}}{r_{12}^{2}}=2\frac{q_{3}}{d_{1}^{2}}cos^{3} \theta\)

so we can now solve this for \(r_{12}\) so we get:

\(r_{12}=\sqrt{\frac{d_{1}^{2}q_{2}}{2q_{3}cos^{3}\theta}}\)

which can be rewritten as:

\(r_{12}=d_{1}\sqrt{\frac{q_{2}}{2q_{3}cos^{3}\theta}}\)

and now we can substitute values.

\(r_{12}=(3cm)\sqrt{\frac{7x10^{-19}C}{2(2x10^{-19}C)cos^{3}(20^{o})}}\)

which solves to:

\(r_{12}=6.16cm\)

now, we must find \(d_{2}\) by using the following equation:

\(r_{12}=d_{1}+d_{2}\)

when solving for \(d_{2}\) we get:

\(d_{2}=r_{12}-d_{1}\)

when substituting we get:

\(d_{2}=6.16cm-3cm\)

so:

\(d_{2}=3.16cm\)

Answer:

Work=Force×distance

Explanation:

work=force×distance

force=64N

distance=11m

work=64×11=704Joules

Remember unit of work is Joules or Newton metre(N/m).

Explanation:

how can I help you that?

Answer:

Electrical energy this is because when the flashlight us turned on the chemical energy stored in the battery is converted to electrical energy that flows through the wire of the flashlight

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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Answer:

No you didn't win the stuffed poodle

Explanation:

From the question we are told that

    The distance of the ramp to the hole is  d =  3 m \

     The angle of inclination is  \(\theta  =  10^o\)

       The coefficient of static friction is \(\mu_s = 0.1\)

     The coefficient of kinetic  friction is \(\mu_k = 0.08\)

      The mass of the puck is  m  =  1 kg

     The velocity of the first slide  is  \(v_1  =  2.0 m/s\)

Generally the kinetic energy at the bottom of the ramp  is equal the energy loss due to friction and this can be mathematically represented as

    \(\frac{1}{2} m *  v^  2 =  \mu_k * [m *  g] *  cos (theta )  *  d\)

=>     \(\frac{1}{2}  *  v^  2 = 0.08 * 9.8 *  cos (10 )  *  3\)

=>     \( v=  2.17 \  m/s \)

Comparing the relative velocity obtained and the velocity of your first throw we can see that you didn't win the stuffed animal  

Answer:

Below

Explanation:

In a mass-spring system that is oscillating horizontally, the energy changes between potential energy and kinetic energy. When the mass is at its maximum displacement from the equilibrium position, it has maximum potential energy and zero kinetic energy. As the mass starts to move towards the equilibrium position, its potential energy decreases while its kinetic energy increases. At the equilibrium position, the mass has zero potential energy and maximum kinetic energy. As the mass moves away from the equilibrium position, its kinetic energy decreases while its potential energy increases. This cycle repeats as long as the system is oscillating.

Now, if the support of the system is vibrating vertically, the energy changes that occur during horizontal oscillations cause the mass to move vertically as well. As the mass moves to its maximum displacement from the equilibrium position horizontally, it also moves upwards, gaining potential energy due to its increased height from the ground. As the mass moves towards the equilibrium position horizontally, it also moves downwards, losing potential energy and gaining kinetic energy due to its increased speed towards the ground. At the equilibrium position, the mass has zero potential energy but maximum kinetic energy, which is all in the vertical direction. As the mass moves away from the equilibrium position horizontally, it also moves upwards, gaining potential energy again. The cycle repeats, causing the mass to oscillate vertically as well.

Therefore, the energy changes that occur during horizontal oscillations in a mass-spring system can cause the system to vibrate vertically if the support is vibrating vertically.

Answer:

v = 1⅓ m/s in the direction of the 8 kg block.

Explanation:

As momentum is a vector, we need to handle direction as well as magnitude.

If we assume the 4 kg block is moving in the positive direction.

4(2.0) + 8(-3) = (4 + 8)v

v = -1.33333...

Answer: current I = 1.875A

Explanation:

If the resistors are connected in series,

Then the equivalent resistance will be

R = 6 + 18 + 15 + 9

R = 48 ohms

Using ohms law

V = IR

Make current I the subject of formula

I = V/R

I = 90/48

I = 1.875A

And if the resistors are connected in parallel, the equivalent resistance will be

1/R = 1/6 + 1/18 + 1/15 + 1/9

1/R = 0.166 + 0.055 + 0.066 + 0.111

R = 1/0.3999

R = 2.5 ohms

Using ohms law

V = IR

I = 90/2.5

Current I = 35.99A

Answer:

It takes 21.7 seconds for Skid to reach the edge of the pond.

Explanation:

We can calculate the time that takes Skid to reach the edge of the pond by conservation of linear momentum:

\( p_{i} = p_{f} \)

\( m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} - m_{2}v_{2_{f}} \)  (1)

Where:

m₁: is the Skid's mass

m₂: is the book's mass = 2.6 kg

\(v_{1_{i}}\): is the initial speed of Skid = 0 (he was at rest)

\(v_{2_{i}}\): is the initial speed of the book = 0 (it was at rest)

\(v_{1_{f}}\): is the final speed of Skid =?

\(v_{2_{f}}\): is the final speed of the book = 4 m/s. This value is negative since it is moving in the opposite direction of Skid.

First, we need to calculate Skid's mass.  

\( m_{1} = \frac{P}{g} \)

Where:

P: is the weight of Skid = 440 N

g: is the acceleration due to gravity  = 9.81 m/s²

\( m_{1} = \frac{P}{g} =\frac{440 N}{9.81 m/s^{2}} = 44.8 kg \)

Now, we can find the speed of Skid from equation (1):

\( 0 = 44.8 kg*v_{1_{f}} - 2.6 kg*4 m/s \)          

\( v_{1_{f}} = \frac{2.6 kg*4 m/s}{44.8 kg} = 0.23 m/s \)

Finally, the time to reach the edge can be found by using the following equation:

\( v_{1_{f}} = \frac{d}{t} \)

Where:

d: is the distance = radius = 5 m

t: is the time =?

\( t = \frac{d}{v_{1_{f}}} = \frac{5 m}{0.23 m/s} = 21.7 s \)

Therefore, it takes 21.7 seconds for Skid to reach the edge of the pond.

I hope it helps you!  

Answer:

B. the number of field lines on the source charge

Explanation:

As we know that electric flux is defined as the number of electric field lines passing through a given area.

So here  electric flux due to a point charge "q" is given by

so here we know that flux depends on the magnitude of charge and hence we can say that number of filed lines originating from a point charge will depends on the magnitude of the charge.

The factor indicates the amount of charge on the source charge is the number of field lines on the source charge.

The electric flux is defined as the number of electric field lines passing through a given area.

The electric flux due to a point charge q is given by the number of filed lines through particular closed area.

We know that flux depends on the magnitude of charge and number of field lines starting from a point charge will depends on the magnitude of the charge.

Thus, the correct option is B.

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Answer:

its and electromagnet

Answer:

D

Explanation:

The acceleration of Thomas is 0.233 m/s^2.

Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.

Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.

We are to find the acceleration of Thomas.

The formula for acceleration is given as :

acceleration = (final velocity - initial velocity) / time

In the given problem, the initial velocity of Thomas, u = 2 m/s.

The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.

Therefore, the acceleration of Thomas will be given as:

a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2

Thus, the acceleration of Thomas is 0.233 m/s^2.

To summarize, the acceleration of Thomas is 0.233 m/s^2.

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(a) The magnitude of the magnetic field at point P1 , midway between the wires is  1.005 x 10⁻⁴ T and the direction will be out of the page.

(b) The magnitude of the magnetic field at point P2 , 25.0 cm to the right of P1 is 2.67 x 10⁻⁶ T and the direction is into the page.

(c) The magnitude of the magnetic field at point P3 , 20.0 cm directly above P1  is 3.88 x 10⁻⁶ T and the direction is downwards.

B = μ/2π[I₁/0.5r + I₂/0.5r]

B = (μ/2π) x (I/0.5r + I/0.5r)

B = (μ/2π) x (2I/0.5r)

B = μI/0.5r

B = 2μI/r

where;

B = (2 x 4π x 10⁻⁷ x 4)/(0.1)

B = 1.005 x 10⁻⁴ T

The direction of the magnetic field is out of the page.

B = μI/2πd

d = 5 cm + 25 cm = 30 cm

B =  (4π x 10⁻⁷ x 4)/(2π x 0.3)

B = 2.67 x 10⁻⁶ T

The direction of the magnetic field is into the page towards P1.

B = μI/2πd

d = √(20² + 5²)

d = 20.62 cm

B =  (4π x 10⁻⁷ x 4)/(2π x 0.2062)

B = 3.88 x 10⁻⁶ T

The direction of the magnetic field is downwards towards P1.

Thus, the magnitude of the magnetic field at point P1 , midway between the wires is  1.005 x 10⁻⁴ T and the direction will be out of the page.

The magnitude of the magnetic field at point P2 , 25.0 cm to the right of P1 is 2.67 x 10⁻⁶ T and the direction is into the page.

The magnitude of the magnetic field at point P3 , 20.0 cm directly above P1  is 3.88 x 10⁻⁶ T and the direction is downwards.

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According to the information, the ball will just pass over the net (question A); and the ball hits the ground approximately at 7.04 meters from the player and after a time of flight of approximately 1.31 seconds (question B).

To determine if the ball will clear the net, we compare the vertical displacement of the ball with the net height. The ball's initial height is 1.1 meters, and it reaches its highest point during flight. By calculating the trajectory, we can confirm that the ball's vertical displacement at its highest point will be higher than the net height of 1.81 meters, ensuring it clears the net.

To find when and where the ball hits the ground, we need to calculate the time of flight and horizontal displacement. Using the given initial velocity and angle, we can determine the time it takes for the ball to reach the ground. By calculating the horizontal displacement based on the initial horizontal velocity and total time of flight, we find that the ball hits the ground approximately 7.04 meters from the player. The time of flight is approximately 1.31 seconds. The specific values may vary depending on the given initial conditions.

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Answer:

B........................