at a cell phone assembly plant, 84% of the cell phone keypads pass inspection. a random sample of 106 keypads is analyzed. find the mean of the sample proportion .

The t-value for a 90% confidence level and 9 degrees of freedom is approximately 1.833. The t-value represents the critical value from the t-distribution corresponding to a specific confidence level and degrees of freedom.

In this case, with a 90% confidence level and 9 degrees of freedom, we can use the t-table or statistical software to find the t-value. The t-value determines the margin of error in estimating population parameters based on sample data.

For a 90% confidence level, there is a 10% chance of making a Type I error (rejecting a true null hypothesis). The t-value at this confidence level and degrees of freedom are approximately 1.833.

This value is used in constructing confidence intervals or performing hypothesis tests in situations where the sample size is small or the population standard deviation is unknown.

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The __sign__ of the correlation coefficient indicates the direction of the correlation, whether it is positive or negative.

The correlation coefficient, often denoted by the symbol "r," is a statistical measure that quantifies the strength and direction of the linear relationship between two variables.

It ranges between -1 and 1, where a value of -1 indicates a perfect negative correlation, a value of 1 indicates a perfect positive correlation, and a value of 0 indicates no correlation.

When the correlation coefficient is positive, it suggests that the two variables have a positive linear relationship. This means that as one variable increases, the other variable tends to increase as well.

For example, a positive correlation may be observed between the amount of studying a student does and their test scores. As the study time increases, the test scores also tend to increase.

Conversely, when the correlation coefficient is negative, it indicates a negative linear relationship between the variables. In this case, as one variable increases, the other variable tends to decrease.

For instance, a negative correlation may exist between the amount of rainfall and the number of hours spent outdoors. As rainfall increases, the time spent outdoors typically decreases.

Therefore, the sign of the correlation coefficient is crucial in understanding the direction of the correlation.

It provides valuable insights into how two variables are related to each other and helps researchers and analysts interpret the nature of their relationship.

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Answer:

C.) x = -5

Step-by-step explanation:

-4x = 20

x = -5

-4(-5) = 20

Answer:

C) x=-5

Step-by-step explanation:

-4x=20

divide both sides by -4.....

-4x÷-4=20÷-4

x=-5

Answer:

Look below

Step-by-step explanation:

Harriet- x books

June=3x-2

Substitute x for 13

(13x3)-2

39-2=37

June has 37 books

Answer:

x = - 2

Step-by-step explanation:

The axis of symmetry passes through the vertex, is a vertical line with equation equal to the x- coordinate of the vertex, that is

equation of axis of symmetry is x = 1

The zeros are equidistant from the axis of symmetry, on either side

x = 4 is a zero and is 3 units to the right of x = 1, so

3 units to the left of x = 1 is 1 - 3 = - 2

The other zero is therefore x = - 2

For a two-tailed hypothesis test with a sample size of 37 and a 0.10 level of significance, the critical values of the test statistic t are approximately ±1.691. These values determine whether we reject or fail to reject the null hypothesis based on the calculated t-value.

To find the critical values of the test statistic t for a two-tailed hypothesis test, we need to use the t-distribution table or statistical software. The critical values of t depend on the level of significance and the degrees of freedom (df), which are calculated as n-1, where n is the sample size.

For a two-tailed test with a level of significance of 0.10 and 37 degrees of freedom, we need to find the t-value that cuts off 0.05 of the area in each tail of the t-distribution. Using a t-distribution table or software, we find that the critical values of t are approximately ±1.691.

This means that if the calculated t-value falls outside the range of ±1.691, we reject the null hypothesis at the 0.10 level of significance, and conclude that there is significant evidence to support the alternative hypothesis. If the calculated t-value falls within the range of ±1.691, we fail to reject the null hypothesis and conclude that there is not enough evidence to support the alternative hypothesis.

It is important to note that the critical values of t depend on the sample size and the level of significance. As the sample size increases, the degrees of freedom increase and the t-distribution approaches the normal distribution. Also, as the level of significance decreases, the critical values of t become more extreme, making it harder to reject the null hypothesis.

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Approximately normal with mean is $206,274 and standard deviation is $3,788 and this can be determined by applying the central limit theorem, option A.

There were 5,317 previously owned homes sold in a western city in the year 2000.

The distribution of the sales prices of these homes was strongly right-skewed, with a mean of $206,274 and a standard deviation of $37,881.

Simple random samples of size 100.

According to the central limit theorem the approximately normal mean is $206274.

Now, to determine the approximately normal standard deviation, use the below formula:

\(s=\frac{\sigma}{\sqrt{n} }\)

where 's' is the approximately normal standard deviation, 'n' is the sample size, and  is the standard deviation.

Now, put the known values in the equation (1).

s = 37881 / √100

= 3788.1

s ≈ 3788

Therefore, option A is correct that Approximately normal with mean $206,274 and standard deviation $3,788.

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Complete question:

There were 5,317 previously owned homes sold in a western city in the year 2000. The distribution of the sales prices of these homes was strongly right-skewed, with a mean of $206,274 and a standard deviation of $37,881. If all possible simple random samples of size 100 are drawn from this population and the mean is computed for each of these samples, which of the following describes the sampling distribution of the sample mean?

(A) Approximately normal with mean $206,274 and standard deviation $3,788

(B) Approximately normal with mean $206,274 and standard deviation $37,881

(C) Approximately normal with mean $206,274 and standard deviation $520

(D) Strongly right-skewed with mean $206,274 and standard deviation $3,788

(E) Strongly right-skewed with mean $206,274 and standard deviation $37,881

Answer: 29.78

Step-by-step explanation:

Answer:

29.78

Step-by-step explanation:

calculator power hun.

Answer:

Option (4)

Step-by-step explanation:

Equation of a line passing through a point \((x_1,y_1)\) and with slope 'm' is,

y - y₁ = m(x - x₁)

Given → Slope 'm' = -2

Point through which the line is passing is (-1, -2)

x₁ = -1 and y₁ = -2

Therefore, equation will be,

y + 2 = -2(x + 1)

y = -2x - 2 - 2

y = -2x - 4

Option (4) is the correct option.

Answer:

Step-by-step explanation:

5x+5

Answer:

the first option will the correct answer

Answer:

5 containers high

Step-by-step explanation:

Given that :

Given :

Width = 20 containers

Length = 50 containers

Total containers = 5000

Hence,

Total containers = width * length * height

5000 = 20 * 50 * height

5000 = 1000 * height

Height = 5000 / 1000

Height = 5 containers

The expected difference is 0.17

A supermarket is a self-service store with various food, drink, and household goods options divided into categories. While this type of store is bigger and has a wider variety of products than older grocery stores, it is smaller and offers a smaller selection of goods than a hypermarket or big-box market. Fresh meat, produce, dairy, deli foods, baked goods, etc. may usually be found in the store.

Additionally, shelf space is set aside for canned and packaged goods as well as a variety of non-food items like pet supplies, cleaning supplies, cookware, and household cleansers.

The table is: 0 1 2 3

x1 0 0.08 0.06 0.04 0.00

1 0.05 0.18 0.05 0.03

2 0.05 0.04 0.10 0.06

3 0.00 0.03 0.04 0.07

4 0.00 0.01 0.05 0.06

Expected difference =

+(0.08*(0-0)) +(0.06*(0-1)) +(0.04*(0-2)) +(0.00*(0-3)) +(0.05*(1-0)) +(0.18*(1-1)) +(0.05*(1-2)) +(0.03*(1-3)) +(0.05*(2-0)) +(0.04*(2-1)) +(0.10*(2-2)) +(0.06*(2-3)) +(0.00*(3-0)) +(0.03*(3-1)) +(0.04*(3-2)) +(0.07*(3-3)) +(0.00*(4-0)) +(0.01*(4-1)) +(0.05*(4-2)) +(0.06*(4-3))

= 0.17

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The series has an alternating sign since every term is positive, and |(an + 1 / an)| is decreasing to 9/49. Therefore, we can use the Alternating Series Test to conclude that the series converges.

Using the Ratio Test:

lim n -> [infinity] |(9^(n+1) / ((n+1)+1)7^(2(n+1) + 1)) / (9^n / (n+1)7^(2n + 1))|

= lim n -> [infinity] |(9^(n+1) / 7^(2n+3)) * ((n+1)7^(2n+1) / (n+2)7^(2n+3))|

= lim n -> [infinity] |(9 / 49) * (n+1) / (n+2)|

= 9/49

Since the limit is less than 1, the series converges.

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The unit rate for each shirt if 24 shirts cost $259.36 as required to be determined is; $10.81.

It follows from the task content that the unit rate is to be determined if 24 shirts cost $259.36.

On this note, it follows that; the unit rate is given by the quotient;

Unit rate = Total cost / No. of units

Unit rate = 259.36 / 24

Unit rate = 10.80667.

Ultimately, the unit rate of the shirts as required is; $10.81.

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Answer:

11/50

Step-by-step explanation:

Answer:

He needs about 12.5 gallons with 0.5 left over.

Step-by-step explanation:

Answer: x ≠ -1/3

Step-by-step explanation:  (f/g)(x) = f(x)/g(x) = ∛2x/(3x+1)

hope this helps

The required in order for Micaela to end up with ,n = 365 , t = 12, P = $360, and A = $670

A relation is any subset of a Cartesian product.

As an illustration, a subset of is referred to as a "binary connection from

A binary relation from A to B is made up of these ordered pairs (a,b),

A to B," and more specifically, a "relation on A."

A binary relation from A to B is made up of these ordered pairs (a,b), here the first component is from A and the second component is from B.

Every item in a set X is connected to one item in a different set Y through a connection known as a function (possibly the same set).

A function is only represented by a graph, which is a collection of all ordered pairs (x, f (x)).

Every function, as you can see from these definitions, is a relation from X.

According to our question-

r=7.5%

Thus, 7.5% would be required in order for Micaela to end up with $670.

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Answer:

2, 5, 10, 50, 55, 275, 280

Step-by-step explanation:

hope this heled you.. :)

Answer:

The girl is 2.5 meters below sea level

Step-by-step explanation:

We are told in the question that:

A girl is snorkeling 1 meter below sea level

Hence, her elevation in meters below the sea level = -1m

We are told in the question that:

She then dives down another 1.5 meters

Once again: Her elevation in meters below the sea level = -1.5m

How far below sea level is the girl?

This is calculated as:

-1 m + -1.5m

= -1m - 1.5m

= -2.5m

Therefore, the girl is 2.5 meters below sea level

Answer:

475767u5yttuyy

Step-by-step explanation:

phobrovicodibfofiffivonf

The mean should be set to 12.07 ounces, so that 1% of the cups will overfill.

12 + (0.07 * 2) = 12.14; 12.14 - (12.14 * 0.01) = 12.07

The mean amount of coffee to be dispensed should be set to 12.07 ounces in order to allow 1% of the cups to overfill. This is calculated by taking the normal value of 12 ounces, and adding the standard deviation of 0.07 ounce, resulting in 12.14 ounces. Then, 1% of that value is subtracted, giving 12.07 ounces. This amount will ensure that 1% of the cups will overfill, while the other 99% will be filled to the normal value of 12 ounces. This is beneficial for the customer, as it guarantees that no cup will be underfilled. It also ensures that the vending machine will not waste any coffee by overfilling the cups too much. Setting the mean to 12.07 ounces is the best solution for both the customer and the vending machine.

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The speed of the car is 100 kilometers per hour, since it traveled 200 kilometers in 2 hours.

Speed = Distance/Time

Speed = 200 kilometers/2 hours

Speed = 100 kilometers/hour

The speed of a car is determined by dividing the distance traveled by the amount of time it took to travel that distance. In this case, the car traveled 200 kilometers in 2 hours. To calculate the speed of the car, we divide the distance (200 kilometers) by the time (2 hours). This gives us 100 kilometers per hour, which is the speed of the car. In other words, the car traveled 100 kilometers in 1 hour.

The speed of a car is an important factor in determining how fast a car can go. It is also important to consider other factors such as the weight of the car, the type of fuel it uses, and the road conditions. All of these factors can affect the speed of the car and should be taken into account when calculating the speed of a car. Knowing the speed of the car can help drivers make better decisions about their speed and can help prevent accident

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Answer:

28

Step-by-step explanation: You need to divide 7 by 1/4. Whenever you divide fractions you keep the first number as it is, change the sign to multiplication and write the reciprocal of the second fraction which is you have to flip the fraction. It is going to be 7 times 4/1. Which is 28/1 which is 28.

The volume of the largest rectangular box in the first octant with three faces in the coordinate planes, and one vertex in the plane is V = xyz, where x, y, and z are the lengths of the sides of the rectangular box.

To find the largest volume, we need to maximize x, y, and z. Since we have three faces in the coordinate planes, one vertex will be at the origin (0, 0, 0). The other two vertices will lie on the coordinate axes.

Let's assume the vertex on the x-axis is (x, 0, 0), and the vertex on the y-axis is (0, y, 0). The third vertex on the z-axis will be (0, 0, z). Since the box is in the first octant, all the coordinates must be positive.

To maximize the volume, we need to find the maximum values for x, y, and z within the constraints. The maximum values occur when the box touches the coordinate planes. Therefore, the maximum values are x = y = z.

Substituting these values into the volume formula, we get V = xyz = x³. Therefore, the volume of the largest rectangular box is V = x³.

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What is the maximum volume of a rectangular box situated in the first octant, with three of its faces lying on the coordinate planes, and one of its vertices located in the plane?

-11, -15, -19

================================================

Explanation:

Plug x = -11 into the function.

f(x) = x-4

f(-11) = -11-4

f(-11) = -15

The output -15 is now the input to set up the next iteration.

f(x) = x-4

f(-15) = -15-4

f(-15) = -19

The first three iterates are -11, -15, -19

Answer:

D) -15, -19, -23

Step-by-step explanation:

\(X_0=-11\)

\(X_1=(-11)-(-4)=-15\)

\(X_2=(-15)-(-4)=-19\)

\(X_3=(-19)-(-4)=-23\)

By using the concept of combinations, there are 13,122,848 ways.

For getting the number of ways to distribute 30 people into 4 distinct rooms with the given conditions, we will use the concept of combinations.

In the case of 2 people in room 3 and 26 in room 4, the number of ways to distribute them is:
²⁸C₂ = 28! / (2!(28-2)!) = 378

After calculating the total number of ways, we find that there are 13,122,848 ways to distribute 30 people into the 4 distinct rooms with the given conditions.

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Answer:

\(y=c_1\cos(x)+c_2\+\sin(x)+\sin^2(x)-\frac{1}{3}\sin^4(x)+\frac{1}{3}\cos^4(x)}}}\)

Step-by-step explanation:

Given the second-order differential equation, \(y'' + y = cos2(x)\), solve it using variation of parameters.

(1) - Solve the DE as if it were homogenous and find the homogeneous solution\(y'' + y = cos2(x) \Longrightarrow y'' + y =0\\\\\text{The characteristic equation} \Rightarrow m^2+1=0\\\\m^2+1=0\\\\ \Longrightarrow m^2=-1\\\\\ \Longrightarrow m=\sqrt{-1} \\\\\Longrightarrow \boxed{m=\pm i} \\ \\\text{Solution is complex will be in the form} \ \boxed{y=c_1e^{\alpha t}\cos(\beta t)+c_2e^{\alpha t}\sin(\beta t)} \ \text{where} \ m=\alpha \pm \beta i\)

\(\therefore \text{homogeneous solution} \rightarrow \boxed{y_h=c_1\cos(x)+c_2\sin(x)}\)

(2) - Find the Wronskian determinant

\(|W|=\left|\begin{array}{ccc}y_1&y_2\\y'_1&y'_2\end{array}\right| \\\\\Longrightarrow |W|=\left|\begin{array}{ccc}\cos(x)&\sin(x)\\-sin(t)&cos(x)\end{array}\right|\\\\\Longrightarrow \cos^2(x)+\sin^2(x)\\\\\Longrightarrow \boxed{|W|=1}\)

(3) - Find W_1 and W_2

\(\boxed{W_1=\left|\begin{array}{ccc}0&y_2\\g(x)&y'_2\end{array}\right| and \ W_2=\left|\begin{array}{ccc}y_2&0\\y'_2&g(x)\end{array}\right|}\)

\(W_1=\left|\begin{array}{ccc}0&\sin(x)\\\cos^2(x)&\cos(x)\end{array}\right|\\\\\Longrightarrow \boxed{W_1= -\sin(x)\cos^2(x)}\\\\W_2=\left|\begin{array}{ccc}\cos(x)&0\\ -\sin(x)&\cos^2(x)\end{array}\right|\\\\\Longrightarrow \boxed{W_2= \cos^3(x)}\)

(4) - Find u_1 and u_2

\(\boxed{u_1=\int\frac{W_1}{|W|} \ and \ u_2=\int\frac{W_2}{|W|} }\)\

u_1:

\(\int(\frac{-\sin(x)\cos^2(x)}{1}) dx\\\\\Longrightarrow-\int(\sin(x)\cos^2(x)) dx\\\\\text{Let} \ u=\cos(x) \rightarrow du=-sin(x)dx\\\\\Longrightarrow\int u^2 du\\\\\Longrightarrow \frac{1}{3}u^3\\ \\\Longrightarrow \boxed{u_1=\frac{1}{3}\cos^3(x)}\)

u_2:

\(\int\frac{\cos^3(x)}{1}dx\\ \\\Longrightarrow \int \cos^3(x)dx\\\\ \Longrightarrow \int (\cos^2(x)\cos(x))dx \ \ \boxed{\text{Trig identity:} \cos^2(x)=1-\sin^2(x)}\\\\\Longrightarrow \int[(1-\sin^2(x)})\cos(x)]dx\\\\\Longrightarrow \int \cos(x)dx-\int (\sin^2(x)\cos(x))dx\\\\\Longrightarrow \sin(x)-\int (\sin^2(x)\cos(x))dx\\\\\text{Let} \ u=\sin(x) \rightarrow du=cos(x)dx\\\\\Longrightarrow \sin(x)-\int u^2du\\\\\Longrightarrow \sin(x)-\frac{1}{3} u^3\)\

\(\Longrightarrow \boxed{u_2=\sin(x)-\frac{1}{3} \sin^3(x)}\)

(5) - Generate the particular solution

\(\text{Particular solution} \rightarrow y_p=u_1y_1+u_2y_2\)

\(\Longrightarrow y_p=(\frac{1}{3}\cos(x))(\cos(x))+(\sin(x)-\frac{1}{3} \sin^3(x))(\sin(x))\\\\ \Longrightarrow y_p=\frac{1}{3}\cos^4(x)+\sin^2(x)-\frac{1}{3}\sin^4(x)\\\\\Longrightarrow \boxed{y_p=\sin^2(x)-\frac{1}{3}\sin^4(x)+\frac{1}{3}\cos^4(x)}\)

(6) - Form the general solution

\(\text{General solution} \rightarrow y_{gen.}=y_h+y_p\)

\(\boxed{\boxed{y=c_1\cos(x)+c_2\+\sin(x)+\sin^2(x)-\frac{1}{3}\sin^4(x)+\frac{1}{3}\cos^4(x)}}}\)

Thus, the solution to the given DE is found where c_1 and c_2 are arbitrary constants that can be solved for given an initial condition. You can simplify the solution more if need be.

Answer:

(x+2)^2 - 6

Step-by-step explanation: