at 313 k, this reaction has a Kc value of 0.0689. x(g) 2y(g)↽−−⇀ 2z(g) calculate Kp at 313 k. note that the pressure is in units of atmosphere (atm).try to derive the result before looking at the hint. recall that from the ideal gas law we can write: p

Answer: 26.07 g Zn if need to correct sig figs its 26 g Zn

Explanation:

use stoichiometry to solve

2.4 X 10^23 atoms Zn X (1mole Zn / 6.02 X 10^23 atoms Zn) X (65.38 g Zn/ 1 mole Zn) =

26.07 g Zn

The process that is not a way for carbon dioxide to reach the atmosphere is Photosynthesis; option C

The carbon cycle is a biogeochemical cycle that describes the processes by which carbon is recycled between the living and non-living components of the environment.

The processes by which carbon is removed from the atmosphere and the processes by which carbon is returned to the atmosphere work together to ensure there is a balance of carbon in the environment.

The processes by which carbon is returned to the atmosphere in the form of carbon dioxide include the following:

The processes by which carbon is removed from the atmosphere include the following:

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Complete question:

Which of the following is not a way for carbon dioxide to reach the atmosphere?

a. forest fires

b. respiration

c. photosynthesis

d. burning of fossil fuels

Explanation

To find the molar mass of sulfur dihydride, you will need to find the sum of all the atomic masses making up sulfur dihydride.

sulfur dihydride is H2S.

Atomic mass of H = 1,00784 u

Atomic mass of S = 32,065 u

Molar mass = (1.00784 x 2) + 32,065 = 34.081 g/mol

Answer

34.081 g/mol

An atom's radius is well under 1 nanometer, or one billionth of a meter.

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\(2\text{Cr(NO}_3\text{)}_3} + 3\text{CuCl}_2 \longrightarrow 2\text{CrCl}_3 + 3\text{Cu(NO}_3\text{)}_2\)

Powdered persulfate salts added to haircolor to increase its lightening ability are c. activators.

Powdered persulfate salts are commonly used as activators in haircoloring products to increase their lightening ability. These activators help to break down the natural pigments in the hair, allowing the new color to be absorbed more effectively.

Activators, such as powdered persulfate salts, are mixed with hair color to increase the lightening ability. They help to break down the melanin in hair, allowing the hair color to penetrate deeper and lighten the hair more effectively. Accelerators speed up the processing time, ammonias are alkaline agents that open the hair cuticle, and diffusers are not related to hair color lightening.

The correct answer is c. activators, as they are the powdered persulfate salts added to hair color to enhance its lightening ability.

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Answer:

0.3M

Explanation:

Find the amount concentration of the anion in a 0.100 mol/L solution of Al(CIO3)3.

FOR EVERY MOLE OF Al(CIO3)3., THERE ARE 3 MOLES OF CIO3.

SO IN A 0.00m SOLUTION, THE CONCENTRATION OF THE ANION

ClO3 IS 3X0.1M = 0.3M

.

Answer:

i would say shape because the other answers do not logically compute. A is a transformation from solids to liquids or vice versa  what B is and C IS THE ANSWER because the only action that is occurring is the tearing of the previous shape of the paper.

Explanation:

Answer:

The correct answer is Choice D.

(Headaches or backaches)​

Explanation:

Hope this helps!

Please mark me as Brainlinieast.

The gas chromatography column has approximately 31,106 theoretical plates.

The number of theoretical plates in a gas chromatography column can be calculated using the formula:

N = 5.54 * (tR / w)^2

The number of theoretical lates in a gas chromatography column can be calculated using the formula:

N = 5.54 * (tR / w)^2

Where N represents the number of theoretical plates, tR is the retention time of the peak, and w is the peak width at its base.

In this case, the peak elutes at 15.0 minutes (tR = 15.0 min) and has a peak width of 12 seconds (w = 12 s).

First, we need to convert the retention time and peak width to the same unit, either minutes or seconds. Let's convert the retention time to seconds:

tR = 15.0 min * 60 s/min = 900 s

Now we can calculate the number of theoretical plates using the given values:

N = 5.54 * (900 s / 12 s)^2

N = 5.54 * (75)^2

N = 5.54 * 5625

N ≈ 31,106

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The answer is 58.4 g of H₃PO₄

Given that mass of Ca₃(PO₄)₂ is 153g

mass of H₂SO₄ is 87.6g

We need to calculate the mass of H₃PO₄

So the balanced chemical reaction is

Ca₃(PO₄)₂  +  3H₂SO₄  ⇒   3CaSO₄  +  2H₃PO₄

Let us calculate the molar mass of the reactants

Ca₃(PO₄)₂ = (3 x 40) + (2 x 31) + (8 x 16)

= 120 + 62 + 128

= 310 g

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4)

= 2 + 32 + 64

= 98 g

Now let us calculate the limiting reactant

The Theoretical Yield =  Ca₃(PO₄)₂ / H₂SO₄

= 310 / 3(98)

= 1.05

The Experimental yield

Ca₃(PO₄)₂ / H₂SO₄

= 153 / 87.6 = 1.74

Because the observed percentage was more than the predicted proportion, H2SO4 is the limiting reactant.

Let us Calculate the molar mass of H₃PO₄

H₃PO₄ = (1 x 3) + (31 x 1) + (16 x 4)

= 3 + 31 + 64

= 98 g

Now Calculate the mass of H₃PO₄

3(98) g of H₂SO₄ ------------------ 2(98) g of H₃PO₄

87.6 g of H₂SO₄ ------------------  x

x = ( 87.6 x 2 x 98) / (3 x 98)

x = 17169.6 / 294

x = 58.4g of H₃PO₄

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The two ways in which the physical state of matter can be changed are melting and freezing.

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Answer:

c

Explanation:

Answer:

the answer of the question is C

The volume of 8.8g of carbon dioxide at STP is 4.38 L.

1 mole of any gas will take up 22.4 L of space at standard temperature and pressure (STP). A balanced chemical equation and the Ideal Gas Law can be used to determine the amount or mass of gas consumed or created in a chemical process.

n = m/M

where m is the molar mass of carbon dioxide and M is its mass in terms of molecules.

Considering that the molar mass of carbon dioxide is 44.01 g/mol:

n = 8.8 g / 44.01 g/mol

n = 0.1998 mol

Next, we can plug in the values of n, R, P, and T into the ideal gas law and solve for V:

V = (nRT)/P

V = (0.1998 mol x 0.0821 L·atm/(mol·K) x 273.15 K) / 1 atm

V = 4.38 L

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Answer:

HEAT OF COMBUSTION PER GRAM OF OCTANE IS 1723.08 J OR 1.72 KJ/G OF HEAT

HEAT OFF COMBUSTION PER MOLE OF OCTANE IS 196.4 KJ/ MOL OF HEAT

Explanation:

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

In other words, 3101.56 J of heat was evolved from the reaction of 1.8 g octane with water.

Heat of combustion of octane per gram:

1.8 g of octane produces 3101.56 J of heat

1 g of octane will produce ( 3101.56 * 1 / 1.8)

= 1723.08 J of heat

So, heat of combustion of octane per gram is 1723.08 J

Heat of combustion per mole:

1.8 g of octane produces 3101.56 J of heat

1 mole of octane will produce X J of heat

1 mole of octane = 114 g/ mol of octane

So we have:

1.8 g of octane = 3101.56 J

114 g of octane = (3101.56 * 114 / 1.8) J of heat

= 196 432.13 J

= 196. 4 kJ of heat

The heat of combustion of octane per mole is 196.4 kJ /mol.

Mass of water = 100 g

Change in temperature = 28.78 °C - 21.36°C = 7.42 °C

Heat capcacity of water = 4.18 J/g°C

Mass of octane = 1.8 g

Molar mass of octane = C8H18 = (12 * 8 + 1 * 18) g/mol= 96 + 18 = 114 g/mol

First is to calculate the heat evolved when 100 g of water is used:

Heat = mass * specific heat capacity * change in temperature

Heat = 100 * 4.18 * 7.42

Heat = 3101.56 J

Answer:

Nuclear Fission is a nuclear reaction or a Radioactive decay progress in which the necleus of an atom splits into two or more smaller, lighter neclei

During translation, the process by which the genetic code in RNA is used to synthesize a polypeptide (protein), the amino acid that always begins the polypeptide is a methionine (abbreviated as Met).

This is because the start codon in RNA, which marks the beginning of the protein sequence, codes for the amino acid methionine. The genetic code is a set of rules that dictate how the sequence of nucleotides in RNA corresponds to the sequence of amino acids in a protein. Each three-nucleotide sequence in RNA is called a codon, and each codon codes for a specific amino acid. The start codon in RNA is the codon AUG, which codes for the amino acid methionine.

Once the methionine residue is added to the growing polypeptide chain, the rest of the amino acids are added in order according to the genetic code. The methionine residue is essential for the proper folding and function of the protein, as it is involved in the formation of the protein's first protein-protein interaction.

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when electric current is passed through an electrolytic cell we can recognise that electrolysis is taking place by :

*there may bubbles of different gases formed on the electrodes.

*if we add vinegar or lime juice we find more bubbles forming

by the we can identify

The Percent error for ice and salt water is 94.55%. The Percent error for ice water is 100.40%.

Absolute zero is the temperature whereby a system in its balanced state contains the lowest energy that corresponds to -273.15 °C.

Using the formula for Percent error, we have:

\(\mathbf{percent \ error = \dfrac{|experimental \ value| - |actual \ value| }{|actual \ value|} \times 100\%}\)

For ice and salt water:

\(\mathbf{percent \ error = \dfrac{|-14.9 -(-273.15)| }{|-273.15|} \times 100\%}\)

Percent error = 94.55%

For Ice water:

\(\mathbf{percent \ error = \dfrac{|1.1 -(-273.15)| }{|-273.15|} \times 100\%}\)

Percent error = 100.40%

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Answer:

You need to make sure the number of atoms of each element on the reactant side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal. :)

Answer:

covalent

Explanation:

Answer:

ok here is you answer

Explanation:

Blood is a liquid because it is composed of cells and plasma that are suspended in a liquid state and can easily flow through the circulatory system, delivering oxygen and nutrients to cells and removing waste products.

b) Filter the sample. If a solid does not completely dissolve in a solvent, the undissolved solid particles can be removed by filtering the sample. This is usually done by passing the mixture through a filter paper.

If a solid does not completely dissolve in a solvent, it is important to properly handle the mixture to obtain a clear solution. One option is to filter the sample to remove the undissolved solid particles. This can be done by passing the mixture through a filter paper or a filter apparatus. The filtered solution can then be used for further analysis or experimentation. Another option is to keep stirring the mixture in the hope that the solid will eventually dissolve. If this is not successful, adding more of the solid to the solvent may help increase the solubility of the substance. However, it is important to consider the solubility limits of the substance in solvent the solvent and to not exceed them, as this may result in a saturated solution.

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Answer:

\(P_2=1.3atm\)

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to model the solubility and pressure of the gas, by knowing that the greater the pressure, the greater the solubility, so that the suitable equation is:

\(\frac{P_2}{s_2}=\frac{P_1}{s_1}\)

In such a way, we will be able to calculate the pressure of the gas by solving for P2 as shown below:

\(P_2=\frac{P_1*s_2}{s_1} \\\\\)

And finally plug in the given data to obtain:

\(P_2=\frac{4.0atm*1.0g/L}{3.0g/L}\\\\P_2=1.3atm\)

Regards!

Answer:

The molar mass of a substance is calculated as the mass of a given chemical compound or substance, which is then divided by the amount of the substance. The mass is calculated in grams and the amount of the substance is calculated in mol. Thus, the standard unit for molar mass is g/mol.

Explanation:

According to the given question, the reaction between iron chloride and sodium carbonate will be given as:  

\(\text {3Na_{2}CO_{3}\text} \;\[+\] \;\text{ 2FeCl_{3} \text}\; \rightarrow\; \text {6NaCl}\; \[+\] \;\text { Fe_{2} (CO_3)_{3} \text}\)

Now, to calculate the mass of iron carbonate formed in the above chemical reaction, it will be given as:

\({ \text Moles\;of}\text \;\text {FeCl_{3} \text} \[=\dfrac{0.15 \;\text {moles} \times 0.015\; \text L}{1.0 { \;\text L}\text}\)

                          \(=\;0.00225\; \text {moles}\text\)

Similarly, for sodium carbonate

\(\text Moles\; of\; Na_{2}CO_{3}}\te \[=\]\dfrac{0.15 \;\text {moles} \times 0.020\; \text L}{1.0 { \;\text L}\text}\\\)

                             \(\[=\]\;0.0003\; {\text moles \text}\)

Limiting reactant is \(\text {FeCl_{3} \text}\)

Now, calculating iron chloride mass:

\(=\dfrac{0.00225 \times 1\;\text{moles}\;\text{Fe}_2 {(\text{CO}_3)}}{2\;\rm{moles\;of\;}Fecl_3}\)

\(=0.001125 \;\text {moles }\)

Now, molar mass of the \(\text{Fe}_{2}\text{CO}_{3}\)  will be  \(=291.71679\;\text{g/ mol}\)

\(\begin{aligned}\text{Mass}&=\frac{\text{Moles}}{\text{Molar mass}}\\\\&=\frac{0.001125\;\text{moles}}{291.71679\; \text{g/mol}} \\\\&=3.85648\times10^{-6} \end{aligned}\)

Answer:

New volume of chlorine gas (V2) = 179 ml (Approx)

Explanation:

Given:

Volume of chlorine gas (V1) = 193 ml

Temperature of chlorine gas (T1) = 21°C = 21 + 273 = 294 k

New temperature of chlorine gas (T2) = 0°C = 0 + 273 = 273 k

Find:

New volume of chlorine gas (V2) = ?

Computation:

Using charle's law

V1 / T1 = V2 / T2

193 / 294 = V2 / 273

V2 = 179.21

New volume of chlorine gas (V2) = 179 ml (Approx)

Answer:

1. Equivalence point

2. Direct titration

3. Primary standard

4. Titrand

5. Back titration

6. Standard solution

7. Titrant

8. Indirect titration

9. End point

10. Indicator

Explanation:

1. The equivalence point is the tiration point at which the quantity or moles  of the added titrant is sufficient or equal to the quantity or moles of the analyte for the neutralization of the solution of the analyte.

2. Direct titration is a method of quantitatively determining the contents of a substance

3. A primary standard is an easily weigh-able representative of the mount of moles contained in a substance

4. A titrand is the substance of unknown concentration which is to be determined

5. The titration method that uses a given amount of an excess reagent to determine the concentration of an analyte is known as back titration

6. A standard solution is a solution of accurately known concentration

7. A titrant is a solution that has a known concentration and which is titrated unto another solution to determine the concentration of the second solution

8. Indirect titration is the process of performing a titration in athe reverse order

9. The end point is the point at which the indicator indicates that the equivalent quantities of the reagents required for a complete reaction has been added

10 An indicator is a compound used to visually determine the pH of a solution.

The titration has been the neutralization reaction in which the titrand and the titrant react to form the salt and the water and help in the determination of the qualitative and quantitative properties.

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Answer:

4 meters

Explanation:

4 centimeters and millimeters are too small, while 4 kilometers is too large.

A change of one unit on the pH scale represents a change in the concentration of hydrogen ions by a factor of 10, a change in two units represents a change in the concentration of hydrogen ions by a factor of 100. Thus, small changes in pH represent large changes in the concentrations of hydrogen ions.

We must establish the relative proportions of each element present in the sample in order to calculate the empirical formula of the compound.

From the masses supplied, we can determine the number of moles of each element in a 100 g sample of the compound:

Moles of carbon = 165 g / 12.01 g/mol = 13.74 mol

Moles of hydrogen = 27.8 g / 1.01 g/mol = 27.52 mol

Moles of oxygen = 220.2 g / 16.00 g/mol = 13.76 mol

The empirical formula uses the compound's simplest whole number atom ratio. We divide each of the mole values by the smallest mole value, in this case 13.74 mol, to get the following ratio:

Carbon: 13.74 mol / 13.74 mol = 1

Hydrogen: 27.52 mol / 13.74 mol = 2

Oxygen: 13.76 mol / 13.74 mol = 1

Therefore, the empirical formula of the compound is \(CH_{2} O\).

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