assuming a constant dew point temperature, how do temperature and relative humidity typically vary over a 24-hour period?
Answers
Changes in relative humidity are more common than changes in dew point. Assuming dew point to be relatively constant over a 24-hour period, relative humidity values change regularly throughout the day as temperatures rise and fall.
When the temperature and dew point are close, the relative humidity is higher than when the temperature and dew point are far apart. At the same temperature and dew point, the air is "saturated" and the relative humidity is 100%.
Clouds form when the temperature drops below the dew point. On the ground, temperatures often drop below the dew point, such as during heavy rains or foggy mornings.
The "relative humidity" of air describes the relationship between temperature and dew point.
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Related Questions
how does the speed of the water in the constriction compare to the speed of the water in the rest of the pipe?
Answers
The speed of water in the constriction is faster when compared to the rest of the pipe.
The venturi effect consists of a physical phenomenon applied in fluid dynamics in which the pressure of flow decreases when there is a constraint in the conduct, accompanied by an increase in velocity of the fluid due to a decrease in cross-sectional area of the conduct.
The constriction is said to have a lower radius when compared to the rest of the pipe.
Applying the equation of continuity, A₁ v₁ = A₂ v₂
where, A is the area
v is the velocity
It is said from the above equation that, if area decreases velocity increases and if area increases velocity decreases, as velocity and area are inversely proportional to each other.
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What is the kinetic energy of an object that has a mass of 50. 0 kg and a velocity of 18 m/s? 450 J 900 J 8,100 J 16,000 J.
Answers
The kinetic energy of an object that has a mass of 50.0 kg and a velocity of 18m/s is 8,100J.
KINETIC ENERGY:Kinetic energy refers to the energy of a body due to its motion. The kinetic energy can be calculated as follows:
K.E = ½ m × v²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, an object that has a mass of 50.0 kg and a velocity of 18m/s. The kinetic energy can be calculated as follows:
K.E = ½ × 50 × 18²
K.E = ½ × 16,200
K.E = 8100J.
Therefore, the kinetic energy of an object that has a mass of 50.0 kg and a velocity of 18m/s is 8,100J.
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To find the change in the electric potential from point/to point f, which do we do? a. We find the ratio of the electric field to the distance between the points. b. We find the ratio of the distance between the points to the electric field. c. We integrate the negative of the electric field along a path from i to f. d. We integrate the negative of the electric field along a path from f to i. e. We differentiate the electric field with respect to distance along the path from i to f.
Answers
The correct option is the third option that is we integrate the negative of the electric field along a path from i to f.
We can find the electrostatic potential at any point due to each individual charge by considering the other charges absent. We then add all the charges algebraically. Hence, the electric potential at a point due to a group of point charges is the algebraic sum of all the potentials due to individual charges. To find the change in the electric potential from point/to point f, we have the following options a. We find the ratio of the electric field to the distance between the points. b. We find the ratio of the distance between the points to the electric field. c. We integrate the negative of the electric field along a path from i to f. d. We integrate the negative of the electric field along a path from f to i. e. We differentiate the electric field with respect to distance along the path from i to f. Hence with this information we can consider that the correct option is the third option that is we integrate the negative of the electric field along a path from i to f.
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Given the following velocity time graph of 7kg object what is the impulse during segment c (from35 to 55 seconds)
Answers
Answer:
9,11 N.s.,.................
If 2 kilograms of water is to be heated from 24.0°C to 100.0°C to make a cup of tea, how much heat must be added? (Water's specific heat is 4186 J/kg°C)A. 640 JB. 64 JC. 640,000 JD.64,000 J
Answers
Answer:
The amount of heat needed to heat 2 kilograms of water from 24.0°C to 100.0°C to make a cup of tea is (C) 640,000 J.
Explanation:
How to calculate the amount of heat needed?
The amount of heat needed can be calculated from the equationQ = m s Δ t
where Q = the amount of heat needed
m = mass of the substance being heated
s = specific heat of the substance being heated
and Δ t = the difference between the final and initial temperatures.
It is given that 2 kilograms of water are to be heated from 24.0°C to 100.0°C to make a cup of tea and the specific heat of water is 4186 J/kg°C.
Therefore,
m = 2 kgs = 4186 J/kg°CΔ t = ( 100 - 24 )°C = 76 °CPutting these values in the equation Q = m s Δ t we find,
Q = 2 x 4186 x 76 J
= 636272 J
≈ 640,000 J.
Thus the amount of heat needed to heat 2 kilograms of water from 24.0°C to 100.0°C to make a cup of tea is (C) 640,000 J.
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A force F is exerted on a 2.0 kg block to move it across a rough surface. The magnitude of the force is initially 5 N, and the block moves at constant velocity. While the block is movingthe force is instantaneous increases to 12 N. How much kinetic energy does the block now gain at it moves a distance of 2 m?
Answers
The block gains 4.49 J of kinetic energy as it moves a distance of 2 m
What is kinetic energy of the block?The increase in kinetic energy of an object can be calculated using the equation:
ΔKE = 1/2 (m)(Δv^2)
where;
m is the mass of the object, Δv is the change in velocity, and ΔKE is the change in kinetic energy.To find the change in velocity, we can use the equation of motion, which states that the net force on an object is equal to its mass times its acceleration:
F = ma
Rearranging this equation, we can find the acceleration:
a = F / m
The acceleration is the same before and after the force increases, so we can equate the two and solve for Δv:
F1 / m = F2 / m
F1 / m = (F1 + ΔF) / m
ΔF / m = F2 / m - F1 / m
ΔF / m = (12 N) / (2 kg) - (5 N) / (2 kg)
ΔF / m = 4.5 m/s^2
Δv = √(2 * ΔF / m)
Now that we have Δv, we can plug this value into the equation for ΔKE:
ΔKE = 1/2 * m * Δv^2
ΔKE = 1/2 * 2 kg * (2.12 m/s)^2
ΔKE = 4.49 J
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if red light of wavelength 700 nm in air enters glass with index of refraction 1.5, what is the wavelength λ of the light in the glass? express your answer in nanometers to thre
Answers
The wavelength of the red light in the glass is approximately 466.67 nm.
When light passes from one medium to another, its wavelength changes due to the difference in the speed of light in each medium. The relationship between the wavelength in one medium \((\(\lambda_1\))\) and the wavelength in another medium \((\(\lambda_2\))\) is given by:\(\[\frac{\lambda_1}{\lambda_2} = \frac{v_1}{v_2}\]\)where \(\(v_1\)\) and \(\(v_2\)\) represent the speeds of light in the first and second mediums, respectively. The speed of light in a medium is related to its refractive index (n) as follows:\(\[v = \frac{c}{n}\]\)where c is the speed of light in a vacuum. Rearranging the equation, we have:\(\[\lambda_2 = \frac{\lambda_1}{n}\]\)Given that the wavelength of red light in air \((\(\lambda_1\))\) is 700 nm and the refractive index of glass \((\(n\))\) is 1.5, we can calculate the wavelength of the light in the glass \((\(\lambda_2\))\):\(\[\lambda_2 = \frac{700 \, \text{nm}}{1.5} \approx 466.67 \, \text{nm}\]\)Therefore, the wavelength of the red light in the glass is approximately 466.67 nm.For more questions on wavelength
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The wavelength of the red light in the glass is approximately 466.67 nm.
To find the wavelength of light in a different medium, we can use Snell's law, which relates the angle of incidence and angle of refraction to the indices of refraction of the two media.
Snell's law states: n1 * sin(θ1) = n2 * sin(θ2)
Where n1 and n2 are the indices of refraction of the initial and final media, θ1 is the angle of incidence, and θ2 is the angle of refraction.
In this case, the light is traveling from air (n1 = 1) to glass (n2 = 1.5). Since we are given the wavelength of the light in air (700 nm), we need to find the corresponding wavelength in glass (λ).
The ratio of the wavelengths in the two media is given by: λ1 / λ2 = v1 / v2
Since the speed of light is reduced in the glass due to the higher refractive index, v2 = v1 / n2.
Substituting the values, we have: λ1 / λ2 = v1 / (v1 / n2) = n2
Therefore, λ2 = λ1 / n2 = 700 nm / 1.5 = 466.67 nm (rounded to three significant figures).
Hence, the wavelength of the red light in the glass is approximately 466.67 nm.
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Water flows at the rate 1.17 along a level channel of width 1.7 m with a depth of 149 mm. An hydraulic jump occurs. Calculate the critical depth in mm. Answer:
Answers
The critical depth in the hydraulic jump can be calculated using the specific energy equation. In this case, with a flow rate of 1.17 m³/s, channel width of 1.7 m, and a depth of 149 mm, the critical depth can be determined.
To calculate the critical depth in the hydraulic jump, we can use the specific energy equation, which relates the flow rate, channel dimensions, and water depth. The equation can be written as:
E = (Q² / (2g)) + (y² / (2g)) + (A² / (P * g))
Where:
E is the specific energy,
Q is the flow rate,
g is the acceleration due to gravity,
y is the water depth,
A is the cross-sectional area of flow,
P is the wetted perimeter of the channel.
In this case, we have a flow rate of 1.17 m³/s, a channel width of 1.7 m, and a depth of 149 mm (or 0.149 m). We need to find the critical depth, which occurs at the hydraulic jump. At the critical depth, the specific energy reaches its minimum value.
To determine the critical depth, we need to set the derivative of the specific energy equation with respect to the water depth equal to zero and solve for y. This will give us the critical depth. However, calculating the critical depth requires knowing additional parameters such as the cross-sectional area and wetted perimeter, which are not provided in the given information. Without these values, it is not possible to calculate the critical depth accurately.
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Ionic compounds _____.
Answers
Explanation:
Are the compounds formed by the ionic bonding or electronic bonding. They are formed by transferring the electron form one element's valance shell to other element's shell.
i hope it helps...
When poked by a spear, an operatic soprano lets out a 1175 Hz shriek. What is its wavelength (in m) if the speed of sound is 345 m/s
Answers
When poked by a spear, an operatic soprano lets out a 1175 Hz shriek. The question asks for the wavelength (in m) if the speed of sound is 345 m/s. Here's the solution to this question: We know that speed = frequency × wavelength Speed of sound (v) = 345 m/s Frequency (f) = 1175 Hz Wavelength = To calculate the wavelength,
we use the formula: Wavelength = speed of sound / frequency Therefore, the wavelength is given by Wavelength = v / f = 345 / 1175 ≈ 0.2936 m or 29.36 cm Therefore, the wavelength of the 1175 Hz sound is approximately 0.2936 meters or 29.36 cm.
Note: The wavelength is a physical quantity that describes the distance between two consecutive points of the same phase on a wave. It is measured in meters (m) or centimeters (cm).
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Two waves leave the same source in phase. The waves travel along different paths and then meet. The wavelength of the waves is 8.0 cm. Which of the following would cause constructive interference when the waves meet?
A path difference of 16.0 cm
B path difference of 3λ/2
C phase difference of 180°
D phase difference of 3π radians
Answers
Answer:
A path difference of 16.0 cm would cause constructive interference when the waves meet.
Explanation:
For constructive interference to occur, the path difference between the waves must be equal to an integer number of wavelengths. In this case, the wavelength is given as 8.0 cm.
Option A gives a path difference of 16.0 cm, which is equal to two wavelengths. Therefore, the two waves will arrive at the meeting point in phase and will reinforce each other, resulting in constructive interference.
Option B gives a path difference of 12.0 cm, which is equal to 1.5 wavelengths. This will result in destructive interference rather than constructive interference.
Option C and D refer to phase differences rather than path differences, and alone they are not enough to determine whether constructive or destructive interference will occur.
Constructive interference occurs when the waves are in phase and their amplitudes add up.
A path difference of one wavelength (λ) corresponds to a phase difference of 2π radians, so a path difference of 2λ corresponds to a phase difference of 4π radians, and so on.
Therefore, a path difference of 16.0 cm corresponds to a phase difference of 2π x 16.0 cm / 8.0 cm = 4π radians, which is a multiple of 2π and results in constructive interference.
A path difference of 3λ/2 corresponds to a phase difference of 3π radians, which is also a multiple of 2π and results in constructive interference.
A phase difference of 180° corresponds to a path difference of λ/2, which is not a multiple of the wavelength and results in destructive interference.
A phase difference of 3π radians corresponds to a path difference of 3λ/2, which we already determined results in constructive interference.
Therefore, the answers that would cause constructive interference when the waves meet are A and D.
For each method - sometimes used a s heuristic, what is the distance from start to end? (ignore any coloring in the boxes)
Answers
Manhattan distance is a popular heuristic function for sliding-tile puzzles. It is calculated by tallying the number of moves along the grid that each tile takes to move away from its intended position.
What is the Manhattan distance heuristic?Manhattan distance is a popular heuristic function for sliding-tile puzzles. It is calculated by tallying the number of moves along the grid that each tile takes to move away from its intended position. The obvious option for a heuristic function is the Euclidean (straight-line) distance, which, as far as we are aware, can never underestimate the distance but might do so if there is a target obstacle to avoid on the way there.
Any problem-solving strategy that employs a practical approach or numerous short cuts in order to provide answers that might not be ideal but are adequate given a constrained timeline or deadline is known as a heuristic, or heuristic technique.
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A 7 kg block is placed on a flat table. A force of 7 newtons is applied to the block parallel to the table. The block moves with a constant velocity.
What is the coefficient of this frictional force?
Answers
The coefficient of the frictional force on the block is 0.102.
The given parameters;
mass of the block, m = 7 kgforce applied, F = 7 NThe normal force on the block is calculated as follows;
\(F_n = mg\\\\F_n = 7 \times 9.8\\\\F_n = 68.6 \ N\)
The frictional force on the block is calculated as;
\(F_f = \mu F_n\\\\F_f = 68.6 \mu\)
The net horizontal force on the block is calculated as;
\(\Sigma F = 0\\\\F - F_f = 0\\\\F_f = F\\\\68.6 \mu = 7\\\\\mu = \frac{7}{68.6} \\\\\mu = 0.102\)
Thus, the coefficient of the frictional force on the block is 0.102.
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Placing a soccer ball on the top shelf increases the...
Kinetic energy
Chemical energy
Gravitational potential energy
Elastic potential energy
Answers
Answer:
Gravitational potential energy
Explanation:
PE = m*g*h
m = mass
g = 9.81m/s², acceleration of gravity
h = height
So m and g stay the same but the height can change so the higher you go the higher the Gravitational potential energy.
Placing a soccer ball on the top shelf increases the Gravitational potential energy
what is Gravitational potential energy ?In a gravitational field the energy possessed by an object due to a change in its position called as gravitational potential energy, it is an energy that is related to gravitational force or to gravity.
When a mass of the body (m) is moved from infinity to a point inside the gravitational influence of a source mass (M) in absence of acceleration and the amount of work done in displacing it into the source field is stored in the form of potential energy denoted with the symbol Ug.
when external force is applied, then the position of the body changes potential energy is equal to the amount of work done on the body by the forces.
The gravitational influence on a body at infinity is zero, then the potential energy is zero, PE = m*g*h where m = mass, g = 9.81m/s², acceleration of gravity, h = height
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One year consists of 365 days. this is closest to how many seconds?
Answers
1 year has 365 days
1 day has 24 hours
Each hour has 60 minutes
And each minute has 60 seconds
The number of seconds in 365 days is 365x24x60x60 = 31536000
So there is 31536000 seconds in 1 year
Hope it helped you!!
If one year consists of 365 days, this is closest to x = 3.15 × 10⁷ seconds.
What is the number of seconds in a year?
Given that;
Number of days in a year = 365Number of seconds in 365 days = ?Note that; there are 24 hours in a day, 1440 minutes in a day and 86400 seconds in a days.
1 day contains 86400 seconds
365 contains x seconds
x = 365 × 86400
x = 3.15 × 10⁷ seconds
Therefore, if one year consists of 365 days, this is closest to x = 3.15 × 10⁷ seconds.
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What is The average power supplied by 600 N student running up a flight of stairs right in vertically 4.0 MN 4.2 is
Answers
The average power supplied by a 600 N student running up a flight of stairs right in vertically 4.0 m in 4.2 s is 887.73 W (watts). the average power supplied by a 600 N student running up a flight of stairs right in vertically 4.0 m in 4.2 s is 887.73 W (watts).
According to the given information:The given data:
Force (F) = 600 N
Displacement (d) = 4.0 m
Time (t) = 4.2 s
The formula for average power can be given as:
Average power = Work done / time taken
The work done (W) can be found out using the formula:
W = F × dW = 600 N × 4.0 mW = 2400 J
Substituting the values in the formula for average power:
Average power = Work done / time taken
Average power = 2400 J / 4.2 s
Average power = 571.42 W
Thus, the average power supplied by a 600 N student running up a flight of stairs right in vertically 4.0 m in 4.2 s is 887.73 W (watts).
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when the angle of inclination of the inclined plane increases, what will happen to the acceleration along the inclined plane?
Answers
When there is acceleration along the inclined plane then accelerations increase as incline angles increase.
angle of inclination :
The angle between a line's inclination and the x-positive axis's direction is known as the inclination.This angle's value ranges from 0° to 180°.It is measured counterclockwise around the positive x-axis direction.The force component parallel to the incline rises as the angle increases, while the force component perpendicular to the incline falls. The acceleration is brought on by the parallel portion of the weight vector.
Therefore, accelerations increase as incline angles increase.
When there is acceleration along the inclined plane then accelerations increase as incline angles increase.
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A current of 5. 0 amperes is passing through a piece of wire. Determine how long it takes for 30 coulombs of charge to pass through this wire
Answers
The time taken for the charge to pass through the cross-section of the wire is 6.0s.
Given the data in the question;
Current; \(I = 5.0A\)
Charge; \(Q = 30C\)
Time; \(t = \ ?\)
CurrentCurrent is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.
If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;
\(I = \frac{Q}{t}\)
Where Q is the charge and t is time elapsed.
We substitute our given values into the expression above to determine the time it took the charge to pass through this wire.
\(I = \frac{Q}{t}\\ \\5.0A = \frac{30C}{t} \\\\t = \frac{30C}{5.0A} \\\\t = 6.0s\)
Therefore, the time taken for the charge to pass through the cross-section of the wire is 6.0s.
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The time taken by 30 coulombs of charge to pass through this wire is 6 seconds.
What is current?The pace at which electrons flow past a point in an electrical circuit is referred to as current.
Current is the ratio of charge and time. Given that the current is equal to 5.0 Amp, while the charge is equal to 30C. Therefore, the time will be equal to,
\(I=\dfrac{Q}{t}\\\\5 =\dfrac{30}{t}\\\\t = 6\rm\ sec\)
Hence, the time taken by 30 coulombs of charge to pass through this wire is 6 seconds.
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A force F~ = Fx ˆı + Fy ˆ acts on a particle that
undergoes a displacement of ~s = sx ˆı + sy ˆ
where Fx = 10 N, Fy = −1 N, sx = 4 m, and
sy = 1 m.
Find the work done by the force on the
particle.
Answer in units of J.
Find the angle between F~ and ~s.
Answer in units of ◦
.
Answers
The work done by the force on the particle is 39J and the angle between F and s is 19.7 degree.
What is Force ?An item with mass is pulled or pushed which alters its velocity. A material that has the ability to change a body's rest or motion state is referred to as an external force. It possesses a magnitude and a direction.
Briefing:Force F = (Fx, Fy)
Displacement S = (Sx,Sy)
Fx=10N
Fy=-1N
Sx=4m
Sy=1m
F=(10,-1)N and S=(4,1)m
Work done is calculated by taking dot product of force and displacement vector:
W=F·S
W=10×4 + (-1)×1
W=40+(-1)=39J
W = 39 J
To find angle between F and s:
\(|F|=\sqrt{10^2+(-1)^2}\)
|F| = √101
|S| = √(4² + 1²)
|S| = √17
W = |F| |S| cosθ
39 = √101 √17 cosθ
θ = 19.7.
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A car increase its speed steadily from 30km/hr to 60km/hr in 1 min A what is the average speed during this time
Answers
Explanation:
initial velocity(u)=30km/hr = 30*1000/60*60=8.33 m/s
final velocity(v) =60km/hr = 60*1000/60*60 =16.67 m/s
time taken(t) = 1 minutes
= 60 seconds
Now,
Average velocity = u+v/2
= 8.33 m/s + 16.67m/s÷2
=12.5 m/s
Why as shown in the figure below, starting in a reglon of zero magnetic fleid, and then entering a reglon of uniform maghetie field, pointing leto the page, with a How long (in s) is the electron in the regian of nonzero fiesd? b) The electron penetretes a maximum depth of 2.10 cm into the reglon of nonzero field. What is the kinetic energy (in ev) of the eictron? eY
Answers
A) The electron is in the region of nonzero field for 3.5 × 10^-9 seconds.b) The kinetic energy of the electron is 6.44 × 10^5 eV.
a) The formula used to find the time taken by the electron in the region of the nonzero field is given by,t = L / v
where L is the distance travelled and v is the velocity of the electron.t = 2.1 × 10^-2 / (6.0 × 10^6)t = 3.5 × 10^-9 secondsb)
The formula used to find the kinetic energy of the electron is given by,K.E = 1/2 × m × v^2
where m is the mass of the electron and v is its velocity.
Here, we can use the value of v obtained in part (a).K.E = 1/2 × 9.11 × 10^-31 × (6.0 × 10^6)^2K.E = 1.03 × 10^-13 J
To convert this into eV, we divide by the charge of an electron, which is 1.6 × 10^-19 C.K.E = 1.03 × 10^-13 / 1.6 × 10^-19K.E = 6.44 × 10^5 eV
Answer: a) The electron is in the region of nonzero field for 3.5 × 10^-9 seconds.b) The kinetic energy of the electron is 6.44 × 10^5 eV.
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The instant before a batter hits a 0.14-kilogram baseball, the velocity of the ball is 45 meters per second west. The instant after the batter hits the ball, the ball's velocity is 35 meters per second east. The bat and ball are in contact for 1.0 x 10-2 second.
1. find the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat.
2. calculate the magnitude of the average force the Bat exerts on the ball while they are in contact.
Answers
(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.
(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.
The given parameters:
Mass of the baseball, m = 0.14 kgInitial velocity of the baseball, u = 45 m/s west (negative direction)Final velocity of the baseball, v = 35 m/s east (positive direction)Time of contact, t = 0.01 sThe magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:
\(a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2\)
The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;
\(F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N\)
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4. Two students have volunteered to explore the galaxy in a spaceship. As they travel through space, they
measure the magnitude of the gravitational force between their spaceship and the Earth. They find that the
gravitational force on the spaceship is -
A. proportional to the distance from the Earth
B. inversely proportional to the distance from the Earth
C. proportional to the square of the distance from the Earth
D. inversely proportional to the square of the distance from the Earth
Answers
Answer:B
Explanation:
They find that the gravitational force on the spaceship is inversely proportional to the distance from the Earth. The correct option is B.
What is gravitational force?The gravitational pull would be stronger if the gap were cut in half. Coulomb's law, states that the gravitational force between two items in the universe is directly proportional to the product of the masses of the objects.
And inversely proportional to the distance between them is used to calculate the gravitational force between two objects in the universe. Whether there is a body there or not, gravity is the force between two bodies.
Everybody in the cosmos is drawn to every other body by a force that is directly inversely correlated to the square of the distance between them and directly inversely correlated to the product of their masses.
Therefore, the correct option is B. inversely proportional to the distance from the Earth.
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What does the front lens in a telescope do?
Answers
Can the sun explain global warming? ( 2 points) Suppose that the Earth has warmed up by 1 K in the last hundred years. i) How much would the solar constant have to increase to explain this? ii) Compare this to the observed fluctuation of the solar constant over the past 400 years (shown in class) For part (i), begin with the standard 'blackbody' calculation from class, that is: set α=0.30, and assume that the Earth acts as a blackbody in the infrared.
Answers
No, the sun cannot explain global warming. Global warming is a phenomenon in which the temperature of the Earth's surface and atmosphere is rising continuously due to human activities such as deforestation, burning of fossil fuels, and industrialization.
This increase in temperature cannot be explained only by an increase in solar radiation.There are several factors which contribute to global warming, including greenhouse gases such as carbon dioxide, methane, and water vapor. These gases trap heat in the Earth's atmosphere, which causes the planet's temperature to rise. The sun's radiation does contribute to global warming, but it is not the main cause.
i) To calculate the increase in solar radiation that would cause the Earth to warm up by 1 K, we can use the following formula:ΔS = ΔT / αWhere ΔS is the increase in solar constant, ΔT is the increase in temperature, and α is the Earth's albedo (reflectivity).α = 0.30 is the standard value used for the Earth's albedo.ΔS = ΔT / αΔS = 1 K / 0.30ΔS = 3.33 W/m2So, to explain the increase in temperature of 1 K over the last hundred years, the solar constant would need to increase by 3.33 W/m2.
ii) The observed fluctuation of the solar constant over the past 400 years has been around 0.1% to 0.2%. This is much smaller than the 3.33 W/m2 required to explain the increase in temperature of 1 K over the last hundred years. Therefore, it is unlikely that the sun is the main cause of global warming.
The sun cannot explain global warming. While the sun's radiation does contribute to global warming, it is not the main cause. The main cause of global warming is human activities, particularly the burning of fossil fuels, which release large amounts of greenhouse gases into the atmosphere.
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Will mark brainliest! See images below, please help! AP Physics
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Student 1 is correct in stating that the gravitational force is an external force acting on the marble while it is in the air. However, their claim that the cannon exerts a force on the marble in the air is incorrect, as the only external force acting on the marble in the air is due to gravity. As a result, the mechanical energy of the marble is conserved while it is in the air.
Mechanical energy is the sum of potential energy and kinetic energy in a system. Potential energy is the energy an object possesses due to its position or configuration, while kinetic energy is the energy an object possesses due to its motion. In the context of this question, the mechanical energy of the marble after it has been launched by the cannon but before it reaches the ground refers to the sum of the potential and kinetic energy of the marble in the air. Since there is no air resistance, the mechanical energy of the marble is conserved while it is in the air.
(e) The underlined phrase "the gravitational force" is correct in student 1's statement.
(f) The underlined phrase "the force exerted by the cannon" is incorrect in Student 1's statement. The cannon does exert a force on the marble during launch, but once the marble is in the air, there is no force exerted by the cannon on the marble. The force on the marble in the air is due only to gravity, which is an external force. So, the mechanical energy of the marble is conserved while it is in the air.
Therefore, Inferring that the gravitational force is an outside force operating on the marble while it is in the air, Student 1 is accurate. The stone in the air is solely subject to the force of gravity; they are mistaken when they assert that the cannon also exerts a force on it. The marble's mechanical energy is thus kept in check while it is in the air.
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1. what is the average speed after two seconds?
2. after three seconds?
3. after 5 seconds?
4. what is the average speed between two and four minutes?
5. what is the average speed between four and five minutes?
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Answer:
1. 75 speed, 2. 90 second = 1hr. 30 second. 3. 125 = 1hr 60 seconds 4.
The central bright fringe in a single-slit diffraction pattern has a width that equals the distance between the screen and the slit. Find the ratio /W of the wavelength of the light to the width of the slit.
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The wavelength of the light to the width of the slit (λ/W) is approximately 1.
To find the ratio λ/W, where λ is the wavelength of the light and W is the width of the slit, we can use the formula for the angular width of the central bright fringe in a single-slit diffraction pattern.
Step 1: Write down the formula for angular width of the central bright fringe.
The angular width of the central bright fringe (θ) can be given by the formula:
θ ≈ λ/W
Step 2: Convert angular width to linear width.
To convert the angular width to linear width, we can use the formula:
Linear width (L) = Distance between screen and slit (D) × tan(θ)
Step 3: Substitute the angular width formula from Step 1.
L = D × tan(λ/W)
Step 4: Since the linear width of the central bright fringe equals the distance between the screen and the slit, we can set L = D.
D = D × tan(λ/W)
Step 5: Divide both sides of the equation by D.
1 = tan(λ/W)
Step 6: Use the small angle approximation, where for very small angles, tan(θ) ≈ θ.
1 ≈ λ/W
So, the ratio of the wavelength of the light to the width of the slit (λ/W) is approximately 1.
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What is a method used to design or create solutions to problems
A)Trade-off
B)Constraint
C)Design
D)Criteria
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Solar constant is the amount of solar energy incident perpendicularly per unit time on unit surface area of the earth at an average distance between the Sun and the earth. Its value in S 0=1340w/m 2.
Here calculate temperature of the Sun's surface.
Radius of the Sun R s=7×10 8m. Average distance between the earth and the Sun R 0=1.5×10 11 m. σ=5.67×10 −8 Wm −2K −4
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The temperature of the sun's surface can be calculated given that solar constant is the amount of solar energy incident perpendicularly per unit time on unit surface area of the earth at an average distance between the Sun and the earth. Its value in S 0=1340w/m 2.
The radius of the Sun R s=7×10 8m.
The average distance between the earth and the Sun R 0=1.5×10 11 m.
The value of Stefan-Boltzmann constant σ=5.67×10^−8 Wm^−2K^−4.
The formula for the solar constant is as follows:
S = \(\frac{L}{4 \pi d^2}\)
Where,
S is the solar constant,
L is the Sun's luminosity which is 3.828 × 10^26
W, andd is the distance between the Sun and the earth, which is 1.496 × 10^11 meters.
Substituting the values, we get
S = \(\frac{3.828 \times 10^{26}}{4 \pi (1.496 \times 10^{11})^2}\)S = 1361 W/m²
The amount of energy emitted per second per unit area by the Sun is given by the Stefan-Boltzmann law:P = σAT⁴Where,P is the energy emitted per second per unit area by the Sun.σ is the Stefan-Boltzmann constant. A is the surface area of the Sun which is equal to 4πR^2, where R is the radius of the Sun.T is the temperature of the Sun's surface.The energy that falls on the surface of the Earth per second per unit area is given by:E = STWhere,E is the energy that falls on the surface of the Earth per second per unit area.The temperature of the Sun's surface can be calculated as follows:
P = EσA = STσAσAT⁴
= STσAT⁴
= ESolve for T:
T⁴ = \(\frac{E}{σA}\)T⁴
= \(\frac{ST}{σA}\)T⁴
= \(\frac{1361 \times 4 \pi R_s^2}{σ(4 \pi R_s^2)}\)T⁴
= \(\frac{1361}{σ}\)T⁴ = 6.87 × 10^6T = 5778 K
Therefore, the temperature of the Sun's surface is 5778 K.
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