Answer:
C
Step-by-step explanation:
If 30% of the entire population of students are seniors, then this will apply to the female population as well. This means that the probability of being a female senior is 30% * 54%=0.3*0.54=0.162=16.2%, or answer choice C. Hope this helps!
Solve for the value of s (3s-2)°
(4s-6)°
Answer:
(3s-2)°+(4s-6)°=90
3s-2+4s-6=90
7s-8=90
7s=90+8
7s=98
Dividing both sides by 7
S=98/7
S=14
please help
bdhdhdhfjci
Answer:
40 degrees
Step-by-step explanation:
A full triangle is 180 degrees
85+55=140
180-140=40
Help me please I would really be happy
The polynomial is not a perfect square trinomial. This is false..
How to illustrate the information?It should be noted that a perfect squares trinomial is the algebraic expression which has the form of ax² + bx + c.
The equation given is 9x² - 30x + 25. This will be expanded as:
9x² - 30x + 25.
9x² - 15x - 15x + 25
3x(3x - 5) - 5(3x - 5)
= (3x - 5)(3x - 5)
In this case, 9x² - 30x + 25 is a perfect square binomial of 3x - 5 and not a trinomial.
Therefore, the correct option is false.
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What does 33=5r-12 equal?
Dr. Jones is a billionaire and an amateur mathematician. Today, she wants to invest 80 million dollars at a fixed annual interest rate of 10% and use this fund to set up a "Nobel prize" for mathematicians: in each year, she awards a sum of money to the most outstanding mathematician. To combat inflation, the size of the prize is x for the first year, 1.045x in the second year, and $1.045t-1x in year t. Suppose that the first prize is scheduled to be given out immediately and Dr. Jones wants this to become a legacy that lasts forever, what is the highest possible value of x in millions of dollars? (For example, if your answer is 5 million, please enter 5 without adding "million".)
The highest possible value of x in millions of dollars is approximately 76.4 million.
To find the highest possible value of x in millions of dollars, we need to determine the value of x that will allow the fund to last forever.
The value of the fund in year t can be expressed as:
V(t) = x + 1.045x + (1.045^2)x + ... + (1.045^(t-1))x
This is a geometric series with a common ratio of 1.045. The sum of a geometric series is given by the formula:
S = a * (1 - r^t) / (1 - r)
where a is the first term, r is the common ratio, and t is the number of terms.
In this case, a = x, r = 1.045, and we want the sum to be infinite (to last forever). Therefore, we can set up the following equation:
V = x / (1 - 1.045) = 80 million
Simplifying this equation, we get:
x / (0.955) = 80 million
x = 80 million * 0.955
x ≈ 76.4 million
So, the highest possible value of x in millions of dollars is approximately 76.4 million.
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The highest possible value of x in millions of dollars is approximately 76.4 million.
To find the highest possible value of x in millions of dollars, we need to determine the value of x that will allow the fund to last forever.
The value of the fund in year t can be expressed as:
V(t) = x + 1.045x + (1.045^2)x + ... + (1.045^(t-1))x
This is a geometric series with a common ratio of 1.045. The sum of a geometric series is given by the formula:
S = a * (1 - r^t) / (1 - r)
where a is the first term, r is the common ratio, and t is the number of terms.
In this case, a = x, r = 1.045, and we want the sum to be infinite (to last forever). Therefore, we can set up the following equation:
V = x / (1 - 1.045) = 80 million
Simplifying this equation, we get:
x / (0.955) = 80 million
x = 80 million * 0.955
x ≈ 76.4 million
So, the highest possible value of x in millions of dollars is approximately 76.4 million.
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Which rays are part of line CF?
Answer:
A C and A F
Step-by-step explanation:
A C goes from A to C
A F goes from A to F
Use the triangle down below to write the given ratios.
Answer:
P=22.6, T=67.4
Step-by-step explanation:
\(sin(P)=\frac{5}{13}\\ P= 22.6\\\\tan(T)=\frac{12}{5}\\ T=67.4\\\\cos(T)=\frac{5}{13} \\T=67.4\)
The last 2 questions & did I do it right pls help me:(
Answer:
Step-by-step explanation:
a. 50x+200
b. 200
c. 50
d. y intercept - the cost to buy the phone
e. slope represents number of months that you have the phone plan
a local meterologist announces to the town that there is a 93% chance it will be cloudy that afternoon. what are the odds it will not be cloudy that afternoon?
If there is a 93% chance of it being cloudy in the afternoon, the odds of it not being cloudy can be calculated as 7:93.
To determine the odds of an event, we divide the probability of the event not occurring by the probability of the event occurring. In this case, the probability of it being cloudy is 93%, which means the probability of it not being cloudy is 100% - 93% = 7%.
To express the odds, we use a ratio. The odds of it not being cloudy can be represented as 7:93. This means that for every 7 favorable outcomes (not cloudy), there are 93 unfavorable outcomes (cloudy).
It's important to note that the odds are different from the probability. While probability represents the likelihood of an event occurring, odds compare the likelihood of an event occurring to the likelihood of it not occurring.
In this case, the odds of it not being cloudy are relatively low compared to the odds of it being cloudy, reflecting the high probability of cloudy weather as announced by the meteorologist.
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I RLLY NEED HELPPP ITS STEM AND LEAF DIAGRAMS!!
Answer:
2/9 or 22%
Step-by-step explanation:
probability would be 4/18 = 2/9 = 22.2%
82929.82 divided by 82992 =
You will get 29 points!
Answer:
0.99925077115
ASAP PLEASE. What is the quotient?
five with an exponet of negative six over five to the power of 3.
5^-6/5^3
a. 1/5^9
b. 1/5^2
c. 5^2
d. 5^9
h+8g
g=5 and h=4
I am not very quick at these and I need an answer ASAP
please!!
Answer:
44
Step-by-step explanation:
4+8(5)
Multiply 8 by 5
4+40=44
Add 4 to the product (40) to get the final answer of 44
Remember PEMDAS
Please help me
Use the story graph of each problem to fill in the blanks of the following sentence frames below.
In problem #1 the motion of the objects starts at ___ seconds and ends at ___ seconds.
The motion of the objects starts at ___ meters and ends at ___ meters.
The objects traveled ___ meters in ____ seconds.
In problem #2 the motion of the objects starts at ___ seconds and ends at ___ seconds.
The motion of the objects starts at ___ meters and ends at ___ meters.
The objects traveled ___ meters in ____ seconds.
Step-by-step explanation:
just as the graph shows.
no trick or hidden meaning or whatever.
#1
0 seconds to 5 seconds.
0 meters to 3 meters.
traveled 3-0 = 3 meters in 5-0=5 seconds
#2
0 seconds to 8 seconds.
0 meters to 5 meters.
traveled 5-0=5 meters in 8-0=8 seconds.
The frequency table shows the results of drawing 20 cards from a bag of 100. There are an
equal number of cards of each color in the bag. Which color has the same frequency as the
distribution of colors in the bag?
White color has the same frequency as the distribution of colors in the bag.
The statistic is the study of mathematics that deals with relations between comprehensive data.
Here,
in the bag, there are 100 cards, and an equal number of cards in colors blue, red, white, and yellow.
Frequency of each color card in bag = 100 / 4 = 25
Now,
if 20 colors have been drawn, the equally distributed frequency of each color,
= 20 / 4 = 5 card,
So from the table, the white color has a frequency of 5.
Thus, the white color has the same frequency as the distribution of colors in the bag.
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A cone has twice the base diameter and three-fourths the height of a cylinder. Can you tell what the relationship between the volume of the cone and the volume of the cylinder is? Explain your reasoning.
Answer:
Equal volumes
Step-by-step explanation:
Given
\(h \to\) height of cone
\(d \to\) diameter of cone
\(H \to\) height of cylinder
\(D \to\) diameter of cylinder
Such that:
\(d = 2D\)
\(h =\frac{3}{4}H\)
Required
The relationship between the volumes
The volume of a cylinder is:
\(V_1 = \pi R^2H\)
Where
\(R = 0.5D\)
So:
\(V_1 = \pi (0.5D)^2H\)
\(V_1 = \pi *0.25*D^2H\)
\(V_1 = 0.25\pi D^2H\)
The volume of the cone is:
\(V_2 = \frac{1}{3}\pi r^2h\)
Where
\(r =0.5d\)
\(r = 0.5 * 2D\)
\(r = D\)
and
\(h =\frac{3}{4}H\)
So, we have:
\(V_2 = \frac{1}{3}\pi * D^2 * \frac{3}{4}H\)
\(V_2 = \frac{1}{4}\pi * D^2H\)
\(V_2 = 0.25\pi * D^2H\)
\(V_2 = 0.25\pi D^2H\)
So, we have:
\(V_1 = 0.25\pi D^2H\)
\(V_2 = 0.25\pi * D^2H\)
\(V_1 = V_2\)
Answer: : When a cone and cylinder have the same height and radius the cone will fit inside the cylinder. The volume of the cone will be one-third that of the cylinder. If the radius or height are different, then there is no relationship between them.
Step-by-step explanation:
-4(2x+4)=-7x
solve for x
Answer:
x should equal 16
Step-by-step explanation:
Raina runs each lap in 6 minutes. She will run less than 48 minutes today. What are the possible numbers of laps she will run today? Use n for the number of laps she will run today. Write your answer as an inequality solved for n.
Raina can run any number of laps (n) less than 8 to ensure her total running time is less than 48 minutes.
To find the possible numbers of laps Raina will run today, we can set up an inequality based on the given information.
Let's assume Raina will run n laps today, and each lap takes 6 minutes. Therefore, the total time she will take to run n laps is 6n minutes.
The problem states that Raina will run less than 48 minutes today. Therefore, we can write the inequality as:
6n < 48.
To solve this inequality for n, we need to isolate n on one side of the inequality.
Dividing both sides of the inequality by 6, we get:
n < 48/6
Simplifying the right side, we have:
n < 8
Therefore, the inequality solved for n is:
n < 8
This means that the possible numbers of laps Raina will run today are any positive integer value less than 8.
Since the number of laps cannot be negative or zero, the feasible values for n are 1, 2, 3, 4, 5, 6, and 7.
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pls give answers + work for these 3 questions asap!
Evaluate e - 1/2 f when c = 15 and f =2
Answer: 14
Step-by-step explanation: I am guessing that you wrote the "c" incorrectly and that meant to be an "e". All you really need to do is replace the letters with the numbers that equal the letters, which would be:
(15) - 1/2(2)
1/2 * 2 = 1
15 - 1 = 14
How does the graph of y = 3^xcompare to the graph of y = 3^-x?
A. The graphs are the same.
B.The graphs are reflected across the x-axis.
C. The graphs are reflected across the y-axis.
Answer:
C
Step-by-step explanation:
The graphs are reflected across the y-axis.
MULTIPLE CHOICE QUESTION
The REFLECTION of a point should ALWAYS be the SAME DISTANCE away from the opposite side of the line of reflection.
FALSE or TRUE?
Answer:
True
Step-by-step explanation:
A reflecrion always is the sam edustance because then it makes it look like they are reflecting each other.
MEASUREMENT A 10-foot-long ladder leans against a wall so that the ladder and the
wall form a 30° angle. What is the distance from the ground to the point where the
ladder touches the wall? Round the answer to the nearest tenth of a foot.
Well visualize a 10 foot ladder leaning on a wall and how the space from the distance of the wall are gonna form an angle in this question it tells you it forms a 30 degree angle so your gonna go up 10 feet and out how much the angle is on a slant and multiply the two numbers?
the space between is what your determining.
/l
/ l < that is the wall
/ l
/ l
^that is the ladder
Please help I attached a photo.
Answer:
55w + 145
Step-by-step explanation:
Total = all accounts, so you have to add 10w to 45w, and 120 to 25
10w + 45w = 55w
120 + 25 = 145
So the answer is 55w + 145
WILL GIVE BRAINLEST HELPPPP
a) Let Q be an orthogonal matrix ( that is Q^TQ = I ). Prove that if λ is an eigenvalue of Q, then |λ|= 1.b) Prove that if Q1 and Q2 are orthogonal matrices, then so is Q1Q2.
Answer: a) Let Q be an orthogonal matrix and let λ be an eigenvalue of Q. Then there exists a non-zero vector v such that Qv = λv. Taking the conjugate transpose of both sides, we have:
(Qv)^T = (λv)^T
v^TQ^T = λv^T
Since Q is orthogonal, we have Q^TQ = I, so Q^T = Q^(-1). Substituting this into the above equation, we get:
v^TQ^(-1)Q = λv^T
v^T = λv^T
Taking the norm of both sides, we have:
|v|^2 = |λ|^2|v|^2
Since v is non-zero, we can cancel the |v|^2 term and we get:
|λ|^2 = 1
Taking the square root of both sides, we get |λ| = 1.
b) Let Q1 and Q2 be orthogonal matrices. Then we have:
(Q1Q2)^T(Q1Q2) = Q2^TQ1^TQ1Q2 = Q2^TQ2 = I
where we have used the fact that Q1^TQ1 = I and Q2^TQ2 = I since Q1 and Q2 are orthogonal matrices. Therefore, Q1Q2 is an orthogonal matrix.
rotate point x (0,0)) 270 degrees clockwise about the origin then T<3,5>
here this probally will help
Answer:
5, 3
Step-by-step explanation:
any number raised to the 2nd power is said to be
Answer: squared
Step-by-step explanation:
a tank holds 4000 liters of water in which 100 grams of salt have been dissolved. saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. write initial the value problem for:
The mass of salt in the tank at time t.
dS/dt = 10 - S/400
S(0) = 100 grams
The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)
A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.
So dS/dt = S(in) - S(out)
S(in) = 1 × 10 = 10 gram/liters
S(out) = S/V × 10 = 10S/V gram/liters
V = V(0) + q(in) - q(out)
V = 4000 + 10t - 10t
V = 4000 liters
dS/dt = 10 - 10S/V
dS/dt = 10 - 10S/4000
dS/dt = 10 - S/400
Now given; S(0) = 100.
Here, p(t) = 1/400, q(t) = 10
\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)
\(\mu=e^{\int p(t)dt}\)
\(\mu=e^{\frac{t}{400}}\)
So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)
S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)
S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)
S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)
S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)
Now solving the bracket
S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)
At S(0) = 100
100 = 4000 + \(e^{\frac{-0}{400}}\) C
100 = 4000 + \(e^{0}\) C
100 = 4000 + C
Subtract 4000 on both side, we get
C = -3900
Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)
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The complete question is:
A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:
The mass of salt in the tank at time t.
dS/dt =
S(0) =
The solution is S(t) =
(01.06 LC)
Expand and simplify: (2x + 5y) (x - 3y) (5 points)
Answer:
2x² - xy - 15y²
Step-by-step explanation:
(2x + 5y)(x - 3y)
Each term in the second factor is multiplied by each term in the first factor, that is
2x(x - 3y) + 5y(x - 3y) ← distribute parenthesis
= 2x² - 6xy + 5xy - 15y² ← collect like terms
= 2x² - xy - 15y²