assume that for a particular group of students, the events is a senior and is female are independent. If 30% of the students are seniors and 54% of the students are female, what is the probability of being a female senior?​

Assume That For A Particular Group Of Students, The Events Is A Senior And Is Female Are Independent.

Answers

Answer 1

Answer:

C

Step-by-step explanation:

If 30% of the entire population of students are seniors, then this will apply to the female population as well. This means that the probability of being a female senior is 30% * 54%=0.3*0.54=0.162=16.2%, or answer choice C. Hope this helps!


Related Questions

Solve for the value of s (3s-2)°
(4s-6)°

 Solve for the value of s (3s-2)(4s-6)

Answers

Answer:

(3s-2)°+(4s-6)°=90

3s-2+4s-6=90

7s-8=90

7s=90+8

7s=98

Dividing both sides by 7

S=98/7

S=14

please help
bdhdhdhfjci

please help bdhdhdhfjci

Answers

Answer:

40 degrees

Step-by-step explanation:

A full triangle is 180 degrees

85+55=140

180-140=40

Help me please I would really be happy

Help me please I would really be happy

Answers

The polynomial is not a perfect square trinomial. This is false..

How to illustrate the information?

It should be noted that a perfect squares trinomial is the algebraic expression which has the form of ax² + bx + c.

The equation given is 9x² - 30x + 25. This will be expanded as:

9x² - 30x + 25.

9x² - 15x - 15x + 25

3x(3x - 5) - 5(3x - 5)

= (3x - 5)(3x - 5)

In this case, 9x² - 30x + 25 is a perfect square binomial of 3x - 5 and not a trinomial.

Therefore, the correct option is false.

Learn more about polynomial on:

brainly.com/question/2833285

#SPJ1

What does 33=5r-12 equal?

Answers

The answer is r=9
:) have a great day

Dr. Jones is a billionaire and an amateur mathematician. Today, she wants to invest 80 million dollars at a fixed annual interest rate of 10% and use this fund to set up a "Nobel prize" for mathematicians: in each year, she awards a sum of money to the most outstanding mathematician. To combat inflation, the size of the prize is x for the first year, 1.045x in the second year, and $1.045t-1x in year t. Suppose that the first prize is scheduled to be given out immediately and Dr. Jones wants this to become a legacy that lasts forever, what is the highest possible value of x in millions of dollars? (For example, if your answer is 5 million, please enter 5 without adding "million".)

Answers

The highest possible value of x in millions of dollars is approximately 76.4 million.

To find the highest possible value of x in millions of dollars, we need to determine the value of x that will allow the fund to last forever.

The value of the fund in year t can be expressed as:

V(t) = x + 1.045x + (1.045^2)x + ... + (1.045^(t-1))x

This is a geometric series with a common ratio of 1.045. The sum of a geometric series is given by the formula:

S = a * (1 - r^t) / (1 - r)

where a is the first term, r is the common ratio, and t is the number of terms.

In this case, a = x, r = 1.045, and we want the sum to be infinite (to last forever). Therefore, we can set up the following equation:

V = x / (1 - 1.045) = 80 million

Simplifying this equation, we get:

x / (0.955) = 80 million

x = 80 million * 0.955

x ≈ 76.4 million

So, the highest possible value of x in millions of dollars is approximately 76.4 million.

Learn more about fund from this link:

https://brainly.com/question/29837697

#SPJ11

The highest possible value of x in millions of dollars is approximately 76.4 million.

To find the highest possible value of x in millions of dollars, we need to determine the value of x that will allow the fund to last forever.

The value of the fund in year t can be expressed as:

V(t) = x + 1.045x + (1.045^2)x + ... + (1.045^(t-1))x

This is a geometric series with a common ratio of 1.045. The sum of a geometric series is given by the formula:

S = a * (1 - r^t) / (1 - r)

where a is the first term, r is the common ratio, and t is the number of terms.

In this case, a = x, r = 1.045, and we want the sum to be infinite (to last forever). Therefore, we can set up the following equation:

V = x / (1 - 1.045) = 80 million

Simplifying this equation, we get:

x / (0.955) = 80 million

x = 80 million * 0.955

x ≈ 76.4 million

So, the highest possible value of x in millions of dollars is approximately 76.4 million.

Learn more about fund from this link:

https://brainly.com/question/1398171

#SPJ11

Which rays are part of line CF?

Which rays are part of line CF?

Answers

Answer:

A C and A F

Step-by-step explanation:

A C goes from A to C

A F goes from A to F

Use the triangle down below to write the given ratios.

Use the triangle down below to write the given ratios.

Answers

Answer:

P=22.6, T=67.4

Step-by-step explanation:

\(sin(P)=\frac{5}{13}\\ P= 22.6\\\\tan(T)=\frac{12}{5}\\ T=67.4\\\\cos(T)=\frac{5}{13} \\T=67.4\)

The last 2 questions & did I do it right pls help me:(

The last 2 questions & did I do it right pls help me:(

Answers

Answer:

Step-by-step explanation:

a. 50x+200

b. 200

c. 50

d. y intercept - the cost to buy the phone

e. slope represents number of months that you have the phone plan

I think you have your equation wrong. It should be 5x+200. 200 is paid once while the five is paid every month. So 200 is the y-intercept and it stands for the purchase of the phone. The slope is how much you’re paying each month!

a local meterologist announces to the town that there is a 93% chance it will be cloudy that afternoon. what are the odds it will not be cloudy that afternoon?

Answers

If there is a 93% chance of it being cloudy in the afternoon, the odds of it not being cloudy can be calculated as 7:93.

To determine the odds of an event, we divide the probability of the event not occurring by the probability of the event occurring. In this case, the probability of it being cloudy is 93%, which means the probability of it not being cloudy is 100% - 93% = 7%.

To express the odds, we use a ratio. The odds of it not being cloudy can be represented as 7:93. This means that for every 7 favorable outcomes (not cloudy), there are 93 unfavorable outcomes (cloudy).

It's important to note that the odds are different from the probability. While probability represents the likelihood of an event occurring, odds compare the likelihood of an event occurring to the likelihood of it not occurring.

In this case, the odds of it not being cloudy are relatively low compared to the odds of it being cloudy, reflecting the high probability of cloudy weather as announced by the meteorologist.

Learn more about probability  here:

https://brainly.com/question/32004014

#SPJ11

I RLLY NEED HELPPP ITS STEM AND LEAF DIAGRAMS!!

I RLLY NEED HELPPP ITS STEM AND LEAF DIAGRAMS!!

Answers

Answer:

2/9 or 22%

Step-by-step explanation:

probability would be 4/18 = 2/9 = 22.2%

82929.82 divided by 82992 =


You will get 29 points!

Answers

Answer:

0.99925077115

ASAP PLEASE. What is the quotient?
five with an exponet of negative six over five to the power of 3.
5^-6/5^3

a. 1/5^9

b. 1/5^2

c. 5^2

d. 5^9

Answers

It’s A since it’s matches the example

h+8g
g=5 and h=4
I am not very quick at these and I need an answer ASAP
please!!

Answers

Answer:

44

Step-by-step explanation:

4+8(5)

Multiply 8 by 5

4+40=44

Add 4 to the product (40) to get the final answer of 44

Remember PEMDAS

Please help me


Use the story graph of each problem to fill in the blanks of the following sentence frames below.

In problem #1 the motion of the objects starts at ___ seconds and ends at ___ seconds.

The motion of the objects starts at ___ meters and ends at ___ meters.

The objects traveled ___ meters in ____ seconds.

In problem #2 the motion of the objects starts at ___ seconds and ends at ___ seconds.

The motion of the objects starts at ___ meters and ends at ___ meters.

The objects traveled ___ meters in ____ seconds.

Please help meUse the story graph of each problem to fill in the blanks of the following sentence frames

Answers

Step-by-step explanation:

just as the graph shows.

no trick or hidden meaning or whatever.

#1

0 seconds to 5 seconds.

0 meters to 3 meters.

traveled 3-0 = 3 meters in 5-0=5 seconds

#2

0 seconds to 8 seconds.

0 meters to 5 meters.

traveled 5-0=5 meters in 8-0=8 seconds.

The frequency table shows the results of drawing 20 cards from a bag of 100. There are an
equal number of cards of each color in the bag. Which color has the same frequency as the
distribution of colors in the bag?

The frequency table shows the results of drawing 20 cards from a bag of 100. There are anequal number

Answers

Yellow because yellow is the color that had the most cards in that color.

White color has the same frequency as the distribution of colors in the bag.

What is Statistic?

The statistic is the study of mathematics that deals with relations between comprehensive data.

Here,
in the bag, there are 100 cards, and an equal number of cards in colors blue, red, white, and yellow.
Frequency of each color card in bag = 100 / 4 = 25

Now,
if 20 colors have been drawn, the equally distributed frequency of each color,
= 20 / 4 = 5 card,
So from the table, the white color has a frequency of 5.

Thus, the white color has the same frequency as the distribution of colors in the bag.

Learn more about Statistics here:

https://brainly.com/question/23091366

#SPJ5

A cone has twice the base diameter and three-fourths the height of a cylinder. Can you tell what the relationship between the volume of the cone and the volume of the cylinder is? Explain your reasoning.

Answers

Answer:

Equal volumes

Step-by-step explanation:

Given

\(h \to\) height of cone

\(d \to\) diameter of cone

\(H \to\) height of cylinder

\(D \to\) diameter of cylinder

Such that:

\(d = 2D\)

\(h =\frac{3}{4}H\)

Required

The relationship between the volumes

The volume of a cylinder is:

\(V_1 = \pi R^2H\)

Where

\(R = 0.5D\)

So:

\(V_1 = \pi (0.5D)^2H\)

\(V_1 = \pi *0.25*D^2H\)

\(V_1 = 0.25\pi D^2H\)

The volume of the cone is:

\(V_2 = \frac{1}{3}\pi r^2h\)

Where

\(r =0.5d\)

\(r = 0.5 * 2D\)

\(r = D\)

and

\(h =\frac{3}{4}H\)

So, we have:

\(V_2 = \frac{1}{3}\pi * D^2 * \frac{3}{4}H\)

\(V_2 = \frac{1}{4}\pi * D^2H\)

\(V_2 = 0.25\pi * D^2H\)

\(V_2 = 0.25\pi D^2H\)

So, we have:

\(V_1 = 0.25\pi D^2H\)

\(V_2 = 0.25\pi * D^2H\)

\(V_1 = V_2\)

Answer: : When a cone and cylinder have the same height and radius the cone will fit inside the cylinder. The volume of the cone will be one-third that of the cylinder. If the radius or height are different, then there is no relationship between them.

Step-by-step explanation:

-4(2x+4)=-7x
solve for x

Answers

Answer:

x should equal 16

Step-by-step explanation:

Raina runs each lap in 6 minutes. She will run less than 48 minutes today. What are the possible numbers of laps she will run today? Use n for the number of laps she will run today. Write your answer as an inequality solved for n.

Answers

Raina can run any number of laps (n) less than 8 to ensure her total running time is less than 48 minutes.

To find the possible numbers of laps Raina will run today, we can set up an inequality based on the given information.

Let's assume Raina will run n laps today, and each lap takes 6 minutes. Therefore, the total time she will take to run n laps is 6n minutes.

The problem states that Raina will run less than 48 minutes today. Therefore, we can write the inequality as:

6n < 48.

To solve this inequality for n, we need to isolate n on one side of the inequality.

Dividing both sides of the inequality by 6, we get:

n < 48/6

Simplifying the right side, we have:

n < 8

Therefore, the inequality solved for n is:

n < 8

This means that the possible numbers of laps Raina will run today are any positive integer value less than 8.

Since the number of laps cannot be negative or zero, the feasible values for n are 1, 2, 3, 4, 5, 6, and 7.

For similar question on inequality.

https://brainly.com/question/30681777  

#SPJ8

pls give answers + work for these 3 questions asap!

pls give answers + work for these 3 questions asap!

Answers

Just use the app Photomath it gives out everything

Evaluate e - 1/2 f when c = 15 and f =2

Answers

Answer: 14

Step-by-step explanation: I am guessing that you wrote the "c" incorrectly and that meant to be an "e". All you really need to do is replace the letters with the numbers that equal the letters, which would be:

(15) - 1/2(2)

1/2 * 2 = 1

15 - 1 = 14

How does the graph of y = 3^xcompare to the graph of y = 3^-x?
A. The graphs are the same.
B.The graphs are reflected across the x-axis.
C. The graphs are reflected across the y-axis.​

Answers

Answer:

C

Step-by-step explanation:

The graphs are reflected across the y-axis.

How does the graph of y = 3^xcompare to the graph of y = 3^-x? A. The graphs are the same. B.The graphs

MULTIPLE CHOICE QUESTION

The REFLECTION of a point should ALWAYS be the SAME DISTANCE away from the opposite side of the line of reflection.

FALSE or TRUE? ​

Answers

Answer:

True

Step-by-step explanation:

A reflecrion always is the sam edustance because then it makes it look like they are reflecting each other.

MEASUREMENT A 10-foot-long ladder leans against a wall so that the ladder and the
wall form a 30° angle. What is the distance from the ground to the point where the
ladder touches the wall? Round the answer to the nearest tenth of a foot.

Answers

Well visualize a 10 foot ladder leaning on a wall and how the space from the distance of the wall are gonna form an angle in this question it tells you it forms a 30 degree angle so your gonna go up 10 feet and out how much the angle is on a slant and multiply the two numbers?

the space between is what your determining.

     /l

   /  l < that is the wall

 /    l

/      l

^that is the ladder

Please help I attached a photo.

Please help I attached a photo.

Answers

Answer:

55w + 145

Step-by-step explanation:

Total = all accounts, so you have to add 10w to 45w, and 120 to 25

10w + 45w = 55w

120 + 25 = 145

So the answer is 55w + 145

WILL GIVE BRAINLEST HELPPPP

WILL GIVE BRAINLEST HELPPPP

Answers

1 = 63
2 = 49
3 = 87
4 = 44
1- 54
2- 49
3- 87
4- 44

Please mark brainliest is correct!!

a) Let Q be an orthogonal matrix ( that is Q^TQ = I ). Prove that if λ is an eigenvalue of Q, then |λ|= 1.b) Prove that if Q1 and Q2 are orthogonal matrices, then so is Q1Q2.

Answers

Answer: a) Let Q be an orthogonal matrix and let λ be an eigenvalue of Q. Then there exists a non-zero vector v such that Qv = λv. Taking the conjugate transpose of both sides, we have:

(Qv)^T = (λv)^T

v^TQ^T = λv^T

Since Q is orthogonal, we have Q^TQ = I, so Q^T = Q^(-1). Substituting this into the above equation, we get:

v^TQ^(-1)Q = λv^T

v^T = λv^T

Taking the norm of both sides, we have:

|v|^2 = |λ|^2|v|^2

Since v is non-zero, we can cancel the |v|^2 term and we get:

|λ|^2 = 1

Taking the square root of both sides, we get |λ| = 1.

b) Let Q1 and Q2 be orthogonal matrices. Then we have:

(Q1Q2)^T(Q1Q2) = Q2^TQ1^TQ1Q2 = Q2^TQ2 = I

where we have used the fact that Q1^TQ1 = I and Q2^TQ2 = I since Q1 and Q2 are orthogonal matrices. Therefore, Q1Q2 is an orthogonal matrix.

rotate point x (0,0)) 270 degrees clockwise about the origin then T<3,5>

Answers

here this probally will help

rotate point x (0,0)) 270 degrees clockwise about the origin then T&lt;3,5&gt;
rotate point x (0,0)) 270 degrees clockwise about the origin then T&lt;3,5&gt;

Answer:

5, 3

Step-by-step explanation:

any number raised to the 2nd power is said to be

Answers

Answer: squared

Step-by-step explanation:

a tank holds 4000 liters of water in which 100 grams of salt have been dissolved. saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. write initial the value problem for:

Answers

The mass of salt in the tank at time t.

dS/dt = 10 - S/400

S(0) = 100 grams

The solution is S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

A tank holds water V(0) = 4000 liters in which salt S(0) = 100 grams.

So dS/dt = S(in) - S(out)

S(in) = 1 × 10 = 10 gram/liters

S(out) = S/V × 10 = 10S/V gram/liters

V = V(0) + q(in) - q(out)

V = 4000 + 10t - 10t

V = 4000 liters

dS/dt = 10 - 10S/V

dS/dt = 10 - 10S/4000

dS/dt = 10 - S/400

Now given; S(0) = 100.

Here, p(t) = 1/400, q(t) = 10

\(\int p(t)dt = \int\frac{1}{400}dt\)\(\int p(t)dt = \frac{1}{400}t\)

\(\mu=e^{\int p(t)dt}\)

\(\mu=e^{\frac{t}{400}}\)

So, S(t) = \(\frac{\int\mu q(t)dt+C}{\mu}\)

S(t) = \(\frac{\int e^{\frac{t}{400}} \cdot10dt+C}{e^{\frac{t}{400}}}\)

S(t) = \(e^{\frac{-t}{400}} \left({\int e^{\frac{t}{400}} \cdot10dt+C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({10\times\frac{e^{\frac{t}{400}}}{1/400} +C}\right)\)

S(t) = \(e^{\frac{-t}{400}} \left({4000\times{e^{\frac{t}{400}} +C}\right)\)

Now solving the bracket

S(t) = 4000 + \(e^{\frac{-t}{400}}\)C.....(1)

At S(0) = 100

100 = 4000 + \(e^{\frac{-0}{400}}\) C

100 = 4000 + \(e^{0}\) C

100 = 4000 + C

Subtract 4000 on both side, we get

C = -3900

Now S(t) = 4000 - 3900\(e^{\frac{-t}{400}}\)

To learn more about mass of salt link is here

brainly.com/question/11192688

#SPJ4

The complete question is:

A tank holds 4000 liters of water in which 100 grams of salt have been dissolved. Saltwater with a concentration of 1 grams/liter is pumped in at 10 liters/minute and the well mixed saltwater solution is pumped out at the same rate. Write initial the value problem for:

The mass of salt in the tank at time t.

dS/dt =

S(0) =

The solution is S(t) =

(01.06 LC)
Expand and simplify: (2x + 5y) (x - 3y) (5 points)

Answers

Answer:

2x² - xy - 15y²

Step-by-step explanation:

(2x + 5y)(x - 3y)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(x - 3y) + 5y(x - 3y) ← distribute parenthesis

= 2x² - 6xy + 5xy - 15y² ← collect like terms

= 2x² - xy - 15y²

Other Questions
Most scientists infer that a major factor in the increased of melting of earths glacers is I'm going to have a state test next month any tips? Anything helps and spring break next week so, maybe study during the break? i dont know.. To a flask, 15.0 mL of 1.25 M hydrofluoric acid is added. Then, 3.05 M NaOH is used to titrate the acid sample. Write the balanced net ionic equation for the acid-base reaction.HF(aq) + OH^- H2O(I) + F^- Who won the election of 1860? How did it impact the southern states? Vaccinations & Economic recovery Suppose you have data on COVID vaccines administered per day & consumer retail spending per day in Chicago between May to July 2021. COVID vaccines are represented by Vacc, and consumer retail spending (in $) is represented by Spend. (a) How would you write this relationship using the core model of econometrics? (b) Interpret the intercept & the slope coefficient in words. (c) Do you expect the slope coefficient to be positive or negative? Explain your reasoning. (d) What are two factors that are likely to be included in the error term of your model? Halla los nmeros desconocidos de estas operaciones A)872+. +173=2000B)9180:. =102C). -99=706Con los mismos nmeros y las mismas operaciones podemos obtener diferentes resultados,coloca los parntesis de manera que se obtengan los resultados indicados. A)3+5x7-2=40B)3+57-2=54C)3+57-2=28ES PARA HOY PORFAVOR,PUEDEN HACER EN UNA HOJA O ESCRIBIR ASI PERO EXPLIQUEN BIEN!!!!!!AYUDA SI NO SABEN NO RESPONDAD in coastal fishing companys suit against dockside marina, inc., the jury returns a verdict in coastals favor. dockside files a motion stating that even if the evidence is viewed in the light most favorable to coastal, a reasonable jury should not have found in its favor. this is a motion for NEED HELP ASAP In Common Sense, Thomas Paine argued thatA. America should be an independent nation.B. America should reconcile with Britain.C. America should submit to British regulations.D. America should have its own monarchy. How does a keystone species positively contribute to biodiversity in an ecosystem?a. predation of many speciesb. predation of one important speciesc. helps invasive species to populate aread. keystone species do not positively contribute to biodiversity, rather hurt it(please help me quickly this is due in 5min my last question) 1. The Persistent GardenerIt was Jilly's last day in the green house. Summer was coming to an end and so was the growing season. School would be starting next week and the fall plants were well enough along to allow Mrs. T. to manage the greenhouses herself. As Jilly worked the plants for the last time, she tried to focus on the new school year instead of the details of the greenhouse. It had been a hard, hot summer, but Jilly was not ready for it to be over.Jilly moved down the tables, tucking a stray hair behind her ear with a gloved and already dirty hand. She'd repotted the last of the rosemary plants and mixed a new batch of potting soil already. Mrs. T. now had enough potting soil to last her through September. Jilly looked at a couple of maiden-hair ferns that were beginning to yellow in their small pots. She loved their lacey fronds and had grown concerned over the last few days that they needed repotting or a boost of fertilizer. She had also worried that she would continue to find chores that needed doing, plants that needed help, right up until the minute she left today. She hated unfinished things. She hated details not being tended to.The sun had been above the trees and blasting the greenhouse for a good hour now. Jilly listened for the familiar whirr of the automatic vents opening. When the greenhouse reached a certain temperature, the vents would open automatically. The vents would have a cooling effect for an hour or so, and then no amount of breeze would put a dent in the heat. Mrs. T. often claimed Jilly must be part reptile as she was able to work longer in the greenhouse than anyone else. The heat just didn't bother her. In fact, Jilly often looked forward to the warmth of the greenhouse and feeling the heat seep into her bones. It felt good to her, but she understood others who found it hard to breathe in 100 degree temperatures.Jilly heard the greenhouse door bang, and looked up from her ferns to see Mrs. T. walking down the aisle with a tray of young plants. Mums, Jilly supposed, the flowers everyone wants for fall. She had helped Mrs. T. take cuttings and plant the small stems in new pots. They were doing nicely from the look of things."We will keep these in here for now," said Mrs. T. "They are getting too much rain outside."It had been a rainy couple of days. Jilly knew, as well as anyone, that overwatering could kill potted plants quickly."Do you remember when I overwatered those mint plants?" Jilly asked Mrs. T."I used to think no one could kill a mint plant," Mrs. T. said, laughing."Well I am full of surprises, apparently," Jilly replied. Jilly remembered the sad green plants that just kept looking more and more wilted no matter how much water she gave them. It was a beginner's mistake, and Jilly had been so embarrassed for making it."That you are," replied Mrs. T. "But I know you learned a lesson you won't ever forget.""Of course. Herbs like their roots damp, not flooded," Jilly answered."Well that is not the lesson I was thinking of," Mrs. T. said.Jilly wondered for a minute what the lesson could be. She straightened the rows of geraniums in front of her, picking up one or two to check for aphids under the leaves. It had been a summer full of lessons, some especially hard for a girl who thought she knew a lot about plants. She breathed deeply the warm, humid air. She hated the cooped up feeling of air conditioned air, the feeling of being cut off from the sun. She knew school and the library would offer only these uncomfortable feelings and little time to spend in the sun or with plants. She had come to understand this over the summer-her need to be around growing things was huge."I'm not sure, Mrs. T." she said, "I've learned so much this summer. I couldn't possibly say what you are thinking.""You did learn many lessons, Jilly. You knew so much when you started. You've gone farther than any other assistants I've had. I will miss you.""And I will miss you," Jilly replied. "Thank you for the opportunity and the job." Jilly watched Mrs. T. put the tray of mums down on the center row of tables. Wearing her familiar brown apron, Mrs. T. looked just as she had on Jilly's first day."My pleasure, of course, dear," Mrs. T. replied. "My hope for you, as for all my assistants over the years, is that you will learn as much about yourself as you do about growing plants."Recalling her thoughts all morning, about what she enjoyed about her summer job, Jilly realized she knew much more than just how to not drown the mint.Which line from the text best describes Mrs. T.? (5 points)Jilly heard ... Mrs. T. walking down the aisle with a tray of young plants.She had helped Mrs. T. take cuttings and plant the small stems in new pots.Wearing her familiar brown apron, Mrs. T. looked just as she had on Jilly's first day."I used to think no one could kill a mint plant," Mrs. T. said, laughing. In triangle CVR, the midpoint of segment CR is S and the midpoint segment CV is T. What term can be used to describe segment STa. angle bisectorb. chord c. midsegmentd. perpendicular bisector Roland had revenues of $606,000 in March. Fixed costs in March were $207,900 and profit was $46,620. a. What was the contribution margin percentage? Contribution Margin % b. What monthly sales volume (in dollars) would be needed to break-even? Break-even Sales Volume c. What sales volume (in dollars) would be needed to earn $168,000? Total Sales Volume : Why is it important to show thanks to the people who mean most in your life? How do you say "Welcome to earth" in Spanish? Which are forms of media? Check all that apply. HELP FIND THE VALUES What is the energy source for producers, consumers, and decomposers? Select the correct text in the passage. In this excerpt from O. Henrys short story A Retrieved Reformation, which sentence supports the theme love can change a person"? Look at the image and choose one blue line pls help 6x = 7xy + 20y where x 0 and y 0 Find the ratio x : y one side of a righr triagle is known to be 23 cm exactly, the angle opposite to this side is measured to be about 60 with 0.1 a. Use differentials to estimate the errors in the adjacent side and the hypothenuse. b. Estimate the percentage errors in the adjacent side and hypothenuse.