Answer:
Aseem’s : 8.3, Stana’s : 11.6
Step-by-step explanation:
Aseem: x
Stana: 2x-5
X+2x-5=20
3x=25
X = 8.3
D. X = 50
24. At a camping site in July, 120 famles stayed for three or more days.
The 120 families represent three-eighths all the families who stayed at the
camping site in July. How many families stayed at the camping site in July?
A. 15
B. 45
C. 320
D. 5
Answer:
The answer is c. :)
Step-by-step explanation:
120 × 3/8 = 320
10x-2(3x-6)=4(3x-6)-8x helpp please
Step-by-step explanation:
10x-6x+12=12x-24-8x
4x+12=4x-24
4x-4x≠-24-12
thus,it is erroneous
Get the quotient of each item up to the nearest ten thousandths place.
Then, round the decimals to their nearest thousandths. Number 1 is done for you.
1.45 + 8 = 5.6250 5.625
2.77 + 9 =
3.81 7 =
4.93=9 =
5. 88 7=
6.55 + 8 =
9514 1404 393
Answer:
see attached
Step-by-step explanation:
This calculator problem can be handled easily by a spreadsheet, which can round to whatever number of digits you desire.
The point is probably to see if you understand that the thousandths place digit will increase by 1 if the ten-thousandths place digit is 5 or more. (That is the case only for problem 2.)
__
Additional comment
When doing this with something that only displays 4 decimal digits, you need to be sure that the 4th digit has not been rounded up to 5. For example, ...
0.00149 rounds to 0.0015 and rounds to 0.001 (not 0.002)
Usually, you would give yourself this assurance by showing the hundred-thousandths place in the calculation if you're intending to round to thousandths.
Solve -3x-4(4x-8)=3(-8-1)
Answer:
any questions i am ready to help
which Of the following is the value of 7-15:3-2?
Answer:
-8:1
Step-by-step explanation:
How to solve the function operation :D
Simplify 7-15= -8
Then simplify 3-2= 1
Total= -8:1
find the limit, if it exists, or show that the limit does not exist (show all work). [25 pts] • a) lim (x,y)→(0,0) (x^2y+ xy^2) /(x^3−y^3)
The limit of the function as (x,y) approaches (0,0) which is lim (x,y)→(0,0) (x^2y+ xy^2) /(x^3−y^3) does not exist.
To find the limit of the given function as (x,y) approaches (0,0), we can try approaching along different paths and check if the limit exists and is the same along all paths.
Let's try approaching along the x-axis, i.e., setting y=0:
lim (x,0)→(0,0) (x^20 + x0^2)/(x^3-0^3) = lim (x,0)→(0,0) 0/ x^3 = 0
Similarly, approaching along the y-axis, i.e., setting x=0:
lim (0,y)→(0,0) (0y + y^20)/(0^3-y^3) = lim (0,y)→(0,0) 0/ (-y^3) = 0
Now, let's try approaching along the line y=x:
lim (x,x)→(0,0) (x^2x + xx^2)/(x^3-x^3) = lim (x,x)→(0,0) 2x/0
This limit does not exist as it gives different values depending on the approach.
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If a pharmacist combined 50-ml portions of thre syrups having specific graveties of 1.10, 1.25, and 1.32, what would be the specific gravity of the combined product?
The specific gravity of the combined product is 1.22
Specific gravity is the ratio of the density of a substance to the density of some substance (such as pure water) taken as a standard when both densities are obtained by weighing in air.
Given,
The total quantity of portion= 50 ml
Specific gravities of the three syrups = 1.10,1.25 and 1.32
Then,
The specific gravity of the combined product= \(\frac{1.10+1.25+1.32}{3}\)
= 1.22
Hence, the specific gravity of the combined product is 1.22.
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Which function's graph is shown below?
O A. y=-sin x
O B. y= -c0s X
O C. y = cos x
O D. y = sin x
Answer:
The function's graph shown is C. y = cos x
Step-by-step explanation:
hope it helps...
have a great day!!
Help me with this Math pleaseee
answer:
a.
explanation:
im sure its a.
hope this helped <3 also if wouldn't mind could you pls give me brainliest? (im trying to level up) thanks! :)
Suppose a random sample of size 36 is selected from a population with o = 100. Find the standard error of the mean for the population size 800.
The standard error of the mean for a population size of 800 is approximately 7.9057.
To find the standard error of the mean (SEM), we can use the following formula:
SEM = o / sqrt(n)
where o is the population standard deviation, n is the sample size.
In this case, o = 100 and n = 36. We want to find the SEM for a population size of 800. To do this, we first need to adjust the sample size by multiplying it by the ratio of the population sizes:
adjusted_n = n * (N / n)^(1/2)
= 36 * (800 / 36)^(1/2)
= 160
where N is the population size.
Now we can calculate the SEM:
SEM = o / sqrt(adjusted_n)
= 100 / sqrt(160)
= 7.9057 (rounded to four decimal places)
Therefore, the standard error of the mean for a population size of 800 is approximately 7.9057.
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QuESTION 15 Which difficulty of range as measure 0f 'variability is overcome by interquartile range? a. The range is difficult to compute b. The range is influcnced t0o much by extreme values The sum of the range variances is ZEtO d. The range is negative
The difficulty of range as a measure of variability that is overcome by interquartile range is option b that is The range is influenced too much by extreme values.
What is variance?The variance is the mean squared difference between each data point and the mean-centered distribution. A statistical assessment of the dispersion of values in a data collection is referred to as variance. Variance explicitly assesses how distant each number in the set is from the mean (average), and consequently from every other number in the set. Variance is a measure of how data points differ from the mean, whereas standard deviation is a measure of statistical data distribution. The primary distinction between the two is that standard deviation is expressed in the same units as the mean of the data, whereas variance is expressed in squared units.
Here,
The interquartile range overcomes the problem of range as a measure of variability. Extreme values have an undue impact on the range.
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let x be a uniformly distributed random variable on [0,1] then x divides [0,1] into the subintervals [0,x] and [x,1]. by symmetry
When x is a uniformly distributed random variable on [0,1], it divides the interval [0,1] into two subintervals: [0,x] and [x,1]. This division exhibits symmetry, as explained in the following paragraphs.
Consider a uniformly distributed random variable x on the interval [0,1]. The probability density function of x is constant within this interval. When x takes a particular value, it acts as a dividing point that splits [0,1] into two subintervals.
The first subinterval, [0,x], represents all the values less than or equal to x. Since x is randomly distributed, any value within [0,1] is equally likely to be chosen. Therefore, the probability of x falling within the subinterval [0,x] is equal to the length of [0,x] divided by the length of [0,1]. This probability is simply x.
By symmetry, the second subinterval, [x,1], represents all the values greater than x. The probability of x falling within the subinterval [x,1] can be calculated as the length of [x,1] divided by the length of [0,1], which is equal to 1 - x.
The symmetry arises because the probability of x falling within [0,x] is the same as the probability of x falling within [x,1]. This symmetry is a consequence of the uniform distribution of x on the interval [0,1].
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1 point) A poll is taken in which 330 out of 550 randomly selected voters indicated their preference for a certain candidate. (a) Find a 90% confidence interval for p. 0.557 < p 0.642 (b) Find the margin of error for this 90% confidence interval for p. 0.042 (c) Without doing any calculations, indicate whether the margin of error is larger or smaller or the same for an 80% confidence interval. A. larger B. smaller C. same
This is because as the level of confidence decreases, the corresponding z-score becomes smaller, which in turn results in a smaller margin of error.
(a) To find a 90% confidence interval for the proportion p, we can use the formula:
CI = p ± z*(sqrt(p*(1-p)/n))
where p is the sample proportion, n is the sample size, and z is the z-score corresponding to the desired level of confidence (in this case, 90%).
We are given that p = 330/550 = 0.6 and n = 550. Using a standard normal distribution table, the z-score for a 90% confidence interval is approximately 1.645.
Substituting these values into the formula, we get:
CI = 0.6 ± 1.645*(sqrt(0.6*(1-0.6)/550))
= 0.6 ± 0.042
= (0.558, 0.642)
Therefore, a 90% confidence interval for the proportion of voters who indicated their preference for the candidate is 0.558 to 0.642.
(b) The margin of error for this 90% confidence interval is given by:
ME = z*(sqrt(p*(1-p)/n))
where z is the z-score corresponding to the desired level of confidence and p and n are as before.
Substituting the values we obtained earlier, we get:
ME = 1.645*(sqrt(0.6*(1-0.6)/550))
= 0.042
Therefore, the margin of error for this 90% confidence interval is 0.042.
(c) Without doing any calculations, we can see that the margin of error for an 80% confidence interval will be smaller than that for a 90% confidence interval. This is because as the level of confidence decreases, the corresponding z-score becomes smaller, which in turn results in a smaller margin of error.
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how much more time in hours did Allen spend Listening to music than playing tenis
f.2.88 hours
g.0.48 hours
h.2.40 hours
j.0.12 hours
Answer:
She spent 48 more min listening to music
Your answer is g 0.48 hours
Step-by-step explanation:
I hope this helps
An automatic machine in a manufacturing process is operating groperly if the iengths of an important subcomponent are normally distributed with a mean of izal cri and a otandard deviation of 5.6 cm. A. Find the probability that one selected subcomponent is longer than 122 cm, Probability = B3. Find the probability that if 3 subcomponents are randomly selected, their mean length exceeds 122 cm. Probability win C. Find the probabilify that if 3 are randomly selected, ail 3 have lengths that exceed 122 cm. Probability =
A. The probability that one selected subcomponent is longer than 122 cm can be found by calculating the area under the normal distribution curve to the right of 122 cm. We can use the z-score formula to standardize the value and then look up the corresponding probability in the standard normal distribution table.
z = (122 - μ) / σ = (122 - 100) / 5.6 = 3.93 (approx.)
Looking up the corresponding probability for a z-score of 3.93 in the standard normal distribution table, we find that it is approximately 0.9999. Therefore, the probability that one selected subcomponent is longer than 122 cm is approximately 0.9999 or 99.99%.
B. To find the probability that the mean length of three randomly selected subcomponents exceeds 122 cm, we need to consider the distribution of the sample mean. Since the sample size is 3 and the subcomponent lengths are normally distributed, the distribution of the sample mean will also be normal.
The mean of the sample mean will still be the same as the population mean, which is 100 cm. However, the standard deviation of the sample mean (also known as the standard error) will be the population standard deviation divided by the square root of the sample size.
Standard error = σ / √n = 5.6 / √3 ≈ 3.24 cm
Now we can calculate the z-score for a mean length of 122 cm:
z = (122 - μ) / standard error = (122 - 100) / 3.24 ≈ 6.79 (approx.)
Again, looking up the corresponding probability for a z-score of 6.79 in the standard normal distribution table, we find that it is extremely close to 1. Therefore, the probability that the mean length of three randomly selected subcomponents exceeds 122 cm is very close to 1 or 100%.
C. If we want to find the probability that all three randomly selected subcomponents have lengths exceeding 122 cm, we can use the probability from Part A and raise it to the power of the sample size since we need all three subcomponents to satisfy the condition.
Probability = (0.9999)^3 ≈ 0.9997
Therefore, the probability that if three subcomponents are randomly selected, all three of them have lengths that exceed 122 cm is approximately 0.9997 or 99.97%.
Based on the given information about the normal distribution of subcomponent lengths, we calculated the probabilities for different scenarios. We found that the probability of selecting a subcomponent longer than 122 cm is very high at 99.99%. Similarly, the probability of the mean length of three subcomponents exceeding 122 cm is also very high at 100%. Finally, the probability that all three randomly selected subcomponents have lengths exceeding 122 cm is approximately 99.97%. These probabilities provide insights into the performance of the automatic machine in terms of producing longer subcomponents.
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Solve the following proportion for x. x/5 = 17/11
Answer:
x=85/11
Step-by-step explanation:
\(\frac{x}{5}= \frac{17}{11} \\\\5*\frac{x}{5} =\frac{17}{11} \\\\x=\frac{85}{11}\)
PLZ HELP WITH THIS QUESTION
Three consecutive integers can be represented by n, n + 1, and n + 2. If the sum of three consecutive integers is 57, what are the integers?
Answer:
18, 19, 20
Step-by-step explanation:
please this is half my grade!!!
Benjamin has a ladder that is 15 ft long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 13.8 ft above the ground. What is the angle, rounded to the nearest tenth, that the ladder makes with the ground? Show your work
2. What is the length of side YZ to the nearest tenth? Show your work.
side XY is 11 feet, and angle Z is 35 degrees(this is a right triangle)
3. What are the exact measures of the other two sides of the triangle? Use special right triangles ratios and show your work.
Side AC is 14 feet, this is a right triangle, and angle A is 30 degrees
The special right triangle is the right triangle that have acute angle values
that simplify the process of finding its dimensions.
The correct values are;
1. The angle the ladder makes with the ground, is approximately 66.93°
2. The length of YZ is approximately 19.18 ft.
3. CB = 7 ft. and AB = 7·√3 ft.
Reasons:
1. The length of the ladder = 15 ft.
Height of the ladder above the ground, h = 13.8 ft.
Required:
The angle the ladder makes with the ground.
Solution:
The angle the ladder makes with the ground is given by the equation;
\(sin(\theta) = \dfrac{Length \ of \ the \ ladder}{Height\ of \ the \ ladder \ above the \ ground} = \dfrac{13.8}{15} = 0.92\)
\(\theta = arcsin\left(0.92 \right) \approx 66.93^{\circ}\)
2. The given parameters are;
XY = 11
∠Z = 35°
YZ = Required
In a right triangle, the side facing the acute angle is a leg of the triangle.
Therefore;
XY is the opposite side to ∠Z
\(sin(\angle Z) = \dfrac{XY}{YZ}\)
Which gives;
\(sin(35^{\circ}) = \dfrac{11}{YZ}\)
\(YZ= \dfrac{11}{sin(35^{\circ}) } \approx 19.18\)
YZ ≈ 19.18 ft.
3. AC = 14 ft.
∠A = 30
Required:
The length of the other two sides
Solution:
Where by AC is the hypotenuse side, we have;
CB = AC × sin(∠A)
Therefore;
CB = 14 × sin(30°) = 7
CB = 7 ft.
AB = AC × cos(∠A) = 14 × cos(30°) = 7·√3
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1. The angle the ladder makes with the ground, is approximately 66.93°
2. The length of YZ is approximately 19.18 ft.
3. CB = 7 ft. and AB = 7·√3 ft.
What is the equation of a line that passes through the point (4,-3) and is parallel to the line that passes through the points (-14,-4) and (48,27)?
A. y = -1/2x + 3
B. y = -9x + 9
C. y = 9x - 3
D. y = 1/2x - 5
In the production of a precision mechanical component, a critical dimension is measured every hour, and at that time we take a sample of n=5 units.
From 30 initial samples we find that xbar= 213 and Sbar= 0.8,
What are the centerline and UCL, LCL for the xbar and Sbar charts? (answered already)
xbar centerline - 213
xbar UCL -214.146
xbar LCL - 211.8584
S Chart Centerline - 0.8
S Chart UCL - 0
S Chart LCL -1.6712
3.2 Observing the charts we conclude that the process is in a state of statistical control. If the part specifications are 212 ± 2, what are:
Cp
Cpk
3.3 Two remedies to the low Cpk have been suggested:
- Center the process at the target - i.e. xbar= 212
- Reduce the standard deviation to half of its original value through better tooling maintenance.
Which will achieve a higher Cpk? (Choose one)
1)Shifting xbar
2) Shifting S
3) They will both achieve the same Cpk
4) Neither change will improve Cpk
Please answer 3.2 & 3.3, I already answered 3.1 so I do not need any assistance there. I am just providing the solution as it is needed for the next part.
The values of Cp and Cpk are 1.04 and 0.5 respectively. Since Cpk is less than 1, this indicates that the process is not capable of meeting the specification limits. 3.3
Cp is given by (USL - LSL) / 6S, where USL = 214 and LSL = 210
Cp = (214 - 210) / (6 x 0.8) = 1.04
Cpk is given by min [(USL - Xbar), (Xbar - LSL)] / 3
S = min[(214 - 213), (213 - 210)] / (3 x 0.8)
= 0.5
Therefore, the values of Cp and Cpk are 1.04 and 0.5 respectively. Since Cpk is less than 1, this indicates that the process is not capable of meeting the specification limits. 3.3
The formula for Cpk indicates that the only way to increase it is to decrease the standard deviation S. Therefore, reducing the standard deviation to half of its original value through better tooling maintenance will achieve a higher Cpk. Shifting xbar to 212 will only improve Cp, but it will not improve Cpk. Therefore, the correct answer is option 2 - Shifting S will achieve a higher Cpk.
In this question, we have calculated the values of Cp and Cpk and found that the process is not capable of meeting the specification limits. We have also discussed two remedies to the low Cpk and concluded that reducing the standard deviation to half of its original value through better tooling maintenance will achieve a higher Cpk.
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Cp and Cpk are calculated using the given values and specification limits. In terms of improving Cpk, reducing the standard deviation (option 2) would result in a higher Cpk as it minimizes variability.
Explanation:The capability of the process Cp and Cpk are both measures of how well a process can meet its specification limits. They are defined as follows:
Cp = (USL - LSL) / 6*SbarCpk = min[(USL - X(bar)) / 3*Sbar, (X(bar) - LSL) / 3*Sbar]
Where USL and LSL are the upper and lower specification limits. In this case, they are 214 and 210 respectively as we have 212 +/- 2. Secondly, X(bar) and Sbar are the sample mean and standard deviation, which you've provided as 213 and 0.8 respectively.
For 3.3, the Cpk will be larger in the scenario that reduces the amount of variation or reduces S (option 2). This is because Cpk is sensitive to the spread (or variability) within the process. So if you reduce the standard deviation, there will be less variability and Cpk will increase as a result.
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Solve the inital value problem dy/dt= ey-t sec(y)(1+t2) y(0)=0. Solve the inital value problem.
The solution of the initial value problem is \(\frac{e^{-y}}{2} [siny - cosy] = -e^{-t} [t^2 + 2t + 3] + \frac{5}{2}\).
What is initial value problem?Initial value issues are a specific kind of calculus issue. Calculus initial value issues include differential equations with a known beginning condition that identifies the function's value at a certain point. Finding the function that best describes the system is the goal of these puzzles, and this can be accomplished by integrating the differential equation.
There is always an unknown constant present when doing an integration with an indeterminate integral or without initial conditions. The constant of integration is what is commonly indicated by the letter C.
Given that the initial value problem is:
dy/dt= e^(y-t) sec(y)(1+t2)
This can be re written as follows:
dy/ dt = e^(y-t) (1 + t^2) / sec (y)
Separate the derivative in terms of y and t and take integration:
\(\int{e^{-y}cos(y)} \, dy = \int {e^{-t}(1 + t^2)} \, dt\)
Integrate the following:
\(\frac{e^{-y}}{2} [siny - cosy] = -e^{-t} [t^2 + 2t + 3] + c\\\)
The initial conditions given are y(0) = 0, substitute the value of the variables as 0:
\(\frac{e^{0}}{2} [sin0 - cos0] = -e^{0} [0^2 + 2(0) + 3] + c\\\\\\\frac{1}{2} [-1] = 3 + c\)
c = 5/2
Hence, the solution of the initial value problem is:
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#SPJ4\(\frac{e^{-y}}{2} [siny - cosy] = -e^{-t} [t^2 + 2t + 3] + \frac{5}{2}\)
which expression is equivalent to 4(5x+3y)
Answer:
20x + 12y
Step-by-step explanation:
4 times 5x = 20x
4 times 3y= 12y
Step-by-step explanation:
I am going to assume that the equivalent expression is fully simplified.
To simplify this expression, we use the distributive method.
Using this method we get:
4·(5x+3y) = 4·5x+4·3y
Now that we have the terms seperated, simplify each of them:
4·5x + 4·3y = 20x + 12y
Our expression is now fully simplified so our answer is:
20x + 12y
1. Simplify \( (6-7 i)-(8-5 i)-7 \) 2. Solve, simplify any radicals or complex/imaginary numbers: \( 6 x^{2}=-384 \)
The expressions when simplified are -9 - 2i and x = ±8i
How to simplify the expressionFrom the question, we have the following parameters that can be used in our computation:
(6 -7i) - (8 - 5i) - 7
When evaluated, we have
(6 -7i) - (8 - 5i) - 7 = -9 - 2i
How to solve the equationHere, we have
6x² = -384
Divide by 6
x² = -64
Take the square roots
x = ±8i
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no 5 how do we do with explanation there is answer but how the
that comes
Answer:
I don't understand what is your question?
Answer:
see explanation
Step-by-step explanation:
(sinA + cosA)² + (sinA - cosA)² ← expand using FOIL
= sin²A + 2sinAcosA + cos²A + sin²A - 2sinAcosA + cos²A ← collect like terms
= 2sin²A + 2cos²A
The arrow on the spinner will be spun one more time. Based on these results, what is the probability that the arrow will land on the purple section?
Please please help me
Please answer the question in the picture
Answer: it soo blurry I did not see it
Step-by-step explanation:
12a^5b^8c^-12/10a^-3b^4c^-6
Answer:6
Step-by-step explanation:
valid ways to prove that a figure is a parallelogram.
Answer:
Both pairs of opposite sides are parallel.
Both pairs of opposite sides are congruent.
Both pairs of opposite angles are congruent.
Diagonals bisect each other.
One angle is supplementary to both consecutive angles (same-side interior
Step-by-step explanation:
hope it helps and if it doesnt sorry ;)
The valid way to prove that a figure is a parallelogram is all pairs of consecutive angles are supplementary.
We are given that;
To prove that a figure is a parallelogram.
Now,
This can be done by using the angle measures, the linear pair theorem, or other tools to show that the sum of the measures of any two adjacent angles is 180°.
For example, if we are given that ABCD is a quadrilateral with ∠A + ∠B = 180°,
∠B + ∠C = 180°, ∠C + ∠D = 180°, and ∠D + ∠A = 180°,
then we can conclude that ABCD is a parallelogram by this property.
Therefore, by parallelogram the answer will be all pairs of consecutive angles are supplementary.
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Click the picture..
Step-by-step explanation:
W = mgW= weight
m= mass
g = gravity acceleration ( Gravitational field concentration)
W in earth = 45 kg × 9.8m/s²= 441 N
2. W in moon = 45kg × 9.8× (1/6)
= 441 × (1/6)
= 73.5 N
Answer:
1) 441 N
2) 73.5 N
Step-by-step explanation: