Asap pls pls. I need help, thank you.

When we divide 5 by 6, we have a proper fraction:

Answer: proper fraction

The fraction is 5/6

The dilation of the rectangle stretches it with regards to the distances from the central point

The option that gives the coordinates of the point D is the option;

D (0, 5)

Reason:

The known parameter;

Coordinates of the center of dilation is M(-3, -4)

Scale factor of dilation = 3

The coordinates of the vertex of the rectangle ABCD are;

A(-2, 2), B(3, 2), C(3, -1), and D(-2, -1)

Length MD = \(\sqrt{(-3 - (-2))^2 + (-4 - (-1))^2} = \sqrt{10}\)

Therefore, length of MD' = 3·√10

Slope of MD, is given as follows;

Therefore, y = 3·x

x² + y² = (3·√10)²

x² + (3·x)² = (3·√10)²

10·x² = 90

x = 3

y = 9

We note that the value of x, and y, are calculated as distance from the central point, M, therefore;

The coordinates of the point D' is (-3 + x, -4 + y)

∴ Coordinates of D' = (-3 + 3, -4 + 9) = (0, 5)

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The value of x for the first figure is 2√2 units, the altitude of the equilateral triangle is 25√3 units, the value of x for the third figure is 11.95 and the side of the square is 8√2 units.

According to the question,

We have four figures:

We will use trigonometric functions in first and third one.

1) Sin 45 = x/4

x = 4/√2

x = 2√2 units

2) Perimeter of equilateral triangle = 18

Side of triangle = 18/3

Side of triangle = 6

Now, the altitude means that it makes 90° angle with the base dividing it into two equal halves.

Using Pythagoras theorem:

Altitude = √\(3^{2} +6^{2}\)

Altitude = √9+36

Altitude = √45

Altitude = 3√5 units

3) Using Cos 23:

Cos 23 = 11/x

x = 11/0.9205

x = 11.95 units

4) Diagonal of square = 16 units

Side of the square = diagonal/√2

Side of the square = 16/√2

Side = 8√2 units

Hence, the value of x for the first figure is 2√2 units, the altitude of the equilateral triangle is 25√3 units, the value of x for the third figure is 11.95 and the side of the square is 8√2 units.

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The response y(t) graphically, we can first plot the individual functions h(t) and x(t) on a graph, and then determine their convolution to obtain y(t). Let's go step by step:

Plotting h(t):

The function h(t) is defined as h(t) = [u(t-1) - u(t-4)].

The unit step function u(t-a) is 0 for t < a and 1 for t ≥ a. Based on this, we can plot h(t) as follows:

For t < 1, h(t) = [0 - 0] = 0

For 1 ≤ t < 4, h(t) = [1 - 0] = 1

For t ≥ 4, h(t) = [1 - 1] = 0

So, h(t) is 0 for t < 1 and t ≥ 4, and it jumps up to 1 between t = 1 and t = 4. Plotting h(t) on a graph will show a step function with a jump from 0 to 1 at t = 1.

Plotting x(t):

The function x(t) is defined as x(t) = t[u(t) - u(t-2)].

For t < 0, both u(t) and u(t-2) are 0, so x(t) = t(0 - 0) = 0.

For 0 ≤ t < 2, u(t) = 1 and u(t-2) = 0, so x(t) = t(1 - 0) = t.

For t ≥ 2, both u(t) and u(t-2) are 1, so x(t) = t(1 - 1) = 0.

So, x(t) is 0 for t < 0 and t ≥ 2, and it increases linearly from 0 to t for 0 ≤ t < 2. Plotting x(t) on a graph will show a line segment starting from the origin and increasing linearly with a slope of 1 until t = 2, after which it remains at 0.

Obtaining y(t):

To obtain y(t), we need to convolve h(t) and x(t). Convolution is an operation that involves integrating the product of two functions over their overlapping ranges.

In this case, the convolution integral can be simplified because h(t) is only non-zero between t = 1 and t = 4, and x(t) is only non-zero between t = 0 and t = 2.

The convolution y(t) = h(t) * x(t) can be written as:

y(t) = ∫[1,4] h(τ) x(t - τ) dτ

For t < 1 or t > 4, y(t) will be 0 because there is no overlap between h(t) and x(t).

For 1 ≤ t < 2, the convolution integral simplifies to:

y(t) = ∫[1,t+1] 1(0) dτ = 0

For 2 ≤ t < 4, the convolution integral simplifies to:

y(t) = ∫[t-2,2] 1(t - τ) dτ = ∫[t-2,2] (t - τ) dτ

Evaluating this integral, we get:

\(y(t) = 2t - t^2 - (t - 2)^2 / 2,\) for 2 ≤ t < 4

For t ≥ 4, y(t) will be 0 again.

Maximum value of y(t):

To find the value of t at which y(t) reaches its maximum value, we need to examine the expression for y(t) within the valid range 2 ≤ t < 4. We can graphically determine the maximum by plotting y(t) within this range and identifying the peak.

Plotting y(t) within the range 2 ≤ t < 4 will give you a curve that reaches a maximum at a certain value of t. By visually inspecting the graph, you can determine the specific value of t at which y(t) reaches its maximum.

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Every quadratic nonresidue of p is a primitive root of p, when p = 2^k + 1 is primeIf p = 2^k + 1 is a prime number, we want to show that every quadratic nonresidue of p is a primitive root of p.

In other words, we aim to prove that if an element x is a quadratic nonresidue modulo p, then it is also a primitive root of p.

Let's assume p = 2^k + 1 is a prime number. To prove that every quadratic nonresidue of p is a primitive root of p, we can use the properties of quadratic residues and quadratic nonresidues.

A quadratic residue modulo p is an element y such that y^((p-1)/2) ≡ 1 (mod p), while a quadratic nonresidue is an element x such that x^((p-1)/2) ≡ -1 (mod p).

Now, let's consider an element x that is a quadratic nonresidue modulo p. We want to show that x is a primitive root of p.

Since x is a quadratic nonresidue, we know that x^((p-1)/2) ≡ -1 (mod p). By Euler's criterion, this implies that x^((p-1)/2) ≡ -1^((p-1)/2) ≡ -1^2 ≡ 1 (mod p).

Since x^((p-1)/2) ≡ 1 (mod p), we can conclude that the order of x modulo p is at least (p-1)/2. However, since p = 2^k + 1 is a prime, the order of x modulo p must be equal to (p-1)/2.

By definition, a primitive root of p has an order of (p-1). Since the order of x modulo p is (p-1)/2, it follows that x is a primitive root of p.

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The normal time for the blood test process performed by Beverly Demarr, a hospital lab analyst, is calculated to be 13.92 minutes. The standard time for the blood test is determined to be 14.04 minutes.

a) The normal time for a process is the time it should ideally take to complete the task under standard conditions, without any personal, fatigue, or delay factors. To calculate the normal time, we need to divide the average observed time by the performance rating. In this case, Beverly's average observed time for blood tests is 12 minutes, and her performance rating is 105%. Therefore, the normal time for the process is calculated as follows:

Normal Time = Average Observed Time / Performance Rating

Normal Time = 12 minutes / 105%

Normal Time ≈ 11.43 minutes

b) The standard time for a process includes not only the normal time but also the allowances for personal, fatigue, and delay factors. The total allowance is 16% of the normal time. To calculate the standard time, we add the total allowance to the normal time. Using the calculated normal time of 11.43 minutes, we can determine the standard time as follows:

Total Allowance = Normal Time× Allowance Percentage

Total Allowance = 11.43 minutes × 16%

Total Allowance ≈ 1.83 minutes

Standard Time = Normal Time + Total Allowance

Standard Time = 11.43 minutes + 1.83 minutes

Standard Time ≈ 13.92 minutes

Therefore, the normal time for the blood test process performed by Beverly Demarr is approximately 13.92 minutes, and the standard time for the blood test is approximately 14.04 minutes.

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The z score that represents the 27th percentile in the standard normal distribution is -0.61.

The standard normal distribution has a mean of 0 and a standard deviation of 1. To find the z score that represents the 27th percentile, we need to find the value of z that corresponds to a cumulative probability of 0.27. Using a standard normal distribution table or calculator, we can find that the closest cumulative probability to 0.27 is 0.2660. The corresponding z score for this probability is -0.61.

To further explain, we can use the following steps to find the z score that represents the 27th percentile:
1. Identify the area to the left of the desired percentile: Since we want to find the z score that represents the 27th percentile, we need to find the area to the left of this percentile. This is simply the cumulative probability up to this point, which is 0.27.
2. Look up the z score for the area using a standard normal distribution table or calculator: Once we have the area, we can look up the corresponding z score using a standard normal distribution table or calculator. The closest cumulative probability to 0.27 is 0.2660, and the corresponding z score for this probability is -0.61.
Therefore, the z score that represents the 27th percentile in the standard normal distribution is -0.61.

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Answer:

Step-by-step explanation:

50.24n2

Answer:

\(\tan \angle T = \dfrac{SR}{TS} = \dfrac 43\)

Step-by-step explanation:

The weightage is given to the most recent values in the time series.

SES is a simple forecasting technique that is easy to implement and can be used with data that has a consistent trend. However, it is not well suited for data that is highly volatile or has a lot of noise.

One of the simplest forecasting techniques is single exponential smoothing (SES). It is a weighted average of past time-series values, where the weightage is given to the most recent values in the time series. This technique is easy to implement and can be used with data that has a consistent trend. However, it is not well suited for data that is highly volatile or has a lot of noise.

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In a two-tailed test, the significance level refers to the combined area under the distribution in both rejection regions, which are located in the extreme ends of the distribution.

1. In a two-tailed test, the null hypothesis is tested against the alternative hypothesis that the parameter is either greater or less than the null value.
2. The significance level, usually denoted by α, is split between the two tails of the distribution. This means that half of the significance level is assigned to the left tail, and the other half is assigned to the right tail.
3. The rejection regions are defined by the critical values, which are the values that separate the acceptance region from the rejection regions.
4. If the test statistic falls within either of the rejection regions, the null hypothesis is rejected in favor of the alternative hypothesis.

In summary, in a two-tailed test, the significance level is divided equally between the two tails, and the area under the distribution in the rejection regions represents the probability of rejecting the null hypothesis when it is true.

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The slope-intercept formula is one of the formulas used to determine a line's equation. Y = mx + b is the slope-intercept formula for a line with slope m and y-intercept b. Any point on the line is (x, y) in this case.

Using a straight line's slope and the location of its y-axis intersection, the slope intercept equation can be used to determine the general equation of the line. Y = mx + b is the equation in slope intercept form.

One of the formulas used to get a line's equation is the slope-intercept formula. Y = mx + b is the slope-intercept formula for a line with slope m and y-intercept b. Any point on the line is (x, y) in this case.

The variables we'll use in our function will be as follows:

m = slope, and b = y-intercept.

It is written as y = mx + b. The m and b variables are changed to numbers, while the x and y variables stay as letters (for example, y = 2x + 4, slope = 2, and y-intercept = 4).

The slope and intercept from an equation are used in the following video through a few examples.

y = mx + b

The slope and intercept are the two integers that make up this equation, which is why it is known as the slope-intercept form.

Remember, the slope (m) is the amount being multiplied to x and the intercept (b) is the number being added or subtracted

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Answer:

258

Step-by-step explanation:

Check the tenth place. It is 4 which is < 5. So, ignore and write the whole number as it is

So, 258.42 = 258

The value of RS is 21.57

Trigonometric ratios are used to calculate the measures of one (or both) of the acute angles in a right triangle, if you know the lengths of two sides of the triangle.

sin(θ) = opp/hyp

cos(θ) = adj/hyp

tan(θ) = opp/adj

The side facing the acute angle is the opposite and the longest side is the hypotenuse.

therefore, adj is 22 and RS is the hypotenuse.

Therefore;

cos(θ) = 20/x

cos 22 = 20/x

0.927 = 20/x

x = 20/0.927

x = 21.57

Therefore the value of RS is 21.57

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Given the following information: Five years ago, someone used her $40,000 saving to make a down payment for a townhouse in RTP. The house is a three-bedroom townhouse and sold for $200,000 when she bought it. After paying down payment, she financed the house by borrowing a 30-year mortgage.

Mortgage interest rate is 4.25%. Right after closing, she rent out the house for $1,800 per month. In addition to mortgage payment and rent revenue, she listed the following information so as to figure out investment return: 1. HOA fee is $75 per month and due at end of each year 2. Property tax and insurance together are 3% of house value 3. She has to pay 10% of rent revenue for an agent who manages her renting regularly 4. Her personal income tax rate is 20%. While rent revenue is taxable, the mortgage interest is tax deductible. She has to make the mortgage amortization table to figure out how much interest she paid each year 5. In the last five years, the market value of the house has increased by 4.8% per year 6.

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Answer:

Step-by-step explanation:

The loop will run an infinite number of times

a) The earnings of Portfolio 1 are given as follows: $679.5.

b) The Portfolio with the greatest earnings is: Portfolio 1.

The earnings are found by the sum of the multiplication of the equivalent decimal of the return by the investment.

The equivalent decimals are given as follows:

Then the earnings of the Portfolio 1 are given as follows:

0.028 x 1425 - 0.0155 x 1380 + 0.117 x 3400 + 0.0849 x 3100 = $679.5.

The earnings of the Portfolio 2 are given as follows:

0.028 x 4500 - 0.0155 x 3600 + 0.117 x 2150 + 0.0849 x 1980 = $489.86.

Hence Portfolio 1 earned the most, as 679.5 > 489.86.

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The product of the factors also has real coefficients and is equal to the polynomial. Given P(x) P(x) = = 9x5 +24x4 - 68x³ - 94x² + 21990, we can factor the polynomial in order to write it in factored form.

Given P(x) P(x) = = 9x5 +24x4 - 68x³ - 94x² + 21990, we can factor the polynomial in order to write it in factored form. Here’s how:

Step 1: Take out the greatest common factor

The greatest common factor of the terms is 1. Therefore, we cannot take out any common factor.

Step 2: Check for sum or difference of two cubes

This polynomial cannot be factored using the sum or difference of two cubes.

Step 3: Check for quadratic form

The polynomial can be expressed in a quadratic form. We can factor it using the quadratic formula.

x = [-b ± sqrt(b^2 - 4ac)] / 2a

Here, a = 9, b = 24, c = 21990

The discriminant is D = b^2 - 4acD = (24)^2 - 4(9)(21990)

D = -1740768

Since the discriminant is negative, there are no real solutions. Therefore, the polynomial cannot be factored in the real number system.

However, we can still write the polynomial in factored form using imaginary numbers.  This is P(x) = (3x - 10i)(x - 2i)(x + 2i)(x + 5)(3x - 10), where i = sqrt(-1)

Note that each complex conjugate (3x - 10i)(3x + 10i) and (x - 2i)(x + 2i) produce a quadratic polynomial that has real coefficients and the other factors (x + 5) and (3x - 10) are both linear factors with real coefficients. Therefore, the product of the factors also has real coefficients and is equal to the polynomial.

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the answer is

Y=(X+3)^2-6

the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h

Let's define the variables:

B = speed of the boat in still water.

S = speed of the stream.

When the boat travels downstream, the total speed of the boat will be equal to the sum of the speed of the stream and the speed of the boat in still water:

speed = B + S

When the boat goes downstream, the speed will be:

speed = B - S

Now, also remember the relation:

speed*time = distance.

The given information is:

In 8 hours the boat can:

go 12 km upstream and 40km downstream.

We now need to define another variable, T, as the time that the boat travels upstream.

Then we can write this as:

12km = (B - S)*T

If the boat travels T hours upstream, and travels for a total of 8 hours, then the amount of time that travels downstream is 8h - T, then we can write:

40km = (S + B)*(8h - T)

Similarly, when we have:

"it can go 16 km upstream and 32 km downstream in the same time."

we can define a new variable T', and write:

16km = (B - S)*T'

32km = (S + B)*(8h - T')

Then we have a system of 4 equations:

16km = (B - S)*T'

32km = (S + B)*(8h - T')

40km = (S + B)*(8h - T)

12km = (B - S)*T

And we need to solve this for S and B.

To do it, we need to isolate one of the variables in one of the equations.

Let's isolate T in the last equation:

T = 12km/(B - S)

now we can replace that in the third equation to get:

40km = (S + B)*(8h - 12km/(B - S))

So now we have 3 equations:

16km = (B - S)*T'

32km = (S + B)*(8h - T')

40km = (S + B)*(8h - 12km/(S - B))

Now we need to do the same thing, this time let's isolate T' in the first equation and replace it in the second one:

T' = 16km/(B - S)

Replacing it in the second equation we get:

32km = (S + B)*(8h - T')

32km = (S + B)*(8h - 16km/(B - S))

So now we have two equations:

40km = (S + B)*(8h - 12km/(B - S))

32km = (S + B)*(8h - 16km/(B - S))

Let's simplify these:

40km = 8h*(S + B) - 12km*(S + B)/(B - S)

32km = 8h*(S + B) - 16km*(S+ B)/(B - S)

Now we can multiply both equations by (B - S) to get:

40km*(S - B) = 8h*(S + B)*(B - S) - 12km*(S + B)

32km*(S - B) = 8h*(S + B)*(B - S) - 16km*(S+ B)

Let's keep simplifying this:

40km*(B - S) + 12km*(S + B) =  8h*(S + B)*(B - S)

32km*(B - S)  + 16km*(S+ B) = 8h*(S + B)*(B - S)

Now we get:

52km*B - 28km*S = 8h*(S^2 + B^2)

48km*B - 16km*S = 8h*(S^2 + B^2)

Notice that the right side of these equations is the same thing, then we can write:

52km*B - 28km*S = 48km*B - 16km*S

(52km - 48km)*B = (28km - 18km)*S

4km*B  =  10km*S

B = (10/4)*S

B = (5/2)*S

Now we can replace this in one of our two equations, let's use the first one:

48km*B - 16km*S = 8h*(S^2 + B^2)

48km*(5/2)*S - 16km*S = 8h*( S^2 + ( (5/2)*S)^2)

Now we can solve this for S

104km*S = 8h*( S^2 + 25/4*S^2)

104km*S = 8h*(29/4*S^2) = 48h*S^2

104km*S = 48h*S^2

dividing at both sides by S we get:

104km = 48h*S

104km/48h = S = 2.167 km/h

And using B = (5/2)*S

We can find the speed of the boat:

B = (5/2)*2.167 km/h = 5.418 km/h

Then:

the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h

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Answer:

-1

Step-by-step explanation:

First you simplify your parenthesis, then subtract 2x from both sides. Then subtract both sides by 2, then finally divide both sides by 10. x > -1 So n = -1

Hope I helped! :)

The triangle with sides 6cm , 8cm and 10cm is a Right Triangle .

A Triangle is called as a Right Triangle if the square of the longest side(hypotnuse) is equal to the sum of square of the other two sides .

the sides of the triangle are given as 6cm , 8cm and 10cm .

the longest sides (hypotnuse) is = 10 cm ;

the perpendicular is = 6cm ;

the base is = 8 cm ;

According to the definition of Right triangle ;

10² = 6² + 8²

100 = 36 + 64

100 = 100

Therefore , Yes , the sides 6cm ,8cm and 10cm forms a Right Triangle .

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Answer:

24

Step-by-step explanation:

4 times 4

8 times 8

Subtract the 2 #'s

Then divide your answer by 2.

Step-by-step explanation:

use Pythagoras theorem

hypotenuse² = base² + height²

8²=base²+4²

64-16=B²

√48=B

√2×3×2×2×2=B

2×2√3

4√3 = B

hope it helps

The following will be the code to input an integer and determine its square root:

Number = Abs(Int(Input("Enter a number:")))

num sqrt = num**0.5

print('the outcome is as follows:',num sqrt)

Please enter -16.

the ultimate result is 4.0.

A set of preset, sequential actions that a computer is designed to perform is known as a program. The 1945 description of the modern computer by John von Neumann contained a series of instructions that the device carried out one at a time. Frequently, the program is kept in a place that the computer can access.

Make a computer software that can take an integer and find its square root of it. Use the absolute value function to ensure that the software won't crash if the user enters a negative integer.

Then, don't forget to print a statement that starts with "The final result is," is followed by the square root, to turn the conclusion into a string.

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Answer:

2 1/4

Step-by-step explanation:

hi <3

I hope i helped you [ ;

Answer:

If it is warm outside, then it is summer

Step-by-step explanation:

To find the converse, interchange the hypothesis and the conclusion

"If it is summer, then it is warm outside"

If it is warm outside, then it is summer

Answer:

A. If it is warm outside, then it is summer

Step-by-step explanation:

statement "If it is summer, then it is warm outside" : warm=summer

A. If it is warm outside, then it is summer. : warm = summer ✓

B. If it is not warm outside, then it is summer. : not warm = summer x

C. If it is warm outside, then it is not summer. : warm =not  summer x

D. If it is not warm outside, then it is not summer. : not warm = not summer x

Answer:

\(\dfrac{1}{2}\) day

Step-by-step explanation:

Given that:

Owen who is an alien has only 4/5 of his socks clean.

and he wears 2/5 socks a day.

Out of his total 4/5 clean socks.

It will take him (4/5 ÷ 2/5) days to wash all his socks

i.e

the numbers of days since he washed all his socked is:

= \(\dfrac{4}{5} \div \dfrac{2}{5}\)

= \(\dfrac{4}{5} \times \dfrac{5}{2}\)

= \(\dfrac{1}{2}\)