as we configure the device and work with various settings to ensure the best quality environment possible, it is important to track and monitor various events so that if they need to be responded to, it can be done so in a timely manner. which of the following components of policies will allow for event-based monitoring?
A) Local group policy
B) Local security policy
C) Group policy
D) Audit login failures

Answer:

gdyc ddxtfvytg4dgtfxdwcftcd3rcby

If the crankshaft end play is out of specifications, check for:

Thrust Bearings

Main Bearings

Crankshaft

Crankshaft Thrust Washers

Engine Block

To understand the crankshaft when it is out of specifications, check for:

Thrust Bearings: Check the condition of the thrust bearings, which are located at the front and/or rear of the engine block. Excessive wear or damage to the thrust bearings can contribute to increased crankshaft end play.

Main Bearings: Inspect the main bearings, which support the crankshaft within the engine block. Worn or damaged main bearings can cause excessive movement of the crankshaft.

Crankshaft: Check the crankshaft itself for any signs of damage, such as scoring or bending. A damaged crankshaft may not sit properly within the bearings, leading to increased end play.

Crankshaft Thrust Washers: Some engines use thrust washers to control the end play of the crankshaft. Inspect these washers for wear, damage, or improper installation.

Engine Block: Check the engine block for any signs of damage or distortion that may affect the alignment and support of the crankshaft.

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Optimism and open-mindedness can greatly contribute to the success of engineers in their jobs by fostering a positive and adaptable mindset.

Firstly, **optimism** enables engineers to approach challenges with a positive attitude and belief in their ability to find solutions. It helps them maintain motivation, resilience, and a proactive approach in the face of obstacles. Optimistic engineers are more likely to persevere through difficulties, think creatively, and explore multiple avenues to solve complex problems.

Secondly, being **open-minded** allows engineers to embrace new ideas, perspectives, and technologies. Open-minded engineers are willing to consider different approaches, listen to diverse viewpoints, and learn from others. This mindset promotes collaboration, encourages knowledge sharing, and facilitates continuous learning and growth. It also enables engineers to adapt to changing circumstances, embrace innovation, and discover novel solutions.

By combining optimism and open-mindedness, engineers can create an environment conducive to exploration, innovation, and effective problem solving. These qualities promote a positive work culture, enhance teamwork, and contribute to the successful execution of engineering projects.

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Z≤ -4.852 ft, Maximum efficiency is η≅ 0.88 ≅ 88% is the maximum discharge possible

Solution

Given Data:-

D = 14.62in, N = 2134 rc/min, T=20°C. At T= 20°C ɣ=ρg= 62.35 lb/ft³, vapor pressure. Pv = 49.2 lb/ft².

The efficienies at each flow rate is computal by using formula

η = ρgθH / (550) (bhp)

→ As we can See the maximum efficiency point is at θ = 6ft³/s (close to 6ft³/s)

Maximum efficiency is η≅ 0.88 ≅ 88%

b) Given NPSHR = 16 ft,hg=22ft. Zactual. = 9ft  (below the sea surface)

To avoid cavitation NPSH < Pa - Pv/ρg - Z - hf

Z < Pa - Pv/ρg - hf

Z < 2116 - 49.2/62.35 - 16 - 22 [1 atm = 2116 lb/ft2]

Z≤ -4.852 ft

-> Keeping the pump 9 ft below the surface gives 4.148 ft of marign against cavitation.

Hence it is Sufficient to avoid cavitation.

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In the given circuit, Z3, Z2, Z1, and Z0 represent the outputs of the 2-to-4 decoder, which are controlled by the priority encoder inputs A, B, C, and D (with I3 having the highest priority). The functions realized by Z3, Z2, Z1, and Z0 are:

- Z3: active when A, B, and C are low, and D is high.
- Z2: active when A and B are low, C is high, and D is irrelevant.
- Z1: active when A is low, B is high, and C and D are irrelevant.
- Z0: active when A is high, and B, C, and D are irrelevant.

The functions of A, B, C, and D that are realized by Z3, Z2, Z1, and Z0 respectively are given below: Z3 = I3 + I2 + I1 + I0Z2 = I3 + I2 + I1' I0'Z1 = I3 + I2' I1 + I1' I0'Z0 = I3 + I2' I1' I0Note: Here, I3 is the highest priority input while I0 is the lowest priority input, hence the values of Z3, Z2, Z1, and Z0 are such that they correspond to the highest priority input (I3) to the lowest priority input (I0). The truth table for the priority encoder is given in the image below: Truth table for the priority encoderTherefore, the output of the encoder is such that when a signal is active high, its corresponding input signal is converted into a binary format with the highest priority input (I3) taking the most significant bit while the lowest priority input (I0) takes the least significant bit.

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Answer:

Tungsten element has the second highest melting point. Pure tungsten can easily cut down with the help of hacksaw.

Answer: Because it does not undergo oxidation and it has a very high melting point when it glows in bulb it temperature goes upto 2500°C

Step-by-step Explanation:

The strength is mainly depends on the some of factors which are described below.

●molecular structure:- The molecular structure is responsible fir the intermolecular force of a metal or material which causes the increase and decrease of strngth of a metal. Tungsten molecular structure is much stringer then that of aluminium.

●Temperature:-The temlerature also plays a rule in the strenghtNess of a metal. Tge high temprature makes a metal soft.

●Composition :- The composition is mostly important for the strengthnesa of material. For ex the pure iron metal is much weeker the alotrophy of iron.

Based on the image attached, the reading of micrometer is= 15.20.

You will see a line of numbers running down the barrel of your micrometer, starting with the barrel scale. On the barrel scale, each number corresponds to 0.100. Looking at the barrel, 1 equals 0.100, 2 equals 0.200, 3 equals 300, and so on. The distance between each tick mark and the larger numbers on the barrel is 0.025, or 25 thousandths. 

Note that micrometer is one that is also referred to as a micrometer screw gauge—is a tool with a calibrated screw that is frequently used for precise measurement of components in mechanical engineering, and others.

Looking at the image, you will see the stop ends at 15 and  and 20 so adding them together will be option A. 15.20.

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Using APA reference style, the references is attached below from Feldman, R. S. (2013) to American Psychology Association (2020)

APA reference style is a style of citing sources used by the American Psychological Association. It is primarily used in the social sciences and includes guidelines for citing sources both within the text of a document and in the reference list at the end of the document. The guidelines provide a consistent way of citing sources to make it easier for readers to identify and locate the sources cited in a document.

In the given problem, if we need to write the reference using APA style, it will take this format below

Reference Page:

Feldman, R. S. (2013). Psychology and your life (2nd ed.). New York, NY: McGraw Hill Companies.

Frontline. (n.d.). League of denial. Retrieved from https://www.pbs.org/wgbh/frontline/film/league-of-denial/

Friends. (2004). The one after Joey and Rachel kiss [Television series episode]. In D. Crane, & M. Kauffman (Executive producers), Friends. Burbank, CA: Warner Bros. Television.

Silver Linings Playbook. (2012). [Motion Picture]. United States: The Weinstein Company.

U.S. Energy Information Administration. (2013). Annual energy outlook 2013 with projections to 2040. Retrieved from http://www.eia.gov/forecasts/aeo/er/pdf/0383er(2013).pdf

Snickers. (2013, April 2). You’re not you when you’re hungry [Video file]. Retrieved from https://youtu.be/2rF_FRCd_LA

American Psychological Association. (2020). Publication manual of the American Psychological Association (7th ed.). doi:10.1037/0000165-000

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Answer:

Bulk modulus: ß = - ∆p/(∆V/V)

∆p = (3039 - 1520)x10³ = 1519 kPa

∆V = 1231 - 1232 = -1 m³

V = 1232 m³

ß = - 1519/(-1/1232) = 1.87x10^6 kPa = 1.87 GPa

Explanation:

a.The average bulk modulus of elasticity of the liquid is 1.87 GPa

b. Coefficient of compressibility 0.5437 GPa-¹

c Velocity of sound 1.87 x 10^9P

a. Bulk modulus of elasticity

ß = - ∆p/(∆V/V)

First step  is to determine ∆p

∆p = (3039 kpa - 1520 kpa)x10³

∆p  = 1519 kPa

Second step is to determine ∆V

∆V = 1231 litres - 1232 litres

∆V = -1 m³

Now let determine the Bulk modulus of elasticity

Bulk modulus of elasticity= - 1519/(-1/1232)

Bulk modulus of elasticity= 1.87x10^6 kPa

Bulk modulus of elasticity= 1.87 GPa

b. The coefficient of compressibility

Coefficient of compressibility=β =1/K

Coefficient of compressibility=β =1/1.87

β =0.5437 GPa-¹

C. Velocity of sounds  in the medium with a density of 1593 kg/m3

V=√K/ρ

V=√1.87×10^9/ 1593

V=1083m/s

V = 1.87 x 10^9P

Inconclusion:

a.The average bulk modulus of elasticity of the liquid is 1.87 GPa

b. Coefficient of compressibility 0.5437 GPa-¹

c Velocity of sound 1.87 x 10^9P

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The problem resulting from using a seat warmer for too long is called "Toasted Skin Syndrome." In rare situations, the condition may cause skin cancer.

Toasted Skin Syndrome is also known as erythema ab igne. It is a condition that causes skin discoloration and pigmentation due to prolonged exposure to low heat. This condition is generally caused by extended periods of exposure to heat sources such as a laptop, heating pad, hot water bottle, or seat warmer. The heat source doesn't have to be too hot to cause this condition.

It takes long-term exposure to lower heat to create this problem. Toasted skin syndrome appears like a spotty or patchy reddish or brownish discoloration of the skin. It is most frequently seen on the thighs, arms, and legs, but it can occur anywhere on the body.

This is a non-cancerous condition that can go away on its own once the heat source has been removed. The affected skin may feel warm, itchy, or tender to the touch. Furthermore,  Therefore, it is essential to take precautions to avoid prolonged exposure to heat sources.

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Answer:

stink

Explanation:

d. diffusion flux

The quantity of mass diffusing through and perpendicular to a unit cross-sectional area of material per unit time is known as diffusion flux.

It represents the rate at which mass is transported due to diffusion across a concentration gradient. Diffusion flux is governed by Fick's laws of diffusion, which describe the behavior of diffusive processes in various materials and systems. Fick's second law specifically deals with the time rate of change of concentration and is often used to analyze diffusion phenomena. Activation energy, on the other hand, is a concept related to chemical reactions and the energy required to initiate a reaction. Membrane separation refers to a process that uses membranes to separate different components of a mixture based on their size or properties.

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Answer:

Option 2, In seismic areas, the most crucial requirement for precast concrete is to tie elements together laterally

Explanation:

In seismic areas, the in-plane lateral  forces are very larger and hence in order to restrict the lateral movement governed by the lateral force, lateral ties are essential .

Specific design detailing such as interior and  perimeter ties in the floors causes diaphragm behavior and hence distribute the load evenly without any movement.

Hence, option 2 is correct

Answer: i believe it’s acoustics

Explanation:

Answer:

(a) the velocity ratio of the machine (V.R) = 1

(b) The mechanical advantage of the machine (M.A) = 0.833

(c) The efficiency of the machine (E) = 83.3 %

Explanation:

Given;

load lifted by the pulley, L = 400 N

effort applied in lifting the, E = 480 N

distance moved by the effort, d = 5 m

(a) the velocity ratio of the machine (V.R);

since the effort applied moved downwards through a distance of d, the load will also move upwards through an equal distance 'd'.

V.R = distance moved by effort / distance moved by the load

V.R = 5/5 = 1

(b) The mechanical advantage of the machine (M.A);

M.A = L/E

M.A = 400 / 480

M.A = 0.833

(c) The efficiency of the machine (E);

\(E = \frac{M.A}{V.R} \times 100\%\\\\E = 0.833 \ \times \ 100\%\\\\ E = 83.3 \ \%\)

Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

Answer:

a) \(\mathbf{Q_c = -3730.8684 \ Btu/hr}\)

b) \(\mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}\)

Explanation:

From the properties of Super-heated Refrigerant 134a Vapor at \(T_1 = 40^0 F\), \(P_1 = 30 \ lbf/in^2\) ; we obtain the following properties for specific enthalpy and specific entropy.

So; specific enthalpy \(h_1 = 109.12 \ Btu/lb\)

specific entropy \(s_1 = 0.2315 \ Btu/lb.^0R\)

Also; from the properties of saturated Refrigerant 134 a vapor (liquid - vapor). pressure table at \(P_2 = 160 \ lbf/in^2\) ; we obtain the following properties:

\(h_2 = 115.91 \ Btu/lb\\\\ s_2 = 0.2157 \ Btu/lb.^0R\)

Given that the power input to the compressor is 2 hp;

Then converting to  Btu/hr ;we known that since 1 hp = 2544.4342 Btu/hr

2 hp = 2 × 2544.4342 Btu/hr

2 hp = 5088.8684 Btu/hr

The steady state energy for a compressor can be expressed by the formula:

\(0 = Q_c -W_c+m((h_1-h_e) + \dfrac{v_i^2-v_e^2}{2}+g(\bar \omega_i - \bar \omega_e)\)

By neglecting kinetic and potential energy effects; we have:

\(0 = Q_c -W_c+m(h_1-h_2) \\ \\ Q_c = -W_c+m(h_2-h_1)\)

\(Q_c = -5088.8684 \ Btu/hr +200 \ lb/hr( 115.91 -109.12) Btu/lb \\ \\\)

\(\mathbf{Q_c = -3730.8684 \ Btu/hr}\)

b)  To determine the entropy generation; we employ the formula:

\(\dfrac{dS}{dt} =\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c\)

In a steady state condition \(\dfrac{dS}{dt} =0\)

Hence;

\(0=\dfrac{Qc}{T}+ m( s_1 -s_2) + \sigma _c\)

\(\sigma _c = m( s_1 -s_2) - \dfrac{Qc}{T}\)

\(\sigma _c = [200 \ lb/hr (0.2157 -0.2315) \ Btu/lb .^0R - \dfrac{(-3730.8684 \ Btu/hr)}{(40^0 + 459.67^0)^0R}]\)

\(\sigma _c = [(-3.16 ) \ Btu/hr .^0R + (7.4667 ) Btu/hr ^0R}]\)

\(\mathbf{\sigma _c = 4.3067 \ Btu/hr ^0R}\)

To determine the type of the system, we need to find the number of poles at the origin (i.e., the number of integrators) in the open-loop transfer function.

The open-loop transfer function, G(s), has three poles at the origin (s² term in the denominator). Hence, the system is a Type 3 system.

Now let's calculate the steady-state error for each input using the steady-state error formula:

1. For the input 80u(t):

The steady-state error, E(s), is given by E(s) = 1 / (1 + G(s)). Since the input is a step function (u(t)), we can substitute s with 0 in the transfer function.

E(s) = 1 / (1 + G(0))

E(s) = 1 / (1 + 60(34)(4)(8) / (0)(6)(17))

Since there is an integrator in the system, the steady-state error for a step input is zero (E(s) = 0).

2. For the input 80tu(t):

The steady-state error, E(s), is given by E(s) = 1 / (1 + G(s)) * 1/s. We can substitute s with 0 in the transfer function.

E(s) = 1 / (1 + G(0)) * 1/0

E(s) = ∞

The steady-state error for a ramp input is infinity.

3. For the input 80t²u(t):

The steady-state error, E(s), is given by E(s) = 1 / (1 + G(s)) * 1/s². We can substitute s with 0 in the transfer function.

E(s) = 1 / (1 + G(0)) * 1/0²

E(s) = ∞

The steady-state error for an acceleration input is also infinity.

In summary:

The complete question should be:

\(80t^{2}u(t)\)

For a unity feedback system with feedforward transfer function as

\(G(s)\frac{60(s+34)(s+4)(s+8)}{s^{2}(s+6)(s+17)}\)

The type of system is:

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Answer:

a) the output voltage is 50 V

b)

- the average inductor current is 10 A

- the maximum inductor current is 13 A

- the maximum inductor current is 7 A

c) the output voltage ripple is 0.006 or 0.6%V₀

d) the average current in the diode under ideal components is 4 A

Explanation:

Given the data in the question;

a) the output voltage

V₀ = V\(_s\)/( 1 - D )

given that; V\(_s\) = 20 V, D = 0.6

we substitute

V₀ = 20 / ( 1 - 0.6 )

V₀ = 20 / 0.4

V₀ = 50 V

Therefore, the output voltage is 50 V

b)

- the average inductor current

\(I_L\) = V\(_s\) / ( 1 - D )²R

given that R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6

we substitute

\(I_L\) = 20 / (( 1 - 0.6 )² × 12.5)

\(I_L\) = 20 / (( 0.4)² × 12.5)

\(I_L\) = 20 / ( 0.16 × 12.5 )

\(I_L\) = 20 / 2

\(I_L\) = 10 A

Therefore, the average inductor current is 10 A

- the maximum inductor current

\(I_{Lmax\) = [V\(_s\) / ( 1 - D )²R] + [ V

given that, R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6, L = 10 μH, T = 1/200 kHz = 5 hz

we substitute

\(I_{Lmax\) = [20 / (( 1 - 0.6 )² × 12.5)] + [ (20 × 0.6 × 5) / (2 × 10) ]

\(I_{Lmax\) = [20 / 2 ] + [ 60 / 20 ]    

\(I_{Lmax\) = 10 + 3

\(I_{Lmax\) = 13 A

Therefore, the maximum inductor current is 13 A

- The minimum inductor current

\(I_{Lmax\) = [V\(_s\) / ( 1 - D )²R] - [ V

given that, R = 12.5 Ω, V\(_s\) = 20 V, D = 0.6, L = 10 μH, T = 1/200 kHz = 5 hz

we substitute

\(I_{Lmin\) = [20 / (( 1 - 0.6 )² × 12.5)] - [ (20 × 0.6 × 5) / (2 × 10) ]

\(I_{Lmin\) = [20 / 2 ] -[ 60 / 20 ]    

\(I_{Lmin\) = 10 - 3

\(I_{Lmin\)  = 7 A

Therefore, the maximum inductor current is 7 A

c)  the output voltage ripple

ΔV₀/V₀ = D/RCf

given that; R = 12.5 Ω, C = 40 μF = 40 × 10⁻⁶ F, D = 0.6, f = 200 Khz = 2 × 10⁵ Hz

we substitute

ΔV₀/V₀ = 0.6 / (12.5 × (40 × 10⁻⁶) × (2 × 10⁵) )

ΔV₀/V₀ = 0.6 / 100

ΔV₀/V₀ = 0.006 or 0.6%V₀

Therefore, the output voltage ripple is 0.006 or 0.6%V₀

d) the average current in the diode under ideal components;

under ideal components; diode current = output current

hence the diode current will be;

\(I_D\) = V₀/R

as V₀ = 50 V and R = 12.5 Ω

we substitute

\(I_D\) = 50 / 12.5

\(I_D\) = 4 A

Therefore, the average current in the diode under ideal components is 4 A

Answer: Sails are made from a wide variety of fabrics, from natural fibers, such as flax, hemp, and cotton in various forms of sails canvas to synthetic fibers such as polyester, nylon, aramids, laminate and carbon fibers.

Explanation:

The correct answer is Specific weight: w = [weight ÷ volume] = [9N ÷ 0.001m³] = 9000N/m³Density: w = [ × g] Where, g = acceleration due to gravity = 9.81m/sec². Specific gravity: G = [density of liquid ÷ density of water] As you know, The density of water = 1000kg/m³.

The density of a substance is divided by the density of water at 4 degrees Celsius to determine its specific gravity. The density of the substance and the density of the water must be represented in the same units for the calculation.distinguishes  While specific weight has dimensions, specific gravity is a dimensionless number. The gravitational field has no effect on a material's specific gravity, but it does have an effect on a material's specific weight. A substance's "Specific Gravity" is determined by dividing its mass by the mass of an equivalent volume of water at the same pressure and temperature.

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The option that is an example of Guarding are:

Circuit breaker locks are used to prevent the unintentional or deliberate shutting off of certain electrical circuits. A circuit breaker lock is fitted on a Square-D circuit breaker, which is suitably colored red and marked. This breaker lock can only be opened with a key.

Guarding is situating or enclosing electric equipment to prevent individuals from unintentionally coming into touch with live parts. Effective guarding necessitates placing equipment with exposed parts that operates at 50 volts or more in a location that is only accessible to authorized individuals who are competent to deal with it.

Shielding, protective barriers, or insulating materials must be used to protect workers from electric shock, burns, or other electrical-related injuries when working on exposed low-voltage parts that may be touched or that may generate hazardous electrical heat or arcing.

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1) No matter how hard you try, Sarah will not be persuaded.

2) The kids are excited to go on vacation.

3. He opted to travel for business in September as opposed to May.

4) They pushed me work hard on my studies while I was in college.

5) I went to my neighbourhood bank to ask about obtaining a loan.

Note: Number 5's corrected sentence was puzzling. I assumed that asking about loans was the intended meaning. If you would like more information so that I can understand what you meant, please let me know.

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The values of h at the two internal boundaries are :

Given data :

Z₁ = Z₂ = Z₃ = 25 m

h top = 120 m

h bottom = 100 m

K₁ = 0.0001 m/s

K₂ = 0.0005 m/s

K₃ = 0.0010 m/s

we will apply the formula below since flow is perpendicular to the bedding plane

Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\)  ----- ( 1 )

Insert values given above into equation 1

Therefore ; Keq = 2.307 * 10⁻⁴ m/s

Hydraulic gradient ( Ieq ) = head loss / length

                                          = ( 120 - 100 ) / 3 * 25

                                   Ieq  = 0.266

Given that the flow is perpendicular to bedding plane

q1 = q2 = q3

V₁ = V₂ = V₃ = V

K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq

Hence :

V = Keq* Ieq

   = 2.307 * 10⁻⁴ * 0.266

   = 6.15 * 10⁻⁵ m/s .

Also;

K₁i₁ =  Keq * ieq = K₂i₂ = K₃i₃

therefore :

  i₁ = 0.615

  i₂ =  0.123

  i₃ = 0.0615

Pressure at point 1 ( i.e. pressure between first two formations )

h₁ = h top - i₁L₁

   = 120 - 0.615 * 25

   = 104.625 m

Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )

h₂ = h₁ - i₂L₂

    = 104.625 - 0.123 * 25

    = 101.55 m

Therefore we can conclude that The values of h at the two internal boundaries are :  h₁ = 104.625 m , h₂ = 101.55 m

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The maximum available fire-resistant protection in underground buildings is typically 3 hours.

An underground building is a building that is mostly or entirely below ground level. Underground buildings serve various purposes, such as storage, protection, living, and working.

Additionally, underground buildings can also protect people from natural calamities, for example, tornadoes, hurricanes, earthquakes, and bomb explosions.

When we talk about fire-resistant protection in underground buildings, typically, the maximum available fire-resistant protection is 3 hours. A concrete structure with proper fire-resistant insulation can survive for at least three hours in case of a fire breakout.

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Analyzing the information from the case above, the ideal would be Sarah to schedule a meeting with your boss to expose the facts and seek a solution, as this is an ethical dilemma that she became aware of and as a new manager she will have to deal with it.

She became aware of an illegal practice that has become part of the company's culture and that her boss is aware of this illegality.

Sarah needs to be aware that her talk about the possibility of changing company policy and complying with ethics could jeopardize her job.

But on the other hand, if Sarah's boss does not accept to change the company's ethical parameters, she will also be running the risk of being part of this illegal act and damaging her reputation.

Therefore, the best option for Sarah is to be honest and talk to her boss about the situation.

In this way, it can help workers receive their rights, if their argument is accepted, and transform the company into an ethical place with a culture focused on the development and compliance with ethics and legislation.

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At 1.2mpa pressure and 50c

What is pressure?
By pressing a knife against some fruit, one can see a straightforward illustration of pressure. The surface won't be cut if you press the flat part of the knife against the fruit. The force is dispersed over a wide area (low pressure).

a)Mass flow rate of the refrigerant
Therefore h1= condenser inlet enthalpy =278.28KJ/Kg
saturation temperature at 1.2mpa is 46.29C
Therefore the temperature of the condenser

T2 = 46.29C - 5
T2 = 41.29C

Now,
d)power consumed by compressor W = 3.3KW
Q4 = QL + w = Q4
QL = mR(h1-h2)-W
= 0.0498 x (278.26 - 110.19)-3.3
=5.074KW
Hence refrigerator load is 5.74Kg

(COP)r = 238/53
(Cop) = 4.490

Therefore the above values are the (a) mass flow rate of the refrigerant, b) the refrigerant load, c) the cop, and d) the minimum power input to the compressor for the same refrigeration load.

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Answer:

10.203 Volts

Explanation:

For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.

First, we need to find the voltage in the circuit.  To do this, we need to find the total resistance of the circuit.  When two resistors are in series, you sum the resistance.  So we can say the following:

R_Total = R1 + R2

R_Total = 570 Ω + 560 Ω

R_Total = 1130 Ω

Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.

V_Total = I_Total * R_Total

V_Total = 17.9 mA * 1130 Ω

V_Total = 20.227 V

Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more.  Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).

V_Total = V_1 + V_2

V_Total = V_1 + I_2*R2

V_Total - I_2*R2 = V_1

20.227 V - (17.9 mA * 560 Ω) = V_1

20.227 V - (10.024 V) = V_1

10.203 V = V_1

Hence, the voltage drop across R1 is 10.203 Volts.

Cheers.