As the temperature increases, the rate of enzymatic reactions can generally increase as well. Higher temperatures provide more kinetic energy to the reacting molecules, leading to more frequent collisions and a greater likelihood of successful enzyme-substrate interactions. This results in an accelerated reaction rate.
However, at extremely high temperatures, the rate of enzymatic reactions will dramatically decrease or even cease altogether. This phenomenon is due to the denaturation of enzymes. At very high temperatures, the delicate three-dimensional structure of enzymes can be disrupted, leading to the loss of their functional shape. Denaturation renders enzymes ineffective in catalyzing reactions, causing a sharp decline in the reaction rate.The specific temperature threshold at which denaturation occurs varies for different enzymes. Some extremophile enzymes are adapted to function at high temperatures and may exhibit more stability, but generally, excessive heat can disrupt enzyme activity and impede the reaction rate.For such more questions on enzymatic reactions
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PLEASE HELPPPP!!
Lab Report
Motion and Forces
Introduction-
1. What was the purpose of the experiment?
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for each part of the experiment.
3. Write a hypothesis based on observations and scientific principles.
Experimental Methods-
4. What tools did you use to collect your data?
5. Write your procedure. List each step so that another student could follow the procedure and repeat your experiment.
Data and Observations-
6. Record your observations.
Conclusions-
7. What conclusions can you draw about how the sum of forces acting on an object affect its motion? Write an evidence-based claim.
8. Which mass, A, B, or C, was the greatest? Use the observations from your experiment and your knowledge of Newton’s laws of motion to write an evidence-based claim.
9. Make a model that shows the forces acting on two blocks on a flat, frictionless surface:
A 1 N block at rest
A 1 N block with 2 N of force applied in one horizontal direction
Include arrows to represent the forces and labels to indicate the magnitude of each force. Use your model to compare and explain the motion of each block.
Answer:
The purpose of this experiment was to see how motion takes place as well as Force The independent was the second item used I think that what happened at the thing I used I took a ball and threw it on the ground from height distance I recorded the time Same height
Calculate the amount of sucrose required to prepare 250g of 5%
solution of glucose by mass? Also determine the mass of solvent
used to prepare this solution.
The amount of sucrose required will be 12.5 grams and the mass of water required will be 250 g.
Stoichiometric problem5% by mass glucose solution is to be prepared. This means that 5g of glucose will be dissolved in 100 mL of water.
250g of such a solution will require 250 mL of water.
5% of 250g = 5/100 x 250 = 12.5 grams
Thus, the solution is prepared by dissolving 12.5 grams of sucrose in 250 grams (250 mL) of water.
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wich organelle is found in photosynthesis organisims and caprures energy from the sun
Plastid is the organelle that can the substance. chlorophyll that performs photosynthesis
A 1200 mL IV drip is labeled to contain 12% of a laxative. Find the number of mL of the IV drip that should be administered if a patient is to receive 21 mL of the laxative.
A 1200 mL IV drip is labelled to contain 12% of a laxative. The number of mL of the IV drip that should be administered if a patient is to receive 21 mL of the laxative is 175 mL.
To find the number of mL of the IV drip that should be administered to provide 21 mL of the laxative, we can set up a proportion using the concentration of the laxative.
Let x represent the number of mL of the IV drip to be administered.
The concentration of the laxative is given as 12% or 0.12, meaning that in 100 mL of the IV drip, there are 12 mL of the laxative.
Using the proportion:
(12 mL of laxative) / (100 mL of IV drip) = (21 mL of laxative) / (x mL of IV drip)
Cross-multiplying, we get:
12 mL * x mL of IV drip = 100 mL * 21 mL of laxative
12x = 210 IV drip0
Dividing both sides by 12:
x = 2100 / 12
x = 175
Therefore, 175 mL of the IV drip should be administered to provide 21 mL of the laxative.
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HFO-1234yf has been tested and found compatible with:
A. PAG oil.
B. Mineral oil.
C. Hydraulic oil.
D. All of the items.
HFO-1234yf has been tested and found compatible with PAG oil.
The correct answer is option A. PAG oil
PAG oil, or Polyalkylene Glycol, is a fully synthetic hygroscopic oil specifically designed for automotive air conditioner compressors. It is used in R-134a air conditioning systems to lubricate the compressor. When looking at PAG oil you will notice various numbers such as PAG46 or PAG100. These numbers refer to the viscosity of the oil, similar to 10W30 oil. In order to determine the correct PAG viscosity for your vehicle you will need to look up the specifications of your make and model of your vehicle either online or in the instruction manual.
Hence, HFO-1234yf is compatible with PAG oil. It is not compatible with mineral oil, hydraulic oil, or all of the items listed.
The correct answer is option A. PAG oil.
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Step 1: Consider 0.10 M solutions of acetic acid, ammonia, hydrochloric acid, and sodium hydroxide. Rank these solutions in order of increasing pH (starting from the lowest, and ending with the highest pH value). Please also make a statement, whether each solution is an acidic or a basic one, and provide an explanation why.
Step 2: How many carbon atoms are there in a molecule of each of the following:
a. ethane b. 1-butyne c. propene d. cyclooctane
Please provide molecular formula for each of the four above mentioned compounds.
Example: 2-pentene - contains 5 atoms of C, molecular formula is C5H10
The order of the increasing pH of the solution is Hydrochloric acid, Acetic acid, Ammonia, and Sodium hydroxide.
Molecular formula of compounds: Ethane: C2H6, 1-Butyne: C4H6, Propene: C3H6 and Cyclooctane: C8H16
Rank of solutions in order of increasing pH:
Hydrochloric acid (HCl) is a strong acid that dissociates completely in water. Its pH is very low (less than 1) and it is strongly acidic. It is an acidic solution. It's a 1.0 M solution of hydrochloric acid.
Ammonia (NH3) is a weak base that does not completely dissociate in water. It is a weak base with a pH greater than 7 but less than 10. It is a basic solution. It's a 1.0 M solution of ammonia.
Acetic acid (CH3COOH) is a weak acid that does not completely dissociate in water. It has a pH of around 3.5-4.0, making it a weakly acidic solution. It is an acidic solution. It's a 1.0 M solution of acetic acid.
Sodium hydroxide (NaOH) is a strong base that dissociates completely in water. It has a very high pH (greater than 14), making it a strongly basic solution. It is a basic solution. It's a 1.0 M solution of sodium hydroxide.
So, from the above explanation, the order of the increasing pH of the solution is
Hydrochloric acid, Acetic acid, Ammonia, and Sodium hydroxide.
Step 2: Molecular formula of compounds:
Ethane: C2H6, contains 2 carbon atoms
1-Butyne: C4H6, contains 4 carbon atoms
Propene: C3H6, contains 3 carbon atoms
Cyclooctane: C8H16, contains 8 carbon atoms
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The unbalanced basic equation for the reaction in most airbags is NaN3 --> Na + N2.
A normal airbag needs about 67 liters of Nitrogen gas to fully inflate. (At STP: 1 mole of gas = 22.4 liters of that gas.) How many grams of reactant is needed to produce that amount of gas?
Answer:52!
Explanation:
1. Is energy something a system does or something
it has? Explain.
Answer:
it has
Explanation:
energy cannot be made, its always there, it just can be activated to do something.
hope this helps
brainliest plzz
Why is the NO bond in N-O (d[NO]/pm = 115) short than that in [NO] [Na] (d[NO]/pm = 119)? (Use the molecular diagram of NO to explain)
The NO bond length in \(\rm N-O\) (115 pm) is shorter than that in \(\rm [NO][Na]\) (119 pm) due to the difference in the electronic structure of the two compounds.
A molecular orbital diagram is a graphical representation of a molecule that shows its constituent atoms and the bonds between them.
In \(\rm N-O\), the bond is a covalent bond, meaning that the electrons are shared between the nitrogen and oxygen atoms. In contrast, the bond in \(\rm [NO][Na]\) is an ionic bond, meaning that the electrons are transferred from one atom to another.
In an ionic bond, the atoms are held together by the electrostatic attraction between the positively charged and negatively charged ions. The presence of the sodium ion in \(\rm [NO][Na]\) causes the NO bond to be longer due to the repulsion between the negatively charged oxygen atom and the positively charged sodium ion.
Therefore, the NO bond in \(\rm N-O\), is shorter than that in \(\rm [NO][Na]\) due to presence of sodium ion in \(\rm [NO][Na]\) which causes repulsion between the negatively charged oxygen atom and the positively charged sodium ion resulting into longer NO bond. The molecular diagram of NO is shown below.
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How many grams of H2SO4 do I need to use in order to produce 3.01 moles of water? consider the equation. _Ca(OH)2 + _H2SO4 = _CaSO4 + _H20
Answer:
148 g H₂SO₄
General Formulas and Concepts:
Chemistry - Stoichiometry
Reading a Periodic TableBalancing RxN'sUsing Dimensional AnalysisExplanation:
Step 1: Define
RxN: Ca(OH)₂ + H₂SO₄ → CaSO₄ + H₂O
Given: 3.01 moles H₂O
Step 2: Balance RxN
Ca(OH)₂ + H₂SO₄ → CaSO₄ + 2H₂O
Need the same amount of O's and H's on both sidesStep 3: Define conversions
Molar Mass of H - 1.01 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol
Step 4: Stoichiometry
\(3.01 \ mol \ H_2O(\frac{1 \ mol \ H_2SO_4}{2 \ mol \ H_2O} )(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4} )\) = 147.625 g H₂SO₄
Step 5: Check
We are given 3 sig figs. Follow sig fig rules.
147.625 g H₂SO₄ ≈ 148 g H₂SO₄
Limestone CaCo3 decomposes to lime according to the equation below
CaCo3 ----> CaO + CO2
(i) balance the equation above
(ii) what mass of limestone would produce 11.2 grams of lime?
Show your working
Answer:
Mass of lime produced = 19.0 g
Explanation:
Given data:
Mass of lime produced = 11.2 g
Mass of limestone react = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Balanced chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of lime:
Number of moles = mass / molar mass
Molar mass of lime 56.1 g/mol
Number of moles = 11.2 g/ 56.1 g/mol
Number of moles = 0.19 mol
Now we will compare the moles of CaO and CaCO₃ from balance chemical equation.
CaO : CaCO₃
1 : 1
0.19 : 0.19
Mass of limestone react:
Mass = number of moles × molar mass
Mass = 0.19 mol × 100.1 g/mol
Mass = 19.0 g
There are three laws of stratigraphy. They include the law of superposition, law of original horizontality, and law of cross-cutting relationships.
Question options:
True
False
false
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Calculate the relative formula mass of strontium nitrate, Sr(NO3)2.
(relative atomic masses: N = 14, O = 16, Sr = 88)
Answer:
its 210
Explanation:
Just add all atomic mass used in the formula together: 2*(14+16*3)+88= 2*62+88=124+88=210
Hope this was helpful
The relative formula mass of strontium nitrate Sr(NO₃)₂ is 210
The relative atomic masses of N, O and Sr are 14,16 and 88 respectively.
In calculating the relative atomic mass of an element with isotopes, the relative mass and proportion of each is taken into account. Adding the atomic masses together gives the relative formula mass of a compound
So, relative atomic mass of Sr(NO₃)₂ is calculated as
88+ 2(14+16×3) = 210
The atomic mass constant (symbol: mu) is defined as being 1/12 th of the mass of a carbon-12 atom. Since both quantities in the ratio are masses, the resulting value is dimensionless; hence the value is said to be relative atomic mass.
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What are some problems an astronaut might experience while traveling in space?
Answer:
The environment of space is lethal without appropriate protection: the greatest threat in the vacuum of space derives from the lack of oxygen and pressure, although temperature and radiation also pose risks. The effects of space exposure can result in ebullism, hypoxia, hypocapnia, and decompression sickness.
a 5.325 g sample of methyl benzoate is found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.251 g of oxygen, what is the empirical formula of this substance
The empirical formula is C₄H₄O.
To find the empirical formula of methyl benzoate, we'll follow these steps:
Step 1: Convert mass to moles
Carbon: 3.758 g / 12.01 g/mol (molar mass of C) = 0.313 moles
Hydrogen: 0.316 g / 1.008 g/mol (molar mass of H) = 0.313 moles
Oxygen: 1.251 g / 16.00 g/mol (molar mass of O) = 0.078 moles
Step 2: Divide by the smallest mole value (0.078 moles)
Carbon: 0.313 moles / 0.078 = 4.01
Hydrogen: 0.313 moles / 0.078 = 4.01
Oxygen: 0.078 moles / 0.078 = 1.00
Step 3: Round to the nearest whole number
Carbon: 4
Hydrogen: 4
Oxygen: 1
Step 4: Combine the whole numbers
The empirical formula is C₄H₄O.
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3. Lemon juice is an acid. What ion is present in lemon juice that
makes it an acid?
Lemon is an acidic fruit with a pH ranging 2 to 3. The acid in lemons are citric acid which makes lemon tart, which is Vitamin C.
Why are there so many transformers placed outside the power plant ?
Answer:
Because they convert the electrical voltage produced by increasing and then it goes into the power lines
Explanation:
The main purpose of the transformers is to convert high electrical voltage to low voltage. The transformers transfer the electrical energy into power lines.
What is a transformer?A transformer can be described as a passive component that transfers electrical energy from one electrical circuit to another circuit or multiple circuits. A varying current produces a varying magnetic flux in the transformer's core, which induces an electromotive force (EMF) across other coils wound around the same core.
When the electricity is generated in the power plant, it has to travel large distances from the stations for supply. The high voltage transmission is more efficient as it allows transmitting a larger part of the generated power.
From the power stations, first, the current is passed through the step-up transformer, then at the high voltage, the current reaches the substations, where the current is traveled through the step-down transformer where the voltage is decreased to an amount of 220V.
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Using the periodic table in Figure 7-1, all of the following elements belong to the main group elements EXCEPT:
a. hydrogen
b. radium
c. aluminum
d. iron
Answer:
c. aluminium ic correct
Determine how many moles of copper (Cu) would be produced when 0.33 mole of copper (II) phosphide (Cu3P2) decomposes.
0.99 moles of copper (Cu) would be made when 0.33 mole of copper (II) phosphide (Cu3P2) deteriorates.
How is copper (II) phosphide (Cu3P2) made?Copper (II) phosphide (Cu3P2) is a compound that can be made through a reaction between copper and phosphorus under controlled conditions. It can also be made by the reaction between copper sulfate and sodium hypophosphite or by reducing copper (II) phosphate with carbon at high temperatures.
What are the uses of copper (II) phosphide?Copper (II) phosphide (Cu3P2) has several uses. It is used as a rodenticide to control rodents, as a catalyst, as a lubricant, as an alloying agent, and as a pigment in some ceramic glazes.
The decomposition of copper (II) phosphide (Cu3P2) can be represented by the following chemical equation Cu3P2 → 3Cu + 2P.
The number of moles of copper produced when 0.33 mole of copper (II) phosphide decomposes will be:
0.33 moles Cu3P2 / 1 x 3 moles Cu / 1 mole Cu3P2 = 0.99 moles Cu
So, 0.99 moles of copper (Cu) would be made when 0.33 mole of copper (II) phosphide (Cu3P2) deteriorates.
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Which factors cause transitions between the solid and liquid state? Check all that apply.
The increase in pressure of most liquids can lead to the transition to the solid phase.
In general, an increase in pressure promotes the formation of a less dense phase.
The increase in pressure of most liquids cannot lead to the transition to the solid phase.
The decrease in pressure of most liquids can lead to the transition to the solid phase.
In general, an increase in pressure promotes the formation of a denser phase.
Increase and decrease in pressure
Explanation:
The factors that cause transitions between the solid and liquid state are:
1. The increase in pressure of most liquids can lead to the transition to the solid phase. This is because, in general, an increase in pressure promotes the formation of a denser phase, which is the solid state in this case.
2. The decrease in pressure of most liquids can lead to the transition to the solid phase. This is not as common, but certain substances may undergo this transition.
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A steam engine depends on what kind of energy conversation
Answer:
mechanical energy
If liquid mercury, hg, has a specific heat of 0. 14 j/g°c and liquid benzene, c6h6, has a specific heat of 1. 75 j/g°c, which would give off more heat if you cooled it by 10 °c?.
If liquid mercury, hg, has a specific heat of 0. 14 j/g°c and liquid benzene, c6h6, has a specific heat of 1. 75 j/g°c, 100 g of benzene give off more heat if you cooled it by 10 °c.
Heat = ms∆T
In case of Hg,
Heat released = 100×0.14×10
= 140 J
In case of Benzene,
Heat released = 100×1.75×10
= 1750 J
Mercury is a chemical element with the atomic number 80 and the symbol Hg. Formerly known as hydrargyrum. Mostly as cinnabar, mercury is found in deposits over the world. Cinnabar, either natural or manufactured mercuric sulphide, is ground to produce the crimson colour vermilion.
Six carbon atoms linked together in a planar ring, with one hydrogen atom connected to each, make up the benzene molecule. Benzene is a hydrocarbon since it is made up only of carbon and hydrogen atoms.
The complete question is:
If liquid mercury. Hg. has a specific heat of 0.14 J/g°C and liquid benzene, C6H6, has a specific heat of 1.75 J/g°C. which would give off more heat if you cooled it by 10°C?
a) 100 g of mercury
b) 100 g of benzene
c) 10 g of benzene
d) 10 g of mercury
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Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition reactions in the table. What products should she record in the last row of the table? 2licl + 3o2 3licl + 2o2 2lio + 3cl2 3lio+ 2cl2.
The products Rosa recorded in the last row of the table should be: 2LiCl + 3O₂.
The type of reaction which Rosa did is a decomposition reaction which involves one compound that yields to more than one (or usually two) product. To determine the product, we can deduce that it has to contain elements of Li, Cl and O₂. So, from the options, the answer is 2LiCl + 3O₂.
What is a decomposition reaction?A decomposition reaction can be described as a chemical reaction in which one reactant breaks down into two or more products. Generally, decomposition reactions need energy input.
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4. What gives blood its red color?
a. hemoglobin
O
b. red blood cells
O
c. platelets
d. plasma
Answer:
the best answer would be A
Explanation:
cause it contains a red colored compound.
How much is 1 ug.min/ml in 1 mg.h/L?
ug/min/ml stands for micrgram per min per millilitre.ug/min/ml is generally used in the field of pharmacokinetics.To generally measure the mean concentration of any drug. These parametres are highly quantitative thus the chances of error is really high.
The units in which pharmacokinetic concepts are represented are a characteristic of the words' definitions and have an impact on the results of numerical calculations.
Consistency in symbol usage would minimise errors that might occur when interpreting values presented for different terms. The specific meaning of a phrase or concept as defined can frequently be clarified by carefully considering the units associated with it.To convert 1 ug/min/ml to mg/h L, the following is the calculation:1 ug/min/ml = 60 ug/h/L1 ug/min/ml = 0.00006 mg/h/L.Thus, 1 ug/min/ml is equal to 0.00006 mg/h/L.
Therefore, the answer is 0.00006.
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23. Use the percent abundance data to calculate the average atomic mass of the following elements. (Show your work!) a. Europium: Percent Abundance = 47.82% Percent Abundance = 52.18% Name: Date: b. Uranium: Percent Abundance = 71.00% Atomic mass=151 Atomic mass = 152 Atomic mass = 234 Period:
Answer: Japenease pls
Explanation:
A student suggests that the colorless liquid collected in the U‐tube is water.
Describe how to test the colorless liquid to show it contains water.
Answer:
How would you confirm that a colourless liquid given to you is pure water? A very easy solution is to take a sample of the colourless liquid and put it on the stove if it starts boiling exactly at 100 ºC then it is pure water. Any other colourless liquid such as vinegar always has a different boiling point.
If an atom, such as hydrogen, is able to form a covalent bond, describe what happens when the
electron shells of two atoms overlap?
The electrons in the shells would experience a decrease in energy.
What is the electron shell?We know that the electron shell in the outermost part of the atom is the shell that gets involved in the bonding of the atom. When the bonding takes place, there could be the sharing of electrons as in the covalent bond or the transfer of electrons as in the ionic bond.
In this case, we are dealing with the covalent bond hence there is the sharing of electrons and the shells that would be involved in this is the outermost shells.
By virtue of the sharing of the electrons and the combination of the shells, the energy of the outermost shell would become reduced as the electrons are now attracted to two nuclei rather than one of the hydrogen atoms in the compound.
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Separate the redox reaction into its component half‑reactions. 3O2+4Co⟶2Co2O3 Use the symbol e− for an electron.
How would these be split into thier respective half-reactions?
The balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -
Given equation: 3O2+4Co⟶2Co2O3Using the symbol e− for an electron. The redox reaction can be broken down into two half-reactions. The reduction half-reaction is the one in which a species gains electrons and the oxidation half-reaction is the one in which a species loses electrons. The half-reactions are as follows: Reduction Half-reaction Half-reaction equation: O2 + 2e- → 2O2 -Oxidation number of oxygen in O2=0 and in O2^-= -1Charge on the left side = 0Charge on the right side = 2 x (-1) = -2Thus, 2 electrons are added to the left side to balance the charge, making the half-reaction:O2 + 2e- → 2O2 -Oxidation Half-reaction Half-reaction equation: 4Co → 4Co2+ + 8e-Oxidation number of cobalt in Co=0 and in Co2+ =+2Charge on the left side = 0Charge on the right side = 4 x (+2) + 8 x (-1) = -4Thus, 8 electrons are added to the right side to balance the charge, making the half-reaction:4Co → 4Co2+ + 8e-Thus, the balanced half-reactions are: Oxidation half-reaction: 4Co → 4Co2+ + 8e-Reduction half-reaction: O2 + 2e- → 2O2 -
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Why isn’t K+ H2O —> KOH + H2 not balanced?
Answer:
The obtained result indicates that the hydrogen atom is not equal on both sides. Thus the reaction is not balanced.
Explanation: