• CHALLENGE You need to move a 105-kg sofa to a different location in the room. It
takes a 403-N force to start the sofa moving. What is the coefficient of static friction
between the sofa and the carpet?
Answer:
μ = 0.391
Explanation:
The friction force is defined as the product of the coefficient of friction by the normal force. In this way, we have the following equation.
F = μ*N
Where:
F = friction force = 403 [N]
μ = static coefficient
N = Normal force [N]
And the normal force of a body lying on a horizontal surface can be calculated by means of the product of mass by gravitational acceleration.
\(N=m*g\\N=105[kg]\\g=9.81 [m/s^{2} ]\\N=105*9.81\\N=1030.05[N]\)
Now we can clear the static coefficient
\(403=u*1030.05\\u=0.391\)
Use Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire loop. Note, an electromagnet is a solenoid with a magnetic material inside its core. In this case, the magnetic material is iron, whose magnetic polarization amplifies the external magnetic field produced by the solenoid. You will need to use the right-hand rule to find the direction of the induced current.
Answer:
By Lenz's law, for, coils, if he North pole is activated on the electromagnet, the pole on the side of the coil closest to the electromagnet will be a North pole and the flow of the current will be counter clockwise
Explanation:
Lenz's law states that where a changing magnetic field induces an electric current in a solenoid, the magnetic field that is produced by the coil opposes the initial activation of the electromagnet in the solenoid
By Flamings right hand rule, we have;
When the thumb points in the direction of motion of the conductor relative to the fieldThe first finger points in the direction of the magnetic fieldThe second finger points in the direction of the induced emfTherefore, by Lenz's law, for, coils, if he North pole is activated on the electromagnet, the pole on the side of the coil closest to the electromagnet will be a North pole and the flow of the current will be counter clockwise.
Please please help me :)
Answer:
Explanation:
2) From F=ma
Force =15×40=600N or kgm/s2
3)From the same equation making acceleration the subject of the formula will give
a=f÷m
=24÷4=6m/s2
4)m=f÷a
=45÷15=3kg
Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs.
Which statement about work and power describes Hiro’s actions?
He did more work running than walking.
He did more work walking than running.
He had more power running than walking.
He had more power walking than running.
Answer:
C) he had more power running than walking
Explanation:
saw it on a quizlet. not 100% sure tho
Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs so He had more power running than walking.
What is power?In physics, power is the amount of energy transferred or converted per unit of time. In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.
Power is related to other quantities; for example, the power involved in moving a ground vehicle is the product of the traction force on the wheels and the velocity of the vehicle.
The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft
Since we know that Hiro will run on stairs to minimize the time of reaching his home so if time decreases then he has to increase his power as power is the ratio of work and time.
Hence Hiro walks up a flight of stairs in his apartment building. Later in the day, he runs up the same flight of stairs so He had more power running than walking.
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A snail crawling at 5 mm/s travels 2 m along a wall. How long does this take?
Answer:
0.4
Explanation:
time is disance divided by speed.
11. The primary job of the cell wall is to
a. protect the cell and keep its shape.
b. store DNA.
c. direct and monitor a cell's activities.
d. help the cell move.
12. Which organelle is not found in animal cells?
a. mitochondrion
b. ribosome
c. chloroplast
d. smooth endoplasmic reticulum
11. protect the cell and keep its shape.
12. chloroplast
Answer:
11. A. Protect the cell and keep its shape
13. C. Chloroplast
Hope this helps :)
_____ is a technique that has been used to temporarily disturb brain area functioning in humans.a. Lesioningb. Ablationc. Transcranial magnetic stimulationd. Orbital magnetic gyration
Transcranial magnetic stimulation (TMS) is a technique that has been used to temporarily disturb brain area functioning in humans
TMS is a technique that has been used to temporarily disturb brain area functioning in humans. It involves the use of magnetic fields to stimulate or inhibit nerve cell activity in the brain.
TMS is used to study brain function, treat medical conditions such as depression and obsessive-compulsive disorder, and develop new treatments for neurological disorders.
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A 1100 kg car starts from rest and accelerates for 5 seconds at 4.6m/s/s how much power does the car generate
Answer:
The power expended by the car during the acceleration is 116.38KW
Explanation:
Power is a term that defines the rate at which energy is expended whenever work is done.
Power can be given as Force X velocity.
Force can be found using the formula:
F = mass X acceleration.
In this case,
F = 1100kg X 4.6m/s2
F = 5060 N
The final velocity, v of the car can be obtained from this formula:
v = u+ at
U = initial velocity = 0 (since the car started from rest)
a = acceleration = 4.6m/s2
t = time = 5 seconds
v = 0 + 4.6 X 5 = 23 m/s
Therefore, the power expended is 5060N X 23m/s=116,380W
The power expended by the car during the acceleration is 116.38KW
Consider a cool gas placed in front of a hot light bulb. The observed spectrum of the light bulb will contain dark lines where some light has been absorbed by the gas. Those dark lines reveal the: ________
The dark lines observed in the __spectrum__ of a hot light bulb when a cool gas is placed in front of it reveal valuable information about the properties of the gas and its interaction with light.
These dark lines are known as absorption lines or Fraunhofer lines, named after the German physicist Joseph von Fraunhofer who first observed them in the early 19th century.
The absorption lines occur because the atoms or molecules of the cool gas can absorb specific wavelengths of light. Each chemical element or compound has a unique set of energy levels that its atoms or molecules can occupy.
When light passes through the cool gas, the atoms or molecules in the gas can absorb photons of specific energies that match the energy differences between these levels.
As a result, the absorbed photons are removed from the incident light, leading to dark lines at those specific wavelengths in the observed spectrum.
The positions and patterns of these dark lines provide a characteristic fingerprint of the gas present. By comparing these lines to known spectral patterns, scientists can identify the elements or compounds in the gas.
Moreover, the intensity or depth of the absorption lines can reveal information about the density or concentration of the gas.
The greater the concentration of absorbing particles in the gas, the deeper and more pronounced the absorption lines will be.
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charges move through the circuit from one plate to the other until both plates areuncharged.
The movement of charges from one plate to the other in a capacitor is a fundamental process that underlies many electronic devices and applications.
When a capacitor is connected to a circuit, charges begin to flow from one plate to the other until both plates reach the same potential and the capacitor becomes fully charged.
This process involves the movement of electrons, which are negatively charged particles, from one plate to the other.
Initially, the capacitor is uncharged, and the plates have an equal number of positive and negative charges.
When a voltage is applied to the capacitor, electrons begin to flow from the negative plate to the positive plate, creating an electric field between the two plates. This electric field stores energy in the capacitor, which can be released later when the capacitor is discharged.
If the voltage across the capacitor is removed, the capacitor will retain its charge and will discharge slowly over time as the electrons flow back from the negative plate to the positive plate.
This discharge process can be used in various applications, such as in flash photography, where a capacitor is charged rapidly and then discharged quickly to produce a bright flash of light.
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two point charges exert a 8.05 n force on each other. what will the force become if the distance between them is increased by a factor of 2?
When the distance between two point charges is increased by a factor of 2, the force they exert on each other decreases to 1/4 of the original force. The relation is governed by the Coulomb's Law.
According to Coulomb's Law, the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this scenario, if the distance between the charges is increased by a factor of 2, it means that the new distance is twice the original distance.
Since the force is inversely proportional to the square of the distance, doubling the distance will result in the force becoming 1/4 of the original force. Mathematically, this can be represented as follows:
\(F' = F / (2^2)\)
\(F' = F / 4\)
Therefore, the force between the two charges will become 1/4 (or 25%) of the original force when the distance between them is increased by a factor of 2.
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How to test the effect of the water throughout the experiment (independent variable) on the cleanliness of water (dependent variable).
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Ancient Greek history shows that winning at any cost was always the goal of sports.
A.
True
B.
False
PLEASE NO LINKS
Answer:
B.false
Explanation:
wining does not only depends on scoring a goal no
Ancient Greek history shows that winning at any cost was always the goal of sports. the statement is false.
what is goal ?Goal can be defined as something where an individual or a group of individual aim to achieve something, they might make an envision, plan and commit to achieve a desired objective within a finite time by setting deadlines.
goal can be denoted as an anticipated result that motivates a person to direct his/ her effort where the Persistence and patience are two important qualities to achieve one’s goals.
Goals van be specific, close-ended quantifiable objectives with a limited time period or achieving them, it can help to concentrate energy by defining what needs to be done and setting reasonable time limits for it,
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Does the velocity of the center of mass change in a collision.
Answer:
The velocity of the system's center of mass does not change, as long as the system is closed. The system moves as if all the mass is concentrated at a single point.
What type of conflict is portrayed when gatsby tries to repeat the past in the great gatsby?
The conflict portrayed in The Great Gatsby when Gatsby tries to repeat the past is a classic example of man versus nature conflict. On one hand, Gatsby is fighting against the forces of nature, which dictate that the past cannot be changed.
On the other hand, he is battling his own internal demons, trying to prove to himself and to others that he can bring back a time that has long since passed. This conflict is central to the novel, as Gatsby's struggle to recreate the past ultimately leads to his downfall. The reader can see Gatsby's inner turmoil as he tries to reconcile his dreams with the reality of the present.
Overall, the portrayal of this conflict adds depth and complexity to the character of Gatsby and helps to drive the plot forward. In conclusion, the conflict between Gatsby's desire to repeat the past and the inevitability of change is a central theme of The Great Gatsby, which is portrayed through Gatsby's struggle against both the natural world and his own inner demons.
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A plane mirror moves towards the object with a velocity of 2m/s and the object itself moves towards the mirror with a velocity of 5m/s. What is the velocity of the image approaching towards the object?
We have that the velocity of the image approaching towards the object is
\(x=3.33m/s\)
From the question we are told
A plane mirror moves towards the object with a velocity of 2m/s and the object itself moves towards the mirror with a velocity of 5m/s. What is the velocity of the image approaching towards the object?
Generally the equation for the velocity of the image is mathematically given as
\(\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\\Therefore\\\\\frac{1}{2}=\frac{1}{x}+\frac{1}{5}\\\\\frac{1}{x}=\frac{1}{2}-+\frac{1}{5}\\\\\frac{1}{x}=0.3\)
\(x=3.33m/s\)
Therefore
the velocity of the image approaching towards the object is
\(x=3.33m/s\)
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The constructor equation of the geometric optics allows to find the result for the speed of the image is 7 m/s
Geometric optics analyzes the formation of images with different objects, for this it uses the constructor equation
\(\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\)
Where f is the focal length, p the distance a to the object and q the distance to the image
In this case we have a plane mirror, a plane object has its radius of curvature at infinity (f = ∞), consequently
p = q
If we derive this expression with respect to time
\(\frac{dp}{dt} = \frac{dq}{dt}\)
The speed of the object and the image is the same.
In all these equation is the mirror or lens are considered fixed in space
In this case we have that the object moves towards the mirror at v₀ = 2 m / s and the mirror moves towards the object at \(v_m\) = 5 m / s
To consider the mirror fixed in space, we must find the relative velocity of the object with respect to the mirror; the body approaches the speeds add
\(v_{om} = v_o +v_m\)
Where \(v_{om}\) speed of the object with respect to the mirror, v₀ and \(v_m\) are the velocities of the object and the mirror, respectively
\(v_{om}\) = 5 + 2
v_{om} = 7 m / s
The speed of the image and the object are equal, therefore the image speed is:
v = 7 m / s
In conclusion using the constructor equation allow to find the result for the image speed is 7 m / s
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The fact that the lunar phases repeat on the same solar dates about every 19 years (the metonic cycle) can be used to __
The Metonic cycle is a period of almost exactly 19 years after which the lunar phases recur at the same time of the year.
The Metonic cycle is defined as ,235 synodic months is just 2 hours, 4 minutes and 58 seconds longer than 19 tropical years.
In Athens, at 5th century BC, give the cycle to be a whole number of days, 6,940. Using these whole numbers facilitates the construction of a lunisolar calendar.
A tropical year is longer than 12 lunar months and shorter than 13 of them. The arithmetic representation of 12×12 + 7×13 = 235 allows it to be seen that a combination of 12 "short" years (12 months) and 7 "long" years (13 months) will be almost equal to 19 solar years.
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An object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg. What is the interaction pair to this force
Answer:
normal contact force
Explanation:
that is the equal and opposite force (as to weight) applied by the table on to the object.
The gravitational force of the earth on the object and the reaction force of the table on the object interact as a pair of forces.
What does gravity mean?The gravitational force is what pulls things with mass in the same direction. People commonly think about the Earth's gravitational pull. Your body is kept on the ground by this force. Yet, gravity pulls all objects with mass in the same direction.
The gravitational force, or g, is the force that the earth exerts on an object, with g equal to 9.8 m/s2.
The information is ,
Place something on the table.
Now that the item is at rest, a force known as gravitational force pushes it downward from the Earth.
The formula for gravitational force is F = mg, where m is the object's mass.
Moreover, Newton's third law states that every action will always have a corresponding and opposing reaction. When the gravitational force acting between two masses is equal in strength and conducted in the opposite direction, an action and reaction pair is produced.
The reaction force is then given by R = -mg, where m is the object's mass and the negative sign denotes that the force is acting in the opposite direction to that of gravity by earth.
Hence , the interaction pair for gravitational is the reaction force
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please type any energy transformation it will help a lot i would really appreciate it
prize: brainliest
Answer:
in electric lamp
Electric Energy to Heat and Light Energy
Explanation:
Answer:
Ex: an electric fan transforms electric energy to kinetic energy
Or
Chemical energy to heat and light energy
Explanation:
Hope this helps
62,143 J of energy is needed to move a box 6m. calulate the force required
Answer: The kinetic energy formula defines the relationship between the mass of an object and its velocity. The kinetic energy equation is as follows: KE = 0.5 * m * v², where: m - mass, v -
Explanation
Noah roller skates with a constant speed of 6 miles per hour. How long will he take to travel a
distance of 18 miles?
18 / 6 = 3 hours for 18 miles
A book of mass 0.4 kg is pushed to the left across a table with a force of 2.4 N. Kinetic friction provides a force of magnitude 0.8 N.
What is the normal force acting on the book? N
If a book of mass 0.4 kg is pushed to the left across a table with a force of 2.4 N. Kinetic friction provides a force of magnitude 0.8 N, then the normal force acting on the book would be 3.92 Newtons.
What is friction?Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.
As given in the problem If a book of mass 0.4 kg is pushed to the left across a table with a force of 2.4 N. Kinetic friction provides a force of magnitude 0.8 N,
The normal force = m × g
= 0.4 × 9.8
= 3.92 Newtons
Thus, the normal force acting on the book would be 3.92 Newtons.
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The magnitude of the electric field 1 m away from the positive charge is ________________ the magnitude of the electric field 2 m away.
The magnitude of the electric field 1 m away from the positive charge is four times the magnitude of the electric field 2 m away. The electric field strength from a point charge is defined as the force per unit charge that a small positive test charge would experience if it was placed at that point in space.
The electric field of a point charge is directly proportional to the strength of the charge, and it decreases as the square of the distance from the charge increases. This means that if the distance between the point charge and the test charge is doubled, the electric field will be reduced to a quarter of its previous value, since two squared is four.
According to Coulomb's law, the electric field strength (E) is inversely proportional to the square of the distance (r) from the charge (Q), thus: E α 1/r².In the formula, "α" stands for "proportional to." The equation could be rewritten as: E = k Q / r², where "k" is a constant equal to 9 × 109 N · m² / C².To calculate the electric field strength (E) at any point due to a point charge (Q), use the formula: E = k Q / r².
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What can be said of the size of the event horizon for a 10Msun black hole?
-larger than that of a 1Msun black hole.
-smaller than that of a 1Msun black hole.
-the same size as for a 1Msun black hole (because the escape velocity for both is the speed of light).
The event horizon of a black hole is the boundary beyond which nothing, not even light, can escape its gravitational pull. The size of the event horizon is directly related to the mass of the black hole.
Specifically, the Schwarzschild radius formula can be used to determine the size of the event horizon, which is given by Rs = 2GM/c^2, where Rs is the Schwarzschild radius (event horizon radius), G is the gravitational constant, M is the mass of the black hole, and c is the speed of light. For a 10Msun black hole, the event horizon will be larger than that of a 1Msun black hole. This is because the mass term (M) in the formula directly affects the event horizon size. When comparing a 10Msun black hole to a 1Msun black hole, the 10Msun black hole has 10 times the mass, which will result in a correspondingly larger event horizon. The escape velocity for both black holes is indeed the speed of light, but their event horizons will differ in size due to the variation in mass.
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Two vehicles are traveling when they enter an intersection and crash and stick together. Both have a mass of 1,650 kg and both are traveling at 15 m/s. If one is headed North and the other is headed East, after the collision they end up traveling NE together at what speed (in m/s)? Please input your answer as a positive number with two decimal places.
Answer:
10.61 m/s
Explanation:
To find the final speed, we will use the conservation of momentum in each direction, so we can write the following equations:
\(\begin{gathered} p_{ix}=p_{fx} \\ m_1v_{1x}+m_2v_{2x}=(m_1+m_2)v_{fx} \\ \text{and} \\ p_{iy}=p_{fy} \\ m_1v_{1y}+m_2v_{2y}=(m_1+m_2)v_{fy} \end{gathered}\)Where m1 and m2 are the mass of the vehicles, v1 and v2 are their respective velocities in each direction, and Vfx and Vfy are the final velocities in each direction.
If one of the vehicles is headed north, its horizontal velocity Vx = 0 m/s. In the same way if the other is headed east, its vertical velocity Vy = 0m/s
Therefore, we can replace the values and solve the first equation as:
\(\begin{gathered} 1650(0)+1650(15)=(1650+1650)v_{fx} \\ 24750=3300v_{fx} \\ \frac{24750}{3300}=v_{fx} \\ 7.5m/s=v_{fx} \end{gathered}\)In the same way, we can solve the second equation as:
\(\begin{gathered} 1650(15)+1650(0)=(1650+1650)v_{fy} \\ 24750=3300v_{fy} \\ \frac{24750}{3300}=v_{fy} \\ 7.5m/s=v_{fy} \end{gathered}\)Now, we know that the vertical and horizontal speed was 7.5 m/s. So, we can calculate the final speed using the Pythagorean theorem as:
\(\begin{gathered} v=\sqrt[]{(v_{fx})^2+(v_{fy})^2} \\ v=\sqrt[]{(7.5)^2+(7.5)^2} \\ v=\sqrt[]{56.25+56.25} \\ v=\sqrt[]{112.5}=10.61\text{ m/s} \end{gathered}\)So, the speed after the collision was 10.61 m/s
What are the two parts of a force pair?
These two forces are called action and reaction forces and are the subject of Newton's third law of motion.
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Which phase of the moon occurs after a waxing gibbous?.
Suppose that a driver applies a force of 140 N to the master cylinder, which has a diameter equal to 14 the diameter of the brake cylinder. What is the force applied by the brake cylinder on the brake shoe?
Answer:
force on brake shoes is 10 N
Explanation:
for the master cylinder;
force applied = 140 N
diameter = 14d
for brake cylinder;
force applied on the brake shoe by the brake cylinder f = ?
diameter = d
The pressure will be transmitted undiminished from the master cylinder to the brake cylinder according to pascals pressure law.
pressure = force/area
but cross sectional area is proportional to diameter of the cylinder
therefore
\(\frac{140}{14d } = \frac{f}{d }\)
the diameters will cancel out, and we're left with
force on brake shoes = 10 N
g The pieces of fruit are still distinguishable and as before you can buy as few or as many of the pieces of fruit that you want. The available quantities are the same. However the number of pears that you buy must be equal to the number of bananas that you buy. Now how many choices do you have
The number of choices you have in this scenario is equal to the number of available quantities for each fruit.
If the number of pears you buy must be equal to the number of bananas you buy, then the choices you have will be limited. Let's say there are n available quantities for each fruit. In this case, you will have n choices because for each possible quantity of pears, there is only one corresponding quantity of bananas that you can buy to maintain the equal count.
For example, if there are 3 available quantities for each fruit (n = 3), your choices could be:
Buy 1 pear and 1 banana
Buy 2 pears and 2 bananas
Buy 3 pears and 3 bananas
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A 7.80-g bullet moving at 590 m/s penetrates a tree trunk to a depth of 5.60 cm.
(b) Assuming the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree and the moment it stops moving.
It takes approximately 0.189 seconds for the bullet to stop moving within the tree trunk, assuming the frictional force is constant.
What is frictional force?
Frictiοn is the fοrce that resists mοtiοn when the surface οf οne οbject cοmes in cοntact with the surface οf anοther.
Given:
Mass of the bullet (m) = 7.80 g = 0.0078 kg
Initial velocity of the bullet (u) = 590 m/s
Final velocity of the bullet (v) = 0 m/s (since it stops moving)
Distance penetrated by the bullet (s) = 5.60 cm = 0.0560 m
To calculate the time it takes for the bullet to stop moving, we can use the equation of motion:
\(\rm v^2 = u^2 + 2as\)
Plugging in the values:
0² = (590 m/s)² + 2 * a * 0.0560 m
Simplifying:
0 = 348100 m²/s²+ 0.112 m * a
Rearranging the equation to solve for deceleration (a):
a = -348100 m²/s² / 0.112 m
a ≈ -3.107 × 10⁶ m²/s²
The negative sign indicates deceleration.
To find the time (t), we can use the equation:
a = (v - u) / t
Plugging in the values:
-3.107 × 10⁶ m²/s² = (0 m/s - 590 m/s) / t
Simplifying:
-3.107 × 10⁶ m²/s² = -590 m/s / t
Cross-multiplying:
-3.107 × 110⁶ m²/s² * t = -590 m/s
Dividing both sides by -3.107 × 10⁶ m²/s²:
t = -590 m/s / (-3.107 × 10⁶ m²/s²)
t ≈ 0.189 s
Therefore, it takes approximately 0.189 seconds for the bullet to stop moving within the tree trunk, assuming the frictional force is constant.
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