For the following questions, choose from the following possibilities: (a) yes; water (b) no; water (c) yes; air (d) no; air. (i) Can light undergo total internal reflection at a smooth interface between air and water? If so, in which medium must it be traveling originally? (ii) Can sound undergo total internal reflection at a smooth interface between air and water? If so, in which medium must it be traveling originally?
For question (i), the answer is (a) yes; water. Light can undergo total internal reflection at a smooth interface between air and water. It must be traveling in air originally to experience total internal reflection at the interface with water.
For question (ii), the answer is (d) no; air. Sound cannot undergo total internal reflection at a smooth interface between air and water as sound waves require a medium to travel through, and the interface between air and water does not provide enough of a change in medium to cause total internal reflection.
Total internal reflection is a physics phenomenon in which waves arriving at an interface from one medium to another are completely reflected back into the first medium rather than refracted into the second medium.
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A satellite of mass 1.02 metric tons orbits Earth at a constant height. If the mass of Earth is 6 x 10^24 kg,its radius is 6,360 km,and the gravitational force between Earth and the satellite is 6.6 x 10^3 N, find the height of the satellite’s orbit rounded to the nearest kilometer. Take the universal gravitational constant, G = 6.67 x 10^-11 Nm^2/kg^2.
Answer:
height = 1.5 x 10⁶ m = 1500 km
Explanation:
We can use the formula of gravitational force from the Newton's Gravitational Law:
\(F = \frac{Gm_{1}m_{2}}{r^2}\)
where,
F = Gravitational Force = 6.6 x 10³ N
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = mass of earth = 6 x 10²⁴ kg
m₂ = mass of satellite = (1.02 tons)(1000 kg/1 ton) = 1.02 x 10³ kg
r = distance between center of earth and satellite = ?
Therefore, using these values in the equation, we get:
\(6.6\ x\ 10^3\ N = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{r^2}\\\\r^2 = \frac{(6.67\ x\ 10^{-11} N.m^2/kg^2)(6\ x\ 10^{24} kg)(1.02\ x\ 10^3\ kg)}{6.6\ x\ 10^3\ N}\\\\\)
\(r = \sqrt{61.84\ x\ 10^{12}\ m^2 }\)
\(r = 7.86\ x\ 10^6 m\)
The distance between center of earth and the satellite is equal to the sum of height of satellite and radius of earth:
\(r = height + radius\ of\ earth\\7.86\ x\ 10^6 m = height + 6.36\ x\ 10^6 m\\height = 7.86\ x\ 10^6 m - 6.36\ x\ 10^6 m\)
height = 1.5 x 10⁶ m = 1500 km
v = Circular motion constant speed
a = Centripetal acceleration
f = Centripetal force
In circular motion with constant speed, the object moves in a circular path at a constant speed, while experiencing centripetal acceleration and centripetal force directed towards the center of the circle.
Using a circular image show the circular motion constant speed, centripetal acceleration, centripetal force?In circular motion with constant speed, the object moves in a circular path at a constant speed. This means that the object covers equal distance in equal time intervals. The velocity of the object is tangential to the circle at every point.
Centripetal acceleration is the acceleration of an object moving in a circular path, directed towards the center of the circle. It is always perpendicular to the velocity of the object and is given by the formula a = v^2/r, where a is the centripetal acceleration, v is the velocity of the object, and r is the radius of the circular path.
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Ehbwiuvuyevuhvwihbwijnwiubbs
Answer:
what this please be clear
An LED light bulb is favored over an incandescent light bulb because it is more , what?
An LED light bulb is favoured because it is more bright.
An LED light is favored over an incandescent light bulb because it is more bright than the incandescent bulb.
What is an LED bulb?An LED is a light emitting diode. It is used widely for the production of light because it shows some advantages which include:
Many traditional lighting systems like the incandescent bulbs turn more than 90% of the energy which they use to heat, allocating only about 10% of energy to actual light production. LEDs emit almost no heat energy, and most of the light energy they emit is within the visible spectrum.
LEDs use much less energy than that of incandescent bulbs because the diode light is much more efficient, power-wise, than the filament light. LED bulbs use more than 75% less energy than those of incandescent lighting.
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which process produces the energy that powers a solar calculater
Nuclear fusion is the process which produces the energy that powers a solar calculator.
What is Nuclear fusion?
This process involves the fusion of hydrogen atoms to form helium with accompanying release of heat energy.
The heat energy is what powers the solar calculator thereby making it the most appropriate choice.
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positively charged center of an atom
Answer:
the nucleus
Explanation
When the Asthenosphere transfers heat, what happens?
Convection Currents, Earthquakes, volcanic eruptions, or weathering?
assume that a rubber-tired tractor has a total weight of 25,000 lb on its driving wheels. the maximum rimpull in low gear is 9,000 lb. if the tractor is operating in wet sand, with a coefficient of traction of 0.30, what is the maximum possible rimpull prior to slippage of the tires? (see example 6.5 in the textbook for reference)
The maximum possible rim pulls prior to tire slippage is 7,500 lb.
The friction between a drive wheel and the road surface is what is referred to as vehicle traction. The percentage of the total engine power that can be propelled forward by the friction between the tire and the track is known as the coefficient of traction.
This is given by the formula, usable traction or usable force = (coefficient of traction x normal force/weight on powered running gear).
Here, the coefficient of traction is 0.30 and the weight on the powered running gear is 25,000 lb. The maximum possible rimpull prior to slippage of the tires is given by,
Usable force=0.30×25,000 lb = 7,500 lb.
The answer is 7,500 lb.
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Ray runs 30 feet north, 30 feet west, and then 30 feet south . what’s the distance and displacement?
What would the gravitational field strength be if 100kJ are required to lift a 6kg mass 20m
Answer:
The formula is: weight/mass = gravitational field strength.
Explanation:
Narcotics are highly addictive and affect the driver's
Oa) decision making
Ob) vision
Oc) motor skills
Od) all of the above
Answer:
D
that's should be the answer
An object of mass m and another object of mass 2m are each forced to move along a circle of radius 1.0 m at a constant speed of 1.0 m/s. The magnitudes of their accelerations are:
The magnitude of centripetal acceleration of the both bodies is 1 m/s^2.
The centripetal acceleration is given by the relation;
a = v^2/r
v = velocity
r = radius of the circular
We have the following information;
v = 1.0 m/s
r = 1.0 m
In each case, the magnitude of centripetal acceleration is;
a = 1^2/1 = 1 m/s^2
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An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.
Answer:
Resultant force = \(\sqrt{91}\)N
Explanation:
Rf = \(\sqrt{f1²+f2²+2.f1.f2.cos60}\)
Rf = \(\sqrt{6²+5²+2.6.5.1/2}\)
Rf = \(\sqrt{36+25+30}\)
Rf = \(\sqrt{91}\)
doesn't look right though...
The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given parameters:
Two forces are 6 N and 5N.
Angle between them is 60 degree.
So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N = = 9.54 N.
Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°) } = 33⁰.
Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
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1
A sound wave produced by a chime 515 m away is heard 1.50 s
later. What is the speed of the sound in air?
a 534 m/s
b 433 m/s
c 234 m/s
d 343 m/s
The speed of the sound in the air is 343.3 m/s.
Option D is correct.
The speed of sound waves in air is discovered to be 340 m/s.The sound wave moves at a speed of 340 m/s. Using the formula d = v • t, the solution is 25.5 m. Since 0.150 seconds relates to the round-trip distance, use 0.075 seconds for the time.
What is the equation for sound wave speed?v=√γRTM. Keep in mind that the velocity is faster at higher temperatures and slower for heavier gases. For air, = 1.4, M = 0.02897 kg/mol, and R = 8.31 J/mol K. The speed of sound is v = 343 m/s at TC = 20 °C (T = 293 K).
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The computation of the speed of the sound in the air is shown below:
As we know that
Speed = Distance ÷ time
So, here distance is 515 m
And, the time is 1.50 seconds
So, the speed of the sound is
= 515 m ÷ 1.50 seconds
= 343.3 m/s
hence, the speed of the sound in the air is 343.3 m/s
which of the following statements is true of gravitational force but cannot describe electric force? responses the magnitude of gravitational force is inversely proportional to the square of the distance between objects. the magnitude of gravitational force is inversely proportional to the square of the distance between objects. gravitational force can be both attractive and repulsive. gravitational force can be both attractive and repulsive. the influence of gravitational force dominates over extremely large scales in the universe. the influence of gravitational force dominates over extremely large scales in the universe. gravitational force is considered a fundamental force.
The statement "the influence of gravitational force dominates over extremely large scales in the universe" is true of gravitational force but cannot describe electric force.
When it comes to gravitational force, the adage "the influence of gravitational force dominates over extremely large scales in the universe" is accurate, but it cannot apply to the electric force. The main force in the cosmos at vast dimensions is gravity, which controls the motion of planets, stars, and galaxies. Although both gravitational and electric forces obey the inverse square law.
The behaviour of charged particles on lower dimensions, such as within atoms and molecules, is mainly governed by electric forces, which are usually much weaker than gravitational forces. In addition, while both forces can be appealing, gravitational forces are always attractive, whereas electric forces can also be repulsive between entities with similar charges. Last but not least, there are four basic forces: gravity, the strong nuclear force, the weak nuclear force, and the electric force. The strong nuclear force is one of these four factors.
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the student measures the length of half a wavelength using a ruler. describe how she could use this measurement and information from the signal generator to calculate the speed of the wave on the string
Answer:
read section b :)
Explanation:
To measure the speed of the wave on the string, the wavelength, and frequency are required. So by calculating the wavelength, the speed can be calculated.
What is wavelength?The distance between two adjacent crests can be used to calculate a transverse wave's wavelength. The distance between two adjacent compressions can be used to calculate the wavelength of a longitudinal wave.
The wave speed can be determined using this equation if the wavelength and frequency are known. The quantity of waves that move in a wave's frequency is measured in waves per second.
Speed = Wavelength x Frequency).
Therefore, the wavelength and frequency of the wave on the string must be determined in order to calculate its speed. Consequently, the speed can be estimated by determining the wavelength.
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A volvo moving at a constant speed of 20 m/s passes a saab waiting at a red light just as the light turns green. if the saab begins from rest and accelerates at 2 m/s2 :_________
The Volvo is moving at a constant speed of 20 m/s, while the Saab is accelerating from rest at a rate of 2 m/s^2. We want to determine how far the Saab travels before drawing even with the Volvo.
d = v_0t + 1/2at^2
d is the distance traveled (in meters)
v_0 is the initial velocity (in meters per second)
a is the acceleration (in meters per second squared)
t is the time (in seconds)
The Saab's initial velocity is 0 m/s, since it is starting from rest. The acceleration is 2 m/s^2, and we want to determine the time it takes for the Saab to draw even with the Volvo, so we can set the final velocity of the Saab to 20 m/s.
Plugging these values into the equation, we get:
d = 0 m/s * t + 1/2 * 2 m/s^2 * t^2
20 m = t^2
t = √20 ≈ 4.5 seconds
Therefore, the Saab travels 4.5 * 2 = 9 meters before drawing even with the Volvo.
Here is a summary of the solution:
The Saab travels 9 meters before drawing even with the Volvo.
The Saab takes 4.5 seconds to travel this distance.
The Saab's final velocity is 20 m/s.
A bicycle gear wheel is a disc with 50 ‘teeth' equally spaced around its edge, as shown. The gear wheel is rotated 10 times each second. A springy strip of metal is vibrated by the rotating ‘teeth'. The metal strip produces a sound of frequency that is equal to the frequency of vibration of the strip
Answer:
0.66mExplanation:
The question is not complete, here is the complete question, also see attached the image.
"A bicycle gear wheel is a disc with 50 ‘teeth’ equally spaced around its edge, as shown. The gear wheel is rotated 10 times each second. A springy strip of metal is vibrated by the rotating ‘teeth’. The metal strip produces a sound of frequency that is equal to the frequency of vibration of the strip. The speed of sound in air is 330ms–1. What is the wavelength of the emitted sound?"
given data
number of teeth= 50
we are told that the gear is rotated 10 times in 1 sec,
hence the frequency of the rotation past the strip is
=50*10
=500Hz
speed of sound= 330m/s
we know that
\(v_w = f \Lambda\)-----------1
where Vw is the speed of sound,
f is its frequency, and
λ is its wavelength.
λ=Vw/f
λ=330/500
λ=0.66m
What are 5 violations of the rules for Ultimate Frisbee
Answer:
Violations. A violation occurs when a player violates the rules in a manner which does not result in physical contact ( e.g. throwing a pass during an approach to the goal line; illegal guarding position by the marker; not establishing a pivot foot after carrying the disc in from out-of-bounds, etc.)
The object of Ultimate Frisbee is to gain points by scoring goals. The disc may only be passed, and a goal is scored when a player successfully passes the disc to a teammate in the end zone which that team is attacking. The team with the most points at the end of the game is declared the winner.
Explanation:
Vert (Vertical) Stack – The most common offensive play in Ultimate Frisbee. The Mailman – An intense offensive tactical maneuver to guarantee a gain of at least 70% of the field. TurboDisc – Can be added to almost any play to ensure max effectiveness.
If contact occurs and the thrower drops the disc, the count stops until the thrower picks up the disc and continues with play. The defensive player will have to back up 5 yards (15 feet) to allow a free throw from the offensive player.
the plane can remain on this trajectory for at most due to the large change in altitude required. if instead of simulating weightlessness, nasa wanted to fly a trajectory that would simulate the gravitational acceleration of mars, for what length of time can the plane simulate mars gravity? assume that the maximum change in altitude is the same for both trajectories, and that free fall acceleration on mars is as high as on earth. give your answer to the nearest second.
The question is to calculate the time of flight of a projectile of a plane on surface of Mars.
The projectile is an object which is launched at angle θ with the horizontal.
The projectile is launched with an initial velocity "u"
The path/trajectory of projectile is a parabola.
The maximum horizontal distance between the point of launching and the point of landing is defined as the range of projectile 'R'.
The maximum time taken by the projectile to be in air or to travel the complete trajectory is defined as the time of flight 'T'.
Both the time of flight and the range depend on the initial velocity and the angle of projection.
Also the two parameters depend on acceleration due to gravity 'g'.
It is mentioned that projectile has same maximum horizontal distance on the earth and Mars.
We have to calculate the time of flight on Mars.
The formula of time of flight T = 2 u sinθ / g
On the earth, g = 9.8 m/s²
The value of acceleration due to gravity on the surface of Mars =
1/3* acceleration due to gravity on the Earth.
Let g' is equal to acceleration due to gravity on Mars.
Then, g = g/3
The time of flight of projectile on the surface of mars T' = 2u sinθ/g
T' = 2u sinθ / (g/3)
T' = (2u sinθ*3)/g
T' = 6u sinθ / g
Therefore, the time of flight of projectile on mars is 6u sinθ / g.
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the tendency of a wave to bend as it passes from one transparent medium to another is called
The tendency of a wave to bend as it passes from one transparent medium to another is called refraction.
This phenomenon occurs because light travels at different speeds through different materials, causing the wave to change direction and bend. The amount of refraction that occurs depends on the angle of incidence and the difference in the refractive indices of the two materials. When light passes from a medium with a higher refractive index to one with a lower refractive index, the wave bends away from the normal (a line perpendicular to the surface of the interface between the two media). Conversely, when light passes from a medium with a lower refractive index to one with a higher refractive index, the wave bends towards the normal.
Refraction is responsible for many optical phenomena, such as the apparent bending of a pencil in a glass of water and the formation of rainbows. Understanding the principles of refraction is important in many fields, including optics, engineering, and medicine.
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which characteristic exists at an erosional-depositional interface in a stream
At an erosional-depositional interface in a stream, the characteristic that exists is a dynamic balance between erosion and deposition.
This interface represents the boundary where the stream is actively eroding and transporting sediment from one area while simultaneously depositing sediment in another.
It is typically characterized by fluctuating water velocities and changing sediment loads. In areas of higher erosion, the stream cuts into the bed and banks, removing sediment and shaping the channel. In areas of deposition, the stream slows down, allowing sediment to settle and build up, forming features such as bars or deltas.
This interface reflects the continuous adjustment and equilibrium between erosional and depositional processes in the stream system.
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A student observes that the temperature of a container of water stops increasing right before it starts to boil and turn into gas. Which statement is correct about the thermal energy of the water? (1 point)
The kinetic energy of the water is still increasing even though the temperature is not increasing.
The thermal energy of the water remains constant as it transforms from liquid to gas.
The thermal energy of the water is still increasing even though the temperature is not increasing. The potential energy of the water remains constant as it transforms from liquid to gas.
During boiling, the temperature of a container of water remains constant because thermal energy of the water is constant during the transformation from liquid to gas.
What is kinetic energy?Kinetic energy is energy possessed by a particle by virtue of its motion. Molecules that compose matter are in constant random motion according to the kinetic theory of molecules.
The temperature of a container of water stops increasing right before it starts to boil and turn into gas because the thermal energy of the water remains constant as it transforms from liquid to gas. The heat that is required to turn the liquid into gas at the boiling point is called the latent heat.
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Describe how the wavelength of a wave changes if the wave slows down but its frequency does not change.
Answer:
If the wave slows down with no change in frequency, the wavelength decreases.
If the wave slows down with no change in frequency, then the wavelength decreases.
What is a wave?A wave is defined as the disturbance that has the ability to transfer energy from one point to another in a medium.
The properties of a wave are given as;
Wavelength can be defined as the distance that is observed between adjacent points in an identical cycle of a waveform.
Frequency is the number of cycles of a wave that can occur per minute time.
Time period can be defined as the time it takes for a complete cycle of wave to occur.
Wave speed can be defined as the distance a wave travels in a given amount of time.
Amplitude can be defined as the distance from the centre line (or the still position) to the top of a crest or to the bottom of a trough.
When there is a change in the speed of the wave then the length of the wave would decrease.
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The potential difference between the ends of a wire is 1.5 V, and it conducts 2.5 A of current. The length of the wire is 2.0 m. What is the resistance of the wire, and what is the magnitude of the electric field in the wire?
The resistance of the wire is 0.6 ohms. The magnitude of the electric field in the wire is 0.75 V/m.
To find the resistance of the wire, we can use Ohm's Law, which states that the resistance (R) is equal to the ratio of the potential difference (V) across a conductor to the current (I) flowing through it:
R = V / I
Given that the potential difference V is 1.5 V and the current I is 2.5 A, we can calculate the resistance:
R = 1.5 V / 2.5 A = 0.6 Ω
Therefore, the resistance of the wire is 0.6 ohms.
To find the magnitude of the electric field in the wire, we can use the relationship between the electric field (E), potential difference (V), and distance (d). For a uniform electric field in a straight wire, the electric field is given by:
E = V / d
Given that the potential difference V is 1.5 V and the length of the wire (distance) d is 2.0 m, we can calculate the magnitude of the electric field:
E = 1.5 V / 2.0 m = 0.75 V/m
Therefore, the magnitude of the electric field in the wire is 0.75 V/m.
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Your friend wants to place an object behind the mirror to prevent the eye from seeing the image in the
mirror. Explain why this won't work.
According to the law of reflection, the light from the item cannot bounce off the mirror and reach his eye across his line of sight.
Briefing:According to the law of reflection, the light from the item cannot bounce off the mirror and reach his eye across his line of sight. Ray is unable to see the object's reflection in the mirror because the object's light does not reach his eye.
What is law of reflection ?The law of reflection, the angle of the reflected beam is equal to the angle of the incident ray while reflecting from a smooth surface. (In geometrical optics, all angles are usually measured in relation to the surface normal, or a line perpendicular to the surface.
How is the law of reflection used?In physics, the rule of reflection is used to locate an image that is reflected in a mirror. One effect of a law is that if you can see someone's eyes through a mirror (or the eyes of another species), you can assume that he may see your eyes as well because of how reflection function.
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What does a foliated metamorphic rock look like?
The platy or sheet-like form that foliated rocks develop serves as a representation of the direction of pressure application. A few examples of rocks with foliated metamorphosed tectonic plates are slate, sandstone, and granite.
What does foliated metamorphic rock look like?Foliated metamorphic rock must grow in a directed force or shear stress environment. When pressure is applied to a parent rock during recrystallization, the platy or extended minerals inside the parent rock become aligned or foliated. The platy and paper structure that foliated rocks take on is a representation of the direction in which pressure is applied. Tectonic plates that were foliated during metamorphism produced the rock types slate, schist, and gneiss. The many different types of foliated metamorphic rocks are classified by grade or quantity of metamorphic rocks, and the type includes slate, phyllite, schist, and gneiss.
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The platy or sheet-like form that foliated rocks develop serves as a representation of the direction of pressure application. A few examples of rocks with foliated metamorphosed tectonic plates are slate, sandstone, and granite.
What does foliated metamorphic rock look like?Foliated metamorphic rock must grow in a directed force or shear stress environment. When pressure is applied to a parent rock during recrystallization, the platy or extended minerals inside the parent rock become aligned or foliated.
The platy and paper structure that foliated rocks take on is a representation of the direction in which pressure is applied. Tectonic plates that were foliated during metamorphism produced the rock types slate, schist, and gneiss. The many different types of foliated metamorphic rocks are classified by grade or quantity of metamorphic rocks, and the type includes slate, phyllite, schist, and gneiss.
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A plumber uses a spanner on a tap. She puts a force of 200N on the spanner 30cm from the tap. What is the size of the moment?
Answer:
60Nm
Explanation:
Given data
Applied force= 200N
length of spanner= 30cm to meter
= 30/100= 0.3m
We know that the formula for the moment is
P=Fl
that is
P= force * length
P= 200*0.3
P= 60Nm
Hence the moment is 60Nm
If the resistance r newton e to the motion of a moving vehicle varries directly as the square of the speed vkm/h
The resistance r newton e to the motion of a moving vehicle varies directly as the square of the speed.
According to the given statement, the resistance (r) experienced by a moving vehicle is directly proportional to the square of its speed (v). This relationship can be expressed as:
r ∝ v^2
This means that as the speed of the vehicle increases, the resistance to its motion also increases, and vice versa. The square of the speed accounts for the quadratic relationship between resistance and speed.
It's worth noting that the specific equation relating resistance and speed may depend on the particular characteristics of the vehicle and the surrounding environment. However, based on the given information, we can conclude that the resistance is directly proportional to the square of the speed.
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