As shown in the figure below, a squirrel is looking for nuts. It first runs rishtward 3 m and runs leftwards
another 10m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was
125
3 m
3 m
10 m

As Shown In The Figure Below, A Squirrel Is Looking For Nuts. It First Runs Rishtward 3 M And Runs Leftwardsanother

Answers

Answer 1

As shown in the figure below, a squirrel is looking for nuts. It first runs rightward 3 m and runs leftwards another 10 m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was 12 s.

Answer:

What is the squirrel's average velocity to reach the third nut?

Answer: =-0.83  m/s

What is the squirrel's average speed to reach the third nut?

Answer: 1.3  m/s

Answer 2

It first runs rightward 3 m and runs leftwards another 10 m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was 12 s.

What is speed?

The average velocity required for squirrels is 0.83  m/s. The average speed required for squirrels is 1.3 m/s.

Speed, which is a scalar quantity, is the "speed at which an object is moving." The rate at which an object travels a distance can be thought of as its speed.

A fast-moving object travels at a high speed and completes a significant distance in a brief period of time. This is in contrast to an object travelling slowly, which travels a relatively short distance in the same length of time.

Therefore,  It first runs rightward 3 m and runs leftwards another 10 m to a second nut, and then runs 3 m leftward to a third nut. The total time spent running was 12 s.

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Related Questions

How does genetics affect our chance of developing certain diseases and disorders?

Answers

Answer:

A genetic predisposition results from specific genetic variations that are often inherited from a parent. These genetic changes contribute to the development of a disease but do not directly cause it. Some people with a predisposing genetic variation will never get the disease while others will, even within the same family.

Explanation:

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Una rueda tiene 4 cm de diámetro y realiza
200 vueltas cada 5 minutos. Calcular:
a. la frecuencia
b. el período
c. la velocidad lineal o tangencial
d. La velocidad angular
e. La aceleración centrípeta.

Answers

Answer:

Una rueda tiene 4 cm de diametro y realiza 200 vueltas cada 4 minutos calcular a frecuencia b el periodo c la velocidad lineal l tangencial

(a) Figure 20.26 Problem 20.4. (b) (c20p4) The plane of a square loop of wire with edge length of 10.00 cm is perpendicular to a 0.014 T magnetic field (see the figure (a)). What is the average emf between the points E1 and E2 when the corner D is quickly folded about the diaconal AC so as to lle on top of B (see the figure (b) ) if it takes 0.140 s to make the fold? Tries 0/5

Answers

When a square loop of wire with an edge length of 10.00 cm is folded about its diagonal AC onto a magnetic field of 0.014 T, an average induced electromotive force (emf) of 1.43 x 10^-4 V is generated between the points E1 and E2.

When the square loop is folded about its diagonal AC, it creates two smaller triangular loops, ACE1 and ACE2. These two loops experience a change in magnetic flux due to their motion through the magnetic field. According to Faraday's law of electromagnetic induction, a change in magnetic flux induces an emf in a closed loop.

The induced emf is given by the equation:

emf = -N(dΦ/dt),

where N is the number of turns in the loop and (dΦ/dt) is the rate of change of magnetic flux.

In this case, the emf is measured between the points E1 and E2. The induced emf is caused by the change in magnetic flux through the loops ACE1 and ACE2. Since the magnetic field is perpendicular to the plane of the loops, the magnetic flux through each loop can be calculated as:

Φ = B*A,

where B is the magnetic field strength and A is the area of the loop.

Since the loops ACE1 and ACE2 are congruent triangles, their areas are equal. The area of each triangle can be calculated using the formula for the area of a triangle:

A = (1/2) * base * height.

Given the edge length of the square loop (10.00 cm), the base and height of each triangle can be calculated as 10.00 cm. Substituting the values into the equation for the area, we find that A = 5.00 cm^2.

The total magnetic flux through the loop is the sum of the flux through each triangle, resulting in 2 * (B * A) = 2 * (0.014 T * 5.00 cm^2) = 0.14 Wb.

To find the rate of change of magnetic flux, we divide the total change in flux by the time taken for the folding action. However, the time is not provided in the given information, so we cannot determine the exact value. Nevertheless, we can use the given average emf and rearrange the equation for emf to solve for (dΦ/dt):

(dΦ/dt) = -emf / N.

Substituting the values, we get (dΦ/dt) = -(1.43 x 10^-4 V) / N.

Therefore, the induced emf between the points E1 and E2 is a result of the change in magnetic flux caused by folding the square loop about its diagonal AC in the presence of the magnetic field. The specific value of the number of turns in the loop (N) and the time taken for the folding action are not provided, so we cannot determine the exact values for the induced emf and the rate of change of magnetic flux.

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5)
A 2.0-meter length of copper wire is connected across a potential difference of 24 millivolts.
The current through the wire is 0.40 ampere. The same copper wire at the same temperature
Is then connected across a potential difference of 48 millivolts. The current through the wire
is
A)
0.20 A
B)
0.80 A
C)
1.6 A
D)
0.40 A

Answers

Answer:

The current through the wire is equal to 0.8 A.

Explanation:

Given that,

The length of a copper wire = 2 m

Potential difference = 24 mV

The current through the wire is 0.40 A.

The new potential difference is 48 mV.

We need to find the current through the wire.

As the potential difference is doubled for second wire. So the new current will be :

I' = 2I

= 2 × 0.4

= 0.80 A

So, the current through the wire is equal to 0.8 A.

i) ii) iii) 12 V What is the total resistance of the circuit? 1+1 30+20. - A 26 30 600 What is the current reading of the ammeter? 600=12 What is the power of the 30 ohm resistor? 144 = 48 30 P = √² 12² - 144 R 30 iv) Explain what is meant by the term e.m.f of the battery. 20. Ω > 30. Ω​

Answers

The answer for (iv) is;

E.M.F of the battery refers to the chemical energy in the battery that is being converted into electrical energy for the flow of electrons to carry current in a circuit.

Matter can undergo chemical reactions and nuclear reactions. Which
property is conserved in chemical reactions but NOT in nuclear reactions?
O A. Type of energy
O B. Kinds of compounds
O c. Number of atoms
O D. State of matter

Answers

State of matter is conserved in chemical reactions but not in nuclear reactions.

What is not conserved in a nuclear reaction?

In a nuclear reaction, mass is not conserved because of the release of radiation. The difference in masses of reactants and product nuclei, occurs due to release of energy.

So we can conclude that State of matter is conserved in chemical reactions but not in nuclear reactions.

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Nuclear and chemical processes are both possible in the matter. In chemical processes, the property of no atoms is conserved, but not in nuclear reactions. Option C is correct.

What is nuclear fusion?

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction.

The more energy it takes to liberate an electron from a smaller atom. This is referred to as binding energy.

In the nuclear reaction, one atom gets disassociated with the other atom. The process is known as nuclear fission.

Nuclear and chemical processes are both possible in the matter. In chemical processes, the property of no atoms is conserved, but not in nuclear reactions.

Hence, option C is correct.

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1. In boxing, fighters wear padded gloves to protect their hands. Which statement explains why a fighter’s hands need protection?
A. There is an equal and opposite velocity impact the hand.
B. There is an equal and opposite acceleration impact the hand.
C. There is an equal and opposite momentum impacting the hand.
D. There is an equal and opposite force impacting the hand.

2. Two balls collide. Under which circumstances will they exert equal and opposite forces on each other?
A. If the sustem is closed
B. in all situations
C. If both are moving at the same speed when they collide
D. if they have the same mass

3. In a closed system, how does an increase in mass change the velocity of an impacted object?
A. Velocity decreases to conserve momentum.
B. Velocity may increase or decrease depending on acceleration.
C. Velocity may increase or decrease depending on force.
D. Velocity increases to conserve momentum.

4. Which of the following provides the correct equation for calculating the momentum of an object?
A. p= mv
B. m= DV
C. F= ma
D. m= vp

5. An object with a mass of 50 kg is moving at a velocity of 2 m/s. What is the momentum of the object?
A. 2 kg*m/s
B. 0.04 kg*m/s
C. 100 kg*m/s
D. 25 kg*m/s

6. A large train car moving along a horizontal track rolls into a smaller stationary train car, causing the cars to attach. Which statement best describes the motion of the cars after the connection?
A. The train cars move in the opposite directions from each other.
B. The train cars move together in the opposite direction the large car was moving.
C. The train cars move together in the direction the large car was moving.
D. The train cars both stay stationary.

7. Which equation correctly represents conservation of momentum for two colliding objects?
A. m1a1+m2a2=0
B. m1v1-m2v2=0
C. m1a1-m2a2=0
D. m1v1+m2v2=0

8. How can the sum of two vectors be found?
A. by drawing the vectors perpendicular to each other
B. by adding the numbers representing the vectors' magnitudes
C. by subtracting the numbers of the vectors' magnitudes
D. by drawing the vectors one right after the other

9. How could a closed system be changed without changing the net force on that system?
A. decrese the acceleration only
B. increase the mass and decrease the acceleration by the same numeric values
C. decrease the acceleration and decrease the mass by the same numeric values
D. increase the mass only

10. Which phrase best describes acceleration?
A. the produce of mass and velocity
B. the change in position over time
C. the product of force and distance traveled
D. the change in velocity over time

11. A ball rolls down a hill at constant velocity. Which of the following conditions must be true?
A. The ball will accelerate as gravity pulls it down the hill.
B. The ball has no net force acting on it.
C. There are no forces acting on the ball.
D. The momentum of the ball increases over time.

12. In an experiment, objects 1 and 2 with masses m1 and m2, respectively, collide with each other. The objects have initial velocities v1i and v2i and final velocities v1f and v2f, respectively. Which result would prove conservation of momentum?
A. m1v1i+m2v2i=m1v1f+m2v2f
B. m1v1i+m1v1f=m2v2i+m2v2f
C. m1v1i+m2v2i+m1v1f+m2v2f>0
D. m1v1i+m2v2i+m1v1f+m2v2f=0

Answers

Answer:

1.) D. There is an equal and opposite force impacting the hand

2.) B. In all situations

3.) A. Velocity decreases to conserve momentum

4.) A. p=mv

5.) C. 100 kg*m/s

6.) C. The train cars move together in the direction the large car was moving

7.) D. m1v1+m2v2=0

8.) D. By drawing the vectors one right after the other

9.) B. Increase the mass and decrease the acceleration by the same numeric values

10.) D. The change in velocity over time

11.) B. The ball has no net force acting on it

12.) A. m1v1i+m2v2i=m1v1f+m2v2f

Explanation:

Did the practice

(1) The fighters wear padded gloves to protect their hands because there is an equal and opposite force impacting the hand.

(2) The two balls when collide in a closed system will exert equal and opposite force.

(3) When the mass of the object increases, the velocity of the object will decrease to conserve momentum.

(4) The equation for calculating the momentum of an object is P = mv

(5) The momentum of the ball is 100 kg.m/s

(6) The train cars move together in the direction the large car was moving.

(7) The conservation of momentum of two objects is \(m_1v_1 - m_2v_2= 0\)

(8) The sum of two vectors can be found by  drawing the vectors perpendicular to each other.

(9) A closed system can be changed without changing the net force on the system by increase the mass and decrease the acceleration by the same numeric values.

(10) Acceleration is defined as the change in velocity over time.

(11) As ball rolls down at constant velocity, the ball has no net force acting on it.

(12) The conservation of momentum of the object is \(m_1v_1_i + m_2v_2_i = m_1v_1_f + m_2v_2_f\)

(1)

According to Newton's third law of motion, action and reaction are equal and opposite.

The fighters wear padded gloves to protect their hands because there is an equal and opposite force impacting the hand.

(2)

Based on the principles of conservation of linear momentum, the two balls when collide in a closed system will exert equal and opposite force.

(3)

The principles of conservation of linear momentum is written as;

\(m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2\)

when the mass of the object increases, the velocity of the object will decrease to conserve momentum.

(4)

The equation for calculating the momentum of an object is written as;

P = mv

(5)

The momentum of the ball is calculated as follows;

P = mv

P = 50 x 2

P = 100 kg.m/s

(6)

For inelastic collision, the collided two objects move in the same direction after collision usually in the direction of heavier object.

The train cars move together in the direction the large car was moving.

(7)

The conservation of momentum of two objects is written as;

\(m_1v_1 = m_2v_2\\\\m_1v_1 - m_2v_2 = 0\)

(8)

The sum of two vectors can be found by  drawing the vectors perpendicular to each other.

(9)

A closed system can be changed without changing the net force on the system by increase the mass and decrease the acceleration by the same numeric values.

(10)

Acceleration is defined as the change in velocity over time.

(11)

At constant velocity , acceleration = 0

∑F = ma

∑F = m x 0

∑F = 0

Thus, as ball rolls down at constant velocity, the ball has no net force acting on it.

(12)

The conservation of momentum of the object is written as;

\(m_1v_1_i + m_2v_2_i = m_1v_1_f + m_2v_2_f\)

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what is the total equivalent resistance of the circuit?
R1= 5Ω, R2= 3Ω, R3= 4Ω, R4= 1Ω, R5= 2Ω

Answers

15 ohms



...............

(b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity?

Answers

Answer:

The time taken is missing in the question. The time is 18 minutes.

The answer is 34.3 km/hr

Explanation:

Average velocity is the speed or the velocity which is required to cover a distance in a time interval.

The time taken is = 18 min

                            = 18/60 hours

The distance from the university to her home is = 10.3 km

Therefore, the average velocity is = displacement/time taken

                                                         = 10.3 / (18/60) km/hr

                                                         = 34.3 km/hr

Hence, the average velocity is 34.3 km/hr

if an identical force were applied to object one with a mass of 100 grams and object two with a mass of 200 grams, what would the relationship between their accelerations be

Answers

According to Newton's second law of motion, the relationship between force (F), mass (m), and acceleration (a) is given by the equation F = ma.

If an identical force is applied to two objects, object one with a mass of 100 grams (0.1 kg) and object two with a mass of 200 grams (0.2 kg), we can compare their accelerations.
Let's assume the force applied is F.
For object one:
F = ma₁
For object two:
F = ma₂
Since the force applied (F) is the same for both objects, we can set the two equations equal to each other:
ma₁ = ma₂
Canceling out the mass (m) from both sides of the equation, we get:
a₁ = a₂
Therefore, the relationship between the accelerations of the two objects is that they are equal. If the force applied is identical, the resulting acceleration will be the same for objects with different masses, as long as no other forces are involved.

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A very rigid material—one that stretches or compresses only slightly under large forces—has a large value of __________.

Answers

Answer: young's modulus

Explanation: A very rigid material—one that stretches or compresses only slightly under large forces—has a large value of young's modulus .

consider a double-slit diffraction experiment with slits of width 0.300 mm. monochromatic light of wavelength 506 nm is used. if the value of the parameter b for a point that is an angular distance of 0.0150 rad form the center of the center diffraction peak id 21.24 rad, what must be the slit separation (in mm)?

Answers

The slit separation in the double-slit diffraction experiment must be approximately 33.73 × 10^-3 mm per rad, given that the parameter b for a point located at an angular distance of 0.0150 rad from the center of the center diffraction peak is 21.24 rad.

In a double-slit diffraction experiment, the value of the parameter b for a point located at an angular distance of 0.0150 rad from the center of the center diffraction peak is given as 21.24 rad. We need to determine the slit separation.

To solve this problem, we can use the formula for the angular position of the m-th order diffraction peak:

θ = mλ / b

where θ is the angular position, λ is the wavelength of the light, m is the order of the diffraction peak, and b is the slit separation.

In this case, the point is located at an angular distance of 0.0150 rad, which corresponds to the first-order diffraction peak (m = 1). The wavelength of the light is given as 506 nm.

We can rearrange the formula to solve for b:

b = mλ / θ

Substituting the given values:

b = (1)(506 nm) / (0.0150 rad)

Now, we can convert the wavelength from nanometers to meters:

b = (1)(506 × 10^-9 m) / (0.0150 rad)

Simplifying the expression:

b = 33.73 × 10^-6 m / rad

Finally, we can convert the slit separation from meters to millimeters:

b = 33.73 × 10^-3 mm / rad

Therefore, the slit separation is approximately 33.73 × 10^-3 mm per rad.

In conclusion, the slit separation in the double-slit diffraction experiment must be approximately 33.73 × 10^-3 mm per rad, given that the parameter b for a point located at an angular distance of 0.0150 rad from the center of the center diffraction peak is 21.24 rad.

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6.There are four mixtures A, B, C and D. The mixture A contains sand and sugar, mixture B contain chalk powder and salt, mixture C contains salt and sugar, whereas mixture D contains sugar and charcoal powder. Which one of these mixtures cannot be separated by using water as a solvent? Why?

Answers

Answer:

Mixture C (salt and sugar)

Explanation:

Both salt and sugar can dissolve in water. And you can't just separate the mixture by filtering it like you could in the other mixtures.

What can chemical formulas represent?

A.) mixtures

B.) elements

C.) compounds

D.) atoms

Answers

Answer:

A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element. In empirical formulae, these proportions begin with a key element and then assign numbers of atoms of the other elements in the compound, by ratios to the key element.

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A device that automatically writes down (records) changes in temp is called?

Answers

A thermograph is a gadget that automatically logs (records) temperature changes.

What is the thermograph used for?

By identifying heat leaks, thermography is able to identify inadequate thermal insulation and boost the effectiveness of heating and cooling systems. Air leaks in windows and doorframes can also be discovered during a building envelope assessment.

What exactly is a thermograph device?

An automatic temperature recorder. The thermometric component is typically either a liquid-filled Bourdon tube or a bimetal strip. The bimetal element in the first scenario is shaped like a helical coil, with one end fixed firmly to the device and the other to recorder pen.

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  do batteries produce or make energy

Answers

Batteries Produce energy

Answer:

Batteries are intended to store chemical energy and then it converts into electricidal energy. So overall, batteries produce energy.

Explanation:

What is the force on a 0.0020 C charge in an electric field of 150 V/m?

A) 0.30 N

B) 7.5 x 10 N

C) 150.002 N

D) 1.3 X 10-5 N

Answers

Answer: The answer is B. 150.002

Explanation: Add 0.0020 by 150

Force on a 0.0020 C charge in an electric field of 150 V/m will be 0.3 N

What is an Electric field ?

An electric field is defined as the electric force per unit charge . The electric field is radially outward from a positive charge and radially in toward a negative charge .

General formula to find Electric field is :

Electric field  = Force / charge

given

charge = 0.0020 C

Electric field = 150 V/m

Force = ?

Force  = Electric field * charge

          =  150 V/m * 0.0020 C

          = 0.3 N

Force on a 0.0020 C charge in an electric field of 150 V/m will be 0.3 N

correct answer is A) 0.30 N

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Water is pumped with a velocity of 2.8 m/s in a 150 mm diameter pipe. The pipe branches at A into a 75 mm diameter pipe, 50 m long with f= 0.008, and a 100 mm diameter pipe, 170 m long with f 0.007, which join up again into a 150 mm diameter pipe. The 100 mm diameter pipe has a valve with an equivalent ratio of 300. Point A is 5.5 m higher than point B.
a The flow rate in each pipe.
bi The pressure at B if pressure at A is 450 kPa.

Answers

The flow rate in each pipe:We can use the following relation to calculate the flow rate in each pipe:q= VA

where q is the flow rate,

V is the velocity, and

A is the cross-sectional area of the pipe

.a)150 mm diameter pipe:

Cross-sectional area, A = π/4 (diameter)²

A = π/4 (150 mm)²A

= π/4 (0.15 m)²

A = 0.0177 m²

Flow rate, q = VAq

= 0.0177 m² × 2.8 m/sq

= 0.04956 m³/s75 mm diameter pipe:

Cross-sectional area, A = π/4 (diameter)²A

= π/4 (75 mm)²A

= π/4 (0.075 m)²A

= 0.00442 m²

Flow rate, q = VAq

= 0.00442 m² × (2.8 m/s)q

= 0.01238 m³/s100 mm diameter pipe:

Cross-sectional area, A = π/4 (diameter)²A

= π/4 (100 mm)²A

= π/4 (0.1 m)²A

= 0.00785 m²

Flow rate, q = VAq

= 0.00785 m² × 2.8 m/sq

= 0.0220 m³/sb)

Pressure at B:We can use Bernoulli’s principle to calculate the pressure at B.

P₁+ 1/2ρv₁²+ ρgh₁ = P₂+ 1/2ρv₂²+ ρgh₂

We are given the following:P₁ = 450 kPa (pressure at A)v₁ = 2.8 m/s (velocity at A)ρ = 1000 kg/m³ (density of water)h₁ = 5.5 m (height at A above B)

The velocity and height at B are unknown. We can assume that the diameter of the pipe is constant between A and B, so the cross-sectional area is constant.

This means that the velocity at B is the same as the velocity in the 150 mm diameter pipe:2.8 m/s = v₂

We can use the pressure drop across the valve to find the pressure at B:Pᵥ= ΔP/K=P₁−P₂/K

Equivalent ratio, K = 300ΔP = K(P₁ − P₂)ΔP = 300(P₁ − P₂)Pᵥ= (300(P₁ − P₂))/K

Here, Pᵥ is the pressure at the valve (point C).

We can assume that the velocity in the 100 mm diameter pipe is constant, so the pressure drop across this pipe is proportional to its length:ΔP = f (L/D) (1/2ρv²)ΔP = 0.007 (170/0.1) (1/2 × 1000 × 2.8²)

ΔP = 918.21 Pa

We can use Bernoulli’s principle to find the velocity in the 100 mm diameter pipe:

1/2ρv² = P₁ − P₂+ ρgh₁ − ρgh₂1/2 × 1000 × v²

= P₁ − P₂+ 1000 × 9.81 × 5.5 − 1000 × 9.81 × 4.5v²

= (P₁ − P₂+ 9810)v = √((P₁ − P₂+ 9810)/1000)

Now we can substitute this expression for v into the pressure drop equation and solve for P₂:ΔP = f (L/D) (1/2ρv²)918.21

= 0.007 (170/0.1) (1/2 × 1000 × [(P₁ − P₂+ 9810)/1000]²)(P₁ − P₂+ 9810)/1000 = 21262.4P₁ − P₂+ 9810

= 21262450 kPa − P₂= 21262440 kPa

= P₂

Pressure at B is 240 kPa.

In conclusion, the flow rate in the 150 mm diameter pipe is 0.04956 m³/s, the flow rate in the 75 mm diameter pipe is 0.01238 m³/s, and the flow rate in the 100 mm diameter pipe is 0.0220 m³/s. The pressure at point B is 240 kPa, given that the pressure at point A is 450 kPa.

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How does information travel during transcription?
a) RNA to amino acid
b) DNA to amino acid
c) DNA to RNA
d) RNA to DNA

Answers

Answer: c) DNA to RNA

A model rocket has a mass of 0.435kg. It is mounted vertically and launches directly up with a thrust force of 13.1N.
What is the weight of the rocket?

Answers

Answer:

17.27N

Explanation:

Given

m = 0.435kg

F = 13.1N

Unknown:

Weight or W

Formula and solution

W = F = mg

W = (0.435kg)(9.8m/s^2)

W = 4.26N + 13.1N

Final answer

W = 17.27N

Question number 10
I need the answer with explanation.. Thank you in advance.

Question number 10 I need the answer with explanation.. Thank you in advance.

Answers

If the coil is rotated about its axis which is perpendicular to its plane in counterclockwise direction by a 90° angle, the flux that penetrates the coil (a) increases.

Why does the flux increase?

When a circular coil is rotated about its axis which is perpendicular to its plane in counterclockwise direction by a 90° angle, the flux that penetrates the coil changes.

This is because the area of the coil that is perpendicular to the magnetic field increases while the area that is parallel to the magnetic field decreases. Therefore, the flux that penetrates the coil increases.

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Complete the sentences to describe the difference between speed and velocity.
Speed describes how fast an object moves. Speed is described by
with
Velocity is described by
Intro
and time.
and time. Velocity is speed
Done

Answers

Answer:

Speed describes how fast an object moves. Speed is \(\dfrac{\rm distance \,\,travelled}{\rm time \,\,taken}\)described by using a scalar with a magnitude but no direction.

Velocity is \(\dfrac{\rm change\,\,in\,\,displacement}{\rm time \,\,taken}\)described by using a vector which has both a magnitude and a direction

Velocity is speed in a given direction.

Done

Explanation:

1. Fit a classification tree with all predictors, using the best-pruned tree. To avoid overfitting set the minimum number of records in a leaf node to 50. Also, set the maximum number of levels displayed at seven (the max. allowed in XLMiner). Is this model practical for predicting the outcome of a new auction?
2. Fit another classification tree (using the best-pruned tree, with a minimum number of records per leaf node =50 and seven displayed levels) this time only with predictors that can be used for predicting the outcome of a new auction. Describe the resulting tree in terms of rules.

Answers

1. Best-pruned classification tree, with minimum 50 records/leaf, predicts auction outcomes accurately and maintains interpretability.

2. Resulting tree uses relevant predictors as rules for predicting outcomes, balancing simplicity and effectiveness.

3. Interpretable classification tree guides predictions based on conditions like starting bid, bidders, duration, and item category.

1. The classification tree with all predictors, using the best-pruned tree, and a minimum number of records in a leaf node set to 50 can be a practical model for predicting the outcome of a new auction. By pruning the tree, we reduce the complexity and avoid overfitting, ensuring that the model generalizes well to unseen data.

Limiting the maximum number of displayed levels to seven helps maintain interpretability while still capturing important patterns in the data. Overall, this model provides a balance between accuracy and practicality for predicting auction outcomes.

2. The resulting classification tree, using the best-pruned tree, with a minimum number of records per leaf node set to 50 and seven displayed levels, focuses on the predictors specifically relevant for predicting the outcome of a new auction. The tree can be described in terms of rules that indicate the conditions for different outcomes. Each branch and node in the tree represents a rule, where the predictors determine the path and the outcome is assigned to the leaf node.

The specific rules in the resulting tree would depend on the dataset and the available predictors. For example, a rule could be: "If the starting bid is higher than X and the number of bidders is less than Y, predict Outcome A." Another rule could be: "If the auction duration is longer than Z and the item category is X, predict Outcome B." The tree provides a structured representation of these rules, allowing for easy interpretation and prediction based on the relevant predictors for auction outcomes.

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The first-order diffraction maximum is observed at 12.6° for a crystal having a spacing between planes of atoms of 0.250 nm. (a) What wavelength x-ray is used to observe this first-order pattern? (b) How many orders can be observed for this crystal at this wavelength?

Answers

Answer:

(a) The wavelength of the x-ray used to observe the first-order diffraction maximum is approximately 0.413 nm.

(b) The maximum number of orders that can be observed for this crystal at this wavelength is 1.

Explanation:

(a) To determine the wavelength of the x-ray used to observe the first-order diffraction maximum, we can use the Bragg's law, which relates the wavelength of the incident x-ray, the spacing between planes of atoms, and the angle of diffraction.

Bragg's law is given by:

nλ = 2d sinθ

Where:

n is the order of diffraction (in this case, n = 1 for the first-order diffraction)

λ is the wavelength of the x-ray

d is the spacing between planes of atoms

θ is the angle of diffraction (given as 12.6°)

Rearranging the equation to solve for λ, we have:

λ = (2d sinθ) / n

Substituting the given values:

d = 0.250 nm = 0.250 × 10^(-9) m

θ = 12.6° = 12.6 × π / 180 radians

n = 1

λ = (2 * 0.250 × 10^(-9) m * sin(12.6 × π / 180)) / 1

λ ≈ 0.413 × 10^(-9) m

(b) To determine the number of diffraction orders that can be observed, we need to consider the condition for constructive interference. For a given crystal, the number of orders that can be observed depends on the maximum value of n, which is determined by the crystal's characteristics and the wavelength of the incident x-ray.

In general, the number of orders that can be observed is given by:

n_max = 2d / λ

λ = 2 * 0.250 × 10^(-9) m * sin(12.6°)

λ ≈ 0.087 × 10^(-9) m

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A common flea is recorded to have jumped as high as 21 cm. Assuming that the jump is entirely in the vertical direction and that air resistance is insignificant, calculate the time it takes the flea to reach a height of 7.0 cm.

Answers

Answer:

t = 0.12 s

Explanation:

Applying the second equation of motion under free fall,

h = ut + \(\frac{1}{2}\)g\(t^{2}\)

where: h is the height, u is its initial velocity, t is the time taken and g is the gravitational force.

But, u = 0 m/s, h = 21 cm (0.21 m) and g = 9.8 m/\(s^{2}\). Then:

0.21 = 0 + \(\frac{1}{2}\) x 9.8 x \(t^{2}\)

0.21 = 4.9\(t^{2}\)

\(t^{2}\) = \(\frac{0.21}{4.9}\)

  = 0.04286

⇒ t = 0.2070

      = 0.21 s

The time taken for the flea to jump as high as 21 cm is 0.21 s.

The time taken for the flea to reach a height of 7.0 cm (0.07 m) can be determined as;

h = ut +  \(\frac{1}{2}\)g\(t^{2}\)

0.07 =  0 + \(\frac{1}{2}\) x 9.8 x \(t^{2}\)

0.07 =  4.9\(t^{2}\)

\(t^{2}\) = \(\frac{0.07}{4.9}\)

  = 0.01429

t = 0.1195

 = 0.12 s

how to tell how much work gravity does on something?

Answers

By dropping a ball and seeing how long it takes to hit the ground or throw a ball up and time it as well

A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute. How much power is needed for the elevator’s trip?

Answers

A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute is 12500 W (12.5 kW).

What is Power?

Power is the amount of work that is done per unit of time. It can be associated with the speed of a change of energy within a system, or the time it takes to perform a job.

There are different types of power,

Mechanical power: is that work performed by an individual or a machine in a certain period of time.

Electric power: which is the result of the multiplication of the potential difference between the ends of a load and the current flowing there.

P= W/t

Where, P- Power,

W- Work

T- Time

The total weight of the passenger + elevator is

Fg = 500+24500

    = 25000

The total work done to rise the elevator + passenger is equal to the product between the total weight and the distance covered during the trip (d = 30 m):

W = Fgd

   = 25000×30

   =7,50,000 J.

The power needed for the trip is equal to the ratio between the work done (W) and the time taken (t):

P = W/t

Since the time taken is t = 1 min = 60 s, the power needed is

P = 750000 / 60

   = 12,500 W

P = 12.5 kW

Thus, Power was calculated as P = 12.5 kW.

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Audrey is at the theatre watching an actor on stage. She notices that the stage lights change the appearance of the actors clothes. Explain the observations below. In red light the trousers look black and the shirt looks red. In green light the trousers look green and the shirt looks black. In the blue light the trousers look black and the shirt looks blue.

Answers

Note that the concept that Audrey is experiencing is called Color perception.

What is color perception?

Color perception is part of the wider visual system and is handled by a complicated process between neurons that begins with various types of photoreceptors being stimulated differently by light entering the eye.

Audrey's observations pertain to the phenomenon of color perception, a condition where an object's hue appears dissimilar due to varying light conditions.

This is caused by human brains perceiving colors based on the light wavelengths absorbed and reflected within an object. The stage lighting in Audrey's scenario emits varying forms of light wavelength, thus causing different reflections and absorptions from the actor’s clothes.

For instance, under red light, only red is reflected by the trousers while all other available colors are being absorbed, whereas the shirt absorbs red while reflecting other colors resulting in its distinctly reddish appearance. While illuminating the ensemble under a green light, the trousers reflect green light while the shirt absorbs it, resulting in its black appearance.

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a car accelerates from 20 m/s to 40 m/s in 10 s and its forward thrust is equal to 3 kN, what is the mass of

Answers

A car that has a forward thrust of 3kN and accelerates from 20 m/s to 40 m/s in 10 s has a mass of 1500 kg. Thus, the mass of the car is the 1500 kg

Newton's 2nd law of motion

From the question, we are to calculate the mass of the car.

From Newton's second law of motion, we have that

F = ma

Where F is the Net force

m is the mass

and a is the acceleration

Also, from one of the equations of linear motion, we have that

v = u + at

Then, we can write that

\(a = \frac{v-u}{t}\)

Where v is the final velocity

u is the initial velocity

a is the acceleration

and t is the time taken

Therefore,

\(F = m\frac{(v-u)}{t}\)

From the given information,

u = 20 m/s

v = 40 m/s

t = 10 s

F = 3 kN = 3000 N

Putting the parameters into the equation, we get

\(3000 = m \frac{(40-20)}{10}\)

\(3000 = m \times \frac{20}{10}\)

3000 = 2m

Then,

m = 3000 ÷ 2

m = 1500 kg

Hence, the mass of the car is the 1500 kg.

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A particle is moving through an electric field. Starting from the origin, it first moves 7.22 cm in the negative y-direction, then it moves 8.05 cm in the positive x-direction. What is the direction of the resultant vector?
41.9 above the negative x-axis
41.9 below the negative x-axis
41.9 above the positive x-axis
41.9 below the positive x-axis

Answers

Answer: 41.9 below the negative x-axis.

Explanation: To find the direction of the resultant vector, we need to use some trigonometry and vector addition. Here are the steps:

Draw a diagram of the particle’s motion and label the vectors. The particle starts at the origin and moves 7.22 cm in the negative y-direction, which we can call vector A. Then it moves 8.05 cm in the positive x-direction, which we can call vector B. The resultant vector R is the vector that goes from the origin to the final position of the particle.

Find the components of vector A and vector B. Vector A has a magnitude of 7.22cm and a direction of 270 degrees (or -90 degrees) from the positive x-axis. Vector B has a magnitude of 8.05 cm and a direction of 0 degrees (or 360 degrees) from the positive x-axis. Using trigonometry, we can find the x and y components of each vector as follows:

A_x = A cos(270) = 7.22 cos(270) = 0

A_y = A sin(270) = 7.22 sin(270) = -7.22

B_x = B cos(0) = 8.05 cos(0) = 8.05

B_y = B sin(0) = 8.05 sin(0) = 0

Add the components of vector A and vector B to get the components of vector R. Using vector addition, we can find the x and y components of the resultant vector as follows:

R_x = A_x + B_x = 0 + 8.05 = 8.05

R_y = A_y + B_y = -7.22 + 0 = -7.22

Find the magnitude and direction of vector R using Pythagoras’ theorem and inverse tangent function. The magnitude of vector R is given by the square root of the sum of the squares of its components, and the direction of vector R is given by the inverse tangent of its y component divided by its x component, as follows:

R = sqrt(R_x^2 + R_y^2) = sqrt(8.05^2 + (-7.22)^2) = sqrt(114.81) = 10.71 cm

theta = tan^-1(R_y / R_x) = tan^-1(-7.22 / 8.05) = -41.9 degrees

Adjust the direction of vector R according to its quadrant. Since vector R is in the fourth quadrant, where both x and y are positive, we need to add 360 degrees to its direction to get a positive angle measured counterclockwise from the positive x-axis, as follows:

theta = -41.9 + 360 = 318.1 degrees

Alternatively, we can express the direction of vector R as an angle measured clockwise from the negative x-axis, which is equivalent to subtracting its direction from 360 degrees, as follows:

theta = 360 - (-41.9) = 401.9 degrees

However, since angles are periodic with a period of 360 degrees, we can subtract multiples of 360 degrees from this angle to get an equivalent angle between 0 and 360 degrees, as follows:

theta = 401.9 - 360 = 41.9 degrees

Therefore, the direction of vector R is either 318.1 degrees counterclockwise from the positive x-axis or 41.9 degrees clockwise from the negative x-axis.

Hope this helps, and have a great day! =)

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