As part of their research on cell reproduction, Ms. Kelly's biology class designed various experiments to determine the best conditions for budding, or asexual reproduction, in common yeast cells. The students added sucrose as a source of food for the yeast and each group added water of a different temperature to the yeast-sugar mix. They used a light microscope to observe and count the yeast cells.

Based on the recorded data, what observation did the students make regarding the growth of yeast cells?

A) Once the temperature reached 50oC, the yeast died.
B) The size of individual yeast cells increased with an increase in temperature.
C) Increased temperature played no role in increasing the number of yeast cells.
D) The number of yeast cells increased as the temperature of the water increased.

Answers

Answer 1
B I hope this helped!

Related Questions

A ball of mass 0.190 kg has a velocity of 1.50 i m/s; a ball of mass 0.305 kg has a velocity of -0.401 i m/s.They meet in a head-on elastic collision. (a) Find their velocities after the collision.

Answers

Answer:

0.329m/s

Explanation:

According to law of conservation of momentum, the momentum of the object before collision is equal to that of the object after collision. Using the formula

m1u1 + m2u2 = (m1+m2)v

m1 and m2 are the masses of the object

u1 and u2 are the respective initial velocities

v is the final velocity

Given

m1 = 0.190kg

u1 = 1.5m/s

m2 = 0.305kg

u2 = -0.401m/s

Substitute

0.19(1.5)+(0.305)(-0.401) = (0.19+0.305)v

0.285 - 0.122305 = 0.495v

0.162695 = 0.495v

v = 0.162695 /0.495

v = 0.329m/s

Hence their velocities after collision is 0.329m/s in the positive x direction

Please help, i don’t understand A through D. Image attached.

Please help, i dont understand A through D. Image attached.

Answers

Explanation:

(a)

The initial kinetic energy is geven by 1/2 m v^2, all of which we are given in the problem.

KE = 1/2 (1500) (32)^2 = 768000 J

(b)

Use the work-kinetic energy theorem. The work-kinetic energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.

ΔKE = KEf - KEi

Since, the car ends at rest (no velocity), the final kinetic energy is 0.

ΔKE = -KEi = -768000 J

Apply the work kinetic energy theorem.

ΔKE = W = -768000 J

(c)

W = F · d = F d cosα

We are given d, and we have W from part b. In this case, α is 180° since the force must be in the opposite direction of the motion to slow the car down. Rearrange the equation for F.

F = W / (d cosα) = -768000 / (21 cos180°) = 36571 N

(d)

The force causing the car to stop is the frictional force, caused by the car's tires rubbing against the pavement.

Give two examples of situations or application where electronic circuits are used

Answers

a battery running to a transistor to regulate voltage to then power an LED lightbulb.

In the diagram, which letter represents the angle of incidence?

In the diagram, which letter represents the angle of incidence?

Answers

Answer:

D.

Explanation:

the required angle is ∠PRS (for more info see the attachment), then it is D.

In the diagram, which letter represents the angle of incidence?

Answer: D

Explanation:

4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V

4. Calculate the total resistance of the circuit if R1=4 , R2=30 , R3=10, R4=5 Determine the current

Answers

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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Please help me



Explain why driver age 16-18 are most likely to be involved in traffic accidents

Answers

Answer:Lack of experience.

Explanation:

Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.

Which of the following statements are true?

It is proper to use the period when it is 1 second or greater.
It is proper to use the frequency when it is 1 Hertz or greater.
It is proper to use the period when it is less than 1 second.
It is proper to use the frequency when it is less than 1 Hertz.

Answers

Both of the first two statements are true:

- It is proper to use the period when it is 1 second or greater. The period is the time it takes for one complete cycle of a wave to occur, and it is typically measured in seconds. When dealing with waves that have periods of 1 second or longer, it is more convenient to use the period rather than the frequency.

- It is proper to use the frequency when it is 1 Hertz or greater. The frequency is the number of cycles of a wave that occur in one second, and it is typically measured in Hertz (Hz). When dealing with waves that have frequencies of 1 Hz or higher, it is more convenient to use the frequency rather than the period.

The last two statements are not true:

- It is not proper to use the period when it is less than 1 second. The period is still a valid measure for waves with periods less than 1 second, but it may be more convenient to use the frequency instead.

- It is not proper to use the frequency when it is less than 1 Hertz. The frequency is still a valid measure for waves with frequencies less than 1 Hz, but it may be more convenient to use the period instead.

A bucket is being lowered by a very light rope with a constant downward velocity. The tension in the rope must be

Answers

Answer:

The tension in the light rope must be equal to the weight of the bucket

Explanation:

Given that,

Constant velocity of bucket and direction of bucket in downward

We need to find the tension in the rope

Using given data,

When a bucket  moves downward with a constant velocity then the net force does not applied on the bucket.

So, The weight of the bucket will be equal to the tension in the light rope

In mathematically,

\(T=mg\)

Where, T = tension

m = mass of bucket

g = acceleration due to gravity

Hence, The tension in the light rope must be equal to the weight of the bucket.

A motivated mule can accelerate an empty cart of mass m - 180 kg from rest to 5.0 m/s in 10 s.
If the cart is loaded with 550 kg of wood, how long will it take the mule to get the cart to 4.6 m/s? Assume a constant acceleration. Also assume the mule exerts the same force as when the cart is
empty

Answers

When the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

Acceleration of the mule

The acceleration of mule is calculated as follows;

a = v/t

a = 5/10

a = 0.5 m/s²

For constant applied force

F1 = F2

m₁v₁/t₁ = m₂v₂/t₂

(180 x 5) / 10 = (550 x 4.6)/t

90 = 2530/t

t = 2530/90

t = 28.11 s

Thus, when the mass of the cart changes, the time to travel at 4.6 m/s is 28.11 s.

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In a model of the solar system that was about as large as a college campus how large would the Sun be?
About the size of a basketball.
About the size of a marble.
About the size of a softball.
About the size of a small car

Answers

Small car is the answer

What is the need for satellite communication elaborate

Answers

The high frequency radio waves used for telecommunications links travel by line of sight and so are obstructed by the curve of the Earth. The purpose of communications satellites is to relay the signal around the curve of the Earth allowing communication between widely separated geographical points.

Explanation:

hope it helps!!

1. At one time, people thought that heat was a
substance called

Answers

Answer:

the thought of people in the pastthat is like fire and that can see than touch

Explanation:

heat is a form of energy that can transfer easly from one to the other

Could you help with this questionConstruct a position-time graph using your data. Draw the smooth curve of best fit. Remember that a good graph has a clear title and clearly labelled axes (with quantity being measured and unit of measurement).

Could you help with this questionConstruct a position-time graph using your data. Draw the smooth curve

Answers

Take into account that each pair of values on the table can be represented by a point in the coordinate system. In this case, the independent variable is time, then, the x-axis represents the values of time. Moreover, position is dependent variable, then y-axis represents the values of position.

By placing the corresponding points on the coordinate system and join them with a curve, you obtain the following graph:

Could you help with this questionConstruct a position-time graph using your data. Draw the smooth curve

A ball rolls down a curved ramp as shown in the diagram below. Which dotted line best represents the path of the ball after leaving the ramp? A) A B) B C) C D) D

Answers

The movement of the ball down the ramp can be shown by option B.

What is the path of the ball?

We know that the question has clearly said that the ramp was curved and this is going to help in shaping our discussion. In this case, it is clear that the the ball  rolls down a curved ramp as shown. The movement of the ball can be typified by the use of dotted lines.

In this case, we can see that the ball is going to continue to move in a curved path as the ball is moving down the ramp as has been shown in the image.

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A ball rolls down a curved ramp as shown in the diagram below. Which dotted line best represents the

dipole moment are used to calculate the​

Answers

Answer:

Explanation:

ádasdasdasd

An airplane flies 2500 miles east in 245 seconds what is the velocity of the plane?

Answers

Speed = (distance) / (time)

Speed = (

Velocity = speed, and its direction

The velocity of the plane is 10.2 miles per second East.

(about 48 times the speed of sound)

Using what you already know about newton’s law’s explain how the force applied to the ball by the pitcher and the force applied to the ball by the bat will impact yours ability ti hit a home run

Answers

An item at rest will remain at rest, and an object in motion will continue to move in a straight path at a constant speed, according to the first law of motion, commonly known as the law of inertia.

How is baseball impacted by Newton's first law?

Newton's laws of motion govern how a baseball moves as a result of being thrown or struck. According to Newton's first law, a moving ball will continue to move in a straight line until other forces are acting on it.

What happens when a baseball bat strikes a ball?

The ball is severely distorted by the enormous force the bat applies to it ball being struck. The average force acting during the bat-ball collision is therefore about two tons, with a peak force of nearly four tons, during the 0.7 millisecond contact time. There's a lot of force there!

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Whenever I visit one of the big membership-driven bulk wholesalers in town, without fail I end up using a junk cart with bum wheels that not only drag, but pull to the left. If a cart requires 20 lb of force forward to overcome the wheel’s drag, but there are also around 3 lb of force pulling it to the left, with what force and in what direction do I need to push in order to make the cart go forward?

Required:
Measure your angle from the forward direction and specify whether it’s to the left or right.

Answers

Answer: Force of magnitude 20.22lbf to the right at angle 8.5°

Explanation: The image named "Untitled" below shows the forces acting on the cart.

The second image, "Untitled2", demonstrate the vector diagram of the forces acting on the kart, in which:

f is force forward

f(left) is pull to the left

f(R) is the resulting force necessary for the kart to move

The drag force is not draw on the vector diagram because its value is already part of the force forward.

As we can see, the diagram forms a right triangle with f(R) as hypotenuse.

Using Pytagorean Theorem:

\([f(R)]^{2}=f^{2}+[f(left)]^{2}\)

\([f(R)]^{2}=20^{2}+3^{2}\)

\([f(R)]^{2}=409\)

\(f(R)=\sqrt{409}\)

f(R) = 20.22

Force forward equals 20.22lbf to the right.

The angle formed form the forward direction and the resulting force is

\(cos\theta=\frac{20}{20.22}\)

cosθ = 0.989

θ = cos⁻¹(0.989)

θ = 8.5°

The forward force is to the right at angle 8.5° and magnitude 20.22lbf.

Whenever I visit one of the big membership-driven bulk wholesalers in town, without fail I end up using
Whenever I visit one of the big membership-driven bulk wholesalers in town, without fail I end up using

If a 500kg elephant is sliding across a frictionless patch of ice, how much force is needed to keep the elephant from slowing down?

Answers

Answer:

4905N

Explanation:

The force needed to keep the elephant from slowing down is expressed as shown according to Newtons second law of motion.

Force = mass * acceleration due to gravity

Given

Mass of elephant = 500kg

acceleration due to gravity = 9.81m/s²

Force = 500*9.81

Force = 4905N

Hence the force needed to keep the elephant from slowing down is 4905N

Harold is using what he knows about cause-and-effect relationships to write a paper explaining cloud shape. How could he describe cause and effect in his paper?

Answers

Harold could use cause-and-effect relationships to describe the formation of different cloud shapes in his paper by explaining how certain environmental factors cause specific cloud formations to occur by explaining the changes in temperature, humidity, and air pressure.

Explain the formation of clouds?

Clouds form when warm, moist air rises and cools, causing the water vapor to condense into tiny water droplets or ice crystals. These droplets or crystals then cluster together to form visible clouds in the atmosphere.

To explain the cause-and-effect relationships, Harold could use phrases like "as a result of," "because of," "due to," and "resulting in." For example, he could write, "When warm, moist air rises and cools, it causes water droplets to condense into cumulus clouds," or "High-altitude cirrus clouds are formed due to the presence of ice crystals in the atmosphere."

By using cause-and-effect relationships in his paper, Harold can help readers understand how and why different types of clouds form, and how they are influenced by various environmental factors.

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Compare sound and earthquake waves

Answers

When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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8.
A skier coasts down a 3.5° slope at constant speed. Find the coefficient of kinetic friction
between the skis and the snow covering the slope.

Answers

The coefficient of kinetic friction between the skis and the snow covering the slope is 0.7.

What is coefficient of kinetic friction?

The coefficient of kinetic friction is the ratio of the kinetic friction force of contacting surfaces to the normal force.

The coefficient of kinetic friction between the skis and the snow covering the slope is calculated by applying the following formula.

μ = Ff/N

μ = mgsinθ/mg cosθ

μ = tanθ

where;

θ is the angle of inclination of the slopeFf is frictional force

μ = tan(35)

μ = 0.7

Thus, the coefficient of friction is determined from the ratio of kinetic friction and normal force.

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The _________ rule says the ball must bounce one on each side before either team may start volleying the ball in the air. Double Bounce

Volley Bounce

Bounce

Two Bounce

Answers

The answer is: Two bounce

A car is travelling at 16.7m/s. If the car can slow at a rate of 21.5m/s^2, how much time does the driver need in order to stop the red light?

Answers

Answer:

About 0.7767 seconds

Explanation:

\(\dfrac{16.7m/s}{21.5m/s^2}\approx 0.7767s\)

Hope this helps!

What is the angle of reflection? ______ degrees

Answer: 45 degrees

Answers

What is the angle of reflection? 45 degrees

Answer: 45 degrees

The way in which one atom interacts with another atom is mostly influenced by the configuration of the
A. electrons farthest from the nucleus.
B. protons in the center of the nucleus.
C. electrons closest to the nucleus.
D. protons on the outer edge of the nucleus.

Answers

The way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

Option A.

What is atom?

An atom can be defined as the smallest part of a substance that cannot be broken down chemically. Each atom has a nucleus (center) made up of protons (positive particles) and neutrons (particles with no charge).

The arrangement of electrons in orbitals and shells around the nucleus is referred to as the electronic configuration of the atom.

Thus, we can conclude that the way in which one atom interacts with another atom is mostly influenced by the configuration of the electrons farthest from the nucleus.

The remaining options do not fit the empty space properly, and they include;

protons in the center of the nucleus.electrons closest to the nucleus.protons on the outer edge of the nucleus.

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Which direction do longitudinal waves travel?

Answers

Answer:

If the particles of the medium vibrate in a direction parallel to the direction of propagation of the wave, it is called a longitudinal wave. In longitudinal waves, the particle movement is parallel to the direction of wave propagation.

Explanation:

Find the terminal velocity of a sphere that has a mass of 600g and a radius of 30cm. Take the density of air 1.2 kg/m^3 . Report the speed in mph.

Answers

The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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Blue light with a wavelength of 4.57 E-7 m is used in Young's experiment with the slits separated by a distance of 2.42 E-4Y
m. The screen is located at a distance from the slits of 4.5 m. Calculate the distance on the screen between the central
bright fringe and the first bright fringe. Show all work for full credit.

Answers

The distance between the central bright fringe and the first bright fringe on the screen is approximately 8.52E-3 meters.

In Young's double-slit experiment, the distance between the central bright fringe (m = 0) and the first bright fringe (m = 1) can be calculated using the following formula:

y = (m * λ * L) / d

where:

y is the distance between the fringes on the screen,

m is the order of the fringe (0 for the central bright fringe, 1 for the first bright fringe),

λ is the wavelength of the light,

L is the distance from the slits to the screen, and

d is the distance between the slits.

Given the values:

λ = 4.57E-7 m (blue light wavelength)

d = 2.42E-4 m (distance between the slits)

L = 4.5 m (distance from the slits to the screen)

For the central bright fringe (m = 0), the distance (y) is:

y = (0 * 4.57E-7 m * 4.5 m) / 2.42E-4 m

y = 0

Therefore, the central bright fringe coincides with the point where the two beams of light overlap.

For the first bright fringe (m = 1), the distance (y) is:

y = (1 * 4.57E-7 m * 4.5 m) / 2.42E-4 m

y ≈ 8.52E-3 m

This calculation demonstrates how the interference pattern in Young's experiment is formed, with bright and dark fringes being produced based on the constructive and destructive interference of the light waves from the two slits. The distance between these fringes depends on the wavelength of light, the separation of the slits, and the distance between the slits and the screen.

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The work-energy theorem states that the change in the kinetic energy of an object is equal to what?

Answers

The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.

Mathematically, it can be expressed as;

ΔKE = W

Where; ΔKE represents the change in kinetic energy of the object,

W represents the net work done on the object.

This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.

This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.

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