As figure has an area of 64 squared units which describes the area of the figure after a dialation with a scale factor of 3 over 2

To find the change in annual cost when q is increased from 346 to 347, you need to calculate the difference in annual costs between these two order sizes.

This can be compared with the instantaneous rate of change, which measures the rate of change in the cost function at a specific point.

To calculate the change in annual cost, subtract the cost at q=346 from the cost at q=347. Let's assume the cost function is denoted by C(q). The change in annual cost can be computed as ΔC = C(347) - C(346).

On the other hand, the instantaneous rate of change can be determined by taking the derivative of the cost function with respect to q, denoted as dC/dq. This measures the rate at which the cost is changing at a specific value of q.

By comparing the change in annual cost ΔC with the instantaneous rate of change dC/dq, you can analyze how the cost function behaves when q is increased from 346 to 347. If the change in annual cost is larger than the instantaneous rate of change, it suggests a significant impact of the increase in order size on the overall cost. If the change is smaller, it indicates a more gradual change in the cost function.

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To find the change in annual cost when q is increased from 346 to 347, you need to calculate the difference in annual costs between these two order sizes.

This can be compared with the instantaneous rate of change, which measures the rate of change in the cost function at a specific point.

To calculate the change in annual cost, subtract the cost at q=346 from the cost at q=347. Let's assume the cost function is denoted by C(q). The change in annual cost can be computed as ΔC = C(347) - C(346).

On the other hand, the instantaneous rate of change can be determined by taking the derivative of the cost function with respect to q, denoted as dC/dq. This measures the rate at which the cost is changing at a specific value of q.

By comparing the change in annual cost ΔC with the instantaneous rate of change dC/dq, you can analyze how the cost function behaves when q is increased from 346 to 347. If the change in annual cost is larger than the instantaneous rate of change, it suggests a significant impact of the increase in order size on the overall cost. If the change is smaller, it indicates a more gradual change in the cost function.

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The data given in the question are: Mass of coal (m) = 8788 kg/hr Ambient pressure (P1) = 100 kPa Moisture present in the coal = 0% Excess air supplied = 15.4% Oxygen (O) in flue gas = 4.87% Carbon dioxide (CO2) in flue gas = 15.25% Nitrogen (N2) in flue gas = 79.58%

The volume flow rate of the wet gas is given as, Q = V x ? Where, V = Volume of the wet gas, and ? = Density of the wet gas. First, we will calculate the percentage of dry flue gases present in the wet flue gas. The percentage of wet flue gases is calculated as,

Total flue gases = Oxygen (O) + Carbon dioxide (CO2) + Nitrogen (N2) + Sulfur (S) + Moisture Total flue gases = 4.87 + 15.25 + 79.58 + 3.24 + 0 = 103.94%

Dry flue gases = Total flue gases - Moisture Dry flue gases = 103.94 - 0 = 103.94%The percentage of excess air supplied is given as 15.4%. The actual air supplied is calculated as, Actual air supplied = (100 + Excess air supplied)/100 x Theoretical air Actual air supplied = (100 + 15.4)/100 x 6.21/2.67Actual air supplied = 3.4654 kg/kg of coal Theoretical air = 6.21/2.67 kg/kg of coal The mass of flue gas is calculated as follows:

Mass of flue gas = Mass of coal x Air-fuel ratio x (1 + Moisture in fuel)

Mass of flue gas = 8788 x 3.4654 x (1 + 0)

Mass of flue gas = 106780.57 kg/hr

The volume flow rate of the wet gas is calculated as follows: Q = V x ?V = Q / ?Where the density of the wet gas is given by,

? = 0.3568 [(P1 x Mw) / (Rwg x (Tg + 273.15))]

The molecular weight of flue gas (Mw) = 28.98 kg/kmol (taken as the average molecular weight of flue gas)

The gas constant of flue gas (Rwg) = 0.2792 kJ/kg-K

The temperature of flue gas (Tg) = 303 + 273.15 = 576.15 K

The density of the wet gas,

? = 0.3568 [(100 x 28.98) / (0.2792 x 576.15)]? = 2.431 kg/m3

Now, we can calculate the volume flow rate of the wet gas as follows:

V = Q / ?106780.57 / (2.431)

= 43967.53 m3/hrQ

= 12.2138 m3/s

The volume flow rate of the wet gas in m3/s can be calculated using the formula, Q = V x ?, where V is the volume of the wet gas and ? is the density of the wet gas. In order to calculate the volume flow rate, we need to determine the mass of flue gas and the density of the wet gas. The mass of flue gas can be calculated using the mass of coal, air-fuel ratio, and moisture in fuel.

The density of the wet gas can be calculated using the molecular weight of flue gas, the gas constant of flue gas, the temperature of flue gas, and the ambient pressure. Once the mass of flue gas and the density of the wet gas have been determined, we can calculate the volume flow rate of the wet gas using the formula Q = V x ?.

In this question, the mass of coal is given as 8788 kg/hr, the ambient pressure is given as 100 kPa, and the temperature of the wet gas is given as 303 0C. The excess air supplied is given as 15.4%, and the Rwg is given as 0.2792 kJ/kg-K.

The moisture present in the coal is given as 0%. Using these values, we can calculate the volume flow rate of the wet gas in m3/s as 12.2138 m3/s. Therefore, the answer is 12.2138 m3/s.

Thus, we can conclude that the volume flow rate of the wet gas in m3/s is 12.2138 m3/s.

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The implicit solution to the given differential equation Dx/dt = 4x² + (9t/√(6²+x²)) / (4tx) using the method for solving homogeneous equations is F(t,x) = C, where C is an arbitrary constant.

To solve the given differential equation, we can separate the variables and integrate both sides. Rearranging the equation, we have:

(4tx) Dx = (4x² + (9t/√(6²+x²))) dt. Next, we integrate both sides. Integrating the left side with respect to x and the right side with respect to t, we get:

∫(4tx) Dx = ∫(4x² + (9t/√(6²+x²))) dt. Integrating both sides will result in a function F(t,x) on the left side and the integral on the right side. Since we are looking for an implicit solution in the form F(t,x) = C, we can write the equation as:

F(t,x) = C. cccThis represents the general solution to the given differential equation, where C is an arbitrary constant. The specific form of the function F(t,x) will depend on the integration process and the initial conditions, if provided.

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Answer:

It should be the third bubble, because all integers are whole numbers

Quadratic function is shown below. A polynomial function of degree two in one or more variables is known in algebra as a quadratic function, quadratic polynomial, polynomial of degree 2, or simply a quadratic.

A quadratic polynomial without any complex roots and two real roots. Other quadratic polynomials that have their minimum above the x axis have two complex roots instead of any real roots.

Authors sometimes mean "having degree exactly 2" and other times "having degree at most 2" when they refer to a quadratic polynomial. This situation may be referred to as a degenerate case if the degree is less than 2. In most cases, the context will determine which of the two is intended.

In some cases, the word order is used to refer to degree, as in the case of a second-order polynomial. Whereas order normally refers to the lowest degree of a non-zero term of a power series, the degree of a polynomial refers to the maximum degree of a non-zero term of the polynomial.

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The amount of money lost per year is 15x

Where 100x can be any amount

The percentage is calculated by dividing the required value by the total value and multiplying by 100.

Example:

Required percentage value = a

total value = b

Percentage = a/b x 100

Example:

50% = 50/100 = 1/2

25% = 25/100 = 1/4

20% = 20/100 = 1/5

10% = 10/100 = 1/10

We have,

Let the total amount of money earned in a year from the field = 100x

The new field area.

= 100% - 15%

= 85%

Now,

The amount of money earned in a year from the new field area.

= 85% of 100x

= 85x

Now,

The amount of money lost per year.

= 100x - 85x

= 15x

Thus,

If 15% of the field is reduce the amount of money lost per year is 15x

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Answer:

250

Step-by-step explanation:

1000 divided by 4, is 250

The unit rate would be 250 calories per mile which is the slope of the given linear function.

The unit rate of a linear function is defined as the slope of the linear function.

The slope is denoted by m

Slope m = (y₂ - y₁)/(x₂ -x₁ )

Consider two points on a line—Point 1 and Point 2. Point 1 has coordinates (x₁,y₁) and Point 2 has coordinates (x₂, y₂)

The given graph represents the number of miles he ran and the number of calories burned.

Taking two points as per the given graph :(2, 500), (6, 1500)

Let

x₁ = 2, y₁ = 500

x₂ = 6, y₂ = 1500

Substitute values in the formula to get

unit rate = (1500 - 500)/(6 - 2)

unit rate = (1000)/(4)

Apply the division operation,

unit rate = 250

Therefore, the unit rate would be 250 calories per mile

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Answer:

That would be D or the last graph

Answer:

D

Step-by-step explanation:

The line passes through point at x = 0, y =3

y = x + 3

Choose 3 points as shown on the graph to deduce the correct one

when

x = 0, y = 3

x = 6, y = 9

x = -10, y = -7

Then;

put points (0,0)

0 = 3

Which is not true, color is placed above the line

I hope this Helps. Have a nice studies

The Perpendicular is 3.1 units and the Base is 5.2 units. The dimension of the triangle is shown in the diagram.

It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.

x = tan⁻¹(3.1 / 5.2)

A tangent of a degree x in a right-angled triangle is equivalent to the ratio of the opposing side to angle x to the adjacent side to angle x in trigonometric.

Then the dimension of the triangle will be

Perpendicular = 3.1

Base = 5.2

Then the triangle is shown in the diagram.

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Answer:

D

Step-by-step explanation:

Answer:

Step-by-step explanation:

interval in mathematics stands for a set of real numbers,

denoted by [a,b] where a and b are the starting and ending real numbers both inclusive respectively.

thus, interval [a,b] is the set of real numbers starting from a to b both are real numbers and are included.

Answer:

4x² + 11x + 6 = (x + 2)(4x + 3)

Answer:

James is 18

Marin is 13

Step-by-step explanation:

31 - 5 = 26

26/2 = 13

13 + 5 = 18

Therefore, the equation of the tangent to the curve at the point (4, 6) by eliminating the parameter is y = 2x - 2.

To find the equation of the tangent to the curve at the point (4, 6) both with and without eliminating the parameter, we need to differentiate the parametric equations and evaluate them at the given point.

Without eliminating the parameter:

Differentiate both equations with respect to the parameter t:

dx/dt = 1/t

dy/dt = 2t

Evaluate dx/dt and dy/dt at t = 4:

dx/dt = 1/4

dy/dt = 8

The slope of the tangent line is given by dy/dx, which can be found by dividing dy/dt by dx/dt:

dy/dx = (dy/dt) / (dx/dt) = (8) / (1/4) = 32

Since the tangent line has a slope of 32 and passes through the point (4, 6), we can use the point-slope form of a line to find the equation of the tangent:

y - y₁ = m(x - x₁)

y - 6 = 32(x - 4)

y - 6 = 32x - 128

y = 32x - 122

Therefore, the equation of the tangent to the curve at the point (4, 6) without eliminating the parameter is y = 32x - 122.

Now, let's find the equation of the tangent by eliminating the parameter:

Solve the first equation, x = 4 + ln(t), for t:

t = e^(x - 4)

Substitute the value of t into the second equation, y = t^2 + 5:

y = (e^(x - 4))^2 + 5

y = e^(2x - 8) + 5

Differentiate the equation y = e^(2x - 8) + 5 with respect to x to find the derivative dy/dx:

dy/dx = 2e^(2x - 8)

Evaluate dy/dx at x = 4:

dy/dx = 2e^(2(4) - 8) = 2e^0 = 2

The slope of the tangent line is 2 at x = 4.

Use the point-slope form of a line with the given point (4, 6) and the slope 2:

y - y₁ = m(x - x₁)

y - 6 = 2(x - 4)

y - 6 = 2x - 8

y = 2x - 2

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Answer:

\(k = 1 - \frac{ \sqrt{313} }{26} \)

\(k = \frac{ \sqrt{313} }{26} + 1\)

Answer:

true

Step-by-step explanation:

Answer:

1 cubic inch

Step-by-step explanation:

The formula for the volume of a rectangle prism is: V (Volume) = L (length) * W (width) * H (height)

L = 2 in

W = 1 in

H = 1/2 in

Therefore

V = L * W * H = 2 * 1 * 1/2 = 1

P.S. Hope it makes sense. If you have any questions, lmk in the comments. I'll be happy to help. Have a wonderful day!

Answer:

Z = 3

Step-by-step explanation:

if y = 3 then 3 x 2 = 6 subtract that from 9 and u get 3 so therefore z is 3

Answer:

I cant see the file with it

Step-by-step explanation:

Total price paid by Michael for the basket of mangoes is $4.48.

For the calculation of total price, price of sales tax will be added with selling price. Forming the equation -

Total price = 4 + 12%×4

Calculating the percentage of sales tax on Right Hand Side of the equation

Total price = 4 + 12×4/100

Solving the percentage part on Right Hand Side of the equation

Total price = 4 + 0.48

Performing addition on Right Hand Side of the equation

Total price = $4.48

Hence, Michael has to pay $4.48 after addition of sales tax for the basket of mangoes.

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Learn more

Answer:

They bisect each other.

Step-by-step explanation:

→Solution,

Here, coordinate of quadrilateral DEFG are D(-3,-5), E(-4,3), F(2,6) and G(3,-2).

⇒For diagonal DF.

Let,(x1,y1)=(-3,-5)

     (X2,Y2)=(2,6)

→Using midpoint formula.

\(x=\frac{x_1+x_2}{2} ,y=\frac{y_1+y_2}{2} \\\\x=\frac{-3+2}{2} ,y=\frac{-5+6}{2}\\\\x=\frac{-1}{2} ,y=\frac{1}{2}\)

⇒For diagonal EG.

Let,(x1,y1)=(-4,3)

     (X2,Y2)=(3,-2)

→Using midpoint formula.

\(x=\frac{x_1+x_2}{2} ,y=\frac{y_1+y_2}{2} \\\\x=\frac{-4+3}{2} ,y=\frac{-2+3}{2}\\\\x=\frac{-1}{2} ,y=\frac{1}{2}\)

Here, the midpoint of diagonal DF and EG is equal.

Hence they bisect each other.

Midpoint of DF and EG must be same

#DF

M(x,y)

#EG

P(x,y)

As mid points are equal diagonals bisect each other

Answer:

The chord is drawn below

Step-by-step explanation:

To find the difference in area between the shaded parts B and D, we need to first find the area of each shaded part separately. Shaded part B is a quarter circle with radius 5cm, so its area can be calculated using the formula for the area of a quarter circle, which is (1/4)πr^2. Plugging in the radius, we get (1/4) x 3.14 x 5^2 = 19.625 cm^2.

To find the difference in area between the shaded parts B and D, we first need to calculate the area of the quarter circle and the semicircle.

1. Quarter Circle (Part B):
- Radius = half of the square's side = 10cm / 2 = 5cm
- Area = (π × r²) / 4 = (3.14 × 5²) / 4 = 19.625 cm²

2. Semicircle (Part D):
- Diameter = square's side = 10cm, so the radius = 5cm
- Area = (π × r²) / 2 = (3.14 × 5²) / 2 = 39.25 cm²

Now, subtract the area of the quarter circle (Part B) from the area of the semicircle (Part D) to find the difference in area:

Difference = 39.25 cm² - 19.625 cm² = 19.625 cm²

So, the difference in area between the shaded parts B and D is 19.625 cm².

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Answer:

5 = 1+4

5 = 5

Step-by-step explanation:

(1,5) is an ordered pair composed of x and y values:

x = 1

y = 5

- Simply, substitute them into the equation in the place of x and y:

y = x +4

5 = 1+4

5 = 5

- both sides are equal, so this point lies on the correct line.

- I hope this helps :)

Step-by-step explanation:

step 1. 3(sqr(27) - 16) sqr is the square root

step 2. 3(3sqr3 -16)

step 3. 9sqr3 - 48.

Answer:

c 3/4, 0.8, 94%

Step-by-step explanation:

I would convert all of these to decimals first so its not as confusing

a). 0.54, 0.70, 0.40 not in order

b). 0.67, 0.50, 0.80 not in order

c). 0.75, 0.80, 0.94 in order

d). 0.70, 0.54, 0.67 not in order

The equation based on the information is:

34 = x - 18

In mathematics, an equation is an expression that states that two expressions are equal by joining them with the equal sign =. Equations and their cousins ​​in other languages ​​may have subtly different meanings. For example, in French an equation is defined as containing one or more variables, whereas in English any well-formed expression consisting of two expressions joined by an equal sign is an equation. To solve an equation involving variables, it is necessary to determine which values ​​of the variables make the equation true. The variables for which the equation must be solved are also called unknowns, and the values ​​of the unknowns that satisfy the equation are called the solution of the equation. There are two types of equations: identities and constraints. The ID applies to all values ​​of the variable. A constraint expression applies only to specific values ​​of a variable.

Given that :

Bella is baking 34 cookie for the holiday party tonight. She baked 18 before leaving for school and will bake the ret when he return home.

Therefore, the equation is:

34 = x - 18

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