As described in the previous problem, Refrigerant-134a enters the condenser of a residential heat pump at 800 kPa and 35 0C and leaves at 800 kPa as a saturated liquid. For a particular configuration (not the one you analyzed in the previous problem) which depends on the mass flow rate of refrigerant through the system, the heat rejected to the surroundings is 3.2 kW. If the compressor consumes 1.3 kW of power, what is the COP of the heat pump

The IC at the moment the ladder slides based on the lengths and other information given will be (0, 1.32)

From the information given, the calculation will be computed below:

l cos a = 1.5

cos a = 1.5/2

cos a = 0.75

a = 41.4°

ab = a/cos a = 1.5/cos41.4

ab = 1.5/0.75

ab = 2

b = 2 × sin 41.4

b = 2 × 0.66

b = 1.32

Therefore, the IC will be (0, 1.32).

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A fabric-based domed structure can last for approximately 20 to 30 years with proper maintenance and care.

The lifespan of a fabric-based domed structure can vary depending on several factors. The quality of the fabric material, the structural design, environmental conditions, and maintenance practices all play a role in determining its longevity. High-quality fabrics made from durable materials, such as architectural-grade PVC or PTFE-coated fiberglass, tend to have a longer lifespan. Regular inspections, cleaning, and repairs are essential to ensure the integrity of the fabric and the structural components. Proper tensioning and periodic maintenance can help prevent issues such as sagging, tears, or UV degradation, which can affect the structure's lifespan.

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Infinite recursion can lead to an error known as stack fault, memory exception, syntax error, or logic error

Infinite recursion can lead to an error known as stack fault, memory exception, syntax error, or logic error. It can occur because the base case is missing one of the necessary termination conditions, the recursive case is invoked with simpler arguments, a second function is called from the recursive one, or the recursive function is called more than once.
In order for the loop to show different behavior when calling the function on the two different kind of objects in the array in the first code snippet, the drew function must be a virtual function in the base class.
In order for pointers to the two different objects to be put into the same array in the second code snippet, the objects must be related to one another via inheritance.
In order for the loop at the end to show different behavior when calling the function on the two different kind of objects in the array in the third and fourth code snippets, the function must be a virtual function in the base class and the array should contain objects, not pointers.

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Answer:

Explanation:

code in the curly braces is treated as regular body and will be executed normally

Increasing the hardness of the metal, increasing the strength of the metal, reducing the ductility of the metal.

What is ductility?
Ductility is the ability of a material to deform under tensile stress; it is often characterized by the material’s ability to be stretched into a wire. Ductility is an important mechanical property of materials, as it allows them to be formed into a variety of shapes and parts. Metals are generally more ductile than other materials and are often used in applications that require flexibility. Ductility is closely related to malleability, which is the ability of a material to be hammered or rolled into a thinner shape.

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As something of a result, the highest electric field in an unpaid labor p-n junction diode is around 8.93 x 104 V/cm. To calculate the maximum electric field (Emax) in an uncompensated p-n junction diode, we can use the following formula:

Emax = V / W

Where V is the applied bias voltage and W is the depletion width of the diode.

The depletion width can be calculated using the following formula for a double-sided abrupt junction:

W = [(2εε0 / q) * (NA*ND / (NA+ND)) * (Vbi + V)]^0.5

Where ε is the permittivity of silicon, ε0 is the vacuum permittivity, q is the charge of an electron, NA is the acceptor doping concentration, ND is the donor doping concentration, Vbi is the built-in potential, and V is the applied bias voltage.

We can first calculate the built-in potential using the following formula:

Vbi = (kT / q) * ln(NA*ND / ni^2)

Where k is the Boltzmann constant, T is the temperature in Kelvin, and ni is the intrinsic carrier concentration of silicon at 300K, which is approximately 1.5 x 10^10 (cm^-3).

Plugging in the given values, we get:

Vbi = (8.617 x 10^-5 eV/K * 300K / 1.602 x 10^-19 C) * ln(28 x 10^16 cm^-3 * 36 x 10^16 cm^-3 / (1.5 x 10^10 cm^-3)^2)

≈ 0.787 V

Next, we can calculate the depletion width using the formula above:

W = [(2εε0 / q) * (NA*ND / (NA+ND)) * (Vbi + V)]^0.5

= [(2 * 11.7 * 8.854 x 10^-14 F/cm / 1.602 x 10^-19 C) * (28 x 10^16 cm^-3 * 36 x 10^16 cm^-3 / (28 x 10^16 cm^-3 + 36 x 10^16 cm^-3)) * (0.787 V - 1.5 V)]^0.5

≈ 0.168 µm

Finally, we can calculate the maximum electric field using the formula at the beginning:

Emax = V / W

= -1.5 V / (0.168 µm * 10^-4 cm/µm)

≈ -8.93 x 10^4 V/cm

Therefore, the maximum electric field in AP the uncompensated p-n junction diode is approximately 8.93 x 10^4 V/cm.

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Answer:

The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.

Explanation:

We must estimate the monthly storage change of the lake by considering inflows, outflows, seepage and evaporation losses and precipitation. That is:

\(\Delta V_{storage} = V_{inflow} -V_{outflow}-V_{seepage}-V_{evaporation}+V_{precipitation}\)

Where \(\Delta V_{storage}\) is the monthly storage change of the lake, measured in cubic feet.

Monthly inflow

\(V_{inflow} = \left(30\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)

\(V_{inflow} = 77.76\times 10^{6}\,ft^{3}\)

Monthly outflow

\(V_{outflow} = \left(27\,\frac{ft^{3}}{s} \right)\cdot \left(3600\,\frac{s}{h} \right)\cdot \left(24\,\frac{h}{day} \right)\cdot (30\,days)\)

\(V_{outflow} = 66.98\times 10^{6}\,ft^{3}\)

Seepage losses

\(V_{seepage} = s_{seepage}\cdot A_{lake}\)

Where:

\(s_{seepage}\) - Seepage length loss, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{seepage} = 1.5\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{seepage} = (1.5\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{seepage} = 2.86\times 10^{6}\,ft^{3}\)

Evaporation losses

\(V_{evaporation} = s_{evaporation}\cdot A_{lake}\)

Where:

\(s_{evaporation}\) - Evaporation length loss, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{evaporation} = 6\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{evaporation} = (6\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{evaporation} = 11.44\times 10^{6}\,ft^{3}\)

Precipitation

\(V_{precipitation} = s_{precipitation}\cdot A_{lake}\)

Where:

\(s_{precipitation}\) - Precipitation length gain, measured in feet.

\(A_{lake}\) - Surface area of the lake, measured in square feet.

If we know that \(s_{precipitation} = 4.25\,in\) and \(A_{lake} = 525\,acres\), then:

\(V_{precipitation} = (4.25\,in)\cdot \left(\frac{1}{12}\,\frac{ft}{in} \right)\cdot (525\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)\)

\(V_{precipitation} = 8.10\times 10^{6}\,ft^{3}\)

Finally, we estimate the storage change of the lake during the month:

\(\Delta V_{storage} = 77.76\times 10^{6}\,ft^{3}-66.98\times 10^{6}\,ft^{3}-2.86\times 10^{6}\,ft^{3}-11.44\times 10^{6}\,ft^{3}+8.10\times 10^{6}\,ft^{3}\)

\(\Delta V_{storage} = 4.58\times 10^{6}\,ft^{3}\)

The storage of the lake has increased in \(4.58\times 10^{6}\) cubic feet during the month.

The volume of water gained and the loss of water through flow,

seepage, precipitation and evaporation gives the storage change.

Response:

Given parameters:

Area of the lake = 525 acres

Inflow = 30 ft.³/s

Outflow = 27 ft.³/s

Seepage loss = 1.5 in. = 0.125 ft.

Total precipitation = 4.25 inches

Evaporator loss = 6 inches

Number of seconds in a month is found as follows;

\(30 \ days/month \times \dfrac{24 \ hours }{day} \times \dfrac{60 \, minutes}{Hour} \times \dfrac{60 \, seconds}{Minute} = 2592000 \, seconds\)

Number of seconds in a month = 2592000 s.

Volume change due to flow, \(V_{fl}\) = (30 ft.³/s - 27 ft.³/s) × 2592000 s = 7776000 ft.³

1 acre = 43560 ft.²

Therefore;

525 acres = 525 × 43560 ft.² =  2.2869 × 10⁷ ft.²

Volume of water in seepage loss, \(V_s\) = 0.125 ft. × 2.2869 × 10⁷ ft.² = 2,858,625 ft.³

Volume gained due to precipitation, \(V_p\) = 0.354167 ft. × 2.2869 × 10⁷ ft.² = 8,099,445.123 ft.³

Volume evaporation loss, \(V_e\) = 0.5 ft. × 2.2869 × 10⁷ ft.² = 11,434,500 ft.³

Which gives;

ΔV = 7776000 - 2858625 + 8099445.123 - 11434500 = 1582823.123

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Answer:

Wireless

Explanation:

A wireless remote control can be an advantage to an operator who is welding close to the power source. Hence, option A is correct.

An electrical device used to wirelessly and remotely operate another device is a remote control, often known as a remote or clicker. Consumer gadgets, such as television sets, DVD players, and other home appliances, can be controlled by a remote control.

In the current electronic market, remote control systems fall into three primary categories: IR-based systems, RD-based systems, and BT-based systems. the receiver and the remote must be lined up exactly for infrared, also known as IR.

IR, on the other hand, is unable to pass through a number of materials but can operate over a much wider spectrum. This allows the user far greater freedom and control in environments with challenging terrain and obstacles.

Thus, option A is correct.

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The correct answer is The combined force engineer oversees a number of engineering tasks, such as: (1) Scheduling and directing the execution of.

The Air Force and Navy are basically the only branches that offer major computer science work, despite the fact that all branches offer information technology training and professions that are excellent prerequisites for the hard-core business of computer science.

These professionals design, create, evaluate, and write programmes that are essential to our ability to wage war. They make sure we have the software and programmes required to carry out our duties successfully, from maintenance tracking applications to tools that organise and show intelligence data. Finding your first job can be challenging if you want to work as a software developer. Getting an interview involves a number of criteria.

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Answer:

Option 2, In seismic areas, the most crucial requirement for precast concrete is to tie elements together laterally

Explanation:

In seismic areas, the in-plane lateral  forces are very larger and hence in order to restrict the lateral movement governed by the lateral force, lateral ties are essential .

Specific design detailing such as interior and  perimeter ties in the floors causes diaphragm behavior and hence distribute the load evenly without any movement.

Hence, option 2 is correct

Answer:

pakipic na lang po question nyo para masagot po

Explanation:

please po di ko masyado gets po e

it is simple the title name after all it is just asking your name

The ratio of the induced EMF in the loop CDBC to the induced EMF in the loop CADC can be calculated as follows:

ecdbc/ecadc = -dΦ_cdbc/dt / (-dΦ_cadc/dt) = dΦ_cadc/dt / dΦ_cdbc/dt

Let's dive deeper into the details below

The induced EMF is the voltage generated by a changing magnetic field in a coil of wire. In a loop, the induced EMF is proportional to the rate of change of the magnetic flux that is threading the loop. Therefore, in a loop, the induced EMF can be calculated as:

induced EMF = -dΦ/dt, where Φ is the magnetic flux threading the loop.

We can assume that both loops are parallel to the surface and therefore perpendicular to the magnetic field. This means that the magnetic flux threading each loop is proportional to the area of the loop, as follows:

Φ_cadc = B A_cadc and Φ_cdbc = B A_cdbc

Therefore, the ratio of the induced EMF in the loop CDBC to the induced EMF in the loop CADC can be calculated as follows:

ecdbc/ecadc = dΦ_cadc/dt / dΦ_cdbc/dt = (B A_cadc)/dt / (B A_cdbc)/dt = A_cadc / A_cdbc

The answer is the ratio of the areas of the loops.

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Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.

Explanation:

Mass is the matter that makes up objects

Answer:

a) 397.89 ohm

b) attached below

c) 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

d)  0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

Explanation:

A) Find the appropriate resistor

c = 0.01 uf

fc = 40 kHz

cut-off frequency ; fo = \(\frac{1}{2\pi RC }\)

from the above equation  R = \(\frac{1}{2\pi foC}\)  = 397.89 ohm

B) sketch of the circuit  is attached

C) The gain of the filter at the cutoff frequency

fc = 40 kHz,  

C = 0.01 uF ⇒ \(\frac{-j}{2\pi foC }\) =  -j 397.89

Vout = Vin * ( R / R- C )

Vout = Vin * ( 397.89 / (397.89 - j 397.89))

Vout = \(\frac{1}{\sqrt{2} }\)  Vin ∠45⁰

therefore gain = |\(\frac{Vout}{Vin }\)| = \(\frac{1}{\sqrt{2} }\) = 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

D) Gain of filter at 55 kHz

c = 0.01 uF =  \(\frac{-J}{2\pi foC }\) =  -j 289.373 ohms

Vout = Vin * \(\frac{R}{R-C}\)  

        = Vin * ( 397.89 / ( 397.89 - j 289.373))

Gain in ratio \(|\frac{Vout}{Vin}|\) = 0.8087 ∠ 36.03⁰

therefore gain in ratio = 0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

The real length of 1 decametre is 10 meters or 1000 centimeters.

In the drawing, a line of 5 cm represents this length.

To find the RF (Representative Fraction), we can use the formula:

When it comes to combining multiple documents, an important word processing skill to know that ensures the final result is organized and easy to use is pagination.

Pagination is a page numbering technique that is done sequentially. These page numbers are usually located at the top or bottom of the web page. In most cases, it is used for main pages and partitions in corporate websites. This kind of design can generally make the user experience simpler on the site. They can also feel more comfortable when it comes to distributing and navigating products within the website.

For example, like this, imagine an e-commerce site that consists of hundreds of product catalogs from various categories. Of course, these products will not be found easily if only placed on one page. As a solution, UI developers and designers can take advantage of pagination to make product placement more structured.

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Answer:

The answer to this question can be defined as follows:

Explanation:

The sky driver began his sky journey from Arkansas, drove across the Tennessee River then landed in North Carolina. He returned to both the north in the very same direction. He began with NC, traveled through Tennessee, eventually lands in Arkansas. But North Carolina has been in the third state on which skydiver was traveling over, and It's also more than 700 miles from Arkansas to the NC.

Secondary enrichment is an important ore forming procedure. This process is known to be secondary because of the fact that in this case the valuable ore minerals do not directly precipitate from a cooling magma.

In this process ore deposits which are exposed to the ground surface, are weathered just as other rocks. When the ore minerals come in contact to the atmospheric oxygen, it gets oxidized and this oxidized forms are readily soluble in the water.

This solution with high concentration of many valuable materials start its journey downwards. As it gets down, it loses some of its dissolved materials in the surrounding areas and forms the Colorful oxidized zone below the surface.

As the solution leaks further downward and reaches the groundwater table the conditions suddenly changes from oxidizing to reducing. In this circumstances the dissolved materials in the leaking water precipitates and forms secondary sulfide deposits.

From the above discussion the points given in the question can be arranged in the following manner:

1) Igneous activity ceases after producing ore bearing deposits.

2) The bearing deposit cools entirely.

3) Groundwater flows through an ore deposit and leaches out material.

4) New ore minerals are precipitated in new locations.

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Answer:

Yes

Explanation:

In such a case, one way to check the credit charge is to contact your bank, doing so would allow the bank to check your account properly to determine where the transaction was originated from.

Another way you could check is to contact the online merchant where such a transaction was initiated.

Applying a second layer of hard wax while the first is setting is unnecessary and may cause skin irritation and damage.

When hard wax is applied to the skin, it adheres to both the hair and the skin. As it cools and hardens, it contracts and creates a tight grip on the hair, making it easy to remove. Applying a second layer of hard wax while the first is setting is unnecessary because the first layer will already have a strong grip on the hair. In fact, adding a second layer could cause skin irritation and damage because the wax will adhere even more strongly to the skin. It's important to wait until the first layer is completely set and then remove it before applying any additional wax.

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If the united states obtained all its energy from oil, 8.3 *10^12 liters oil would be needed each year.

=E (US) / E (oil)

= (10^20) / (1.2 * 10^7)

=8.3 *10^12 liters

Fossil fuel power plants use the heat produced by burning coal or oil to produce steam, which drives turbines to produce electricity.

A non-renewable energy source is oil. This implies that crude oil will eventually run out. Carbon dioxide gas is created by burning oil. This gas acts as a greenhouse and accelerates climate change.

Oil, coal, and natural gas are examples of non-renewable fossil energy resources that were created when extinct prehistoric plants and animals were progressively buried under layers of rock.

Chemical energy is the energy held in atom and molecule bonding. Chemical energy can be found in things like batteries, biomass, oil, natural gas, and coal.

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Answer:

This article deals with weight formula and its derivation. Weight refers to the force which acts on a body or object due to the effect of gravity. So, when an individual stands on a scale, the reading that appears is the weight. The more an individual weighs consequently means a higher reading on the scale. When an individual loses weight, he should think of it as lessening one’s force on the Earth due to gravity.

weight formula

What is Weight?

Simply speaking, weight refers to the force of gravity. Weight is certainly a force that acts on all bodies or objects at all times near a heavenly body such as the Earth. The Earth pulls all objects downward towards the center with a force of gravity. One can find the magnitude of the force of gravity by multiplying the magnitude of the acceleration due to gravity by the mass of the particular object.

Some books describe weight as a scalar quantity, the magnitude of the gravitational force. In contrast, some books refer to weight as a vector quantity, the gravitational force which acts on the object. Moreover, some experts explain weight as referring to the magnitude of the reaction force which is exerted on a body by various mechanisms. Also, these mechanisms keep the body in place.

The unit of measurement for weight is certainly that of force. This unit in the International System of Unit (SI) is the newton. The object with a mass of 1 kilogram would weigh about 9.8 Newtons on the Earth’s surface. Furthermore, it would weigh about one-sixth as much on the moon.

Weight Formula

The weight of an object or body certainly depends on the mass of the object and the gravity acting on it. This is why, the weight is different from mass. The mass of an object would be same whether on the Earth or on the Moon. The weight of an object due to the influence of gravity would be different on the Earth than on the Moon. The weight formula can be explained as follows:

Weight = mass × gravity

The formula for this is:

w = mg

Here we have,

w = weight

m = mass

g = gravity

Explanation:

Solution :

1. PL \($= \frac{11.53 - 10.49}{10.49 - 4.5} \times 100$\)

       = 17.36 %

2. Liquid limit at 25 number of blows,

  \($LL = \frac{(26-25)\times 49.8 + (25 - 2.17) \times 47.5}{26-17}$\)

       \($= 47.75 $\) %

Since 84 % of the passes the number 200 sieve the soil is immediately fine grained and MI, OI or CI because LL = 47.75 % > 35%

Therefore, the Plasticity index, PI  \($=47.75 - 17.36 = 30.39$\) %

Equation of A-line \($= 0.73 \times [47.75 - 20]$\)

                             \($=20.25 $\) %

Thus the soil lies above the A-line, that is soil is medium compressible clay ---- CI

Answer:

True

Explanation:

The most likely creep mechanism at high temperatures and low applied stresses is "dislocation motion (climb)". Option e is answer.

This mechanism involves the movement of dislocations through the lattice structure of a material, which leads to deformation or strain. When high temperatures and low applied stresses are present, the movement of dislocations through the lattice structure becomes the dominant mechanism for creep.

Other creep mechanisms such as crack propagation, grain boundary diffusion, and bulk diffusion are more likely to occur under different conditions such as low temperatures, high applied stresses, or in materials with specific microstructures. Understanding the dominant creep mechanism is important in designing and selecting materials for high-temperature applications where creep resistance is critical.

Option e is answer.

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Answer:

A pipe support or pipe hanger is a designed element that transfer the load from a pipe to the supporting structures. ... The four main functions of a pipe support are to anchor, guide, absorb shock, and support a specified load. Pipe supports used in high or low temperature applications may contain insulation materials.

The thing that happens when a capacitor is connected to a DC source is that Capacitors charge up until the voltage across the capacitor is equal to the externally applied voltage when they are linked across a direct current DC supply voltage.

Capacitors slowly charge in a DC circuit until the charging voltage of the capacitor is equal to the supply voltage. The capacitor will not permit any extra charges to travel through it after it has been fully charged.

Note that the link between a capacitor and voltage and current can be summarized as follows: the capacitance and the rate of rise or fall of the voltage determine how much current flows through a capacitor. A strong positive current will be produced through a capacitor if the voltage across the capacitor rises quickly.

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Answer:

A

Explanation:

Answer:

A

Explanation:

The fuse breaks the circuit if a fault in an appliance causes too much current to flow. The fuse contains a piece of wire that melts easily. If the current going through the fuse is too great,the wire heats up until it melts and breaks the circuit

Answer:

41.015

Explanation:

Solution

Given that:

Th first step to take is to find  the longitudinal stress in the cylinder

σl = PD/4t

P = the pressure

D = the diameter

t = the thickness

Thus,

σl = 1.25 * ^ 6 * 0.45 / 4 * 6 * 10 ^ ⁻3

=23.475Mpa

Now. we find the hoop stress in the cylinder∠

σh = PD/2t

σh = 1.25 * ^ 6 * 0.45/ 2 * 6 * 10 ^ ⁻3

σh  =46.875 Mpa

Then

we find the normal stress in the line of the 30° angle with the longitudinal axis stated below:

σab = σh + σl/2 + ( σh - σl/2) cos 2θ + t sin 2θ

So,

σab  =46.875 + 23.4375/2 + ( 46.875 - 23.4375/2) cos 2(30°) + 0

σab= 41.015

Therefore the normal stress to line A-B is 41.015