as a safety precaution, electric duct heaters should be wired so that they will not operate unless:
Answers
As a safety precaution, electric duct heaters should be wired so that they will not operate unless the proper interlocking mechanisms, such as airflow sensors and thermostat controls, are in place and functioning correctly. This ensures safe and efficient operation of the heaters while preventing potential hazards.
As a safety precaution, electric duct heaters should be wired so that they will not operate unless the airflow through the duct is present. This is achieved by connecting a current sensing switch to the fan motor circuit, which will cut off power to the duct heater if the fan motor fails or the airflow stops. This ensures that the heater will not overheat and cause a fire hazard.
As a safety precaution, electric duct heaters should be wired so that they will not operate unless the proper interlocking mechanisms, such as airflow sensors and thermostat controls, are in place and functioning correctly. This ensures safe and efficient operation of the heaters while preventing potential hazards.
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As a safety precaution, electric duct heaters should be wired so that they will not operate unless the "proper airflow is detected within the duct system".
Duct heaters are a crucial component of HVAC systems as they warm up the air before distributing it to different rooms in a property. Electrical duct heaters are the most widely used type, generating heat by passing an electric current through coils, which offer resistance. As air passes through the ducts, it absorbs the heat from the coils and is then directed into the rooms. Inline electric duct heaters can be utilized for a variety of heating applications, including primary, supplementary, and space heating.
This is done to prevent overheating and potential fire hazards.
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Related Questions
a dipole of moment p=Qa coul-m is aligned parallel to an electric field along the x axis. The field is non-uniform and varies in magnitude lineary along the x axis with a rate of change dE/dx=K. find the force on the dipole.
Answers
Answer:
F = Qa*K
Explanation:
The force on the dipole is expressed as the negative gradient of the potential energy.
Thus;
Force; F = -dU/dx
Now, the potential energy is given as;
U = -pE
So, dU/dx = -pdE/dx
Since F = -dU/dx
Then, F = p*dE/dx
We are given p = Qa
Then;
F = Qa(dE/dx)
We are given that dE/dx = K
Thus;
F = Qa*K
Taking the convection heat transfer coefficient on both sides of the plate to be 860 W/m2 ·K, deter- mine the temperature of the sheet metal when it leaves the oil bath. Also, determine the required rate of heat removal from the oil to keep its temperature constant at 45°C.
Answers
Answer:
Hello your question is incomplete attached below is the complete question
answer :
a) 95.80°C
b) 8.23 MW
Explanation:
Convection heat transfer coefficient = 860 W/m^2 . k
a) Calculate for the temp of sheet metal when it leaves the oil bath
first step : find the Biot number
Bi = hLc / K ------- ( 1 )
where : h = 860 W/m^2 , Lc = 0.0025 m , K = 60.5 W/m°C
Input values into equation 1 above
Bi = 0.036 which is < 1 ( hence lumped parameter analysis can be applied )
next : find the time constant
t ( time constant ) = h / P*Cp *Lc --------- ( 2 )
where : p = 7854 kg/m^3 , Lc = 0.0025 m , h = 860 W/m^2, Cp = 434 J/kg°C
Input values into equation 2 above
t ( time constant ) = 0.10092 s^-1
Determine the elapsed time
T = L / V = 9/20 = 0.45 min
∴ temp of sheet metal when it leaves the oil bath
= (T(t) - 45 ) / (820 - 45) = e^-(0.10092 * 27 )
T∞ = 45°C
Ti = 820°C
hence : T(t) = 95.80°C
b) Calculate the required rate of heat removal form the oil
Q = mCp ( Ti - T(t) ) ------------ ( 3 )
m = ( 7854 *2 * 0.005 * 20 ) = 26.173 kg/s
Cp = 434 J/kg°C
Ti = 820°C
T(t) = 95.80°C
Input values into equation 3 above
Q = 8.23 MW
3. Would you characterize yourself as a technophile or a Luddite? Explain, and use examples.
Answers
A technophile is someone who is enthusiastic and embraces technology, often seeing it as a positive force for progress and improvement in various aspects of life. Technophiles are usually eager to adopt new technologies and explore their potential benefits.
A technophile might be among the first to purchase and use the latest smartphones, gadgets, or smart home devices as soon as they are released.
Technophiles are more likely to embrace automation and artificial intelligence technologies in various domains, such as using voice assistants, self-driving cars, or home automation systems.
Technophiles tend to have an optimistic view of emerging technologies like virtual reality, augmented reality, blockchain, or autonomous robots, recognizing their potential benefits and actively exploring their applications.
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Determine the maximum stress in the bar if the bar is designed with grooves having semicircular portions of radius shown in the figure. (Round the final answer to one decimal place.) 10 mm, as 100 mm 150 mm 18 mm MPa The maximum stress in the bar is
Answers
The maximum stress in the bar is 118.2 MPa.
Given the following diagram: Given, the bar is designed with grooves having semicircular portions of radius: 10 mm, 100 mm, 150 mm, and 18 mm. From the above diagram, we can see that due to the application of force, the bar tends to bend as shown below: From the above diagram, it can be observed that there will be maximum stress at the topmost edge of the bar, i.e., at point A. The maximum stress (σ) in a beam is given by:σ = My/I, where, M is the maximum bending moment acting on the beam, and I is the moment of inertia of the beam's cross-sectional area about the neutral axis. Substituting the values of M and I from the above diagram, we get:σ = 15 × 120/(20 × 25³)σ = 118.2 MPaTherefore, the maximum stress in the bar is 118.2 MPa (approx).
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In a vehicle with front disc brakes, the vehicle pulls to the left when braking. What causes this?
A. Seized left brake caliper piston
B. Collapsed left brake line hose
Answers
One reason tombstones are rarely used is that each tombstone must persist to prevent the dangling pointer problem. We may be able to solve this problem by implementing garbage collection on the tombstones. If we do so, should we use reference counters or mark-and-sweep? Either argue that one method is superior to the other or argue that both methods are equally good (or equally poor).
Answers
Both reference counting and mark-and-sweep are widely used garbage collection techniques, and each has its own advantages and limitations.
The choice between the two depends on the specific requirements and constraints of the system. Let's examine the characteristics of both methods:
1. Reference Counting:
- Reference counting works by maintaining a count of the number of references to an object. When the count reaches zero, indicating that no references exist, the object can be safely deallocated.
- The main advantage of reference counting is its efficiency in reclaiming memory. Objects are deallocated immediately when their reference count reaches zero, which helps in minimizing memory usage.
- However, reference counting can be problematic in the presence of circular references, where objects reference each other in a cycle. In such cases, reference counting alone cannot reclaim memory, leading to memory leaks. Additional techniques, like cycle detection algorithms, are required to handle circular references.
2. Mark-and-Sweep:
- Mark-and-sweep is a tracing garbage collection algorithm that identifies and reclaims objects that are no longer reachable by traversing the object graph.
- One advantage of mark-and-sweep is its ability to handle circular references effectively. It can detect and collect objects involved in circular references as long as they are not reachable from the root set.
- Mark-and-sweep introduces a pause during garbage collection as it traverses the object graph, which may cause temporary interruptions in the execution of the program.
- Additionally, mark-and-sweep can lead to fragmentation of the memory space, as it collects objects based on reachability rather than compacting the memory.
Considering these aspects, it is difficult to definitively claim that one method is superior to the other in all scenarios. The choice between reference counting and mark-and-sweep depends on various factors, such as the nature of the application, memory usage patterns, performance requirements, and available resources.
In the context of tombstone management, both reference counting and mark-and-sweep can be viable options. Reference counting can be effective if the system does not involve circular references or if circular references can be handled separately. On the other hand, mark-and-sweep can handle circular references but may introduce some pause time during garbage collection.
Ultimately, the decision should be based on careful analysis of the specific requirements, constraints, and trade-offs of the system at hand. It may even be possible to combine elements of both techniques or utilize alternative garbage collection algorithms tailored to the tombstone management needs of the system.
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43) According to kinetic-molecular theory, if the temperature of a gas is raised from 100°C to 200°C, the average kinetic energy of the gas will
A) double
B) increase by a factor of 1.27
C) increase by a factor of 100
D) decrease by half
E) decrease by a factor of 100
Answers
A) double
According to the kinetic-molecular theory, the temperature of a gas is a measure of the average kinetic energy of the gas molecules. The kinetic energy of a molecule is the energy it possesses due to its motion. As the temperature of a gas increases, the average kinetic energy of the molecules increases.
If the temperature of a gas is raised from 100°C to 200°C, the average kinetic energy of the molecules will double. This is because the temperature increase is a 100% increase, and the average kinetic energy of the molecules will also increase by 100%.
It is important to note that this is only true if the volume and number of molecules in the gas are held constant. If the volume or number of molecules changes, the relationship between temperature and average kinetic energy may be different.
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You have a piece of film paper that is 3 in x 5 in. You fix it inside the back of a pinhole camera with a focal length of 5.5 in. You want to use it to take a picture of your team’s mascot – a giant guinea pig that just barely fits in a 4 ft. tall cube. The picture will be taken directly in front, from a stool that places the aperture 2 ft. above the ground. You have to determine how far away the camera must be from your mascot to get a good portrait that fills up the whole film paper, without cutting any part of him off. How far apart should the camera and the mascot be to take the portrait? Show your work.
Answers
Answer:
In order to take a portrait, the distance of the mascot from the camera should be approximately 7.33 feet
Explanation:
The size of the film paper = 3 in. × 5 in.
The focal length of the camera = 5.5 in.
The height and width of the guinea pig = 4 ft.
The height of the aperture above the ground = 2 ft.
Therefore, we have;
Magnification = Height of image/(Height of object)
Withe the 3 in. wide film, we have;
Magnification = 3 in./(4 ft.) = 3 in./(48 in.) = 0.0625
Magnification = Length of camera/(Distance of object from pin hole)
∴ Length of camera/(Distance of object from pin hole) = 0.0625
Length of camera = Focal length of the camera = 5.5 in.
Therefore;
5.5 in./(Distance of object from pin hole) = 0.0625
Distance of object from pin hole = 5.5/0.0625 = 88 inches = 7.33 ft
Therefore, the camera should be approximately 7.33 ft. from the mascot to take a portrait.
In this exercise we have to use the magnification knowledge to calculate the distance that the photograph should be taken, thus we have to:
Distance of the mascot from the camera should be approximately 7.33 feet
To calculate the best distance to take the photo, we have that some information must be taken into account such as:
Size of the film paper: \((3)*(5) in\) Focal length of the camera: \(5.5 in\) Height and width of the guinea pig: \(4 ft\) Height of the aperture above the ground: \(2 ft\)
Therefore, we have that the formula of magnification is:
\(Magnification = Height \ of \ image/(Height \ of \ object)\)
With the 3 in wide film, we have;
\(Magnification = 3 in/(4 ft) \\= 3 in/(48 in) = 0.0625 in\)
Rewriting the magnification formula as:
\(Magnification = Length \ of \ camera/(Distance \ of \ object \ from \ pin \ hole)\)
Substituting the values already known we have the equation will be matched as:
\(Length\ of \ camera/(Distance\ of\ object \ from \ pin \ hole) = 0.0625\\Length \ of \ camera = Focal \ length \ of \ the \ camera = 5.5 in.\)
Therefore;
\(5.5 /(Distance \ of \ object\ from \ pin\ hole) = 0.0625 in\\Distance \ of \ object\ from \ pin \ hole = 5.5/0.0625\\ = 88 inches = 7.33 ft\)
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when servicing piston rods and pins it is important to always
Answers
Answer:
Pistons should be inspected and measured.
Explanation:
Nec ________ covers selection of time-delay fuses for motor- overload protection.
Answers
Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
What article in the NEC covers motor overloads?Article 430 that is found in National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .
Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.
Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
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Which wheel alignment term describes the way that the front wheels align themselves with the rear wheels when the car is moving in straight line
Answers
Answer:
Thrust angle
Explanation:
The term that describes the way that the front wheels align themselves with the rear wheels when the car is moving in a straight line is called "thrust angle."
Thrust angle refers to the angle between the geometric centerline of the rear axle and the centerline of the vehicle. When a vehicle is properly aligned, the thrust angle should be parallel to the vehicle's centerline, which ensures that the front wheels are also aligned with the rear wheels and the vehicle moves in a straight line.
However, if the thrust angle is not properly aligned, the front wheels will not track straight ahead and the vehicle may pull to one side or the other. In these cases, a wheel alignment service may be necessary to adjust the thrust angle and ensure proper alignment.
For a telephone line, if an input signal power is measured as 0.5 W, and the noise level is measured as 4.5μW. Calculate the signal-to-noise ratio in dB ?
Answers
In a telephone line, if an input signal power is measured as 0.5 W, and the noise level is measured as 4.5μW. the signal-to-noise ratio is approximately 80.46 dB.
To calculate the signal-to-noise ratio (SNR) in decibels (dB), you can use the following formula:
SNR (dB) = 10 * log10(Signal Power / Noise Power)
First, convert the power values to the same unit, such as watts or microwatts:
Signal Power = 0.5 W
Noise Power = 4.5 μW = 4.5 * 10⁻⁶ W
Now, substitute the values into the formula:
SNR (dB) = 10 * log10(0.5 : 4.5 * 10⁻⁶)
SNR (dB) = 10 * log10(1.1111 * 10⁸)
Then, evaluate the logarithm:
SNR (dB) = 10 * 8.0458
Finally, calculate the result:
SNR (dB) ≈ 80.46 dB
Therefore, the signal-to-noise ratio is approximately 80.46 dB.
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What is the document used when there is a potential of fire
Answers
Answer:
A fire safety plan.
Explanation:
A fire safety plan is a detailed document that covers all aspects of fire safety for a specific building or property.
Key to the success of grid computing is a(n) _____ that acts as a grid leader and traffic monitor.
Answers
Key to the success of grid computing is a(n) central server that acts as a grid leader and traffic monitor.
What is grid computing?Grid computing refers to the use of widely dispersed computer resources. A computer grid is analogous to a distributed system that contains multiple files and non-interactive tasks. Grid computers, as opposed to traditional high-performance computing systems such as cluster computing, have each node configured to run a distinct job or application. Furthermore, grid computers are typically more diverse and geographically distributed than cluster computers (and hence not physically connected). Although a single grid may be dedicated to a specific application, grids are frequently used for a variety of purposes. Grids are frequently built using software libraries for general-purpose grid middleware. Grid sizes are available in a variety of sizes.To learn more about Grid computing, refer to:
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Write a program that computes the square footage of a house given the dimensions of each room.Have the program ask the user how many rooms in the house and then request the dimensions of eachroom. Display the resulting total square footage.
Answers
int main () {
printf("Program to calculate the square footage of the house.\n");
int total_rooms;
double length, width;
double total_square_footage = 0.0;
printf("Enter total number of rooms in the house:");
scanf("%d", &total_rooms);
for (int i = 0; i
printf("Enter the lenght and width of room %d: ", i+1);
scanf("%if %if", &lenght, &width);
total_square_footage += lenght*width;
}
printf("Total square footage of the house: %if\n", total_square_footage);
return 0;
}
Please mark it as brainliest answer:).
Water flows around the vertical two-dimensional bend with circular streamlines and constant velocity as shown in Fig. P3.12. If the pressure is 40 kPa at point (1), determine the pressures at points (2) and (3). Assume that the velocity profile is uniform as indicated. (3) V=10m/s Figure P3.12
Answers
Without a visual representation of Figure P3.12, it is difficult to provide a detailed answer to the problem. However, I can provide some general information about fluid flow around a bend and how pressure varies in such a flow.
When a fluid flows around a bend, the fluid particles experience a centripetal acceleration due to the curvature of the path. This acceleration causes a pressure gradient in the fluid, with higher pressure on the outer side of the bend and lower pressure on the inner side of the bend. This pressure gradient causes the fluid to continue flowing along the curved path.The magnitude of the pressure gradient depends on various factors such as the fluid velocity, the radius of curvature of the bend, and the density and viscosity of the fluid.
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what is the most common type of suspensions system used on body over frame vehicles?
Answers
Answer:
Engine
Explanation:
Semi-independent suspension is the most common type of suspension system used on body over frame vehicles.
What is a Semi-independent suspension?Semi-independent suspension give the front wheels some individual movement.
This suspension only used in rear wheels.
Thus, the correct option is Semi-independent suspension
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an analysis used for one discrete independent variable with four levels, and one continuous dependent variable:
Answers
A suitable analysis for one discrete independent variable with four levels and one continuous dependent variable would be a one-way analysis of variance (ANOVA) .It allows for the comparison of means across the different levels and provides statistical evidence of any significant differences observed.
ANOVA is used to determine whether there are any significant differences between the means of two or more groups. In this case, the four levels of the discrete independent variable represent the different groups or categories being compared, while the continuous dependent variable represents the measurement or outcome being assessed.
By conducting a one-way ANOVA, we can assess whether there are any significant differences in the mean values of the continuous dependent variable across the four levels of the independent variable. The ANOVA analysis will provide an F-statistic, p-value, and potentially other relevant statistics that help determine the significance of the observed differences.
If the p-value is below a predetermined significance level (usually 0.05), it suggests that there are significant differences between at least two of the groups. In such cases, additional post-hoc tests, such as Tukey's Honestly Significant Difference (HSD) test, can be conducted to identify which specific groups differ significantly from each other.
Overall, a one-way ANOVA is an appropriate analysis to examine the relationship between a discrete independent variable with four levels and a continuous dependent variable. It allows for the comparison of means across the different levels and provides statistical evidence of any significant differences observed.
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what is the division of demand
Answers
Thinking Critically and Solving Problems
Posttest
Which step comes first in the decision making process?
A) Analyze the actions.
B) Collect information.
C) List all possible actions.
D) Identify the problem.
G
Submit
Answers
D) Identify the problem step comes first in the decision-making process.
What is decision-making?In psychology, decision-making (also spelled decision making and decisionmaking) is regarded as the cognitive process resulting in the selection of a belief or a course of action among several possible alternative options. It could be either rational or irrational. The decision-making process is a reasoning process based on assumptions of values, preferences and beliefs of the decision-maker. Every decision-making process produces a final choice, which may or may not prompt action. Research about decision-making is also published under the label problem solving, particularly in European psychological research. Decision-making can be regarded as a problem-solving activity yielding a solution deemed to be optimal, or at least satisfactory. It is therefore a process which can be more or less rational or irrational and can be based on explicit or tacit knowledge and beliefs. Problem solving and critical thinking refers to the ability to use knowledge, facts, and data to effectively solve problems.
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Give an example of one technology that is well matched to the needs of the environment, and one technology that is not.
Answers
Answer:
oh god... i have no idea lm.ao
Explanation:
A data bus can be visualized as a multilane highway
A. and each component is located at an intersection where it will turn or go straight
B. with each component having an individual address
C. and each component located in a curve where the data will slow down
D. with each component acting as a traffic light, stop-go
Answers
Answer:
B. with each component having an individual address
Explanation:
Data bus is a system within a computer or device, consisting of a connector or set of wires, that provides transportation for data. Data bus needs an address unique to each component in order to deliver the right data to the right place. Every memory location has a unique binary address. A microprocessor architecture is mainly composed of two main buses: The data bus and the address bus.
When the pressure relief valve in a system opens during work
Answers
Answer:
The relief valve will open as pressure caused by a downstream load or backpressure increases high enough to force the poppet or spool open against its spring.
Explanation:
A counterflow heat exchanger operating at steady state has water entering as saturated vapor at 1 bar with a mass flow rate of 2 kg/s and exiting as saturated liquid at 1 bar. Air enters in a separate stream at 300 K, 1 bar and exits at 335 K witha negligible change in pressure. Heat transfer between the heat exchanger and its surroundings is negligible. Determine (a) the change in the flow exergy rate of each stream, in kW. (b) the rate of exergy destruction in the heat exchanger, in kW. Ignore the effects of motion and gravity. Let To 300 K,P) 1 bar.
Answers
Flow exergy rate = mass flow rate * (specific exergy + kinetic exergy + potential exergy)
Exergy destruction rate = (T_hot - T_cold) * (entropy generation rate)
where T_hot and T_cold are the hot and cold stream temperatures, respectively, and entropy generation rate can be calculated using the following equation:
Entropy generation rate = (heat transfer rate / T_hot) - (heat transfer rate / T_cold)
Given:
- Water enters at 1 bar as saturated vapor with a mass flow rate of 2 kg/s and exits as saturated liquid at 1 bar.
- Air enters at 300 K, 1 bar and exits at 335 K with negligible change in pressure.
- Heat transfer between the heat exchanger and its surroundings is negligible.
Assumptions:
- Negligible effects of motion and gravity.
- Negligible changes in kinetic and potential energy.
(a) Change in flow exergy rate:
For water:
- Inlet: The specific enthalpy and specific entropy of saturated vapor at 1 bar can be found from the steam tables to be h_in = 2776.1 kJ/kg and s_in = 7.3607 kJ/(kg*K), respectively. The specific volume can be found using the ideal gas law to be v_in = R_w*T_in/p_in = 0.2968 m^3/kg, where R_w is the specific gas constant for water vapor.
- Exit: The specific enthalpy and specific entropy of saturated liquid at 1 bar can be found from the steam tables to be h_out = 419.06 kJ/kg and s_out = 1.3043 kJ/(kg*K), respectively. The specific volume can be found using the tables to be v_out = 0.001043 m^3/kg.
- Flow exergy rate change: Using the equation above, we can find the change in flow exergy rate for water to be ΔE_dot_water = m_dot_water*(h_out + v_out*(P_0-P_in) - h_in - v_in*(P_0-P_in)) = 2*(419.06 + 0.001043*(1-1)*(10^5-1) - 2776.1 - 0.2968*(1-1)*(10^5-1)) = -5284.8 kW, where P_0 is the reference pressure of 1 bar.
For air:
- Inlet: The specific enthalpy and specific entropy of air at 300 K and 1 bar can be found from the air tables to be h_in = 301.27 kJ/kg and s_in = 1.9745 kJ/(kg*K), respectively. The specific volume can be found using the ideal gas law to be v_in = R_a*T_in/p_in = 0.8251 m^3/kg, where R_a is the specific gas constant for air.
- Exit: The specific enthalpy and specific entropy of air at 335 K and 1 bar can be found from the tables to be h_out = 331.46 kJ/kg and s_out = 2.1619 kJ/(kg*K), respectively. The specific volume can be found using the ideal gas law to be v_out = 0.9076 m^3/kg.
- Flow exergy rate change: Using the equation above, we can find the change in flow exergy rate for air to be ΔE_dot_air = m_dot_air*(h_out + v_out*(P_0-P_out) - h_in - v_in*(P_0-P_in)) = 2*(331.46 + 0.9076*(1-1)*(10^5-1) - 301.27 - 0.8251*(1-1)*(10^5-1)) = 618.5 kW, where P_out is the pressure at the exit of the heat exchanger.
Therefore, the change in flow exergy rate is -5284.8 kW for water and 618.5 kW for air.
(b) Rate of exergy destruction:
Using the entropy generation rate equation above, we can find the entropy generation rate for the heat exchanger to be:
S_gen = (Q_dot/T_hot) - (Q_dot/T_cold) = (m_dot_air*Cp_air*(T_out_air-T_in_air)/T_hot) - (m_dot_water*Cp_water*(T_out_water-T_in_water)/T_cold)
where Cp_air and Cp_water are the specific heat capacities of air and water, respectively, and T_in_air, T_out_air, T_in_water, and T_out_water are the inlet and outlet temperatures of air and water, respectively.
We know that the heat transfer rate Q_dot is the same for both fluids, so we can write:
S_gen = (Q_dot/T_hot) * (Cp_air*(T_out_air-T_in_air) - Cp_water*(T_out_water-T_in_water)/T_cold)
Substituting the given values, we get:
S_gen = (Q_dot/300) * ((1.005*(335-300)) - (4.179*(100-0)) / 373)
S_gen = 0.0145*Q_dot
where Cp_air = 1.005 kJ/(kg*K), Cp_water = 4.179 kJ/(kg*K), T_hot = 300 K, T_cold = 373 K, and Q_dot is the heat transfer rate.
The rate of exergy destruction is equal to the entropy generation rate multiplied by the average temperature, which is (T_hot + T_cold)/2 = 336.5 K, so we have:
ΔE_dot_dest = S_gen*(T_hot + T_cold)/2 = 0.0145*Q_dot*336.5
Substituting the given values, we get:
ΔE_dot_dest = 0.0145*Q_dot*336.5 = 0.0145*Q_dot*336.5 = 63.9 kW
Therefore, the rate of exergy destruction in the heat exchanger is 63.9 kW.
A house is maintained at 1 atm and 248C, and warm air inside a house is forced to leave the house at a rate of 150 m^3/h as a result of outdoor air at 58C infiltrating into the house through the cracks. Required:
Determine the rate of net energy loss of the house due to mass transfer.
Answers
The house is losing 186 J of energy per second due to the combined effects of warm air leaving and cool air entering.
To solve the problem, we need to calculate the rate of heat loss due to the infiltration of outdoor air. We can do this using the heat transfer equation:
Q = hAΔT
where Q is the heat transfer rate, h is the convective heat transfer coefficient, A is the area of the crack, and ΔT is the temperature difference between the indoor and outdoor air.
Assuming a heat transfer coefficient of 10 W/m^2K and an average crack area of 0.1 m^2, we have:
Q = 10 x 0.1 x (248-58) = 1800 W
This means that the house is losing 1800 J of energy per second due to the infiltration of outdoor air.
To convert this to a rate of net energy loss, we need to factor in the rate of warm air leaving the house. The heat capacity of air at constant pressure is approximately 1 kJ/kgK, so the rate of energy loss due to mass transfer is:
E = (150 m^3/h) x (1.225 kg/m^3) x (1000 J/kgK) x (248 - 58) K/3600 s/h = 1986 W
This means that the net energy loss rate of the house due to mass transfer is: 1986 - 1800 = 186 W
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A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print: 1. The printer's electronic circuits must be energized. 2. Paper must be loaded and ready to advance. 3. The printer must be "on line" with the microprocessor. As each of the above conditions is satisfied, a HIGH is generated and applied to a 3-input logic gate. When all three conditions are met, the logic gate produces a HIGH output indicating readiness to print. The basic logic gate used in this circuit would be an): A) NOR gate. B) NOT gate. C) OR gate. D) AND gate.
Answers
Answer:
D) AND gate.
Explanation:
Given that:
A certain printer requires that all of the following conditions be satisfied before it will send a HIGH to la microprocessor acknowledging that it is ready to print
These conditions are:
1. The printer's electronic circuits must be energized.
2. Paper must be loaded and ready to advance.
3. The printer must be "on line" with the microprocessor.
Now; if these conditions are met the logic gate produces a HIGH output indicating readiness to print.
The objective here is to determine the basic logic gate used in this circuit.
Now;
For NOR gate;
NOR gate gives HIGH only when all the inputs are low. but the question states it that "a HIGH is generated and applied to a 3-input logic gate". This already falsify NOR gate to be the right answer.
For NOT gate.
NOT gate operates with only one input and one output device but here; we are dealing with 3-input logic gate.
Similarly, OR gate gives output as a high if any one of the input signals is high but we need "a HIGH that is generated and applied to a 3-input logic gate".
Finally, AND gate output is HIGH only when all the input signal is HIGH and vice versa, i.e AND gate output is LOW only when all the input signal is LOW. So AND gate satisfies the given criteria that; all the three conditions must be true for the final signal to be HIGH.
a coiled spring is stretched 31.50 cm by a 2.00N weight. How far is it stretched by a 10.00 N weight?
Answers
K = 2/0.315 =6.35 N/m
x = 10/6.35 = 1.57m
Segments ab and cd of the assembly are solid circular rods, and segment bc is a tube. If the assembly is made of 6061-t6 aluminum, determine the displacement of end d with respect to end a.
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The displacement of end D with respect to end A is \(-0.488 \times 10^{-3}\;m\)
Given the following data:
Length = 435 mm to m = 0.435 meter.Modulus of elasticity = 68.9 GPa.Radius A = 20 mm to m = 0.03 meter.Inner radius BC = 30 mm to m = 0.03 meter.Outer radius BC = 40 mm to m = 0.04 meter.Force A = 10 kN.Force B = 15 kN.To determine the displacement of end D with respect to end A:
How to calculate the displacement.First of all, we would do a sectional cut of the circular rods at point A and then determine the sum of forces acting on it:
\(\sum F=0\\\\ 10000+N_1=0\\\\N_1 = -10000\;N\)
Mathematically, the displacement of a circular rod is given by this formula:
\(d = \frac{NL}{AE}\)
Where:
N is the normal force.L is the length.A is the area.E is the modulus of elasticity.Substituting the given parameters into the formula, we have;
\(d_1 = \frac{-10000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_1 = \frac{-4350}{0.0003142 \times 68.9 \times 10^9}\\\\d_1 =-0.201 \times 10^{-3}\;meter\)
For section cut BC:
\(\sum F=0\\\\ 10000-20000+N_2=0\\\\N_2 = 10000\;N\)
\(radius = outer\;radius^2 - inner\;radius^2\\\\radius = 0.04^2 -0.03^2=0.0007\;m\)
\(d_2 = \frac{10000 \times 0.435}{\frac{3.142 \times 0.0007^2}{4} \times 68.9 \times 10^9} \\\\d_2 = \frac{4350}{0.00054985 \times 68.9 \times 10^9}\\\\d_2 =0.115 \times 10^{-3}\;meter\)
For section cut D:
\(\sum F=0\\\\ -20000-N_3=0\\\\N_3 =- 20000\;N\)
\(d_3 = \frac{-20000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_3 = \frac{-8700}{0.0003142 \times 68.9 \times 10^9}\\\\d_3 =-0.402 \times 10^{-3}\;meter\)
For the total displacement:
The total displacement is equal to the displacement of end D with respect to end A.
\(d_T = d_1 +d_2+d_3\\\\d_T = -0.201 \times 10^{-3} + 0.115 \times 10^{-3}-0.402 \times 10^{-3}\\\\d_T = -0.488 \times 10^{-3}\;m\)
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technician a says that two 120-ohm resistors in series will measure 240 ohms, using an ohmmeter. technician b says that two 120-ohm resistors in parallel will measure 60 ohms, using an ohmmeter. who is correct?
Answers
Technician A and technician B are both incorrect. When two 120 ohm resistors are placed in series, their total resistance can be calculated by adding the individual resistances, which gives a total resistance of 240 ohms
\((120 ohms + 120 ohms)\).
However, an ohmmeter would not be used to measure the resistance of resistors in series; rather, the resistance is calculated using Ohm's Law.
When two 120 ohm resistors are placed in parallel, the total resistance can be calculated using the following formula:
\(1/Rt = 1/R1 + 1/R2\)
where Rt is the total resistance and R1 and R2 are the individual resistances.
Substituting the given values, we get:
\(1/Rt = 1/120 + 1/1201/Rt = 2/120Rt = 60 ohms\)
Therefore, technician B is correct about the resistance of two 120 ohm resistors in parallel being 60 ohms. However, neither technician A nor B is correct about using an ohmmeter to measure the resistance of resistors in series. An ohmmeter is used to measure the resistance of individual resistors, not resistors in series or parallel.
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what does a convective outlook (ac) describe for a following 24 hour period?
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A convective outlook (AC) is a forecast issued by the National Weather Service that describes the potential for thunderstorm development and severe weather in a specific region over a 24-hour period.
The outlook takes into account various atmospheric factors such as instability, moisture, and wind shear to assess the likelihood of thunderstorms and severe weather. The outlook is designed to help the public and emergency management personnel prepare for potential severe weather events.
The outlook considers various meteorological factors, including atmospheric instability, moisture availability, wind shear, and lift mechanisms, to assess the potential for convective storms. These factors are analyzed to determine the overall risk of severe weather within a defined geographical area.
The AC also includes a graphic representation of the outlook, often displayed as a color-coded map, with delineated areas of interest and associated risk levels. This map helps users, including emergency managers, meteorologists, and the general public, to easily identify the areas most likely to experience severe weather.
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