The time at which the amount of honey in the hive is the most, and the corresponding maximum value, can be determined by finding the maximum point of the function h(t) over the first 2 years.
To find the maximum point, we need to analyze the rate of change of h(t). We can start by calculating the derivative of the function h(t) with respect to time (t). Let's denote the derivative as h'(t).
Once we have the derivative, we can set it equal to zero and solve for t to find the critical points of the function. In this case, the critical points represent the times when the rate of honey production is neither increasing nor decreasing.
Finally, we evaluate the function h(t) at the critical points and identify the time t at which the amount of honey in the hive is the most, which corresponds to the maximum value of h(t).
By analyzing the function h(t), we can see that it represents the rate of honey production over time. To determine the exact nature of the function h(t) and obtain the maximum value, we would need the specific form of the function or additional information about the rate of honey production. Without this information, it's challenging to provide a precise answer.
In summary, to find the time at which the amount of honey in the hive is the most and the maximum value, we need the function h(t) that describes the rate of honey production over time. Without this specific information, it is not possible to calculate the maximum point.
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HELP PLEASE (CIRCLES) (40 points)
the line 3y - x = 5 is the tangent to a circle at the point A(1,2). (1) Find the equation of the line passing through A and the centre of the circle. The equation of another line passing through the centre of the circle is x + 3y = 15. (2) Find the equation of the circle.
Answer:
x² + (y - 5)² = 10Step-by-step explanation:
Tangent line is:
3y - x = 5 ⇒ 3y = x + 5 ⇒ y = 1/3 x + 5/3, the slope is 1/3Perpendicular line to this has a slope of -3 and passes through point (1, 2).
Its equation is:
y - 2 = -3(x - 1) ⇒ y = -3x + 3 + 2 ⇒ y = -3x + 5Using the second line passing through the center, find the coordinates of the center:
x + 3y = 15 ⇒ 3y = -x + 15 ⇒ y = -1/3x + 5Solve the system by elimination:
-3x + 5 = -1/3x + 5 ⇒ x = 0Then
y = 5The center is (0, 5) and radius is the distance from center to point (1, 2):
r² = (0 - 1)² + (5 - 2)² = 1 + 9 = 10The equation of circle:
(x - h)² + (y - k)² = r²(x - 0)² + (y - 5)² = 10 ⇒ x² + (y - 5)² = 10how many ways are there to roll 5 distinct (6-sided) dice and get 3 of a kind? (three dice will show the same number, one die will show a different number, and one die will show yet g
Number of ways to roll 5 distinct dice and get 3 of a kind is 7200
To find the number of ways to roll 5 distinct dice and get 3 of a kind:
Choose which number appears three times. There are 6 possible choices.
Choose which three dice will show the chosen number. There are 5 ways to choose the first die, 4 ways to choose the second die, and 3 ways to choose the third die, for a total combinations 5 x 4 x 3 = 60 ways.
Choose the numbers that the remaining two dice will show. There are 5 choices for the first die and 4 choices for the second die, but the order in which we choose them doesn't matter, so we need to divide by 2 to correct for overcounting. This gives us (5 x 4) / 2 = 10 ways.
Choose which of the two remaining dice will show the first chosen number. There are 2 choices.
Multiply all of the choices together: 6 x 60 x 10 x 2 = 7,200.
Therefore, there are 7,200 ways to roll 5 distinct dice and get 3 of a kind.
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If log (100ab^2) is expressed as a function of log b, the result would be:
1). 2 log a + 2 log b
2). 100 log a + 2 log b
3). 2 + log a + 2 log b
4). 2 + 2 log a + 2 log 6
Answer: Choice (3)
2 + log(a) + 2*log(b)
======================================================
Work Shown:
The log rules we'll use are
log(xy) = log(x)+log(y)log(x^y) = y*log(x)log(10) = 1, where the log is base 10So,
c = log(100ab^2)
c = log(100) + log(a) + log(b^2) ......... use log rule 1
c = log(10^2) + log(a) + log(b^2)
c = 2*log(10) + log(a) + 2*log(b) ......... use log rule 2
c = 2*1 + log(a) + 2*log(b) .................... use log rule 3
c = 2 + log(a) + 2*log(b)
Note: The use of rule 3 assumes that all logs shown are in base 10, which is the default assumed base. Rule 3 doesn't work for any general base. The more generalized rule is \(\log_b(b) = 1\). If b = 10, then we get rule 3 above.
Part C
Now that the first factors are grouped and the powers of 10s are grouped, multiply the first factors in the expression from part B. Then multiply
the powers of 10 by using the properties of exponents.
Answer:
The expression from part B is = (1 • 2) • (106 • 10-8).
Multiply the first factors.
1 • 2 = 2
Multiply the powers of 10 using this property of exponents: anam = an + m.
106 • 10-8 = 106 + (-8) = 10-2
The expression is 2 × 10-2.
Step-by-step explanation:
This is Plato and edmentumm sample response. Please paraphrase other wise you will get in trouble. I'm sorry if I'm late!
I have 20 mins to do this... If i dont finish I fail i have a C atm if I get a D i fail. PLZ HELP
Answer: Mean is 7 and median is 7
Step-by-step explanation:
2+6+3+10+9+8+10+6+6+10/10
=7
2,3,6,6,6,8,9,10,10,10
6+8/2
=7
Answer:
Terry= mean is 7, median is 7
David= mean is 4.4, median is 4
Step-by-step explanation:
I do not really understands what it means by compare them.
Find p(2) for the polynomial, p(x) = 3x (x - 2)
Answer:
p(2) = 0
Step-by-step explanation:
p(2) = 3(2)(2-2)
p(2) = 6(2-2)
p(2) = 6(0)
p(2) = 0
Solve for x. Round your answer to the nearest tenth.
9.2
X
16.5
Answer:
152
Step-by-step explanation:
Given f(x)=x²+2 and g(x)=-x-1, find (fog)(5) (Enter the answer to the nearest tenth.)
The composition (fog)(5) is equal to 38. We substitute 5 into g(x) to find g(5) = -6. Then, substituting -6 into f(x), we get f(-6) = 38.
To find (fog)(5), we need to substitute the value of 5 into g(x) and then use the resulting expression as the input for f(x).
Evaluate g(5)
We substitute x = 5 into g(x) to find g(5):
g(5) = -(5) - 1
g(5) = -6
Evaluate f(g(5))
Now that we know g(5) is equal to -6, we substitute -6 into f(x):
f(g(5)) = f(-6)
f(-6) = (-6)² + 2
f(-6) = 36 + 2
f(-6) = 38
Simplify the result
The final step is to simplify the result to the nearest tenth. In this case, the value is already a whole number, so we don't need to make any further adjustments. Therefore, (fog)(5) = 38.
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ASAP PLZ HELP I will give brainlyleist
Answer:what is the questionStep-by-step explanation:
11 Finding a difference quotient for a linear or quadratic function V Find the difference quotient f(x)=-3x²-2x+5 Simplify your answer as much as possible. f(x +h)-f(x) h f(x+h)-f(x) h = ( where h#0,
The difference quotient for the given function is 9 -2/h.
The difference quotient for the given function can be calculated as:
[f(x+h) - f(x)]/h
= [(3(x+h)² - 2(x+h) + 5) - (3x² - 2x + 5)]/h
= (3x² + 6xh + 3h² - 2x - 2h + 5 - 3x² + 2x - 5)/h
= (6xh + 3h² - 2h)/h
= (6x + 3h -2)/h
Simplifying the expression further, we get:
(6x + 3h -2)/h = 6 + 3h/h -2/h
= 6 + 3 -2/h
= 9-2/h
Therefore, the difference quotient for the given function is 9 -2/h.
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"Your question is incomplete, probably the complete question/missing part is:"
Find the difference quotient [f(x+h)-f(x)]/h, where h≠0, for the function below.
f(x)=3x² -2x+5. Simplify your answer as much as possible.
HELPPPPPPPPPPPPPPPPPPP!
Answer: Real, equal, rational.
Step-by-step explanation:
\(-x^2-8x-16=0\\-(x^2+8x+16)=0\\Multiply \ the\ left \ and\ right \ sides\ of\ the\ equation\ by \ -1:\\x^2+8x+16=0\\x^2+2*x*4+4^2=0\\(x+4)^2=0\\x+4=0\\x=-4.\)
The box plots display the same data for the number of crackers in each snack bag, but one includes the outlier in the data and the other excludes it. 4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21 number of crackers in each bag, with outlier a number line goes from 0 to 26. the whiskers range from 4 to 21, and the box ranges from 15 to 20. a line divides the box at 16. number of crackers in each bag, without outlier a number line goes from 0 to 26. the whiskers range from 14 to 21, and the box ranges from 15 to 20. a line divides the box at 17. which statement comparing the box plots is true? both the median and the range changed. both the range and the lower quartile changed. both the median and the interquartile range changed. both the interquartile range and the lower quartile changed.
Both the median and the range changed, the correct option is A.
What is the median?Median, in statistics, is the middle value of the given list of data, when arranged in an order.
The data set that contains the outlier is given as:
4, 14, 15, 15, 16, 16, 18, 19, 20, 20, 21
The minimum value of the data is: 4
The median or middle quartile i.e. \(\rm Q_2\) is the central tendency of the data and exists in the middle of the data.
The median is: 16
Also, the lower set of data is:
4,14,15,15,16
The lower quartile i.e. \(\rm Q_1\) is the median of the lower set of data.
The lower quartile i.e. \(\rm Q_1\) = 15
Similarly, the upper set of data is:
18, 19, 20, 20, 21
the upper quartile i.e. \(\rm Q_3\) is the median of the upper set of data.
upper quartile i.e. \(\rm Q_3\) = 20
Also, the interquartile range is:
\(\rm Q_3-Q_1=20-15=5\)
The maximum value of the set is 21.
Range = Maximum value-Minimum value =21 - 4 = 17
As we know that 4 is the outlier of the data as it is the smallest as compared to all the data points.
After removing the outlier the data set is:
14, 15, 15, 16, 16, 18, 19, 20, 20, 21
The minimum value of the set =14
The maximum value of set =21
Range = Maximum value-Minimum value =21-14 = 7
Hence, Both the median and the range changed.
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Find the volume of the sphere. Enter your exact answer in terms of π .
___ π cubic units
Answer:
2048/3 π cubic units
Step-by-step explanation:
You want the exact volume of a sphere with radius 8 units.
VolumeThe volume of a sphere is given by the formula ...
V = 4/3πr³
V = 4/3π(8³) = 2048/3·π . . . . cubic units
The volume of the sphere is 2048/3·π cubic units.
__
Additional comment
That's (682 2/3)π.
<95141404393>
Which of the following statements are equivalent to the implication, "if you win the lottery, then you will be rich," and which are equivalent to the converse of the implication? (a) Either you win the lottery or else you are not rich. (b) Either you don't win the lottery or else you are rich. (c) You will win the lottery and be rich. (d) You will be rich if you win the lottery. (e) You will win the lottery if you are rich. (f) It is necessary for you to win the lottery to be rich. (g) It is sufficient to win the lottery to be rich. (h) You will be rich only if you win the lottery. (i) Unless you win the lottery, you won't be rich. (j) If you are rich, you must have won the lottery. (k) If you are not rich, then you did not win the lottery. (1) You will win the lottery if and only if you are rich.
Equivalent to the original implication, "if you win the lottery, then you will be rich," are statements (d), (h), (j), and (1). Equivalent to the converse of the implication are statements (b), (e), (i), and (k).
The original implication states that winning the lottery leads to being rich. The equivalent statements are those that express the same relationship, while the converse of the implication reverses the order of the events.
Equivalent to the original implication:
(d) You will be rich if you win the lottery.
(h) You will be rich only if you win the lottery.
(j) If you are rich, you must have won the lottery.
(1) You will win the lottery if and only if you are rich.
Equivalent to the converse of the implication:
(b) Either you don't win the lottery or else you are rich.
(e) You will win the lottery if you are rich.
(i) Unless you win the lottery, you won't be rich.
(k) If you are not rich, then you did not win the lottery.
Not equivalent to either the implication or its converse:
(a) Either you win the lottery or else you are not rich.
(c) You will win the lottery and be rich.
(f) It is necessary for you to win the lottery to be rich.
(g) It is sufficient to win the lottery to be rich.
These statements do not capture the exact relationship between winning the lottery and being rich or its converse.
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Please I need help my teacher told me to do 3.14 x 81 but it’s wrong
well, let's take a looksie, hmm the sector is really a sector with a central angle of 90°, wait a second!! a circle has a total of 360°, so 90°+90°+90°+90° = 360°, so 90°is really just one quarter that of a circle.
Now, if we just get the whole area of the circle, then grab only one quarter of that, we'll be set, yeahhhh!!
\(\textit{area of a circle}\\\\ A=\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=9 \end{cases}\implies A=\pi (9)^2 \\\\\\ \stackrel{\textit{one quarter of that}}{\cfrac{1}{4}\cdot \pi (9)^2}\implies \cfrac{81\pi }{4}\implies \cfrac{81(3.14)}{4} ~~ \approx ~~ \text{\LARGE 63.6}\)
Find the value of x so that the function has the given value: g(x)= -10x,g(x)=15
Answer:
-25
Step-by-step explanation:
-10--25=15
A car tyre has a diameter of 60 cm.
How far will the wheel travel in one revolution?
Answer:
Step-by-step explanation:
If 60cm is the outer diameter of the rim, then the rim without a tire would travel 188.50 (not 188.4) cm per revolution. There will of course be a tire, and the extra diameter of wheel+tire will increase the distance traveled by the bike. If e.g. the tire is 3cm from bead to outermost tread (and is properly inflated), then the extra circumference would be 2 x 3cm x pi = 18.850cm of distance traveled, for a total of just over 207.3 cm per revolution.
I NEED HELP THIS IS DUE AT 11:59
Answer:
False I believe
Step-by-step explanation:
Point (w, z) is transformed by the rule (w 5, z) . what type of transformation occurred?
Scaling transformation onto the x co ordinate by a factor of 5.
What is a co-ordinate system ?A co-ordinate system represents two points one for x axis and another for y axis in a ordered pair (x,y)
According the given question Point (w, z) is transformed by the rule (w5, z).
Here w represents x co-ordinate points and z represents y co-ordinate points.
We can observe that the x co-ordinate point have been scaled by a factor of 5.We can think of that after this transformation the line has become less steeper from origin.
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"Find a curve y = y(x) through the point (1, −1) such that the
tangent to the curve at any point (x0, y(x0)) intersects the y-axis
at y = x0^3"
The final equation of the curve is y = -x + (1/2)x^3 - 2/3 log(x^3 - y) + 2/3 log(x^3) + 2/3.
To find a curve y = y(x) through the point (1, -1) such that the tangent to the curve at any point (x0, y(x0)) intersects the y-axis at y = x0^3, we can use the method of differential equations.
Let the curve be represented by y = f(x).
Then, the slope of the tangent line at any point (x0, y(x0)) on the curve is given by dy/dx evaluated at x = x0.
We know that the tangent line intersects the y-axis at y = x0^3.
Hence, the point of intersection is (0, x0^3).
The equation of the tangent line can be written in the point-slope form as follows: y - y(x0) = (dy/dx)|x
=x0 * (x - x0)
Using the point of intersection (0, x0^3),
we get: x0^3 - y(x0) =
(dy/dx)|x=x0 * (-x0)Simplifying the above equation,
we get: (dy/dx)|x=x0
= (y(x0) - x0^3) / x0
Now, we can write this equation in the differential form as follows: dy/dx = (y - x^3) /x Integrating both sides of the above equation, we get
∫[1, x] dy / (y - x^3)
= ∫[1, x] dx / x
Using partial fractions, we can write the left-hand side as follows:
A / (y - x^3) + B / y = 1 / x
Multiplying both sides by xy(y - x^3),
we get: Axy + Bxy - Bx^3
= y - x^3
Solving for A and B, we get:
A = 1 / x^3 and B = -1 / (x(x^3 - y))
Hence, we get the following integral equation:∫[-1, y] dy / (y - x^3) + ∫[1, x] dx / x = 0
Solving the above equation for y, we get: y = -x + Cx^3 - 2/3 log(x^3 - y) + 2/3 log(x^3) + 2/3
where C is a constant of integration. Using the initial condition y(1) = -1,
we get:C = -1/2
Hence, the equation of the curve is:y = -x + (1/2)x^3 - 2/3 log(x^3 - y) + 2/3 log(x^3) + 2/3: We started by assuming that the curve can be represented by y = f(x).
Then, we used the fact that the slope of the tangent line at any point (x0, y(x0)) on the curve is given by dy/dx evaluated at x = x0.
We know that the tangent line intersects the y-axis at y = x0^3. Hence, the point of intersection is (0, x0^3).Using the point-slope form of the equation of a line, we derived an expression for the slope of the tangent line at any point (x0, y(x0)).
Then, we used this expression to write the differential equation dy/dx = (y - x^3) / x that the curve must satisfy.
We then integrated both sides of this equation to obtain the integral equation ∫[-1, y] dy / (y - x^3) + ∫[1, x] dx / x = 0. Solving this equation for y, we obtained the equation of the curve. Using the initial condition y(1) = -1, we determined the constant of integration C.
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Which of the following statements are true? There may be more than one correct statement; check all that are true. a) The t distribution is a discrete probability distribution. b) The t distribution tends toward the standard normal distribution as the degrees of freedom increase. c) The t distribution is right skewed unless the degrees of freedom are very large. d) A random variable that has a t distribution cannot take on negative values.
Explanation:
Let's go over the possible choices to see which statements are true and which are false.
a) This is false. The T distribution is continuous.b) This is true. When n > 30, the T distribution looks a lot like the standard normal Z distribution. The difference between the two becomes negligible. This is why you're able to use the Z distribution if n > 30, even if you don't know sigma.c) This is false. The T distribution is symmetric for any degrees of freedom value.d) This is false. Negative values are possible in a T distribution.To summarize, only choice B is true. The rest are false.
find (f•g) (k) equations in red letters
The answer is (f . g)(x) = - (34k + 17k⁷ + 17k⁵ + 40k³ + 20k² + 60).
Remember that :
(f . g)(x) = f(x) × g(x)
Hence :
(f . g)(x) = (2k³ + k² + 3)(-17k⁵ - 20)(f . g)(x) = -34k⁸ - 17k⁷ - 17k⁵ - 40k³ - 20k² - 60(f . g)(x) = - (34k + 17k⁷ + 17k⁵ + 40k³ + 20k² + 60)Can you solve?
|x+5|=12
What is the answer please
The local animal shelter had 18 dogs atthe beginning of the week. Since then, thenumber of dogs at the shelter has decreasedby 6. What is the percent change in thenumber of dogs at the animal shelter thisweek?
at initial the number of dogs were , 18 dogs
final number of dogs is 18 - 6 = 12
so the percentage change is
\(\begin{gathered} =\frac{6}{18}\times100 \\ =33.33 \end{gathered}\)so the change is 33.33%.
Find the midpoint of the segment with the following endpoints.
(-3,5) and (0, -1)
among the six who are taking the test for the first time. (a) What kind of a distribution does X have (name and values of all parameters)? nb(x;6, 18
8
)
h(x;6,8,18)
h(x;6, 18
8
)
b(x;6, 18
8
)
b(x;6,8,18)
nb(x;6,8,18)
(b) Compute P(X=2),P(X≤2), and P(X≥2). (Round your answers to four decimal places.) P(x=2)=1
P(x≤2)=1
P(x≥2)=
(c) Calculate the mean value and standard deviation of X. (Round your answers to three decimal places.) mean individuals standard deviation individuals
The distribution for X is a negative binomial distribution, denoted as nb(x;6, 188), with parameters r = 6 (number of successes), p = 8/18 (probability of success in each trial).
To compute the probabilities:
P(X = 2): nb(2;6, 8/18)
P(X ≤ 2): nb(0;6, 8/18) + nb(1;6, 8/18) + nb(2;6, 8/18)
P(X ≥ 2): 1 - P(X < 2) = 1 - P(X ≤ 1)
To calculate the mean value and standard deviation of X:
Mean (μ) = r * (1 - p) / p
Standard Deviation (σ) = sqrt(r * (1 - p) / (p^2))
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The table below shows the linear relationship between the number of people at a picnic and the total cost of the picnic.
95% as a real number
how many possibilities are there if you toss coin 7 times
each toss results in 2 possible outcomes, head or tail so the number of possible outcomes for 7 would be
Answer:
2^7
2x2x2x2x2x2x2 = 2^7
solve 2+2x4
O 16
O 13
O 12
O 15
Answer:
the answer is 16 hahaha