As a falling rocket plunges toward the event horizon, an observer in the orbiting rocket would see that the falling rocket ______.

Explanation:

a) To solve this question we need to know that the molar volume occupied by any gas at STP is equal to 22.4 L/mol.

So in this case we have the following reaction:

2 NO(g) + O2(g) → 2 NO2(g)

The stoichiometric ratio between NO and O2 is 2:1.

If we have 150 mL of NO, we can find the value into moles using the molar volume:

22.4 L ---- 1 mol

0.150 L ---- x mol

x = 0.150/22.4

x = 6.7 x 10^-3 moles NO

using the stoichiometric ratio between NO and O2 we can find the quantity on moles of O2:

2 moles of NO --- 1 mole of O2

6.7 x 10^-3 moles NO ---- x mole of O2

x = 3.3 x 10^-3 moles of O2

Now let's transform to liters:

22.4 L ---- 1 mol

x L ---- 3.3 x 10^-3 mol

x = 0.075 L = 75 mL

b) It is formed 150 mL of NO2, because the stoichiometric ratio between NO and NO2 is 2:2, so it will form the same amount of NO used.

Answer: a) 75 mL of O2

b) 150 mL of NO2

Taking into account the ideal gas law, a mass of 0.00314 grams of H₂ is collected.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

In this case, you know:

Replacing in the ideal gas law:

0.985526 atm× 0.039 L = n× 0.082 (atm×L)÷(mol×K)× 298 K

Solving:

[0.985526 atm× 0.039 L]÷ [0.082 (atm×L)÷(mol×K)× 298 K]= n

0.00157 moles= n

Considering that the molar mass of H₂ is 2 g/mole, the mass can be calculated as:

mass= number of moles× molar mass

mass= 0.00157 moles× 2 g/mole

mass= 0.00314 grams

Finally, you collected a mass of 0.00314 grams.

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The mass of Na₂CO₃ needed to generate 0.0135 mole of CO₂ is 1.431 grams

We'll begin by obtaining the mole of Na₂CO₃ that reacted to produce 0.0135 mole of CO₂

Na₂CO₃ + 2HCl -> 2NaCl + H₂O + CO₂

From the balanced equation above,

1 mole of CO₂ was obtained from 1 mole of Na₂CO₃

Therefore,

0.0135 mole of CO₂ will also be obtained from 0.0135 mole of Na₂CO₃

Now, we shall determine the mass of Na₂CO₃ needed for the reation. Details below:

Mole = mass / molar mass

0.0135 = Mass of Na₂CO₃ / 106

Cross multiply

Mass of Na₂CO₃ = 0.0135 × 106

Mass of Na₂CO₃ = 1.431 grams

Therefore, the mass of Na₂CO₃ needed is 1.431 grams

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Answer:

Sugar, Carbon Dioxide, And Water

Explanation:

A chemical substance is a form of matter having constant chemical composition and characteristic properties. Some references add that chemical substance cannot be separated into its constituent elements by physical separation methods, i.e., without breaking chemical bonds. Chemical substances can be simple substances, chemical compounds, or alloys. Chemical elements may or may not be included in the definition, depending on expert viewpoint.

Molarity or molar concentration is a measure of the concentration of a chemical species, of a solute in a solution, using as units, number of moles, and volume in liters. The formula for Molarity is:

M = n/V

Where:

n = number of moles, 1.7 moles

V = volume in Liters, 2.8 Liters

Now we add these values into the formula:

M = 1.7/2.8

M = 0.61

The Molarity is 0.61 M

The correct procedure for handling microorganisms is to wash your hands frequently to make preventive doings. For the safest reason, using Personal Protective Equipment is recommended.

What is Personal Protective Equipment?

Personal Protective Equipment (PPE) is equipment that must be used when working, according to the potential hazards and work risks on the job. This is used to maintain the safety of the workers themselves and those around them. Personal Protective Equipment must be in accordance with the type of work so that the safety and health of workers can be guaranteed.

Activities in the microbiology laboratory will always be closely related to the following things

The tool used in assisting the examination or identification of microorganisms can be in the form of a Bunsen which uses spirit, which has flammable properties. If the test tube is not used carefully, it can break and can injure the limbs.

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Answer:

Use aseptic techniques, Wash your hands frequently, and use disinfectants to clean lab surfaces.

Explanation:

According to the kinetic molecular theory, the argon would have its molecules in a state of constant motion.

According to the kinetic molecular theory, gas molecules are in constant random motion and the behavior of a gas can be explained by considering the behavior of its individual molecules

This implies that under constant pressure, the molecules of the argon would bombard each other and the walls of the container that is holding them up according to the theory.

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Answer:

\(1190\ \text{mL}\)

Explanation:

\(M_1\) = Initial Concentration of KCl = 2.7 M

\(V_1\) = Volume of KCl = 1 M

\(M_2\) = Final concentration of KCl = 1 M

\(V_2\) = Amount of water

We have the relation

\(M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}\)

The amount of water that is to be added is \(1890-700=1190\ \text{mL}\).

Answer: A. 212

Explanation:

The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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If the person drops the ball, its velocity gets bigger and bigger as it falls.

What effect does gravity have on a falling ball?

When something falls, it is due to gravity. Because the item feels a force, it accelerates, causing its velocity to increase as it falls. A sort of acceleration is the force with which the Earth pushes on something in the form of gravity. The Earth exerts the same amount of force on everything.

Gravity is the force that causes objects to fall to the ground. When you drop a ball (or anything else), it falls to the ground. Everything falls at the same rate due to gravity. When you drop the ball, gravity pulls it down and accelerates it. It collides with the ground and squashes at contact. As the squished ball recovers its former shape

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Complete question:

The diagram below shows a person holding a ball standing at three different places on earth. if the person drops the ball, gravity will make it fall.

Which of the following diagrams best shows the direction the dropped ball will fall at the three different positions?

b. b

a. a

c. c

d. d

Answer: i’m taking a test w this question rn and i think the best answer is D. When the water begins to boil, some of the water molecules will gain enough energy to change into a gas. i could def be wrong tho

After Rounding off The percentage yield is 64%

It is the ratio of actual yield to theoretical yield multiplied by 100% .

It is given in the question

20.0 g of bromic acid, HBrO3, is reacted with excess HBr.

The reaction is

HBrO₃ (aq) + 5 HBr (aq) → 3 H₂O (l) + 3 Br₂ (aq)

Actual yield = 47.3 grams

Molecular weight of Bromic Acid is 128.91 gram

Moles of Bromic Acid = 20/128.91 = 0.155 mole

Mole fraction ratio of Bromic Acid to Bromine is 1 :3

Therefore for 0.155 mole of Bromic Acid 3 * 0.155 = 0.465 mole of Bromine is produced.

1 mole of Bromine = 159.8 grams of Bromine

0.465 of Bromine = 74.31 grams of Bromine

Percentage Yield = (47.3/74.31)*100 = 63.65 %

After Rounding off The percentage yield is 64% .

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Tablespoon of sugar will dissolve faster in a cup of hot tea

Generally, a solute dissolves faster in a warmer solvent than it does in a cooler solvent because particles have more energy of movement. For example, if you add the same amount of sugar to a cup of hot tea and a cup of iced tea, the sugar will dissolve faster in the hot tea.

In the above case we can say that a tablespoon of sugar will dissolve faster  in a cup of hot tea because when we compared table spoon of sugar with cube of sugar the surface area in grounded sugar is more and for cube of sugar the surface area is less and hence will take more time to dissolve.

So we can conclude that tablespoon of sugar will dissolve faster in a hot cup of tea.

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1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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Answer:

To find the number of moles in 78.3 grams of ammonium sulfite, you would divide the mass by the molar mass of the substance. The molar mass of ammonium sulfite is (14.0067 + 14.0067 + 32.065 + 64.0638) g/mol = 124.1472 g/mol.

78.3 g / 124.1472 g/mol = 0.63 moles

Explanation:

Answer:

0,6746 moles of ammonium sulfite

Explanation:

(NH₄)₂SO₃  - ammonium sulfite \(\equiv \, N_2H_8SO_3\)

Atomic weight of each element:

N = 14.00 * 2  = 28

H = 1.00   * 8  = 8

S = 32.065 * 1 = 32.065

O = 16 * 3 =  48

Total atomic weight = 28 + 8 + 32.065 + 48

Total atomic weight = 116,065 gr/mol

\(78.3\,g \,* \frac{1mol\,of\, (NH_4)_2SO_3}{116.065g \, \,of \, (NH_4)_2SO_3 } \approx 0,6746\, moles \, of \, (NH_4)_2SO_3\)

Answer:

(A) and (D)is the correct answer

Explanation:

(A) in terms of electronic concept and (D) in terms of classical concept

coz you know

hope, it helps.......

Answer:

A. It gives up electrons

Explanation:

on PLATO

I got 5 out of 5 on quiz

Answer:

A

Explanation:

Answer:

C

Explanation:

Pretty sure!

If the caffeine concentration in a particular brand of soda is 2.99 mg/oz, drinking, The number of cans of soda would be lethal is 258 cans.

Caffeine is a stimulant. In the brain, it blocks the effects of a chemical called adenosine, which makes you feel sleepy. we then feel more alert and energetic, which is why many people drink soda, coffee or tea to stay awake. Caffeine may keep you awake even if you don't want it to

Given

v = 10 000/3.23 =3095.96 oz

Therefore,

Number of cans = 3095.96 /12 =258 cans

If the caffeine concentration in a particular brand of soda is 2.99 mg/oz, drinking, The number of cans of soda would be lethal is 258 cans.

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Given :

For a chemical reaction, the activation energy for the forward reaction is +181 kJ and the activation energy for the backward reaction is +62 kJ.

To Find :

The overall energy change for the forward reaction.

Solution :

The overall energy change for the forward reaction is :

\(\Delta E_f = E_f - E_b\\\\\Delta E_f = 181 - 62 \ Kj\\\\\Delta E_f = 119 \ Kj\)

Therefore, the overall energy change for the forward reaction is 119 Kj.

Answer:The fishing way and how fast is going

Explanation:Because of the variables the fishing we will flow much more faster

Answer:

A

Explanation:

A ball buried under the ground is the answer because it has no kinetic energy because of it's inability to move

Answer:

Explanation:

Use the formula PV=nRT

P is pressure in atm

V is volume in whatever unit you're working in as long as everything is in that unit (anything volume related)

n is the number of moles

R is the constant so 0.08206

and T is temperature and this MUST be in Kelvin which is 173.15 + C

the equation can be shifted depending on what you need to solve

(a)  The mass percent of HCl in the solution is approximately 36.1%.

(b)  The molality of HCl in the solution is approximately 15.5 mol/kg.

(c)  The mole fraction of HCl in the solution is approximately 0.218.

(a) To calculate the mass percent of HCl, we need to determine the mass of HCl in a given volume of the solution.

Given: Concentration of HCl = 11.8 M

Density of the solution = 1.190 g/mL

First, we need to calculate the mass of the solution. Since density is mass per unit volume, the mass of 1 mL of the solution is 1.190 g.

Next, we need to calculate the mass of HCl in 1 mL of the solution. Since the concentration is given in moles per liter (M), and the molar mass of HCl is 36.46 g/mol, we can calculate the mass of HCl in 1 mL as follows:

Mass of HCl = concentration × volume × molar mass

          = 11.8 mol/L × 0.001 L × 36.46 g/mol

          = 0.430 g

Now, we can calculate the mass percent of HCl using the following formula:

Mass percent = (mass of solute ÷ mass of solution) × 100

           = (0.430 g ÷ 1.190 g) × 100

           ≈ 36.1%

(b) The molality of HCl is calculated by dividing the moles of solute (HCl) by the mass of the solvent (water) in kilograms.

Since the density of the solution is given as 1.190 g/mL, the mass of 1 mL of the solution is 1.190 g. However, we need to consider the density of the solvent (water) to calculate the mass of water in the solution.

Assuming the density of water is 1 g/mL, the mass of water in 1 mL of the solution is (1.190 g - 0.430 g) = 0.760 g.

To calculate the molality of HCl, we need to convert the mass of water to kilograms:

Mass of water (kg) = 0.760 g ÷ 1000 = 0.000760 kg

The molality (m) is calculated using the formula:

Molality = (moles of solute ÷ mass of solvent in kg)

        = (11.8 mol/L × 0.001 L) ÷ 0.000760 kg

        ≈ 15.5 mol/kg

(c) The mole fraction (X) of HCl is calculated by dividing the moles of HCl by the total moles of all components in the solution.

To calculate the mole fraction, we need to consider the volume of the solution and convert it to liters.

Given: Concentration of HCl = 11.8 M

Volume of the solution = 1 mL

Volume of the solution (L) = 1 mL ÷ 1000 = 0.001 L

To calculate the mole fraction of HCl, we need to calculate the moles of HCl and the moles of water (solvent) in the solution.

Moles of HCl = concentration × volume

            = 11.8 mol/L × 0.001 L

            = 0.0118 mol

Moles of water = mass of water ÷ molar mass of water

             = 0.760 g ÷ 18.015 g/mol (molar mass of water)

             = 0.0422 mol

Total moles in the solution = moles of HCl + moles of water

                           = 0.0118 mol + 0.0422 mol

                           = 0.054 mol

Mole fraction of HCl = moles of HCl ÷ total moles

                   = 0.0118 mol ÷ 0.054 mol

                   ≈ 0.218

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To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.

Given:

Mass of Bal2 = 413 g

Volume of solution = 750 ml = 0.75 L

1. Calculate the number of moles of Bal2:

First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):

Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)

Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)

Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol

Molar mass of Bal2 = 264.61 g/mol

Now we can calculate the number of moles of Bal2:

Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2

Moles of Bal2 = 413 g / 264.61 g/mol

Moles of Bal2 ≈ 1.561 mol

2. Calculate the molarity of the solution:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity (M) = 1.561 mol / 0.75 L

Molarity (M) ≈ 2.081 M

Therefore, the molarity of the solution is approximately 2.081 M.

The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.

The molar mass of BaI₂ is:

Ba (barium) atomic mass = 137.33 g/mol

I (iodine) atomic mass = 126.90 g/mol

Molar mass of  BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)

= 137.33 + 2 × 126.90

= 137.33 + 253.80

= 391.13 g/mol

Given that the mass of BaI₂ is 413 g,

Number of moles = Mass / Molar mass

= 413 g / 391.13 g/mol

= 1.056 moles

Volume of solution = 750 ml = 750/1000 = 0.75 L

Finally, one can calculate the molarity of the solution using the formula:

Molarity = Number of moles / Volume of solution

= 1.056 moles / 0.75 L

= 1.408 M

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Answer:

See explanation

Explanation:

Now taking A, we can see that if we double the amount of A while keeping the amount of B constant, the rate of reaction doubles, hence we can write;

2^n = 2^1

hence n =1

For B, when the amount of B is doubled while keeping the amount of A constant, the rate of reaction increases eight times. Hence we can write;

2^n = 8

2^n = 2^3

n=3

Hence this reaction has an overall order of 1 + 3 = 4

So we can write;

rate =k[A] [B]^3

Answer: 24.305052 (8 sig figs)  [Mg]

Explanation:  The AMU of each isotope is multiplied by it's percent abundance to yield a weighted average for each isotope.  The sum of these weighted averages will be the wighted average of the element's isotopes:

Isotope    Mass (AMU)     %            Weighted AMU

24Mg 23.985042 78.99% 18.94578468

25Mg 24.985837 10.00%   2.4985837

26Mg 25.982593 11.01%   2.860683489

                                   24.305052 (8 sig figs)

The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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