As a beam of light enters a swimming pool, it will because light waves when they pass from one medium to a different medium.

The sound of a lamb is grave due to its high pitch depending on its low frequency. Option B is correct.

A sound pressure wave's frequency is the number of times it repeats itself every second.

The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.

Pitch and the frequency of sound are inverse to each other. A lamb's sound is grave because of its high pitch and low frequency.

The sound of a lamb is grave due to its high pitch depending on its low frequency.

Hence, option B is correct.

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Answer:

The industry standard life span is about 25 to 30 years, and that means that some panels installed at the early end of the current boom aren't long from being retired is the operating life time of a PV module .

The length of the spring during the motion is 16.875 cm

We'll begin by obtaining the velocity during the first 1.60 s. This is illustrated as follow:

Velocity = distance / time

Velocity = 0.96 / 1.6

Velocity = 0.6 m/s

Next, we shall determine the acceleration.

a = (v – u) / t

a = (0.6 – 0) / 1.6

a = 0.6 / 1.6

a = 0.375 m/s²

Next, we shall determine the force.

Mass (m) = 12.5 kg

Acceleration (a) = 0.375 m/s²

Force (F) =?

Force = mass × acceleration

Force = 12.5 × 0.375

F = 4.6875 N

Next, we shall determine the extension of the spring.

F = Ke

Divide both sides by K

e = F / K

e = 4.6875 / 2.5

e = 1.875 cm

Finally, we shall dtermin the length of the spring. This can be obtained as follow:

Length of spring = 15 + 1.875

Length of spring = 16.875 cm

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Answer:

Sand is a form of physical change because it shows how one object is being worn out (broken down) into another object by nature.

Explanation:

An airplane is flying with a force of 800 N. It experiences a force of air resistance of 40 N and a wind force of 60 N, both acting in the opposite direction that the plane is traveling. The net force on the airplane will be 700 N

Force with which airplane is flying ( F1 ) = 800 N

opposite to which two forces are acting

air resistance = 40 N

wind force = 60 N

net force = F1 - 40 - 60 = 800 - 100 = 700 N

The net force on the airplane will be 700 N

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Answer:

See below

Explanation:

Distance covered = 400 + 200 = 600 km

displacement =   400 w   -  200 e  = 200 km  west

0.7 mL of HEPARIN 10,000 units/mL is needed for a 7,000 unit dose.

To calculate the volume of HEPARIN 10,000 units/mL needed for a 7,000 unit dose, we can use the formula:

Volume (mL) = Dose (units) / Concentration (units/mL)

Given that the dose is 7,000 units and the concentration of HEPARIN is 10,000 units/mL, we can plug these values into the formula:

Volume (mL) = 7,000 units / 10,000 units/mL

Volume (mL) = 0.7 mL

So, 0.7 mL of HEPARIN 10,000 units/mL is needed for a 7,000 unit dose. However, none of the provided answer choices match exactly with 0.7 mL. The closest option is B. 0.07 mL, which is one-tenth of 0.7 mL. Therefore, the correct answer is B. 0.07 mL.

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Answer:

(a) ω = 12.57 rad/s

(b) a = 189.5 m/s²

(c) T = 9.47 N

Explanation:

(a)

The speed of rotation is given by the formula:

ω = θ/t

where,

ω = speed of rotation = ?

θ = angular displacement = (1 rotation)(2π rad/1 rotation) = 2π rad

t = time taken = 0.5 s

Therefore,

ω = 2π rad/0.5 s

ω = 12.57 rad/s

(b)

The centripetal acceleration of the object is given by the formula:

a = v²/r

where,

a = Centripetal Acceleration = ?

v = linear speed of object = rω

r = length of rope = 1.2 m

Therefore,

a = (rω)²/r

a = rω²

a = (1.2 m)(12.57 rad/s)²

a = 189.5 m/s²

(c)

The tension required to maintain the motion is equal to the centripetal force:

Tension = Centripetal Force

T = ma

where,

m = mass of object = 50 g = 0.05 kg

Therefore,

T = (0.05 kg)(189.5 m/s²)

T = 9.47 N

Answer:

The answer is -30.95.

Explanation:

Use the lens equation: 1/focal length = 1/object distance + 1/image distance. The answer comes out to -30.95. This is correct on Acellus.

When it is held 5.20 cm in front of an object, the image distance will be "-30.95 cm". To understand the calcultaion, check below.

According to the question,

Object distance, u = -5.20 cm

Focal length, f = 6.25 cm

By using the Lens formula, we get

→ \(\frac{1}{f} = \frac{1}{v} - \frac{1}{u}\)

or,

→ \(\frac{1}{v} = \frac{1}{f} + \frac{1}{u}\)

By substituting the values, we get

     \(= \frac{1}{6.25} - \frac{1}{5.20}\)

  \(\frac{1}{v} = -\frac{21}{650}\)

By applying cross-multiplication,

   v = -30.95 cm

Thus the above answer is correct.  

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{force}{mass} \\ \)

From the question

force = 97.7 N

mass = 34.2 kg

We have

\(a = \frac{97.7}{34.2} = 2.856725 \\ \)

We have the final answer as

Hope this helps you

Answer:

(a) When the resistance R is doubled, I = 1 A

(b) When the peak emf εo is doubled, I = 4 A

(c)  When the frequency ω is doubled, I = 2 A

Explanation:

Given;

peak current through the resistor, I = 2.0 A

According to ohms law the peak current through the circuit is given by;

\(I = \frac{V}{R}\)

(a) When the resistance R is doubled;

\(I = \frac{V_R}{R} \\\\I_1R_1 = I_2R_2\\\\I_2 = \frac{I_1R_1}{R_2} \\\\I_2 = \frac{2*R_1}{2R_1} \\\\I_2 = 1 \ A\)

(b)When the peak emf εo is doubled

\(I = \frac{V}{R} = \frac{\epsilon_o}{R} \\\\R = \frac{\epsilon_ o}{I} \\\\\frac{\epsilon_ o_1}{I_1} = \frac{\epsilon_ o_2}{I_2} \\\\I_2 = \frac{\epsilon_ o_2 *I_1}{\epsilon _o_1} \\\\I_2 = \frac{2 \epsilon_ o_1 *2}{\epsilon _o_1} \\\\I_2 = 4 \ A\)

(c) When the frequency ω is doubled

Peak current through resistor is independent of frequency

I₂ = 2.0 A

The total charge in the circuit is 240 microcoulombs.

To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.

In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.

To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.

Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.

Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.

Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.

Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.

The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the  wavelength.

Given the time period of the wave = 2.09 Hz

then frequency = 1/2.09 Hz = 0.47 s.

Therefore, the time period  of the wave is 0.47 seconds.

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Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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The power at which the crane operates, if it can lift a mass of 500 kg is 1225 Watts.

Power is the rate at which work is done.

To calculate the power the crane operates with, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the right option is B. 1225 Watts.

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The average speed of the whole journey is 54 mph.

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A.  The motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of this motor as a function of the field resistance RF is approximately 1086 r/min

A. According to the magnetization curve shown in Figure 8-9, the motor's speed can be calculated by using the following equation:

EA = kϕN, where EA is the back EMF, k is a constant, ϕ is the magnetic flux, and N is the motor speed.

Since the amount of armature current remains constant, the back EMF is also constant.

Therefore, the magnetic flux must also be constant. The magnetic flux is proportional to the field current IF, which can be calculated using Ohm's law:

IF = (250 V - EA)/(RF + R₁)

At the initial field resistance of 41.67 Ω, the field current is IF = (250 V - EA)/(41.67 Ω + 0.03 Ω) = (250 V - EA)/41.70 Ω.

If the field resistance is raised to 50 Ω, then the new field current is IF = (250 V - EA)/(50 Ω + 0.03 Ω) = (250 V - EA)/50.03 Ω.

Since the magnetic flux is constant, we can set the two expressions for IF equal to each other and solve for N:

kϕN/IF1 = kϕN/IF2

N = (IF2/IF1)N1 = (250 V - EA)/(50.03 Ω + 0.03 Ω) * 1103 r/min ≈ 1086 r/min

Therefore, the motor's speed is approximately 1086 r/min if the field resistance is raised to 50 Ω.

B. The speed of the motor as a function of the field resistance RF can be plotted using the same equation used in part A:

N = (250 V - EA)/(RF + R₁ + Radj) * 1103 r/min

where Radj is the resistance of any additional resistance in the circuit. Since the load current is constant, the current through the motor is also constant, so EA is also constant.

Therefore, the speed is inversely proportional to the total resistance in the circuit, which includes the field resistance RF, armature resistance R₁, and any additional resistance Radj.

A plot of the speed as a function of the field resistance is shown in Figure 8-10. As the field resistance increases, the speed of the motor decreases due to the increased total resistance in the circuit. This relationship is linear for this type of constant-current load.

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Answer:

v = 2.94 m/s

Explanation:

Given that,

Mass of anvil, m = 15 kg

The gravitational potential energy relative to the floor, P = 65 J

We need to find the speed just before it hits the floor when the Anvil is released. Let it is v.

We can use the conservation of energy.

\(\dfrac{1}{2}mv^2=mgh\\\\65=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{65\times 2}{15}} \\\\v=2.94\ m/s\)

So, the required speed is 2.94 m/s.

If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then a. likely to worsen

Astronomers already have a serious problem with light pollution from cities and other sources, which makes it more challenging to detect dim objects in the night sky. Light pollution is predicted to get worse unless action is taken to stop it as urbanisation grows and more artificial lights are installed.

Astronomical observations can be affected by radio interference from telecommunications, and unless steps are taken to reduce the issue, the issue is only going to become worse as the number of radio-emitting devices rises. In addition, astronomers' instruments and spacecraft are increasingly in danger from space debris. The probability of collisions and other accidents is anticipated to rise as the amount of trash in space continues to rise.

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Complete Question:

If no action is taken to address the issues evaluate whether the impact of light pollution radio interference and space debris on the field of astronomy is then -

a. likely to worsen

b. lessen or remain the same during the next 50 years

According to the Keynesian view, manipulating foreign sector spending is not a reliable way to move the U.S. economy toward a more acceptable equilibrium because it does not address the fundamental causes of economic instability.

Keynesian economics focuses on the role of domestic demand in driving economic growth and stability. The government can use fiscal and monetary policy to stimulate aggregate demand and promote full employment. However, changes in foreign sector spending can be unpredictable and beyond the control of domestic policymakers. For instance, an increase in foreign demand for U.S. exports could boost economic growth and employment in the short run, but it may not be sustainable if the foreign demand later decreases. Similarly, a decrease in foreign demand for U.S. exports could have negative short-term effects on the economy, but it may not necessarily lead to a long-term decline. In short, Keynesian economics emphasizes the importance of domestic demand management and stabilizing the economy through government intervention. While changes in foreign sector spending can have some impact on the economy, they are generally seen as unreliable and unpredictable, and therefore not a reliable tool for achieving economic stability in the long run.

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The intrepid hero has done 2.332 x Joules of work in pushing the crate.

To ascertain the work done by the traveler, we first need to find the power he applied on the case. As per Newton's subsequent regulation, force is equivalent to mass times speed increase, so the power applied by the traveler on the container is:

Force = mass x speed increase = 220 kg x 2  = 440 N

Then, we really want to work out the distance the case was moved. The pilgrim pushed the box a distance of 5.3 km, or 5,300 m.

At long last, we can compute the work done by the pioneer utilizing the equation:

Work = force x distance = 440 N x 5,300 m = 2.332 x 10^6 Joules

Thusly, the valiant legend has done 2.332 x  Joules of work in pushing the case.

The space pilgrim takes care of business on the case by applying a power that makes it speed up. The work done is equivalent to the power duplicated by the distance over which the power is applied. Involving the recipe for force, F=ma, and the given qualities for mass and speed increase, we can ascertain the power applied. Then, at that point, involving the recipe for work, W=Fd, and the given distance, we can ascertain the work done. The work done by the adventurer is 2.332 x  J.

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The initial potential energy of the arrow is,

The energy before it is shot is the total potential energy that is 800 J.

After the shot, as there is no energy loss due to friction, the total energy remains the same.

Total energy after the shot is 800 J.

During flight, the total energy will also be 800 J.

When it hits the target, the energy is not lost. The total energy remains the same as before, which means 800 J.

We here are applying the energy conservation principle.

Answer: 25230800 Joules

Explanation: We can treat the copper tank and the water inside as two different objects since they have different specific heats. We will utilize Q=Mcdelta(t) in this problem where M is mass, c is specific heat, and delta t is the change in temperature.

Since we are treating the copper and water separately we can make a Mcdelta(t) for each one of them. This gives us Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t)). The delta t will be the same because both the copper and water are at 15 celsius. Now we just do some calculations.

Q=(mass of copper)(specific heat of copper)(delta(t))+(mass of water)(specific heat of water)(delta(t))

Q=(20)(385)(55-15)+(150)(4200)(55-15)

Q=30800+25200000

Q=25230800 J

This number may seem absurdly high but there is 150 kg of water being heated up which is 150 liters(A LOT!).

Hope this helps!

a particle of violet light has exactly the same energy as a particle of red light

The total solar heat gain through the south windows of the building at solar noon in April is approximately 10397 W if the windows have a shading coefficient of 0.30, and it would be approximately 34680 W if there were no blinds at the windows.

Solar radiation intensity: The solar radiation intensity on the surface of the windows can be calculated using the formula:

I = Io * cos(θ) * cos(φ)

where I is the solar radiation intensity on the surface of the windows, Io is the extraterrestrial solar radiation intensity (1367 W/m²), θ is the solar altitude angle (54°), and φ is the azimuth angle (180°). Substituting these values, we get:

I = 1367 * cos(54°) * cos(180°)

I ≈ 455 W/m²

Window area: The window area on the south wall is given as 76 m².

Window type and shading coefficient: The windows have a shading coefficient of 0.30. This means that only 30% of the solar radiation that falls on the windows is transmitted through them, while the remaining 70% is absorbed or reflected.

Total solar heat gain: The total solar heat gain through the south windows of the building at solar noon in April can be calculated as:

Q = I * A * SC

where Q is the total solar heat gain, I is the solar radiation intensity, A is the window area, and SC is the shading coefficient. Substituting the values, we get:

Q = 455 * 76 * 0.30

Q ≈ 10397 W

Therefore, the total solar heat gain through the south windows of the building at solar noon in April is approximately 10397 W if the windows have a shading coefficient of 0.30.

If there were no blinds at the windows, the shading coefficient would be 1.0, meaning that all of the solar radiation that falls on the windows would be transmitted through them. In this case, the total solar heat gain through the south windows would be:

Q = I * A * SC

Q = 455 * 76 * 1.0

Q ≈ 34680 W

Therefore, if there were no blinds at the windows, the total solar heat gain through the south windows of the building at solar noon in April would be approximately 34680 W.

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In a scenario where an egg is free-falling from a nest in a tree and neglecting air resistance, there is one force acting on the egg and the force is unbalanced which is denoted as option B.

This is referred to as an external agent which is capable of influencing the motion of an object or body. It is also capable of changing the state of rest of a body and the unit in Newton.

When an object is falling from a height and there is no air resistance then the only force acting on it is gravitational force which is unbalanced as there is no equal and opposite force to make it stable.

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Explanation:

Given that,

Initial speed of a ranger, u = 36.2 mi/h

Distance dove by the ranger, d = 205 ft

Due to the application of brakes, the acceleration reached is 8.83 ft/s².

We need to find the maximum reaction time allowed if she is to avoid hitting the deer.

We know that,

1 mph = 1.46667 ft/s

36.2 mi/h = 53.09 ft/s

Let t is time.

Using second equation of kinematics to find it as follows :

\(d=ut+\dfrac{1}{2}at^2\\\\ 205=53.09t-\dfrac{1}{2}\times 8.83t^2\\\\4.415t^{2}-53.09t+205=0\)

The above is a quadratic equation. We need to solve it for t as follows :

\(t=x=\dfrac{-\left(-53.09\right)-4\left(4.415\right)\left(205\right)}{2\cdot4.415},\dfrac{-\left(-53.09\right)+4\left(4.415\right)\left(205\right)}{2\cdot4.415}\\\\t=-403.98\ s,416.01\ s\)

Hence, 416.01 seconds is the maximum reaction time allowed if she is to avoid hitting the deer.

Stochastic impacts of radiation allude to those that happen arbitrarily and are not reliant upon the portion got. These impacts are related to the likelihood of events and incorporate disease and hereditary changes. Non-stochastic impacts, then again, have a limit, and their seriousness increments with expanding portions.

Models incorporate radiation consumption and intense radiation conditions. Understanding the qualification among stochastic and non-stochastic impacts of radiation is significant in fields like radiation security, atomic medication, and radiobiology.

It assists in setting radiation with dosing limits, creating well-being rules, and carrying out suitable radiation safeguarding measures. By separating these impacts, experts can evaluate and deal with the dangers related to openness to ionizing radiation all the more successfully.

This information guides choices in regard to radiation wellbeing conventions, word-related openness limits, and the improvement of radiation therapy systems in medication.

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Answer:

A and C I think

Explanation:

The two statements describe behaviors of particles that are related to the physical properties of the materials are A and C.

Physical properties are measurable property whose value represents a condition of an object.

The two statements describe behaviors of particles that are related to the physical properties of the materials are ;

A. They allow electrons to move freely between them.

c. They change their positions relative to one another.

The two statements describe behaviors of particles that are related to the physical properties of the materials are A and C.

Hence, option A and C are correct.

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Answer:

a = 0.273 m/s²

Explanation:

I would assume that the rider starts at 0m/s.

a = average acceleration

v = final velocity = 3 m/s

v0 = initial velocity = 0 m/s

t = time = 11 s

a = (v-v0)/t

a = (3m/s - 0m/s) / 11s

a = 0.273 m/s²

I am not sure how many decimals I should round it to, so I just gave three. If your teacher has instructions on that, do so accordingly.