Arlo throws a rock down with speed 14 m/s from the top of a 30 m tall cliff. what is the rock's speed just as it hits the ground?

Answers

Answer 1

The rock's maximum speed just as it hits the ground is 28m/s.

Given that the initial speed of the rock is u = -14m/s. (speed taken as negative because the rock thrown down from the cliff)

The height of the tower is h=30m.

Taking height of the tower as origin, then final position of the rock is s= -h= -30m.

On applying the second equation of motion:

s= ut +¹/₂ at²

-30 = -14t+0.5×(-9.8)t²

4.9t²+14t-30=0

On Solving the equation we get, t=1.43s.

To calculate that final speed when rock hits the ground, we apply first equation of motion:

v=u+gt

v=-14+(-9.8)(1.43)

v=-28m/s.

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Related Questions

10. Forces have different effects
Use the correct answer from the box to complete the sentence.


Slowing
Stretching
Turning

The moment of a force is the __________ effect of the force​

Answers

Answer:

turning

Explanation:

because the moment of a force is for pivots

the moment of a force can be clockwise motion and anti clockwise motion

hope this helps

when will he love me 

Answers

Put a fork under your pillow tonight, and your wish will come true tomorrow.

Answer:

When you go bald

Explanation:

An astronaut is moving in space when a big explosion occurs about 50 meters behind him. How will the astronaut come to know about the explosion?
Choose:--
From the sound of the explosion
From the light due to the explosion
From light and sound due to the explosion
From the vibrations due to the explosion

Answers

Answer:

The correct answer is B.

The astronaut will know due to the light from the explosion.

Explanation:

Sound and vibrations require a medium such as air to travel through. Space, there is no air. Only a vacuum. So sound and vibrations are unable to travel. Light requires no medium to travel. It can go through a vacuum.  

Therefore the Astronaut will see a bright flash of light as it travels from the explosion to outer space. It is also important to note that light can travel very far because nothing else interacts with its wave particles and as such, it cannot be impeded.

Cheers!

how is gas different from liquid?

Answers

Answer:

Gas is different from liquid. Liquid has a definite volume but takes the shape of the container it is in. Gas on the other hand, has no definite shape or volume.

Explanation:

A rock is placed into a graduated cylinder and the volume of water increases from 50 ml to 60 ml. If the rock has a mass of 25 grams, what is its density?

Answers

The density of the rock, having a mass of 25 grams which increases the volume of water from 50 mL to 60 mL is 2.5 g/mL

How do I determine the density of the rock?

To obtain the density of the rock, we must know the volume of the rock. The volume of the rock can be obatined as follow:

Volume of water = 50 mL Volume of water + rock = 60 mL Volume of rock =?

Volume of rock = (Volume of water + rock) - volume of water

Volume of rock = 60 - 50

Volume of rock = 10 mL

Now, we shall determine the density of the rock. This is illustrated below:

Volume of rock = 10 mL Mass of rock = 25 grams Density of rock = ?

Density = mass / volume

Density of rock = 25 / 10

Density of rock = 2.5 g/mL

Thus, we can say that the density of the rock is 2.5 g/mL

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540 J of work must be done to compress a gas to half its initial volume at constant temperature. Part A How much work must be done to compress the gas by a factor of 12.0, starting from its initial volume? Express your answer with the appropriate units.

Answers

5940 J of work must be done to compress the gas by a factor of 12.0, starting from its initial volume.

To help you with your question, let's first establish the relationship between the work done and the volume change. Initially, 540 J of work is required to reduce the volume to half (a factor of 2). Now, you want to find the work needed to compress the gas by a factor of 12.
Since the work done is directly proportional to the change in volume, we can set up a proportion:
(Work done for factor 12) / (Work done for factor 2) = (12 - 1) / (2 - 1)
Let W represent the work done for a factor of 12:
W / 540 J = 11 / 1
Now, solve for W:
W = 11 * 540 J
W = 5940 J
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Two masses are 3 meters apart, and the force of gravity between the masses is 8 lbs. If the masses are moved to 6 meters from each other, the force of gravity between them is _____ lbs.

Answers

Two masses are 3 meters apart, and the force of gravity between the masses is 8 lbs. If the masses are moved to 6 meters from each other, the force of gravity between them is 2 lbs.

The force of gravity between two masses can be calculated using the equation:

F = (G * m1 * m2) / r^2

Where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses, and r is the distance between the masses.

Given that the force of gravity between the masses when they are 3 meters apart is 8 lbs, we can set up the equation as:

8 = (G * m1 * m2) / (3^2)

To find the force of gravity when the masses are 6 meters apart, we need to calculate the new force using the equation:

F' = (G * m1 * m2) / (6^2)

We can solve for F' by rearranging the equation and substituting the given values:

F' = (8 * (6^2)) / (3^2) = 2 lbs

Therefore, the force of gravity between the masses when they are 6 meters apart is 2 lbs.

The force of gravity between two masses is inversely proportional to the square of the distance between them. When the masses are moved to twice the original distance, the force of gravity decreases to one-fourth of its initial value. In this case, the force of gravity decreases from 8 lbs to 2 lbs when the masses are moved from 3 meters to 6 meters apart.

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help!! this makes no sense to me

help!! this makes no sense to me

Answers

3 meters i’m pretty sure

Answer:

3 meters

Explanation:

Velocity = displacement/time

Displacement=velocity×time

As, time from 7 to 8 is 1 sec. And velocity increases from 0 to 3 m/s

So, Displacement = 3×1

=3m

Please give me brainlist.

If the deflection of a spring is doubled, then how much does the force change?

Answers

Answer:

The force is doubled as well.

Explanation:

If you double the spring then the force doubles as well.

If the deflection of the spring is doubled, the force exerted by the spring will also be doubled.

What is the Hooke's Law?

The relationship between the deflection of a spring and the force it exerts is described by Hooke's Law, which states that the force exerted by a spring is directly proportional to its deflection. Mathematically, this can be expressed as:

F = kx

where F is the force exerted by the spring, x is the deflection of the spring, and k is the spring constant, which represents the stiffness of the spring.

If we double the deflection of the spring, then x becomes 2x, and the force exerted by the spring becomes:

F = k(2x) = 2kx

Thus, if the deflection of the spring is doubled, the force exerted by the spring will also be doubled (assuming the spring constant remains constant).

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What happens during 1/2 life of a radioactive isotope?

Answers

A radioactive isotope's half-life is the length of time it takes for one half of it to decay.

What is the radioisotopes' half-life?

The duration needed for a quantity of a radioisotope to decay by half is known as its radioactive half-life. If an isotope has a half-life of only a few hours or less, the majority of the radioactivity will dissipate within a few days.

How does half-life work?

A radioactive element's half-life is the amount of time it takes for it to decay to half of its original value. It can be concluded from this that a source's activity has a half-life if it takes some time before it drops to half its starting value.

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Help help help help help

Help help help help help

Answers

I am not sure on the rest but the answer to question 4 is volts. sorry i couldn’t be of more help!

I already found Rx = -0.2 and Ry = -3. The magnitude is the square root of 0.2^2 + 3^2 = 3.01 I only need help understanding why when I plus in to solve for the direction why it won’t accept 86.2 when tan^-1(-3/0.2) doesn’t work. Please help explain to me the real answer or how I’m wrong. Thank you in advance

I already found Rx = -0.2 and Ry = -3. The magnitude is the square root of 0.2^2 + 3^2 = 3.01 I only

Answers

The values you found are incorrect.

The sum/resultant vector is

\(\hat R = \hat A + \hat B \\\\ \hat R = (5.00\,\mathrm m)\,\hat\imath + (6.00\,\mathrm m)\,(-\cos(30.0^\circ)\,\hat\imath - \sin(30.0^\circ)\,\hat\jmath) \\\\ \hat R = (2.00\,\mathrm m) \,\hat\imath - (3\sqrt3\,\mathrm m)\,\hat\jmath \\\\ \hat R \approx \boxed{(2.00\,\mathrm m)\,\hat\imath - (5.20\,\mathrm m)\,\hat\jmath}\)

The magnitude of the resultant is

\(\|\hat R\| = \sqrt{(2.00\,\mathrm m)^2 + (-5.20\,\mathrm m)^2} \approx \boxed{5.57\,\mathrm m}\)

The direction or angle the resultant makes with the positive horizontal axis is \(\theta\) such that

\(\tan(\theta) \approx \dfrac{-5.20\,\mathrm m}{2.00\,\mathrm m} \approx -2.60\)

Note the signs of the \(\hat\imath\) and \(\hat\jmath\) components of \(\hat R\). They tell us that \(\hat R\) points into the fourth quadrant, and this means we can take the inverse tangent of both sides without any extra steps*. We then get

\(\theta \approx \tan^{-1}(-2.60) \approx \boxed{-67.0^\circ}\)

* There would have been an extra step if \(\hat R\) were pointing into either the second (negative \(\hat\imath\), positive \(\hat\jmath\)) or third quadrant (both negative \(\hat\imath\) and \(\hat\jmath\)). The inverse tangent function has a range of -90° to 90°, which means upon taking the inverse tangent of both sides of

\(\tan(\theta) = \dfrac{R_y}{R_x} \implies \theta = \tan^{-1}\left(\dfrac{R_y}{R_x}\right)\)

we would only recover some angle \(\theta\) between -90° and 90°. Yet our resultant must have some angle between -180° and -90°, or between +90° and +180° to belong to quadrant II or III. To get around this, we add an appropriately chosen multiple of 180° to the right side after taking the inverse tangent.

Be sure to answer all parts. chlorine has two naturally occurring isotopes, 35cl and 37cl. what is the mass number of each? how many protons, neutrons, and electrons are present in each?

Answers

Chlorine has two naturally occurring isotopes, \(^{35}Cl\) and \(^{37}Cl\).

What is the mass number,  number of  protons, neutrons, and electrons are present in \(^{35}Cl\)?

The mass number of \(^{35}Cl\) is 35.

The number of protons present in \(^{35}Cl\) is 17.

The number of neutrons present in \(^{35}Cl\) is 18.

The number of electrons present in \(^{35}Cl\) is 17.

What is the mass number,  number of  protons, neutrons, and electrons are present in \(^{37}Cl\)?

The mass number of \(^{37}Cl\) is 37.

The number of protons present in \(^{37}Cl\) is 17.

The number of neutrons present in \(^{37}Cl\) is 20.

The number of electrons present in \(^{37}Cl\) is 17.

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partes son de un estadio de futbol

Answers

Las dos líneas más largas del terreno de juego se denominarán líneas de banda. Las dos más cortas se llamarán líneas de meta. El terreno de juego será rectangular y la longitud de las líneas de banda deberá ser mayor que las de las líneas de meta. La longitud de la línea de banda debe tener como mínimo 90 metros y como máximo 120 metros. La anchura de la línea de meta debe de tener como mínimo 45 metros y como máximo de 90 metros. Todas las líneas del terreno de juego deberán se líneas continuas y tener la misma anchura, como máximo 12 cm., menos las líneas de meta que deben tener la misma anchura que los postes y larguero de la portería. Todas las líneas que delimitan al campo forma parte del terreno de juego. El terreno de juego puede ser de tierra, césped natural ó césped artificial de color verde según las normas del reglamento de la competición. El terreno de juego está dividido en dos partes iguales por una línea que unirá los puntos medios de las dos líneas de banda. El centro del campo estará marcado con un punto situado en la mitad de la línea media que divide las dos partes iguales del campo, tomando este punto como centro, haremos circulo de un radio de 9,15 metros. También se puede poner un banderín en cada extremo de la línea de media, a una distancia mínima de 1 m al exterior de la línea de banda.

Two football players are running towards each other in a straight line (exact opposite directions). Player A is running at 3.3 m/s and has a mass of 105 kg. Player B is 126 kg. The players collide and their net momentum after the collision is 0 Ns. How fast was Player B running before they collided? QUESTION 2 If the gauge pressure reads 33psi and the ambient pressure is 13psi, what is the absolute pressure? Not enough information to determine. 20psi
46psi
33psi

QUESTION 3 If fluid pressure through an artery is high, that means that more blood volume flows through the artery every second. True False

Answers

Two football players are running towards each other in a straight line (exact opposite directions). Player A is running at 3.3 m/s and has a mass of 105 kg. Player B is 126 kg.

The players collide and their net momentum after the collision is 0 Ns. How fast was Player B running before they collided? The law of conservation of momentum states that in a closed system, the total momentum remains constant. Therefore, the total momentum of both players before collision equals the total momentum of both players after collision. This means: mA * VA + mB * VB = (mA + mB) * V, where VA and VB are the initial velocities of A and B, respectively, and V is their final velocity after the collision (which is 0).

So, we can rearrange the above equation to solve for VB. VB = (mA * VA) / mB Here, mA = 105 kg and VA = 3.3 m/s, and mB = 126 kg. Substituting the values, we get: VB = (105 * 3.3) / 126= 2.75 m/s Therefore, Player B was running at 2.75 m/s before they collided.

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a boat ended up with a velocity of 30.m/s [N30.E] after it experienced an acceleration of 3.0m/s^2 [S] for a period of 4.0s what displacement did the boat cover

Answers

Answer:

  96 m

Explanation:

The average velocity over those 4 seconds is the velocity after 2 seconds:

  30 m/s -(2 s)(3.0 m/s^2) = 24 m/s

The displacement is the product of this average velocity and the duration of the acceleration:

  d = (24 m/s)(4 s) = 96 m

The boat covered 96 m while being accelerated.

A RAU80 with 4-lanes and a design radius of 300m requires a spiral-circular curve-spiral transition system, the deflection angle at the Point of Intersection is 16d30m14.0s.
a) Using Superelevation and Minimum Spiral Parameters, emax = 0.06 m/m what is the minimum recommended spiral parameter?
b) Determine the distance P
c) Determine the distance Q
d) Determine the angle Φs
e) Determine the distance Tc

Answers

A) Minimum recommended spiral parameter: 150.03m.

b) Distance P: 150.03m.

c) Distance Q: 4.122m.

d) Angle Φs: 16°30'14.0".

e) Distance Tc: 150.03m.

a) Calculation for the minimum recommended spiral parameter:

Design radius (R) = 300 m

Maximum superelevation (e_max) = 0.06 m/m

Spiral Parameter (A) = (R + e_max) / 2

A = (300 m + 0.06 m/m) / 2

A ≈ 150.03 m

b) Calculation for the distance P:

Distance P is equal to the length of the first spiral curve, which is the same as the minimum recommended spiral parameter.

P ≈ 150.03 m

c) Calculation for the distance Q:

Distance Q represents the length of the circular curve. It is given by the formula:

Q = (Deflection angle at Point of Intersection) / (Degree of Curve, D)

Deflection angle at Point of Intersection = 16°30'14.0"

Converting the angle to decimal degrees:

16° + (30'/60) + (14.0"/3600) = 16.504°

Q = 16.504° / (360° / D)

Q ≈ D / 21.814

Since the RAU80 has 4 lanes, the degree of curve (D) is 360° / 4 = 90°.

Q ≈ 90° / 21.814

Q ≈ 4.122 m

d) Calculation for the angle Φs:

The angle Φs is the deflection angle at the Point of Intersection.

Φs = 16°30'14.0"

e) Calculation for the distance Tc:

Distance Tc is equal to the length of the second spiral curve, which is the same as the minimum recommended spiral parameter.

Tc ≈ 150.03 m

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a 30 kg cart is travelling in a zero friction environment at a constant velocity of 5m/s. It's about to go up a very steep hill. How high will the cart be when the velocity changes to zero? PLEASE HELP

Answers

Answer:

1.27551m

Explanation:

This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.

Thus, we get:

\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)

We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)

One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.

\(KE_{initial} = PE_{final}\)

Plugging in:

\(\frac{1}{2}*30*5^2 = 30*9.8*h\)

Solving for h, we get 1.27551m

within most of the temperature range that we find liquid water on earth, what happens to the density of that water as its temperature decreases?

Answers

As the temperature of liquid water on Earth decreases within most of its temperature range, its density increases.

This is because as the temperature decreases, the water molecules move slower and come closer together, making the water more dense. However, this trend reverses as the temperature approaches 4°C, where the density of water reaches its maximum. Below 4°C, the density of water decreases as it freezes and its molecules form a crystalline structure that takes up more space.

This unique property of water allows it to form ice that floats on the surface of bodies of water, insulating the water below and allowing life to thrive in aquatic environments even in cold temperatures.

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Please Help!!! I WILL GIVE BRAINLIEST!!!! An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C and separation between the charged plates is 2.0 cm. a.) Determine the horizontal distance traveled by the electron when it hits the plate. b.)Determine the velocity of the electron as it strikes the plate.

Answers

Answer:

a. 9.52 cm b. 4.34 × 10⁶ m/s

Explanation:

a. The horizontal distance traveled by the electron when it hits the plate.

The electric force F on the electron due to the electric field E of mass, m is

F = -eE = ma

a = -eE/m where a = acceleration of electron

The vertical distance moved by the electron is given by

Δy = ut +1/2at²

u = initial vertical velocity = 0. and take the top plate as y = 0 and bottom plate as y

So,

0 - y = 0 × t + 1/2at²

-y = 1/2at²

substituting a = -eE/m

-y = 1/2(-eE/m)t²

y = eEt²/2m

making t subject of the formula,

t = √(2ym/eE) where t is the time it takes to reach the bottom plate.

Since E = 4.0 × 10² N/C, y = distance between plates = 2.0 cm = 0.02 m, m = 9.109 × 10⁻³¹kg and e = 1.602 × 10⁻¹⁹ C

t = √[(2 × 0.02 m × 9.109 × 10⁻³¹kg)/(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C)]

t =  √[(0.36436 × 10⁻³¹kgm)/(6.408 × 10⁻¹⁷ N)]

t = √[(0.0569 × 10⁻¹⁴kgm/N)t

t = 0.238 × 10⁻⁷ s

t = 23.8 × 10⁻⁹ s

t = 23.8 ns

The horizontal distance moved when it hits the plates x = vt where v = initial horizontal velocity = 4.0 × 10⁶ m/s

x = 4.0 × 10⁶ m/s × 23.8 × 10⁻⁹ s

= 0.0952 m

= 9.52 cm

b. The velocity of the electron as it strikes the plate.

To find the velocity of the electron as it strikes the plates, we calculate its final vertical velocity V as it strikes the plate. This is gotten from

v' = u + at since u = 0,

v' = at

= -eEt/m

= -(1.602 × 10⁻¹⁹ C × 4.0 × 10² N/C × 0.238 × 10⁻⁷ s)/9.109 × 10⁻³¹kg

= -1.525 × 10⁻²⁴ Ns/9.109 × 10⁻³¹kg

= -0.167 × 10⁷ m/s

= -1.67 × 10⁶ m/s

So, the resultant velocity as it strikes the plate v = √(v'² + v²)

= √((-1.67 × 10⁶ m/s)² + (4 × 10⁶ m/s)²)

= √(2.7889  + 16) × 10⁶ m/s

= √18.7889 × 10⁶ m/s

= 4.335 × 10⁶ m/s

≅ 4.34 × 10⁶ m/s

Show that the number of photons per unit volume in a photon gas of temperature T is approximately (2×107 K−3m−3)T3. (Note: ∫0[infinity]​x2(ex−1)−1dx≅2.40.)

Answers

The number of photons per unit volume in a photon gas of temperature T is approximately (2×10^7 K^−3 m^−3)T^3.

What is the expression for the number of photons in a photon gas?

In a photon gas, the number of photons per unit volume can be approximated using the Bose-Einstein distribution. The distribution function for photons is given by:

n(V,T) = [8π/(c^3h^3)] ∫[0,∞] x^2/(ex - 1) dx

where n(V,T) is the number of photons per unit volume, V is the volume, T is the temperature, c is the speed of light, and h is the Planck's constant.

To evaluate this integral, we can use the approximation:

∫[0,∞] x^2/(ex - 1) dx ≅ 2.40

Substituting this value into the expression for n(V,T), we have:n(V,T) ≅ (8π/(c^3h^3)) * 2.40

Simplifying further, we get:

n(V,T) ≅ (2.40 * 8π/(c^3h^3))

Since the quantity (8π/(c^3h^3)) is a constant, we can represent it as a single constant term:

n(V,T) ≅ K * T^3

where K is the constant (2.40 * 8π/(c^3h^3)). Therefore, the number of photons per unit volume in a photon gas of temperature T is approximately (2×10^7 K^−3 m^−3)T^3.

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is newton third law accurate for electric forces?

Answers

An object with greater charge will exert a greater force on an object than an object with smaller charge would. However, if you consider two charges that exert a force on each other, regardless of the magnitude of charge, both charges will exert an equal force on each other because of Newton's third law.

Explain why the coin is able to float on top of the water in this glass.

Answers

Answer:

Surface tension is the result of water molecules pulling inward with a strong attractive force. This attractive force brings the molecules on the surface of the water close together and causes the surface of the water to be drawn toward the water molecules beneath the surface. Since there are no water molecules above the surface, there are uneven forces. This causes surface tension, allowing the coin to float on the water’s surface.

Explanation:

Brainliest pls

The table shows information about four students who are running around a track. Which statement is supported by the information in the chart?

Autumn has more kinetic energy than Chiang.
Mohammed has less kinetic energy than Autumn.
Lexy has more kinetic energy than Mohammed.
Chiang has less kinetic energy than Lexy.

The table shows information about four students who are running around a track. Which statement is supported

Answers

Answer:

Correct option: Mohammed has less kinetic energy than Autumn.

Explanation:

Kinetic Energy

Is the energy an object has due to its motion. If the object has a mass m and travels at a speed v, then the kinetic energy K is:

\(\displaystyle K=\frac{1}{2}mv^2\)

The information about four students includes their mass and velocity as follows:

Autumn has a mass of m1=50 kg and a velocity (magnitude) of v1=4 m/s, thus their kinetic energy is:

\(\displaystyle K_1=\frac{1}{2}50\cdot 4^2\)

\(K_1=400\ J\)

Mohammed has a mass of m2=57 kg and a velocity (magnitude) of v2=3 m/s, thus their kinetic energy is:

\(\displaystyle K_2=\frac{1}{2}57\cdot 3^2\)

\(K_2=256.5\ J\)

Lexy has a mass of m3=53 kg and a velocity (magnitude) of v3=2 m/s, thus their kinetic energy is:

\(\displaystyle K_3=\frac{1}{2}53\cdot 2^2\)

\(K_3=106\ J\)

Chiang has a mass of m4=64 kg and a velocity (magnitude) of v4=5 m/s, thus their kinetic energy is:

\(\displaystyle K_4=\frac{1}{2}64\cdot 5^2\)

\(K_4=800\ J\)

Sorted from lower kinetic energy to higher:

Lexy, Mohammed, Autumn, Chiang. Thus:

Autumn has more kinetic energy than Chiang. False

Mohammed has less kinetic energy than Autumn. True

Lexy has more kinetic energy than Mohammed. False

Chiang has less kinetic energy than Lexy. False

Correct option: Mohammed has less kinetic energy than Autumn.

Answer:

its b

Explanation:

got in right on edge

how fast does sound travel through glass in meters per second (m/s)

Answers

The sound travelled through glass in meters per second (m/s) is 4540 m/s .Because air is so easy to compress.

The typical glass material is not only much denser but also much stiffer than air. For air the sound speed is around 330 m/s under conventional circumstances. Sound speeds range from 2000 m/s to 6000 m/s for the majority of typical glass materials, depending on the type of glass and the type of sound.

Can sound travel through glass?

Windows are one of the most common sources of exterior noise intrusion from everyday irritants like pedestrians, traffic, and construction because glass easily transmits sound vibrations.

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the average power output of the human heart is 1.33 w . how much energy does the heart produce in a day?

Answers

The energy produced by the heart in a day when the power output of the heart is given is calculated to be 1.15 × 10⁵ J.

Given that,

Power output of human heart = 1.33 W

Time in one day = 24 hours = 24×60 min = 24×60×60 s = 86400 s

Energy produced by heart in a day = ?

The expression for energy, power and time is given as, E = P t

where, P is power

t is time

E is energy

The energy it produces is equal to the power output times the time the heart does work.

E = P t = 1.33 × 86400 = 1.14912 × 10⁵ J ≈ 1.15 × 10⁵ J

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What is the anomalous expansivity of water

Answers

Answer:

The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4°C to 0°C, and it becomes less dense. The density becomes less and less as it freezes because molecules of water normally form open crystal structures when in solid form.

A 7.40-kg object initially has 347 J of gravitational potential energy. Then an elevator lifts the object a distance of 20.6 m above its previous position. How much work did the elevator perform on the object?

Answers

Answer:

W = 1493.9 J = 1.49 KJ

Explanation:

The work done by the elevator on the object will be equal to the gain in is potential energy:

W = ΔP.E

W = mgΔh

where,

W = Work = ?

m = mass of object = 7.4 kg

g = 9.8 m/s²

Δh = gain in height = 20.6 m

Therefore,

W = (7.4 kg)(9.8 m/s²)(20.6 m)

W = 1493.9 J = 1.49 KJ

in a 4-pole, 60 hz, 200v inudction motor having a full-load current of 350 a, torque developed is 700 n-m. what is the approximate speed of the motor

Answers

The approximate speed of the motor is 1800 RPM.

To determine the approximate speed of the motor, we can use the formula:

Speed (in RPM) = (120 x Frequency) / Number of Poles

The speed of the motor is calculated by the ratio of the product of 120 and frequency by the number of poles. the speed is measured in rotation per minute.

Given information:

Frequency (f) = 60 Hz

Number of Poles (p) = 4

Using the formula, the speed will be calculated as:

Speed = (120 x 60) / 4

Speed = 1800 RPM

Therefore, the approximate speed of the motor is 1800 RPM.

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7) You think you have found a diamond. Its mass is 5.28 g and its volume is 2 cm3. Calculate the density
and say if it is a diamond or not.

Answers

Answer:

\(\boxed {\tt d=2.64 \ g/cm^3}\)

\(\boxed {\tt Not \ a \ diamond}\)

Explanation:

Density can be found by dividing the mass by the volume.

\(d=\frac{m}{v}\)

The mass is 5.28 grams and the volume is 2 cubic centimeters.

\(m=5.28 \ g\\v= 2 \ cm^3\)

Substitute the values into the formula.

\(d=\frac{5.28 \ g }{2 \ cm^3}\)

Divide.

\(d=2.64 \ g/c^3\)

The density of the unknown substance is 2.64 grams per cubic centimeter.

The density of a diamond is about 3.5 grams per cubic centimeter. Since 2.64 is not equal to 3.5, the unknown substance is not a diamond.

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