Are the following combinations allowed? If not, show two ways to correct them:
(b) n=4 ; l=3 ; ml=-1

A single substitution reaction a strip or zinc metal is added to a copper(II) nitrate solution. Copper will be pushed out of the solution by zinc. As a result, zinc nitrate, Zn(NO3)2, and copper metal, Cu, produced.

An illustration of a single substitution reaction is the reaction of potassium (K) and water (H2O). In the process, hydrogen gas (H2) is released and potassium hydroxide (KOH), a colourless solid chemical, formed. 2K + 2H2O 2KOH + H is the reaction's equation.

This page explains the Copper II Nitrate formula, sometimes referred to as Cupric nitrate or Copper Dinitrate formula. This inorganic substance exists as a solid with blue crystals. Cu(NO3)2 is the chemical formula for Copper II Nitrate.

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There were 1.58 x 10^20 atoms of calcium left on the paper.

To determine the number of calcium atoms in CaCO3, we first need to know the molecular formula weight of CaCO3, which is 100.0869 g/mol.

Then, we can use this formula to calculate the number of moles of CaCO3:

moles of CaCO3 = mass of CaCO3 / molecular weight of CaCO3

mass of CaCO3 = (1.57 x 10^22 atoms) x (100.0869 g/mol / 6.022 x 10^23 atoms/mol) = 2.62 x 10^-2 g

Now we can calculate the number of moles of CaCO3:

moles of CaCO3 = 2.62 x 10^-2 g / 100.0869 g/mol = 2.62 x 10^-4 mol

number of calcium atoms = moles of CaCO3 x Avogadro's number

number of calcium atoms = 2.62 x 10^-4 mol x 6.022 x 10^23 atoms/mol = 1.58 x 10^20 atoms

Therefore, there were 1.58 x 10^20 atoms of calcium left on the paper.

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Answer:

erm-- how do i answer this question xd

Explanation:

Gaining of an electron is most exothermic for Fluorine.

N2(g)+O2(g)→2NO(g) is an endothermic response because heat is absorbed on this reaction. all of the other reactions are exothermic as the warmth is launched for the duration of the method.

Any manner that absorbs warmness from its environment is an endothermic system. consequently, all endothermic reactions are endothermic strategies. An endothermic reaction is any chemical response that absorbs warmth from its surroundings. The absorbed electricity provides the activation electricity for the reaction to arise.

Fluorine is important for the manufacturing of nuclear material for nuclear power vegetation and for the insulation of electrical towers. Hydrogen fluoride, a compound of fluorine, is used to etch glass. Fluorine, like Teflon, is used to make plastics and is also essential in dental fitness.

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Option A,  Ninhydrin is a chemical that is used to detect the presence of amino acids in a sample. It reacts with the amino acids in a sample, such as skin, to form a complex that is blue in color.

Ninhydrin is a chemical that is used to detect the presence of amino acids in a sample. It reacts with the amino acids in a sample, such as skin, to form a complex that is blue in color. This is because when Ninhydrin reacts with an amino acid it forms a complex with the nitrogen in the amino group, and this complex is blue in color. It is also commonly used in forensic science to detect fingerprints, as fingerprints contain amino acids from the oils and sweat on the skin. The blue coloration of the skin is an indication of the presence of amino acids, which are found in many biological molecules such as proteins and enzymes.

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The mass transfer rate of CO₂ through the tube is 0.0584 g/s.

We can use Fick's Law of Diffusion to calculate the mass transfer rate of CO₂ through the tube:

J = -D * dC/dx

where J is the mass transfer rate, D is the diffusion coefficient, and dC/dx is the concentration gradient.

First, we need to calculate the diffusion coefficient of CO₂ in N₂ at 298 K. We can use the Wilke-Chang equation for this:

\(D12 = (1.013 * 10^-^5) * (T/M)^0^.^5 * (1/φ1 + 1/φ2) * (M1/M2)^0^.^5\)

where D12 is the diffusion coefficient of CO₂ in N₂, T is the temperature in K, M is the molar mass in g/mol, φ is the viscosity, and the subscripts 1 and 2 refer to CO₂ and N₂, respectively.

At 298 K, the molar masses and viscosities of CO₂ and N₂ are:

M_CO₂ = 44.01 g/mol

M_N₂ = 28.01 g/mol

φ_CO₂ = 0.0000178 Pa s

φ_N₂ = 0.0000172 Pa s

Substituting these values into the Wilke-Chang equation, we get:

D12 = 0.148 cm²/s

Next, we need to calculate the concentration gradient of CO₂. We can use the equation:

dC/dx = (C2 - C1) / L

where C1 and C2 are the partial pressures of CO₂ at the two ends of the tube, and L is the length of the tube.

Substituting the given values, we get:

dC/dx = (50 Torr - 100 Torr) / (1 m) = -50 Torr/m

Finally, we can calculate the mass transfer rate:

J = -D * dC/dx * A

where A is the cross-sectional area of the tube.

Substituting the values, we get:

J = -0.148 cm₂/s * (-50 Torr/m) * π*(0.5 cm)₂ = 0.0584 g/s

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As the first blank is already filled, this first property is called the Cohesive property of water, which is what makes it possible to clump together into drops, due to their intermolecular forces.

The second blank is talking about density, and as we can see in our daily lives, ice is less dense than water, therefore in this blank liquid water will be MORE dense than ice, this is due to the hydrogen bonds and the orientation in which they are causing the molecules to push farther apart.

As we have discussed in the second blank, this 3rd blank is ICE FLOATS

Explanation:

area of triangle is 1÷2 base xheight

\(1 \div 2 \times45 \times 11 \\ = 247.5\)

Answer:

Mass of butane = 1.87 g

Explanation:

Form a balanced chemical equation for the reaction stated:

C₄H₁₀ + 13/2 O₂ → 4CO₂ + 5H₂O

Number of moles of CO₂

\( = \frac{mass}{molar \: mass} \)

\( = \frac{15}{12 + 2(16)} \)

\( = 0.34 \: mol\)

From the equation,

1 mol C₄H₁₀ : 4 mol CO₂

0.085 mol C₄H₁₀ : 0.34 mol CO₂

Mass of butane

\( = number \: of \: moles \times molar \: mass\)

\( = 0.085 \times (12 + 10(1))\)

\( = 1.87 \: g\)

The grams of butane must be burned in an excess of Oxygen, to produce 15g of CO₂ is 1.87 grams.

Relation between mass and moles will be represented as:

n = W/M, where

W = require or given mass

M = molar mass

Given balance chemical reaction is:

C₄H₁₀ + 13/2O₂ → 4CO₂ + 5H₂O

Moles of 15g of CO₂ = 15g / 44g/mol = 0.34 moles

From the stoichiometry of the reaction, it is clear that:

4 moles of CO₂ = produced by 1 mole of C₄H₁₀

0.34 moles of CO₂ = produced by 1/4×0.34=0.085 moles of C₄H₁₀

Now we convert moles of butane to mass as:

W = (0.085)(22) = 1.87 g

Hence required mass of butane is 1.87 grams.

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Answer:

Jane and Matt inherited eye color from their mother.

Explanation:

Their mom has brown eyes, and both jane and matt have brown eyes. They didnt get the eye color from their father.

The number of calories required for 47.5g of Al to go from 25 to 62 is 3,689.9 cal.

Calories are a measure of energy. They are the amount of energy that is released when food is digested, broken down and converted into energy for the body to use. The energy from calories is used to fuel physical activities, as well as all the bodily functions that keep us alive. Eating food is the main source of calories, although some drinks also contain calories. Different types of food contain different amounts of calories. Foods that are high in fat and sugar tend to contain more calories.

Calories (cal) = Heat (J) / 4.184
Heat (J) = Mass (g) x Specific Heat (J/g C) x Change in Temperature (C)
Heat (J) = 47.5g x 0.900 J/g C x (62 - 25) C
Heat (J) = 15,495 J
Calories (cal) = 15,495 J / 4.184
Calories (cal) = 3,689.9 cal.

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water is to gas as liquid is to solid

The mini marshmallows would extend to a height of 1.843 x 10 km above the surface of Colorado if they covered the state without any space between them.

To find the height of an Avogadro number of Marshmallows, first, we need to find the total volume of all the mini marshmallows.

Each mini marshmallow has a diameter of 0.635 cm and a height of 2.54 cm, so its volume can be calculated as:

V = πr²h

Volume = π * (0.3175 cm) * (2.54 cm)

Volume = 0.8217 cm³

Avogadro's number is 6.02 x 10²³, so the total volume of all the mini marshmallows can be calculated as:

Total volume = 6.02 x 10²³ * 0.8217 cm³

Total volume = 4.947 x 10³ cm³

Now we can use the land area of Colorado to find the height to which the mini marshmallows would extend if packed together without any space between them.

1.037 x 10⁵ mi² is equal to (1.037 x 10⁵ mi² * 2.59 x 10⁶  = 2.685 x 10¹¹ m²

If the mini marshmallows cover this area without any space between them, their height can be calculated as:

Height = total volume/area

Height = (4.947 * 10²³ cm³) / (2.685 x 10¹¹ cm²)

Height = 1.843 x 10² cm

Converting to kilometers, we get:

Height = (1.843 x 10¹ ²cm) / (100,000 cm/km)

Height = 1.843 x 10⁷ km

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we are given the pH of the solution as 3.17 are we are required to find the [H₃O+]

we know that :

pH = - log[H₃O+]

-pH = log[H₃O+]

10⁻ᵖᴴ = 10ˡᵒᵍ[ᴴ₃ᴼ⁺]

10⁻ᵖᴴ = [H₃O+]

therefore:

10⁻³.¹⁷ = [H₃O+]

6.8x10⁻⁴ M = [H₃O+]

therefore the [H₃O+] is 6.8x10 minus 4 Molar

The reaction that take place when active metals react with acids are:

Active metals are those metals which are very reactive and are found high above hydrogen in the activity series of metals.

The reactivity of metals is determined by the ability of the meta to give up electrons to form positive ions called cations.

Therefore, active metals are those metals that readily give up their electrons to form cations.

The active metals are found in the group 1A and 2A and 3A of the periodic table.

The active metals include; sodium, potassium, calcium, aluminum, magnesium, zinc etc.

The active metals react with dilute acids to displace hydrogen, resulting in the evolution of hydrogen gas.

Considering the given equations, the reactions of the active metals are:

Mg (s) + 2HCl (aq) → MgCl₂ (aq) + H₂ (g)

Zn (s) + 2 HCl (aq) → ZnCl₂ (aq) + H₂ (g)

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Answer:

scientific community's consensus on the human causes of global climate change

Explanation:

Answer:

c. H2 andO2

I think this is the answer not sure ok

Answer:

34545 J

Explanation:

Applying,

E = mc'+cm(t₂-t₁)+Cm(t₂-t₀).............. Equation 1

Where E = Total energy, m = mass of the ice, c' = latent heat of ice, c = specific heat capacity of ice, t₂ = final temperature, t₁ = initial temperature, C = specific heat capacity of water, t₀ = temperature of ice at 0°C

From the question,

Given: m = 35 g = 0.035 kg, t₁ = -10°C, t₂ = 100°C, t₀ = 0°C

Constant: C = 4200 J/kg.K, c = 2100 J/kg.K, c' = 336000 J/kg

Susbtitute these values into equation 1

E = [336000(0.035)]+[0.035×2100(100+10)]+[4200×0.035(100-0)]

E = 11760+8085+14700

E = 34545 J

The pH before any base is added to the butanoic acid solution is 10. The concentration of H₂SO₄ is 0.234 M.

a) To find the pH before any base is added to the butanoic acid solution, we need to calculate the concentration of H⁺ ions using the dissociation of butanoic acid:

CH₃CH₂CH₂COOH ⇌ H⁺ + CH₃CH₂CH₂COO⁻

The initial concentration of butanoic acid is 0.150 M, and the Ka of butanoic acid is \(1.5 \times 10^{-5}\).

Using the equation for Ka:

\(Ka = \frac {[H^+] [CH_{3}CH_{2}CH_{2}COO^-]}{[CH_{3}CH_{2}CH_{2}COOH]}\)

Since the initial concentration of butanoic acid is equal to the concentration of CH₃CH₂CH₂COOH, we can assume that the concentration of H⁺ at equilibrium will be negligible compared to the initial concentration of butanoic acid. Therefore, we can approximate the initial concentration of H⁺ as 0.

Using the equation for Ka:

\(Ka = \frac {[H^+] [CH_{3}CH_{2}CH_{2}COO^-]}{[CH_{3}CH_{2}CH_{2}COOH]}\)

Since [H⁺] = 0, we can rearrange the equation to solve for [CH₃CH₂CH₂COO⁻]:

\([CH_{3}CH_{2}CH_{2}COO^-] = \frac {Ka}{[CH_3CH_2CH_2COOH]}\)

             \(= \frac {(1.5 \times 10^{-5})}{(0.150)}\)

            \(= 1 \times 10^{-4}\)

Taking the negative logarithm (pOH) of [CH₃CH₂CH₂COO⁻]:

\(pOH = -log_{10}([CH_{3}CH_{2}CH_{2}COO^-])\)

   \(= -log_{10}(1 \times 10^{-4})\)

   = 4

Since pH + pOH = 14, we can find the pH:

pH = 14 - pOH

  = 14 - 4

  = 10

Therefore, the pH before any base is added to the butanoic acid solution is 10.

b) To determine the concentration of H2SO4, we can use the stoichiometry of the reaction between H2SO4 and NaOH:

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

The balanced equation shows that 1 mole of H₂SO₄ reacts with 2 moles of NaOH. From the volume of NaOH required to reach the equivalence point (62.5 mL), we can calculate the number of moles of NaOH used:

moles of NaOH = 0.375 M NaOH (0.0625 L NaOH)

                          = 0.0234 mol NaOH

Since the stoichiometry is 1:2 for H2SO4 to NaOH, the number of moles of H₂SO₄ present in the solution is half the number of moles of NaOH used:

moles of H₂SO₄ = 0.0234 mol NaOH / 2

                          = 0.0117 mol H2SO4

To calculate the concentration of H2SO4, we divide the moles of H₂SO₄ by the volume of the solution:

concentration of H₂SO₄ = 0.0117 mol H2SO4 / 0.0500 L solution

                                        = 0.234 M

Therefore, the concentration of H₂SO₄ is 0.234 M.

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Answer:

539.3mmHg of H₂

179.7mmHg of N₂

Explanation:

Ammonia, NH₃, reacts completely producing N₂ and H₂ thus:

2 NH₃ → N₂ + 3H₂

That means there are produced 4 moles of gases and 3 are of H₂ and 1 of N₂

Total pressure (Sum of pressures of N₂ and H₂) is 719mmHg. 3 parts are of H₂ and 1 of H₂

Thus, partial pressures of the products after reaction are:

719mmHg ₓ (3 H₂ / 4) = 539.3mmHg of H₂

719mmHg ₓ (1 N₂ / 4) = 179.7mmHg of N₂

The resistance of a nickel silver wire that is 25 cm long and has a cross-sectional area of 0.05 m² is 0.000425 Ω (or 4.25 × 10⁻⁴ Ω).

The formula for calculating the resistance of a wire is:R=ρL/ATo find the resistance of a nickel silver wire that is 25 cm long and has a cross-sectional area of 0.05 m², we will need to use the formula.

R = ρL/A

Where R is resistance, ρ is resistivity, L is the length of the wire, and A is the cross-sectional area.

We are also given the following constants:

Resistivity of nickel silver = 8.5 × 10⁻⁸ Ωm

Length of wire = 25 cm

= 0.25 m

Cross-sectional area of wire = 0.05 m²

Now we can substitute the given values into the formula and solve for R:

R = (8.5 × 10⁻⁸ Ωm) × (0.25 m) / (0.05 m²)R

= 0.000425 Ω or 4.25 × 10⁻⁴ Ω

Therefore, the resistance of a nickel silver wire that is 25 cm long and has a cross-sectional area of 0.05 m² is 0.000425 Ω (or 4.25 × 10⁻⁴ Ω) (to 3 significant figures).

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Answer:

1

Explanation:

Maximum value of azimuthal quantum number (l) = (n-1)

Value of azimuthal quantum number can never be equal to principal quantum number

In general, single-displacement reactions are more reactive compared to synthesis and decomposition reactions. In terms of energy involved, single-displacement reactions require the least amount of energy to take place.

The energy that is involved in chemical reactions is the energy required to break the bonds of the reactants as well as the energy that is released when the new bonds form during the creation of the products. In synthesis and decomposition reactions, more energy is required compared to single-displacement reactions.

Synthesis reactions combine two or more reactants to form a single product. This process requires energy to break the bonds in the reactants and additional energy to create the bonds between the new atoms in the product. In contrast, decomposition reactions involve breaking down a single compound into two or more simpler products. This process requires energy to break the bonds within the compound, which is generally more energy than is required in a single-displacement reaction.

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Answer:

equal

Explanation:

According to the law of conservation of matter, the number of atoms before and after a chemical reaction should be equal, such that no atoms are, under normal circumstances, created or destroyed.

Answer:

the molecules in a liquid don't move apart.

Explanation:

The molecules of a gas move apart when they collide. The average kinetic energy of the particles in a liquid (or solid) is small enough that the forces of attraction between them is sufficient to hold the particles close together. The molecules in a liquid (or solid) do not move apart.

Answer: When a gas changes to a liquid, the molecules in the gas lose some of their kinetic energy and their molecular attraction increases.

Explanation:

In a gas, the molecules are moving around rapidly and colliding with each other and with the walls of the container. These collisions create pressure, and the average kinetic energy of the molecules is high. However, when the gas cools down, the average kinetic energy of the molecules decreases, and they move around more slowly.

As the gas cools down further, the molecules start to come closer together, and the intermolecular attractive forces become more important. Eventually, the attractive forces between the molecules become strong enough to overcome the kinetic energy of the molecules, and the gas condenses into a liquid.

In a liquid, the molecules are still in motion, but they are much closer together and have much lower average kinetic energy than in a gas. The attractive forces between the molecules are strong enough to keep them close together in a fixed volume, but not so strong that they are unable to move around freely.

When, pH of the resulting solution is 2.41. Then, the Ka for the weak acid is 1.75 × 10⁻⁴.

The first step is to set up the balanced equation for the ionization of the weak acid;

HA + H₂O ⇌ A⁻ + H₃O⁺

Next, write out the expression for the acid dissociation constant, Ka;

Ka = [A⁻][H₃O⁺] / [HA]

Since the concentration of the weak acid is given as 0.0194 M, we can assume that the initial concentration of HA is 0.0194 M. Let x be the concentration of H₃O⁺ ions and A⁻ ions formed when the acid dissociates.

HA + H₂O ⇌ A⁻ + H₃O⁺

Initial; 0.0194 M 0 0

Change; -x +x +x

Equilibrium; 0.0194 - x x x

We know that the pH of the solution is 2.41, so we can use the pH expression to find the concentration of H3O+ ions:

pH = -log[H₃O⁺]

2.41 = -log[H₃O⁺]

[H₃O⁺] = \(10^{(-2.41)}\)

= 6.43 × 10⁻³ M

Substitute the equilibrium concentrations into the Ka expression and solve for Ka;

Ka = [A-][H₃O⁺] / [HA]

Ka = (x)(6.43 × 10⁻³) / (0.0194 - x)

Since the weak acid is monoprotic, the concentration of A⁻ ions formed will be equal to the concentration of H₃O⁺ ions formed;

x = [A⁻] = 6.43 × 10⁻³ M

Substitute this value of x into the Ka expression and solve for Ka;

Ka = (6.43 × 10⁻³)² / (0.0194 - 6.43 × 10⁻³)

Ka = 1.75 × 10⁻⁴

Therefore, the Ka for the weak acid is 1.75 × 10⁻⁴.

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Answer:

A. 3

B . 2

C. 2

D. 2

E. 4 significant figures

Group B is incorrect,They most likely added too much acid .

Let's check the reaction

\(\\ \tt\hookrightarrow HCl+NaOH=NaCl+H_2O\)

Answer:

Explanation:

Answer

It's a very strong base. The closer you are to column 1 you are, the stronger the base.

#1

\(\\ \sf\longmapsto {}^{88}_{38}Sr^{2+}\)

#2

\(\\ \sf\longmapsto {}^{51}_{23}V^{3+}\)

#3

\(\\ \sf\longmapsto {}^{55}_{26}Fe^{3+}\)

#4

\(\\ \sf\longmapsto {}^{112}_{48}\)

#5

\(\\ \sf\longmapsto {}^{210}_{82}Pb^{2+}\)