Answer:
no, they are not the same
Finding Dimensional Formula For x=vt+1/2at is
Answer:
In the picture above.
Explanation:
I hope that it's a correct answer for dimensional analysis.
A group of students are doing an electrostatic experiment. One touches an electroscope with her finger, and a second student then brings a charged plexiglass rod near the electroscope but does not touch it. The first student removes her finger from the electroscope before the second student removes the plexiglass. Meanwhile a third student touches a different electroscope with a charged PVC pipe. Are both electroscopes charged? If so, are they the same charge or different charges? Explain your reasoning. Feel free to include any drawings or diagrams.
Answer:
a) If both are charged
b) the first team has a load and the second half of it
c) The first team has a charge contrary to the rod, it is charged by induction and the second team has a charge equal to the rod, it is charged by contact
Explanation:
For this exercise let's analyze the charge on each electroscope separately
electroscope 1
Suppose the student with her finger on the device is grounded,
When bringing the rod closer to the electroscope a charge is indexed, on the side of the rod on the opposite side there is the same charge but with the opposite sign, as the student is grounded, this charge passes to the ground, this side remains neutral.
When removing the finger, loads can no longer pass, and when removing the rod the load from this side distributes throughout the equipment, therefore it has a load of the same magnitude as the rod
Electroscope 2
In this case, the equipment is touched, so the load redistributes in the two, when separating it remains with half the load of the cheek.
After analyzing each device separately we can answer the questions.
a) If both are charged
b) the first team has a load and the second half of it
c) The first team has a charge contrary to the rod, it is charged by induction and the second team has a charge equal to the rod, it is charged by contact
A regulation soccer ball has a mass of 0.45 KG in order to accelerate the ball at a rate of 8 m/s2 how much force would you need to apply when you kick the ball? Show FUN AL 
This is an exercise in Newton's second law, also known as the law of force or law of dynamics, which states that the net force acting on an object is equal to the object's mass multiplied by its acceleration. This law describes how force affects the motion of an object and is one of the fundamental laws of physics used to describe the motion of objects.
Net force refers to the sum of all forces acting on an object. If the net force is zero, the object is in equilibrium and is not moving. If the net force is greater than zero, the object accelerates in the direction of the net force. This acceleration depends on the mass of the object and the magnitude of the net force.
The mathematical formula that represents Newton's second law is F = m × a, where F represents the net force acting on the object, m represents the mass of the object, and a represents its acceleration. It is important to keep in mind that force, mass, and acceleration are vector magnitudes, that is, they have direction and magnitude.
Force is measured in newtons (N), mass in kilograms (kg), and acceleration in meters per second squared (m/s²). Therefore, the resulting unit of net force is newtons.
We solve the exercise:
To solve the force you will need the regulation soccer ball.
We apply the formula:
F = m × a
It tells us that the ball has a mass of 0.45 kg to accelerate the ball at a rate of 8 m/s².
We substitute and solve:
F = m × a
F = (0.45 kg)(8 m/s²)
F = 3.6 N
Therefore, to accelerate the ball at a rate of 8 m/s², a force of 3.6 N needs to be applied.
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Answer:
You would need to apply a force of 3.6 Newtons when you kick the ball in order to accelerate it at a rate of 8 m/s².
Explanation:
The force required to accelerate the soccer ball can be calculated using Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) times its acceleration (a):
\(\sf\qquad\dashrightarrow F = m * a\)
In this case, the mass of the soccer ball is 0.45 kg and the desired acceleration is 8 m/s². Plugging these values into the equation above, we get:
\(\sf\qquad\dashrightarrow F = 0.45\: kg * 8\: m/s^2\)
\(\sf\qquad\dashrightarrow F = \boxed{\bold{\:\:3.6\: N\:\:}}\)
Therefore, you would need to apply a force of 3.6 Newtons when you kick the ball in order to accelerate it at a rate of 8 m/s².
Question 2 of 10
What happens to the resistance of a wire as its length increases?
A. The resistance is not affected by a change in wire length.
B. The resistance decreases.
C. The resistance alternates between high and low values.
D. The resistance increases.
Answer:
D. resistance increases
Explanation:
The relationship between resistance and wire length is directly proportional, meaning the longer the wire the greater the resistance.
Answer: The resistance increases.
Explanation: A wire's resistance is directly proportional to its length. This implies that as a wire's length increases, so does its resistance. The following formula describes this relationship:
R = ρ (L/A)
where L is the wire's length, A is its cross-sectional area, R is the wire's resistance, and ρ is the wire material's resistivity.
This formula shows that the resistance will rise when the wire's length is extended while its cross-sectional area remains the same. On the other hand, if we shorten the wire, the resistance will rise. As a result, choice D is the right response.
In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.
Answer:
\(CPD = 80\)
\(PCD = 44\)
Explanation:
Given
\(AB || CD\)
\(BAD = 56\)
\(CPA = 100\)
See attachment
Required
Determine PCD and CPD
First, we need to calculate CPD
Since DPA is a straight line and CPA = 100;
We have that:
\(CPA + CPD = 180\) --- angle on a straight theorem
Substitute 100 for CPA
\(100 + CPD = 180\)
Subtract 100 from both sides
\(100-100 + CPD = 180-100\)
\(CPD = 80\)
Next, we calculate PCD
We have that:
\(DAB= ADC = 56\) --alternate angle
In triangle PCD
\(PCD + CPD + PDC = 180\) --- angles in a triangle
Where
\(PDC = ADC = 56\)
So, we have:
\(PCD +80 + 56 = 180\)
\(PCD +136 = 180\)
Subtract 136 from both sides
\(PCD = 180 - 136\)
\(PCD = 44\)
A sphere of radius 10cm carries a charge of 1uC.Calculate the electric field.
The electric field is 9 * 10^6 N/m
What is the electric field of a sphere?The electric field of a sphere can be calculated using Coulomb's law, which states that the magnitude of the electric field at a point in space is proportional to the electric charge at that point and inversely proportional to the square of the distance between the point and the charge.
For a uniformly charged sphere, the electric field inside the sphere is zero, and the electric field outside the sphere is given by:
E = kQ / r^2
where:
E is the electric field strength, measured in units of volts per meter (V/m)
k is the Coulomb constant, with a value of approximately 9 x 10^9 N·m^2/C^2
Q is the total charge of the sphere, measured in units of Coulombs (C)
r is the distance from the center of the sphere to the point where the electric field is being measured, measured in units of meters (m).
Given that;
E = Kq/r^2
E = 9 * 10^9 * 1 * 10^-6/(10 * 10^-2)^2
E = 9 * 10^6 N/m
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What physical quantity does the slope of the v2/2 v/s h graph represent: #Hint: The algebraic statement of the conservation of Mechanical Energy is FEequals 1 half m v squared plus m g h where E,m, and g are constants. Solve for v2/2and determine what the slope would be if 'h' was on the horizontal axis. slope--g slope=-Elm slope-E slope-h
The physical quantity that does the slope of the v2/2 v/s h graph represent is the slope-g. The slope is representing the change in v over the change in time.
By definition, that is the acceleration. Also extra than only a gimmick, it is geometry's manner of displaying us how variables now no longer most effective relate to 1 another, however how they are able to constitute the fee of alteration among the variables.
The slope of the displacement time graph offers us the bodily amount called pace. The slope of a pace graph represents an object's acceleration. As a result, the cost of the slope at a given time represents the object's acceleration at that time. The fee of changing of an object's pace with admire to time is described as acceleration.
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In the diagram, q1, q2, and q3 are in a striaght line. each of these particles has a charge of -2.35 x 10^-6 C. Particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. What is the net force on particle q1?
PLEASE ANSWER IVE BEEN STUCK ON THIS SECTION FOR A WEEK
The net force on q1 is 9.94 N.
What is the net force on q1?From Coulomb's Law, the force between two point charges is given by:
F = (k * q1 * q2) / r²where;
F is the force,k is Coulomb's constant (9 * 10⁹ N * m²/C²),q1 and q2 are the charges,r is the distance between the charges.All the charges have the same charge and magnitude and are separated by the same distance.
The force between q1 and q2 is:
F12 = (9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²
F12 = 4.97 N
The positive sign indicates that the force is repulsive
Similarly, the force between q2 and q3 is:
(9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²
F12 = 4.97 N
The positive sign indicates that the force is repulsive
The net force on q1 will be:
Fnet = F12 + F23
Fnet = 4.97 N + (4.97)
Fnet = 9.94 N
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what is the difference between mass and weight
Answer:
The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it. The pull of gravity on the earth gives an object a downward acceleration of about 9.8 m/s2.
Answer:
Explanation:
The mass is essentially "how much stuff" is in an object. ... Weight: There is a gravitational interaction between objects that have mass. If you consider an object interacting with the Earth, this force is called the weight. The unit for weight is the Newton (same as for any other force).
Given F1: a force of magnitude 6 N at an angle of 30°
F2: a force of magnitude 8 N at an angle of 50°C
a. Find F1+ F2 analytically (using equations instead of graphing) and write it in the form Fr1i + Fr2 j
b. Find the magnitude FR and θ_resultant
Answer:
13.8 N
\(41.44^{\circ}\)
Explanation:
\(F_1=6\ \text{N}\)
\(F_2=8\ \text{N}\)
\(F_1\cos\theta_1\hat{i}+F_1\sin\theta_1\hat{j}\\ =6\cos30^{\circ}+6\sin30^{\circ}\hat{j}\\ =5.2\hat{i}+3\hat{j}\)
\(F_2\cos\theta_2\hat{i}+F_2\sin\theta_2\hat{j}\\ =8\cos50^{\circ}+8\sin50^{\circ}\hat{j}\\ =5.14\hat{i}+6.13\hat{j}\)
\(F_R=F_1+F_2=10.34\hat{i}+9.13\hat{j}\)
\(|F_R|=\sqrt{10.34^2+9.13^2}=13.8\ \text{N}\)
The magnitude of the resultant is 13.8 N
Direction is given by
\(\tan^{-1}=\dfrac{y}{x}=\tan^{-1}\dfrac{9.13}{10.34}=41.44^{\circ}\)
The angle of the resultant is \(41.44^{\circ}\)
Given the two vectors below, find the magnitude of the resultant vector's force in Newtons if both vectors are added together. Round your answer to 1 decimal place precision.Force Vector 1 = 59 Newtons inclined at 90 degrees to the positive x-axisForce Vector 2 = 33 Newtons inclined at 0 degrees to the positive x-axis
Answer:
Below
Explanation:
You can just use Pythagorean theorem for this one because the vectors are at a right angle to each other
59^2 + 33^2 = R^2
R = 67.6 N
A sample of vegetable oil with density 913 kg/m3 is found to have a mass of 0.0365 kg. Find the volume of this sample
The volume of the vegetable oil is 0.00003998 m³.
The density of vegetable oil,
ρ = 913 kg/m³
The mass of vegetable oil,
m = 0.0365 kg
To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.
The formula for density is:
ρ = m/V
where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:
V = m/ρSubstituting the given values of mass and density in the above formula,
We get:
V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)
Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.
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Which formula is used to find an object’s acceleration?
Its not A. btw
Can someone plz respond with an answer.
Answer:
Δv/Δt
Explanation:
I beat your game SAW.
Which of the following materials offer the least opposition to the flow of magnetic lines of force? A.steel b.copper c. Brass d.air
Air offers the least opposition to the flow of magnetic lines of force compared to the other materials listed.
This is because air is a non-magnetic material, which means it does not contain any magnetic properties. Magnetic lines of force can pass through air with minimal interference, as there are no magnetic fields generated to oppose the magnetic lines.
In contrast, materials such as steel, copper, and brass have magnetic properties, which means that they can create their own magnetic fields that can oppose the flow of magnetic lines of force. Therefore, air is the least resistive material for the flow of magnetic lines of force.
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A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.65 ms from an initial speed of 5.25 m/s . What is the magnitude of the average contact force exerted on the leg, assuming the total mass of the hand and the forearm to be 1.75 kg
Answer:
the magnitude of the average contact force exerted on the leg is 3466.98 N
Explanation:
Given the data in the question;
Initial velocity of hand v₀ = 5.25 m/s
final velocity of hand v = 0 m/s
time interval t = 2.65 ms = 0.00265 s
mass of hand m = 1.75 kg
We calculate force on the hand F\(_{hand\)
using equation for impulse in momentum
F\(_{hand\) × t = m( v - v₀ )
we substitute
F\(_{hand\) × 0.00265 = 1.75( 0 - 5.25 )
F\(_{hand\) × 0.00265 = 1.75( - 5.25 )
F\(_{hand\) × 0.00265 = -9.1875
F\(_{hand\) = -9.1875 / 0.00265
F\(_{hand\) = -3466.98 N
Next we determine force on the leg F\(_{leg\)
Using Newton's third law of motion
for every action, there is an equal opposite reaction;
so, F\(_{leg\) = - F\(_{hand\)
we substitute
F\(_{leg\) = - ( -3466.98 N )
F\(_{leg\) = 3466.98 N
Therefore, the magnitude of the average contact force exerted on the leg is 3466.98 N
Find the vector whose magnitude is 5 and which is in the direction of the vector 4i -3j +k
The vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
To solve this problemThe given vector can be normalized before being multiplied by the desired magnitude. This is how to locate the vector:
The vector that has been provided should be normalized by dividing each of its components by its magnitude. The Pythagorean theorem can be used to determine the magnitude of the vector 4i - 3j + k:
Magnitude = √(4² + (-3)² + 1²) = √(16 + 9 + 1) = √26
Normalize the vector by dividing each component by the magnitude:
Normalized vector = (4/√26)i + (-3/√26)j + (1/√26)k
Multiply the normalized vector by the desired magnitude:
To obtain a vector with a magnitude of 5, multiply each component of the normalized vector by 5:
Desired vector = 5 * ((4/√26)i + (-3/√26)j + (1/√26)k)
Simplifying the expression gives:
Desired vector ≈ (20/√26)i + (-15/√26)j + (5/√26)k
So, the vector with a magnitude of 5 and in the direction of the vector 4i - 3j + k is approximately (20/√26)i + (-15/√26)j + (5/√26)k.
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In a hydraulic system, a force of 400 N is exerted on a piston with an area of 0.001 m2. The load-bearing piston in the system has an area of 0.2 m^2.
Required:
a. Calculate in kPa the pressure in the hydraulic fluid induced by the applied pressure.
b. What is the magnitude of the force exerted on the load bearing piston by the hydraulic fluid?
Answer:
Explanation:
Pressure on the hydraulic system is expressed as;
Pressure = Force/Area
Given
Force on the fluid = 400N
Area = 0.001m²
Pressure in the fluid = 400/0.001
Pressure in the fluid = 400,000N/m²
1N/m² = 0.001kPa
400,000N/m² = x
x = 400,000 × 0.001
x = 400kPa
Hence the pressure in kPa is 400kPa
b) Using the formula;
Pa = Pb
Fa/Aa = Fb/Ab
Pa = Fb/Ab
Fb = PaAb
Fb = 400,000(0.2)
Fb = 80,000N
Hence the magnitude of the force exerted on the load bearing piston by the hydraulic fluid is 80,000N
A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?
A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.
The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the sourceFor such more question on parallel circuit
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Question 5 (2 points)
How many players are on each team playing on the court in an official game of
basketball?
3
4
5
6
Answer:
5
Explanation:
searched it up
The student has a mass of 50.0 kg. What is her momentum at 2 s (in kgm/s)?
Answer:
50kgm/2
Explanation:
Calculate the volume of a parallelepiped with sides give as
a
=
(
7,2
,
4
)
,
b
=
(
4,7
,
6
)
and
c
=
(
3,4
,
7
)
Select one:
105
cubic units
125
cubic units
115
cubic units
135
cubic units
To calculate the volume of a parallelepiped given the sides, we can use the scalar triple product. The formula for the volume of a parallelepiped with sides a, b, and c is:
Volume = |a · (b × c)|
where · represents the dot product and × represents the cross product.
Using the given sides:
a = (7, 2, 4)
b = (4, 7, 6)
c = (3, 4, 7)
First, calculate the cross product of b and c:
b × c = (7*7 - 4*4, 6*3 - 7*7, 4*4 - 2*3)
= (49 - 16, 18 - 49, 16 - 6)
= (33, -31, 10)
Next, calculate the dot product of a and the cross product (b × c):
a · (b × c) = 7*33 + 2*(-31) + 4*10
= 231 - 62 + 40
= 209
Finally, take the absolute value of the result to obtain the volume:
Volume = |209| = 209 cubic units
Therefore, the correct answer is:
209 cubic units
Which law of thermodynamics does each of the following scenarios violate (if any)?
A machine that can turn 1000J of heat directly into 1000J of electricity
1.
The first law of thermodynamics
2.
The second law of thermodynamics
3.
The third law of thermodynamics
4.
It is allowed
Answer: The scenario violates the second law of thermodynamics.
Explanation: The second law states that heat cannot be converted into work without some loss of usable energy, and that the amount of usable energy in a closed system will always decrease over time. Therefore, the machine described in the scenario cannot exist because it would violate the second law by converting all of the heat into electricity without any loss of usable energy.
A deer with a mass of 156 kg is running head on toward you with a speed of 10 m/s. Find the momentum of the deer
Hi there!
\(\large\boxed{1560 kgm/s}\)
Recall that:
P = m · v, where:
P = momentum
m = mass (kg)
v = velocity (m/s)
Thus:
P = 156 · 10
P = 1560 kgm/s
A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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CAN YOU GUYS PLEASE ANSWER THIS QUICKLY THIS IS DUE IN AN HOUR AND IM GETTING WORRIED
I'm pretty sure I the third option C.
Explanation:
sorry if I'm wrong
Electron energylevelsNucleusElectronResults from stellar spectroscopy (emission and absorption spectra) can only beexplained if light has an)as shown by Bohr's atom.wave natureparticle natureelliptical orbitenergy level
When a particle present on an energy level absrobs the energy it gets excited to the higher energy levels which can form the absorption spectra. When a particle present in the higher energy levels emits energy to get into lower energy levels it forms emission spectra. These phenomenons are explained by the particle nature of the atoms. Therefore, second option is the correct option.
slug
Something established by authority as a rule for measurement is called a
standard
unit
The statement "Something established by authority as a rule for measurement is called a standard unit" is True.
Something established by authority as a rule for measurement is called a standard unit. Standard units provide a consistent and universally accepted basis for measuring quantities in various fields such as science, engineering, and commerce.
Standard units are essential because they ensure consistency and accuracy in measurements across different contexts and locations. They serve as a reference point for comparing and quantifying physical quantities. By establishing standardized units, authorities promote uniformity and facilitate effective communication and collaboration in scientific research, technological advancements, and global trade.
In the International System of Units (SI), which is the most widely used system of measurement, there are seven base units: meter (length), kilogram (mass), second (time), ampere (electric current), kelvin (temperature), mole (amount of substance), and candela (luminous intensity). These base units are defined based on fundamental physical constants or natural phenomena, providing a reliable and reproducible foundation for measurement.
Standard units are typically defined and maintained by internationally recognized organizations like the International Bureau of Weights and Measures (BIPM) to ensure global consistency. These organizations establish precise definitions, measurement protocols, and calibration procedures for standard units, often using advanced scientific techniques and technologies.
The use of standard units simplifies scientific research, enables accurate engineering designs, ensures fair trade practices, and facilitates international cooperation. It allows for the seamless exchange of information and data, promotes quality assurance, and supports the development of common standards and regulations in various industries.
In summary, a standard unit is a measurement rule established by authority to provide a consistent and universally accepted reference for quantifying physical quantities. It is a fundamental aspect of scientific progress, technological advancements, and global collaboration.
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How much heat energy must be added to a 7.6- cm -diameter copper sphere to raise its temperature from -50 ∘C to 190 ∘C ?
Answer:
V = 4/3 π R^3 = 4/3 π 3.8^3 = 230 cm^3
M = ρ V = 8.89 g/cm^3 * 230 cm^3 = 2045 g
ΔQ = C M ΔT = .093 cal /g deg C * 2045 g * 240 deg C
ΔQ = 45,640 cal
Add to
♡
Average velocity and RC Truck Sample Problem
Homework 2
Imagine you drive an RC truck along a straight road for 0.7 km at 20 km/h. Here, your truck runs out of battery
and stops. Over the next 30 min, you walk 2.0 km farther along the road to a hobby store.
TEAM
1. What is your total displacement from the beginning of your drive to your arrival at the hobby store?
2.What is the time interval At from the beginning of your drive to your arrival at the hobby store?
3.What is your average velocity Vavg from the beginning of your drive to your arrival at the hobby store?
Express your answer both with numbers and a graphic.
0:59.20 / 1:04:43
Answer:
1) x_total = 2.7 km=2700 m, 2) t_total = 1926 s, 3) v_avg = 1.40 m / s
Explanation:
1) To solve this uniform velocity problem, we must find the displacement of each part and add them.
x_total = x₁ + x₂
x_total = 0.7 + 2.0
x_total = 2.7 km
2) how long does it take for this tour
truck
v = x₁ / t₁
t₁ = x₁ / v
t₁ = 0.7 / 20
t₁ = 0.035 h
Let's reduce the time to the SI system
t₁ = 0.035 h (3600 s / 1h) = 126 s
when he is walking
t₂ = 30 min (60 s / 1min) = 1800 s
the total time is
t_total = t₁ + t₂
t_total = 126 + 1800
t_total = 1926 s
3) the average velocity is defined as the displacement in the inerval between time
v_avg = x_total / t_total
v_avg = 2700/1926
v_avg = 1.40 m / s
A tuning fork with a frequency of 512 Hz is struck at the same time as a guitar string. If 24 beats are heard in
6.0 s, find the possible frequency or frequencies of the guitar string.
The possible frequencies of the guitar string are 488 Hz and 536 Hz.
What are the possible frequencies of the guitar string?
The possible frequency or frequencies of the guitar string is calculated by applying beat frequency formula.
Fb = Ft - Fg or
Fb = Fg - Ft
where;
Fb is the beat frequencyFg is frequency of the guitarFt is the frequency of the tuning forkFg = Ft - Fb
Fg = 512 Hz - 24 Hz
Fg = 488 Hz
Fg = Fb + Ft
Fg = 24 Hz + 512 Hz
Fg = 536 Hz
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