Anyone seek for a challenge? (It's not that hard) (11 yr old or +)

The coordinates of each points are:

A = (-0.5, -5)

B = (0.8, -1.8)

C = (-2.6, -2.2)

D = (-1.5, -8.9)

E = (2.5, -6.5)

F = (-1.5, 3.1)

G = (-2.4, 4.1)

H = (1.5, 3)

I = (2.7, 1.5)

J = (-1.5, 0)

K = (-6.5, 0)

We have,

The coordinates of each point are in an ordered form.

i.e

(x, y)

x is the x-axis value.

y is the y-axis value.

Thus,

A = (-0.5, -5)

B = (0.8, -1.8)

C = (-2.6, -2.2)

D = (-1.5, -8.9)

E = (2.5, -6.5)

F = (-1.5, 3.1)

G = (-2.4, 4.1)

H = (1.5, 3)

I = (2.7, 1.5)

J = (-1.5, 0)

K = (-6.5, 0)

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To find the combined rate of all the individuals working together, you must add the individual rates.

When calculating the combined rate of individuals working together, you need to add up the individual rates. Each worker contributes their own rate of work or productivity, and by adding these rates together, you can determine the combined rate at which they are working collectively.

This allows you to assess the overall efficiency and output of the team or group. By summing up the individual rates, we have better understanding of the overall productivity and performance of the group.

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After 300 trials, the experimental probabilities may not align perfectly with the theoretical probabilities. However, with more trials, the experimental probabilities tend to converge towards the theoretical probabilities for closer alignment.

To examine whether experimental probabilities after 300 trials align closely with theoretical probabilities, let's consider an example of flipping a fair coin.

Theoretical probability: When flipping a fair coin, the theoretical probability of obtaining heads or tails is 0.5 each. This assumes that the coin is unbiased and has an equal chance of landing on either side.

Experimental probability: After conducting 300 trials of flipping the coin, we record the outcomes and calculate the experimental probabilities. Let's assume that heads occurred 160 times and tails occurred 140 times.

Experimental probability of heads: 160/300 = 0.5333

Experimental probability of tails: 140/300 = 0.4667

Comparing the experimental probabilities to the theoretical probabilities, we can observe that the experimental probability of heads is slightly higher than the theoretical probability, while the experimental probability of tails is slightly lower.

In this particular example, the experimental probabilities after 300 trials do not align perfectly with the theoretical probabilities. However, it is important to note that these differences can be attributed to sampling variability, as the experimental outcomes are subject to random fluctuations.

To draw a more definitive conclusion about the alignment between experimental and theoretical probabilities, a larger number of trials would need to be conducted. As the number of trials increases, the experimental probabilities tend to converge towards the theoretical probabilities, providing a closer alignment between the two.

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The question probable may be:

Do experimental probabilities after 300 trials tend to align closely with theoretical probabilities? Consider an example scenario and calculate both the theoretical and experimental probabilities to determine if they are close.

Answer:

The relative frequency of the last class interval is 0.2.

Step-by-step explanation:

Relative frequency:

The relative frequency of an interval is the size of the interval divided by the total size of the sample.

10 out of 50 items:

So the relative frequency is:

10/50 = 0.2

The relative frequency of the last class interval is 0.2.

Answer:

\(\frac{dA}{dt} = 7200\pi t\)

a) \(\frac{dA}{dt} = 7200\pi\ cm^2/s\)

b) \(\frac{dA}{dt} = 21600\pi\ cm^2/s\)

c) \(\frac{dA}{dt} = 36000\pi\ cm^2/s\)

We can conclude that the area of the circle increases faster when the time increases.

Step-by-step explanation:

First let's write the equation for the area of the circle:

\(A = \pi*r^2\)

The rate that the radius of the circle increases is 60 cm/s, so we have:

\(\frac{dr}{dt} = 60\)

\(dr = 60dt \rightarrow r = 60t\)

To find the rate that the area increases, let's take the derivative of the equation of the area in relation to time:

\(\frac{dA}{dt} = \pi*\frac{d}{dt} r^2\)

\(\frac{dA}{dt} = \pi *\frac{dr^2}{dr} \frac{dr}{dt}\)

\(\frac{dA}{dt} = \pi *2r *\frac{dr}{dt}\)

\(\frac{dA}{dt} = 2\pi *(60t) *60\)

\(\frac{dA}{dt} = 7200\pi t\)

a)

Using t = 1, we have:

\(\frac{dA}{dt} = 7200\pi *1 = 7200\pi\ cm^2/s\)

b)

Using t = 3, we have:

\(\frac{dA}{dt} = 7200\pi *3 = 21600\pi\ cm^2/s\)

c)

Using t = 5, we have:

\(\frac{dA}{dt} = 7200\pi *5= 36000\pi\ cm^2/s\)

We can conclude that the area of the circle increases faster when the time increases.

Answer:

Its B

Step-by-step explanation:

Answer:

First, let's find where the lines:

x + 2y = 0

2x - y - 12 = 0

intersect.

First, let's isolate the variable y in one side of the equalities.

y = (-x/2)

y = 2x - 12

Now we have:

-(x/2) = 2x - 12

We can solve this for x.

12 = 2*x + x/2 = 2.5*x

12/2.5 = x = 4.8

Then, replacing that value in any of the lines, we can find the value of y.

y = 2*8 - 12 = 2*4.8 - 12 = -2.4

Then those lines intersect in the point (4.8, -2.4)

Now we want to find the line that passes through the points (-2, 3) and (4.8, -2.4)

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Then, the slope for our line is:

a = (3 - (-2.4))/(-2 - 4.8) = -0.79

And the

y-intercept will be:

y = -0.79*x + b

when x  = -2, y = 3.

3 = -2*-0.79 + b

3 - 2*0.79 = b = 1.42

The line is:

y = -0.79*x + 1.42

9514 1404 393

Answer:

  13

Step-by-step explanation:

The segments WX and WY are congruent, so ...

  5n -2 = 2n +7

  3n = 9 . . . . . . . . . . add 2-2n to both sides

  n = 3 . . . . . . . . . . . .divide by 3

  WY = 2n +7 = 2(3) +7 . . . . substitute for n in the expression for WY

  WY = 13

Answer:

it became 1.9 times larger

Step-by-step explanation:

The true statements are;

1) AB + BC = AC

Length of BC = |6 - 1|

2) ∠JMK = 50°

∠KML = 35°

1) From the given number line interval, we can deduce the interpretation as follows;

AB + BC = AC

Length of BC = 5 units or |6 - 1|

Length of B = 3 Units

2) We can see that ∠JML is an angle triangle. Thus, ∠JML = 85°. Thus;

6x + 2 + 4x + 3 = 85

10x + 5 = 85

10x = 85 - 5

10x = 80

x = 80/10

x = 8°

Thus;

∠JMK = 6(8) + 2

∠JMK = 50°

∠KML = 85° - 50°

∠KML = 35°

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Answer:

Step-by-step explanation:True.

If a function has an empty formal parameter list, the parentheses after the function name are not required in some programming languages. For example, in Python, the parentheses can be omitted when defining or calling a function with an empty parameter list.

For instance, the following function definition and function call are both valid in Python:

def print_hello():

   print("Hello!")

print_hello()

However, some programming languages, such as C and Java, require parentheses for all function definitions and calls, even when the parameter list is empty.

given that m is parallel to n,

the angle opposite (2x + 16)° is also (2x + 16)° as vertically opposite angles are equal.

using the corresponding angle rule we know that:

2x + 16 = 96

2x = 80

so x = 40

If angles C and D are the acute angles of a right triangle, we have the image as shown below:

The question gives that:

Comparing with the Sine Trigonometric Ratio given to be:

we thus have that the Sine ratio of angle D in the triangle drawn above will be:

Hence, we can have the triangle look as shown below:

Therefore, the cosine of angle C, with the ratio:

will be given to be:

Therefore, the correct option is the FIRST OPTION.

The sequence is an arithmetic sequence and the common difference is 5

From the question, we have the following parameters that can be used in our computation:

4, 9, 14

The above definitions imply that we simply add 5 to the previous term to get the current term

Using the above as a guide,

so, we have the following representation

Sequence type = arithmetic

Common difference = 5

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Answer:

See below for answers

Step-by-step explanation:

a) invNorm(0.66,1112,56) = 1153.097936 ≈ 1153 lbs

b) invNorm(0.94,1152,56) = 1199.067321 ≈ 1199 lbs

Answer:

1st step

Step-by-step explanation:

7/10 is greater than 1/2

Answer:

Step 1

Step-by-step explanation:

A .The canoe left the campsite did the motorboat catch up with it 3 hrs and 40 minutes

B . The motorboat travel at 1 hr 40 minutes

A group of campers and one group leader left a campsite in a canoe.

They traveled at an average rate of 10 km/h.

1st Group DATA:

rate = 10 km/h ; distance = x km ; time = d/r = x/10 hrs

Two hours later, the other group leader left the campsite in a motorboat.

He traveled at an average rate of 22 km/h.

Group Leader DATA:

rate = 22 km/h ; distance = x km ; time = d/r = x/22 hrs

A. How long after the canoe left the campsite did the motorboat catch up with it?

Group time - Leader time = 2 hr

x/10 - x/22 = 2

Multiply thru by 110 to get:

11x - 5x = 220

6x = 220

x = 110/3 = km

canoe total time = x/10 = (110/3)/(10) = 11/3 = 3 hrs and 40 minutes

B. How long did the motorboat travel?

motorboat time = x/22 = (110/3)/22 = 1 hr 40 minutes

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Answer:

2nd option -7 - 13i

Step-by-step explanation:

took review

Answer:

17.1%

Step-by-step explanation:

To find the percentage of oak trees in the wood, divide the number of oak trees by the total number of trees (sum of all tree types), and then multiply by 100 to express it as a percentage:

\(\begin{aligned}\textsf{Percentage of oak trees}&= \dfrac{\textsf{Number of oak trees}}{\textsf{Total number of trees}} \times 100\\\\&= \dfrac{130}{420+130+210} \times 100\\\\&= \dfrac{130}{760} \times 100\\\\&=0.171052631... \times 100\\\\&=17.1\%\; \sf (1\;d.p.)\end{aligned}\)

Therefore, approximately 17.1% of the trees in the wood are oak trees.

Answer:

17.1%

Step-by-step explanation:

In order to calculate the percentage of trees that are oak trees, we can use the following formula:

\(\textsf{Percentage of oak trees }=\dfrac{\textsf{ Number of oak trees }}{\textsf{total number of trees} }\cdot 100\% \)

We know that the number of oak trees is 130 and the total number of trees is 420 + 130 + 210 = 760.

Substituting these values into the formula, we get:

\(\textsf{Percentage of oak trees }=\dfrac{130}{760}\cdot 100\% \\\\ = 0.1710 \cdot 100\% \\\\ \approx 17.1 \% \textsf{( in 1 d.p.)}\)

Therefore, 17.1% of the trees in the wood are oak trees.

Answer:

f(x) = x³ - 4x + 6

f'(x) = 3x² - 4

a) f'(2) = 3(2²) - 4 = 12 - 4 = 8

6 = 8(2) + b

6 = 16 + b

b = -10

y = 8x - 10

b) 3x² - 4 = 0

3x² = 4, so x = ±2/√3 = ±(2/3)√3

= ±1.1547

f(-(2/3)√3) = 9.0792

f((2/3)√3) = 2.9208

c) 3x² - 4 = 8

3x² = 12

x² = 4, so x = ±2

f(-2) = (-2)³ - 4(-2) + 6 = -8 + 8 + 6 = 6

6 = -2(8) + b

6 = -16 + b

b = 22

y = 8x + 22

f(2) = 6

y = 8x - 10

The equation perpendicular to the tangent is y = -1/8x + 25/4

-The smallest slope on the curve is 2.92

The curve has the smallest slope at the point (1.15, 2.92)

The equations at tangent points are y = 8x + 16 and  y = 8x - 16

From the question, we have the following parameters that can be used in our computation:

y = x³ - 4x + 6

Differentiate

So, we have

f'(x) = 3x² - 4

The point is (2, 6)

So, we have

f'(2) = 3(2)² - 4

f'(2) = 8

The slope of the perpendicular line is

Slope = -1/8

So, we have

y = -1/8(x - 2) + 6

y = -1/8x + 25/4

We have

f'(x) = 3x² - 4

Set to 0

3x² - 4 = 0

Solve for x

x = √[4/3]

x = 1.15

So, we have

Smallest slope = (√[4/3])³ - 4(√[4/3]) + 6

Smallest slope = 2.92

So, the smallest slope is 2.92 at (1.15, 2.92)

Here, we set f'(x) to 8

3x² - 4 = 8

Solve for x

x = ±2

Calculate y at x = ±2

y = (-2)³ - 4(-2) + 6 = 6: (-2, 0)

y = (2)³ - 4(2) + 6 = 6: (2, 0)

The equations at these points are

y = 8x + 16

y = 8x - 16

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The required value of 4/ 27 to tenth decimal places is 0.1.

To determine the 4/ 27 to the tenth decimal place.

Decimals is defined as one of the digits, which has a number and the fractional part separated by a decimal point after the whole number.

Recurring Decimal is defined as also named repeating decimal, is a decimal number that only consists of repeating digits after a certain interval after the decimal. For example, 94.642642642..., 213.569569... etc.

Here,
= 4 / 27
dividing 4 by 27
4/27 = 0.148148148148148
now round of the above digit to tenth decimal place means place after the decimal is tenth place. So,
= 0.1

Thus, the required value of 4/ 27 to tenth decimal place is 0.1.

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Answer:

Use the following Financial Ratios to measure financial performance against standards. In addition, analysts compare these ratios to industry averages (benchmarking), industry standards or rules of thumbs and against internal trends (trends analysis). Furthermore the most useful comparison when performing financial ratio analysis is trend analysis They are derived from thethree following financial

statements:

⚫Balance Sheet

•Income Statement

⚫Statement of Cash Flows

.5 Categories

The five (5) major categori in the financial ratios list include the following:

•Liquidity Ratios

•Activity Ratios

•Debt Ratios

•Profitability Ratios

•Market Ratios

Step-by-step explanation:

Sana makatulong

Ratios dealing with short-term debts are Liquidity Ratios; those gauging efficiency in using assets for sales are Activity Ratios, and those scrutinizing long-term debt handling are Leverage Ratios. Along with the calculations, observations and identification of trends and their driving factors are also necessary.

In finance and business, ratio analysis is a tool used for conducting quantitative analysis on a company's financial statements. It involves the calculation and interpretation of various financial ratios. The following are the answers to the question's blanks:

However, only calculating ratios is not enough; you must also observe and identify trends suggested by the analysis, as well as identify the factors that drive these trends. These additional steps provide context and deeper insights into the company's financial performance.

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Answer:

k=14

Step-by-step explanation:

The value of the missing side lengths x and y are 5√2 and 5 respectively.

The figure in the image is a right triangle.

Angle θ = 45 degree

Hypotenuse = x

Opposite to angle θ = y

Adjacent to angle θ = 5

To solve for side x and side y, we use the trigonometric ratio.

Note that:

Cosine = adjacent / hypotenuse

tangent = opposite / adjacent

Solving for x:

Cosine = adjacent / hypotenuse

Plug in the values

cos( 45 ) = 5/x

x = 5 / cos( 45 )

x = 5√2

Solving for side y:

tangent = opposite / adjacent

Plug in the values

tan( 45 ) = y/5

y = tan( 45 ) × 5

y = 5

Therefore, the value of side length x is 5 units.

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Answer:

A.=False

B.=True

C.=False

D.=True

Step-by-step explanation:

The original ration is 2 gallons of water for 4 players.

Each player requires 1/2 gallon of water.

To get the amount of water needed multiply 1/2 by the amount of players.

1*(1/2) does not equal 1

2*(1/2) equals 1

10*(1/2) does not equal 4

30*(1/2) equals 15

ANSWER:

49 ft

STEP-BY-STEP EXPLANATION:

Given:

g = 32 ft/m^2

v = 56 ft/s

Replacing:

We solve for h which would be how far the object fell:

The object was 49 feet high

Answer:

54t-17 =65 78 98. 56 76 45

The steps to sketch the graph of a rational function in the appropriate order is in the order: 1,4,2,3

The steps to sketch the graph of a rational function will be first to find the function's zeros and vertical asymptotes, and plot them on a number line, the second step is to choose test numbers to t the left and right of each of these places, and find the value of the function at each test number., the third step is to use test numbers to find where the function is a positive and where it is negative and the last step is to sketch the function's graph, plotting additional points as guides as negative.

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Place the steps to sketch the graph of a rational function in the appropriate order.

1)find the function's zeros and vertical asymptotes, and plot them on a number line.

2) use test numbers to find where the function is positive and where it is negative.

3) sketch the function's graph, plotting additional points as guides as negative.

4)choose test numbers to t the left and right of each of these places, and find the value of the function at each test number.​