anyone able to help me

a. O(n^2)

b. O(1)

c. O(n log n)

d. O(log n)

e. O(n^23)

a. The function 5n^2 - 2 has a complexity of O(n^2) because the highest power of n is 2, and the coefficient (5) is not significant when considering the growth rate as n approaches infinity.

b. The function 7 has a constant complexity of O(1) because it doesn't depend on the input size n. It will always require the same amount of time to execute, regardless of the input.

c. The function 4n * 10log(n) + 25 has a complexity of O(n log n) because the term 4n dominates the growth rate (linear) and the term 10log(n) represents a logarithmic growth rate. In Big O notation, we consider the term with the highest growth rate, which is n log n.

d. The function 3 * 4 log(n) has a complexity of O(log n) because the base 2 logarithm term is a slower growth rate compared to linear or polynomial terms. The constant coefficient (3 * 4) is not significant when determining the complexity class.

e. The function n^2 * n^(3 * 10) has a complexity of O(n^23) because the exponents are added when multiplying terms. The highest power of n is 23, and the coefficients and lower-order terms become insignificant as n approaches infinity

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Since X is an odd number, x+2 is the following odd number. If x is an even number, the subsequent odd number is x + 1.

The vehicles that will travel on the highways on particular days are decided by the Odd-Even rule, a space rationing system. According to the plan, vehicles with odd and even numbers will travel the roads on alternate days.

In jQuery, the odd() method is used to pick elements with odd index numbers (such as 1, 3, 5, etc.). The index begins at zero. It picks odd numbers, unlike the even() function, which is comparable. From the set of chosen items, the odd() method returns the odd indexed elements.

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Using the slope concept, it is found that the rate of download of the file is of 1920 MB/s.

The slope of a linear function is given by the change in the output divided by the change in the input.

In this problem:

\(m  = \frac{3840}{2} = 1920\)

The rate of download of the file is of 1920 MB/s.

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The absolute value is:

Work/explanation:

First, we will evaluate 2-7.

It evaluates to -5.

Now, let's find the absolute value of -5 by using these rules:

\(\sf{\mid a\mid=a}\)

\(\sf{\mid-a \mid=a}\)

Similarly, the absolute value of -5 is:

\(\sf{\mid-5\mid=5}\)

Answer:

The length of each side is three foot.

Step-by-step explanation:

Answer:

1 ft.

Step-by-step explanation:

see attached

The sum of interior Angles of Hexagon is always 720°

Any hexagon's internal angles add up to 720° in all cases. By dividing 720° by 6, we may get the size of each interior angle of a regular hexagon. As a result, we have:

720°÷6 = 120°

In a regular hexagon, each inside angle is 120°.

An example of a regular hexagon with equal-length sides and angles is shown in the diagram below. By multiplying the six 120° angles together, we can demonstrate that the result is 720°.

Therefore, the interior angles of a hexagon are always added up to 720°.

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\((\stackrel{x_1}{9}~,~\stackrel{y_1}{-9})\hspace{10em} \stackrel{slope}{m} ~=~ 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-9)}=\stackrel{m}{ 4}(x-\stackrel{x_1}{9}) \implies y +9= 4 (x -9)\)

Answer:

m = 4

Step-by-step explanation:

slope = 4

Answer:

2/9

Step-by-step explanation:

5/9 -2/6 = 2/9

(decimal: 0.222222)

The value of the expression 5/9 - 2/6 is 2/9.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

5/9 - 2/6

Find the LCM of 9 and 6.

= (10 - 6)/18

= 4/18

= 2/9

Thus,

The value is 2/9.

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Factoring integers with sublinear resources on a superconducting quantum processor can be achieved using quantum approximate optimization algorithm" (QAOA) or quantum phase estimation algorithm (QPE) approach.

Factoring large integers is a problem of significant importance in the field of cryptography.

Classical computers have limited efficiency in solving this problem, and their performance is expected to decline further as the size of the integers to be factored increases.

In contrast, quantum computers are expected to have exponential speedup in factoring large integers, thanks to Shor's algorithm.

Recently, researchers have been exploring the possibility of using superconducting quantum processors to factor integers with sublinear resources.

One approach is to use a so-called "quantum approximate optimization algorithm" (QAOA), which maps the problem of factoring integers to a problem of finding the ground state of a certain Hamiltonian.

The QAOA can be implemented using a superconducting quantum processor, with the problem Hamiltonian implemented by a set of two-qubit gates.

Another approach is to use the quantum phase estimation algorithm (QPE) to estimate the eigenvalues of the problem Hamiltonian.

This can be used to factor integers by finding the period of a certain function using the quantum Fourier transform, as in Shor's algorithm. QPE can be implemented on a superconducting quantum processor using phase estimation circuits, which require only polynomial resources.

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Answer:

It has one solution but technically you could solve for either X or Y.

The number of ways to select 3 pages in ascending index order depends on the total number of pages available.

To find the number of ways to select 3 pages in ascending index order, we can use the concept of combinations . In combinatorics, selecting objects in a specific order is often referred to as permutations. However, since the order does not matter in this case, we need to consider combinations instead.

The number of ways to select 3 pages in ascending index order can be calculated using the combination formula. Since we are selecting from a set of pages, without replacement and order doesn't matter, we can use the formula C(n, k) = n! / (k!  (n-k)!), where n is the total number of pages and k is the number of pages we want to select.

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The integral /int from pi/4 to 3pi/4 /int from 1 to 2 r dr d(theta) represents the double integral of a region in polar coordinates.

The region can be visualized as a sector of a circle in the polar plane, bounded by the angles pi/4 and 3pi/4, and by the radii 1 and 2. The first integral /int from 1 to 2 r dr integrates over the radial direction, while the second integral /int from pi/4 to 3pi/4 d(theta) integrates over the angular direction.

To evaluate the integral, we integrate the radial part first. Integrating r with respect to r yields (1/2)r^2. Plugging in the limits of integration, we get [(1/2)(2)^2] - [(1/2)(1)^2] = 2 - 1/2 = 3/2.

Next, we integrate the angular part. Integrating d(theta) with respect to theta gives theta. Evaluating the limits of integration, we have (3pi/4) - (pi/4) = pi/2.

Finally, multiplying the results of the radial and angular integrals, we have the value of the double integral as (3/2) * (pi/2) = 3pi/4. Thus, the integral evaluates to 3pi/4.

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Answer:

b. 8/17

Step-by-step explanation:

hope this helps ;)

It will take Stella 24 days to finish all the oatmeal in the container if she eats 1/4 cup every day for breakfast.

The container has 6 cups of oatmeal and Stella eats 1/4 cup every day for breakfast.

To find the number of days it will take Stella to finish all the oatmeal, we can use the formula:

Total amount of oatmeal in the container = 6 cups

Amount of oatmeal consumed by Stella per day = 1/4 cup

Therefore, it will take Stella 24 days to finish all the oatmeal in the container if she eats 1/4 cup every day for breakfast.

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Answer:

\(\pink{\boxed{{\colorbox{white}{Answer}}}}\)

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In the figure, the slope of mid-segment DE is -0.4. The slope of segment AC is?

A.) 0.4

B.) -0.4

C.) 2

D.) -2

\(\purple {\overline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }} \)

Step-by-step explanation:

\( \pink{\boxed{{\colorbox{white}{- MsTiyana}}}}\)

# i hope it helps you

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If a student receives a score of 80, how many questions did this student answer ... (5). Let x = the first number, and y = the second number ... If John only has 25 coins in his pocket, how many of the coins are quarters?

       Hence, OPTION (C) is your answer:  X  =  44

Step-by-step explanation:

       √x + 5 - 3 = 4

        √x +  5   =  3  +  4

        √x +  5   =   7

         (√x  +   5)2     =     (7)2

            x   +   5         =   49

        x   -  44     =   0

             +44      =   44

       X                =   44

       Hence,  X  =  44

        Equation: √x  +  5  =  7

      √(44)  +  5  =  7

    √49  =   7

            Hence,   x   =   44

        I hope this helps!

We are given two figure, i) Cube, ii) rectangular box

The volume of any shape is calculated by multiplying height, width, length.

Volume = height x length x width

In the case of a cube, all the dimensions are the same. So volume would be = length x length x length

here, length = 6

So,

V(cube) = 6^3

For a rectangular box:

V(rect) = height x length x width

V(rect) = h x 12 x 6

As given, V(cube) = V(rect). Therefore,

6^3 = h x 12 x 6

Hence, the first option is correct.

Answer:

No, these three sides form a right triangle 7yd,3yd,9yd wont work

Step-by-step explanation:

a^2 + b^2 = c^2

lonest length is c (hypotenuse) : 9yd

(7)^2 + (3)^2 = (9)^2

49 + 9 = 81

58 = 81                      NOT TRUE

The relationship between the points on the line and solutions to the linear equation is, the equation has a solution at each point along the line.

In the given question, we have to find the relationship between the points on the line and solutions to the linear equation.

The equation has a solution at each point along the line. This simply means that it is easy to tell whether an ordered pair is a solution to an equation. The ordered pair is a solution to the equation if it lies on the line drawn by the linear equation.

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Answer:

Step-by-step explanation:

Let X denote the random variable that obeys the normal distribution.

Given that:

For morning flights

Mean \(\mu_1\) = 15

standard deviation \(\sigma_1\) = 5

Sample size \(n_1\) = 10

\(X_1 \sim Normal ( \mu_1, \sigma _1)\)

The Z - score is calculated as:

\(Z = \dfrac{x_1 - \mu_1}{\sigma_1}\)

\(Z = \dfrac{30 -15}{5}\)

\(Z = \dfrac{15}{5}\)

Z = 3

For evening flights

Mean \(\mu_2\) = 20

standard deviation \(\sigma_2\) = 3

Sample size \(n_2\) = 10

\(X_2 \sim Normal ( \mu_2, \sigma _2)\)

\(Z = \dfrac{x_2 - \mu_2}{\sigma_2}\)

\(Z = \dfrac{30 -20}{3}\)

\(Z = \dfrac{10}{3}\)

Z = 3.33

Hence, from the above z-scores, we will realize that the evening flight is more late than usual.

When the shape being rotated has a hole or an empty region, we use slicing of washers to find the volume. If the shape is solid and without any holes, we use slicing of disks.

The volume of a cylindrical disk =

The term "cylindrical disk" is not commonly used in mathematics. Instead, we usually refer to a disk as a two-dimensional shape, while a cylinder refers to a three-dimensional shape.

Volume of a Cylinder:

A cylinder is a three-dimensional shape with two parallel circular bases connected by a curved surface.

To find the volume of a cylinder, we use the formula:

V = πr²h,

where V represents the volume, r is the radius of the circular base, and h is the height of the cylinder.

Volume of a Disk:

A disk, on the other hand, is a two-dimensional shape that represents a perfect circle.

Since a disk does not have height or thickness, it does not have a volume. Instead, we can find the area of a disk using the formula:

A = πr²,

where A represents the area and r is the radius of the disk.

The volume of a solid of revolution =

When finding the volume of a solid of revolution, we typically rotate a two-dimensional shape around an axis, creating a three-dimensional object. Slicing is a method used to calculate the volume of such solids.

To find the volume of a solid of revolution using slicing, we divide the shape into thin slices or disks perpendicular to the axis of revolution. These disks can be visualized as infinitely thin cylinders.

By summing the volumes of these disks, we approximate the total volume of the solid.

The volume of each individual disk can be calculated using the formula mentioned earlier: V = πr²h.

Here, the radius (r) of each disk is determined by the distance of the slice from the axis of revolution, and the height (h) is the thickness of the slice.

By summing the volumes of all the thin disks or slices, we can obtain an approximation of the total volume of the solid of revolution.

As we make the slices thinner and increase their number, the approximation becomes more accurate.

Now, let's address the question of why we might need to use the slicing of washers versus disks.

When calculating the volume of a solid of revolution, we use either disks or washers depending on the shape being rotated. If the shape has a hole or empty region within it, we use washers instead of disks.

Washers are obtained by slicing a shape with a hole, such as a washer or a donut, into thin slices that are perpendicular to the axis of revolution. Each slice resembles a cylindrical ring or annulus. The volume of a washer can be calculated using the formula:

V = π(R² - r²)h,

where R and r represent the outer and inner radii of the washer, respectively, and h is the thickness of the slice.

By summing the volumes of these washers, we can calculate the total volume of the solid of revolution.

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The lower bound of the mass at the end of the experiment is 65.25 g and the upper bound is 64.25 g.

To calculate the lower and upper bounds of the mass of the chemicals at the end of the experiment, we need to take into account the uncertainty in the initial mass and the change in mass.

The initial mass of the chemicals is given as 73 g, rounded to 2 significant figures. This means that the actual value of the initial mass could lie anywhere between 72.5 g and 73.4 g, since the last significant digit (the 3) is uncertain.

Similarly, the change in mass during the experiment is given as 8.2 g, rounded to 2 significant figures. This means that the actual value of the change in mass could lie anywhere between 8.15 g and 8.25 g.

To find the lower bound of the mass at the end of the experiment, we assume that the initial mass was at its upper bound (73.4 g) and the change in mass was at its lower bound (8.15 g):

Lower bound = 73.4 g - 8.15 g = 65.25 g

To find the upper bound of the mass at the end of the experiment, we assume that the initial mass was at its lower bound (72.5 g) and the change in mass was at its upper bound (8.25 g):

Upper bound = 72.5 g - 8.25 g = 64.25 g

Therefore, the lower bound of the mass at the end of the experiment is 65.25 g and the upper bound is 64.25 g.

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Answer:

2j+8

Step-by-step explanation:

2(j+4) .    use distributive property

2j+8

We can use the standard normal distribution table or calculate the z-score and find the corresponding area under the curve. The percentage of the population for X ≥ 124.75 is approximately 3.86%.

To find the percentage of the population for X ≥ 124.75, we need to calculate the z-score, which represents the number of standard deviations an observation is from the mean. The formula for the z-score is:

z = (X - μ) / σ

In this case, X is 124.75, μ is 100, and σ is 15. Plugging in these values, we get:

z = (124.75 - 100) / 15 = 1.65

Using the standard normal distribution table or a calculator, we can find the area under the curve to the right of the z-score of 1.65. The area represents the percentage of the population for X ≥ 124.75.

From the standard normal distribution table, we find that the area to the right of the z-score 1.65 is approximately 0.0495. Multiplying this by 100, we get 4.95%.

However, since we are interested in X ≥ 124.75, we need to consider the area to the left of the z-score of 1.65 and subtract it from 1. This gives us:

1 - 0.0495 = 0.9505

Multiplying 0.9505 by 100, we find that the percentage of the population for X ≥ 124.75 is approximately 95.05%. Therefore, the percentage of the population for X ≥ 124.75 is approximately 3.86%.

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When a converging lens with a focal length of 10.6 cm is held 8.10 cm in front of a newspaper with a print size of 2.06 mm, the image formed by the lens is virtual, upright, and magnified. The height of the image is 8.32 mm.

The characteristics of the image formed by a lens can be determined by using the thin lens equation and the magnification equation. The thin lens equation relates the object distance, image distance, and focal length of the lens. The magnification equation relates the size of the object and the size of the image.

In this problem, the lens is held 8.10 cm in front of the newspaper, which is the object. The focal length of the lens is 10.6 cm. Using the thin lens equation, we can find the image distance, which is 0.322 m. The negative sign of the magnification value indicates that the image is inverted with respect to the object. The magnification value of -3.98 indicates that the image is magnified, which means that it appears larger than the object.

To find the height of the image, we use the magnification equation. The height of the object (the print size of the newspaper) is given as 2.06 mm. Using the magnification value of -3.98, we can find the height of the image, which is 8.32 mm.

Therefore, the image appears much larger than the object, and is located on the same side of the lens as the object. The image is virtual and upright, which means that it appears to be behind the lens and is not a real image that can be projected onto a screen.

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Answer:

The second one the amount of monthly sales

Step-by-step explanation:

The 2000 is the total