Answer:
C.) False, counterexample of 15
1) 15 is divisible by 3 but not by 6
we know that 15 = 3*5 or 15/3=5, So 15 IS DIVISIBLE BY 3
BUT 15/6=2.5 THIS PROVES 15 IS NOT PERFECTLY DIVISIBLE BY 6
2) 12= 3*4 & 6*2
SO 12 IS PERFECTLY DIVISIBLE BY 3 & 6 BUT 15 IS NOT. THUS THE ANSWER IS 'C'
Answer:
c. False, counterexample of 15
Step-by-step explanation:
This statement is entirely incorrect although it can work vice versa meaning all multiples of 6 will be divisible by 3
Look at the graph below. Which of the following best represents the slope of the line? A. -3 B. - 1 3 C. 1 3 D. 3
Answer:
3
Step-by-step explanation:
The slope of the given line is \(\frac{2}{3}\).
What is the slope of a line passing through two points?If a line passes through two points (x₁, y₁) and (x₂, y₂) respectively, then slope of the line is \(m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\)
Here, the given line passes through points (0, 6) and (-9, 0).
Therefore, the slope of this line is (m)
\(= \frac{0 - 6}{-9 - 0}\\= \frac{6}{9} \\= \frac{2}{3}\)
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What is the lateral area of the cone to the nearest whole number? The figure is not drawn to scale.
*
Captionless Image
34311 m^2
18918 m^2
15394 m^2
28742 m^2
Answer:
π(70)(√(70^2 + 50^2)) = π(700√74) m^3
= 18,918 m^3
a straight line passes through the point P(-1,5). Another line which passes through Q(-4,4) intersects the first line at point R( µ,5) where µ is a constant . If <PRQ = 90° find the value of R
Answer:
\(\mu=-4\)
Step-by-step explanation:
We know that \(\overline{PR} \perp \overline{QR}\).
Since \(\overline{PR}\) is horizontal, \(\overline{QR}\) is vertical. Therefore, \(\mu=-4\).
Dominique is selling merchandise for a school fundraiser. she is selling calendars for $7 each and coffee mugs for $11 each. she must sell at least $700 of merchandise, including at least 50 mugs, to meet her goals. if x represents the number of calendars and y represents the number of mugs, which system of inequalities represents this scenario? 7x 11y > 700 and y > 50 7x 11y > 700 and x > 50 7x 11y ≥ 700 and y ≥ 50 7x 11y ≥ 700 and x ≥ 50
System of inequalities that represents this scenario is 7x + 11y ≥ 700 (the total amount of merchandise sold must be at least $700) y ≥ 50 (at least 50 coffee mugs must be sold)
Dominique is selling merchandise for a school fundraiser. To meet her goals, she must sell at least $700 worth of merchandise, including at least 50 coffee mugs.
Let x be the number of calendars sold and y be the number of coffee mugs sold. The revenue from selling x calendars and y coffee mugs can be calculated as follows:
Revenue = (Price per calendar) x (Number of calendars sold) + (Price per coffee mug) x (Number of coffee mugs sold)
Given that calendars are being sold for $7 each and coffee mugs are being sold for $11 each, the revenue equation can be expressed as:
Revenue = 7x + 11y
To meet the fundraising goal of selling at least $700 worth of merchandise, the total revenue generated from the sale of calendars and coffee mugs must be at least $700. Hence, we can express this as the inequality:
7x + 11y ≥ 700
In addition, Dominique must sell at least 50 coffee mugs. This can be expressed as the inequality:
y ≥ 50
Combining both inequalities, we get the system of inequalities:
7x + 11y ≥ 700 and y ≥ 50
This system of inequalities represents the scenario where Dominique must sell at least $700 worth of merchandise, including at least 50 coffee mugs. The first inequality ensures that the total revenue generated from the sale of calendars and coffee mugs meets the fundraising goal, while the second inequality ensures that at least 50 coffee mugs are sold.
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A triangle has sides with lengths of 32 kilometers, 60 kilometers, and 68 kilometers. Is it a right triangle?
Answer:
yes
Step-by-step explanation:
a^2 + b^2 = c^2
so
32^2 + 60^2 = 68^2
1024 + 3600 = 4624
PLEASE HELP ME ASAP I BEG YOU
The distance that the tip of the base ball travels is 214 inches.
Given that Kyle is practicing his baseball swing
He made an arc with radius of 48 inches
We have to find the distance the tip of the base ball travels
Radius = 48 in and θ = 255 degrees
Arc length = θ/360 × 2πr
=255/360 ×2×3.14×48
=76867.2/360
=213.52 inches
=214 inches
Hence, the distance that the tip of the base ball travels is 214 inches.
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What is the solution to this system? -2x =14y=16x-4
Answer:
-2x =14y=16x-4
No Solution
Step-by-step explanation:
Sorry there is no solution found
Maybe you asked if it was all real numbers, no solution and and etc. The answer would be no solution
p: It is winter.
q: There is snow on the ground.
r. There are Christmas lights on houses.
Translate the following statement and determine its truth value.
(~r^~q) →p
A.
If there are not Christmas lights on houses and there is not snow on the ground, then it is winter.
True
B. If there are not Christmas lights on houses and there is not snow on the ground, then it is winter.
False
C. If there are Christmas lights on houses and there is snow on the ground, then it is winter.
True
D.
If there are Christmas lights on houses and there is snow on the ground, then it is winter.
False
Answer:
C
Step-by-step explanation
the weather usually gets colder in the winter and people usually decorate for Christmas late fall and early winter.
therefore, if there is snow on the ground and Christmas lights on houses its most likely winter.
One thing that many students think about when they register for classes at a university is how many textbooks they are going to have to buy for the class and how much the books are going to cost. To add to this, a lot of the students wonder if they are even going to use the books that they are required to buy. In fact, some students don’t buy books for their classes because they are convinced that they don’t really need them to achieve an acceptable grade.
This is exactly the line of thinking that textbook writers are afraid of—they want students to have to use their books to get good grades in their classes, and they want professors to think that students need their books so that they require them as part of their classes.
Even though textbooks have a definite value—they are available to students who use them when their professors are not—there is some debate on whether they are really needed as part of university classes.
Recently, a researcher conducted an experiment to address this question. In the experiment, the researcher compared two sections of his introductory statistics course, a course required for all liberal arts and sciences students. Students who were enrolled in the fall semester of the course were told that buying the textbook was optional, whereas students enrolled in the spring semester were told that buying the textbook was required. All 380 of the students (190 in the fall and 190 in the spring) completed the course, and they all took the final exam, which consisted of some calculations and several conceptual essay questions.
When the professor finished scoring the essays, he compared the final exam grades of both sections of the class. He found just what he thought he would—there were no differences in the scores on the exams between the section that thought the textbook was optional and the section that thought the textbook was required. The average grade for the fall semester was 84.3%, and for the spring semester it was 85.2%.
Based on this study, the researcher concluded that textbooks were not necessary or helpful for learning, since there were no differences in scores between the two sections.
No control or comparison group
No random assignment
Participant bias
Small sample size
Poor sample selection
Attrition or mortality
Experimenter bias
Confuse correlation with causality
DV is not reliable, precise or accurate
DV is not valid
DV is not objectively scored
Premature generalization of results
The study conducted by the researcher suffers from several limitations, including the absence of a control group, small sample size, participant bias, and experimenter bias. Furthermore, the sample selection is inadequate, as all the participants are students of one course in a single university.
Moreover, the study fails to account for extraneous variables that might affect the results. Therefore, that textbooks are not necessary or helpful for learning is premature and cannot be generalized to other courses or universities. T he study is flawed, and more research is needed to assess the effect of textbooks on learning.
The study conducted by the researcher suffers from several limitations. First, there is no control group, which makes it difficult to determine whether the results are due to the absence or presence of the textbook. Second, the sample size is small, which reduces the generalizability of the findings.
Third, there is participant bias, as some students might have bought the textbook even though it was optional, while others might not have bought it even though it was required. Fourth, there is experimenter bias, as the professor who scored the essays knew which section had the textbook and which did not.
Fifth, the sample selection is inadequate, as all the participants are students of one course in a single university. Moreover, the study fails to account for extraneous variables that might affect the results, such as the students' prior knowledge, motivation, and study habits.
Therefore, the textbooks are not necessary or helpful for learning is premature and cannot be generalized to other courses or universities. The study is flawed, and more research is needed to assess the effect of textbooks on learning.
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McDonald's sells about 150 hamburgers every 3 seconds. How many seconds will it take McDonald's to sell 6,400 hamburgers
Answer:
6250
Step-by-step explanation:
Hope the answer is correct.
twelve bronchial cancer patients who received a certain treatment had an average survival time of 111.3 days with standard deviation 62.9 days. can we conclude from this that the average survival time for all bronchial cancer patients who receive that treatment will be different from 90 days? we will use a 5% significance level.
The one-sample t-test with a significance level of 5% fails to reject the null hypothesis that the mean survival time for all bronchial cancer patients who receive that treatment is equal to 90 days, and the P-value is 0.0974.
To determine whether the average survival time for all bronchial cancer patients who receive that treatment is different from 90 days, we can perform a one-sample t-test. The null hypothesis is that the mean survival time is equal to 90 days, and the alternative hypothesis is that the mean survival time is different from 90 days.
We can use the following formula to calculate the t-statistic:
\($t = \frac{\bar{x} - \mu}{s/\sqrt{n}}$\)
Substituting the given values, we get:
t = (111.3 - 90) / (62.9 / √12) = 1.83
Using a t-distribution table with 11 degrees of freedom, and a significance level of 5%, we find the critical values to be ±2.201.
Since the calculated t-value of 1.83 falls within the range of -2.201 to +2.201, we fail to reject the null hypothesis. This means that we do not have sufficient evidence to conclude that the average survival time for all bronchial cancer patients who receive that treatment is different from 90 days.
To find the P-value using a calculator, we can use the t-distribution with 11 degrees of freedom and calculate the probability of getting a t-value greater than 1.83 or less than -1.83 (since it is a two-tailed test). The P-value turns out to be 0.0974. Rounded to the nearest 4th decimal digit, the P-value is 0.0974.
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Complete question:
Twelve bronchial cancer patients who received a certain treatment had an average survival time of 111.3 days with a standard deviation of 62.9 days. Can we conclude from this that the average survival time for all bronchial cancer patients who receive that treatment will be different from 90 days? We will use a 5% significance level. Do the T-test on your calculator and enter the P-value below. Enter it as a decimal (not a percentage), and round it to the nearest 4th decimal digit.
Find the percent the first number is of the second: 1.5, 7.5
Describe the translation from shape A to
shape B as a vector.
Y
10-
703
9-
8-
7-
6-
5-
4-
3-
2-
1
0
1
23
A
4 5
6 7 8
B
9
10
X
Step-by-step explanation:
vector equals to 5 times 3 times 5 times 7 times 6 times 8 equals 260 ÷ 5454 equals 2 over 1,000 to 0.554
Please help 25 points
Answer:
this is a required answer.
Answer:
Not sure
Step-by-step explanation:
In each of the following equations, determine which variable represents the angle and which variable represents the value of the trigonometric function. (a) In the equation q = sin d, represents the angle and represents the value of the trigonometric function. (b) In the equation p = tan^1 c, represents the angle and represents the value of the trigonometric function. (c) In the equation arccos n = upsilon, represents the angle and represents the value of the trigonometric function.
a) q= sin d
Angle is represented by d, and value is represented by q.
b) p = tan1 c
Angle is represented by c, and value is represented by p.
c) arccos n = ν
Angle is represented by n, and value is represented by v.
Given that,
We have to find the variables that indicate the angle and the value of the trigonometric function in each of the following equations.
In the following three equations:
(a) q = sin d;
(b) p = tan1 c; and
(c) arccos n = ν,
We know that,
a) q= sin d
Angle is represented by d, and value is represented by q.
b) p = tan1 c
Angle is represented by c, and value is represented by p.
c) arccos n = ν
Angle is represented by n, and value is represented by v.
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The measures of two complementary angles are 4x + 14 and 3x - 15. Find the measures of the angles.
Answer:
Step-by-step explanation:
Two angles are complementary if their sum is equal to 90 degrees. So, we can write an equation:
4x + 14 + 3x - 15 = 90
Simplifying and solving for x, we get:
7x - 1 = 90
7x = 91
x = 13
Now, we can use x to find the measures of the two angles:
The first angle is 4x + 14 = 4(13) + 14 = 66 degrees.
The second angle is 3x - 15 = 3(13) - 15 = 24 degrees.
Therefore, the measures of the two angles are 66 degrees and 24 degrees.
a laptop computer is purchased for . each year, its value is of its value the year before. after how many years will the laptop computer be worth or less? (use the calculator provided if necessary.) write the smallest possible whole number answer.
We know that after 10 years, the laptop computer will be worth $100 or less. The smallest possible whole number answer is 10.
Assuming the missing value in the question is the purchase price of the laptop, let's call it "x".
According to the given information, the value of the laptop after one year will be 0.8x (80% of its value the year before).
Similarly, after two years, the value will be (0.8x) x 0.8 = 0.64x (64% of its value the year before).
We can continue this pattern and create an equation:
0.8^n x = 100
where n is the number of years it takes for the laptop to be worth $100 or less.
To solve for n, we can divide both sides by x and take the logarithm base 0.8:
log(100/x) / log(0.8) = n
Using a calculator, we get n = 10.
Therefore, after 10 years, the laptop computer will be worth $100 or less. The smallest possible whole number answer is 10.
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Multiply. Write your answer as a fraction in simplest form.
5/6(−8/15)=
Answer:
-4/9
Step-by-step explanation:
I used a calculator.
5/6(−8/15) in simplest form is -4/9.
What is a fraction ?A fraction is written in the form of a numerator and a denominator.There are two types of fractions. One is proper fraction in which numerator is less than the denominator and another one is improper fraction in which denominator is less than the numerator.All fractions can be written in the form of p/q, where q ≠ 0 cause anything divided by 0 is undefined.
According to the given questions we have to multiply two fractions (5/6)(-8/15) which is
= -40/90.
= -4/9.
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needed by midnight. will give brainliest to best answer
The solution set is n ≥ 4.
What is an inequality?In mathematics, "inequality" refers to a relationship between two expressions or values that is not equal to each other.
We have the inequality,
4n -1 ≥ 15
To solve the inequality, you may multiply or divide each side by the same positive number, add the same amount to each side, take the same amount away from each side, and more. You must flip the inequality sign if you multiply or divide either side by a negative number.
4n - 1 +1 ≥ 15 +1
4n ≥ 16
n ≥ 4.
And N = 3, inequality does not hold.
Therefore, The solution set is n ≥ 4.
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PLS HELP I WILL MARK BRAINLIST AND GIVE THANKS!!
Answer:
25(7)=175
Step-by-step explanation:
hope this help :3
merry christmas! my teachers gave me work. ill be happy if u help
CAN YALL HELP ME WITH THIS ONEEE!!!!! PLZ
Answer:
b
Step-by-step explanation:
12x12
11x11
10x10
9x9
8x8
7x7
6x6
5x5
4x4
3x3
2x2
1x1
add em together equal 650
Uh plz help ;-;
Plzzzzz
Answer:
B)
the (8+7) x (10 + 7) x (6 + 4)
Step-by-step explanation:
Answer:
D- (8×10×6) + (7×7×4)
Step-by-step explanation:
The formula for volume is Length×Width×Height.
So you have to find the volume for each one individually then add them up together.
(You can give the other person brainliest if u want.)
Hope it Helps!:)
Area = 17.45cm?
Find the size of the angle in the sector below.
Give your answer to 1 decimal place. IM
e
5cm
Enter your maths answer
Answer:
\(\theta=79.98^{\circ}\)
Step-by-step explanation:
Given that,
The area of sector, A = 17.45 cm²
Radius, r = 5 cm
We need to find the angle in the given sector. The area of a sector is given by :
\(A=\dfrac{\theta}{360}\times \pi r^2\)
Where
\(\theta\) is the angle of sector
\(\theta=\dfrac{360\times A}{\pi r^2}\\\\\theta=\dfrac{360\times 17.45}{\pi \times (5)^2}\\\\\theta=79.98^{\circ}\)
So, the angle of sector is \(79.98^{\circ}\).
Please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!
Answer:
Step-by-step explanation:
C
Write an absolute value inequality for the recommended air pressure range for each type of ball. Use the variable x for the ball's actual air pressure. Soccerball 12.05 recommended psi tolerance+3.55 Basketball 8.00 average recommended psi tolerance +0.5 volleyball 4.44 average recommended psi tolerance +0.18
Answer:
For Soccer ball:
x = | 12. 05 + 3.55 |
For basketball:
x = | 8.00 + 0.5 |
For volleyball:
x = | 4.44 + 0.18 |
Step-by-step explanation:
Given the following :
Let x = ball's actual air pressure
_________avg Recommended psi ___tolerance
Soccer ball____ 12. 05 ____________+3.55
Basketball _____8. 00_____________+0.5
Volleyball _____ 4.44 _____________ + 0.18
Actual air pressure = | average recommended psi + tolerance |
Hence ;
For Soccer ball:
x = | 12. 05 + 3.55 |
For basketball:
x = | 8.00 + 0.5 |
For volleyball:
x = | 4.44 + 0.18 |
$52 for 4 hours of work. How much is earned in 1 hour?
Answer:
$13.50 Per Hour
Step-by-step explanation:
We find the unit rate by dividing it to the number of hours at work
$54/4 = $13.50
The answer will be $13.50 per hour
Answer:
You earn $ 13.5 in an hour
test the hypothesis that the mean weight of the two sheets is equal (μ1−μ2)against the alternative that it is not (and assume equal variances). find the t-stat to 3 decimal places.
To test the hypothesis that the mean weight of two sheets is equal (μ1 - μ2) against the alternative that it is not, and assuming equal variances, we can use a two-sample t-test. The t-statistic can be calculated using the following formula:
t = (x1 - x2) / (s_p * sqrt(1/n1 + 1/n2))
where:
x1 and x2 are the sample means of the two sheets,
s_p is the pooled standard deviation,
n1 and n2 are the sample sizes.
The pooled standard deviation (s_p) can be calculated using the following formula:
s_p = sqrt(((n1 - 1) * s1^2 + (n2 - 1) * s2^2) / (n1 + n2 - 2))
where:
s1 and s2 are the sample standard deviations.
To calculate the t-statistic, we need the sample means, sample standard deviations, and sample sizes.
Once you provide the specific values for these variables, I can assist you in calculating the t-statistic to 3 decimal places.
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To test the hypothesis that the mean weight of the two sheets is equal (μ1 - μ2) against the alternative that it is not, we can use a paired t-test assuming equal variances. The paired t-test is used when we have paired data or measurements on the same subjects or objects.
The t-statistic for a paired t-test is calculated as follows:
t = (X1 - X2) / (s / √n)
where X1 and X2 are the sample means of the two samples, s is the pooled standard deviation, and n is the number of pairs.
Please provide the sample means, standard deviation, and sample size for each sheet so that we can calculate the t-statistic to 3 decimal places.
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A pilot flies in a straight path for 4 hours. He then makes a course correction, heading 20° to the right of his original course, and flies 4 hours in the new direction. If he maintains a constant speed of 115 miles per hour, how far is he from his starting position? Round your final answer to the nearest mile.
To find the distance the pilot is from his starting position, we can break down the problem into two components the horizontal distance covered during the course correction. As a result, total distance is 460 + 460 × 0.9397 ≈ 460 + 432.662 ≈ 892.66 miles.
First, let's calculate the distance covered in the initial straight path. Since the pilot flies for 4 hours at a constant speed of 115 miles per hour, the horizontal distance covered can be found using the formula: distance = speed × time. Thus, the distance covered in the initial straight path is 115 × 4 = 460 miles.
Next, let's calculate the distance covered during the course correction. The pilot makes a course correction of 20° to the right of his original course and flies for 4 hours. We can use trigonometry to calculate the horizontal distance covered.
The horizontal distance can be found using the formula: distance = speed × time × cosine(angle). In this case, the speed is still 115 miles per hour, the time is 4 hours, and the angle is 20°. Thus, the distance covered during the course correction is 115 × 4 × cos(20°) = 460 × cos(20°) miles.
To find the total distance from the starting position, we need to sum the distance covered in the initial straight path and the distance covered during the course correction. So the total distance is 460 + 460 × cos(20°) miles.
Now, we can calculate the final answer by plugging in the values. Using a calculator, we find that cos(20°) is approximately 0.9397. Therefore, the total distance is 460 + 460 × 0.9397 ≈ 460 + 432.662 ≈ 892.66 miles. Rounding to the nearest mile, the pilot is approximately 893 miles from his starting position.
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Which tatement are true? Select all that apply. A) The equation |-x - 4| = 8 will have two olution. B) The equation 3. 4|0. 5x - 42. 1| = -20. 6 will have one olution. C) The equation |1/2x - 3/4| = 0 will have no olution. D) The equation |2x - 10| = -20 will have two olution. E) The equation |0. 5x - 0. 75| 4. 6 = 0. 25 will have no olution. F) The equation |1/8x - 1| = 5 will have infinitely many olution
The true statement is option (A) The equation |-x - 4| = 8 will have two solution
Consider each statement
All the statements are absolute value equation
Part A
|-x-4| = 8
We can write it in two way
-x - 4 = 8
- x = 12
x = -12
Then,
-(-x-4) = 8
x+4 = 8
x = 4
It has two solution
Part B
3. 4|0. 5x - 42. 1| = -20. 6
Divide both side by 3.4
|0.5x - 42.1| = -103/17
Absolute value cannot be negative
The equation has no solution
Part C
|1/2x - 3/4| = 0
1/2x - 3/4 = 0
1/2x = 3/4
x = 3/4 ÷ 1/2
x = 3/2
The equation has one solution
Part D
|2x - 10| = -20
Absolute value cannot be negative
This equation has no solution
Part E
|0. 5x - 0. 75| 4. 6 = 0. 25
Divide both side by 4.6
|0.5x - 0.75| = 5/92
The equation divided into two
0.5x - 0.75 = 5/92
x = 37/23
0.5x - 0.75 = -5/92
x = 32/23
The equation has two solution
Part F
|1/8x - 1| = 5
1/8x - 1 = 5
x = 48
1/8x - 1 = -5
x = -32
The equation has two solution
Therefore, the equation |-x - 4| = 8 will have two solution is true
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