Anthony walks to Village Italian pizza place for lunch. He walks 1 km east, then 3 km south and then 1 km west again. What is the total distance Anthony travels to eat pizza? What is his displacement?

Answer:

110N north west

Explanation:

.........

If three forces F1 = 20N, 300NE, F2 = 50N along W, F3 = 40N 500NW act on a body. The resultant in magnitude and direction  is 110N north west

Force is a  quantitative parameter and it is an interaction between two physical bodies such as an object and its environment, there are different types of forces in nature.

it can be  defined as pushing or pulling of any object resulting from the object’s interaction or movement, without force the objects can not move

If an object in moving state the it will be either static or motion, the position of the object will only be changed if it is pushed or pulled and The external push or pull upon the object called as Force.

The contact force types  are  Spring Force, Applied Force, Air Resistance Force, Normal Force, Tension Force, Frictional Force

Non-Contact forces are occur from a distance  such as Electromagnetic Force, Gravitational Force, Nuclear Force

For more details Force,  visit

brainly.com/question/13691251

#SPJ2

270 FAST bacteria occupy the culture at time t = 10 s and 318 FAST bacteria occupy the culture at time t = 11 s.

Define FAST bacteria.

A group of bacteria with the property of acid fastness is referred to as acid-fast bacteria, sometimes known as acid-fast bacilli or simply AFB. A bacterium's capacity to withstand acid decolorization during staining methods is known as acid fastness.

Mycobacteria's high mycolic acid concentration, which causes the staining pattern of poor absorption followed by significant retention, is what makes them acid-fast.

At t = 10 s

N(t) = 10+6t+2t^2

N(t) = 10 +6*10 + 2*10*10

      = 270

At t  = 11s

N(t) =  10+6*11+2*11*11

     =  318

Difference between two will be 318 - 270 =  48

Rate of bacterial growth will be (270-10/270) *100%

i.e. 96.2%

To learn more about bacteria use link belwo:

https://brainly.com/question/8695285

#SPJ1

Answer:

1.5

Explanation:

Answer:

v=fy

Explanation:

v=fy

v= speed of light

f=frequency

y=wave lenght

make f subject of formula in this case

v=fy

f=v/y

f=20/5

f=4Hz

Answer: 2a- 0.4167s

Explanation:

Given: distance= 5m, speed= 12m/s

Unknown: time

Equation: t= d/s

Substitution: t=5/12

t=0.4167s

Protein

it's the main component of muscles, bones, organs ext.

Answer:

Earth is on a tilted axis.

Explanation:

Answer:

The magnitude of the angular acceleration of the wheel is 14.53 rad/s².

Explanation:

The angular acceleration can be found by using the following equation:

\( \omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \Delta \theta \)  (1)

Where:

\( \omega_{f}\): is the final angular velocity = 18 rad/s

\(\omega_{0}\): is the initial angular velocity

α: is the angular acceleration =?

Δθ = 19 rev*(2π/1 rev) = 119.4 rad

The initial angular velocity can be found knowing that the wheel turns through 19 revolutions during a 3 s time interval:

\( \omega_{f} = \omega_{0} + \alpha t \)

Where:  

t: is the time = 3 s

By solving the above equation for ω₀ we have:

\( \omega_{0} = \omega_{f} - \alpha t \)   (2)

Now, by entering equation (2) into (1) we have:

\( \omega_{f}^{2} = (\omega_{f} - \alpha t)^{2} + 2\alpha \Delta \theta \)                        

\( \omega_{f}^{2} = \omega_{f}^{2} - 2\omega_{f} \alpha t + (\alpha t)^{2} + 2\alpha \Delta \theta \)                              

\((9\alpha)^{2} + 130.8 \alpha = 0\)  

By solving the above equation for "α" we have:

α = -14.53    

The minus sign means that the wheel is decelerating.

Hence, the angular acceleration of the wheel is -14.53 rad/s².                                                                                            

I hope it helps you!

Answer:

19.01 N

Explanation:

F = Force being applied to the crate = 45 N

\(\theta\) = Angle at which the force is being applied = \(65^{\circ}\)

Horizontal component of force is given by

\(F_x=F\cos\theta\\\Rightarrow F_x=45\times \cos65^{\circ}\\\Rightarrow F_x=19.01\ \text{N}\)

The horizontal component of the force acting on the crate is 19.01 N.

Answer:

The graphs are attached

Explanation:

We are told that he started at rest at rest and travelled down the hill reaching a velocity of 20 m/s after 13 seconds.

Acceleration is gotten from;

v = u + at

a = (v - u)/t

a = (20 - 0)/13

a = 20/13 m/s² or 1.54 m/s²

Distance in this period is gotten from;

v² = u² + 2as

s = (v² - u²)/2s

s = (20² - 0²)/(2 × 20/13)

s = 400/(40/13)

s = 130 m

We are told that after reaching the bottom of the hill, he travelled at a constant velocity of 20 m/s for the next 7 seconds.

At constant velocity, acceleration is 0.

Thus,distance in this period is;

s1 = vt = 20 × 7 = 140 m

I've attached the graphs

Firstly, the fibers that constitute a shirt are usually transparent. Shirt materials are mostly transparent and reflect slightly light rays that interact with its surface. It is most likely for all the light to be

reflected, the light that gets to the lower layers of the fibers is also reflected.

Spilling water on your shirts blocks the pore spaces of the shirt where air usually resides. This singular act c

Answer:

a Doe

A baby mouse is called a 'pinky', a male is called a 'buck' and a female is called a 'doe'.

(hope that helped)

Answer:

Muscle Tissue

Explanation:

Sorry if I'm wrong

The escape velocity (Ve) which is required by the particle to escape the gravitational field of the Earth is 110.87  × 10³ km/sec.

Escape velocity is the minimum velocity that a moving body such as a rocket must possess to escape from the gravitational field of a celestial body like the Earth and move outward into space.

Particle is above the surface of Earth (r) = 1600 km = 16 × 10⁵m

Radius of Earth (Re) = 6400 km = 64 × 10⁵m

Acceleration due to gravity (g) = 9.8m/s²

To find the value of escape velocity (Ve),

We know,

Ve = √2 gR

Ve = √2 g (Re + r)

Ve = √2 g (64 + 16) × 10⁵

Ve = √2 × 9.8 × 80 × 10⁵

Ve = 1108.743 × 10⁵

Ve =  110.8743 × 10⁶

Ve = 110.87 × 10³ km/sec.

Therefore, the escape velocity (Ve) is 110.87 × 10³ km/sec.

Learn more about Escape velocity here:

https://brainly.com/question/14297933

#SPJ1

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

To know more about Work:

https://brainly.com/question/13662169

#SPJ1

equal in magnitude but opposite in direction

Heya!!

For calculate aceleration, lets applicate formula:

                                                   \(\boxed{a=\frac{V-V_o}{t} }\)

                                                   Δ   Being   Δ

                                          V = Final Velocity = 5 m/s

                                         Vo = Initial Velocity = 2 m/s

                                          a = Aceleration = ? m/s²

                                                   t = Time = 7 s

⇒ Let's replace according the formula:

\(\boxed{a=\frac{5\ m/s - 2 \ m/s}{7\ s} }\)

⇒ Resolving

\(\boxed{ a=0,428\ m/s^{2}}\)

Result:

The aceleration of the object is 0,428 m/s²

Good Luck!!

Answer:

Ksasdasd

Explanation:

The release of energy during fusion because the mass of the resulting single nucleus is smaller than the combined mass of the two initial nuclei, the process produces energy. Remaining mass is converted to energy.

what is Nuclear fusion?

A reaction known as nuclear fusion occurs when two or more atomic nuclei fuse to create new atomic and subatomic particles.

Mass energy equivalence describes the relation between mass and energy  when system is in rest frame. According to Einstein's equation, mass and energy can be transformed into one another (E=mc2).

when energy is lost the mass of the system will also decrease in proportion. The energy and mass can be discharged into the environment as heat energy or radiant energy like light.

TO MORE ABOUT MASS ENERGY EQUIVALENCE REFER

brainly.com/question/27919071

#SPJ10

This means that the release of energy from a nuclear reaction creates enough of a mass difference to be measured.

To learn more about Mass-Energy Equivalence refer:

https://brainly.com/question/3171044

#SPJ10

Answer:

T = 1733.16 s = 28.88 min

Explanation:

The orbital velocity of a satellite about Earth is given as follows:

\(v = \sqrt{\frac{GM}{R}}\)

where,

v = orbital speed = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

M = Mass of Earth = 5.982 x 10²⁴ kg

R = Orbit Radius = 3.117 x 10⁶ m

Therefore,

\(v = \sqrt{\frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(5.982\ x\ 10^{24}\ kg)}{(3.117\ x\ 10^{6}\ m)}}\\\\v = 11.3\ x\ 10^{3}\ m/s\)

but the velocity is given as:

\(v = \frac{distance}{time}\)

for distance = circumference = 2πR

time = time period = T = ?

Therefore,

\(11.3\ x\ 10^{3}\ m/s = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{T}\\\\T = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{11.3\ x\ 10^{3}\ m/s}\\\\\)

T = 1733.16 s = 28.88 min

To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

As a result, when Andrew is moving at a speed of 31 m/s, his momentum is 2077 kg*m/s.

Kinetic energy has the following formula: K.E. = 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilogrammes-meters squared per second squared if the mass is measured in kilogrammes and the velocity is measured in metres per second.

An object's mass (m) and velocity (v) can be multiplied to find its momentum (p), which is written as:

p = m * v

Given that Andrew's mass is 67 kg and his velocity is 31 m/s, his momentum can be calculated as:

p = 67 kg * 31 m/s

p = 2077 kg*m/s

To know more about momentum visit:-

https://brainly.com/question/30677308

#SPJ1

Question:

Andrew is riding his bike up a hill. At some point, he stops and rests at the top of the hill. He then turns around and starts riding down the hill. When he reaches a velocity of 31 m/s, calculate his momentum. Andrew's mass is 67 kg.

Answer:(-4,3)

Explanation: They didn’t show the whole graph so it looks confusing but it’s not.

The time taken for the object to travel the given height is determined as 12.48 seconds.

Time of motion of an object is the total time taken by the object to travel a given height or distance.

The time of motion of the boulder is calculated as follows;

h = vt + ¹/₂gt²

where;

1300 = 43t  +  0.5(9.8)t²

1300 = 43t + 4.9t²

4.9t² + 43t - 1300 = 0

solve the quadratic equation using formula method as shown below;

a = 4.9, b = 43, c = -1300

t = 12.48 seconds

Thus, the time taken for the object to travel the given height is determined as 12.48 seconds.

Learn more about time of motion here: https://brainly.com/question/2364404

#SPJ1

The image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.

Given that,

Object distance, u = -15 cm

The radius of curvature of the concave mirror, R = 20 cm

Focal length, f = R/2 = -10 cm (negative for concave mirror)

Let v is the distance between mirror and the formed image. Using mirror's formula to find it as :

\($\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$\)

\($\frac{1}{v}=\frac{1}{f}-\frac{1}{u}$\)

\($\frac{1}{v}=\frac{1}{(-10)}-\frac{1}{(-15)}$\)

\($v=-30 \mathrm{~cm}$\)

So, the image will be formed at a distance of 30 cm in its front. Hence, this is the required solution.

To learn more about concave mirror visit:https://brainly.com/question/3555871

#SPJ9

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

To know more about fusion heat , visit ;

brainly.com/question/14053504

#SPJ1

a. The ball's velocity after 0.24 s is 0.75 m/s

b. The acceleration of the ball is given by the acceleration due to gravity

a. The ball's velocity can be calculated with the following equation:

\( v_{f} = v_{0} - gt \)

Where:

\( v_{f} \): is the final speed =?

\(v_{0}\): is the initial speed = 3.1 m/s

g: is the acceleration due to gravity = 9.81 m/s²

t: is the time = 0.24 s

The minus sign is because the acceleration is in the opposite direction (downward) of the motion of the ball (upward).

The final speed is:

\( v_{f} = v_{0} - gt = 3.1 m/s - 9.81 m/s^{2}*0.24 s = 0.75 m/s \)

Hence, the ball's velocity after 0.24 s is 0.75 m/s.

b. The acceleration of the ball is given by the acceleration due to gravity because the ball is thrown straight up (the motion of the ball is in the y-direction). The velocity of the ball in the x-direction is zero so the acceleration in the same direction is also zero.  

You can see another example of velocity here: https://brainly.com/question/13388351?referrer=searchResults

I hope it helps you!