Animal cells contain one large, central vacuole while plant cells have
many smaller vacuoles throughout the cell.
True or false?
Answers
Related Questions
HELP PLZZ i think the answer is either C or D.
Scientists hypothesize Earth’s early atmosphere was a result of outgassing from the interior of the planet. Gravity trapped the gasses (including NH3 and CO2) close to Earth’s surface. Over time, bacteria with the ability to perform photosynthesis changed the composition of the atmosphere. As plants evolved, levels of oxygen continued to increase as the levels of carbon dioxide decreased. The hydrosphere – primarily the ocean – played a major role absorbing carbon dioxide from the atmosphere. As plants grew on Earth’s surface, they weathered the geosphere producing soil. Microorganisms in the soil allowed for the evolution of land plants which also extended the boundaries for early animal populations.
As outgassing and volcanic eruptions created Earth’s early atmosphere, what two spheres directly affected one another?
A) Biosphere and geosphere
B) Hydrosphere and biosphere
C) Geosphere and atmosphere
D) Atmosphere and hydrosphere
Answers
Answer:
hi I believe the answer is (C)
Explanation:
I'm not 100%, sure if (C) is the right answer sorry I just have a feeling that's it (C) and also after I did a little tad bit of research but I'm sorry if it isn't right. ( well I'm going to go to sleep.,. I hope you get a good grade in your assignment:>)
2 moles of NO, was placed in an empty I dm' bottle and allowed to reach equilibrium according to the equation:
At equilibrium, 1.2 moles of N,O, dissociated. Calculate the value of the equilibrium constant for the reaction at that
temperature.
Answers
2NO(g) ⇌ N2(g) + O2(g)
According to the problem statement, 2 moles of NO were placed in a 1 dm^3 bottle and allowed to reach equilibrium, and at equilibrium, 1.2 moles of NO had dissociated. This means that the initial concentration of NO was:
[NO]initial = 2 mol / 1 dm^3 = 2 M
And the concentration of NO at equilibrium is:
[NO]equilibrium = (2 - 1.2) mol / 1 dm^3 = 0.8 M
Since the stoichiometry of the balanced equation is 2:1:1 for NO, N2, and O2, respectively, the equilibrium concentrations of N2 and O2 will also be 0.6 M.
The equilibrium constant (Kc) can be calculated using the equilibrium concentrations of the reactants and products, raised to the power of their stoichiometric coefficients. Therefore:
Kc = ([N2][O2]) / ([NO]^2)
Substituting the equilibrium concentrations into the equation, we get:
Kc = (0.6 M x 0.6 M) / (0.8 M x 0.8 M)
Kc = 0.5625
Therefore, the value of the equilibrium constant for the reaction at that temperature is 0.5625. Note that the units of Kc depend on the stoichiometry of the balanced equation. Since the stoichiometric coefficients are all 1, the units of Kc in this case are M^-1
What color would the methyl orange indicator turn in a solution with a pH of 2?
Answers
Answer:
The answer is red.
Explanation:
Methyl orange is an organic dye that used as an indicator in acid-base titrations because its color is changed according to pH of the medium (acidic, neutral or basic).Methyl orange is red in acidic solutions, orange in neutral solutions, and yellow in basic solutions.Since pH of the solution is 2, the solution is acidic, the color of the solution will be red.
ASAP PLS
Identify the correct formula for each of the following compounds.
Carbon tetrabromide
4CBr
CBr4
C4Br
Chlorine monofluoride
ClF
FCl
Cl1F1
Answers
Answer:
1.CBr4
2.CIF
Explanation:
Covalent compound are formed by sharing of electron and ionic compound formed by complete transfer of electron. The chemical formula for Carbon tetrabromide is CBr₄ and for Chlorine monofluoride is ClF.
What is chemical Compound?Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.
Ionic compounds are more stronger than covalent compound. Ionic compounds have higher melting and boiling point than covalent compounds.
The chemical formula for Carbon tetrabromide is CBr₄, tetra means four. The chemical formula for Chlorine monofluoride is ClF, mono means one.
Therefore, the chemical formula for Carbon tetrabromide is CBr₄ and for Chlorine monofluoride is ClF.
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How many grams are there in 7.40 moles of AgNO3
Answers
Answer:
169.87 grams
Explanation:
Consider the following reaction… 5C + 2SO2 CS2 + 4CO a) How many moles of CS2 would be produced by reacting 9.50 moles of SO2 with an excess of C? _________________ b) How many grams of C would be needed to fully react 5.5 L of SO2 at STP? _________________ c) How many liters of CO can be produced from 20.0 moles of C at STP?
Answers
We first verify that the equation is balanced. We have 5 carbons (C), 2 sulfurs (S), and 4 oxygens (O) on each side of the reaction. So the reaction is balanced.
a) Now if we look at the reaction we can see that when 2 moles of SO2 react, 1 mole of CS2 is produced. That is, the ratio is 2 to 1. For each mole of SO2 half as many moles of CS2 will be produced.
So if we have 9.5 moles of SO2 we will have 9.5/2 moles, that is 4.75 moles of CS2.
Answer a) By reacting 9.50 moles of SO2 with an excess of it would be produced 4.75 moles of CS2.
Now, for the following parts of the question, we can apply the ideal gas law. This is because the reaction is in the gas phase and the law applies only to gases.
\(PV=nR_{}T\)Where,
P= Pressure at STP = 1 atm
T= Temperature at STP = 273.15K
R= Ideal law constant = 0.08206 (atm L)/(mol K)
V= Volume of the gas
n= Numer of moles
b)We clear n and we replace the known values of SO2 to find the number of moles of SO2 that react.
\(\begin{gathered} n=\frac{PV}{RT}=\frac{1at_{}m\times5.5L}{0.08206\frac{atm.L}{\text{mol}\mathrm{}K}\times273.15K} \\ n=0.24mol\text{ SO}_2 \end{gathered}\)Now, for each mole of SO2 that reacts we need 5/2 moles of C, that is 0.24x5/2=0.61 moles of C.
We use mass molar of C to calculate the grams.
Mass molar of C=12.01g/mol
Mass of C= Moles of C x Mass Molar
Mass of C= 0.61 mol x 12.01 g/mol = 7.37 g
So, To fully react 5.5 L of SO2 at STP we will need 7.37 g of C.
c)We apply the gas law again but this time we clear the volume.
We also take into account that for each mole of C, 4 moles of CO are produced, so if we have 20 moles of C we will produce 20x4=80 moles of CO.
\(\begin{gathered} V=\frac{nRT}{P} \\ V=\frac{80mol\times0.08206\frac{atm.L}{mol.K}\times273.15K}{1atm} \\ V=\text{ 1793.18 L} \end{gathered}\)So, from 20.0 moles of C at STP can be produced 1793.18 liters of CO
element e reacts with oxygen to produce eo2. identify element e if 16.5 g of it react with excess oxygen to form 26.1 g of eo2.
Answers
Element e reacts with oxygen to produce eo2. The unknown element e is sulfur (S) if 16.5 g of it react with excess oxygen to form 26.1 g of eo2.
We can use the given information to find the molar mass of the unknown element E and then use that to identify the element.
First, we can use the given mass of EO2 to calculate the number of moles of EO2 produced:
Mass of EO2 = 26.1 g
Molar mass of EO2 = 16.00 g/mol (oxygen) + 1.00 g/mol (element E) = 17.00 g/mol
Number of moles of EO2 = Mass of EO2 / Molar mass of EO2 = 26.1 g / 17.00 g/mol = 1.535 moles
Since the balanced chemical equation for the reaction is E + O2 → EO2, we know that the number of moles of E is the same as the number of moles of EO2.
Number of moles of E = 1.535 moles
Now we can use the mass of E and the number of moles of E to find the molar mass of E:
Mass of E = 16.5 g
Number of moles of E = Mass of E / Molar mass of E
Molar mass of E = Mass of E / Number of moles of E = 16.5 g / 1.535 mol = 10.74 g/mol
Based on the molar mass, we can identify the element as sulfur (S), which has a molar mass of 32.06 g/mol. Therefore, the unknown element E is sulfur (S).
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Which physical change is represented by the diagram below? SC.8.P.9.2
Answers
Answer: Substances giving off heat and light, themselves, is always chemical. What we see in the sky are new colors and light. 1. Changing the size and shapes of pieces of wood would be a chemical change. 2. In a physical change, the makeup of matter is changed.
Explanation:
what is 0.1 n hcl standardization?
Answers
The abbreviation 0.1 N HCl means normal hydrochloric acid.By comparing a solution to a standard solution with a known concentration, standardisation is the process of determining the precise concentration
By comparing a solution to a standard solution with a known concentration, standardisation is the process of determining the precise concentration of the solution. As precise concentration measurements are necessary for many scientific and industrial applications, it is a crucial stage in chemical analysis. In order to determine the concentration of the unknown solution, the standardisation procedure entails mixing a measured amount of the standard solution with a known quantity of the solution being tested. The primary standard, which is a pure material with a known and steady concentration, is often the standard solution. Standardization is used in many disciplines, including chemistry, biology, and engineering, to assure
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calculate the ph of a solution prepared by dissolving 0.150 mol of benzoic acid and 0.300 mol of sodium benzoate in water sufficient to yield 1.00 l of solution. the ka of benzoic acid is 6.30 x 10-5. group of answer choices 10.158 4.195 4.502 2.516 3.892
Answers
Benzoic acid is a weak acid that will undergo dissociation in water to produce H+ ions. The balanced chemical equation for this dissociation is as follows:
C6H5COOH + H2O ⇌ C6H5COO- + H3O+
The Ka expression for this reaction is:
Ka = [C6H5COO-][H3O+] / [C6H5COOH]
Since we know the value of Ka and the initial concentrations of benzoic acid and sodium benzoate, we can set up an ICE table to determine the equilibrium concentrations of the species in solution.
Initial concentrations:
[C6H5COOH] = 0.150 M
[C6H5COO-] = 0.300 M
[H3O+] = 0 M
Change in concentrations:
[C6H5COOH] = -x
[C6H5COO-] = +x
[H3O+] = +x
Equilibrium concentrations:
[C6H5COOH] = 0.150 - x
[C6H5COO-] = 0.300 + x
[H3O+] = x
Now, we can substitute these values into the Ka expression and solve for x.
Ka = 6.30 x 10^-5 = (0.300 + x)(x) / (0.150 - x)
Solving for x gives us x = 3.47 x 10^-3 M.
Therefore, the pH of the solution is:
pH = -log[H3O+] = -log(3.47 x 10^-3) = 2.46
Therefore, the pH of the solution is 2.46.
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write the net cell equation for the electrochemical cell. phases are optional. do not include the concentrations.sn(s)||sn2 (aq,0.0155 m)‖‖ag (aq,1.50 m)||ag(s) net cell equation: calculate ????∘cell and ????cell at 25 °c , using standard potentials as needed.????∘cell
Answers
The ∆cell° is +0.66 V and Ecell at 25 °C is +1.94 V.
The net cell equation for the electrochemical cell you provided is as follows:
Sn(s) + 2Ag+(aq) → Sn2+(aq) + 2Ag(s)
In this cell, solid tin (Sn) is in contact with a solution of tin ions (Sn2+) with a concentration of 0.0155 M, and solid silver (Ag) is in contact with a solution of silver ions (Ag+) with a concentration of 1.50 M.
To calculate ∆cell° and Ecell at 25 °C, you will need to use standard potentials. The standard potential of a half-cell reaction is the potential of the reduction half-reaction when all reactants and products are at standard state conditions (1 M concentration and 1 atm pressure). The standard potential of the half-cell reaction involving tin is given by the equation:
Sn2+(aq) + 2e- → Sn(s) E°red = +0.14 V
The standard potential of the half-cell reaction involving silver is given by the equation:
Ag+(aq) + e- → Ag(s) E°red = +0.80 V
To calculate ∆cell°, you need to subtract the standard reduction potential of the anode reaction (tin) from the standard reduction potential of the cathode reaction (silver). In this case:
∆cell° = E°cathode - E°anode
= (+0.80 V) - (+0.14 V)
= +0.66 V
To calculate Ecell at 25 °C, you can use the Nernst equation:
Ecell = E°cell - (0.0592 V/n) log(Q)
Where Q is the reaction quotient. In this case, Q can be calculated using the concentrations of Sn2+ and Ag+:
Q = [Sn2+]/[Ag+]^2
= (0.0155 M)/(1.50 M)^2
= 0.0065
Plugging the values into the Nernst equation:
Ecell = +0.66 V - (0.0592 V/2) log(0.0065)
Ecell = +0.66 V - 0.0296 V log(0.0065)
Ecell = +0.66 V - (-1.28 V)
Ecell = +0.66 V + 1.28 V
Ecell = +1.94 V
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Mole Conversion: How many atoms are in 0.830 moles of gold?
Answers
Answer:
4.99 × 10²³ atomsExplanation:
The number of atoms of gold can be found by using the formula
N = n × Lwhere n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.83 × 6.02 × 10²³
We have the final answer as
4.99 × 10²³ atomsHope this helps you
Taking two positively charged objects and holding them close to one another creates a system with electric potential energy
One way to lower the electric potential energy in a system like this would be to
A increase the distance between the two charges.
B decrease the distance between the two charges.
C decrease the mass of one of the objects
D increase the mass of one of the objects
Answers
Electric potential energy is the energy that is stored in a system of two or more electrically charged objects due to their position relative to each other. As the distance between the charged objects increases, the electric potential energy of the system decreases. This is because the electrical force between the objects decreases as the distance between them increases. Therefore, by increasing the distance between two positively charged objects, the electric potential energy of the system will decrease.
Decreasing the distance between the two charges (option B) would actually increase the electric potential energy of the system, as the electrical force between the objects would increase. Changing the mass of the objects (options C and D) would not have any effect on the electric potential energy of the system, as electric potential energy depends only on the charges and their separation distance.
What are the IUPAC names for Ascorbic Acid, Fructose, and Glucose?
Answers
Answer:
The IUPAC names for Ascorbic Acid, Fructose, and Glucose are L-ascorbic acid, D-fructose, and D-glucose, respectively.
Explanation:
IUPAC (International Union of Pure and Applied Chemistry) names are standardized names used to identify chemical compounds. These names are based on the structure of the compound, and they provide a unique and unambiguous way to identify each compound.
The IUPAC name for Ascorbic Acid is L-ascorbic acid. Ascorbic acid is a compound with the chemical formula C6H8O6. It is a white, crystalline solid that is soluble in water. The "L" in the name indicates that the compound has a specific configuration of atoms, which is called the L-configuration.
The IUPAC name for Fructose is D-fructose. Fructose is a simple sugar with the chemical formula C6H12O6. It is a sweet-tasting substance that is commonly found in fruits and honey. The "D" in the name indicates that the compound has a specific configuration of atoms, which is called the D-configuration.
The IUPAC name for Glucose is D-glucose. Glucose is a simple sugar with the chemical formula C6H12O6. It is a sweet-tasting substance that is commonly found in plants and is an important source of energy for living organisms. The "D" in the name indicates that the compound has a specific configuration of atoms, which is called the D-configuration.
Answer:
The IUPAC name for ascorbic acid is 2-(1,2-dihydroxyethyl)-4,5-dihydroxyfuran-3-one.
The IUPAC name for fructose is (2R,3S,4R,5R)-2-(hydroxymethyl)-3,4,5-trihydroxytetrahydrofuran-3-ulose.
The IUPAC name for glucose is (2R,3R,4S,5S)-2-(hydroxymethyl)-3,4,5-trihydroxytetrahydrofuran-3-ulose.
Write the names of the metalloids in order from lowest to highest atomic number.
Answers
Answer:
Element 5 - Boron
Element 14 - Silicon
Element 32 - Germanium
Element 33 - Arsenic
Element 51 - Antimony
Element 52 - Tellurium
General Formulas and Concepts:
Chemistry
Reading a Periodic TablePeriodic Table Groups/PeriodsChemical PropertiesExplanation:
Your Metalloids on the Periodic Table define what we know as "The Staircase." It separates the Transition Metals from the Non-metals. Metalloids are found in Groups 13 - 16.
Attached below is the Metalloids in order from the Periodic Table (in Cyan).
The force between electrically charged particles depends on the magnitude of each charge, their separation distance, and what else?.
Answers
When charged matter is placed in an electromagnetic field, it experiences a force due to its physical attribute of electric charge.To understand more about the force between electrically charge particles, we should grasp the idea of Coulomb's Law. It explains that the interaction between charged items is a non-contact force that operates over some distance.On the other hand, magnetic forces could also be generated by moving electric charges. It is categorized as a force due to the motion of the charged particles.
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⚠️Warning need help quick ⚠️
Balancing Equations
I need the solving steps as well
Answers
In the first step in the life cycle of a
star, it is called a:
Answers
Brainiest plx
What does the symbol 2CO represent in the model below? 2CO + o^2 -> 2CO2
Answers
Answer:2CO (g) + O2 (g) 2CO2 (g)This Equation Means That No Matter How Much Carbon Monoxide And Oxygen ... Question: 2CO (g) + O2 (g) 2CO2 (g)This Equation Means That No Matter How Much Carbon Monoxide And Oxygen Gas Is Added To The Flask, Only 2 Moles Of CO And 1 Mole Of O2 Will React To Make Two Moles Of Co2.What Is Wrong With This Statement?
Explanation:
Answer: a reactant
Explanation: online physics class
Can someone please help !! I just need someone to help me figure out how to solve it and solve the picture as an example
Answers
The molar concentration of Al(OH)₃ in the solution is 1.61 M.
we need to calculate the number of moles of Al(OH)3 in the solution:
Number of moles of Al(OH)₃ = mass of Al(OH)3 / molar mass of Al(OH)3
Molar mass of Al(OH)₃ = (1 x atomic mass of Al) + (3 x atomic mass of O) + (3 x atomic mass of H)
Molar mass of Al(OH)₃ = (1 x 26.98 g/mol) + (3 x 16.00 g/mol) + (3 x 1.01 g/mol) = 78.00 g/mol
Number of moles of Al(OH)₃ = 62.7 g / 78.00 g/mol = 0.804 moles
Next, we need to calculate the volume of the solution in liters:
Volume of solution = 500.0 mL = 500.0 mL x (1 L/1000 mL) = 0.500 L
Finally, we can calculate the molar concentration of Al(OH)₃
Molarity = moles of solute/volume of solution in liters
Molarity = 0.804 moles / 0.500 L = 1.61 M
Therefore, the molar concentration of Al(OH)₃ in the solution is 1.61 M.
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how many grams of copper will be plated out by a current of 2.3 a
Answers
To determine the amount of copper plated out by a current of 2.3 A, we need to consider Faraday's law of electrolysis. By applying the formula Q = It, where Q is the quantity of electricity, I is the current, and t is the time.
Faraday's law of electrolysis states that the mass of a substance deposited or liberated during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte. The formula Q = It represents the relationship, where Q is the quantity of electricity in coulombs, I is the current in amperes, and t is the time in seconds.
To calculate the mass of copper plated out, we need to know the molar mass of copper, which is approximately 63.55 g/mol. By rearranging the formula Q = It to solve for Q, we have Q = I × t. Substituting the given current (2.3 A) and the time, we obtain the quantity of electricity in coulombs.
Finally, to find the mass of copper, we divide the quantity of electricity by the Faraday constant, which is 96,485 coulombs per mole. Multiplying this result by the molar mass of copper gives us the mass of copper plated out.
Therefore, by applying Faraday's law of electrolysis, a current of 2.3 A will plate out a certain mass of copper, which can be calculated using the formula Q = It and considering the molar mass of copper.
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A front is a boundary between two _________ ________. *
A. Bodies of land
B. Bodies of water
C. Air masses
D. Cloud sides
Answers
Explanation:
Answer:
C. Air massesExplaination :depending on the air masses involved and which way the fronts move, fronts can be either warm, cold, stationary, or occluded.
Which of the following is the correct order of boiling points for KNO3, CH3OH, C2H6, Ne? (Arranged from lowest to highest boiling point.)a. Ne < CH3OH < C2H6 < KNO3b. KNO3 < Ne < CH3OH < C2H6c. KNO3 < Ne < C2H6 < CH3OHd. Ne < C2H6 < CH3OH < KNO3e. CH3OH < C2H6 < KNO3 < Ne
Answers
The order of the boiling points from highest to lowest is;
\(Ne < C_{2} H_{6} < CH_{3} OH < KNO_{3}\). Option C
What is the boiling point?We know that the boiling point has to do with the temperature of the substance would be equal to the atmospheric pressure that is prevailing in the vicinity. Let us note that the boiling point of the substance would depend on the magnitude of the intermolecular forces that is acting in the substnace.
The greater the magnitude of the intermolecular forces, the more the molecules of the substance would have to be together and a greater energy would have to be exerted so as to break the intermolecular forces that are holding the molecules together.
Since potassium nitrate is an ionic substance then it would have the highest boiling point while the neon that has only dispersion forces would have the lowest boiling point.
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Catabolic reactions are generally used to build molecules and are hydrolytic. Group of answer choices True False
Answers
The statement "Catabolic reactions are generally used to build molecules and are hydrolytic" is false.
Catabolic reactions are generally involved in the breakdown of complex molecules into simpler ones. These reactions release energy by breaking chemical bonds. They are often hydrolytic, meaning they involve the addition of water molecules to break the bonds.
Catabolic reactions are opposite to anabolic reactions, which involve the synthesis or building of complex molecules using energy. Some examples of catabolic reactions include glycolysis, the citric acid cycle, and oxidative phosphorylation.
Catabolic reactions are the opposite of anabolic reactions, which are used to build up molecules. Catabolic reactions are typically hydrolytic, meaning they use water to break down bonds. This releases energy, which can be used for cellular processes. Therefore, the given statement is False.
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how can you blance it and make it equal on both sides
2H2+o2=2H2o blance it
Answers
Answer:
it have been already balanced
2H2 + O2 = 2H2O.
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Question 7
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Question text
Consider the following reaction:
2Si2H6(g) + 7O2(g) ⇌ 4SiO2(g)+6H2O (l)
Give the expression for the equilibrium constant for this reaction. A. (PSi2H6)2(PO2)7/(PSiO2)4
B. (PSi2H6)2(PO2)7(PSiO2)4
C. (PSiO2)4/(PSi2H6)2(PO2)7
D. (PSiO2)4[(H2O])6/(PSi2H6)2(PO2)7
Answers
The equilibrium constant expression for the reaction is (PSiO2)4/(PSi2H6)2(PO2)7. Hence, the correct option is C.
In this expression, the concentrations of the reactants (Si2H6 and O2) are raised to the power of their respective stoichiometric coefficients, and the concentration of the product (SiO2) is raised to the power of its stoichiometric coefficient. The concentration of the liquid product (H2O) is not included in the equilibrium constant expression because it is in the liquid state.
The correct expression for the equilibrium constant (K) for the given reaction is:
C. (PSiO2)4/(PSi2H6)2(PO2)7
Therefore, the equilibrium constant expression for the reaction is (PSiO2)4/(PSi2H6)2(PO2)7.
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Use the periodic table to compare the sizes of ionic radii with the corresponding atomic radii or other ionic radii. Choose from smaller and larger in the blanks below: A sodium cation is than a sodium atom. A phosphorus anion is than a phosphorus atom. A magnesium ion is than a sodium ion. A chlorine ion is than a phosphorus ion. A potassium ion is than a sodium ion.
Answers
Answer:smaller larger smaller smaller larger
Explanation:
Just took the test on edge
Answer:
smaller
larger
smaller
smaller
larger
Explanation:
on edge
300mL of 0.83mol/L acetic acid reacts with 12.0g of sodium carbonate at 21 C and 100.3kPa. What volume of dry carbon dioxide is released in this reaction? Water vapour pressure at this temperature is 2.49 kPa.
Answers
Answer:
The volume that carbon dioxide release is 2.83L
Explanation:
The reaction of acetic acid (CH₃COOH) with sodium carbonate (Na₂CO₃) is:
2 CH₃COOH + Na₂CO₃ →Na₂(CH₃COO)₂ + CO₂ + H₂O
Moles of acetic acid and sodium carbonate (Molar mass: 105.99g/mol) in the reaction are:
Acetic acid: 0.300L ₓ (0.83mol / L) = 0.249 moles.
Sodium carbonate: 12g ₓ (1mol / 105.99g) = 0.113 moles.
Based on the chemical equation, 2 moles of acetic acid reacts per moles of sodium carbonate. For a complete reaction of sodium carbonate you need:
0.113 moles Na₂CO₃ ₓ (2 moles CH₃COOH / 1 mole Na₂CO₃) = 0.226 moles of CH₃COOH
As you have 0.249 moles, Na₂CO₃ is limitng reactant.
As 1 mole of sodium carbonate produce 1 mole of CO₂, from 0.113 moles of Na₂CO₃ you obtain 0.113 moles of CO₂
Using PV = nRT, it is possible to find the volume that a gas occupies, thus:
V = nRT / P
n = 0.113 moles
R = 8.314 kPa×L/mol×K
T = 21°C + 273.15 = 294.15K
P = 100.3kPa - 2.49kPa = 97.81kPa
The vapor pressure is subtracted because is the pressure that water exerted.
Replacing:
V = 0.113mol×8.314 kPa×L/mol×K×294.15K / 97.81kPa
V = 2.83L
The volume that carbon dioxide release is 2.83LWhat is the pH of a solution formed when 100 ML of an acid with a pH of two is diluted 1 L with pure water
Answers
Answer: look down hope I helped
Explanation:
1) First convert to pOH as OH is the dissociating species in a base equilibrium.pH + pOH = 14 (at 25 C)pH=13, hence pOH = 1,Hence [OH] = 10^-1 Mdiluting by factor of 10 with pure water gives [OH] = 10^-2 MThe new pOH = 2, hence the new pH is 12In general, dilution (with pure water) by a factor of 10 moves the pH 1 unit in the direction of the pH of water (pH 7). i.e. it moves up for acids, down for bases.(At infinite dilution of either acids or bases, you’d have pure water - obvious when you think of it like that)
Question 2 (1 point)
N2 + 3H2 --> 2NH3
How many moles of N2 are needed to produce 4.5 moles of NH3?
2.25 moles
3 moles
b
4.5 moles
d
1 mole
Question 3 (1 point)