Andrew is half his brother's age. Three years ago, the sum of their ages was 24. How old are they each now? Please answer Fast.

"High school class rank" is an ordinal-level measurement.

To classify the variable, we need to understand the characteristics of each level of measurement:

Nominal-level: Variables that can be categorized but do not have any inherent order or numerical value. Examples include gender, ethnicity, or favorite color.

Ordinal-level: Variables that can be categorized and have a meaningful order or ranking, but the differences between the categories may not be equal. Examples include satisfaction levels (e.g., very satisfied, satisfied, neutral, dissatisfied, very dissatisfied) or education levels (e.g., high school, bachelor's, master's, Ph.D.).

Interval-level: Variables that have a meaningful order or ranking, and the differences between the categories are equal, but there is no true zero point. Examples include temperature measured in Celsius or Fahrenheit.

Ratio-level: Variables that have a meaningful order or ranking, the differences between the categories are equal, and there is a true zero point. Examples include height, weight, or income.

In the case of "high school class rank," it can be categorized and has a meaningful order or ranking (e.g., first, second, third, etc.). However, the differences between the ranks are not necessarily equal, as there can be a significant gap between ranks. Therefore, "high school class rank" is classified as an ordinal-level measurement.

"High school class rank" is an ordinal-level measurement.

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ACB = AC + BC

ACB = 122 + 192 = 314

The answer is b. 314 degrees

The value of XS = 116, UZ = 43, and VY = 84.

What are perpendicular bisectors?

A line or line segment that divides a given line segment into two equal portions is known as a perpendicular bisector.

Here, we have

Given

The perpendicular bisectors of its sides are TS, US, and VS. They meet at a single point S.

VS 80, YZ=86, and ZS=116 and we have to find XS, UZ, and VY.

TS, US, and VS are perpendicular bisectors

So, XV = VY, YU = UZ, XT = TZ

Then, ΔYST ≅ ΔZST

ΔYSV ≅ ΔXSV

ΔYUS ≅ ΔZUS

So, XS = ZS = 116

UZ = 1/2YZ = 1/2×86 = 43

VY = VX

VX² + VS² = XS²

VX = √XS² -VS²

VX = √116² - 80²

VX = 84

Hence, the value of XS = 116, UZ = 43, and VY = 84.

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Given:

\(\begin{aligned}&x^2+y^2=16 \\&z=x y\end{aligned}\)

Express 16 as \(4^{2}\): \(x^2+y^2=16\)

\(x^2+y^2=4^2\\x^2+y^2=4^2 \times 1\)

Trignometry,

\(\cos ^2(t)+\sin ^2(t)=1\)

Now, substitute \(\cos ^2(t)+\sin ^2(t)\) for 1:

\(\begin{aligned}&x^2+y^2=4^2 \times 1 \\&x^2+y^2=4^2 \times\left[\cos ^2(t)+\sin ^2(t)\right]\end{aligned}\\x^2+y^2=4^2 \times \cos ^2(t)+4^2 \times \sin ^2(t)\)

Law of indicates:
\(\begin{aligned}&x^2+y^2=[4 \times \cos (t)]^2+[4 \times \sin (t)]^2 \\&x^2+y^2=[4 \cos (t)]^2+[4 \sin (t)]^2\end{aligned}\\x^2=[4 \cos (t)]^2 \text { and } y^2=[4 \sin (t)]^2\)

Taking positive square roots as follows:

\(x=4 \cos (t), y=4 \sin (t)\)

Recall that, z = xy.

Now, we have:

\(\begin{aligned}&z=4 \cos (t) \times 4 \sin (t) \\&z=16 \cos (t) \cdot \sin (t)\end{aligned}\)

Now, substitute the values:
\(r(t)=x_t i+y_t j+z_t k\)

So, the vector r(t) is: \(r(t)=(4 \cos (t)) i+(4 \sin (t)) i+(16 \cos (t) \cdot \sin (t)) i\)

Therefore, the vector function r(t) is written as: \(r(t)=x_t i+y_t j+z_t k\)

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Answer:

10

Step-by-step explanation:

-3 = 7 - x

Add x to both sides

x -3 = 7 - x +x

x - 3 = 7

Now, add 3 to both sides

x - 3 + 3 = 7 + 3

x = 10

Answer:

\(\boxed{10}\)

Step-by-step explanation:

\(-3=7- \sf BLANK\)

\(\sf Subtract \ 7 \ from \ sides.\)

\(-3-7=-7+7- \sf BLANK\)

\(-10=- \sf BLANK\)

\(\sf Multiply \ both \ sides \ by \ -1.\)

\(-10(-1)=(-1)- \sf BLANK\)

\(10= \sf BLANK\)

The food percentage would be 19%, 51% and 30%.

Given that we've done it

Number of meals consumed by X = 57

Food consumed by Y = 153.

Number of meals consumed by Z = 90

Total amount of meals consumed = 57 + 153 +90 = 300

Food proportion of flock X thus Equals 57 / 300 * 100 = 19 %

flock food percentage Y =153/300 * 100 = 51 %

flock food percentage Z = 90/300 * 100 = 30 %

This means that the percentages are 19%, 51%, and 30%.

Based on the given information, we have:

Flock X ate 57 pieces of food.

Flock Y ate 153 pieces of food.

Flock Z ate 90 pieces of food.

The total number of pieces of food eaten is 300 (sum of the individual flock's food).

The food percentage for Flock X is 57/300 ≈ 0.19 or 19%.

The food percentage for Flock Y is 153/300 ≈ 0.51 or 51%.

The food percentage for Flock Z is 90/300 = 0.3 or 30%.

The total number of birds for the second generation is 30 (given).

To find the simulated number of birds in each flock for the second generation, we multiply the food percentage for each flock by the total number of birds (30).

For Flock X: 0.19 × 30 = 5.7 (rounded to the nearest whole number: 6 birds)

For Flock Y: 0.51 × 30 = 15.3 (rounded to the nearest whole number: 15 birds)

For Flock Z: 0.3 × 30 = 9 (rounded to the nearest whole number: 9 birds)

Therefore, the simulated number of birds in Flock X, Flock Y, and Flock Z for the second generation are 6, 15, and 9 birds, respectively.

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Complete Question

Flock X Flock Y Flock z Total Pieces of Food Eaten 57 153 90 Food Percentage* % 1% % Simulated Number of Birds in Flock for 2nd Generation ** * Divide each flock's total pieces of food by 300, the total number of pieces of food eaten. ** Multiply the food percentage for each flock by the total number of birds (30). DONE

Answer:

19 51 30

6 15 9

second part Is Y then X

Step-by-step explanation:

The three approximations for \(\sqrt{1.1}\)using the given Taylor polynomials are: p0(x): 1, p1(x): 1.05, p2(x): 1.04875

A Taylor polynomial is a polynomial approximation of a function that is centred at a particular point in calculus. It is created by multiplying the value of a function's derivative calculated at the centre point by a power of the distance from the centre point for each term in the function expansion as a power series. As the degree of the polynomial rises, the Taylor polynomial provides a more precise approximation of the function. Calculus uses it extensively in areas like numerical analysis, optimisation, and approximation theory.

Recall that the Taylor polynomials are used as approximations for a function near a given point, in this case, centered at 0.

1. Using p0(x) = 1:
Since p0(x) = 1 is a constant, it does not depend on x, so the approximation for  \(\sqrt{1.1}\) is simply 1.

2. Using p1(x) = 1 + x/2:
Substitute x = 0.1 (since 1.1 = 1 + 0.1) into p1(x): p1(0.1) = 1 + (0.1)/2 = 1 + 0.05 = 1.05.

3. Using p2(x) = 1 + x/2 - \(x^2\)/8:
Substitute x = 0.1 into p2(x): p2(0.1) = 1 + (0.1)/2 - (0.1)^2/8 = 1 + 0.05 - 0.00125 = 1.04875.

So, the three approximations for  \(\sqrt{1.1}\)  using the given Taylor polynomials are:
1. p0(x): 1
2. p1(x): 1.05
3. p2(x): 1.04875

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Answer:

Step-by-step explanation:

hello : 12=4x   and   x-3=0

The total amount accrued, principal plus interest, with compound interest on a principal of $12,000.00 at a rate of 14% per year compounded 12 times per year over 5 years is $24,067.32.The amount of the initial loan, or principal, is multiplied by one plus the annual interest rate raised to the number of compound periods minus one to determine compound interest.

To begin, change R from a percentage to a decimal, using the formula:

r = R/100 r = 14/100

r = 0.14 rate per year;

Next, find A by solving

A = P(1 + r/n)nt A = 12,000.00(1 + 0.14/12)(12). (5)

A = 12,000.00(1 + 0.011666666666667)(60) (60)

A = $24,067.32

Summary: The total amount accrued, principal plus interest, with compound interest on a principal of $12,000.00 at a rate of 14% per year compounded 12 times per year over 5 years is $24,067.32.

The amount of the initial loan, or principal, is multiplied by one plus the annual interest rate raised to the number of compound periods minus one to determine compound interest. You will then be left with the loan balance plus compound interest.

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Answer: a. ​is always an upper tail test.

Step-by-step explanation:

The chi-square goodness-of-fit test is a test to check whether the sample comes from the population with the expected distribution or not.

If the observed frequency is close to the expected frequency, then the square of the deviations will be small. The square of the deviation is divided by the expected frequency to get the weighted frequencies.

If the sum of these weighted squared deviations is large is then it creates a doubt for the distribution claimed other wise not. Therefore, the chi-square goodness-of-fit test is always a right tail test.

Hence correct option is "a. ​is always an upper tail test. "

A perfect square means that the given value is the result of the multiplication of an integer with itself, for example 2*2=4 →√

This system of equations have infinite solution.

If solving an equation yields a statement that is true for a single value for the variable, like x = 3, then the equation has one solution. If solving an equation yields a statement that is always true, like 3 = 3, then the equation has infinitely many solutions.

Given that,

The system is 2x + y = 1 and 4x + 2y = 2. It is graphed below.

Solutions to a system are the intersection points. Since these two lines are the same line they intersect everywhere. There are infinitely many solutions.

2x+y = 1   ...........(1)

4x+2y = 2  .......(2)

Then from equation (2) dividing by 2 on both side

2x+y = 1

since both lines are same. They overlap to each other.it means the equation have many solution.

Hence,This system of equations have infinite solution.

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The above question is not complete.

How many solutions does this system of equations have?

(a) none

(b) exactly two

(c) infinitely many

(d) exactly one

Graph of a system of linear equations. Equation 1 is 2x plus y equals 1.. Equation 2 is 4x plus 2y equals 2. The graphs are the same line.

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.

The value for the hotspots of the similar triangles ∆ABC and ∆PWR are:

(1). angle B = 68°

(2). PQ = 5cm

(3). BC = 19.5cm

(4). area of ∆PQR = 30cm²

Similar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.

(1). angle B = 180 - (22 + 90) {sum of interior angles of a triangle}

angle B = 68°

Given that the triangle ∆ABC is similar to the triangle ∆PQR.

(2). PQ/7.5cm = 12cm/18cm

PQ = (12cm × 7.5cm)/18cm {cross multiplication}

PQ = 5cm

(3). 13cm/BC = 12cm/18cm

BC = (13cm × 18cm)/12cm {cross multiplication}

BC = 19.5cm

(4). area of ∆PQR = 1/2 × 12cm × 5cm

area of ∆PQR = 6cm × 5cm

area of ∆PQR = 30cm²

Therefore, the value for the hotspots of the similar triangles ∆ABC and ∆PWR are:

(1). angle B = 68°

(2). PQ = 5cm

(3). BC = 19.5cm

(4). area of ∆PQR = 30cm²

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Answer:

so line them up up try to find 5he answer

The area or the common pasture will be 12 acres.

Based on the information given, the formula to use will be:

ab/ac = 2/4

b/c = 1/2 .... i

Also, ab/bd = 2/6

a/d = 1/3 .... ii

Multiply both equation

1/2 × 1/3 = 1/6

Therefore, the area will be

= 6 × 2

= 12 acres

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Elyse's garden is not a square because the length of the diagonal is not identical to the length of the sides.

The geometric form known as a square has four equal-length sides and four right angles (90-degree angles). Each corner of a square connects to the other corner perpendicularly, and the diagonals (lines dividing the corners) are equally long. You can calculate a square's area by multiplying one of its edges by itself. The method for calculating a square's area is:

given

The square of the hypotenuse, or longest side, in a right triangle, is equivalent to the sum of the squares of the other two sides. Since the square's edges are all equal in this instance, the Pythagorean theorem is expressed as:

\(a^2 + a^2 = d^2\)

We can construct the equation if Elyse determined the diagonal to be 4 times the square root of 2 feet.

a sqrt = 4sqrt(2) (2)

When we simplify this solution, we obtain:

where an is the square's longest edge and d is the diagonal's length.

When we simplify this solution, we obtain:

\(2a^2 = d^2\)

a = 4 feet

Since the length of each diagonal can be determined using the Pythagorean theorem and Elyse's garden has sides measuring 4 feet, we can determine if her garden is square by computing the diagonal using the formula we created earlier:

5.656854249 feet is = to d = a sqrt(2)/4sqrt(2).

Elyse's garden is not a square because the length of the diagonal is not identical to the length of the sides.

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Answer:

2.5

Step-by-step explanation:

8 times 4 is 32, and 80/32 is 2.5. When you have to find another measurement and you know 2 of them, you just have to divide the total of the 2 measurements with the volume. it would be 2.5 feet as the height.

Answer: 1324.12 sq. cm.

Step-by-step explanation:

A=2πrh+2πr2

A = 2π x 8.2 x 17.5 + 2π x 8.2^2

A = 2π x 143.50 + 2π x 67.24

A= 1324.12

Answer:

SA = 1324.1 cm²

Step-by-step explanation:

Surface Area of Cylinder = \(2\pi rh+2\pi r^2\)

Where r = 8.2 cm, h = 17.5 cm

=> SA = \(2(3.14)(8.2)(17.5)+2(3.14)(8.2)^2\)

=> SA = \(901.6+2(3.14)(67.24)\)

=> SA = 901.6 + 422.5

=> SA = 1324.1 cm²

The probability mass function (PMF) for x is {0.0004, 0.0588, 0.3432, 0.941192}, and the cumulative mass function (CMF) for x is {0.0004, 0.0592, 0.4024, 1.0}.

The probability mass function (PMF) and cumulative mass function (CMF) for the random variable x, which denotes the number of parts correctly classified in an optical inspection system, can be determined.

Since the classifications of the parts are independent, we can use the binomial probability distribution to model this scenario. The PMF gives the probability of obtaining a specific value of x, and the CMF gives the probability of obtaining a value less than or equal to x.

The PMF of x is given by the binomial probability formula:

P(x) = (n C x) * p^x * (1 - p)^(n - x)

where n is the number of trials (number of parts inspected), x is the number of successes (number of parts correctly classified), and p is the probability of success (probability of correct classification of any part).

In this case, n = 3 (three parts inspected) and p = 0.98 (probability of correct classification).

Let's calculate the PMF for x:

P(x = 0) = (3 C 0) * (0.98^0) * (1 - 0.98)^(3 - 0) = 0.0004

P(x = 1) = (3 C 1) * (0.98^1) * (1 - 0.98)^(3 - 1) = 0.0588

P(x = 2) = (3 C 2) * (0.98^2) * (1 - 0.98)^(3 - 2) = 0.3432

P(x = 3) = (3 C 3) * (0.98^3) * (1 - 0.98)^(3 - 3) = 0.941192

The PMF for x is:

P(x = 0) = 0.0004

P(x = 1) = 0.0588

P(x = 2) = 0.3432

P(x = 3) = 0.941192

To calculate the CMF, we sum up the probabilities up to x:

F(x) = P(X ≤ x) = P(x = 0) + P(x = 1) + ... + P(x = x)

Using the calculated probabilities, the CMF for x is:

F(x = 0) = 0.0004

F(x = 1) = 0.0592

F(x = 2) = 0.4024

F(x = 3) = 1.0

Therefore, the probability mass function (PMF) for x is {0.0004, 0.0588, 0.3432, 0.941192}, and the cumulative mass function (CMF) for x is {0.0004, 0.0592, 0.4024, 1.0}.

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Step-by-step explanation:

5 (18 - y) when y=6

5 (18 - 6)

5 × 18 - 5× 6

90 - 30

60

Answer:

-44

Step-by-step explanation:

7×-5y

7(-2)-5(6)

-14-30

-44

Answer:

19654,67397,67923,91945

Step-by-step explanation:

Ascending order mean arrange the number from smaller value to bigger value

Answer:

19654,67397,67923,91945

plz mark me as brainliest

The simplified form of the expression 2x^2 - 3x - 2 remains as 2x^2 - 3x - 2.

To simplify the expression 8x - 2x - x^2, we can combine like terms by adding or subtracting coefficients.

8x - 2x - x^2

First, let's combine the x terms:

(8x - 2x) - x^2

This simplifies to:

6x - x^2

Therefore, the simplified form of the expression 8x - 2x - x^2 is 6x - x^2.

Now, let's simplify the expression 2x^2 - 3x - 2:

The expression is already in simplified form, and no further simplification is possible.

Therefore, the simplified form of the expression 2x^2 - 3x - 2 remains as 2x^2 - 3x - 2.

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Answer:

A function is a relation for which each value from the set the first components of the ordered pairs is associated with exactly one value from the set of second components of the ordered pair.

Step-by-step explanation:

there you go.

Answer:

For each element in the domain, there is exactly one corresponding element in the range.

Step-by-step explanation:

Just took test

Answer: (k - 1) (9k^2 + 1)

Answer:

3.00

Step-by-step explanation:

Answer:

3.00

Step-by-step explanation:

Since three is a whole number, that means it would be in front of the decimal.

The binary structures U₅ and U₆, consisting of the fifth and sixth roots of unity respectively, are not isomorphic due to the difference in their element compositions.

To determine if the binary structures U₅ and U₆, consisting of the fifth and sixth roots of unity respectively, are isomorphic, we need to compare their algebraic properties.

The group U₅ consists of the fifth roots of unity, which can be represented as {1, ω, ω², ω³, ω⁴}, where ω is a complex number satisfying the equation ω⁵ = 1.

The group U₆ consists of the sixth roots of unity, which can be represented as {1, ξ, ξ², ξ³, ξ⁴, ξ⁵}, where ξ is a complex number satisfying the equation ξ⁶ = 1.

To determine if U₅ and U₆ are isomorphic, we need to check if there exists a bijective function (an isomorphism) between the two groups that preserves their binary operation. In other words, we need to see if there is a mapping between the elements of U₅ and U₆ that preserves the multiplication of the roots of unity.

By comparing the elements of U₅ and U₆, we notice that U₅ does not contain all the elements present in U₆. Specifically, U₅ does not include the element ξ⁵, which is a part of U₆. Since there is no one-to-one correspondence between the elements of U₅ and U₆, we can conclude that U₅ and U₆ are not isomorphic.

In summary, since their elemental compositions differ, the binary structures U₅ and U₆, which represent the fifth and sixth roots of unity, respectively, are not isomorphic.

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