The candle that burned faster is: the cinnamon-scented jar candle
To solve this problem we have to consider which candle has the least duration time of burn so we can decide which one burned faster.
Information about the problem:
t(cinnamon-scented jar candle) = 30 hourst(berry-scented pillar candle) = 88 hoursComparing times we have:
t(cinnamon-scented jar candle) < t(berry-scented pillar candle)
30 hours<88 hours
We can affirm that the cinnamon-scented jar candle is the one that burned faster also we can say that its speed of burn is higher than the berry-scented pillar candle
What is speed?It is a physical magnitude that indicates the distance of a mobile per unit of time
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Calculate the impulse when an average force of 10N is exerted on a cart for 2.5s
The impulse (J) is defined as the product of the force (F) and the time (Δt) for which it is applied:
J = FΔt
Substituting the given values, we get:
J = 10 N × 2.5 s = 25 N·s
Therefore, the impulse when an average force of 10 N is exerted on a cart for 2.5 s is 25 N·s.
An astronaut and his space suit have a combined mass of 157 kg. The
astronaut is using a 5 kg tqol kit to repair a solar panel on the International
Space Station. When the têther connecting the astronaut to the space
station becomes unattached, the astronaut, still holding the tool kit, starts
to float away at 0.2 m/s. Calculate the velocity with which the astronaut
must throw the tool kit in order to float back toward the space station at
0.1 m/s. Show your calculations and include units in your answer.
*
Answer:
v₃ = 9.62[m/s]
Explanation:
To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.
We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.
Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.
In this way, we can construct the following equation.
\(-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})\)
where:
m₁ = mass of the astronaut = 157 [kg]
m₂ = mass of the toolkit = 5 [kg]
v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]
v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]
v₃ = velocity at which the toolkit should be thrown [m/s]
Now replacing:
\(-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]\)
The velocity with which the astronaut must throw the tool kit is 9.62 m/s.
The given parameters:
Mass of the astronaut and space suit, m₁ = 157 kgMass of the tool kit, m₂ = 5 kgVelocity of the astronaut and tool kit, v = 0.2 m/sVelocity of the astronaut and space station, u₁ = -0.1 m/sApply the principle of conservation of linear momentum to determine the velocity of the tool kit;
\(m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\-0.1(157) \ + 5u_2 = 0.2(157 + 5) \\\\-15.7 + 5u_2 = 32.4\\\\5u_2 = 32.4 + 15.7\\\\5u_2 = 48.1\\\\u_2 = \frac{48.1}{5} \\\\u_2 = 9.62 \ m/s\)
Thus, the velocity with which the astronaut must throw the tool kit is 9.62 m/s.
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Explain the difference between transverse and longitudinal waves.
A transverse wave is a wave in which particles of the medium move in a direction perpendicular to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil up and down. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced upwards and downwards. In this case, the particles of the medium move perpendicular to the direction that the pulse moves. This type of wave is a transverse wave. Transverse waves are always characterized by particle motion being perpendicular to wave motion.
A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves. Suppose that a slinky is stretched out in a horizontal direction across the classroom and that a pulse is introduced into the slinky on the left end by vibrating the first coil left and right. Energy will begin to be transported through the slinky from left to right. As the energy is transported from left to right, the individual coils of the medium will be displaced leftwards and rightwards. In this case, the particles of the medium move parallel to the direction that the pulse moves. This type of wave is a longitudinal wave. Longitudinal waves are always characterized by particle motion being parallel to wave motion.
John has a utility function of the following: UL, C) = L ^BC ^(1-ẞ), where L is leisure and C is consumption. If he works, he receives a real wage w. Outside of the labor market, he has nonlabor market income V. And his endowment of time T is normalized to 1. And the price of goods p is also normalized to 1.
(a) Please write down his budget constraint.
(b) Assuming ẞ = 1/2, V = 100, w = 200, what is his optimal supply of labor?
(c) How much total income does he have?
(d) How much consumption will he make?
(e) Now, consider the case where John is subject to a 10% income tax on labor income only. What is his new optimal supply of labor?
(a) The budget constraint can be written as: C = wL + V, where C is consumption, w is the real wage, L is leisure, and V is non-labor market income.
(b) With ẞ = 1/2, V = 100, and w = 200, John's optimal supply of labor cannot be determined without information about his preferences for leisure and consumption. The utility function only represents his preferences, but we need additional information to determine the specific amount of labor he would choose to supply.
(c) John's total income is the sum of his labor income and non-labor market income: Total income = Labor income + Non-labor income = wL + V. Without knowing the specific value of L, we cannot calculate the total income.
(d) Similarly, without knowing John's preferences for leisure and consumption, we cannot determine the specific level of consumption he would choose.
(e) In the case where John is subject to a 10% income tax on labor income only, his new optimal supply of labor would depend on the tax rate's impact on his preferences and the trade-off between leisure and consumption. Without further information on his preferences and the specific tax structure, we cannot determine the new optimal supply of labor.
Additional information about John's preferences for leisure and consumption, as well as the specific tax structure, is necessary to calculate his optimal labor supply, total income, consumption, and the impact of the income tax on his labor supply.
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an example of acceleration
Answer:
Explanation:
Newton’s Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass.
The vertical and horizontal ditance of the projectile will be equal if the angel of the progectile i
The vertical and horizontal distance of a projectile will be equal if the angle of projection is 45 degrees.
What angle the range of projectile equal?Any two angles with a 2:1 ratio when launched at the same speed will have the same range.This is due to the fact that the projectile will be equally influenced by the horizontal and vertical components of its velocity at a 45 degree angle. Consequently, the missile will cover the same amount of ground horizontally as it does vertically.The projectile will be more affected by either the horizontal or vertical component of its velocity for different projection angles, depending on the angle. The projectile will be predominantly impacted by the vertical component of its motion at an angle of 90 degrees (straight up), while the horizontal component of its motion will be most influential at an angle of 0 degrees (horizontal).To learn more about angle the range of projectile equal refers to:
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PLEASE ANSWER THE QUESTION AS SOON AS POSSIBLE
Answer: the answer is (1) B only
Explanation: In A the ball is being acted upon by the ground. In B in order for the ball to move upwards the ball had to have force acted upon at R. In C from U to V the ball has been acted upon by the ground
a 4.40 μf capacitor that is initially uncharged is connected in series with a 5.80 kω resistor and an emf source with e= 150 v negligible internal resistance.
the 4.40 μF capacitor in series with the 5.80 kΩ resistor and 150 V emf source will charge up to 63.2% of its maximum voltage after one time constant, and will approach 150 V after several time constants.
When the emf source is connected to the circuit, current will start to flow and charge will begin to accumulate on the capacitor. The rate of charging will be determined by the time constant of the circuit, which is equal to the product of the resistance and capacitance (RC). In this case, the time constant is:
RC = 5.80 kΩ * 4.40 μF = 25.52 ms
After one time constant (25.52 ms), the capacitor will have charged to approximately 63.2% of its maximum voltage. After two time constants, it will have charged to approximately 86.5% of its maximum voltage, and after three time constants it will have charged to approximately 95% of its maximum voltage.
The maximum voltage that the capacitor will reach is equal to the emf of the source (150 V) because there is negligible internal resistance in the source. Therefore, the capacitor will eventually charge to 150 V, but it will take multiple time constants to get close to this value.
the 4.40 μF capacitor in series with the 5.80 kΩ resistor and 150 V emf source will charge up to 63.2% of its maximum voltage after one time constant, and will approach 150 V after several time constants.
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a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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What is the electric potential of a 4.5x10^-5 C charge that has an electric potential energy of 0.027 J?
Answer:
600 volts
Explanation: just do 4.5x10^-5c lol i hope this helps if it dont im so sorry
Ball X has a mass of 8kg and is moving toward ball Y (which is sitting still) at 2m/s. After they collide, ball X is
sitting still. How fast is ball Y moving after the collision if it has a mass of 4kg?
Answer:
v = 4 m/s
Explanation:
Given :
Ball X :
Mass, m1 = 8kg ;
Initial Velocity, u1 = 2 m/s
Final velocity, v1 = 0
Ball Y:
Mass, m2 = 4kg ;
Initial Velocity, u2 = 0 m/s
Final velocity, v2 = v
(m1u1 + m2u2) = (m2v2 + m1v1)
(8*2 + 4*0) = (4*v + 4*0)
16 + 0 = 4v + 0
16 = 4v
v = 16 / 4
v = 4 m/s
Answer:
Explanation:
This is the Law of Momentum Conservation which for us looks like this:
\([m_xv_x+m_yv_y]_b=[m_xv_x+m_yv_y]_a\) and that should look familiar to you if this is what you are doing in physics. Filling in our particular info:
[(8.0 × 2.0)+ (4.0 × 0.0)] = [(8.0 × 0.0) + (4.0v)] and
16 + 0 = 0 + 4.0v and
16 = 4.0v so
v = 4.0 in the direction of ball X
A large rock has a mass of 7.84 x 107 grams. What is this mass inItons. 1 ton = 907.2 kilograms.
The mass of the rock is approximately 86.304 tons.
To convert the mass of the rock from grams to tons, we can use the conversion factor that 1 ton is equal to 907.2 kilograms.
Mass of the rock = 7.84 x 10^7 grams
To convert grams to kilograms, we divide by 1000:
Mass in kilograms = (7.84 x 10^7 grams) / 1000 = 7.84 x 10^4 kilograms
Now, to convert kilograms to tons, we divide by 907.2:
Mass in tons = (7.84 x 10^4 kilograms) / 907.2 = 86.304 tons
Therefore, the mass of the rock is approximately 86.304 tons.
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A 20 kg boy climbs 10 m up a tree. When he stops to have a look
around, what is the boys potential energy?
A1960 J
B3920 J
C 4120 J
D4210 J
Answer:
Explanation:
c
Why is terminal voltage of the cell more than its emf?
The terminal voltage of a cell is less than its emf because of the internal resistance of the cell.
The voltage of the cell is commonly called the emf, or electromotive force. The energy of the cell, which is supplied by the chemical reactions that take place inside it, is represented by this voltage. The terminal voltage of a cell is the voltage that is present at the ends of the cell's terminals when the cell is connected to a circuit. When a cell is connected to a circuit, the current that flows through it experiences some resistance. This resistance causes the voltage that is present at the terminals of the cell to decrease. As a result, the terminal voltage of the cell is lower than its emf. The resistance is due to the internal resistance of the cell, which is the resistance of the cell's components to the flow of current. The internal resistance of the cell is caused by the cell's components, such as the electrodes and electrolytes. This resistance is always present, regardless of whether the cell is connected to a circuit or not. When the cell is connected to a circuit, the internal resistance is in series with the external resistance of the circuit. This causes the voltage that is present at the terminals of the cell to decrease.
When a cell is connected to a circuit, it is possible for the voltage that is present at the terminals of the cell to be less than the emf of the cell. This happens because of the internal resistance of the cell, which is always present. The internal resistance is caused by the components of the cell, such as the electrodes and electrolyte. This resistance is always present, regardless of whether the cell is connected to a circuit or not.When the cell is connected to a circuit, the internal resistance is in series with the external resistance of the circuit. This causes the voltage that is present at the terminals of the cell to decrease. The voltage drop that is caused by the internal resistance is directly proportional to the current that flows through the cell. As the current that flows through the cell increases, the voltage drop that is caused by the internal resistance also increases.
In conclusion, the terminal voltage of a cell is less than its emf because of the internal resistance of the cell. This resistance is caused by the components of the cell, such as the electrodes and electrolyte. When the cell is connected to a circuit, the internal resistance is in series with the external resistance of the circuit. This causes the voltage that is present at the terminals of the cell to decrease. The voltage drop that is caused by the internal resistance is directly proportional to the current that flows through the cell.
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if a wave of length of 32 and frequency of 5. What is the speed of the wavelength?
a.23 m/s
b.98 m/s
c.160 m/s
d.54 m/s
Answer:
The speed of a wave can be calculated using the formula:
v = λ * f
where v is the wave speed, λ is the wavelength, and f is the frequency.
Plugging in the values given, we get:
v = 32 * 5 = 160 m/s
Therefore, the speed of the wavelength is 160 m/s, which corresponds to option (c).
Explanation:
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A box experiences a 20 N force to the left and two different 8 N forces to the right, is that will accelerate to the right, to the left, or will not accelerate at all
Answer:
that the acceleration is negative therefore it is directed to the left.
Explanation:
To find the acceleration of a system we must use Newton's second law
∑ F = m a
To apply this equation to our case we set a reference system where the direction to the right is positive.
We have 3 forces, a force F₁ = -20 N, a negative sign indicates that it is directed to the left, two forces F₂ and F₃ of magnitude 8N each directed to the right.
We substitute
-F₁ + F₂ + F₃ = m a
- 20 +8 + 8 = m a
-4 = m a
a = -4 / m
Here we can see that the acceleration is negative therefore it is directed to the left.
Question 1 (1 point)
A boy on a treasure hunt walks 12 paces West, then 21 paces North, then 25 paces
East. What is the magnitude of boy's resultant displacement in meters?
Answer:
The magnitude of the boy's displacement is 24.698 paces which is in the direction of approximately 58.24° North of East
Explanation:
The given parameters are;
The distance West the boy on a treasure hunt walks = 12 paces
The distance North the boy on a treasure hunt then walks = 21 paces
The distance East the boy on a treasure hunt then walks = 25 paces
Writing the displacement in vector format, gives;
d = -12·i + 21·j + 25·i
Which gives
d = 13·i + 21·j
The magnitude of the boy's resultant displacement is given as follows;
\(\left | \mathbf{d} \right | = \sqrt{d_x^2 + d_y^2}\)
Where;
\(d_x = 13, \ d_y = 21\)
\(\left | \mathbf{d} \right | = \sqrt{13^2 + 21^2} = \sqrt{610} \approx 24.698 \ paces\)
The magnitude of the boy's displacement is 24.698 paces
The direction of the displacement is tan⁻¹(21/13) ≈ 58.24° North of East.
Calculate the total charge Q of a thin plate with the charge density distribution p(x,y) = x²y mC/m². The plate shape is restricted by the lines: y=2-x² and y=2x-1, where x and y are measured in metres. a) Sketch the plate shape. [10 marks] [4 marks] b) Present the total charge through the double integral. c) Reduce the double integral to the repeated integrals and show limits of integration. [6 marks] d) Calculate the integral and present your answer with five significant figures. [20 marks]
a) Sketch the plate shape: we get a shape that resembles a trapezoid.
The plate shape is determined by the lines y = 2 - x² and y = 2x - 1. To sketch the plate shape, we can plot these two lines and shade the region in between them. The intersection points of the lines are found by solving the equations simultaneously:
2 - x² = 2x - 1
Simplifying, we get:
x² + 2x - 3 = 0
Factoring, we have:
(x - 1)(x + 3) = 0
So, x = 1 and x = -3. Plugging these values into the equations of the lines, we find the corresponding y-values:
For x = 1:
y = 2 - (1)² = 1
For x = -3:
y = 2(-3) - 1 = -7
Plotting these points and connecting them with the lines, we get a shape that resembles a trapezoid.
b) Total charge through the double integral:
To find the total charge Q, we need to integrate the charge density p(x, y) over the entire plate. We can express this as a double integral:
Q = ∬ p(x, y) dA
c) Reducing the double integral to repeated integrals: The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.
Since the plate shape is described by the lines y = 2 - x² and y = 2x - 1, we can rewrite the double integral as a repeated integral by integrating with respect to x and y separately:
Q = ∫∫ p(x, y) dy dx
The limits of integration for y are from the lower curve y = 2 - x² to the upper curve y = 2x - 1. The limits of integration for x are the values of x that define the boundaries of the plate shape, which are -3 to 1.
d) Calculating the integral: The total charge Q of the thin plate is approximately 12.4 mC.
Now, we can evaluate the double integral to find the total charge Q:
Q = ∫(-3 to 1) ∫(2 - x² to 2x - 1) x²y dy dx
Performing the inner integral with respect to y first, we get:
Q = ∫(-3 to 1) [x²(y²/2 - y)] from 2 - x² to 2x - 1 dx
Simplifying the inner integral, we have:
Q = ∫(-3 to 1) [(x²/2)(2 - x²) - x²(2x - 1)] dx
Expanding and simplifying further, we get:
Q = ∫(-3 to 1) (x² - x⁴/2 - 4x³ + 2x²) dx
Integrating term by term, we have:
Q = [x³/3 - x⁵/10 - x⁴ + 2x³/3] from -3 to 1
Evaluating the integral at the limits, we get:
Q ≈ 12.4 mC (rounded to five significant figures)
Therefore, the total charge Q of the thin plate is approximately 12.4 mC.
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When I increase the wavelength of the wave, what changes about the light wave: Greater/Smaller distance between peaks/crests of wave.
The frequency and energy (E) of a wavelength drop as it grows in size. You may conclude from these equations that the wavelength shortens with increasing frequency.
What changes when the wavelength of a light wave grows?The frequency and energy (E) of a wavelength drop as it grows in size. You may conclude from these equations that the wavelength shortens with increasing frequency. The wavelength lengthens with decreasing frequency.The wavelength shortens with increasing frequency. As the frequency rises, the wavelength falls, forming what is known as an inverse relationship between the two quantities.Therefore, a shorter wavelength of a light wave will result in a higher frequency since one cycle may be completed in less time. Accordingly, more cycles can pass through the set point in a second.To learn more about Wavelength refer to:
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During which interval is the cart accelerating?
the barriers if the interval are Aand B the of displacement goes up.
from B to C it just stays the same, then from C to D no Movement, and from time D to E movement, but steady
Rank the five modes of transportation from 1 - 5 based on CO2 Emissions. (1=best performance; 5 worst performance) = Air [ Choose] Ocean [ Choose ] Pipeline [ Choose] < Rail [ Choose] < Truck [ Choose ]
This ranking is based solely on CO2 emissions and does not take into account other factors such as energy efficiency, cost, or suitability for specific types of goods.
Ranking the five modes of transportation based on CO2 emissions from best performance (lowest emissions) to worst performance (highest emissions), the ranking would be as follows:
1. **Pipeline**: Pipelines generally have the lowest CO2 emissions among the listed modes of transportation. They transport large quantities of goods through dedicated infrastructure, minimizing energy consumption and emissions per unit of transported goods.
2. **Rail**: Rail transportation is known for its relatively lower CO2 emissions compared to other modes. Trains can move large volumes of cargo using electric power or more efficient diesel engines, resulting in reduced emissions per ton-mile.
3. **Ocean**: While ocean shipping can be energy-efficient for transporting large volumes of goods, it ranks slightly higher in CO2 emissions due to the use of heavy fuel oils by cargo ships. However, when measured on a per-ton basis, ocean shipping is generally more carbon-efficient than other modes.
4. **Truck**: Trucks have higher CO2 emissions compared to the previous modes mentioned. They are more fuel-intensive and emit more greenhouse gases per unit of cargo transported. However, advancements in vehicle technology and the use of alternative fuels can help reduce emissions in the future.
5. **Air**: Air transportation is the mode with the highest CO2 emissions among the listed options. Aircraft engines consume significant amounts of fuel, resulting in substantial emissions. However, air transport is often favored for its speed and long-distance capabilities, despite its environmental impact.
Remember, this ranking is based solely on CO2 emissions and does not take into account other factors such as energy efficiency, cost, or suitability for specific types of goods.
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A + 9.4 nC point charge and a - 2.31 nC point charge are 4.94 cm apart. What is the electric field strength at the midpoint between the two charges?
Given:
The charge is q1 = 9.4 nC
The charge q2 = -2.31 nC
The distance between them is r = 4.94 cm
To find the electric field strength at the midpoint between two charges.
Explanation:
The electric field strength at the midpoint will be the sum of electric field strength due to q1 and q2.
The electric field strength can be calculated by the formula
\(E=\frac{kq}{r^2}\)Here, k is the electrostatic constant whose value is
\(k=9\times10^9\text{ N m}^2\text{ /C}^2\)The electric field strength due to the charge q1 is
\(\begin{gathered} E_1=\frac{kq1}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times9.4\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =1.39\times10^5\text{ V/m} \end{gathered}\)The electric field strength due to the charge q2 is
\(\begin{gathered} E_2=\frac{kq2}{(\frac{r}{2})^2} \\ =\frac{9\times10^9\times2.31\times10^{-9}}{(\frac{4.94}{2}\times10^{-2})^2} \\ =3.4\times10^4\text{ V/m} \end{gathered}\)The electric field strength at the midpoint will be
\(\begin{gathered} E=E_1+E_2 \\ =(1.39\times10^5)+(3.4\times10^4) \\ =173000\text{ V/m} \end{gathered}\)Thus, the electric field strength at the midpoint between the two charges is 173000 V/m
Greg is giving a slide show presentation to a large audience. How might a laser best help him with the presentation?
A)He can use the laser to enlarge images on slides.
B)He can use the laser to point to specific information on the slides.
C)He can use the laser to scan and record information about the slides.
D)He can use the laser to make the images more clear.
Answer:
he can use the laser to point to specific information on the slides.
he can use the laser to point to specific information on the slides.Explanation:
He can use the laser to point to specific information on the slides might a laser best help him with the presentation. Hence, option B is correct.
What is meant by specific information?When something is referenced in the text, "specific information" refers to an explicit, precise fact or description of that item. Generally speaking, general information is nebulous and serves as a wide description of something.
A particular instance is a particular example. In order to present a specific example of technology, one could write about specific individuals using a specific machine. You would need to write about specific individuals in order to provide a concrete example of any human activity.
There are various specific issues that need to be resolved. To address particular challenges, specific groups may be formed. I prompted him to provide further details. She is from the United States, namely Boston.
Thus, option B is correct.
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what is potential difference
Answer:
VOLTAGE
Explanation:
Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit. ... A potential difference of one Volt is equal to one Joule of energy being used by one Coulomb of charge when it flows between two points in a circuit
A tire on a Scooter has a radius of 0.14 m, if the Velocity is 15 m/s . What is the Angular Velocity of the tire?
The angular velocity of the tire is 107.14 rad/s.
ω = v/r
where ω is the angular velocity, v is the linear velocity, and r is the radius of the tire.
Substituting the given values, we get:
ω = 15 m/s / 0.14 m
ω = 107.14 rad/s
Angular velocity is a concept in physics that describes the rate of change of an object's angular position with respect to time. In other words, it measures how quickly an object is rotating or turning around an axis. The unit of angular velocity is usually radians per second (rad/s) or degrees per second (deg/s).
Angular velocity can be calculated by dividing the change in angular displacement by the change in time. It is a vector quantity that has both magnitude and direction, with the direction being perpendicular to the plane of rotation. Angular velocity plays a crucial role in many areas of physics, such as mechanics, electromagnetism, and quantum mechanics. It is used to describe the motion of objects ranging from planets orbiting around a star to electrons moving around an atom's nucleus.
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How do interaction forces act on different masses and on different objects?
Dosen't make sense
Explanation:
TRUE - Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations. ... FALSE - In any collision, the colliding objects exert equal and opposite forces upon each other as the result of the collision interaction.
Suppose a is a 2x4 matrix, and the columns of a span a line. how many pivots must matrix a have?
The matrix a must have at most 1 pivot, since the columns span a line and not the entire 2D space.
Since the columns of matrix a span a line, this means that the columns are linearly dependent. In a 2x4 matrix, there can be at most 2 linearly independent columns. In order for a matrix to have a pivot, the column associated with that pivot must be linearly independent. Therefore, since there can be at most 2 linearly independent columns in a 2x4 matrix, the matrix a can have at most 1 pivot.
Having more than 1 pivot would imply that there are more than 2 linearly independent columns, which contradicts the fact that the columns span a line.
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To open and close a circuit, a
can be used.
From a penalty kick, the ball rebounds off the goalkeeper back to the player who took the kick. That player then kicks the ball into the goal. What is the correct restart
The correct restart is for there to be another kick off taken in this type of scenario.
What is Kick-off in Soccer?This is a method of restarting play in which the ball is put on the center circle and passed by a player.
Kick offs occur at the beginning of any halves or when a goal is scored during the match which is why it's the most appropriate choice.
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Answer:Kick offs occur at the beginning of any halves or when a goal is scored during the match which is why it's the most appropriate choice.
Explanation:
What formula is used for the questions two forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other determine the magnitude of the acceleration of the body
The magnitude of the acceleration of the body is approximately 1.802 m/s^2 when forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other.
To determine the magnitude of the acceleration of a body when two forces act on it at a right angle, we can use the Pythagorean theorem and Newton's second law of motion.Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the vector sum of the two forces acting on the body.Using the Pythagorean theorem, we can find the magnitude of the net force. Let's call the force with magnitude 5 Newton as F1 and the force with magnitude 4 Newton as F2. The net force (Fnet) can be calculated as the square root of the sum of the squares of the individual forces: Fnet = sqrt(F1^2 + F2^2).Now we can substitute the net force into Newton's second law to find the acceleration (a). Rearranging the formula, we have a = Fnet / m.Plugging in the values, Fnet = sqrt(5^2 + 4^2) = sqrt(25 + 16) = sqrt(41) Newtons. The mass (m) is given as 4.0 kg.
Finally, the magnitude of the acceleration of the body is calculated as a = Fnet / m = sqrt(41) / 4.0 ≈ 1.802 m/s^2.
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