analyze. what was the importance of a control in your experiment? what would you conclude if the color of the solution in the control changed?

Answer

C) no energy is lost; the total amount of energy remains the same.

Explanation

The law of conservation of energy states that "The energy can neither be created nor destroyed - only converted from one form of energy to another." Therefore some energy will be used for metabolism while the other can be used for other properties and some can be stored.

24074 (Rh) atoms would have to be placed side by side to span a distance of 6.0.

The smallest piece of matter that exists in the universe is an atom. Atoms that are neutral or ionized make up every material in our environment. The atoms are tiny, spherical objects, and the Armstrong unit is used to measure their diameter.

1A = (10^-10)

The diameter of a rhodium atom (Rh) is approximately d = 2.7 x 10^-10

so,

It is assumed that if we keep n atoms next to one another, we will create a distance of L = 6.5μm  = 6.5 x 10^-6

In this case,

We can see that if we keep the atoms side by side, the total length of them will be determined by adding the total diameters.

we have:

L = n d

n = L/d

Putting values :

n = (6.5 x 10^-6)/( 2.7 x 10^-10)

n = 24074

24074 (Rh) atoms would have to be placed side by side to span a distance of 6.0

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Answer:

Ways we use radio waves on Earth are television and FM and AM radio broadcasts, military communications, mobile phones, ham radio, wireless computer networks, and numerous other communications applications.

Explanation:

Ways we use radio waves on Earth are television and FM and AM radio broadcasts, military communications, mobile phones, ham radio, wireless computer networks, and numerous other communications applications.

An electromagnetic wave of a frequency between about \(10^4\) and \(10^{11}\)or \(10^{12}\) Hz, as used for long-distance communication.

AM and FM Radio Broadcasting which involves transmitting sound to a wide audience.

Radar is a detection system that uses radio waves to get information about objects.

Bluetooth and wireless communication use radio waves to create connections between devices.

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Explanation

NH4Cl(s) = NH4+(aq) + Cl-(aq) AH = +3.5 kcal/mole

We have some changes that shift the equilibrium to the right, according to Le Châtelier's principle.

I will write some of them:

By Adding amount of NH4Cl or by increasing the temperature because according to the heat of the reaction this is an endothermic reaction.

Answer: Increasing the temperature of the system.

Answer:

False

Explanation:

Molecules of the same substance are made up of the same type of atoms and look exactly alike.

Hence, if I have two molecules of methane having exactly the same atoms of carbon and hydrogen,the both are indistinguishable from each other based on appearance.

Hence all molecules of methane are exactly alike if they are composed of atoms of the same isotope of hydrogen and carbon.

The answer is option

The reaction:

is a Synthesis reaction, because from 2 different substances it is produced

It is a physical property

Color odour and taste are a properties that are detected by sense organs.

When a drug is administered as a salt, it is typically combined with an appropriate counterion to form a salt form of the drug. This salt form enhances the solubility of the drug in aqueous solutions, which can improve its bioavailability and allow for better dissolution and absorption in the body.

The correct answer is Many drugs are administered as salts rather than as the corresponding neutral compounds because salts often have greater water solubility and stability. This is important for effective delivery and absorption of the drug in the body. Furthermore, salts often provide improved stability compared to the corresponding neutral compounds. The addition of counterions in the salt form can enhance the chemical and physical stability of the drug molecule, protecting it from degradation or hydrolysis.

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Answer:

(CH3COO)2 + redP + Cl2 → ClCH2COOH + HCl

Explanation:

This is an example of halogenation of carboxylic acids at alpha carbon atom. In this reaction, red phosphorus and chlorine are treated with carboxylic acids having alpha hydrogen atom followed by hydrolysis to form alpha chloro carboxylic acid.

The theoretical yield of the water in the reaction is 329.4 g.

We know that we can be able to obtain the theoretical yield when we look at the stoichiometry of the reaction that we have here. In this case, it is clear that would need to rely on the reaction equation and it would be our guide.

We have that;

2 moles of hydrogen would produce 2 moles of water

18.3 moles of hydrogen would also produce 18.2 moles of water.

Theoretical yield of water would now be;

18.3 * 18 g/mol

= 329.4 g

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A 70.0‑g piece of metal at 80.0 °C is placed in 100 g of water at 22.0 °C contained in a calorimeter. After reaching a temperature of 24.6 °C, the heat given up by the metal to the water is -1.08 kJ.

What is a calorimeter?

A calorimeter is an object used for calorimetry, or the process of measuring the heat of chemical reactions or physical changes as well as heat capacity.

A 70.0‑g piece of metal at 80.0 °C is placed in 100 g of water at 22.0 °C contained in a calorimeter. The final temperature of the system is 24.6 °C.

Let's use the following expression to calculate the heat absorbed by the water.

Qw = c × m × ΔT

Qw = (4.184 J/g.°C) × 100 g × (24.6 °C - 22.0 °C) = 1.08 kJ

where,

Qw is the heat absorbed by the water.

c is the specific heat capacity of water.

m is the mass of water.

ΔT is the change in the temperature for water.

According to the law of conservation of energy, the sum of the heat absorbed by the water and the heat released by the metal (Qm) is zero.

Qw + Qm = 0

Qm = -Qw = -10.8 kJ

A 70.0‑g piece of metal at 80.0 °C is placed in 100 g of water at 22.0 °C contained in a calorimeter. After reaching a temperature of 24.6 °C, the heat given up by the metal to the water is -1.08 kJ.

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ANSWER

EXPLANATION

Ammonia (NH3) is a base that does not contain hydroxyl ion but dissolved in water to produce ammonium ion and hydroxyl ion.

Recall, that pH scale is one of the tool used in determining a strong base and a weak base

The pH of ammonia is 11 and this make ammonia (NH3) to fall under the category of weak base

Therefore, ammonia is a weak base

The empirical formula for the substance, given the data from the question is H₂O

From the question given above, the following data were obtained:

We can determine the empirical formula for the substance as shown below:

Divide by their molar mass

H = 11.190 / 1 = 11.190

O = 88.810 / 16 = 5.551

Divide by the smallest

H = 11.190 / 5.551 = 2

O = 5.551 / 5.551 = 1

Thus, the empirical formula for the substance that is most abundant in the human body is H₂O

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Since there are the same number of molecules in the liquid and vapour phases in this situation, the end pressure would be the same as the initial pressure at equilibrium, before the stopcock was opened.

When a reversible chemical reaction is occurring, chemical equilibrium is the state in which there is no net change in the number of reactants or products. In a reversible chemical reaction, the products start interacting with the initial reactants as soon as they are created.

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Sodium from Na3PO4(aq) could be prepared by electrolysis of the aqueous solution shown. Based on the provided options, the element that could be prepared by electrolysis of the aqueous solution shown

Potassium from KCl(aq)
Here's why:
- Sodium from Na3PO4(aq) and Nitrogen from AgNO3(aq) are not possible because these ions are more stable in solution than undergoing electrolysis.
- Sulfur from K2S04(ed) is not valid as the compound should be K2SO4(aq) and even then, it would produce oxygen at the anode instead of sulfur.
- Oxygen from H2SO4(aq) can be prepared through electrolysis, but this is not an element directly obtained from the compound.
Potassium from KCl(aq) can be prepared by electrolysis. During this process, K+ ions are reduced to potassium metal at the cathode, and Cl- ions are oxidized to chlorine gas at the anode.

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The given statement is "lithium one of the major chemical building blocks of modern life" is false. Lithium is not the budling block of the modern life.

The Lithium is not  one of the major chemical the budling block of the modern life. The building blocks of the modern life is the carbon , oxygen, and the nitrogen. There are the six main elements that are the fundamental unit of the building blocks of the life. The order of the buildings blocks of the modern life from the least common to the most common is as follows :

The sulfur, the phosphorous, the oxygen, the nitrogen, the carbon, and the hydrogen.

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The molarity of NaOH is calculated to be 0.079 mol/L. It is important to include the correct unit of molarity,

The given information states that the mass of KHP is 0.325 g and the volume of NaOH used is 20.15 mL. To find the molarity of NaOH, we can use the formula: Molarity = number of moles of NaOH / Volume of NaOH in liters. The number of moles of NaOH can be determined by the number of moles of KHP used in the neutralization reaction, as per the balanced chemical equation: KHP + NaOH → NaKP + H2O. In this equation, 1 mole of KHP requires 1 mole of NaOH for neutralization.

To calculate the number of moles of KHP, we divide the mass of KHP by its molar mass. The molar mass of KHP (C8H5KO4) is 204.22 g/mol. Therefore, the number of moles of KHP is 0.325 g / 204.22 g/mol = 0.001591 mol.

Since the stoichiometry of the reaction indicates that the number of moles of NaOH is the same as the number of moles of KHP, the number of moles of NaOH is also 0.001591 mol.

The volume of NaOH used is given as 20.15 mL, which needs to be converted to liters by dividing by 1000. So, the volume of NaOH is 20.15 mL / 1000 = 0.02015 L.

Substituting these values into the formula for molarity, we get Molarity = 0.001591 mol / 0.02015 L = 0.079 mol/L.

Therefore, the molarity of NaOH is calculated to be 0.079 mol/L. It is important to include the correct unit of molarity, which is mol/L or M, in the answer.

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The ion responsible for the solution being basic or acidic in NaC2H3O2 is the Acetate ion.

The Acetate ion, CH3COO- is responsible for the solution being acidic or basic in NaC2H3O2.

NaC2H3O2 is also known as Sodium Acetate. It is a common compound in the laboratory that is colorless, deliquescent, and odorless. It dissolves easily in water, and its pH varies depending on the solution's acetate and acetic acid concentration.

Because acetate ion is a weak base, its solution has a higher pH than a solution containing just the acid. The buffer capacity of a solution of the salt NaC2H3O2 (Acetate ion) is dependent on the concentration of the salt and the pH of the solution. A solution with a pH of 7.0 and a 0.1 M NaC2H3O2 concentration would have a buffer capacity of 1.4. A solution with a pH of 5.0 and the same salt concentration would have a buffer capacity of 13.0.The equation for the dissociation of sodium acetate is given below:

NaC2H3O2 ⇌ Na+ + C2H3O2-

We can say that the solution is basic if the pH is greater than 7, acidic if the pH is less than 7, and neutral if the pH is equal to 7.

Hence, the Acetate ion is responsible for the solution being basic or acidic in NaC2H3O2.

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1) The substances present before the reaction has occurred.

2) The substances formed after the reaction has occurred.

3) A negatively charged ion, typically non-metal, that gains electrons to become stable.

4) A positively charged ion, typically metal, that losses electrons to become stable.

5) A chemical reaction in which the reactants absorb heat energy from the surroundings to form products.

6) A chemical reaction in which the reactants release heat energy into the surroundings to form products.

The % composition of a substance can be used to calculate empirical formulas. The molar mass of the chemical must also be known in order to determine its molecular formula.

What is empirical formula explain?

A compound's various atoms are arranged in an empirical formula in the simplest whole-number ratio.

                               The exact amount of various atom types that make up a compound's molecule are displayed in the molecular formula. The empirical formula for acetylene is CH. Example: C2H2 is the empirical formula for acetylene.

An illustration of an empirical formula?

Its chemical name is C6H12O6, and it is a simple sugar. Every mole of carbon and oxygen is accompanied by two moles of hydrogen. Glucose's empirical formula is  CH2O.

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Asexual reproduction results in two organisms with the same parent and the same DNA.

Asexual reproduction produces offspring which are genetically identical to the parent because the offspring are all clones, that is, identical copies of the original parent.

Asexual reproduction in animals occurs through various process such as fission, fragmentation, budding and parthenogenesis. A single individual can produce offspring asexually and large numbers of offspring can be produced quickly with asexual reproduction.

A new potato growing from an old potato can be an example of asexual reproduction. Variation is not possible or significantly reduced in asexual reproduction. Asexual reproduction results in offspring with the same combination of genetic information as the parents.

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The equation 2Al + _F₂ → 2AlF₃ is balanced by making the coefficient of fluorine, F₂ three (3)

To obtain the coefficient of fluorine, F₂ that will balanced the equation, we must obtain the balance equation.

The equation 2Al + _F₂ → 2AlF₃ can be balanced as illustrated below:

2Al + F₂ → 2AlF₃

There are 2 atoms of F on the left side and 6 atoms on the right side. It can be balanced by writing 3 before F₂ as shown below:

2Al + 3F₂ → 2AlF₃

Now, the equation is balanced.

Thus, we can conclude that the coefficient of fluorine, F₂ that balanced the equation is 3

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1. \(\rm \text{{moles of NaOH}} = 1.45 \times 10^{-3} \, \text{{mol}}\)

2. The moles of ascorbic acid reacted is also 1.45 × \(10^{-3\) mol.

3. \(\rm \text{{grams of ascorbic acid}} = 0.255 \, \text{{g}}\)

4. The purity of the ascorbic acid in the powder is approximately 98.8%.

To calculate the purity of the ascorbic acid, we can follow these steps:

1. Calculate the moles of NaOH used in the titration:

The volume of NaOH used is 14.50 mL, and the concentration is 0.100 M.

Using the formula:

\(\[\text{{moles of NaOH}} = \text{{concentration}} \times \text{{volume}}\]\\\\text{{moles of NaOH}} = 0.100 \, \text{{M}} \times 14.50 \times 10^{-3} \, \text{{L}}\]\\\\text{{moles of NaOH}} = 1.45 \times 10^{-3} \, \text{{mol}}\]\)

2. Calculate the moles of ascorbic acid reacted:

From the balanced chemical equation of the neutralization reaction, we know that the ratio of NaOH to ascorbic acid is 1:1. Therefore, the moles of ascorbic acid reacted is also 1.45 × \(10^{-3\) mol.

3. Calculate the grams of ascorbic acid in the sample:

To calculate the mass of ascorbic acid, we need to use the molar mass of ascorbic acid, which is 176.12 g/mol.

\(\[\text{{grams of ascorbic acid}} = \text{{moles of ascorbic acid}} \times \text{{molar mass of ascorbic acid}}\]\\\\text{{grams of ascorbic acid}} = 1.45 \times 10^{-3} \, \text{{mol}} \times 176.12 \, \text{{g/mol}}\]\\\\text{{grams of ascorbic acid}} = 0.255 \, \text{{g}}\]\)

4. Calculate the percent purity of the powder:

The purity is the ratio of the mass of pure ascorbic acid to the total mass of the sample, multiplied by 100%.

\(\[\text{{Percent purity}} = \left(\frac{{\text{{grams of ascorbic acid}}}}{{\text{{mass of the sample}}}}\right) \times 100\%\]\\\\text{{Percent purity}} = \left(\frac{{0.255 \, \text{{g}}}}{{0.258 \, \text{{g}}}}\right) \times 100\%\]\\\\text{{Percent purity}} = 98.8\%\]\)

Therefore, the purity of the ascorbic acid in the powder is approximately 98.8%.

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Your question is incomplete, but most probably your full question was.

A 0.258 g sample of a powder containing some ascorbic acid required 14.50 mL of 0.100 M NaOH for complete neutralization. Calculate the purity of the ascorbic acid.

1. moles of NaOH used in the titration________.

2. moles of ascorbic acid reacted________.

3. grams of ascorbic acid in sample_________.

4. Percent purity of the powder________.

Answer:

Explanation:

When we go down in a column , we are going down in a period . In going down , one additional orbit go on adding to the atom . But the total number of electrons in the outermost orbit which is also called valence electron remains the same .

For example , when we go down in the first   group A , the outermost orbit go on changing like 1 s¹ , 2 s¹ , 3 s¹ . 4 s ¹ etc which represents hydrogen , lithium . sodium , potassium etc.

So we see that , it is number of valance electrons that remains constant.

Answer:

Matter

Explanation:

The Law of Conservation of Mass

Answer:

C. Hydrogen ion donor.

Explanation:

According to bronsted -lowery an acid is a substance that donates a proton (H+) to other substances.

The stroke volume in the next few cardiac cycles will be 100 ml if the end-diastolic volume is increased from 135ml to 165m.

The formula for stroke volume is given as;

SV = EDV - ESV

Here SV represents stroke volume, EDV represents end-diastolic volume and ESV represents end-systolic volume.

First, we calculate this person's end-systolic volume as follows;

If the person’s stroke volume was 70ml and his initial diastolic volume was 135 ml, then:

70 = 135 - ESV

70 - 135 = -ESV

-65 = -ESV

ESV = 65ml

Now the stroke volume in the next few cycles if the end-diastolic volume increase to 165 ml can be calculated as follows;

SV = 165 - 65

SV = 100ml

Therefore, the stroke volume in the next few cardiac cycles is calculated to be 100ml.

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Answer: -162,120J

Explanation:

Okay, so q stands for work, given by the formula q = -P∆V,

For the first round, we have 2atm (for P) and a volume change of 3.2 (6.4-3.2) for the first experiment.

Find the work: q = -2 • (3.2 - 6.4) = 6.4L/atm

For the second experiment, it is now 2.5atm, with the change in volume going from 3.2 to 2.56.

So, work is q = -2.5(2.5 - 3.20) = 1.6L/atm

Add the total work: 1.6 + 6.4 = 8L/atm

To find the Joules per L/atm, recall that a mol of gas in K is 8.31447J, while the gas constant where a liter of gas per mol in K is 0.08206L/atmK. Divide these two values, which leaves us with 101,325J

So, for the first round, multiply 8 x 101,325, which leaves us with 810,600J.

Second round: The pressure is 2.5atm, with the volume change from 6.40 to 2.56

Solve for work: q = -2.5(2.56-6.4) = 9.6L/atm

Multiply with the Joule unit found earlier: 9.6 x 101,325 = 972,720J.

To find the difference, subtract the value of the single-step process (second round) from the first round (multistep)

810600 - 972720 = -162,120J. Therefore, it takes more heat to do the single step than the multistep process.

Answer:

1171.12 mL

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (milliliters)

V2 = final volume (milliliters)

T1 = initial temperature (Kelvin)

T2 = final temperature (Kelvin)

According to the information provided in this question:

P1 = 300 mmHg

P2 = 140 mmHg

V1 = 400 mL

V2 = ?

T1 = 0°C = 273K

T2 = 100°C = 100 + 273 = 373K

Using P1V1/T1 = P2V2/T2

300 × 400/273 = 140 × V2/373

120000/273 = 140V2/373

120000 × 373 = 273 × 140V2

44760000 = 38220V2

V2 = 44760000 ÷ 38220

V2 = 1171.115

The new volume is 1171.12 mL

A) Out of the given options, Pyruvate is the compound that is not a component of the citric acid cycle.

The citric acid cycle, also known as the Krebs cycle or the tricarboxylic acid (TCA) cycle, is a central metabolic pathway that occurs in the mitochondria of cells. It is responsible for the oxidation of acetyl-CoA derived from various fuel sources, generating energy in the form of ATP and producing NADH and FADH2.

Pyruvate, which is a product of glycolysis, serves as the starting point for the citric acid cycle. It enters the cycle by being converted into acetyl-CoA through a series of enzymatic reactions.

On the other hand, the compounds α-Ketoglutarate, Succinate, and Malate are all intermediates of the citric acid cycle. They are involved in various steps of the cycle, participating in the generation and transfer of energy-rich electrons and the production of ATP and reduced coenzymes.

Therefore, out of the given options, Pyruvate is the compound that is not a component of the citric acid cycle.

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