An ultrasound wave travels form soft tissue into bone. Some of the wave is reflected, some is transmitted.
What waves will experience a phase shift? (A) Both waves (B) Only the transmitted wave (C) Only the
reflected wave (D) None of the waves

The critical angle of the transparent material is 35.3 degrees.

The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:

sin(critical angle) = sin(90 degrees) / sin(angle of refraction)

sin(critical angle) = 1 / sin(32 degrees)

sin(critical angle) = 0.574

critical angle = arcsin(0.574)

critical angle = 35.3 degrees

Therefore, the critical angle of the transparent material is 35.3 degrees.

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Answer:

Below :)

Explanation:

It is the powerhouse of the cell and creates chemical energy.

Cylinders containing oxygen or acetylene can only be placed in confined spaces if they are secured in an upright position and the area is well-ventilated, as both gases are highly flammable and can cause explosions in the presence of heat or sparks.

Proper safety measures, including proper storage, handling, and transportation of gas cylinders, must also be taken to ensure the safety of personnel and property. The area should be properly marked with appropriate safety signs, and anyone entering the confined space should be trained in gas cylinder safety procedures.

In addition, the use of gas detectors is recommended to monitor the levels of oxygen and acetylene in the confined space to prevent the buildup of explosive concentrations. Proper protective gear and respiratory equipment may also be required in certain situations.

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Oxygen or acetylene cylinders are to be placed in confined spaces under specific safety conditions only. The area should have good ventilation, no ignition sources, well-functioning equipment, and temperature monitoring. Uncontrolled conditions may lead to accidents.

Cylinders containing oxygen or acetylene should only be placed in confined spaces under very specific circumstances, due to high risks associated with gas leaks, pressure builds-up, and the potential for explosions. The main safety considerations include ensuring the room has adequate ventilation, that there is no source of ignition nearby, and the regulator and valve of the cylinder are functioning properly. It is also important to respect the temperature limits as gases like acetylene and oxygen can behave differently at different temperatures. For example, at temperatures above the critical point (31°C for CO2 for instance), even high pressure can't force the gas into a liquid state—maintaining safety becomes very difficult under these conditions. The use of oxygen in rocket engines, for instance, requires controlled conditions with proper measures to prevent accidents.

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When we go 19113 Km above the surface of earth, the weight of the person will become half.

The weight of the person is given by

W = Mg

Where,

M is mass of the person and g is the gravitational acceleration.

The gravitational acceleration of the earth varies with the height from the surface of the earth as,

g' = g(R/(R+H))²

Where,

R is the radius of earth,

g' is the gravitational acceleration at height H,

For g' = g/2,

g/2 = g(R/(R+H))²

1/√2 = (R/(R+H))²

Solving further,

H = 3R

So, when we go to a distance 3R above the surface of earth the weight of the person will become half.

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Answer:

according to the graph, vavg= Stotal/Ttotal =10

(a) The resonant frequency of an LC circuit is given by the equation:

f = 1 / (2π√(LC))

Where f is the frequency, L is the inductance, and C is the capacitance.

We can rearrange this equation to solve for L:

L = 1 / (4π²f²C)

Plugging in the given values, we get:

L = 1 / (4π² * (10.4kHz)² * 340μF) = 0.115H

Therefore, the inductance of the circuit is 0.115H.

(b) The total energy in an LC circuit is given by the equation:

E = 1/2 * L *\(I_{max}\)²

Where E is the total energy, L is the inductance, and \(I_{max}\) is the maximum current.

Plugging in the given values, we get:

E = 1/2 * 0.115H * (7.20mA)² = 0.032J

Therefore, the total energy in the circuit is 0.032J.

(c) The maximum charge on the capacitor is given by the equation:

\(Q_{max}\)= C *\(V_{max}\)

Where \(Q_{max}\) is the maximum charge, C is the capacitance, and \(V_{max}\) is the maximum voltage.

At resonance, the maximum voltage across the capacitor and inductor are equal and given by:

\(V_{max}\) = \(I_{max}\) / (2πfC)

Plugging in the given values, we get:

\(V_{max}\) = 7.20mA / (2π * 10.4kHz * 340μF) = 0.060V

Therefore, the maximum charge on the capacitor is:

\(Q_{max}\) = 340μF * 0.060V = 20.4μC

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Digital stopwatches and mechanical stopwatches are two types of stopwatches that can be used for timing events. Digital stopwatches use electronic circuits to measure time, while mechanical stopwatches use a mechanical mechanism.

There are a few key differences between these two types of stopwatches.

Firstly, digital stopwatches tend to be more accurate than mechanical stopwatches. Digital stopwatches can measure time with greater precision, often down to hundredths or even thousandths of a second. Mechanical stopwatches, on the other hand, are typically only accurate to within a few tenths of a second.

Secondly, digital stopwatches are generally easier to read. They have a digital display that shows the elapsed time in clear, easy-to-read numbers. Mechanical stopwatches, meanwhile, use rotating dials or hands that can be more difficult to read, especially when the stopwatch is in motion.

Thirdly, digital stopwatches tend to be more reliable than mechanical stopwatches. Mechanical stopwatches rely on a series of delicate springs, gears, and levers to function. These can be prone to wear and tear, and can malfunction if they are not maintained properly. Digital stopwatches, on the other hand, use solid-state electronics that are less susceptible to damage.

In summary, while both digital and mechanical stopwatches can be used for timing events, digital stopwatches tend to be more accurate, easier to read, and more reliable than mechanical stopwatches. However, some people may prefer the aesthetic or tactile experience of using a mechanical stopwatch.

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The star is moving at 2,713.816 km/s towards us.

We have to use the Doppler Effect equation to find the velocity of the star in which this line appears at wavelength 120.5.

The Doppler Effect equation is :

v/c = Δλ / λ₀

In this equation,

Δλ = difference between the measured wavelength of the line in the star’s spectrum and its wavelength in the lab

λ₀ = rest wavelength

c  = Speed of light [ 3 × \(10^5\) km/s]

v = radial velocity of the star

For this star,  λ₁ = 120.5 nm

⇒   v/c = Δλ / λ₀

⇒    v/c = 120.5 - 121.6 / 121.6

              = - 0.00905 × 3 × \(10^5\) km/s

     v  =  - 2,713.816 km/s

Since the sign of velocity is negative the star is moving towards us.

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The complete question is:

"In hydrogen, the transition from level 2 to level 1 has a wavelength of 121.6 nm. Find direction (toward or away from us) of a star in which this line appears at wavelength 120.5 nm."

Answer:

the moving of something from its place or position or the occupation by a submerged body or part of a body of a volume which would otherwise be occupied by a fluid

Explanation:

c:

Answer:

Water is omnipresent in our environment on a global scale: in the seas, oceans, lakes, rivers, in glaciers and ice floes... but also in the atmosphere (clouds,

Rain, hail, snow, water vapor...). Water is also omnipresent in our environment

Daily: water to drink, to cook, to wash...

a. The minimum inductance of the tank circuit is 56.85 H

b. The maximum inductance of the tank circuit is 199.86 H

The resonant frequency of a series RLC circuit is given by

f = 1/2π√LC where

Making L subject of the formula, we have

L = (2πf)²/C

The minimum inductance of the tank circuit is 56.85 H

To find the minimum inductance, we substitute the value of

L = (2πf)²/C

L = (2π × 4.8 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (9.6π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (30.159 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = 909.583 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F

L = 568.489 × 10⁻¹ H

L = 56.8489 H

L ≅ 56.85 H

The minimum inductance of the tank circuit is 56.85 H

The maximum inductance of the tank circuit is 199.86 H

To find the maximum inductance, we substitute the value of

L = (2πf)²/C

L = (2π × 9.0 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (18π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (56.549 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = 3197.75 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F

L = 1998.59 × 10⁻¹ H

L = 199.859 H

L ≅ 199.86 H

The maximum inductance of the tank circuit is 199.86 H

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Answer: 5.39g/L

Explanation:

We need to calculate the average molar mass of the mixture which will be:

= (10 × 32) + (50 × 40) + (40 × 244) / 100

= (320 + 2000 + 9760) / 100

= 12080 / 100

= 120.8g/mol

Since the volume occupied is 22.4L and 1 mole of the gas will occupies 22.4L given the standard temperature conditions, then the density of the mixture will be:

= Mass / volume

= 120.8 / 22.4

= 5.39g/L

Therefore, the density of the mixture will be 5.39g/L.

The correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.

To find the distance from the conductor at which the magnetic field caused by the current is equal to the Earth's magnetic field, we'll use the formula for the magnetic field around a long straight conductor:

\(B = (de * I) / (2 * \pi  * r)\)

Where B is the magnetic field, μ₀ is the permeability of free space (\(4\pi  * 10^-7 Tm/A\)), I is the current, and r is the distance from the conductor. We want to find the value of r when B equals Earth's magnetic field (0.5 x 10⁻⁴ T).

\(0.5 * 10^-4 T = (4\pi  * 10^-7 Tm/A * 100 A) / (2 * \pi  * r)\)
To solve for r, we can first simplify the equation by cancelling the π terms:

\(0.5 * 10^-4 T = (4 * 10^-7 Tm/A * 100 A) / (2 * r)\)

Now, cancel out the A (Amperes) terms:

\(0.5 * 10^-4 T = (4 * 10^-7 Tm) / (2 * r)\)

Divide both sides by 4 x 10⁻⁷ T:

\(r = (0.5 * 10^-4 T) / (4 * 10^-7 T)\)

Simplify the equation:

r = \(0.5 * 10^3 m / 4\)
r = 500 / 4
r = 125

So, the correct answer is not provided in the given options A, B, C, or D. The distance from the axis at which the magnetic field caused by the current is equal in magnitude to Earth's magnetic field is 125 meters.

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Answer:

25 mm = 0 deg C

200 mm = 100 deg C

200 - 25 = 175 = change in thread per 100 deg C

95 - 25 = 70 mm - change in thread from 0 deg C

70 / 175 * 100 = 40 deg C    final temperature at 95 mm

you can swing your leg so it can't be kick, and remove up doesn't make sense and dodging it won't get you anywhere, so scooping it

Answer:

the reflection of the candle in the concave mirror formed upside down real image that is diminished

The average acceleration of the baseball while it is compressing the glove is 1008 10⁻³ m / s². The kinematic formula used is v² = v₀² - 2 a x.

Acceleration is the rate of change in a moving object's speed and direction over time. When a point or object accelerates or decelerates, it is moving straight forward. Motion on a circle increases despite the same speed because the direction is always changing.

Because the acceleration occurs in the opposite direction as the speed and the end speed is zero, the sign is negative.

0 = v₀² - 2 an x

a = v₀² / 2x

Consider converting the magnitudes to the SI system.

x = 2.4 mm (1 meter / 103 mm) = 2.4 103 m

Let's compute.

a = 2.2²/2 2.4 10⁻³

a = 1008 10⁻³ m / s²

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Within the subject of technology, radiogenic heat may be described because of the type of warmth that is released when radioactive isotopes disintegrate. consequently, we say that the thermal strength is launched by means of the nuclear disintegration of the radioactive isotopes.

Approximately 50% of the Earth's inner warmness originates from radioactive decay. four radioactive isotopes are chargeable for the general public of radiogenic warmness because of their enrichment relative to different radioactive isotopes uranium-238 (238U), uranium-235 (235U), thorium-232 (232Th), and potassium-40 (40K).

Radioactive heating refers back to the power dissipated within the interiors of planets, satellites, or asteroids as a consequence of the radioactive decay of radioactive isotopes (see radiochemistry). Radioactive isotopes are characterized by their decay energies and their half-lives.

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Answer:

Increase the amount of gas

Explanation:

By increasing the pressure of the solution, the amount of gas will have to increase. Solubility of gases increases as the pressure is made to increase. Before the pressure was increased, the gases moved freely about. But as it was increased, theses gases had more frequent collisions within this solution. Causing an increase. The liquid on its own will experience no changes.

Answer:

Increase the amount of gas

Explanation:

The speed of the 120 g ball after the collision is 4.0 m/s to the right.

To solve this problem, we can apply the principle of conservation of momentum for an elastic collision. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Let's denote the initial velocity of the 120 g ball as u₁, the initial velocity of the 400 g ball as u₂, and the final velocities of the balls after the collision as v₁ and v₂, respectively.

The momentum of an object is given by its mass multiplied by its velocity. Therefore, the initial momentum before the collision can be calculated as:

Initial momentum before collision = (mass₁ * velocity₁) + (mass₂ * velocity₂)

= (0.120 kg * 4.0 m/s) + (0.400 kg * 1.0 m/s)

= 0.480 kg·m/s + 0.400 kg·m/s

= 0.880 kg·m/s

Since the collision is perfectly elastic, the total momentum after the collision will also be 0.880 kg·m/s.

Now, we can set up the equation for the final momentum after the collision:

Final momentum after collision = (mass₁ * velocity₁') + (mass₂ * velocity₂')

Since only the 120 g ball is asked for its final velocity, we can express the equation as:

0.880 kg·m/s = (0.120 kg * velocity₁') + (0.400 kg * 1.0 m/s)

Now we can solve for velocity₁':

0.880 kg·m/s = (0.120 kg * velocity₁') + 0.400 kg·m/s

0.880 kg·m/s - 0.400 kg·m/s = 0.120 kg * velocity₁'

0.480 kg·m/s = 0.120 kg * velocity₁'

Divide both sides by 0.120 kg:

4.0 m/s = velocity₁'

Therefore, the speed of the 120 g ball after the collision is 4.0 m/s to the right.

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The portal should be placed at 97.50 m in order to intercept the turd at its highest point above the ground.

When a particle is hurled obliquely near the surface of the earth, it travels along a curved path while accelerating continuously in the direction of the planet's center (we assume the particle stays close to the surface of the globe). Such a particle's motion is known as projectile motion, and its route is referred to as a projectile.

Given parameters:

Initial speed of the turd: u = 51 m/s.

Angle of projection θ = 59°

Acceleration due to gravity: g = 9.8 m/s².

So, maximum height obtained by it be:

H = u²sin²θ/2g.

= 51² × sin²59°/(2×9.8) m

= 97.50 m.

Hence,  a portal should be placed at 97.50 m in order to intercept the turd at its highest point above the ground.

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The north and west components of this displacement are 9.19 km and -7.71 km respectively.

The north component of the displacement is calculated as follows;

Dy = D sinθ

Dy = 12 km x sin50

Dy = 9.19 km

Dx = D x cosθ

Dx = - 12 km x cos(50)

Dx = -7.71 km

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The focal length of the converging lens can be calculated using the formula 1/f = 1/d0 + 1/di where f is the focal length of the lens, d0 is the distance of the object from the lens, and di is the distance of the image from the lens.

In this case, the magnification produced by the lens is given as 3.2, which means that di/d0 = 3.2 ,Using this information and the formula above, we can solve for f as follows ,1/f = 1/d0 + 1/di 1/f = 1/0.17 + 1/(0.17 x 3.2 1/f = 5.8 ,f = 0.17/5.88. let's denote the object distance (u) as -17 cm, image distance (v) as a positive value since it's a real image.

The magnification (M) as 3.2. We can use the magnification formula to find the image distance ,M = -(v/u) 3.2 = -(v/-17)
v = 3.2 × 17 = 54.4 cm ,Next, we'll use the lens formula ,1/f = 1/v - 1/u Where f is the focal length. Plug in the values for u and v , 1/f = 1/54.4 - 1/-171/f = 0.01838 + 0.05882 1/f = 0.07720 To find the focal length, take the reciprocal of both sides f = 1/0.07720 ≈ 6.82 cm.
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Answer:

440kgm/s

Explanation:

Momentum= mass × velocity

= 110× 4

= 440kgm/s

The thermal capacitance of the coil is neglected with respect to the tank wall and the tank liquid. Energy balance is done only on the tank liquid. Option C is the correct answer.

The consequence of neglecting the thermal dynamics of the cooling coil in a stirred tank can vary depending on the specific situation and the magnitude of the neglected effects. However, in general, neglecting the thermal capacitance of the cooling coil in relation to the tank wall and the tank liquid can have the following consequences:

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Answer:

False

Explanation:

Just took the test

False, because hypochondriacs think they have a significant, undetected medical ailment even when testing reveal they are healthy.

A hypochondriac is someone who, despite diagnostic testing showing they have no health issues, lives in constant anxiety that they have a terrible, undetected medical illness. They are obsessed with the concept that they suffer from a major illness that has gone untreated.

In adults, hypochondriasis often begins to manifest. Among the symptoms are a persistent, strong anxiety of developing a major illness and concern that seemingly little symptoms portend a larger problem. A patient may change physicians or see them regularly.

Medication and counselling could be helpful.

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The work was done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\) and at an angle of \(29^o\) 42.83 J.

When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.

To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.

Given:

The mass, m = 2 kg,

The acceleration, g = 9.81 \(m/s^2\),

θ = angle between block and surface kinetic friction = μ

Calculate the work done by the formula given below,

\(W_{fy}\) = F sinθ

\(W_{fy}\) =  (\(mgsin\)θ)/ (sinθ -  μ * cosθ)

Substitute the values

\(W_{fy}\)  = \((2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o\)

\(W_{fy}\)  = 42.83 J

Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of  9.81 \(m/s^2\), and at an angle of \(29^o\) is 42.83 J.

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Answer: 4.44302176697 m/s^2

Explanation:

formula for acceleration is (final velocity - initial velocity)/time.   So in your case:

(34.7m/s - 0m/s)/ 7.81s  = 4.44302176697 m/s^2