An oxygen tank used in a hospital setting has a pressure of 4.0 atm and contains 60.0% O₂ and 40.0% N₂ by volume. the partial pressure of oxygen in the tank is 2.4 atm
given that :
the total pressure of gas = 4 atm
percent by volume of oxygen = 60.0 % = 0.6
percent by volume of nitrogen = 40 % = 0.4
According to the Dalton's law of partial pressure is given as :
Partial pressure = mole fraction of gas × P total
Partial pressure of O₂ = 0.6 × 4
Partial pressure of O₂ = 2.4 atm
Thus, the partial pressure of the oxygen gas is 2.4 atm.
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Which best describes what tends to occur in groups that results in an increase in atomic radius?
As you move down a group (vertical column) in the periodic table, the atomic radius tends to increase.
This is because the number of energy levels (or shells) increases as you move down a group, while the effective nuclear charge (which determines the attractive force between the nucleus and the valence electrons) remains relatively constant. As a result, the valence electrons are farther from the nucleus and the size of the atom increases. For example, as you move from top to bottom in the alkali metal group (Group 1), the atomic radius increases because the number of energy levels increases from one to seven. Similarly, as you move from top to bottom in the halogen group (Group 17), the atomic radius increases because the number of energy levels increases from two to seven.
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A cell is a system of parts that work together to carry out basic life processes. An animal is also a system of parts that work together to carry out basic life processes. Match each organ or organ system with the cell part that has a similar function.
Answer: the cell wall is the skeletal system
The nucleus is the brain
The mitochondria is the digestive system
The cell membrane is the skin
Explanation:
How many moles of Ca(OH)2 are needed to make 200.0 mL of 0.250 M solution? Ca(OH)2
Answer:
0.05 moles of Ca(OH)2
Explanation:
The formula for molarity is: mol/L = M
First, convert 200.0 mL to L.
200 mL/1000 = 0.2 L
Next, plug in the values given.
mol/0.2 = 0.250
Rearrange the equation.
mol = 0.2*0.250
mol = 0.05
If you'd like to check it, simply plug in 0.05 to mol and divide it by 0.2. In theory, you should get 0.250.
Pedro's book weighs 19/4 pounds. Blanca's book weighs 17/7 pounds. Use estimation to determine about how much more Perdro's book wweighs than Blanca's.
A 1lbs
Sorry I meant math.
B 2lbs
C 6lbs
D 7lbs
Answer:
2pounds
Explanation:
Given parameters:
Weight of Pedro's book = \(\frac{19}{4}\) pounds
Weight of Blanca's book = \(\frac{17}{7}\) pounds
Unknown:
How much more does Pedro's book weigh more than Bianca's book ?
Solution:
To Solve this problem, let us convert the fractions to decimal;
Weight of Pedro's book = 4.75 pounds
Weight of Bianca's book = 2.43 pounds
Differences = 4.75pounds - 2.43 pounds
= 2.32 pounds
Estimating gives 2pounds
Please see the picture, I could really use some help!
Answer:
yo no se de eso preguntale a otro si
_________________ are changes in an organism's genetic material.
Answer:
Mutation
Explanation:
because Mutation is , an alteration in the genetic material (the genome) of a cell of a living organism or of a virus that is more or less permanent and that can be transmitted to the cell's or the virus's descendants.
Answer:
Mutations are changes in an organism's genetic material.
Explanation:
Hope it Helps! :)
A pyrotechnician mixes 280 g of black powder for a firework. Find the amount of oxygen, carbon dioxide, and sulfur dioxide generated when this firework bursts, if the oxidizing agent in the powder is saltpeter.
The mass of oxygen, carbon dioxide, and sulfur dioxide generated from the reaction of black powder and saltpeter is:
The mass of SO₂ produced is 56.0 g SO2 The mass of CO₂ produced is 154 g CO₂The total mass of O₂ produced is 140 gWhat is the equation of the reaction of black powder and saltpeter?The percentage by mass of the constituents of black powder is as follows:
KNO₃ = 75%
S = 10%
C = 15%
The mass of oxygen, carbon dioxide, and sulfur dioxide generated is calculated from the given percentages by mass as follows:
For SO₂; 1 mole S produces 1 mole SO₂:
mass of SO₂ = 280 g * 0.10 / 32.g S * 1 mol SO2 / 1 mol S) * 64.0 g
mass of SO₂ = 56.0 g SO2
mass of O₂ that reacted with S to produce SO₂ will be:
1 mole O₂ reacts with 1 mole S
mass of O₂ = 56.0 / 64 * 32.0
mass of O₂ = 28.0 g O₂
For CO₂; 1 mole C produces 1 mole CO₂
mass of CO₂ produced = 280 g * 0.15 / 12.g/mol x * 44.0 g/mol)
mass of CO₂ produced = 154 g CO₂
mass of O₂ that reacted with C to produce CO₂ will be:
1 mole O₂ reacts with 1 mole C
mass of O₂ = 154 / 44 * 32.0
mass of O₂ that reacted with C = 112.0 g O₂
The total mass of O₂ produced = 112 + 28
The total mass of O₂ produced = 140 g
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In an atom:
The nucleus is made of electrons and protons.
Protons have positive charges.
Neutrons have negative charges.
All of the above.
can someone please help me ived this 2 times
Answer:
Explanation:
The nucleus of an atom contains protons and neutrons.
Protons have positive charges, neutrons have neutral charges (no charge), and electrons have negative charges. That is why when you determine net charge of atom you only look at the proton to electron ratio since the neutrons don't matter when it comes to charge.
I hope this helps. Let me know in the comments if anything is unclear.
in the nacl crystal lattice, how many composite cl- ions are in a single unit cell?
Negative and positive ions alternate in the ionic crystals. For instance, the melting point of calcium fluoride (CaF) is 1418 °C. Therefore, four Cl⁻ ions are in a single unit cell.
What is Crystalline Solid?The description of crystalline solid states that it is a substance whose atoms or even subatomic particles are organized in a highly structured form. Atomic nuclei in metallic crystals are surrounded by a "sea" of delocalized electrons.
Molecules of many types make up molecular crystals. Atoms that are covalently bound to one another make up covalent network crystals. Jewelry is crafted with diamond. Quartz is used to create things like watches and wall clocks. One unit cell of the sodium chloride lattice includes eight ions in total, four of which are Na+ ions and four of which are Cl⁻ ions.
Therefore, four Cl⁻ ions are in a single unit cell.
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What is the main idea of science? (states of matter)
Answer:
STATES OF MATTER AREliquid statesolid stategaseous statewhat ocurrrs when the vapor pressure of a liquid is equal to the external atmospheric pressure
Answer:
The change from a liquid phase to a gaseous phase.
so the answer would be it changed to a gaseous phase
---------------
This is what occurs when the vapor pressure of the liquid is equal to the atmospheric pressure exerted on the liquid.
classify of covalent bond according to the
number of bonds between atoms
Explanation:
Covalent bonds can be classified based on the number of bonds between atoms into three categories:
1. Single Covalent Bond: In a single covalent bond, two atoms share one pair of electrons. This is the most common type of covalent bond. For example, in H2O, each hydrogen atom forms a single covalent bond with the oxygen atom.
2. Double Covalent Bond: In a double covalent bond, two atoms share two pairs of electrons. This bond is stronger than a single covalent bond. For example, in O2, the oxygen atoms are connected by a double covalent bond.
3. Triple Covalent Bond: In a triple covalent bond, two atoms share three pairs of electrons. This bond is the strongest among the three types. For example, in N2, the nitrogen atoms are connected by a triple covalent bond.
It is important to note that the number of bonds between atoms is determined by the number of electrons they need to achieve a stable electron configuration, which varies depending on the elements involved.
The covalent bond is classified mainly into three types
single, double and triple bonds.
Covalent bond is a bond formed between two atoms through the sharing of two electrons between them. The atoms will share more than one electron pairs if the valency is not satisfied. the three types of covalent bond are single bond, double bond and triple bond.
single bond is formed when one pair of electrons are shared between atoms, while if two pairs or three pairs are shared, it is called double or triple bond respectively. Covalent compounds are those which contains covalent bonding.
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The dog will eat more food to store fat and grow more hair.
The dog will lay in the sunlight to transpire
The dog will pant to circulate air throughout the body to cool
down
3.
The dog will grow a thick winter coat to keep warm during the
In the summer months, what is this dog's likely response to the rising temperatures?
summer
CLEAR ALL
hibernation exclamation mark
1. Look up bromine on the periodic table. What is the most common isotope of bromine?
Answer:
The most common isotope is Bromine-79.
Explanation:
state the characteristics that show a transition on moving down a subgroup
pls answer fast
Answer:
1. Valency of electrons.
2. Chemical properties. Characteristics which show a transition or moving down a group are:
1. Metallic character increases down the group.
2. Number of electron shells increases down the group. 3. Atomic size increases down the group.
4. Ionisation potential decreases dowRead
Explanation:
In a container with volume of 25.0 L, there are 40 g of CH4 gas. If the number of gas is reduced to 15.0 L, what is the new amount inmole?
Answer
1.50 mol
Explanation
Given:
Initial volume, V₁ = 25.0 L
Mass of CH4 gas in 25.0 L container = 40 g
Final volume, V₂ = 15.0 L
From the Periodic Table; molar mass of CH4 = 16.04 g/mol
What to find:
The new amount in mole.
Step-by-step solution:
According to Avogadro’s law: For a confined gas, the volume (V) and number of moles (n) are directly proportional if the pressure and temperature both remain constant. That is:
\(\frac{V_1}{n_1}=\frac{V_2}{n_2}\)n₁ = Mass/Molar mass = (40.0g/16.04 g/mol) = 2.493765586 mol
n₂ is the new amount in mole and can be calculated as follows:
\(\begin{gathered} \frac{25.0\text{ L}}{2.493765586\text{ mol}}=\frac{15.0\text{ L}}{n_2} \\ \text{Cross multiply} \\ n_2\times25.0\text{ L }=15.0\text{ L }\times2.493765586\text{ mol} \\ \text{Divide both sides by 25.0 L} \\ \frac{n_2\times25.0\text{ L}}{25.0\text{ L}}=\frac{15.0\text{ L }\times2.493765586\text{ mol}}{25.0\text{ L}} \\ n_2=1.496259352\text{ mol} \\ To\text{ 3 significant digits} \\ n_2=1.50\text{ mol} \end{gathered}\)The new amount in moles is 1.50 moles
A scientist is investigating the rate of cellular respiration when a person is exercising and when at rest. How would the amount of gas released be different in these two situations?
A) Less oxygen would be released when exercising than when at rest.
B) More oxygen would be released when exercising than when at rest
C) Less carbon dioxide would be released when exercising than when at rest
D) More carbon dioxide would be released when exercising than when at rest.
5.(08.02 MC)
A 0.680 M Ca(OH)2 solution was prepared by dissolving 55.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution formed? (4 points)
O 1.09 liters
0 1.23 liters
2.01 liters
O 2.18 liters
Answer: 1.09 Liers
Explanation:
I did the problem and got it correct.
Answer:
A. 1.09
Explanation:
I did the Chemistry Exam
how is oxygen transported in the blood?multiple choice10-20% dissolved in plasma; 80-90% as oxyhemoglobin98-99% dissolved in plasma; 1-2% as oxyhemoglobin50% dissolved in plasma; 50% as oxyhemoglobin1-2% dissolved in plasma; 98-99% as oxyhemoglobin
The correct answer is A. 10-20% of oxygen is dissolved in plasma and 80-90% is transported as oxyhemoglobin in the blood.
Oxygen is transported in the blood primarily through a combination of dissolved oxygen in plasma and oxygen bound to hemoglobin within red blood cells. Approximately 10-20% of oxygen is found dissolved in plasma, while the remaining 80-90% is bound to hemoglobin in the form of oxyhemoglobin. The concentration of oxygen in plasma is determined by the partial pressure of oxygen in the environment, while the amount bound to hemoglobin is determined by the amount of hemoglobin present in the blood. Oxygen can also be transported in the form of bicarbonate and other small molecules.
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complete question: how is oxygen transported in the blood?multiple choice
A.10-20% dissolved in plasma; 80-90% as oxyhemoglobin
B.98-99% dissolved in plasma; 1-2% as oxyhemoglobin
C.50% dissolved in plasma; 50% as oxyhemoglobin
D. 1-2% dissolved in plasma; 98-99% as oxyhemoglobin
how much heat is released when 32g of water cools from 46°C and freezes
The amount of heat released when 32g of water cools from 46°C and freezes is 6182.4 J
Heat: This is a form of energy that brings about the sensation of warmth. The S.I unit of heat is Joules (J)
⇒ Formula:
Q = cm(t₂-t₁).................. Equation 1⇒ Where:
Q = amount of heat releasedc = specific heat capacity of waterm = mass of watert₁ = Initial temperaturet₂ = Final temperatureFrom the question,
⇒ Given:
m = 32 g = 0.032 kgt₁ = 46 °Ct₂ = 0 °C (Freezing point)c = constant = 4200 J/kg.°C⇒ Substitute these values into equation 1
Q = 0.032(4200)(0-46)Q = -6182.4 JNote: The negative sign tells that heat is released and as such can be ignored.
Hence, The amount of heat released is 6182.4 J
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✓ Details
1. 2HCl(aq) + Zn(s)→ H₂(g) + ZnCl₂(aq)
You have 100. mL of a .300 M solution of HCI. As the reaction occurs, the volume of solution is unchanged.
1. How many grams of Zn were used up?
2. How many liters of hydrogen gas at STP were formed?
3. What is the molar concentration of the zinc chloride formed?
k
The number of grams of Zinc used is 1962g, the volume of hydrogen gas formed at STP is 672.071L and the molar concentration of Zinc Chloride is 300M.
1. The number of moles of Zn used up is given by the equation:
n = CV
Since the volume is given in mL, we must convert it to L before plugging it into the equation.
n = (300 mol/L)(100 mL)(1 L/1000 mL)
n = 30 mol
The molar mass of Zn is 65.39 g/mol, so the number of grams of Zn used up is given by:
m = nM
m = (30 mol)(65.39 g/mol)
m = 1962 g
2. The number of moles of H₂ formed is also 30 mol. One mole of any gas occupies 22.4 L at STP, so the number of liters of H₂ formed is given by:
V = nRT/P
V = (30mol)(0.08206 L•atm/mol•K)(273 K)/(1 atm)
V = 672.071 L
The volume of liters of H2 formed is 0.6L
3. The molar concentration of ZnCl₂ is given by the equation:
C = n/V
Here, number of moles is n and the volume is V The number of moles of ZnCl₂ is 30 mol, and the volume is 100 mL, so the molar concentration is:
C = (30 mol)/(0.1L)
C = 300 M
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list the steps for preparing magnesium sulphate christalls from aqueous magnesium sulphate orderly
Steps for preparing magnesium sulphate christalls from aqueous magnesium sulphate orderly is magnesium sulphate crystals are prepared by the following steps:
Place a filter paper on a funnel and use it. Place an evaporating basin under the funnel after preparing it. On the filter paper, now sprinkle some magnesium oxide powder. Magnesium oxide powder should be covered with diluted sulfuric acid before being collected in an evaporating basin. Observe the solution gathering in the basin. After gathering the solution in the basin, either let it evaporate naturally or heat it.Crystals of magnesium sulfate are found in the residue that remains after the solution has evaporated.To learn more about magnesium sulphate crystals visit: https://brainly.com/question/17208797
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how is this equation read?
4Na (1) +Mn(SO 4 ) 2 (aq) Mn (3) +2Na 2 SO
What is the pOH of water?
Answer:
A. 7
(assuming the water is neutral)
compare and contrast gamma, alpha, and beta raditiaion in terms of componets, energy level, examples, how it's created, safety in types of nuclear energy.
Gamma, alpha, and beta radiation are all forms of ionizing radiation emitted during radioactive decay, but they differ in terms of their components, energy levels, examples, creation, and safety in various types of nuclear energy.
Gamma radiation consists of high-energy photons, similar to X-rays. It possesses the highest energy level among the three types and can penetrate several centimeters of lead or several meters of concrete.
Examples of gamma-emitting isotopes include cobalt-60 and cesium-137. Gamma rays are created during nuclear reactions and decay processes, such as fission or fusion reactions. They pose a significant risk to human health due to their ability to damage living tissue, but their penetration power makes them useful in medical imaging and cancer treatment.
Alpha radiation consists of alpha particles, which are composed of two protons and two neutrons (helium nuclei). They have low energy levels and can be stopped by a sheet of paper or a few centimeters of air.
Examples of alpha-emitting isotopes include uranium-238 and radon-222. Alpha particles are created through the decay of heavy elements. While they can cause significant damage if inhaled or ingested, they are less penetrating and therefore less hazardous outside the body.
Beta radiation involves the emission of beta particles, which are high-energy electrons (beta-minus) or positrons (beta-plus). They have moderate energy levels and can penetrate several millimeters of aluminum.
Examples of beta-emitting isotopes include carbon-14 and strontium-90. Beta particles are created during the decay of certain isotopes, where a neutron is transformed into a proton or vice versa. Beta radiation poses an intermediate level of risk, as it can penetrate the skin and cause tissue damage, but it is less harmful than gamma radiation.
In terms of nuclear energy, gamma radiation is a concern in all types of reactors, as it is released during fission and fusion reactions. Shielding is necessary to protect workers and the environment.
Alpha radiation is of particular concern in nuclear fuel cycle processes like uranium mining and enrichment. Beta radiation is relevant in nuclear power plant operations, as some fission products emit beta particles. It requires appropriate shielding and monitoring to ensure worker safety.
Overall, gamma radiation has the highest energy, alpha radiation has the lowest, and beta radiation falls in between. Their differing penetration abilities, creation mechanisms, and safety considerations make them suitable for various applications and require tailored safety measures.
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HELP
our response should be at least 5-7 sentences at a minimum.
Question: A chemical reaction absorbs energy when occurring. Is this reaction Exothermic or Endothermic? If the enthalpy of the reactants was 300kJ and the enthalpy of the products was 450kJ, list one possible value for the enthalpy value of the transition state (the activation energy).
Explanation:
a chemical reaction that absorbs energy is known to be endothermic since heat is being taken in by the reaction. The value of the transition state would be 150 because you have to subtract the product's enthalpy and the reactant's enthalpy to obtain it. A positive value for the transition state also corroborates that the reaction is endothermic.
6.Find the empirical formula of a compound that contains:19.16 g Sodium1.680 g Hydrogen25.81 g Phosphorus
The empitical formula shows the simplest ratio of elements in a compound (not the total number of atoms in the molecule).
So to find the empirical formula we need to calculate how many moles of each atom we have in this sample. Then we will see the ratio of each element.
We are given the mass, so to convert it to moles we use the molar mass. For this we go to the periodic table and see that the values for each element are:
Na (sodium): 22,99 g/mol
H (hydrogen): 1 g/mol
P (phosphorus): 25,81 g/mol
So we calculate the moles of each element as follows:
\(\begin{gathered} moles_{Na}=\frac{Mass_{Na}}{Molar\text{ }mass_{Na}}=\frac{19.16g}{22.99g/mol}=0.833\text{ mol} \\ moles_H=\frac{Mass_H}{Molar\text{ }mass_H}\text{ }=\frac{1.68g}{1g/mol}=1.68mol \\ moles_P=\frac{Mass_P}{Molar\text{m}ass_P}\text{=}\frac{25.81g}{30.97\frac{g}{mol}}=0.833mol \end{gathered}\)And as we see, for every 0.833 moles of Na we have the same number of moles of P, so the ratio of these elements in the molecule is 1 to 1.
As for the hydrogen:
\(\frac{moles_{Na}}{moles_H}=\frac{0.833}{1.68}\approx\frac{1}{2}\)So the ratio Na to H is 1 to 2.
Now we can write the empirical formula as follows=
\(NaH_2P\)
Which statements are real-world applications of life science? Check all that apply.
Farmers study plant growth and are able to grow more fruits and vegetables.
Doctors can determine what is wrong with a patient and prescribe the right medicine.
Scientists study weather patterns to provide information about future weather
Scientists can track animal movements and predict where they might be feeding
Dentists recommend you brush and floss daily because bacteria cause tooth decay
Answer:
A,B,D,E
Explanation:
A, B, D and E-statements are real-world applications of life science.
What is science?The concept of science can be defined as a body of systematized knowledge acquired through observation, identification, research and explanation of certain categories of phenomena and facts, and formulated methodically and rationally.
Farmers study plant growth and are able to grow more fruits and vegetables -Farmers protect crops from diseases and adverse climatic conditions. It protects crops from wind and rodents. Farmers have bountiful crops. Farmer's crops are also protected from birds and animals.
Doctors can determine what is wrong with a patient and prescribe the right medicine - A doctor writes a prescription based on a patient's medical history, symptoms, and other factors.
Scientists study weather patterns to provide information about future weather and dentists recommend you brush and floss daily because bacteria cause tooth decay.
Hence, options A, B, D and E are correct.
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Consider the following reaction in a gas phase:C(s) + H2O(g) ⇄ CO(g) + H2(g) KC = 0. 2 at 1000 °CCalculate the concentration of CO in an equilibrium mixture (in mol/L) if a reaction mixture initially contains only reactants, and the equilibrium concentration of H2O(g) is [H2O] = 0. 500 M at 1000 °C
The concentration of CO (g) in the equilibrium mixture is 0.020 M. In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.
The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.
Given that the concentration of H2O (g) is [H2O] = 0.500 M at 1000°C, and the reaction is:
C(s) + H2O(g) ⇄ CO(g) + H2(g) KC = 0.2 at 1000°C
We need to determine the concentration of CO in an equilibrium mixture (in mol/L)
if a reaction mixture initially contains only reactants.
We can solve this problem using the ICE table method as follows:
Let x be the change in concentration of H2O (g) and CO (g) when they reach equilibrium.
Then the equilibrium concentrations of CO (g) and H2 (g) are equal to x. Hence, the equilibrium concentration of H2O (g) is (0.500 - x) M. Substitute these values in the expression for Kc and solve for x.
Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]
= 0.2[CO (g)] = Kc [H2O (g)] [C (s)] / [H2 (g)]
= 0.2 × (0.500 - x) / x
We can simplify this expression by cross-multiplication to get:
5x = 0.1 - 0.2xx = 0.02 M
Substituting x = 0.02 M in the expression for [CO (g)], we get:
[CO (g)] = 0.2 × (0.500 - 0.02) / 0.02 = 5.8 M (approx.)
Therefore, the concentration of CO (g) in an equilibrium mixture (in mol/L) is 5.8 M. The problem requires us to find the equilibrium concentration of CO (g) in a mixture that initially contains only reactants.
To solve this problem, we need to use the expression for the equilibrium constant Kc, which is given by:
Kc = [CO (g)] [H2 (g)] / [H2O (g)] [C (s)]
We can also use the ICE table method to solve this problem. In this method, we start with the initial concentration of the reactants and calculate the change in concentration of each species as they reach equilibrium.
We then use the equilibrium concentrations to calculate the value of Kc and solve for the unknowns. Here is how we can set up the ICE table for this problem: Reaction:
C(s) + H2O(g) ⇄ CO(g) + H2(g)
Initial: [C] = [H2]
= 0 M,
[H2O] = 0.500 M
Equilibrium: [C] = [H2] = x,
[H2O] = 0.500 - x,
[CO] = [H2] = x
Change: +x +x -x -x
Substituting the equilibrium concentrations into the expression for Kc, we get:
Kc = [CO] [H2] / [H2O] [C]
= x² / (0.500 - x)
= 0.2
Solving for x, we get: x = 0.020 M
Substituting this value of x into the expression for [CO], we get:
[CO] = x = 0.020 M
Therefore, the concentration of CO (g) in the equilibrium mixture is 0.020 M.
In other words, only a small amount of CO (g) is produced in this reaction at 1000°C. T 0.020 M.
The concentration of CO in an equilibrium mixture (in mol/L) is 5.8 M.
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A student states that a graduated cylinder contains 150 mL of water the statement is
Answer:
Explanation:
An Observation