An organ pipe is 151cm\; cm long. The speed of sound in air is 343 m/s. Part A: What are the fundamental and first three audible overtones if the pipe is closed at one end? What are the fundamental and first three audible overtones if the pipe is open at both ends? Express awnsers to 3 signiicant figures seperated by commas
Answers
For an organ pipe that is closed at one end and is 151 cm long:
Part A:
Fundamental frequency (first harmonic) = (speed of sound) / (2 x length of pipe)
= 343 / (2 x 1.51)
= 113.91 Hz
First overtone (second harmonic) = 3 x fundamental frequency
= 3 x 113.91
= 341.73 Hz
Second overtone (third harmonic) = 5 x fundamental frequency
= 5 x 113.91
= 569.55 Hz
Third overtone (fourth harmonic) = 7 x fundamental frequency
= 7 x 113.91
= 797.37 Hz
For an organ pipe that is open at both ends and is 151 cm long:
Fundamental frequency (first harmonic) = (speed of sound) / (2 x length of pipe)
= 343 / (2 x 1.51)
= 113.91 Hz
First overtone (second harmonic) = 2 x fundamental frequency
= 2 x 113.91
= 227.82 Hz
Second overtone (third harmonic) = 3 x fundamental frequency
= 3 x 113.91
= 341.73 Hz
Third overtone (fourth harmonic) = 4 x fundamental frequency
= 4 x 113.91
= 455.64 Hz
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The fundamental frequency (first harmonic) of a closed-end pipe is given by:
f1 = v/4L
where v is the speed of sound in air and L is the length of the pipe.
For a closed-end pipe with L = 151 cm and v = 343 m/s, we have:
f1 = 343/(4 x 151/100) = 571 Hz
The frequency of the first overtone (second harmonic) is:
f2 = 2f1 = 2 x 571 = 1142 Hz
The frequency of the second overtone (third harmonic) is:
f3 = 3f1 = 3 x 571 = 1713 Hz
The frequency of the third overtone (fourth harmonic) is:
f4 = 4f1 = 4 x 571 = 2284 Hz
For an open-end pipe, the fundamental frequency is given by:
f1 = v/2L
where L is the length of the pipe.
For an open-end pipe with L = 151 cm and v = 343 m/s, we have:
f1 = 343/(2 x 151/100) = 1136 Hz
The frequency of the first overtone (second harmonic) is:
f2 = 2f1 = 2 x 1136 = 2272 Hz
The frequency of the second overtone (third harmonic) is:
f3 = 3f1 = 3 x 1136 = 3408 Hz
The frequency of the third overtone (fourth harmonic) is:
f4 = 4f1 = 4 x 1136 = 4544 Hz
Therefore, for a closed-end pipe with a length of 151 cm, the fundamental frequency is 571 Hz, and the first three overtones are 1142 Hz, 1713 Hz, and 2284 Hz.
For an open-end pipe with a length of 151 cm, the fundamental frequency is 1136 Hz, and the first three overtones are 2272 Hz, 3408 Hz, and 4544 Hz.
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Related Questions
A
heat engine is measured to have 30% efficiency. Is the theoretical
efficiency going to be greater or less than that? Why?
Answers
The theoretical efficiency is greater than that of the actual efficiency of the engine. This is because heat engine always produces some waste heat.
The Second Law of Thermodynamics states that a heat engine cannot be 100% efficient. In practice, a heat engine is only 100% efficient when it is operating at about 30-50% efficiency.
If we were to multiply this by 100, we would get the efficiency as a percent: 49%. This is the theoretical maximum efficiency. If we were to actually build an engine, it would be less efficient than the theoretical engine. The theoretical engine that can achieve this theoretical maximum efficiency is called the Carnot Engine.
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Which of the following would be potential impacts of global climate change on thermohaline circulation in the oceans?
A: slowing the rate of circulation
B: no effect of circulation
C: changing the direction of circulation
D: increasing the rate of circulation
Answers
The potential impacts of global climate change on thermohaline circulation in the oceans is increasing the rate of circulation. That is option D.
What is thermohaline circulation?The thermohaline circulation is defined as the process by which deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline).
When there is global climate change increased temperature of water masses would cause these currents to flow faster given the higher kinetic energy of the water molecules.
Therefore, there is increase in rate of circulation when there is global climate change.
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Abu Dhabi classical FM Radio station Broadcasts on a frequency of 91.6 MHz calculate the wavelength of the electromagnetic radiation emitted by the transmitter. Which part of the electromagnetic spectrum does it belongs?
Answers
Answer:
C=F×W
so, W=C/F
Explanation:
frequency=F
wavelength=W
speed of light =C in that medium
earths mass is aproximately 81 times the mass of the moon. if earth exerts a gravtational force of magnitude f on the moon, the magnitude of the gravitational force of the moon on earth is
Answers
The magnitude of the gravitational force of the Moon on Earth is also 1.99 x 10^20 N. The gravitational force of the moon on Earth.
The magnitude of the gravitational force of the moon on Earth is the same as the magnitude of the gravitational force of Earth on the moon, as stated by Newton's third law. However, let's look at how the gravitational force between these two celestial objects is calculated.
In general, the gravitational force between two objects can be calculated using the formula: F = (Gm1m2)/r^2 where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.
The mass of the Earth is approximately 81 times greater than that of the Moon. The mass of the Earth is about 5.97 x 10^24 kg, while the mass of the Moon is approximately 7.34 x 10^22 kg.
As a result, we may use these values to calculate the magnitude of the gravitational force exerted by Earth on the Moon.
Assume that the distance between the centers of mass of Earth and Moon is 384,400 km.
Furthermore, G has a value of 6.67 x 10^-11 Nm^2/kg^2.
Using the formula: F = (Gm1m2)/r^2
we get: F = (6.67 x 10^-11 Nm^2/kg^2)(5.97 x 10^24 kg)(7.34 x 10^22 kg)/(384,400,000 m)^2
= 1.99 x 10^20 N
The magnitude of the gravitational force of Earth on the Moon is about 1.99 x 10^20 N.
Again, due to Newton's third law, the magnitude of the gravitational force of the Moon on Earth is also 1.99 x 10^20 N.
Therefore, this is our final answer.
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HELP FAST What is voltage, and what is its relationship to amperage and power?
(10 points)
Answers
Answer:
Amperage is the rate of electrical charge per time.
1 amp = 1 coulomb / second
Power is the product of amperage and voltage.
P = IV
Explanation:
Which force keeps an object moving in a circle? centripetal force fluid friction inertia momentum
Answers
Answer:
Any object moving in a circle (or along a circular path) experiences a centripetal force. That is, there is some physical force pushing or pulling the object towards the center of the circle. This is the centripetal force requirement.
Explanation:
a long straight wire lies on a horizontal table and carries an ever-increasing current toward the north. two coils of wire lie flat on the table, one on either side of the wire. when viewed from above, the direction of the induced current in these coils is 60) a) counterclockwise in both coils. b) counterclockwise in the east coil and clockwise in the west coil. c) clockwise in the east coil and counterclockwise in the west coil. d) clockwise in both coils
Answers
option C is correct.
Using the right-hand thumb rule, the direction of the magnetic field is out of the page for the top coil and the direction of the magnetic field is into the page for the bottom coil.
As the current is increasing, there will be an increase in flux and as a result, an induced magnetic field will be set up.
For top coil, as the flux out of the page is increasing, the induced field will be into the page to oppose the original flux, therefore, an induced current is clockwise.
For the bottom coil, the flux into the page is increasing so the induced field will be out of the page so the induced current is counterclockwise.
so, option C is correct.
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Does anybody know anything about speed and velocity? im hella stuck.
Answers
Answer:
lm.ao i was stuck too when i was on that
Explanation:
what u need to know sis?
speed, being a scalar quantity, is the rate at which an object covers distance. The average speed is the distance (a scalar quantity) per time ratio. Speed is ignorant of direction. On the other hand, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes.
Yani is speaking to an elementary school class on the importance of good nutrition. Without getting into the breakdown of macronutrients and what they
do, how might Yani BEST advise these children to have a balanced diet?
OA. Stick to meat and dairy only, cutting out carbs.
O B.
Don't ever eat candy, cake, or other junk food.
O c.
Try to have many different colors of foods.
OD.
Stick with raw foods instead of cooked ones.
Answers
The best advice Yani can give these elementary school children to have a balanced diet is "Don't ever eat candy, cake, or other junk food".
All the given options are true and correct regarding a balanced diet. But for an elementary school child to understand about a balanced diet, one must not et into the breakdown of macronutrients and what they do.
Option A mentions carbs which is a macronutrient. So it is incorrect. Option C is explaining to eat different types of fruits and vegetables. But it might be interpreted wrongly because even junk foods and candies will look colorful. Option D is not a good diet for a child.
Therefore, the best advice Yani can give these elementary school children to have a balanced diet is "Don't ever eat candy, cake, or other junk food".
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Answer:
Try to have many different colors of foods.
Explanation:
Action-reaction forces do not cancel each other because the action force is always greater than the reaction force
True
False
Answers
A paratrooper is inltially falling dowtward at a speed of 30.3 m/s before her parachute opens, When it opens, she expeliences an upnard instantaneous acceleration of 69 m/s² (a) if this acceleration remained coestant, how much tima would be required to reduce the paratrooper's speed to a sate 5.25 m/s² (Actually the acceleratien is not constant in this case- tut. the equations of constant acceleration provide an easy estimate.) (b) How far does the paratreoper fall during this time interval?
Answers
(a) The time required to reduce the paratrooper's speed to 5.25 m/s², assuming the acceleration is constant, can be found using the formula `v = u + at`, where `v` is the final velocity, `u` is the initial velocity, `a` is the acceleration, and `t` is the time taken.
Initially, the paratrooper is falling downward at a speed of 30.3 m/s, and after the parachute opens, the upward acceleration is 69 m/s². Therefore, the net acceleration is given by:
Net acceleration = upward acceleration - downward acceleration= 69 - 9.81= 59.19 m/s²
The time taken to reduce the speed to 5.25 m/s can be found by substituting the values into the above formula as shown below:5.25 = 30.3 + 59.19t⇒ t = (5.25 - 30.3)/59.19≈ -0.421 s
Since the time can't be negative, the above estimate is invalid.
(b) The distance fallen during the time interval can be found using the formula `s = ut + 1/2 at²`. If the acceleration is not constant, an easy estimate can be obtained by taking the average of the initial and final speeds, and multiplying by the time taken, which is approximately the same as the actual distance fallen.
The average speed is given by:(30.3 + 5.25)/2 = 17.78 m/s
Therefore, the approximate distance fallen is:s ≈ ut = 17.78 × t
(a), the time taken to reduce the speed to 5.25 m/s is approximately -0.421 s, which can be disregarded since time can't be negative.
Therefore, the actual time taken is:5.25 = 30.3 + at⇒ t = (5.25 - 30.3)/a= 1.435 sSubstituting this into the above formula, the actual distance fallen is:s = 17.78 × 1.435≈ 25.50 m
Therefore, the paratrooper falls a distance of approximately 25.50 m during this time interval.
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you slide a slab of dielectric between the plates of a parallel-plate capacitor while keeping the charges on the plates constant. what happens to v, the potential difference between the two plates, and u, the potential energy of the capacitor?
Answers
Decrease in potential difference causes decrease in potential energy.
A dielectric produces an internal electric field when it is exposed to an electric field because the dielectric is polarized. The potential difference between the plates is caused by the internal electric field within the dielectric, which is in the opposite direction of the field between the plates of the capacitor. As a result, the effective electric field between the plates of the capacitor diminishes.
E = ΔV/Δr
Where, Δr = distance between plates, which is constant
Potential energy of a capacitor is;
U = (1/2)qΔV
Where, Charge is constant .
Therefore, potential energy U likewise drops as a result of the potential difference V being smaller.
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if the same amount of sunlight is hitting an area of land and an are of water, which area would heat more rapidly
Answers
Water would heat more rapidly than land. The area of water on the land would heat more rapidly.
At the point when the sun is radiating on both an area of land and an area of water, the land will warm up quicker. This is on the grounds that land has a lower capacity to store heat contrasted with water. Consider it like this, when you empty high temp water into a container, it warms up quicker contrasted with when you empty it into a pot. The pot has a higher capacity to store heat, so it requires additional significant investment to warm up, yet it likewise remains warm for a more extended time frame.
The equivalent goes for the sun radiating ashore and water. The land warms up rapidly in light of the fact that it has a lower capacity to store heat, while the water takes more time to warm up however holds heat for a more extended timeframe. Thus, if you need to heat up rapidly on a bright day, it's ideal to track down a decent fix of grass or sand as opposed to hopping into a lake or sea.
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Position vs Time
Which statements describe the motion of the object
represented by the graph? Select three options.
12
10
8
Position (m)
The object is moving away from the origin.
The object is moving towards the origin.
The object started at the origin.
The object started at 2 meters.
The object is traveling at a constant velocity.
on
6 4
.
N
2
0
1
4
ch
2. 3
Time (s)
5
Answers
Answer:
1. the object is moving away from the origin.
4. the object started at 2 meters.
5. the object is traveling at a constant velocity.
Explanation:
did it on edge
A 30 ohm resistor and a 20 ohm resistor are
connected in series with a 100 volt battery. What is
the electrical current that would pass through the
30 ohm resistor?
Answers
The current that would pass through the 30 ohms resistor is 2 A.
What is electric current?Electric current is the rate of flow of electric charge round a conductor.
To calculate the electric current that would pass through the 30 ohms resistor, we use the formula below
Formula:
I = V/Rt........... Equation 1Where:
I = Electric current passing through the 30 ohms resistorV = VoltageRt = Total or effective resistance of the resistors.From the question,
Given:
V = 100 voltsRt = (30+20) ohms (since both resistors are connected in series)Rt = 50 ohmsSubstitute these values into equation 1
I = 100/50I = 2 AHence, The current that would pass through the 30 ohms resistor is 2 A.
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Urgent! Which is not an example of work? Question 2 options: pushing a box across the floor picking up a box off the floor raising a barbell over your head trying to push a rock that never moves
Answers
Answer:
trying to push a rock that never moves
Explanation:
The small capillaries in the lungs are in close contact with the alveoli. A red blood cell takes up oxygen during the 0. 75 s that it squeezes through a capillary at the surface of an alveolus. What is the diffusion time for oxygen across the 2. 0- μm -thick membrane separating air from blood? Assume that the diffusion coefficient for oxygen in tissue is 1. 1×10−11m2/s?
Answers
The diffusion time for oxygen across the 2.0-μm-thick membrane separating air from blood is approximately 3.64 × 10^-5 s.
The Oxygen Diffusion Time.The diffusion time for oxygen across the 2.0-μm-thick membrane can be calculated using Fick's law of diffusion:
J = -D * (ΔC/Δx)
Where:
J = rate of diffusion
D = diffusion coefficient
ΔC/Δx = concentration gradient
Assuming that the concentration gradient across the membrane is constant, we can simplify the equation to:
t = x^2 / (2D)
Where:
t = diffusion time
x = thickness of the membrane
Substituting the given values:
t = (2.0 × 10^-6 m)^2 / (2 × 1.1 × 10^-11 m^2/s)
t = 3.64 × 10^-5 s
Therefore, the diffusion time for oxygen across the 2.0-μm-thick membrane separating air from blood is approximately 3.64 × 10^-5 s.
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how does wood and plastic relate to forces
Answers
Answer:
There are six kinds of forces that act on objects when they come into contact with one another: Normal force, applied force, frictional force, tension force, spring force and resisting force. These forces make objects change their motion or movement , the act of going from one place to another.
What is the frequency of an electromagnetic wave having a wavelength of 300 000 km.
Answers
Answer:
below
Explanation:
300 000 km = 300 000 000 m
c = wl * f
3 x 10^8 = 300 000 000 m * f
1 hz = f
A ball of mass 0.25 kg falls from a height of 50 m. Using energy
considerations, find the final velocity. Let g = 9.8 m/s
A . 2.97 m/s
B . 21.0 m/s
C . 33.3 m/s
D . 44.1 m/s
Answers
Therefore, the velocity of the ball just before it hits the ground is approximately 22.1 m/s. Therefore, the closest value to this option is 21.0 m/s.
When a ball of mass 0.25 kg falls from a height of 50 m, we can calculate its velocity using the principle of conservation of energy. According to this principle, the sum of the potential and kinetic energy of an object remains constant.
Therefore, we can equate the potential energy at the initial height to the kinetic energy at the final velocity.Let's calculate the potential energy of the ball at the initial height
:Eg = mghEg = 0.25 kg × 9.81 m/s² × 50 m
Eg = 122.625 J
This is the energy that the ball has due to its position. As it falls, this energy is transformed into kinetic energy. At the moment the ball reaches the ground, all the potential energy has been transformed into kinetic energy
.Ek = 1/2mv²Ek = Egv² = 2Ek/mv = √(2Ek/m)
Let's plug in the values we obtained:Eg = 122.625 Jm = 0.25 kgv = √(2Ek/m)
We obtain:v = √(2 × 122.625 J / 0.25 kg)v = √(245.25 J/kg)v = 22.116 m/s
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What's Alpha beta gamma emission??
Answers
A wave with a frequency of 10 Hz and wavelength of 12m has what velocity?
The equations you will need:
v = λ x f λ=v/f f=v/λ
Answers
Answer:
120
Explanation:
lambda = 12
f=10
10×12=120
Which of these actions is an example of chemical weathering? A. Freezing water widens the cracks in rocks B. plant roots force their way into cracks and rocks and brake them C. oxygen an area eggs with our content in rocks causing them to change color D. strong winds peel soft rock away leaving hard rock behind
Answers
Answer:
A. freezing water widens the cracks in rocks
Explanation:
chemical weathering (from what i can tell anyways) is when water comes in contact with rocks and over time wears it down.
The distance a toy car travels over time is shown in the graph.
Motion of a Toy Car
Distance (m)
Time (1)
Which table best shows the average speed of the toy car at different time intervals?
А
Time (s)
Time (5)
Average
Speed (m/s)
1.0
Average
Speed (m/s)
2.0
0-2
0-2
2-4
0.5
2-4
3.0
4-6
0
4-6
3.0
Time (s)
Average
Speed (m/s)
Time (s)
Average
Speed (m/s)
0-2
2.0
1.0
2-4
0.75
2-4
0.75
4-6
0.75
4-6
0
Answers
Answer:
a toy car speed is about 2.5 to 3.5 mph
An object falls for 2 seconds after being dropped from rest. Its velocity is:
Answers
Answer:
V = 19.62 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics:
\(v=v_{o} +(g*t)\)
where:
V = final velocity [m/s]
Vo = initial velocity = 0
g = gravity acceleration = 9.81 [m/s²]
t = time = 2 [s]
V = 0 + (9.81*2)
V = 19.62 [m/s]
you weigh 500n,what stops you from falling to the center of the earth
Answers
Answer:
bedrock?
Explanation:
The ground is in the way.
When do sea breezes occur
Answers
An object of mass m is acted upon by a net force F and experiences an acceleration of a. The same object is then acted upon by a net force of ½ F. What is the resulting acceleration in terms of a?
a. a
b. 2a
c. ½ a
d. ¼ a
Answers
Answer:
heyyyy
Explanation:
sorry i need points
Is this conversion correct?
11.3g/ cm^3 to kg/ m^3
Since 1000 g = 1 kg and 100 cm = 1 m
Therefore, (11.3 x 1000)/ 100
= 113 kg/ m^3
Answers
11.3 g/cm³ equals to 1130 kg/m³.
What is density?The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol ρ, however Latin letter D may also be used. Density is calculated mathematically by dividing mass by volume.
Given that 11.3 g/cm³.
Know that
1000 grams = 1 kg
1 grams = 1/1000 kg.
100 cm = 1 m
1 cm = 1/100 m.
Therefore, 1 cm³ = (1/100)³ m³
= 1/1000000 m³
Hence, 1 g/cm³ = (1/1000) ÷ (1/1000000) kg/m³
= 1000000/1000 kg/m³
= 1000 kg/m³.
Hence, 11.3 g/cm³ = (11.3 × 1000) kg/m³
= 1130 kg/m³
Hence, 11.3 g/cm³ equals to 1130 kg/m³.
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If a car accelerates from 0 m/s to 120 m/s in 6 seconds, what is the acceleration of the car?
Answers
Answer:
20 m/second squared
Explanation:
Initial velocity of the car (u) = 0 m/s
Final Velocity of the car (v) = 120 m/s
Time (t) = 6 seconds
\(Acceleration \: of \: the \: car = \frac{v - u}{t} \\ \\ = \frac{120 - 0}{6} \\ \\ = \frac{120}{6} \\ \\ = 20 \: m {s}^{ - 2} \)
u= 0m/s
v= 120 m/s
t= 6s
v=u+at
120 = 0 + 6a
120 = 6a
Dividing both sides by 6
We get,
a= 20 m/s^2
Hope this helps you!