An Olympic sprinter runs two laps around an 800 m circular track in 5 minutes.
What is the sprinter's displacement after she returns to her initial position?
O
O
O
0m
800 m
160 m
1,600 m

The engines of a 1,000 kg car have to produce a force of 4,000N to accelerate at a rate of 4 m/s2 while experiencing 300N of drag force.

This can be calculated using the formula:

Fnet = Fengines - Fdrag = m * a

Where Fnet is the net force, Fengines is the force produced by the engines, Fdrag is the drag force, m is the mass of the car, and a is the acceleration.

Plugging in the known values, we get:

Fengines = m * a + Fdrag = 1000 kg * 4 m/s2 + 300 N = 4000 N

Therefore, the engines of the 1,000 kg car will produce of a force of 4000 N and drag of 300N.

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Answer:

B

Explanation:

In most situations, the strong correlation usually ranges between 0.7 to 0.9. So 0.5 is not a strong correlation.

Correlation is an important concept in statics. This helps to associate the relationship between two variables. This is of two types namely positive correlation and negative correlation.

In a positive correlation, the association of two variables occurs in the same way. That is they both decrease or increase. In a negative correlation, the association of one variable occurs oppositely to another variable. That is, when one variable decreases, another variable increases.

This correlation is represented by the symbol r. This r-value range from +1 to -1. So the perfect positive correlation is +1 and the perfect negative correlation is -1.

In, the positive correlation, the values from 0.1 to 0.3 is considered weak or low correlation. The values from 0.4 to 0.6 are considered a moderate correlation and the values from 0.7 to 0.9 are considered a strong correlation.

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By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.

First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:

S = ut + ½gt²

49 = 0(t) + ½ × 9.8 × t²

49 = 4.9t²

t² = 49/4.9

t = √10

t = 3.16 seconds.

Now, we can determine the speed at which he threw the second stone:

Note: Time = 3.16 - 1 = 2.16 seconds.

S = ut + ½gt²

49 = u(2.16) + ½ × 9.8 × 2.16²

49 = 2.16u + 22.86

2.16u = 49 - 22.86

u = 26.14/2.16

u = 12.10 m/s.

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The average emf induced in the coil is 0. 533 V. The average emf induced in the coil can be calculated using Faraday's law of electromagnetic induction. The formula for the average emf induced in a coil is given by:

E = N * (ΔΦ / Δt)

where E is the average emf, N is the number of turns in the coil, ΔΦ is the change in magnetic flux, and Δt is the time interval.

In this case, the number of turns is 80, and the time interval is 0.0600 s. The change in magnetic flux can be calculated by finding the initial and final flux values.

The initial flux is given by Φ1 = B * A * cos(θ1), where B is the magnetic field, A is the area of the coil, and θ1 is the angle between the coil and the magnetic field.

The final flux is given by Φ2 = B * A * cos(θ2), where θ2 is 90 degrees since the coil is perpendicular to the field.

Substituting the values into the formula, we have:

\(E = 80 * (Φ2 - Φ1) / Δt\)

Calculating the values, we find:

\(Φ1 = (1.10 T) * (0.25 m) * (0.40 m) * cos(37.0°) = 0.536 WbΦ2 = (1.10 T) * (0.25 m) * (0.40 m) * cos(90°) = 0.110 WbΔΦ = Φ2 - Φ1 = 0.110 Wb - 0.536 Wb = -0.426 Wb\)

Substituting the values into the formula, we get:

E = 80 * (-0.426 Wb) / 0.0600 s = -0.568 V

Taking the absolute value, the average emf induced in the coil is 0.568 V or approximately 0.533 V.

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Answer:

490.5N

Explanation:

Step one:

given data

We are told that the mass is 50kg

m= 50kg

From Isaac Newton's first law of motion

F=ma

assuming a= 9.81m/s^2

Substituting we have

F=50*9.81

F= 490.5N

Hence the minimum force required to move the slab is

490.5N

Answer:

 θ = 73.6º

Explanation:

To solve this exercise, let's use Newton's second law. Let's set a reference system where the x-axis is parallel to the inclined plane

with trigonometry we can find the components of the weight

           sin θ = Wₓ / W

           cos θ= W_y / W

           Wₓ = W sin θ

           W_ = W cos θ

Y axis  

           N - W_y = 0

           N = W_y

X axis

           Wₓ - fr = m a

            mg cos θ - fr = m a

indicate that friction is zero, fr = 0

            cos θ = a / g

            θ = cos⁻¹  \(\frac{a}{g}\)

let's calculate

            θ = cos⁻¹  \(\frac{2.77}{9.8}\)

            θ = 73.6º

First, let

f = mag. of static friction

n = mag. of normal force

w = m g = mag. of gravitational force (the weight of the block)

m = mass of the block

g = 9.80 m/s² (the mag. of the acceleration due to gravity)

a = acceleration of the block

It's the static friction that interests us at the moment "when it begins to slide", meaning the precise moment at which static friction is at its maximum. At that point, the friction has magnitude f such that

f = 0.5 n

The problem is much easier to work through if you split up the forces into components acting parallel and perpendicular to the ramp. By Newton's second law, we have

• the net force acting parallel to the ramp is

∑ F = - f + w sin(30°) = m a

• and the net force acting perpendicular to the ramp is

∑ F = n - w cos(30°) = 0

Hence the net force on the block as it begins to slide acts only in the parallel direction. Note that we take the positive parallel direction to be the one in which the block slides down the ramp (i.e. opposing the friction force), and the positive perpendicular direction to be the same as the normal force.

Solve the second equation for n :

n = m g cos(30°) = (100 kg) (9.80 m/s²) cos(30°) ≈ 849 N

Then

f = 0.5 (849 N) ≈ 424 N

and so the net force on the block is

∑ F ≈ - 424 N + (100 kg) (9.80 m/s²) sin(30°) ≈ 65.6 N

Next, you want to find the acceleration of the block as it is sliding down the ramp, during which time kinetic friction kicks in. We have the same equations as above, except now f = 0.3 n. So we still have n ≈ 849 N, which gives

f = 0.3 (849 N) ≈ 255 N

∑ F = - f + w sin(30°) = m a

→   - 255 N + (100 kg) (9.80 m/s²) sin(30°) ≈ (100 kg) a

→   a ≈ 2.35 m/s²

Using everyday objects like a paperclip or a cent, monitoring the development of droplets, or using a soap bubble, one can illustrate surface tension at home or in the lab.

With a force tensiometer and a Du Noüy ring or Wilhelmy plate, surface tension can be detected. Or you might use an optical tensiometer and the pendant drop technique.

A stalagmometer is a device used to calculate surface tension using the stalagmometric method. . A stactometer or stalogometer is another name for it. A hygrometer is a type of weather instrument used to gauge the humidity level in the air.

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This relationship between amplitude and energy holds true for many types of waves, including mechanical waves and electromagnetic waves. Increasing the amplitude of a wave corresponds to an increase in the magnitude of its oscillations or fluctuations, which in turn leads to higher energy content.

If you double the amplitude of a wave, the energy of the wave increases by a factor of four. The energy of a wave is directly proportional to the square of its amplitude. Doubling the amplitude means multiplying it by a factor of 2. Since energy is proportional to the square of the amplitude, doubling the amplitude results in an energy increase of (2^2) = 4 times the original energy. Therefore, when you double the amplitude of a wave, the energy of the wave increases by a factor of four.

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Answer:

Thus 1 Ampere is the current is defined as flow of 1 coulomb charge through a conductor in 1 second.

Explanation:

Hope it helps

When a boxer is moving away from a punch, the force experienced is reduced because C) increased.

The force created when things collide is known as the force of impact. The impact or hitting power of your vehicle increases as you increase your speed. The force of impact rises with the square of the increase in speed, according to the rules of physics.

When you throw a punch, you'll apply force to the target by using the momentum that was built during the action and the addition of the snap. This results in impulse (force x time). You may transfer a lot of impulse to the target area and build momentum if you do so.

Therefore, option C is correct.

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missing options

A) no different, but the timing is different

B) decreased

C) increased

D) all of the above

Answer:

12761

Explanation:

The rotational kinetic energy of the earth is 2.587 × 10²⁹ J

The rotational kinetic energy of the earth is given by K = 1/2Iω² where I = rotational inertia of earth = 2MR²/5 where M = mass of earth = 5.972 1× 0²⁴ kg and R = radius of earth = 6.4 × 10⁶ m. ω = angular speed of earth = 2π/T where T = period of earth = 24 hours = 24 × 60 ×  60 = 86400 s = 8.64 × 10⁴ s

So, K = 1/2Iω²  

K = 1/2 × 2MR²/5 × (2π/T)²  

K = 4π²MR²/5T²  

Substituting the values of the variables into the equation, we have

K = 4π²MR²/5T²

K = 4π² × 5.972 × 10²⁴ kg × (6.4 × 10⁶ m)²/[5(8.64 × 10⁴ s)²]  

K = 4π² × 5.972 × 10²⁴ kg × 40.96 × 10¹² m²/[5(74.6496 × 10⁸ s)²]  

K = 4π² × 244.61312 × 10³⁶ kgm²/373.248 × 10⁸ s²  

K = 9656.93890286 × 10³⁶ kgm²/373.248 × 10⁸ s²  

K = 25.87 × 10²⁸ kgm²/s²

K = 2.587 × 10²⁹ J

So, the rotational kinetic energy of the earth is 2.587 × 10²⁹ J

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Answer:

False

Explanation:

It is actually I = V/R and V = I × R

The acceleration of the object is 5.3 cm/\(s^{2}\) and is directed towards the negative x - axis.

We have an object moving with uniform acceleration along the + x axis.

We have to determine of the acceleration of object after 3.25 seconds.

According to the question -

initial velocity = u = 11 cm/s along +x axis.

Now, using the second equation of motion -

\($S=ut +\frac{1}{2}at^{2}\)

S = x(2) - x(1) = - 5 - 2.91 = - 7.91 = 7.91 cm along -x axis.

u = 11 cm/s

Substituting the values -

7.91 = 11 x 3.25 + 0.5 x 3.25 x 3.25  x a

7.91 = 35.75 + 5.3a

a = - 5.3 cm/\(s^{2}\)

Hence, the acceleration of the object is 5.3 cm/\(s^{2}\) and is directed towards the negative x - axis.

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The potential difference between the battery's terminals, which is produced by the chemical reactions inside the battery, causes the flow of electrons and produces electrical energy.

A battery generates electrical energy by creating a potential difference in electric charge between its negative terminal and its positive terminal.

This potential difference, also known as voltage, creates an electric field that causes electrons to flow from the negative terminal, through the circuit, to the positive terminal.

As the electrons flow, they create a current that can be used to power electronic devices or perform other useful work. The chemical reactions that occur within the battery create the potential difference between its terminals, which drives the flow of electrons and generates electrical energy.

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B. The only option that could NOT have been the car’s displacement is 1,900 m west.

The displacement of an object is the change in the position of an object.

The displacement of the car is calculated as follows;

Δx = vt

where;

Δx = 23 x 82

Δx = 1,886 m

Since displacement is all about shortest distance traveled by an object, the only option that could NOT have been the car’s displacement is 1,900 m west.

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Answer:

the image can be rather real or virtual

Answer:If a hole is dug into the ground deep enough that it reaches a confined aquifer, the pressure can be great enough to shoot water up the well without any help from a pump. Such a well is called a flowing artesian well

Explanation:

The cannon, which has a mass of 2020 kg and discharges a ball weighing 20 kg horizontally, moves at a speed of 1.27 m/s right after the shot. Following its exit from the barrel, the cannonball moves at a speed of 139 m/s.

m1: Cannon mass, 2260 kg

v1 denotes the cannon's speed.

the ball's velocity is 105 m/s, and its mass is 21 kg.

We have m1v1=m2v2, v1=20*139/2020, and v1=1.27 m/s due to the system's preserved momentum.

The cannon travels at 1.27 meters per second.

Add together the individual momentums of the two objects in a collision to get the total momentum. If p represents momentum, m is mass, and v is velocity, then the equation p=mv can be used to calculate a method for calculating the individual objects' respective velocities.

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The total energy of the gas is increased by 57.27 kJ and is 3407.27 kJ at the end of the process.

Given that pressure, P1 = 5 MPa; Initial volume, V1 = 123 in³ = 0.002013 m³; Final volume, V2 = 456 ft³ = 12.91 m³; Heat transferred, Q = 789 kJ.

We need to calculate the total energy of the gas, ΔU and determine if it is increased or not. The change in internal energy is given by ΔU = Q - W where W = PΔV = P2V2 - P1V1

Here, final pressure, P2 = P1 = 5 MPa

W = 5 × 10^6 (12.91 - 0.002013)

= 64.54 × 10^6 J

= 64.54 MJ

= 64.54 × 10^3 kJ

ΔU = Q - W = 789 - 64.54 = 724.46 kJ.

The total energy of the gas is increased by 57.27 kJ and is 3407.27 kJ at the end of the process.

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The plane's speed is 450 miles per hour, and the wind speed is 50 miles per hour. This is determined by solving the equations derived from the distances and times of the flight with and against the wind.

Let's assume the speed of the plane (without considering the wind) is P, and the speed of the wind is W.

When flying into a headwind, the effective speed of the plane is reduced by the wind speed. So the equation for the outbound flight is:

P - W = 2000 miles / 5 hours

P - W = 400 miles per hour (mph)  ---(Equation 1)

When flying with a tailwind, the effective speed of the plane is increased by the wind speed. So the equation for the return flight is:

P + W = 2000 miles / 4 hours

P + W = 500 miles per hour (mph)  ---(Equation 2)

Now we have a system of two equations (Equation 1 and Equation 2) with two variables (P and W). We can solve this system to find the values of P and W.

Adding Equation 1 and Equation 2 together, we eliminate the variable W:

(P - W) + (P + W) = 400 mph + 500 mph

2P = 900 mph

P = 450 mph

Substituting the value of P back into Equation 1 or Equation 2, we can solve for W:

450 mph - W = 400 mph

W = 450 mph - 400 mph

W = 50 mph

Therefore, the plane's speed is 450 mph and the wind speed is 50 mph.

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Answer:

over weight

Explanation:

being over weight

hope this helps

If a fish looks upward at 45 degrees with respect to the water's surface, it will see option a, the sky and possibly some hills.

When a fish looks upward at a 45-degree angle with respect to the water's surface, it will see the sky and possibly some hills. This is because light rays refract when they pass from one medium to another with different optical densities.

As light travels from air to water, it slows down, and its path bends towards the normal, which is perpendicular to the water's surface. This bending of light is called refraction. When the fish looks upwards, it sees the light that has been refracted by the water, and this light carries information about the sky and the surrounding landscape.

However, the amount of refraction depends on the angle of incidence of the light ray, so the fish will not see the entire sky but only a portion of it. At a 45-degree angle, the fish will see a wider view of the sky and possibly some hills, depending on the surrounding topography. Therefore, the fish will not see the bottom of the pond, which is below its line of sight.

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Given data

*The given storm cloud has a charge is q = +0.35 C

*The tree gains a charge is Q = -0.02 C

*The distance between them is r = 150 m

*The value of the Coulomb's constant is k = 9 × 10^9 N.m^2/C^2

The formula for the amount of force between the cloud and the tree is given as

Substitute the known values in the above expression as

Here the negative sign indicates that the charges are attractive in nature.

Hence, the amount of force between the cloud and the tree is F = -2.8 × 10^3 N

An alien spacecraft is cruising along at 5000 km/s. Suddenly the late Leonard Nimoy appears 25,000 km in front of the spacecraft, the decelerate (in km/s/s ) to avoid hitting Mr. Nimoy at 6250 km/s/s.

If it decelerates at a slower rate, it will hit Mr. Nimoy before it can come to a stop. Given that the alien spacecraft is cruising at 5000 km/s and suddenly, Leonard Nimoy appears 25,000 km in front of the spacecraft. To avoid hitting Leonard Nimoy, the spacecraft must come to a complete stop before it reaches him. The time it takes the spacecraft to stop can be determined by dividing the distance by the velocity of the spacecraft.

Time taken to stop = 25,000 km / 5000 km/s = 5 seconds.

The deceleration required to achieve this can be calculated by dividing the velocity by the time taken to stop.

Deceleration = 5000 km/s / 5 s = 1000 km/s/s.

Therefore, the alien spacecraft must decelerate at 6250 km/s/s to avoid hitting Mr. Nimoy.

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Answer:

i) 20-30 kg

Explanation:

The child with the smallest mass range of 20-30 kg will require the smallest force to move his skate board because he/she has a smaller inertia force to overcome. The mass of a body is the measure of the inertia forces of the body. The inertia force makes it difficult for a body at rest to start moving, and a body already in motion to stop moving.

When the children try to move the skateboard, they exert a force that is proportional to the product of their mass and the acceleration with which they start moving. This force must exceed their body's inertia force before they would start moving.

from

F = ma

where F is the force required

m is the mass

a is the acceleration

We can see that for the given mass ranges, the children with the larger mass range will require more force in order to move their skateboard. Consequently, the child with the smallest mass range will require the smallest pushing force to move his skate board.