Answer:
b 43 kg
Explanation:
mass doesn't differ from place to place.
but the weight may
irst, you must find the wavelength of the laser. you shine the laser into the interferometer and then move one of the mirrors until you have counted 100.0 fringes passing the crosshairs of the telescope. the extremely accurate micrometer shows that you have moved the mirror by 0.03164 millimeters. what is the wavelength λλlambda of the laser?
In conclusion, to find the wavelength of the laser, we measured the displacement of the mirror and calculated the fringe spacing. By multiplying the fringe spacing by 2, we determined the wavelength of the laser to be 0.0003164 mm (or 316.4 nm).
To find the wavelength (λ) of the laser, we can use the given information. When you shine the laser into the interferometer and move one of the mirrors, you observe 100.0 fringes passing the crosshairs of the telescope. By measuring the displacement of the mirror using the accurate micrometer (0.03164 millimeters), we can determine the wavelength of the laser.
Here's how we can calculate it:
1. Recall that the distance between two adjacent fringes is equal to half the wavelength of the laser. So, if we count 100 fringes passing the crosshairs, we've actually observed 200 fringe spacings.
2. Divide the displacement of the mirror (0.03164 mm) by the number of fringe spacings observed (200) to get the fringe spacing (δ).
δ = 0.03164 mm / 200 = 0.0001582 mm
3. Finally, multiply the fringe spacing (δ) by 2 to get the wavelength of the laser (λ).
λ = 2 * δ = 2 * 0.0001582 mm
To convert the wavelength from millimeters to meters, you can divide by 1000:
λ = 2 * 0.0001582 mm / 1000 = 0.0003164 mm
Therefore, the wavelength of the laser is 0.0003164 mm (or 316.4 nm).
In conclusion, to find the wavelength of the laser, we measured the displacement of the mirror and calculated the fringe spacing. By multiplying the fringe spacing by 2, we determined the wavelength of the laser to be 0.0003164 mm (or 316.4 nm).
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Show your work: zero credit for this question. pieces and the lengths are 49.19 cm and 49.93 cm. What is the total Taguchi quality cost of these two pieces of metal? a) The Taguchi parameter T is $/cm^2
(round your response to two decimal places). b) The Taguchi Quality Cost of the second metal rod is $ (round your response to two decimal places). c) The Taguchi Quality Cost of the first metal rod is $ (round your response to two decimal places). d) What is the total Taguchi Quality Cost of that sample of two units? \$ (round your response to two decimal places).
To calculate the Taguchi quality cost, we need to multiply the length of each piece by the Taguchi parameter T, and then sum up the costs.
Given:
Length of the first metal rod = 49.19 cm
Length of the second metal rod = 49.93 cm
a) Taguchi parameter T:
Since we don't have the specific value of T, we cannot calculate it.
b) Taguchi Quality Cost of the second metal rod:
Taguchi Quality Cost = Length of the second metal rod * Taguchi parameter T
c) Taguchi Quality Cost of the first metal rod:
Taguchi Quality Cost = Length of the first metal rod * Taguchi parameter T
d) Total Taguchi Quality Cost of the two units:
Total Taguchi Quality Cost = Taguchi Quality Cost of the first metal rod + Taguchi Quality Cost of the second metal rod
Since we don't have the Taguchi parameter T, we cannot calculate the specific values for parts (b), (c), and (d).
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PLEASE HELP!
Name two elements that have the Lewis dot diagram shown in the image.
Answer:
Nitrogen and Phosphorus
Explanation:
Generally as we know, the lewis dot diagrams for elements use the number of valence electrons that the element has
From the diagram above, we can see that the element in question has 5 valence electrons
so therefore, we need two elements with 5 valence electrons
These are elements are nitrogen (2,5) and phosphorus (2,8,5)
The linear expansivity of a metal p Is twice that of metal q. When these metals are heated through the same temperature, their increase in length is the same. Calculate the ratio of the original length of p to that of q
Answer:0-------0
do we have options?
Explanation:
A jogger whose mass is 60 KG is moving at a speed of 3m/s what is his kinetic energy
Which of these is the shortest distance?
A. 713 parsec
B. 0.0001337 megaparsec
C.42 light years
D. 525600 AU
E. 1 x 10^15 km
In astronomy, parsecs are used to measure vast distances. It is defined as the distance at which an object would have a parallax angle of one arcsecond when seen from opposite ends of the Earth's orbit.
The shortest distance among the given options is B. 0.0001337 megaparsec.
Parsec (pc) is a unit of length commonly used in astronomy. It is defined as the distance at which an object would have a parallax angle of one arcsecond when observed from opposite ends of the Earth's orbit. Megaparsec (Mpc) is a million parsecs, and it is used to measure vast distances in the universe. Light-year (ly) is the distance that light travels in one year, and astronomical unit (AU) is the average distance between the Earth and the Sun.
To determine the shortest distance, we need to convert all the given units into a common unit. Let's convert them into kiloparsecs (kpc) for comparison.
A. 713 parsec = 713 kpc
B. 0.0001337 megaparsec = \(0.0001337 x 10^6 kpc\) = 0.1337 kpc
C. 42 light-years = 42 x 0.3066 kpc = 12.868 kpc (using 1 ly = 0.3066 kpc)
D. 525600 AU = \(525600 x 4.84814 x 10^-^6 kpc = 2.542 kpc (using 1 AU = 4.84814 x 10^-^6 kpc)\)
E. \(1 x 10^1^5 km = 1 x 10^1^5 x 3.24078 x 10^-^1^4 kpc\) = 32.4078 kpc (using 1 km = \(3.24078 x 10^-^1^4 kpc\))
Comparing the values, we find that the shortest distance is 0.1337 kpc (option B).
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A student shakes a rope such that 36 complete vibrations are
made in 9.00 seconds. determine the vibrational period of
the rope, along with the corresponding unit.
The vibrational period of the rope, when a student shakes it is 0.25 s.
What is the frequency?Frequency is the number of oscillations per second.
Given is the number of vibrations =36 in time t = 9s, then frequency will be
f = 36/9 =4Hz
The time period is the reciprocal of the frequency.
T = 1/f
Plug the frequency value, we get
T = 1/4 Hz = 0.25 seconds
Thus, the vibrational time period is 0.25s.
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What happens to the capacitance of a parallel plate capacitor when it is connected to a battery and dielectric is inserted?
(pls help fast it's urgent)
Answer:
After the dielectric is inserted the capacitance is increased hence the stored energy is also increased . It may be noted here that since voltage between the capacitor V0 is constant the electric field between the plates also remains constant .
The attaction between magnets is a chemical property.
True
Or
False
Answer:
false its an attraction property
Answer:
True
The attraction is a chemical property.
You are at a circus and you see a stunt man climb up 29.4 meters into a cannon. He gets fired horizontally out of the cannon with a speed of 57.1 m/s.
How long was stunt man in the air for? Round your answer with TWO decimal places. *Correct rounding rules apply
Answer:2.45 s rounded
Explanation:
29.4m=1/2(-9.8)t^2
29.4/-4.9=6
√6= 2.44> rounded> 2.45 s
Your car battery is a 12 V DC source. Typically you might find a fuse that can handle a 5 amp surge. What resistance is that fuse protecting?
Answer:
2.4 ohms
Explanation:
From the question,
Applying ohm's law,
V = IR.................... Equation 1
Where V = Voltage of the car battery, I = current, R = resistance
Make R the subject of the equation
R = V/I.................. Equation 2
Given: V = 12 V, I = 5 amp.
Substitute these values into equation 2
R = 12/5
R = 2.4 ohms
A 4. 0 nc positive point charge is located at point a in the figure. (figure 1) what is the electric potential at point b?.
The electric potential at point b experienced by the charge cab be determined using the formulas given.
Electric potentialThe electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.
V = Ed
V = (F/q)d
V = (Fd)/q
where;
V is the electric potentialF is electric forceE is the electric fieldq is the chargeThus, the electric potential at point b experienced by the charge cab be determined using the formulas given.
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7.) A neutral atom loses two electrons. Which of the following ions might result? HELP ME ASAP!!!
Answer:
A. Mg+2
Explanation:
im not sure, but since it lost two electrons which have a negative charge it gained two charge.
IIIIIII-PLEASE HELP-IIIIII THERE ARE TWO QUESTIONS (ILL GIVE BRAINLIST)
Answer:
the answers should be B and D
Answer:
Q. 1 is transform
Q. 2 is plates move past each other sideways
Explanation:
A child is swinging back and forth on a tire swing that is attached to a tree branch by a single rope. Shown are two positions during a swing from right to left. Three students are discussing the tension in the rope at the bottom of the swing.
Alia:
“At the bottom of the swing, she will be moving exactly horizontally. Since she is not moving vertically at that instant, the vertical forces cancel. The tension in the rope at that instant equals the weight.”
Brian:
“Just looking at the velocity vectors, the change in velocity points upward between A and B. So that is the direction of the acceleration, and also of the net force. To get a net force pointing upward, the tension would have to be greater than the weight.”
Clara: “But there aren’t just two forces acting on her at the bottom of the swing. Since she’s moving in a circle, there’s also the centripetal force, which acts toward the center of the circle. Since both the tension and the centripetal force point upward, and the weight points downward, to get zero net force the tension actually has to be less than the weight. The tension plus the centripetal force equals the weight.”
With which, if any, of these students do you agree?
Clara gave agreeable reason of swinging back and forth of the boy on the tire.
What is centripetal force?According to the definition of centripetal force, this force is applied to an object moving curvilinearly and is targeted at the axis of rotation or the center of curvature. Newtons are used to measure centripetal force.
Since she is being affected by more than two forces at the bottom of the swing, There is also the centripetal force, which acts in the direction of the circle's center because she is rotating in a circle. In order to achieve zero net force, the tension must actually be smaller than the weight because the centripetal force and tension both point upward while the weight points downward. The weight is equal to the tension plus the centripetal force.
Hence, Clara gave agreeable reason.
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The cerebellum is part of the
____?
Explanation:
i think it the central nervous system
question 2what is the major source of competition for motor carrier?2 points
The major sources of competition for motor carriers are: Intermodal transportation, Other motor carriers.
Motor carriers face significant competition from other companies operating in the same industry. These competitors offer similar transportation services, and customers often have the option to choose among different carriers based on factors such as pricing, reliability, service quality, and geographic coverage. Motor carriers must differentiate themselves and provide competitive advantages to attract and retain customers.Intermodal transportation, which involves using multiple modes of transportation (such as combining trucking with rail or sea transport), is a significant source of competition for motor carriers. Intermodal transportation can offer cost savings, efficiency improvements, and environmental benefits, attracting customers who are seeking alternative transportation options. Motor carriers need to adapt to this competition by providing efficient and reliable services or by integrating intermodal capabilities into their own operations to meet customer demands.
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23 and 24 only please help!
Answer:
23: Acceleration 24:1m/s^2
Explanation:
\(a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2\)
You use a rope and pulley system with an ideal mechanical advantage of 2.00. How big of an output load can you lift with an input
force of 200 N?
When two rope segments pull up on the load in the single movable pulley, the optimal mechanical advantage is 2. This sort of pulley does not change the direction of the applied force, but it does increase it by a factor of two.
What is the ideal mechanical advantage?There are two methods for calculating a pulley system's mechanical advantage.
The mechanical advantage may be calculated simply by counting the number of falls (or active lifting ropes) that are really attached to the load. You may also split the effort distance by the load distance.
Assuming an ideal rope and pulley system with a mechanical advantage of \(2.00\) , the output load that can be lifted with an input force of \(200 N\) can be calculated using the formula:
Output force = Input force x Mechanical advantage
Where the mechanical advantage is given as \(2.00\) .
Thus, the output force is:
Output force \(= 200 N \times 2.00 = 400 N\)
Therefore, with an input force of \(200 N\) , the rope and pulley system can lift an output load of up to \(400 N\) .
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Which thymocyte developmental checkpoint tests the functionality of the recombined beta chain of the pre-T cell
receptor (pre-TCR)?
10 pts
nts
Positive selection
Negative selection
Peripheral tolerance in spleen
Beta selection
The thymocyte developmental checkpoint that tests the functionality of the recombined beta chain of the pre-T cell receptor (pre-TCR) is called Beta selection.
During T cell development in the thymus, thymocytes undergo several checkpoints to ensure proper maturation and functionality. Beta selection is one such checkpoint that occurs at the double-negative stage of thymocyte development. At this stage, the recombined beta chain of the pre-TCR is tested for its functionality.
The pre-TCR, composed of the beta chain and a surrogate alpha chain, plays a crucial role in thymocyte development and selection. Beta selection specifically assesses the ability of the recombined beta chain to pair with the surrogate alpha chain and form a functional pre-TCR complex.
If the recombined beta chain is functional and capable of pairing with the surrogate alpha chain, signaling through the pre-TCR occurs, leading to positive selection. Positive selection allows thymocytes with functional pre-TCRs to survive and progress further in development.
On the other hand, if the recombined beta chain is non-functional or unable to properly pair with the surrogate alpha chain, signaling through the pre-TCR does not occur, resulting in negative selection. Thymocytes that fail the beta selection checkpoint are eliminated through apoptosis.
In summary, the beta selection checkpoint in thymocyte development is responsible for testing the functionality of the recombined beta chain of the pre-TCR. It determines whether thymocytes progress through positive selection or undergo negative selection based on the ability of the recombined beta chain to form a functional pre-TCR complex.
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Which of the following is a combustion reaction?
O A. 2503 (9)
->
2502 (9) + 02 (9)
O B. 2Na (s) + Cl2 (9) → 2NaCl (s)
C. C3H8 (g) + 502 (9) — 3C02 (9) + 4H20 (9)
O D. 2KCIO3 (s) — 2KCI (s) + 303 (9)
Answer:
Option C
Explanation:
Hydrocarbon + Oxygen = Carbon dioxide + Water
is example of combustion reaction
Un movil avanza a 20 m/s y recorre una distancia de 800 km. Determinar el tiempo en horas que utiliza
Answer:
t = 11.1 hours
Explanation:
The question says that, "A mobile advances at 20 m / s and travels a distance of 800 km. Determine the time in hours you use".
Given that,
Speed of a mobile, v = 20 m/s = 72 km/h
Distance, d = 800 km
We know that,
Speed = distance/time
So,
\(t=\dfrac{d}{v}\\\\t=\dfrac{800}{72}\\\\t=11.1\ h\)
So, it will take 11.1 hours.
A man who weights 900 N stands on a platform scale in a elevator the elevator has made 4000 kg the reading on the scale is 700 N
Answer:
a = -2.17 m / s²
Explanation:
In this problem you must ask for the acceleration of the elevator.
Let's use Newton's second law
F-W = ma
a =\(\frac{F}{m} - g\) F / m-g
the weight of the body is 900 N and the force is the reading of the scale, let's find the mass
w = mg
m = w / g
m = 900 / 9.8
m = 91.84 kg
let's calculate
a = 700 / 91.84 - 9.8
a = -2.17 m / s²
The negative sign indicates that the elevator is going down
What causes water molecules to be attracted to each other?
Answer:
the positive and negative charges of the hydrogen and oxygen atoms that make up water molecules makes them attracted to each other
Explanation:
Hope this helps dude
How do we represent Earth’s face?
Answer:
Human-driven changes in arrive utilize and arrive cover such as deforestation, urbanization, and shifts in vegetation designs moreover change the climate, coming about in changes to the reflectivity of the Soil surface (albedo), emanations from burning timberlands, urban warm island impacts and changes within the normal water cycle.
The gravitational acceleration on Earth is 9.8 m/s2. What is the weight of a car on Earth (to the nearest whole number) if it has a mass of 1360 kg? 14 N 139 N 1333 N 13,328 N
Weight = (mass) x (gravitational acceleration where the mass is)
Weight = (1360 kg) x (9.8 m/s²)
Weight = 13,328 kg-m/s²
That's 13,328 Newtons
Given:-
Mass (m) of the car = 1360 kgAcceleration due to gravity (g) = 9.8 m/s²To Find: Weight (W).
We know,
W = mg
where,
W = Weight,m = Mass &g = Acceleration due to gravity.Thus,
W = (1360 kg)(9.8 m/s²)
→ W = 13,328 N (D)
A body is in equilibrium under the action of three forces one of the force is 6.0N acting due East and one is 3.0N in a direction 60degrees North east what is the magnitude and direction of the third force
The magnitude of the third force is 7.93 N and South west direction.
Force \( F_{1}\) = 6 N in east direction
Force \( F_{2}\) = 3 N 60 degrees in northeast direction
Three forces are acting on the body. For a body to be in equilibrium the sum of all three forces must be zero.
Net force = \( F_{1}\) + \( F_{2}\) + \( F_{3}\)
Resolving the forces in x and y directions,
\( F_{1x}\) = 6N
\( F_{1x}\) = 0N
\( F_{2y}\) = 3cos(60) = 1.5 N
\( F_{2y}\) = 3sin(60) = 2.59 N
Hence calculating the third force magnitude
\( F_{3x}\) = net F - \( F_{1x}\) - \( F_{2x}\)
\( F_{3x}\) = 0-6-1.5
\( F_{3x}\) = -7.5 N
Similarly
\( F_{3y}\) = net F - \( F_{1y}\) - \( F_{2y}\)
\( F_{3y}\) = 0-0-2.59
\( F_{3y}\) = -2.59 N
Magnitude of resultant
\( F_{3} = \sqrt[ 2 ] {{F_{3x}}^{2} +{F_{3y}}^{2} }\)
\( F_{3} = \sqrt{ { - 7.5}^{2} + { - 2.59}^{2} } \)
\( F_{3}\) = 7.93 N
Since the resultant is the closing vector the direction is south west.
Hence the magnitude and direction if Third force are 7.39 N and Southwest respectively.
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The total amount of carbon dioxide in the atmosphere is estimated to have decreased by 10 to 15 percent since 1900.
True False
Answer: False
Explanation:
The speed of sound in a particular gas is 675 m/s. A sound wave propagating in this material has a wavelength offifteen meters. What is the frequency of this sound?knowns and unknownsolveright answer
Given, Speed of the sound, v=675 m/s
The wavelength of the wave, λ=15 m
Relation between speed, wavelength, and frequency of a wave is given by
\(v=f\lambda\)Where f is the frequency of the sound.
On substituting the known values,
\(675=f\times15\)Which gives us,
\(f=\frac{675}{15}=45\text{ Hz}\)Therefore the frequency of the sound in the given medium is 45 Hz.
the block of mass m in the following figure slides on a frictionless surface
For the right block to balance the forces and remain steady, it needs to weigh 7.9 kg.
The force is an external agent which is applied to the body or an object to move it or displace it from one position to another position.
When there is no net force acting on the system, the two blocks stay in place. In this instance, the strain in the rope holding the two blocks together balances the pull of gravity on them. The sine of the angles, along with the masses of the blocks, can be used to calculate the tension in the rope.
\(T= (m_1 \times g) \times sin(\theta_1) + (m_2\times g) \times sin(\theta_2)\)
Substituting the known values:
\(T = (10 \times 9.8 )\times sin(23^o) + (m_2\times 9.8 )\times sin(40^o)\)
Solving for m₂:
\(m_2= \dfrac{(T- (10 \times 9.8 )\times sin(23^o)} { (9.8\times sin(40^o))}\)
The mass of the right block must be 7.9 kg for the two blocks to remain stationary.
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The question is -
Two blocks in the Figure below are at rest on frictionless surfaces What must be the mass of the right block so that the two blocks remain stationary? 4.9kg 6.1kg 7.9kg 9.8kg