"an object with a mass of 0.20 kg has an acceleration of 5.0 m/s^2 when an unbalanced force of 1.0 n is applied to it" can be explained by newton's second law.

The resulting speed of the 50 kg kid, if was moving with an initial speed of 2 m/s is 0.8 m/s.

Speed is the rate of change of distance.

To calculate the resulting speed of the kid, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solv for v

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Answer:

2/3 Amp

Explanation:

Write the two equations for the two complete loops in the circuit:

Upper loop:   i1 * 1 Ω + 7 V + (i1 - i2) 1 Ω - 6 V= 0

2 i1 - i2 = -1

Lower loop:  (i2 - i1) 1 Ω + 6 V + i2 1 Ω - 3 V = 0

- i1 + 2 i2 = -3

Solve the system of two equations:

i1 = -5/3 Amp

i2 = - 7/3 Amp

Therefore, an amp-meter in the branch of the 6V battery will read the difference between current i1 and i2. That is 2/3 Amp.

Solution :

It is given that the lamp glows brightly for a shorter period of time when the switch is closed on it the switch is put on. But after the some time the lamp goes off and it stops working.

This is because as soon as we on the switch, the current start flowing to the lamp which makes the filament of the lamp to glow, but due to some issue, the current stop flowing even when the switch is on and this stops the lamp from glowing and hence the lamp does not work.

The inverse square relation implies that  force resulting from gravity between two masses will decrease as the square of the distance between the two masses increases.

The force of gravity between any two objects is given by,

F = GM₁M₂/R²

Where,

M₁ and M₂ are the masses of the bodies.

R is the distance between them.

We know, if the masses are constant. then the force of gravity will be inversely proportional to the square of the distance between them.

This is what inverse square relation means here.

As the force of gravity and the square of the distance are inversely proportional to each other,

So, when the square of the distance between the masses increases, the force of gravity between the decreases.

Hence of all the options provided, b is the correc0,t which says, the force will decrease on increasing the inverse square of the distance.

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A bowl of water containing 1.44 kilogram of hydrogen will have 12.9 kilograms of water.

As per the known fact, 18 grams of water has 11.2% hydrogen. Amount of hydrogen in 18 grams of water = 18×11.2%

Amount of hydrogen in 18 grams of water = 2.016 grams

Amount of hydrogen in question = 1.44 × 1000

Amount of hydrogen in question = 1440 grams

2.016 grams of hydrogen is present in amount in of water = 18 grams

1440 grams of hydrogen will be in amount of water = (18/2.016) × 1440

Amount of water = 8.93 × 1440

Amount of water = 12,859.2 grams or 12.9 kg

Thus, amount of water is 12.9 kilograms.

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The three wavelengths that will produce standing waves on this string are 4 m, 2 m, and 1.33 m.

To find the wavelengths that will produce standing waves on a stretched string fixed at both ends, we can use the formula:

λn = 2L/n

where λn is the wavelength of the nth harmonic, L is the length of the string, and n is the harmonic number.

For the fundamental frequency (n = 1), the wavelength would be:

λ1 = 2L/1 = 4 m

For the second harmonic (n = 2), the wavelength would be:

λ2 = 2L/2 = L = 2 m

For the third harmonic (n = 3), the wavelength would be:

λ3 = 2L/3 ≈ 1.33 m

So, the three wavelengths that will produce standing waves on this string are 4 m, 2 m, and 1.33 m.

Now, for a wavelength that would not produce a standing wave pattern, we can consider the case where the wavelength is equal to the length of the string, i.e., λ = L. In this case, the wave will not produce a standing wave pattern because the ends of the string are fixed nodes, and the only possible standing wave pattern is one that has a node at each end. If the wavelength is equal to the length of the string, the only possible pattern would be a single wave with an antinode at the center, which is not a standing wave.

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Answer:

work = power × time

time = work ÷ power

Explanation:

Power is defined as the rate at which work is done.

 It is mathematically expressed as;

     Power  = \(\frac{work}{time}\)  

 From this expression, if we cross multiply, we get;

        work  = power x time

Also,   if we divide both sides by power, we get;

      time  = work ÷ power

Answer:

Cytokinesis occurs differently in animal and plant cells. In animal cells, the plasma membrane of the parent cell pinches inward along the cell's equator until two daughter cells form. In plant cells, a cell plate forms along the equator of the parent cell.

Explanation:

The acceleration of the airplane is \(7.88\times 10^{-3} m/s^2\) and the time elapsed while the airplane covers \(49700\) \(m\) is \(1294.42s\).

Let us consider the value of acceleration is \(a\) \(m/s^2\) and the time elapsed while the airplane covers \(49700\) \(m\) is \(t\) \(s\).

It is given that,

The initial velocity of the airplane, \(u=33.3 m/s\).

The final velocity of the airplane, \(v=43.5m/s\).

The distance covered by the airplane, \(s=49700 m\).

It is known that, \(v^2=u^2+2as\).

\(\Rightarrow (43.5)^2=(33.3)^2+2a(49700)\)

\(\Rightarrow 1892.25=1108.89+99400a\)

\(\Rightarrow 1892.25-1108.89=99400a\)

\(\Rightarrow 783.36=99400a\)

\(\Rightarrow a=\frac{783.36}{99400}\)

\(a=7.88\times 10^{-3} m/s^2\)

Hence, the acceleration of the airplane is \(7.88\times 10^{-3} m/s^2\).

It is known that, \(v=u+at\).

\(\Rightarrow 43.5=33.3+(7.88\times10^{-3})t\)

\(\Rightarrow 43.5-33.3=(7.88\times10^{-3})t\)

\(\Rightarrow 10.2=(7.88\times10^{-3})t\)

\(\Rightarrow t=\frac{10.2}{7.88\times10^{-3}}\)

\(\Rightarrow t=1294.42 s\)

Hence, the time elapsed while the airplane covers \(49700\) \(m\) is \(1294.42s\).

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Answer:

Explanation:

To calculate the height of the table in this scenario, we can use the equations of motion. Let's define the variables first:

Initial velocity (u) = 2.50 m/s (given)

Time taken to reach the floor (t) = 0.391 s (given)

Acceleration due to gravity (g) = 9.8 m/s² (assuming the ball falls freely near the surface of the Earth)

Now, we can use the kinematic equation:

h = u * t + (1/2) * g * t²

Plugging in the given values, we have:

h = (2.50 m/s) * (0.391 s) + (1/2) * (9.8 m/s²) * (0.391 s)²

Simplifying the equation:

h = 0.97875 m + 0.07511 m

h = 1.05386 m

Therefore, the height of the table is approximately 1.05386 meters.

The speed between P and Q remains the same throughout the 2.0-second interval.

The speed of the bubble between positions P and Q can be determined by dividing the displacement by the time taken. In this case, the displacement is the distance between positions P and Q, and the time taken is 2.0 seconds.

To calculate the speed, we need to know the numerical values for the displacement and the time taken. Let's assume that the displacement is represented by Δx, and the time taken is 2.0 seconds.

The speed can then be calculated using the formula: speed = displacement / time.

For example, if the displacement Δx is 10 meters and the time taken is 2.0 seconds, the speed of the bubble between P and Q would be 10 meters / 2.0 seconds = 5 m/s. It's important to note that in this scenario, since the bubble is rising at a constant speed, the speed between P and Q remains the same throughout the 2.0-second interval.

The question was incomplete. find the full content below:

A student determines the average speed of a bubble rising through a liquid at constant speed. When the student starts the stopwatch the bubble is at position P. After 2.0 s the bubble is at position Q.

What is the speed of the bubble between P and Q?

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Answer:   0.0035

============================================

Explanation:

The exponent is -3, so we move the decimal point 3 spots to the left to go from 3.5 to 0.0035

If the exponent was positive, then we would move the decimal point to the right that amount of spaces.

Answer The force is multiplied times 9

Explanation:

As the distance between charged tape and charged rod decreases, the force of interaction between them increases.

The force of interaction between the charged tape and charged rod is governed by Coulomb's Law.

This law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

So, as the distance between the charged tape and charged rod decreases, the force of interaction increases.

This is because the charges on the objects are now closer to each other, allowing for a stronger attraction or repulsion, depending on the nature of the charges (like charges repel, opposite charges attract).

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Answer:

Gravitational potential energy

Explanation:

Gravity would act upon it if it were not suspended.

Answer: Gravitational potential energy

Explanation: I did the quiz! Hope it helped!

Answer:

348

Explanation:

because maths ;)

The box of macaroni are in the shape of a cuboid, and the volume of the cuboid in the same unit will be 348 cm.

A three-dimensional space's volume can be calculated.  It is frequently expressed in numerical form using SI-derived units or by different imperial units (such as the gallon, quart, and cubic inch). Volume and length are related by the definition of length (cubed). In contrast to how much space the container occupies, the volume of a container is typically thought of as its carrying capacity or the amount of fluid (liquid or gas) that it could hold.

According to the question, the given values are :

Length, l = 16 cm

Width, b = 7.5 cm

Height, h = 2.9 cm

So, the volume of the Cuboid will be, V : l × b × h

V = 16 × 7.5 × 2.9

V = 348 cm³.

Hence, the volume of macaroni box will be 348 cm³.

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a) When the length of the copper wire is reduced, the reading in the ammeter will remain unchanged as long as the resistance of the wire remains constant.

This is because the current flowing through a wire is inversely proportional to its length, according to Ohm's Law (V = IR), where V is the voltage, I is the current, and R is the resistance. As long as the voltage and resistance remain constant, the current will also remain constant.

b) If a thicker copper wire is used, the reading in the ammeter will decrease. This is because the resistance of a wire is inversely proportional to its cross-sectional area. When a thicker wire is used, its cross-sectional area increases, leading to a decrease in resistance. According to Ohm's Law, with a constant voltage, a decrease in resistance will result in an increase in current. Therefore, the ammeter reading will be higher when a thicker wire is used.

c) If a nichrome wire of the same length and cross-sectional area is used in place of the copper wire, the reading in the ammeter will depend on the resistance of the nichrome wire. Nichrome has a higher resistivity compared to copper, meaning it has a higher resistance for the same length and cross-sectional area. Therefore, when the nichrome wire is used, the resistance of the circuit increases, resulting in a decrease in current according to Ohm's Law. As a result, the ammeter reading will be lower when the nichrome wire is used

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Answer: energy=mc^2 is the answer

Answer:

E represents units of energy

Explanation:

Answer:

Explanation:

You didn't ask a question here, but I assume you want the pressure? You can use the ideal gas equation stating that:

PV = nRT

The 'P' is pressure, the 'V' is volume, the 'n is number of moles of gas, the 'R' is the ideal gas constant, and the 'T' is the temperature. First convert the Celsius degrees into Kelvin by using the following relation:

C + 273.15 = K

4 + 273.15 = 277.15K

Now, find the volume of a cylinder by using:

\(V=\pi r^2l\)

The 'l' is the length of the cylinder

Now just plug and chug everything into the ideal gas equation:

\(PV=nRT\)

\(P(\pi r^2l)=(5moles)(8.3145J/moles*K)(277.15K)P=\frac{11.52J}{\pi r^2l}\)

Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. Therefore, the frequency of wave is 25 Hz.

Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave

speed of wave= distance travelled by wave ÷ time taken by the wave

speed of wave=  5,000m/s

distance travelled by wave = wavelength of wave = 200 meters

Substituting all the given values in the above equation, we get

5,000m/s=  200 meters ÷ time taken by the wave

time taken by the wave= 0.04 s

Frequency = 1 ÷time taken by the wave

                  = 1÷0.04

                  =25 Hz

Therefore, the frequency of wave is 25 Hz.

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True. In circular motion, the centripetal acceleration changes only the direction of velocity, but not its magnitude.

Centripetal acceleration is the acceleration directed toward the center of the circular path and is responsible for keeping an object moving in a curved path. It is always perpendicular to the velocity vector of the object at any given point on the path.

The magnitude of the centripetal acceleration, denoted as "a_c," can be calculated using the following formula:

a_c = (v^2) / r

Where:

- v is the magnitude of the velocity of the object

- r is the radius of the circular path

As the object moves along the circular path, its velocity vector constantly changes direction. However, the magnitude of the velocity, represented by "v," remains constant unless acted upon by an external force.

Therefore, the centripetal acceleration only affects the direction of the velocity vector, causing it to continuously change, while the magnitude of the velocity remains constant.

True. In circular motion, the centripetal acceleration changes only the direction of velocity, but not its magnitude.

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Answer: C

Explanation:

Explanation: Well, If you arrive in my class 45 seconds after leaving math, which is 90 meters away. you traveled 2m/s ( I hope this helped <3)

When you are driving with a trailer in tow and the road curves to the right, you should move closer to the edge of the roadway during the traffic. Hence, the correct option is (b).

This will help ensure that the trailer does not swing out into the oncoming traffic lane while you are navigating the curve. Additionally, it is important to allow more distance from the edge of the pavement, as the trailer will require more room to make the turn. Driving in heavy traffic can be stressful, but there are some tips and strategies that can help make it easier. First, make sure to leave yourself plenty of time to reach your destination. This will help reduce your stress levels, as you won't be rushing to get somewhere. Second, try to stay in the center lane as much as possible. This will give you the most flexibility and maneuverability in traffic. Third, keep your speed steady, as sudden acceleration and deceleration can make it difficult to navigate traffic and can also be distracting to other drivers.

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The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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The relative position vector pointing from q₁ to q₂ (-0.68 î + 0.71 ) and the distance between q₁ and q₂ (0.983 m)

According to Newton's universal law of gravitation, there is a direct relationship between the sum of the masses of the two bodies and an inverse relationship between the square of the distance between them.

Given m₁=m₂

                      =0.002kg

q₁= -8×10⁻⁹ C  at (0.37, -0.26, 0) m

q₂= -6×10⁻⁹ C at ( -0.31, 0.45, 0)m

a) Position vector from q₁ to q₂ is :

ř = Position vector of q₂ - Position vector of q₁

ř = ř₂ - ř₁

ř₂ = -0.31 î + 0.45 ĵ

ř₁ = 0.37 î + -(0.26) ĵ

ř = ř₂ - ř₁

= (-0.31 î + 0.45 ĵ ) - (0.37 î  - 0.26 ĵ )

=( -0.31 - 0.37)î + (0.45+0.21)ĵ

= -0.68 î + 0.71 ĵ

b)  distance between q₁ and q₂ is |ř| :

                   = √-0.68² + 0.71²

                = √ 0.4624 +0.504

               =  0.983 m

c)  unit vector in direction of r is ř/|r| :

=  -0.68 î + 0.71 ĵ / 0.983

=  -0.6916 î + 0.7223 ĵ

d)  the strength of the gravitational pull that q₁ has on q₂ :

                          Fg = G×m₁×m₂/|r²

           =  6.67× 10⁻¹¹ ×0.002×0.002/ 0.983²

                 =  2.76×10⁻¹⁶  N

e) the gravitational force is always attracted so it will be toward q₁

so the vector is ř₃ = ř₁ - ř₂

= ( 0.37 î + 0.26 ĵ ) - ( -0.31 î + 0.45 ĵ )

= ( 0.68 î - 0.71 ĵ )

ř₃ = √0.68² + 0.71²

          = √0.4624 + 0.504

                 = 0.983

f)  infact ř₃ = -ř & |ř₃| = |ř|

so unit vector in direction  of r₃ is

ř₃/ |r₃|

( 0.69 î - 0.71 ĵ ) / 0.983

ř₃ = 0.6916 î - 0.7223 ĵ

in vector form force  bye q₁ on q₂ is

Fg = 2.76×10⁻¹⁶  × (0.6916 î - 0.7223 ĵ)

= 1.908×10⁻¹⁶  î - 1.9935× 10⁻¹⁶ ĵ

g)  the electric force on q₂ by q₁ :

          (Fe) = k×q₁×q₂/r²

=  9 × 10⁹ × (-8 ×10⁻⁹ ) × (-6 ×10⁻⁹ ) / 0.983²

= 4.47× 10⁻⁷ N

in vector form, since  the force is repulsive  so it is  away from the  charge

Fe =  4.47×10⁻⁷ × ( -0.6916 î + 0.7223 ĵ)

= -3.0914× 10⁻⁷ î + 3.22868× 10⁻⁷ ĵ

h) ratio |Fe| / |Fg|

= 4.47× 10⁻⁷ / 2.76× 10⁻¹⁶

= 1.61 × 10⁹ N

i) The new distance between the particle is now 6(ř) :

On applying formula

F'e = k×q₁×q₂ / (6|r|)²

=  k×q₁×q₂ / 36 (r)²

= 1 / 36( k×q₁×q₂ / r ) = Fe/36

F'g = G ×m₁ ₓm₂ /  (6|r|)²

=  G× m₁ × m₂  / 36 (r)²

= 1 / 36(G×m₁×m₂ / r²) Fg/36

Ratio Fe/36/Fg/36

= Fe/Fg = 1.61  ×10⁹  N

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