An object travels 7.5 m to the right, then immediately travels 4.5 m to the left. If the entire trip is 3 seconds, what is the object’s speed?

Answer:

B. Luminosity

Explanation:

The luminosity of a star is a measure of its brightness.

Have a good day and stay safe!

Answer:

The answer to your question is 2

The weight we experience on our planet is the product of our mass and acceleration due to gravity. This is the force by our own weight. if an object of 15 kg mass weighs 60 on planet X, acceleration due to gravity on planet X  will be  4 m/s².

Gravitational force is an attractive force by which an object attracts other objects into its center of mass. We are all standing on the surface of earth due to the gravitational pull of earth.

Gravitational force is directly proportional to the mass of the object and inversely proportional to the distance from the ground. Acceleration due to gravity is the acceleration of a moving body against the gravitational filed.

Given that the mass of the object is 15 Kg and the gravitational force or weight is 60 N. Then the acceleration due to gravity a is the ratio of its weight to the mass.

a = w/m

  = 60 N/ 15 Kg

  = 4 m/s².

Therefore, the acceleration due to gravity of the planet x is 4 m/s².

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Answer:

b 15

Explanation:

the atomic number is the number of the element

According to this equation, so f = 3.29 x 1014 Hz. The light therefore has a frequency of 3.29 x 1014 Hz. The wavelength range of visible light is roughly 400–700 nm, and its frequency range is roughly 400–800 tHz.

The frequencies used by white LED lighting devices are a combination of 474 terahertz, 535 terahertz, and 638 terahertz. White LED technology has made it possible to create inexpensive, energy-efficient lighting that may be utilised in a range of applications, from desk lamps to street lamps.

The capacity to render different kinds of light visible for human sight makes light energy a type of kinetic energy. Light is referred to as an electromagnetic radiation that is produced by hot objects like the sun, lasers, and lightbulbs. Photons, which are tiny energy packets, are present in light.

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Answer:

heat and power

Explanation:

is the simultaneous production of electricity and heat both of which are used

1. phase difference = 45.1318°

2. phase difference = 54.52°

3. phase difference = 62.153°

Case 1: C = 56.4 ₙF

V₁ = \(\frac{156}{\sqrt[]{2} }\)

\(x_{c}\) = \(\frac{1}{2\pi fc}\)

\(x_{c}\) = \(\frac{1}{2\pi * 60*56.4*10^{-9} }\)

\(x_{c}\) = 47.031 KΩ

here, \(V_{0} = V_{A}\)

\(X_{L}\) = 2πfL

\(X_{L}\) = 2π x 60 x 125

\(X_{L}\) = 94.247 KΩ

Apply KCV of node "A"

\(\frac{V_{A}-0 }{-jX_{c} +jX_{L}+R_{2} }\) + \(\frac{V_{A} -V_{1} }{R_{1} }\) = 0

\(V_{A}\) ( \(\frac{1}{R_{2} +j(X_{L} -X_{C} )} + \frac{1}{R}\) ) = \(\frac{V_{1} }{R_{1} }\)

\(V_{A}\) ( \(\frac{1}{47 + j(94.247 - 47.031)} + \frac{1}{67}\) = \(\frac{156/\sqrt[]{2} }{67}\)

\(V_{0} = V_{A} = \frac{84.227}{\sqrt{2} }\)

\(V_{A}\) = 84.227 sin (2π x 60t + 22.663) Volts

\(V_{R} _{1}\) = \(V_{1}\) = \(V_{A}\) = \(\frac{84.706}{\sqrt{2} }\)

V\(R_{1}\) = 84.706 sin [2π x 60t + (-22.498°)] Volts

phase difference = 22.6333 - (-22.498)

phase difference = 45.1318°

Case 2: C = 100ₙF

\(X_{C}\) = \(\frac{1}{2\pi * 60 * 100 * 10^{-9} }\)

\(X_{C}\) = 26.525 Ω

\(V_{0}\) = \(\frac{156}{\sqrt{2} }\) x \(\frac{R_{2} + j (X_{L} - X_{C}) }{R_{1} + R_{2} +j(X_{L} - X_{C} )}\)

\(V_{0}\) = \(\frac{96.98}{\sqrt{2} }\) \(\\ 24.52\)° Volts

\(V_{R1}\) = \(V_{1}\) - \(V_{0}\) = \(\frac{78.82}{\sqrt{2} }\) -30° Volts

phase difference = 24.52 - (-30)

phase difference = 54.52°

Case 3: C = 500ₙF

\(X_{C\) = 5.305 KΩ

\(V_{0}\) = \(\frac{156}{\sqrt{2} }\) (\(\frac{47 + j 94.247 - j 5.305}{67 + j 94.247 - j 5.305 + 47}\))

\(V_{0}\) = \(\frac{108.533}{\sqrt{2} }\) (24.186°)

\(V_{R1} = V_{1} - V_{0}\) = \(\frac{72.28}{\sqrt{2} }\) (-37.967°) Volts

phase difference = 24.186 - (-37.967) Volts

phase difference = 62.153°

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Answer:

La fuerza que se ejerce entre las dos cargas es 2880 N.

Explanation:

La ley de Coulomb indica que los cuerpos cargados sufren una fuerza atractiva o repulsiva al acercarse. La fuerza es atractiva si las cargas son del signo opuesto y repulsión si son del mismo signo. El valor de la fuerza es proporcional al producto del valor de sus cargas e inversamente proporcional al cuadrado de la distancia que los separa. Esto se expresa matemáticamente como:

\(F=k*\frac{Q*q}{r^{2} }\)

donde:

En este caso:

Reemplazando:

\(F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{4*10^{-5} C*2*10^{-5}C }{(0.05 m)^{2} }\)

F= 2880 N

La fuerza que se ejerce entre las dos cargas es 2880 N.

If a 30-meter long rope hangs freely from a ledge then the work done if the top 1/3 of the rope is pulled up to the ledge is  4900 Joules.

To solve this problem, we need to first find the mass of the rope. We know that the density of the rope is 5 kg/m, and the length of the rope is 30 meters. Therefore, the total mass of the rope is:

mass = density * length

mass = 5 kg/m * 30 m

mass = 150 kg

Next, we need to find the mass of the top 1/3 of the rope that is pulled up to the ledge. We can do this by multiplying the total mass of the rope by the fraction of the rope that is pulled up, which is 1/3:

mass_pulled = (1/3) * mass

mass_pulled = (1/3) * 150 kg

mass_pulled = 50 kg

Now that we know the mass of the part of the rope that is pulled up, we can find the change in potential energy of the rope when it is lifted to the ledge. The change in potential energy is given by:

ΔPE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the change in height. In this case, the change in height is equal to 1/3 of the length of the rope, or 10 meters.

ΔPE = mass_pulled * g * h

ΔPE = 50 kg * 9.8 m/s^2 * 10 m

ΔPE = 4900 J

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Answer:

A

Explanation:

Answer:

Proxima Centauri is a small, low-mass star located 4.244 light-years (1.301 pc) away from the Sun in the southern constellation of Centaurus. Its Latin name means the "nearest [star] of Centaurus". This object was discovered in 1915 by Robert Innes and is the nearest-known star to the Sun.

Star system: Alpha Centauri

Category: Star, Flare star

Constellation: Centaurus

Discoverer: Robert T. A. Innes

Explanation:

u should make it into an essay

The initial speed of the projectile is 18.5m/s

Projectile motion is the motion of an object thrown into the air under gravity. Examples of projectiles include a fired bullet, a thrown javelin e t.c

When a projectile is launched horizontal, it's horizontal range is given as R = u(√2h/g)

R = 300ft = 91.44meters

h= 120m

therefore 91.44= u( √ 2×120/9.8)

91.44 = u ( √24.49)

91.44 = 4.95 u

divide both sides by 4.95

u = 91.44/4.95

u = 18.5m/s

therefore the speed of the projectile is 18.5m/s

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Radio waves allows the charges in the receiving antenna to respond to the electric field portion of the carrier wave.

This refers to a type of disturbance which transports energy from one place to another without the actual movement of the particles and of various types such as  microwaves, radio waves etc.

The radio wave allows the electrons in the rod to vibrate with amplitudes which emulates those of the carrier wave and in this case, it is the antenna thereby resulting in the signals in the car radio being provided as a result of these type of interactions.

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Answer: green car and red car

Explanation:

Answer:

it is white car for the first question and for the second it goes green slowest and white fastest red is in the middle

The nickname for the six basic aircraft instruments is "the six-pack".

Aircraft instruments are instruments that are installed on an aircraft's instrument panel to provide the pilot with essential information about the aircraft's state and performance.

The six-pack, often known as the six basic flight instruments, consists of the following: Airspeed Indicator (ASI)Altimeter Attitude Indicator (AI)Turn Coordinator Heading Indicator, Vertical Speed Indicator (VSI)The six-pack is used to assist pilots in determining the plane's orientation in space and its location in relation to the ground.

They're also crucial for safe and efficient flight operations.

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Explanation:

Efficiency is a way of describing the amount of useful ​output​ a process or machine can generate as a percentage of the ​input​ required to make it go. In other words, it compares how much energy is used to do work versus how much is lost or wasted to the environment. The more efficient the machine, the less energy wasted.

For example, if a heat engine is able to turn 75 percent of the fuel it receives into motion, while 25 percent is lost as heat in the process, it would be 75 percent efficient. Out of the original 100 percent of the fuel, 75 percent was output as useful work.  

the equation:

energy efficiency =useful output energy/total input energy

Answer: Different types of fuels have varying compositions and release different amounts of pollutants when burned. Here are some common types of fuels and the pollutants associated with them:

Fossil Fuels:

a. Coal: When burned, coal releases pollutants such as carbon dioxide (CO2), sulfur dioxide (SO2), nitrogen oxides (NOx), and particulate matter (PM).

b. Petroleum (Oil): Burning petroleum-based fuels like gasoline and diesel produces CO2, SO2, NOx, volatile organic compounds (VOCs), and PM.

Natural Gas:

Natural gas, which primarily consists of methane (CH4), is considered a cleaner-burning fuel compared to coal and oil. It releases lower amounts of CO2, SO2, NOx, VOCs, and PM.

Biofuels:

Biofuels are derived from renewable sources such as plants and agricultural waste. Their environmental impact depends on the specific type of biofuel. For example:

a. Ethanol: Produced from crops like corn or sugarcane, burning ethanol emits CO2 but generally releases fewer pollutants than fossil fuels.

b. Biodiesel: Made from vegetable oils or animal fats, biodiesel produces lower levels of CO2, SO2, and PM compared to petroleum-based diesel.

Renewable Energy Sources:

Renewable energy sources like solar, wind, and hydropower do not produce pollutants during electricity generation. However, the manufacturing, installation, and maintenance of renewable energy infrastructure can have environmental impacts.

It's important to note that the environmental impact of a fuel also depends on factors such as combustion technology, fuel efficiency, and emission control measures. Additionally, advancements in clean technologies and the use of emission controls can help mitigate the environmental impact of burning fuels.

An Atwood's machine is a device used to analyze the movement of two masses with a pulley that acts as a point of rotation. The movement of two masses in an Atwood's machine can be used to determine the magnitude of the acceleration due to gravity.

The modified Atwood machine is similar to the Atwood's machine except that it uses a cart rather than a hanging mass. The acceleration of a modified Atwood machine with a cart mass of 4 kg and a hanging mass of 1 kg can be determined using the following equation:`a = (m1 - m2)g / (m1 + m2)`where a is the acceleration, m1 is the mass of the cart, m2 is the mass of the hanging weight, and g is the acceleration due to gravity.

The value of g is 9.8 m/s². The mass of the cart is 4 kg and the mass of the hanging weight is 1 kg, therefore:m1 = 4 kgm2 = 1 kgg = 9.8 m/s²Substitute these values into the equation:`a = (m1 - m2)g / (m1 + m2) = (4 - 1) x 9.8 / (4 + 1) = 2.94 m/s²`Therefore, the magnitude of the acceleration of a modified Atwood machine with a cart mass of 4 kg and a hanging mass of 1 kg is 2.94 m/s².

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The probability of stopping at a traffic light is about 47.22%.

With 10 traffic lights, expect to be stopped for approximately 5 minutes and 45 seconds along the main street.

(a) To calculate the probability of stopping at a particular traffic light, we need to consider the cycle time of the traffic lights. The cycle time is the total time taken for one complete sequence of green, amber, and red signals. In this case, the cycle time is 55 + 17 + 48 = 120 seconds.

The probability of stopping at a particular traffic light can be calculated by dividing the red signal duration by the cycle time. Therefore, the probability is 48/120 = 0.4 or 40%.

However, in California, no one stops on amber, so we need to exclude the amber duration from the calculation. Therefore, the probability becomes 48/(55 + 48) ≈ 0.4722 or 47.22%.

(b) If there are 10 traffic lights on the main street, we can calculate the expected amount of time spent stopped at traffic lights by multiplying the probability of stopping at each traffic light by the average duration of being stopped.

The average duration of being stopped at a traffic light is the sum of the red signal duration and half of the amber signal duration. So, the average duration is (48 + 17/2) = 56.5 seconds. To find the expected amount of time stopped at traffic lights, we multiply the average duration by the number of traffic lights: 56.5 seconds * 10 = 565 seconds.

Therefore, if you drive all the way down the main street, the expected amount of time you are likely to be stopped at traffic lights is approximately 565 seconds, which is equivalent to 5 minutes and 45 seconds.

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The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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Answer:

I gonna give you the number so but you need to round 6.19047619048

Explanation:

The velocity of the football thrown is approximately 23.76 meters per second.

Momentum is simply the product of the mass of an object and its velocity.

This is expressed as;

P = m × v

Where m is the mass of the object and v is its velocity.

Given that;

Plug the given values into the above formula and solve for v.

P = m × v

v = P / m

v = 10.1kgm/s / 0.425kg

v = 23.76 m/s

Therefore, the velocity of the ball is 23.76 m/s.

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Answer: A

Explanation:

A

We can use the formula:

Energy (E) = Charge (Q) × Potential difference (V)

          V = E / Q = 20 J / 80 × 10^-3 C = 250 V

         I = Q / t = 80 × 10^-3 C / 5.0 × 10^-3 s = 16 A

          P = E / t = 20 J / 5.0 × 10^-3 s = 4,000 W

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The mass of the box is approximately 6.8 kg. To calculate the mass of the box, we need to use the formula for work: work = force x distance x cos(theta),.

where theta is the angle between the force and the displacement. In this case, we know that the work done was 100 J and the distance lifted was 1.5 m. We also know that the force required to lift the box is equal to its weight, which can be calculated using the formula weight = mass x gravity, where gravity is approximately 9.8 m/s^2.

So, we can rearrange the formula for work to solve for force: force = work / (distance x cos(theta)). Since the box was lifted vertically, the angle between the force and the displacement is 0 degrees, so cos(theta) = 1.
Therefore, force = 100 J / (1.5 m x 1) = 66.67 N. To find the mass of the box, we can use the formula weight = mass x gravity and plug in the force we just calculated:
weight = mass x gravity
66.67 N = mass x 9.8 m/s^2
mass = 6.80 kg

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The given forces are a 100 N force and a 50 N force acting on point P. The 100 N force acts due north. We have to calculate the magnitude and direction of the resultant force. Use vector addition to find the resultant force, we can use the Pythagorean theorem. The magnitude of the resultant force is 111.8 N (approximately)

We haveF1 = 100N force acting due north.F2 = 50N force acting at an unknown direction

Therefore, Resulant force, F = √(F1² + F2²) Resulant force, F = √(100² + 50²) Resulant force, F = √10000 + 2500Resulant force, F = √12500Resulant force, F = 111.8 N (approximately)Now, we can use trigonometry to find the direction of the resultant force. We can find the angle using sine and cosine functions.

We have the angle that the resultant force makes with the north direction as follows; sin(θ) = opposite/hypotenuse = F2/Fcos(θ) = adjacent/hypotenuse = F1/F Solving for θ, we get;θ = tan⁻¹(F2/F1)θ = tan⁻¹(50/100)θ = tan⁻¹(0.5)θ = 26.57°

Hence, the magnitude of the resultant force is 111.8 N (approximately) and the direction of the resultant force makes an angle of 26.57° with the north direction.

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The length of a side of the cube is 21.83 cm.

We need to know about cube volume to solve this problem. Cube volume can be calculated by multiplying the length of the cube. It can be written as

V = L³

where V is cube volume and L is cube length.

From the question above, we know that

V = 11 quart = 2.75 gallon

1 gallon = 3.786 liters

Convert volume to liters

V = 2.75 gallon

V = 2.75 x 3.786 liters

V = 10.41 liters

V = 10.41 dm³

Find the length

V = L³

10.41 = L³

L = ³√10.41

L = 2.18 dm

Convert length to cm

L = 2.183 dm

L = 21.83 cm

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