an object is suspended on a frictionless inclined plane by a rope parallel to the incline as shown. if the angle of the incline is 25o and the tension in the rope is 5000. n, what is the weight of the object?

Answer:

dont know

Explanation:

need points

Answer:

Explanation: 1: The gas particles move in a straight line before colliding with something, usually the wall of their containers.

2: The is no attraction or repulsion between the gas particles.

The linear speed of a swimming whale is 50 km/h. and it will have traveled approximately 138.9 km after 2 and a half hours.

First, we need to convert the linear speed into m/s:

1 km/h = 1000/3600 m/s= 5/18 m/s

Therefore,50 km/h = 50 × 5/18 m/s = 125/9 m/s

Now, the distance traveled by the whale can be found using the formula:

Distance = speed × time

Since the time is 2.5 hours, we have that convert it to seconds:

2.5 hours = 2.5 × 60 × 60 seconds = 9000 seconds

Therefore, the distance traveled is:

Distance = (125/9) m/s × 9000 s= 1250000/9 m ≈ 138888.89 m≈ 138.9 km

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Answer:

the answer is b

Explanation:

Answer:

object with larger mass

Explanation:

the momentum of an object is directly proportional to its mass. larger mass = more momentum

Answer:

The one with a larger mass should have the higher momentum.

Explanation:

Answer: 20 m/a

Explanation: 600/30=20

Answer:

:)

Explanation:

i need 5 points i really do :)

Answer:

55mph

Explanation:

a 0.11kg moving hockey puck is caught by a 80kg goalie who then slides on the frictionless ice at 0.076 m/s. the initial velocity of the hockey puck was 55mph

Velocity is a parameter which can be defined as the rate at which the object change the position with respect to time, basically speeding the object in a specific direction.

It  is a  vector quantity which shows both magnitude  and direction  and The SI unit of velocity is meter per second (ms-1). the  change in magnitude or the direction of velocity of a body, then it is said to be accelerated.

Finding the total velocity is simple but few calculations and basic conceptual knowledge are needed.

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Its average speed will be 25 m/s approximately. The correct answer is option C

Average speed is the ratio of total distance travelled to the total time taken. It is a scalar quantity and the S.I unit is m/s

Given that a car travels one third of a path with speed of 50 m/s and two third of path with 20m/s.

If the car travels one third of a path with speed of 50 m/s, then the time taken will be

Speed = distance / time

Time = distance / speed

Time = 1/3 ÷ 50

Time = 6.67 x \(10^{-3}\) s

If the car travels the remaining two third of a path with speed of 20 m/s, then, the time taken will be

Time = distance / speed

Time = 2/3 ÷ 20

Time = 0.0333

Total time = 0.03333 + 0.00667

Total time = 0.04

The total distance travelled = 1

Average speed = Total distance travelled ÷ Total time

Average speed = 1/0.04

Average speed = 24.99979 m/s

Therefore, its average speed will be 25 m/s approximately.

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Maximum resultant pulse will be 22.36 cm, if the amplitude of pulse A is 20 cm, and that of pulse B is 10 cm.

Equations of two superimposing waves with a phase difference of π/2, are:

y₁ = a₁sin(ωt) and y₂ = a₂sin(ωt + π/2) = a₂cos(ωt)

The equation of the resultant wave will be:

y = y₁ + y₂

y = a₁sin(ωt) + a₂cos(ωt)

Assuming a₁ = acos(Φ),  a₂ = asin(Φ)

So, y = asin(ωt+Φ)

(a₁)² + (a₂)² = a²(sin²Φ + cos²Φ)

(a₁)² + (a₂)² = a²

a = √((a₁)² + (a₂)²)

a = √(20²+10²)

a = √500

a = 22.36 cm.

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The speed of the water as it exits the tap is approximately 1.89 m/s.

We can use the principle of conservation of mass and energy to solve this problem. Assuming that the water is incompressible and the flow is steady, the mass flow rate of water at the tap is constant. Therefore, the mass flow rate at the tap is equal to the mass flow rate at the exit:

ρ1A1v1 = ρ2A2v2

where:

We can rearrange this equation to solve for v2:

v2 = (ρ1A1v1) / (ρ2A2)

We know that A1 = 1.5 cm², A2 = 0.45 cm², and the vertical distance fallen is 6.0 cm. We can find the speed of water at the tap using the equation for the potential energy:

mgh = (1/2)mv1²

where m is the mass of the water, g is the acceleration due to gravity, h is the vertical distance fallen, and v1 is the speed of water at the tap.

We can rearrange this equation to solve for v1:

v1 = √(2gh)

where;

We also know that the density of water at room temperature is approximately 1000 kg/m³, which is equivalent to 0.001 g/cm³.

Putting all these values into the equation for v2, we get:

v2 = (0.001 g/cm³ x 1.5 cm² x sqrt(2 x 9.81 m/s² x 6.0 cm)) / (0.001 g/cm³ x 0.45 cm²)

Simplifying this expression, we get:

v2 = 1.89 m/s

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Answer:5.45X10^3m

Explanation:So use the formula,v= fλ

3X10^8=5.5X10^4λ what Im saying is divide both and u should get 5454.54m but do sig figs to get answer

Answer:

5.45X10^3m

Explanation:

The average person's vertical jump on the Moon would be 0.65 m.

The gravitational acceleration near the surface of the Moon is 1.62 m/s2, which is about one sixth the gravitational acceleration on Earth.

As a result, an average person's vertical jump on the Moon would be less than on Earth.

To calculate the vertical jump on the Moon, we need to use the formula h = 1/2 x g x t2.

This equation is used to calculate the height h (in meters) that an object will reach when thrown into the air, given the gravitational acceleration g (in m/s2) and the time t (in seconds) it takes to reach the peak of the jump.

Since the gravitational acceleration on the Moon is 1.62 m/s2, and the time taken to reach the peak of the jump is the same (assume 0.5 s), then h = 0.5 x 1.62 x (0.5)2, which is 0.65 m.

Therefore, an average person's vertical jump on the Moon would be 0.65 m.

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Answer:

When a projectile reaches maximum height, the vertical component of its velocity is momentarily zero (vy = 0 m/s). However, the horizontal component of its velocity is not zero.

Explanation:

Hope this helps

Answer:it's a chemical change.physical changes occur without 2 or more reactants,a reaction,and a product

Explanation:

Answer:

The assertion is true and reason is false.

Explanation:

Assertion: I P+ Q I = I P- QI, then P must be perpendicular to Q.

Reason : The relation will hold even when Q is a null vector.

Now

\(\left | P + Q \right |=\left | P - Q \right |\\\\P^2 + Q^2 + 2 P Q cos \theta =P^2 + Q^2 - 2 P Q cos \theta\\\\4 P Q cos \theta = 0 \\\\cos \theta = 0 \\\\\theta = 90 degree\)

So, P and Q are perpendicular to each other.

So, the assertion is true.

Reason is false.

The period of a wave is the time it takes for one complete wave to pass a fixed point. We are given that 4 complete waves pass a fixed point in 10 seconds.

To find the period, we can divide the total time by the number of complete waves:  10 seconds ÷ 4 waves = 2.5 seconds per wave


To determine the period of a water wave, we need to know how much time it takes for one complete wave to pass a fixed point. In this case, 4 complete waves pass in 10 seconds.

Step 1: Find the time it takes for one complete wave to pass.
Divide the total time (10 seconds) by the number of complete waves (4 waves).

10 seconds / 4 waves = 2.5 seconds

Step 2: Identify the corresponding answer choice.
The period of the water wave is 2.5 seconds, which corresponds to answer choice C.

Your answer: C: 2.5 s

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At equal pressure, less lp(liquefied petroleum) gas will flow through an orifice than natural gas. False.

At equal pressure, LP (liquefied petroleum) gas will generally flow through an orifice more easily than natural gas. This is due to the differences in the physical properties of the two gases.

LP gas, such as propane or butane, is stored in a liquid state under pressure. When the pressure is released, it vaporizes and becomes a gas. As a result, LP gas has a higher energy content and a higher vapor pressure compared to natural gas.

On the other hand, natural gas primarily consists of methane and is typically supplied through pipelines. It is in a gaseous state at normal atmospheric conditions.

When an orifice or a restricted opening is present, the flow rate of gas is determined by several factors, including the pressure difference across the orifice, the size of the orifice, and the properties of the gas.

Given equal pressure conditions, LP gas will tend to flow more readily through an orifice compared to natural gas. This is because LP gas has a higher vapor pressure, which means it has a greater tendency to expand and fill the available space. The higher energy content of LP gas also contributes to its ability to flow more easily through the orifice.

Therefore, the statement that less LP gas will flow through an orifice than natural gas at equal pressure is false. LP gas is expected to flow more readily through the orifice compared to natural gas.

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The number of photons in the pulse is 1.21 × 1022.

The energy of a photon can be calculated using the equation:

E = hf, where

E is the energy of a photon,

h is the Planck's constant, and

f is the frequency of the light.

Then, using the equation c = λf, where

c is the speed of light,

λ is the wavelength of the light and

f is the frequency of the light, the frequency of the light can be determined.

Planck's constant (h) is a fundamental constant in quantum mechanics that relates the energy of a photon to its frequency.

Its value is 6.626 × 10-34 joule seconds (J·s).

The frequency of the light is:

f = c / λ

= 3.00 × 108 / 480 × 10-9

= 6.25 × 1014 Hz

The energy of the photon can be calculated:

E = hf

= 6.626 × 10-34 × 6.25 × 1014

= 4.14 × 10-19 J

The number of photons can be determined by dividing the energy of the pulse by the energy of a photon:

n = E / E_photon

= 5.0 × 103 / 4.14 × 10-19

= 1.21 × 1022 photons

Therefore, the number of photons in the pulse is 1.21 × 1022.

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Answer:

1-state what the lab is about, that is, what scientific concept (theory, principle, procedure, etc.) you are supposed to be learning about by doing the lab. You should do this briefly, in a sentence or two. If you are having trouble writing the opening sentence of the report, you can try something like: "This laboratory experiment focuses on X…"; "This lab is designed to help students learn about, observe, or investigate, X…." Or begin with a definition of the scientific concept: "X is a theory that…."

2-give the necessary background for the scientific concept by telling what you know about it (the main references you can use are the lab manual, the textbook, lecture notes, and other sources recommended by the lab manual or lab instructor; in more advanced labs you may also be expected to cite the findings of previous scientific studies related to the lab). In relatively simple labs you can do this in a paragraph following the initial statement of the learning context. But in more complex labs, the background may require more paragraphs.

Explanation:

When Diego is in the race, he would be using only aerobic exercise.

The term aerobic exercise has to do with the type of exercise that require brisk repetitive movements in which the consumption of oxygen is elevated during the process.

A person tends to breath faster and more deeply when carrying out an aerobic exercise and the rapid movements is the reason why there is an intense demand for oxygen in the process.

As such, when Diego is in the race, he would be using aerobic exercise.

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Answer:

The height of the wall is 45 m

Explanation:

Horizontal Motion

When an object is thrown horizontally with an initial speed v from a height h, the maximum horizontal distance traveled by the object, also called the range can be calculated as follows:

\(\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}\)

If we know the range and want to calculate the height it was thrown from, we solve the equation for h:

\(\displaystyle h=\frac{d^2g}{2v^2}\)

We'll use the approximate value of g=10\ m/s^2.

The stone was thrown from the top of a wall with a speed of v=15 m/s and it hits the ground d=45 m away from the base of the wall. Calculating:

\(\displaystyle h=\frac{45^2\cdot 10}{2\cdot 15^2}\)

\(\displaystyle h=\frac{2025\cdot 10}{2\cdot 225}\)

\(\displaystyle h=\frac{20250}{450}\)

h = 45 m

The height of the wall is 45 m

Answer:

Explanation:

This sounds complicated but  ,  Butternight,  and maybe there is some difficulty in the ricochet.  I think the question is asking if the bullet bounces off a rock and heads North East....  or  NE,  but you've got it as  EN ?   Then how far does it go.  In my drawing,  what is X,  is the question.

We need to know how far the bullet travels East, and how far the bullet travels North.

Then we could put those two parts together and find the length of the red line in my drawing.  The red line is also referred to as the Magnitude.  

To find how far the bullet travels East,  use sine and cosine.  Do you know these?   if not,  start knowing  :D

Sine(36) = 0.587785....

Cosine(36)=0.809016....

640 * Sine(36)  => 640 * 0.587785  = 376.1825....  m  North

640 *Cosine(36)  => 640 * 0.809016 = 517.7708... m  East

Then the total distance traveled by the bullet to the East is 850 + 517.7708 = 1367.7708... m East

we can find the magnitude by using this \(\sqrt{North^{2} + East^{2} }\)

\(\sqrt{376.1825^{2} + 1367.7708^{2} }\) = 1418.559.... m NE

I used my calculator to find that.  :P

The distance traveled by object is 120 m in given time 10 seconds.

If other information is known, a set of four equations called the kinematic equations can be used to predict unknown information about an object's motion.

The equations can be applied to any motion that can be classified as either a constant velocity motion (with an acceleration of 0 m/s/s) or a constant acceleration motion. They are never permitted to be used over any time frame in which the acceleration is changing.

Four variables are present in each of the kinematic equations. The fquations offer a useful method of predicting details about an object's motion.

The kinematic equation for distance is,

\(\boxed{\mathrm{ d = (v +v_0) \dfrac{t}{2} }}\)

Where,

\(\mathrm{V_0}\) - initial speed = 8 m/s

V - final speed = 16 m/s

t - time = 10 s

Put the values in formula,

\({\mathbf{ {d = (16+9) \dfrac{10}{2} }}\)

\(\mathbf{d=120m}\)

Thus, The distance traveled by object is 120 m in given time 10 seconds.

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The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,

F = kx

Therefore,

k = F/x

We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,

K = 50.174/0.25 N/m

K = 200.696 N/m

Therefore, The Spring Constant is 200.696 N/m

On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:

h = \(1/2 kx^{2}\)

We know that k=200.696 N/m and x=0.25 m. Therefore the height is:

h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)

h = 2.5087 m

Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

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Answer:

We just know that the metal is called Vibranium.

to place something is the table   we need to know its atomic number and its mass. so if we can get that we can ans it.

Explanation:

The magnitude of the average acceleration is approximately\(-2.57 m/s^2\)(\(2.57 m/s^2\)), and its direction is southward. The negative sign indicates that the average acceleration is directed opposite to the initial velocity.

To find the average acceleration of the plane during landing, we can use the following formula:

Average acceleration = (change in velocity) / (time taken)

Here, the change in velocity is the difference between the initial velocity and the final velocity, and the time taken is the distance covered divided by the average speed.

Given:

Initial velocity (u) = 61 m/s (northward)

Final velocity (v) = 6.2 m/s (northward)

Distance covered (s) = 715 m

Change in velocity = v - u = 6.2 m/s - 61 m/s = -54.8 m/s (negative sign indicates the change is in the opposite direction)

Time taken (t) = s / average speed

Average speed = (u + v) / 2 = (61 m/s + 6.2 m/s) / 2 = 67.2 m/s / 2 = 33.6 m/s

Plugging the values into the equation:

Average acceleration = (-54.8 m/s) / (715 m / 33.6 m/s)

Simplifying:

Average acceleration ≈ -54.8 m/s / 21.30 s ≈ \(-2.57 m/s^2\)

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The maximum current in the circuit is approximately 0.206A.

The maximum current in the circuit can be found by using the formula:

\(I = \frac{V_{\text{max}}}{X_{C}}[\tex]

Where \(I\) is the maximum current, \(V_{\text{max}}\) is the maximum voltage across the capacitor, and \(X_{C}\) is the capacitive reactance.

To find the maximum voltage across the capacitor, we can use the formula:

\(V_{\text{max}} = V_{\text{rms}} \times \sqrt{2}[\tex]

Where \(V_{\text{rms}}\) is the rms voltage of the AC source.

Given that the rms voltage is 36.0V, we can calculate the maximum voltage across the capacitor:

\(V_{\text{max}} = 36.0V \times \sqrt{2}[\tex]

To find the capacitive reactance \(X_{C}\), we can use the formula:

\(X_{C} = \frac{1}{2\pi fC}[\tex]

Where \(f\) is the frequency of the AC source and \(C\) is the capacitance.

Given that the frequency is 60.0 Hz and the capacitance is 12.0µF, we can calculate the capacitive reactance:

\(X_{C} = \frac{1}{2\pi \times 60.0\text{ Hz} \times 12.0\mu\text{F}}[\tex]

Now, we can substitute the values into the formula to find the maximum current:

\(I = \frac{36.0\text{V} \times \sqrt{2}}{\frac{1}{2\pi \times 60.0\text{Hz} \times 12.0\mu\text{F}}}[\tex]

Simplifying the expression, we get:

\(I = \frac{36.0\text{V} \times \sqrt{2}}{\frac{1}{4\pi \times 720.0\times 10^{-6}}}[\tex]

\(I = \frac{36.0\text{V} \times \sqrt{2}}{\frac{1}{2.8622\times 10^{-3}}}[\tex]

\(I = \frac{36.0\text{V} \times \sqrt{2}}{349.02}[\tex]

\(I \approx 0.206\text{A}[\tex]

Therefore, the maximum current in the circuit is approximately 0.206A.

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